How to grep curl -I header information
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by Mint
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Published on 2010-06-03T11:27:27Z
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2010/06/03
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Im trying to get the redirect link from a site by using curl -I then grep to "location" and then sed out the location text so that I am left with the URL.
But this doesn't work, it will outputs the URL to screen and doesn't put it
test=$(curl -I "http://www.redirectURL.com/" 2> /dev/null | grep "location" | sed -E 's/location:[ ]+//g')
echo "1..$test..2"
Which then outputs:
..2http://www.newURLfromRedirect.com/bla
Whats going on?
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