BASH: Checking for environment variables

Posted by Hamza on Stack Overflow See other posts from Stack Overflow or by Hamza
Published on 2010-06-05T20:02:10Z Indexed on 2010/06/05 20:02 UTC
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Hi folks,

I am trying to check the value of an environment variable and depending on the value do certain things and it works fine as long as the variable is set. When it isn't though I get a whole bunch of errors (as BASH is trying to compare the string I specify with an undefined variable, I guess)

I tried implementing an extra check to prevent it happening but no luck. The block of code I am using is:

#!/bin/bash

if [ -n $TESTVAR ]
then
  if [ $TESTVAR == "x" ]
  then
    echo "foo"
    exit
  elif [ $TESTVAR == "y" ]
  then
    echo "bar"
    exit
  else
    echo "baz"
    exit
  fi
else
  echo -e "TESTVAR not set\n"
fi

And this the output:

$ export TESTVAR=x
$ ./testenv.sh 
foo
$ export TESTVAR=y
$ ./testenv.sh 
bar
$ export TESTVAR=q
$ ./testenv.sh 
baz
$ unset TESTVAR
$ ./testenv.sh 
./testenv.sh: line 5: [: ==: unary operator expected
./testenv.sh: line 9: [: ==: unary operator expected
baz

My question is, shouldn't 'unset TESTVAR' nullify it? It doesn't seem to be the case...

Thanks.

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