how to list out the submited data in same page where form submitted?

Posted by OM The Eternity on Stack Overflow See other posts from Stack Overflow or by OM The Eternity
Published on 2010-06-15T13:29:11Z Indexed on 2010/06/15 13:32 UTC
Read the original article Hit count: 120

Filed under:
|
|
|

I have a form with 3 text values and one image.. I want to save these values such that i can display these records in the list below.. how can i do that... I am using osCommerce

For example:

<form method="post" id="fm-form" action ="" enctype="multipart/form-data">
      <label>Name:</label>
          <input type="text" id="fm-name" name="fm-name" value="" />
          <label>Email:</label>
          <input type="text" id="fm-email" name="fm-email" value="" />
          <label>Birthdate:</label>
          <input type="text" id="fm-birthdate" name="fm-birthdate" value="" />
          <input type="file" id="fm-image" name="fm-image"/>
          <input type="submit" id="fm-submit" value="Save it">
      </form>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr >
<td align="center" class="productListing-heading">Product(s)</td>
<td align="center" class="productListing-heading">Edit</td>
<td align="center" class="productListing-heading">Delete</td>
</tr>
<?php for($i=0;$i<$count_image;$i++){?>
<tr>
<td align="left" class="productListing-data1">
<?php echo tep_image(DIR_WS_IMAGES . $file_realname, $save_image[$i], '110', '110');?>
</td>
<td align="center" class="productListing-data1">Edit</td>
<td align="center" class="productListing-data1">Delete</td>
</tr>
<tr><td>&nbsp;</td></tr>
     <?php }?>         </table>

In the above format as the form is submitted the image has to be stored in a count_image array variable... and the on its count, the list below the form is displayed.. but i cannot get it worked.. could u pls help in doing this...

© Stack Overflow or respective owner

Related posts about php

Related posts about form