How can I filter these Django records?

Posted by mipadi on Stack Overflow See other posts from Stack Overflow or by mipadi
Published on 2010-06-15T19:36:23Z Indexed on 2010/06/16 10:33 UTC
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I have a set of Django models as shown in the following diagram (the names of the reverse relationships are shown in the yellow bubbles):

Django models

In each relationship, a Person may have 0 or more of the items.

Additionally, the slug field is (unfortunately) not unique; multiple Person records may have the same slug fields. Essentially these records are duplicates.

I want to obtain a list of all records that meet the following criteria: All duplicate records (that is, having the same slug) with at least one Entry OR at least one Audio OR at least one Episode OR at least one Article.

So far, I have the following query:

Person.objects.values('slug').annotate(num_records=Count('slug')).filter(num_records__gt=1)

This groups all records by slug, then adds a num_records attribute that says how many records have that slug, but the additional filtering is not performed (and I don't even know if this would work right anyway, since, given a set of duplicate records, one may have, e.g., and Entry and the other may have an Article).

In a nutshell, I want to find all duplicate records and collapse them, along with their associated models, into one record.

What's the best way to do this with Django?

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