Shell Script- each unique user

Posted by Dinis Monteiro on Stack Overflow See other posts from Stack Overflow or by Dinis Monteiro
Published on 2011-01-10T18:42:39Z Indexed on 2011/01/10 18:53 UTC
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Hi guys

I need "for each unique user, report which group they are a member of and when they last logged in"

so i have:

#!/bin/sh

echo "Your initial login:"
who | cut -d' ' -f1 | sort | uniq

echo "Now is logged:"
whoami

echo "Group ID:"
id -G $whoami

case $1 in
   "-l") last -Fn 10 | tr -s " " ;;
   *)    last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c
esac

My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users.

anyone can help?

thanks

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