Correct usage of "<T extends SuperClass>"

Posted by yusaku on Stack Overflow See other posts from Stack Overflow or by yusaku
Published on 2011-02-17T14:58:29Z Indexed on 2011/02/17 15:25 UTC
Read the original article Hit count: 174

Filed under:
|

I am not familiar with "Generics". Is it a correct use of "<T extends SuperClass>" ? And do you agree that the codes after using generics are better?

Before using Generics
=================================================

public abstract class SuperSample {

    public void getSomething(boolean isProcessA) {
        doProcessX();
        if(isProcessA){
            doProcessY(new SubASample());
        }else{
            doProcessY(new SubBSample());
        }
    }

    protected abstract void doProcessX();

    protected void doProcessY(SubASample subASample) {
        // Nothing to do
    }

    protected void doProcessY(SubBSample subBSample) {
        // Nothing to do
    }

}

public class SubASample extends SuperSample {

    @Override
    protected void doProcessX() {
        System.out.println("doProcessX in SubASample");
    }

    @Override
    protected void doProcessY(SubASample subASample) {
        System.out.println("doProcessY in SubASample");
    }

}

public class Sample {

    public static void main(String[] args) {
        SubASample subASample = new SubASample();
        subASample.getSomething(true);
    }

}

After using Generics
=================================================

public abstract class SuperSample {

    public void getSomething(boolean isProcessA) {
        doProcessX();
        if(isProcessA){
            doProcessY(new SubASample());
        }else{
            doProcessY(new SubBSample());
        }
    }

    protected abstract void doProcessX();

    protected abstract <T extends SuperSample> void doProcessY(T subSample);

}

public class SubASample extends SuperSample {

    @Override
    protected void doProcessX() {
        System.out.println("doProcessX in SubASample");
    }

    @Override
    protected <T extends SuperSample> void doProcessY(T subSample) {
        System.out.println("doProcessY in SubASample");
    }

}

public class Sample {

    public static void main(String[] args) {
        SubASample subASample = new SubASample();
        subASample.getSomething(true);
    }

}

© Stack Overflow or respective owner

Related posts about java

Related posts about generics