find files their name is smaller or greater than a given parameter

Posted by Tzury Bar Yochay on Server Fault See other posts from Server Fault or by Tzury Bar Yochay
Published on 2011-03-09T09:00:08Z Indexed on 2011/03/09 16:12 UTC
Read the original article Hit count: 197

Filed under:
|
|

Say that in a given directory I got

tzury@x200:~/Desktop/sandbox$ ls -l
total 20
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P000
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P001
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P002
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P003
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P004
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P000
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P001
drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P002

I seek for a bash way to grab the list of files which their name is either grater or smaller than a given parameter, for instance:

$ my_finder lt N00.P003

shall return N00.P000, N00.P001 and N00.P002

$ my_finder gt N00.P003

shall return N00.P004, N01.P000, N01.P001 and N01.P002

I was thinking of iterating over for name in $(ls) and while $name != $2 but believe there are more elegant way of doing so

© Server Fault or respective owner

Related posts about bash

Related posts about file