storing data at remote server using php

Posted by VIPUL GOYAL on Stack Overflow See other posts from Stack Overflow or by VIPUL GOYAL
Published on 2012-03-20T17:27:14Z Indexed on 2012/03/20 17:29 UTC
Read the original article Hit count: 298

Filed under:
|
|
|
|

I want to send data to php file and execute insert query in it to store data in database. When i execute this code, it executes but database does not get updated.

Code of PHP file

Java code------------------------------Remote.java------------------------------

    public class Remote extends Activity {
    EditText name;
    Button s;
    String r;
    @Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    name= (EditText)findViewById(R.id.editText1);
    s=(Button)findViewById(R.id.button1);

    s.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
        try {
             r = name.getText().toString();
             ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();  
             postParameters.add(new BasicNameValuePair("username", r));  
         CustomHttpClient.executeHttpPost("http://vipul.eu5.org/abc.php", postParameters);  //Enetr Your remote PHP,ASP, Servlet file link  

        } catch (Exception e) {
        e.printStackTrace();
        }
        }
        });


}

}

-----------------------------CustomHttpClient.java----------------------------

            public class CustomHttpClient {

    private static HttpClient getHttpClient() {  
    if (mHttpClient == null) {  
    mHttpClient = new DefaultHttpClient();  
    final HttpParams params = mHttpClient.getParams();  
    HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);  
    HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);  
    ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);  
    }  
    return mHttpClient;  
    }  
    /** 
    * Performs an HTTP Post request to the specified url with the 
    * specified parameters. 
    * 
    * @param url The web address to post the request to 
    * @param postParameters The parameters to send via the request 
    * @return The result of the request 
    * @throws Exception 
    */  
    public static void executeHttpPost(String url, ArrayList postParameters) throws Exception {  

    try {  
    HttpClient client = getHttpClient();  
    HttpPost request = new HttpPost(url);  
    UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);  
    request.setEntity(formEntity);  
    HttpResponse response = client.execute(request);  

}
    catch(Exception e)
    {


    }
    }

}

© Stack Overflow or respective owner

Related posts about android

Related posts about mysql