T-SQL: how to sort table rows based on 2 columns

Posted by Criss Nautilus on Stack Overflow See other posts from Stack Overflow or by Criss Nautilus
Published on 2012-10-27T16:55:14Z Indexed on 2012/10/27 17:00 UTC
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I'm quite stuck with this problem for sometime now..

How do I sort column A depending on the contents of Column B?

I have this sample:

    ID  count   columnA     ColumnB
    12  1   A       B
    13  2   C       D
    14  3   B       C

I want to sort it like this:

    ID  count   ColumnA     ColumnB
    12  1   A       B
    14  3   B       C
    13  2   C       D

so I need to sort the rows if the previous row of ColumnB = the next row of ColumnA I'm thinking a loop? but can't quite imagine how it will work... I was thinking it will go like this (maybe)

SELECT a.ID, a.ColumnA, a.ColumnB
FROM TableA WITH a (NOLOCK) 
    LEFT JOIN TableA b WITH (NOLOCK) 
        ON a.ID = b.ID
        and a.counts = b.counts
Where a.columnB = b.ColumnA

the above code isn't working though and I was thinking more on the lines of...

DECLARE @counts int = 1
DECLARE @done int = 0

--WHILE @done = 0
BEGIN
    SELECT a.ID, a.ColumnA, a.ColumnB
    FROM TableA WITH a (NOLOCK) 
    LEFT JOIN TableA b WITH (NOLOCK) 
        ON a.ID = b.ID
        and a.counts = @counts
    Where a.columnB = b.ColumnA

    set @count = @count +1
END

If this was a C code, would be easier for me but t-sql's syntax is making it a bit harder for a noobie like me.

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