C# program for finding how many numbers are devidable by 5 in give range

Posted by user1639735 on Stack Overflow See other posts from Stack Overflow or by user1639735
Published on 2012-11-04T22:44:45Z Indexed on 2012/11/04 23:00 UTC
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My task is: Write a program that reads two positive integer numbers and prints how many numbers p exist between them such that the reminder of the division by 5 is 0 (inclusive). Example: p(17,25) = 2.

Console.Write("Enter min: ");
            int min = int.Parse(Console.ReadLine());
            Console.Write("Enter max: ");
            int max = int.Parse(Console.ReadLine());
            Console.WriteLine("The numbers devidable by 5 without remainder from {0} to {1} are: ",min,max);
            for (int i = min; i <= max; i++)
            {
                if (i % 5 == 0)
                {

                    Console.WriteLine(i);
                }
            }

This prints out the numbers that are devidable by 5 in the range...How do I count how many are there and print the count in the console? Thanks.

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