C# has generic function types such as Action<T> or Func<T,U,V,...>
With the advent of C++0x and the ability to have template typedef's and variadic template parameters, it seems this should be possible.
The obvious solution to me would be this:
template <typename T>
using Action<T> = void (*)(T);
however, this does not accommodate for functors or C++0x lambdas, and beyond that, does not compile with the error "expected unqualified-id before 'using'"
My next attempt was to perhaps use boost::function:
template <typename T>
using Action<T> = boost::function<void (T)>;
This doesn't compile either, for the same reason.
My only other idea would be STL style template arguments:
template <typename T, typename Action>
void foo(T value, Action f) {
f(value);
}
But this doesn't provide a strongly typed solution, and is only relevant inside the templated function.
Now, I will be the first to admit that I am not the C++ wiz I prefer to think I am, so it's very possible there is an obvious solution I'm not seeing.
Is it possible to have C# style generic function types in C++?
