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• "dm-tool lock" doesn't lock my session

  - by cape1232

  When I use dm-tool to lock the screen for userA, I can log in as userB and then use dm-tool to switch back to userA's session without having to enter a password. Is that the expected behavior? If not, how should I switch from A to B without leaving userA exposed? userA$ dm-tool lock -- Shows Greeter. Login as userB. userB$ dm-tool switch-to-user userA -- Expected this to go to greeter, but it goes right back to userA's session. Do I have something mis-configured, or what?

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• How to create a shared lock blocking an intent exclusive lock

  - by FremenFreedom

  As I understand it, a SELECT statement will place a shared lock on the rows that it will return. While that SELECT is running, if an UPDATE statement comes along and needs to grab an intent exclusive lock then that UPDATE statement will need to wait until the SELECT statement releases its shared locks. I am trying to test this SELECT shared lock thing by doing a BEGIN TRAN and then running a SELECT, not COMMITing, and then running an UPDATE in another session on the exact same row. The UPDATE worked fine -- no lock, no wait. So this must not be a valid way to simulate a shared lock blocking an intent exclusive lock? Can you give me a scenario where I can create a lock with a SELECT that would force an UPDATE to wait? I'm working with SQL Server 2000 and 2005 across a linked server: the table is on the 2005 instance, the select is happening on 2000, and the update is executed from 2005. All in SSMS 2005.

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• How pattern lock disbles screen lock in android

  - by CED

  Hi, In android 2.1, if we enable pattern lock, then the screen lock (slide to unlock) is not displayed and if pattern lock is disabled then screen lock is enabled again. Can someone point me out the java file in framework and the function where this happens. I mean when the screen is about to get locked, how does android decide that whether it will display pattern lock or screen lock and if pattern lock, how it prevents the screen lock from getting displayed.

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• Using CTAS & Exchange Partition Replace IAS for Copying Partition on Exadata

  - by Bandari Huang

  Usage Scenario: Copy data&index from one partition to another partition in a partitioned table. Solution: Create a partition definition Copy data from one partition to another partiton by 'Insert as select (IAS)' Create a nonpartitioned table by 'Create table as select (CTAS)' Convert a nonpartitioned table into a partition of partitoned table by exchangng their data segments. Rebuild unusable index Exchange Partition Convertion Mutual convertion between a partition (or subpartition) and a nonpartitioned table Mutual convertion between a hash-partitioned table and a partition of a composite *-hash partitioned table Mutual convertiton a [range | list]-partitioned table into a partition of a composite *-[range | list] partitioned table. Exchange Partition Usage Scenario High-speed data loading of new, incremental data into an existing partitioned table in DW environment Exchanging old data partitions out of a partitioned table, the data is purged from the partitioned table without actually being deleted and can be archived separately Exchange Partition Syntax ALTER TABLE schema.table EXCHANGE [PARTITION|SUBPARTITION] [partition|subprtition] WITH TABLE schema.table [INCLUDE|EXCLUDING] INDEX [WITH|WITHOUT] VALIDATION UPDATE [INDEXES|GLOBAL INDEXES] INCLUDING | EXCLUDING INDEXES Specify INCLUDING INDEXES if you want local index partitions or subpartitions to be exchanged with the corresponding table index (for a nonpartitioned table) or local indexes (for a hash-partitioned table). Specify EXCLUDING INDEXES if you want all index partitions or subpartitions corresponding to the partition and all the regular indexes and index partitions on the exchanged table to be marked UNUSABLE. If you omit this clause, then the default is EXCLUDING INDEXES. WITH | WITHOUT VALIDATION Specify WITH VALIDATION if you want Oracle Database to return an error if any rows in the exchanged table do not map into partitions or subpartitions being exchanged. Specify WITHOUT VALIDATION if you do not want Oracle Database to check the proper mapping of rows in the exchanged table. If you omit this clause, then the default is WITH VALIDATION.  UPADATE INDEX|GLOBAL INDEX Unless you specify UPDATE INDEXES, the database marks UNUSABLE the global indexes or all global index partitions on the table whose partition is being exchanged. Global indexes or global index partitions on the table being exchanged remain invalidated. (You cannot use UPDATE INDEXES for index-organized tables. Use UPDATE GLOBAL INDEXES instead.) Exchanging Partitions&Subpartitions Notes Both tables involved in the exchange must have the same primary key, and no validated foreign keys can be referencing either of the tables unless the referenced table is empty.  When exchanging partitioned index-organized tables: – The source and target table or partition must have their primary key set on the same columns, in the same order. – If key compression is enabled, then it must be enabled for both the source and the target, and with the same prefix length. – Both the source and target must be index organized. – Both the source and target must have overflow segments, or neither can have overflow segments. Also, both the source and target must have mapping tables, or neither can have a mapping table. – Both the source and target must have identical storage attributes for any LOB columns. 

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• copy boot-able partition

  - by Dima

  I have an disk image with 3 partitions: first partition (hd0,0) is boot-able with GRUB1 with the following configuration GRUB file: default=0 timeout=5 title Bank A root (hd0,1) chainloader +1 title Bank B root (hd0,2) chainloader +1 The partitions (hd0,1) and (hd0,2) are also boot-able. I'm trying to clone partition (hd0,1) to (hd0,2) by creating device map using kpartx and copying whole partition using dd command. The problem is: after partition cloning, the cloned partition did not boot (but all files are OK). What the wrong? I need both partitions to bee identical (I'm using them for fail-over purposes into embedded device)

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• Why lock-free data structures just aren't lock-free enough

  - by Alex.Davies

  Today's post will explore why the current ways to communicate between threads don't scale, and show you a possible way to build scalable parallel programming on top of shared memory. The problem with shared memory Soon, we will have dozens, hundreds and then millions of cores in our computers. It's inevitable, because individual cores just can't get much faster. At some point, that's going to mean that we have to rethink our architecture entirely, as millions of cores can't all access a shared memory space efficiently. But millions of cores are still a long way off, and in the meantime we'll see machines with dozens of cores, struggling with shared memory. Alex's tip: The best way for an application to make use of that increasing parallel power is to use a concurrency model like actors, that deals with synchronisation issues for you. Then, the maintainer of the actors framework can find the most efficient way to coordinate access to shared memory to allow your actors to pass messages to each other efficiently. At the moment, NAct uses the .NET thread pool and a few locks to marshal messages. It works well on dual and quad core machines, but it won't scale to more cores. Every time we use a lock, our core performs an atomic memory operation (eg. CAS) on a cell of memory representing the lock, so it's sure that no other core can possibly have that lock. This is very fast when the lock isn't contended, but we need to notify all the other cores, in case they held the cell of memory in a cache. As the number of cores increases, the total cost of a lock increases linearly. A lot of work has been done on "lock-free" data structures, which avoid locks by using atomic memory operations directly. These give fairly dramatic performance improvements, particularly on systems with a few (2 to 4) cores. The .NET 4 concurrent collections in System.Collections.Concurrent are mostly lock-free. However, lock-free data structures still don't scale indefinitely, because any use of an atomic memory operation still involves every core in the system. A sync-free data structure Some concurrent data structures are possible to write in a completely synchronization-free way, without using any atomic memory operations. One useful example is a single producer, single consumer (SPSC) queue. It's easy to write a sync-free fixed size SPSC queue using a circular buffer*. Slightly trickier is a queue that grows as needed. You can use a linked list to represent the queue, but if you leave the nodes to be garbage collected once you're done with them, the GC will need to involve all the cores in collecting the finished nodes. Instead, I've implemented a proof of concept inspired by this intel article which reuses the nodes by putting them in a second queue to send back to the producer. * In all these cases, you need to use memory barriers correctly, but these are local to a core, so don't have the same scalability problems as atomic memory operations. Performance tests I tried benchmarking my SPSC queue against the .NET ConcurrentQueue, and against a standard Queue protected by locks. In some ways, this isn't a fair comparison, because both of these support multiple producers and multiple consumers, but I'll come to that later. I started on my dual-core laptop, running a simple test that had one thread producing 64 bit integers, and another consuming them, to measure the pure overhead of the queue. So, nothing very interesting here. Both concurrent collections perform better than the lock-based one as expected, but there's not a lot to choose between the ConcurrentQueue and my SPSC queue. I was a little disappointed, but then, the .NET Framework team spent a lot longer optimising it than I did. So I dug out a more powerful machine that Red Gate's DBA tools team had been using for testing. It is a 6 core Intel i7 machine with hyperthreading, adding up to 12 logical cores. Now the results get more interesting. As I increased the number of producer-consumer pairs to 6 (to saturate all 12 logical cores), the locking approach was slow, and got even slower, as you'd expect. What I didn't expect to be so clear was the drop-off in performance of the lock-free ConcurrentQueue. I could see the machine only using about 20% of available CPU cycles when it should have been saturated. My interpretation is that as all the cores used atomic memory operations to safely access the queue, they ended up spending most of the time notifying each other about cache lines that need invalidating. The sync-free approach scaled perfectly, despite still working via shared memory, which after all, should still be a bottleneck. I can't quite believe that the results are so clear, so if you can think of any other effects that might cause them, please comment! Obviously, this benchmark isn't realistic because we're only measuring the overhead of the queue. Any real workload, even on a machine with 12 cores, would dwarf the overhead, and there'd be no point worrying about this effect. But would that be true on a machine with 100 cores? Still to be solved. The trouble is, you can't build many concurrent algorithms using only an SPSC queue to communicate. In particular, I can't see a way to build something as general purpose as actors on top of just SPSC queues. Fundamentally, an actor needs to be able to receive messages from multiple other actors, which seems to need an MPSC queue. I've been thinking about ways to build a sync-free MPSC queue out of multiple SPSC queues and some kind of sign-up mechanism. Hopefully I'll have something to tell you about soon, but leave a comment if you have any ideas.

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• Software installed on root partition or on home partition

  - by Tim

  I am planning to install some big softwares such as Matlab (4GB), Mathematica (4GB) on my Ubuntu partitions. I was wondering if I installed them on my home partition, when I reinstall Ubuntu without touching the home partition, will the softwares still be runnable after reinstallation? what are the advantage and disadvantages of installing softwares on root partition and of on home partition? with your answer to the previous questions, what are some reasonable plans for the sizes of root partition and of home partition? Note that I would like to learn programming in C, C++, Java, Python, Lisp, databases under both Ubuntu and Windows, and no games. My laptop has around 230 GB, where I plan to install both Windows and Ubuntu, and reserve 40 GB for Ubuntu (three partitions: swap, root and home), 110 GB for NTFS partition shared between the two OSes, 70 GB for Windows OS partition, and 10 GB that can be added to any of the above partitions. I will change my plan according to your suggestions. Thanks and regards!

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• Purpose of /run/lock/ (empty except for ./whoopsie/)

  - by Aeyoun

  My /run/lock/ directory is empty except for ./whoopsie/. I have understood /run/lock/ as a replacement for /var/lock/ but was surprised to find it entirely empty. Is whoopsie meant as a deterrent from using this directory? I did find other lock files under /run/, though. Most notably in /run/user/<me>/. I would have expect per-users lock files in /run/lock/user/ and not in a separate directory. Hoping for some clarification!

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• Lock a partition to a few folders

  - by Oxwivi

  I want to have a few folders on a partition whose contents I can freely edit, but outside nothing should be saved. Specifically, I want the folders in my Home (Documents, Music, etc) on a different partition, but rest of the normally hidden folders remain in the main partition with Ubuntu. I can make the files within the Home folders save in another partition using fstab binding, but I still can't think of how to lock the partition from edits outside those folders. I'm open to suggestions of alternatives to binding - but please, no symbolic links.

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• Know More About Oracle Row Lock

  - by Liu Maclean(???)

  ??????Oracle??????????row lock,??ORACLE????????????????????,row lock???????????????????????????????,??Server Process?pin????block buffer????????? ????????,?process A ??update???????? Z?????????, ???????rollback???commit;??Process B??????DML??, ???????rowid???? Z???, ???????????process A????????ITL???,????????cleanout??,????????row???????????commit, ???????Process B????”enq: TX – row lock contention”??????? ????Process B????????????? ?????????Process A???????row,??Process B???????”enq: TX – row lock contention”???? ????????  ????????: SESSION A: SQL> select * from v$version; BANNER ---------------------------------------------------------------- Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi PL/SQL Release 10.2.0.5.0 - Production CORE    10.2.0.5.0      Production TNS for Linux: Version 10.2.0.5.0 - Production NLSRTL Version 10.2.0.5.0 - Production SQL> select * from global_name; GLOBAL_NAME -------------------------------------------------------------------------------- www.oracledatabase12g.com SQL> create table maclean_lock(t1 int); Table created. SQL> insert into maclean_lock values (1); 1 row created. SQL> commit; Commit complete. SQL> select dbms_rowid.rowid_block_number(rowid),dbms_rowid.rowid_relative_fno(rowid) from maclean_lock; DBMS_ROWID.ROWID_BLOCK_NUMBER(ROWID) DBMS_ROWID.ROWID_RELATIVE_FNO(ROWID) ------------------------------------ ------------------------------------                                67642                                    1 SQL>  select distinct sid from v$mystat;        SID ----------        142 SQL> select pid,spid from v$process where addr = ( select paddr from v$session where sid=(select distinct sid from v$mystat));        PID SPID ---------- ------------         17 15636 ??SESSION A ????savepoint ,?update ?????????         SQL>  savepoint NONLOCK; Savepoint created. SQL> select * From v$Lock where sid=142; no rows selected SQL> set linesize 140 pagesize 1400 SQL>  update maclean_lock set t1=t1+2; 1 row updated. SQL> select * From v$Lock where sid=142; ADDR             KADDR                   SID TY        ID1        ID2      LMODE    REQUEST      CTIME      BLOCK ---------------- ---------------- ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- 0000000091FC69F0 0000000091FC6A18        142 TM      55829          0          3          0          6          0 00000000914B4008 00000000914B4040        142 TX     393232        609          6          0          6          0         SQL> select dump(3,16) from dual; DUMP(3,16) -------------------------------------------------------------------------------- Typ=2 Len=2: c1,4 ALTER SYSTEM DUMP DATAFILE 1 BLOCK 67642;  Object id on Block? Y  seg/obj: 0xda16  csc: 0x00.234718  itc: 2  flg: O  typ: 1 - DATA      fsl: 0  fnx: 0x0 ver: 0x01  Itl           Xid                  Uba         Flag  Lck        Scn/Fsc 0x01   0x000a.00f.000001e0  0x00800075.02a6.29  C---    0  scn 0x0000.00234711 0x02   0x0007.018.000001fe  0x0080065c.017a.02  ----    1  fsc 0x0000.00000000 data_block_dump,data header at 0x81d185c =============== tsiz: 0x1fa0 hsiz: 0x14 pbl: 0x081d185c bdba: 0x0041083a      76543210 flag=-------- ntab=1 nrow=1 frre=-1 fsbo=0x14 fseo=0x1f9a avsp=0x1f83 tosp=0x1f83 0xe:pti[0]      nrow=1  offs=0 0x12:pri[0]     offs=0x1f9a block_row_dump: tab 0, row 0, @0x1f9a tl: 6 fb: --H-FL-- lb: 0x2  cc: 1 col  0: [ 2]  c1 04 end_of_block_dump ?? BLOCK DUMP ???? ??????XID=0x0007.018.000001fe ?transaction?? lb:0x1 ??SESSION B ,?????UPDATE?? ???enq: TX - row lock contention ?? SQL> select distinct sid from v$mystat;        SID ----------        140 SQL> select pid,spid from v$process where addr = ( select paddr from v$session where sid=(select distinct sid from v$mystat));        PID SPID ---------- ------------         24 15652 SQL> alter system set "_trace_events"='10000-10999:255:24'; System altered.         SQL> update maclean_lock set t1=t1+2; select * From v$Lock where sid=142 or sid=140 order by sid; SESSION C: SQL> select * From v$Lock where sid=142 or sid=140 order by sid; ADDR             KADDR                   SID TY        ID1        ID2      LMODE    REQUEST      CTIME      BLOCK ---------------- ---------------- ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- 0000000091FC6B10 0000000091FC6B38        140 TM      55829          0          3          0         84          0 00000000924F4A58 00000000924F4A78        140 TX     458776        510          0          6         84          0 00000000914B51E8 00000000914B5220        142 TX     458776        510          6          0        312          1 0000000091FC69F0 0000000091FC6A18        142 TM      55829          0          3          0        312          0 ???? SESSION B SID=140 ?SESSION A ?TX ENQUEUE ?X mode?REQUEST SQL> oradebug dump systemstate 266; Statement processed. SESSION B waiter's enqueue lock       SO: 0x924f4a58, type: 5, owner: 0x92bb8dc8, flag: INIT/-/-/0x00       (enqueue) TX-00070018-000001FE    DID: 0001-0018-00000022       lv: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  res_flag: 0x6       req: X, lock_flag: 0x0, lock: 0x924f4a78, res: 0x925617c0       own: 0x92b76be0, sess: 0x92b76be0, proc: 0x92a737a0, prv: 0x925617e0 TX-00070018-000001FE=> TX 458776 510 SESSION A owner's enqueue lock       SO: 0x914b51e8, type: 40, owner: 0x92b796d0, flag: INIT/-/-/0x00       (trans) flg = 0x1e03, flg2 = 0xc0000, prx = 0x0, ros = 2147483647 bsn = 0xed5 bndsn = 0xee7 spn = 0xef7       efd = 3       file:xct.c lineno:1179       DID: 0001-0011-000000C2       parent xid: 0x0000.000.00000000       env: (scn: 0x0000.00234718  xid: 0x0007.018.000001fe  uba: 0x0080065c.017a.02  statement num=0  parent xid: xid: 0x0000.000.00000000  scn: 0x00 00.00234718 0sch: scn: 0x0000.00000000)       cev: (spc = 7818  arsp = 914e8310  ubk tsn: 1 rdba: 0x0080065c  useg tsn: 1 rdba: 0x00800069             hwm uba: 0x0080065c.017a.02  col uba: 0x00000000.0000.00             num bl: 1 bk list: 0x91435070)             cr opc: 0x0 spc: 7818 uba: 0x0080065c.017a.02       (enqueue) TX-00070018-000001FE    DID: 0001-0011-000000C2       lv: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  res_flag: 0x6       mode: X, lock_flag: 0x0, lock: 0x914b5220, res: 0x925617c0       own: 0x92b796d0, sess: 0x92b796d0, proc: 0x92a6ffd8, prv: 0x925617d0        xga: 0x8b7c6d40, heap: UGA       Trans IMU st: 2 Pool index 65535, Redo pool 0x914b58d0, Undo pool 0x914b59b8       Redo pool range [0x86de640 0x86de640 0x86e0e40]       Undo pool range [0x86dbe40 0x86dbe40 0x86de640]         ----------------------------------------         SO: 0x91435070, type: 39, owner: 0x914b51e8, flag: -/-/-/0x00         (List of Blocks) next index = 1         index   itli   buffer hint   rdba       savepoint         -----------------------------------------------------------             0      2   0x647f1fc8    0x41083a     0xee7 ?SESSION A? ROLLBACK ?savepoint: SQL> rollback to NONLOCK; Rollback complete. ????savepoint ??update??????? ??UPDATE???????? ROLLBACK: SQL> select * From v$Lock where sid=142 or sid=140; ADDR             KADDR                   SID TY        ID1        ID2      LMODE    REQUEST      CTIME      BLOCK ---------------- ---------------- ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- 00000000924F4A58 00000000924F4A78        140 TX     458776        510          0          6        822          0 0000000091FC6B10 0000000091FC6B38        140 TM      55829          0          3          0        822          0 00000000914B51E8 00000000914B5220        142 TX     458776        510          6          0       1050          1 ???? SESSION A 142 ???SAVEPOINT ???????TM LOCK ????? ROLLBACK TO SAVEPOINT?????SESSION???TX LOCK!!!! ??????SESSION 142???TX ID1=458776 ID2=510, ????ROLLBACK TO SAVEPOINT?????????ABORT TRANSACTION ?? SESSION B  SID=140??  SESSION A ?? , ?????????SESSION B? update???HANG?? ?????????CACHE?????:  Object id on Block? Y  seg/obj: 0xda16  csc: 0x00.2347b7  itc: 2  flg: O  typ: 1 - DATA      fsl: 0  fnx: 0x0 ver: 0x01  Itl           Xid                  Uba         Flag  Lck        Scn/Fsc 0x01   0x000a.00f.000001e0  0x00800075.02a6.29  C---    0  scn 0x0000.00234711 0x02   0x0000.000.00000000  0x00000000.0000.00  ----    0  fsc 0x0000.00000000 data_block_dump,data header at 0x745d85c =============== tsiz: 0x1fa0 hsiz: 0x14 pbl: 0x0745d85c bdba: 0x0041083a      76543210 flag=-------- ntab=1 nrow=1 frre=-1 fsbo=0x14 fseo=0x1f9a avsp=0x1f83 tosp=0x1f83 0xe:pti[0]      nrow=1  offs=0 0x12:pri[0]     offs=0x1f9a block_row_dump: tab 0, row 0, @0x1f9a tl: 6 fb: --H-FL-- lb: 0x0  cc: 1 col  0: [ 2]  c1 02 end_of_block_dump ???? ITL=0x02? ?????????,col  0: [ 2]  c1 02 ????????? ?????????SESSION D ,??????row lock?? ?UPDATE???????? SESSION D: SQL> update maclean_lock set t1=t1+2; 1 row updated. SQL> rollback; Rollback complete. ??SESSION B ??????????? ?????ORACLE????????, ??????????? TX lock?? row lock , ????????2??? row lock?????????, ?TX lock????????ENQUEUE LOCK???? ?????????PROCESS K?DML???????????????????????,??????????TX LOCK, ????PROCESS Z?????????????????????????ROW LOCK????????, ???????OLTP?????????????????????? ??ROW LOCK?Release ??????TX?ENQUEUE LOCK,?????????Process J ????????????, Process K??????????? ,Process K?????????,???row piece?lb??0x0 ,?????ITL, Process Z???ITL???????Process J????XID,?????Process J?????TX lock, PROCESS K ???TX resource?Enqueue Waiter Linked List?????X mode(exclusive)?enqueue lock? ???Process J??TX lock?,Process J?????TX resource?Enqueue Waiter Linked List ???Process K??????,??POST?????Process K? TX lock??????, ???????row lock???????,????????? ?????????? ?????: SESSION A ???PID =17 ?????????????????? SESSION B ???PID =24 ??????? "_trace_events"='10000-10999:255:24';  KST trace ??????? Server Process??? SESSION A PID=17  ?? acqure?SX mode???TM Lock ,?? ????Transaction?????UNDO SEGMENT 7,???XID 7.24.510, ?acquire ?X mode? TX-00070018-000001fe ? ?????? 00070018-000001fe ???? 7- 24 - 510? XID ? 781F4B8A:007A569C    17   142 10704  83 ksqgtl: acquire TM-0000da15-00000000 mode=SX flags=GLOBAL|XACT why="contention" 781F4B92:007A569D    17   142 10704  19 ksqgtl: SUCCESS 781F4BB3:007A569E    17   142 10812   2 0x000000000041083A 0x0000000000000000 0x0000000000234717 781F4BBA:007A569F    17   142 10812   3 0x0000000000000000 0x0000000000000000 0x0000000000000000 781F4BC0:007A56A0    17   142 10812   4 0x0000000000000000 0x0000000000000000 0x0000000000000000 781F4BD3:007A56A1    17   142 10812   5 0x000000000041083A 0x0000000000000000 0x0000000000000000 781F4BFE:007A56A2    17   142 10811   1 0x000000000041083A 0x0000000000000000 0x0000000000234711 0x0000000000000002 781F4C06:007A56A3    17   142 10811   2 0x000000000041083A 0x0000000000000000 0x0000000000234718 0x00007FA074EDA560 781F4C26:007A56A4    17   142 10813   1 ktubnd: Bind usn 7 nax 1 nbx 0 lng 0 par 0 781F4C43:007A56A5    17   142 10813   2 ktubnd: Txn Bound xid: 7.24.510 781F4C4A:007A56A6    17   142 10704  83 ksqgtl: acquire TX-00070018-000001fe mode=X flags=GLOBAL|XACT why="contention" 781F4C51:007A56A7    17   142 10704  19 ksqgtl: SUCCESS ?????????? ???????? 781F4CBF:007A56A8    17   142 10005   1 KSL WAIT BEG [SQL*Net message to client] 1650815232/0x62657100 1/0x1 0/0x0 781F4CCC:007A56A9    17   142 10005   2 KSL WAIT END [SQL*Net message to client] 1650815232/0x62657100 1/0x1 0/0x0 time=13 781F4CDE:007A56AA    17   142 10005   1 KSL WAIT BEG [SQL*Net message from client] 1650815232/0x62657100 1/0x1 0/0x0 786BD85D:007A57E0    17   142 10005   2 KSL WAIT END [SQL*Net message from client] 1650815232/0x62657100 1/0x1 0/0x0 time=5016447 786BD966:007A57E1    17   142 10005   1 KSL WAIT BEG [SQL*Net message to client] 1650815232/0x62657100 1/0x1 0/0x0 786BD96E:007A57E2    17   142 10005   2 KSL WAIT END [SQL*Net message to client] 1650815232/0x62657100 1/0x1 0/0x0 time=8 SESSION B ???PID =24  ,??????? SX mode? TM lock,??row lock? acquire X mode?TX-00070018-000001fe ksqgtl: acquire TM-0000da15-00000000 mode=SX flags=GLOBAL|XACT why="contention" ksqgtl: SUCCESS 0x000000000041083A 0x0000000000000000 0x00000000002354F8 0x0000000000000000 0x0000000000000000 0x0000000000000000 0x0000000000000000 0x0000000000000000 0x0000000000000000 0x000000000041083A 0x0000000000000000 0x00000000002354F8 0x0000000000000001 0x000000000041083A 0x0000000000000000 0x00000000002354F8 0x0000000008A63780 0x0000000000000001 0x0000000000800861 0x0000000000000241 0x0000000000000001 0x000000000041083A 0x0000000000000001 0x0000000000000001 0x000000000041083A 0x0000000000000000 0x00000000002354F9 0x0000000000000002 ksqgtl: acquire TX-00070018-000001fe mode=X flags=GLOBAL|LONG why="row lock contention" C4048EBD:007F52B6    24   140 10005   2 KSL WAIT END [enq: TX - row lock contention] 1415053318/0x54580006 458776/0x70018 510/0x1fe time=2929879 C4048ED4:007F52B7    24   140 10005   1 KSL WAIT BEG [enq: TX - row lock contention] 1415053318/0x54580006 458776/0x70018 510/0x1fe C43146CA:007F535E    24   140 10005   2 KSL WAIT END [enq: TX - row lock contention] 1415053318/0x54580006 458776/0x70018 510/0x1fe time=2930676 ????????? ,PID=24 ??????ksqcmi???????? deadlock C43146D9:007F535F    24   140 10704 134 ksqcmi: performing local deadlock detection on TX-00070018-000001fe C43146F8:007F5360    24   140 10704 150 ksqcmi: deadlock not detected on TX-00070018-000001fe ?? ??? PID 17 ??ROLLBACK ???? ,????????: PID 17 ROLLBACK; D7A495BB:007F9D3E    17   142 10005   4 KSL POST SENT postee=24 loc='ksqrcl' id1=0 id2=0 name=   type=0 D7A495D8:007F9D3F    17   142 10444  12 ABORT TRANSACTION - xid: 0x0007.018.000001fe ??  PID 17 ??? TX resource?Enqueue Waiter linked List ???PID 24???,????KSL POST SENT ?? PID 24, ???ksqrcl???ENQUEUE LOCK ?PID 24??????KSL POST (KSL POST RCVD poster=17), ?ksqgtl???? TX-00070018-000001fe ?? ksqrcl??, ??PID 24???????? TX lock?USN ,??????? USN 3 XID 3.11.582 ,???acquire TX-0003000b-00000246 D7A49616:007F9D41    24   140 10005   3 KSL POST RCVD poster=17 loc='ksqrcl' id1=0 id2=0 name=   type=0 fac#=0 facpost=1 D7A4961C:007F9D42    24   140 10704  19 ksqgtl: SUCCESS D7A4967D:007F9D43    24   140 10704 117 ksqrcl: release TX-00070018-000001fe mode=X D7A496A5:007F9D44    24   140 10813   1 ktubnd: Bind usn 3 nax 1 nbx 0 lng 0 par 0 D7A496C2:007F9D45    24   140 10813   2 ktubnd: Txn Bound xid: 3.11.582 D7A496C7:007F9D46    24   140 10704  83 ksqgtl: acquire TX-0003000b-00000246 mode=X flags=GLOBAL|XACT why="contention" D7A496E4:007F9D47    24   140 10704  19 ksqgtl: SUCCESS ROW LOCK?Release ??????TX?ENQUEUE LOCK,?????????Process J ????????????, Process K??????????? ,Process K?????????,???row piece?lb??0×0 ,?????ITL,Process Z???ITL???????Process J????XID,?????Process J?????TX lock,PROCESS K ???TX resource?Enqueue Waiter Linked List?????X mode(exclusive)?enqueue lock? ???Process J??TX lock?,Process J?????TX resource?Enqueue Waiter Linked List ???Process K??????,??POST?????Process K? TX lock??????,???????row lock???????,?????????

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• Partition table correpted in windows 7 machine as simple dynamic partition

  - by raki

  I have Windows 7 installed in my system. When I originally partitioned it I made 3 partitions and 16 gb space as unallocated. Later I tried to create a partition using this free space using diskmanagement tool. It shows free space as unusabe space and the only one option available is to make it as a simple partition. Unfortunately I made it as simple partition and all my partitions converted to simple dynamic partition. Now after reboot the OS is not loading. I tried to reinstall the OS by formatting the C drive, but it doesn't work. Now I can't load the OS properly. How can I install Windows 7 on my system without losing my data on the other two drives?

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• convert a logical partition to a primary partition

  - by ant2009

  Hello, Fedora 14 xfce I have the following partition setup. I would like to know how can I convert the logical partition sda6 to a primary partition. Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x1707a8a5 Device Boot Start End Blocks Id System /dev/sda1 2048 1026047 512000 83 Linux /dev/sda2 1026048 205844479 102409216 83 Linux /dev/sda3 205844480 214228991 4192256 82 Linux swap / Solaris /dev/sda4 214228992 625141759 205456384 5 Extended /dev/sda5 214231040 573562879 179665920 83 Linux /dev/sda6 573564928 625141759 25788416 7 HPFS/NTFS Filesystem Size Used Avail Use% Mounted on /dev/sda2 97G 5.0G 91G 6% / tmpfs 494M 176K 494M 1% /dev/shm /dev/sda1 485M 68M 392M 15% /boot /dev/sda5 169G 26G 135G 16% /home # partition table of /dev/sda unit: sectors /dev/sda1 : start= 2048, size= 1024000, Id=83 /dev/sda2 : start= 1026048, size=204818432, Id=83 /dev/sda3 : start=205844480, size= 8384512, Id=82 /dev/sda4 : start=214228992, size=410912768, Id= 5 /dev/sda5 : start=214231040, size=359331840, Id=83 /dev/sda6 : start=573564928, size= 51576832, Id= 7 I would like to convert sda6 to a primary partition, the reason for this it to install windows 7 starter. Many thanks for any suggestions,

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• Partition table correpted in windows 7 machine as simple dynamic partition

  - by raki

  I have Windows 7 installed in my system. When I originally partitioned it I made 3 partitions and 16 gb space as unallocated. Later I tried to create a partition using this free space using diskmanagement tool. It shows free space as unusabe space and the only one option available is to make it as a simple partition. Unfortunately I made it as simple partition and all my partitions converted to simple dynamic partition. Now after reboot the OS is not loading. I tried to reinstall the OS by formatting the C drive, but it doesn't work. Now I can't load the OS properly. How can I install Windows 7 on my system without losing my data on the other two drives?

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• Quantifying the effects of partition mis-alignment

  - by Matt

  I'm experiencing some significant performance issues on an NFS server. I've been reading up a bit on partition alignment, and I think I have my partitions mis-aligned. I can't find anything that tells me how to actually quantify the effects of mis-aligned partitions. Some of the general information I found suggests the performance penalty can be quite high (upwards of 60%) and others say it's negligible. What I want to do is determine if partition alignment is a factor in this server's performance problems or not; and if so, to what degree? So I'll put my info out here, and hopefully the community can confirm if my partitions are indeed mis-aligned, and if so, help me put a number to what the performance cost is. Server is a Dell R510 with dual E5620 CPUs and 8 GB RAM. There are eight 15k 2.5” 600 GB drives (Seagate ST3600057SS) configured in hardware RAID-6 with a single hot spare. RAID controller is a Dell PERC H700 w/512MB cache (Linux sees this as a LSI MegaSAS 9260). OS is CentOS 5.6, home directory partition is ext3, with options “rw,data=journal,usrquota”. I have the HW RAID configured to present two virtual disks to the OS: /dev/sda for the OS (boot, root and swap partitions), and /dev/sdb for a big NFS share: [root@lnxutil1 ~]# parted -s /dev/sda unit s print Model: DELL PERC H700 (scsi) Disk /dev/sda: 134217599s Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 63s 465884s 465822s primary ext2 boot 2 465885s 134207009s 133741125s primary lvm [root@lnxutil1 ~]# parted -s /dev/sdb unit s print Model: DELL PERC H700 (scsi) Disk /dev/sdb: 5720768639s Sector size (logical/physical): 512B/512B Partition Table: gpt Number Start End Size File system Name Flags 1 34s 5720768606s 5720768573s lvm Edit 1 Using the cfq IO scheduler (default for CentOS 5.6): # cat /sys/block/sd{a,b}/queue/scheduler noop anticipatory deadline [cfq] noop anticipatory deadline [cfq] Chunk size is the same as strip size, right? If so, then 64kB: # /opt/MegaCli -LDInfo -Lall -aALL -NoLog Adapter #0 Number of Virtual Disks: 2 Virtual Disk: 0 (target id: 0) Name:os RAID Level: Primary-6, Secondary-0, RAID Level Qualifier-3 Size:65535MB State: Optimal Stripe Size: 64kB Number Of Drives:7 Span Depth:1 Default Cache Policy: WriteBack, ReadAdaptive, Direct, No Write Cache if Bad BBU Current Cache Policy: WriteThrough, ReadAdaptive, Direct, No Write Cache if Bad BBU Access Policy: Read/Write Disk Cache Policy: Disk's Default Number of Spans: 1 Span: 0 - Number of PDs: 7 ... physical disk info removed for brevity ... Virtual Disk: 1 (target id: 1) Name:share RAID Level: Primary-6, Secondary-0, RAID Level Qualifier-3 Size:2793344MB State: Optimal Stripe Size: 64kB Number Of Drives:7 Span Depth:1 Default Cache Policy: WriteBack, ReadAdaptive, Direct, No Write Cache if Bad BBU Current Cache Policy: WriteThrough, ReadAdaptive, Direct, No Write Cache if Bad BBU Access Policy: Read/Write Disk Cache Policy: Disk's Default Number of Spans: 1 Span: 0 - Number of PDs: 7 If it's not obvious, virtual disk 0 corresponds to /dev/sda, for the OS; virtual disk 1 is /dev/sdb (the exported home directory tree).

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• Setting up a Pagefile and Partition in Server 2008

  - by Brett Powell

  I am setting up 18 new machines for our company, and I have instructions from my new boss on setting up a Pagefile and Partition. I have looked at their existing machines to base the new setups off of, but there is no consistency between any 2 machines, which has left me extremely frustrated to say the least. My instructions are... 1) Set a static pagefile (use recommended value as max/min), set it on SSD if SSD available. 2) Make 3 partitions: C: is used for OS and install files D: is used for backups on machines with a SSD. On machines without SSD create a D: partition for pagefile (2*installed RAM for partition size) E: must be the partition hosting user files I have never messed with Pagefiles before, and looking at their existing machines is offering no help. My questions are... 1) As the machines I am setting up have no SSD (just 2 SATA drives) does it sound like the Pagefile should be setup on the C: (primary) drive or the D:? The instructions are vague so I have no idea. 2) As C: and D: are both Physical drives, does it sound like C: should be partitioned out to create the E: drive or D:? Thanks for any help I can get. I am extremely stressed out under a massive workload right now, and these vague instructions are quite infuriating.

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• Unable to remove the lock by normal means

  - by Loki

  I've been installing ubuntu restricted extras via the software center. Everything was going well at first, but then the installation process froze on 'applying changes' stage. I've had this in the past already, and usually just hitting the 'cancel' button helped, but not this time. Obviously, the install process has placed a lock, and I couldn't issue any apt-get commands. then i've tried doing what was suggested here Fixing Could not get lock /var/lib/dpkg/lock : sudo fuser -cuk /var/lib/dpkg/lock; sudo rm -f /var/lib/dpkg/lock but it seemed to me that it has only killed my X server. Okay, i've just pressed the power button on my PC, and restarted, hoping that the lock was finally off and i could reinstall the stuff. No dice. when I open the software center, I still have one operation in process, a weird one: " Searching | Cancelling ". The 'cancel' button is either inactive, or it just does nothing. So I've become desperate and decided to write here. How do I fix the problem? Can't install anything on a fresh ubuntu 12.04 :) Thanks in advance

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• “BAD” partition showing up in Partition Manager

  - by Quintin Par

  I tried to partition my primary hard disk (NTFS partitions) with qtparted and got stuck in the process. Consequently I had to kill the process and exit my knoppix live CD boot up. Even though I was expecting XP to get corrupted, it booted fine and showed up all the drives accessible. But when I opened this with partition manager 8, it shows up as “BAD”. I ran chkdsk /f without any success. My objective with qparted and partition magic was to resize my existing partitions and add some space to c: How do I fix this problem and resize my partitions? Edit: Here's how my primary drive as per windows is

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• win 2008 core create a partition with an offset to allow other partition expand

  - by Rqomey

  We are running a win 2008 core host in a HyperV role. We have expanded the logical drive on a RAID 1+0 array belonging to the server, as we needed more space. We have two data partitions D: and E: I want to expand them both so they use all space, and are equally sized. There is data on all partitions, although E is not in live use (so files can be moved and copied from it. Current: What I want- temporary Partition (F:) at end of drive: I am going to create a temporary partition F: so I can move the files from E: onto it, then delete E:, expand D: to the desired size, then rename F: to E: To do this I need to create F: from the end of the drive, ie. have unused space between E: and F: tl;dr How do I create a partition with a large offset in Windows server?

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• Hidden Recovery Partition became visible after using GParted on another partition

  - by farrukh

  Just used GPartEd for resizing of D: partition, but now the hidden recovery partition became visible in windows explorer which is prone to accidental deletion etc. Any solution to this except gpedit.msc which is not available in windows7 home premium edition?

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• Java ReentrantReadWriteLocks - how to safely acquire write lock?

  - by Andrzej Doyle

  I am using in my code at the moment a ReentrantReadWriteLock to synchronize access over a tree-like structure. This structure is large, and read by many threads at once with occasional modifications to small parts of it - so it seems to fit the read-write idiom well. I understand that with this particular class, one cannot elevate a read lock to a write lock, so as per the Javadocs one must release the read lock before obtaining the write lock. I've used this pattern successfully in non-reentrant contexts before. What I'm finding however is that I cannot reliably acquire the write lock without blocking forever. Since the read lock is reentrant and I am actually using it as such, the simple code lock.getReadLock().unlock(); lock.getWriteLock().lock() can block if I have acquired the readlock reentrantly. Each call to unlock just reduces the hold count, and the lock is only actually released when the hold count hits zero. EDIT to clarify this, as I don't think I explained it too well initially - I am aware that there is no built-in lock escalation in this class, and that I have to simply release the read lock and obtain the write lock. My problem is/was that regardless of what other threads are doing, calling getReadLock().unlock() may not actually release this thread's hold on the lock if it acquired it reentrantly, in which case the call to getWriteLock().lock() will block forever as this thread still has a hold on the read lock and thus blocks itself. For example, this code snippet will never reach the println statement, even when run singlethreaded with no other threads accessing the lock: final ReadWriteLock lock = new ReentrantReadWriteLock(); lock.getReadLock().lock(); // In real code we would go call other methods that end up calling back and // thus locking again lock.getReadLock().lock(); // Now we do some stuff and realise we need to write so try to escalate the // lock as per the Javadocs and the above description lock.getReadLock().unlock(); // Does not actually release the lock lock.getWriteLock().lock(); // Blocks as some thread (this one!) holds read lock System.out.println("Will never get here"); So I ask, is there a nice idiom to handle this situation? Specifically, when a thread that holds a read lock (possibly reentrantly) discovers that it needs to do some writing, and thus wants to "suspend" its own read lock in order to pick up the write lock (blocking as required on other threads to release their holds on the read lock), and then "pick up" its hold on the read lock in the same state afterwards? Since this ReadWriteLock implementation was specifically designed to be reentrant, surely there is some sensible way to elevate a read lock to a write lock when the locks may be acquired reentrantly? This is the critical part that means the naive approach does not work.

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• Formatted Ubuntu partition & now grub says "error: no such partition" - can't enter windows

  - by qwBJ

  I had installed Ubuntu (current version: 11.xx) alongside Windows Vista. Now I formatted the Ubuntu partition & merged it with another partition (without thinking, obviously). Now, when I restart the computer, GRUB probably tries to find the old partition (which does no longer exist) and says: error: no such partition. grub rescue> Now I dont know what to do (I'm a total beginner). I tried to re-install Ubuntu on the newly formatted partition but this won't work, because after removing the install-usb (which I am said to do during installation) I find the above error-message again. I guess I need some way to reconfigure grub OR to reinstall grub/ubuntu (on the newly formatted partition) OR to reinstall the windows boot manager (without reinstall. Windows), but I have no idea how to do either of these things.

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• Lock Question - 'U' lock vs. 'X' lock

  - by Randy Minder

  I have a couple questions concerning Update (U) locks and Exclusive (X) locks. 1) Am I correct that an 'X' lock is put on a resource when the resource is about to get updated? 2) I'm a little fuzzy on U locks. Am I correct that a U lock is applied when a resource is read and SQL Server thinks it might need to update the resource later? If this is correct, would a 'U' lock only get applied when a read is being done within the context of a transaction? I guess I'm trying to understand under what circumstances SQL Server thinks it might need to update later a row it just read now. Thanks - Randy

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• Installation Error, "Unable to lock the administration directory"

  - by kern

  Whenever I try to install any software through Terminal or Software on my Ubuntu 11.04, I'm getting this response: In Terminal: E: Could not get lock /var/lib/dpkg/lock - open (11: Resource temporarily unavailable) E: Unable to lock the administration directory (/var/lib/dpkg/), is another process using it? In Software Center An unhandlable error occured There seems to be a programming error in aptdaemon, the software that allows you to install/remove software and to perform other package management related tasks. What should I do?

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• Lock screen does not display all users (ubuntu 14.10)

  - by Ali Alwan

  When I lock my screen using ctrl+alt+L, I am not able to see other users listed within the lock screen so I can switch instead. The lock screen shows only my name as an option for login, however I would like to switch to other user accounts. In Ubuntu 12.04 it used to show all system available users in lock screen and I was able to switch easily. Last night I upgraded to Ubuntu 14.04 and this option is gone. How do I set back this option?

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• Create a AD-LDS partition under a child of the primary partition

  - by ixe013

  I have a AD-LDS instance running on a Server 2008 R2. I have this application partition, created at installation : dc=enterprise,dc=example,dc=com I have succesfully followed this procedure to create application partitions. They are named : cn=stuff,dc=enterprise,dc=example,dc=com cn=things,dc=enterprise,dc=example,dc=com If I configure my client(s) to follow referals, I can search from dc=enterprise,dc=example,dc=com and find objects under cn=stuff and cn=things. How can I create (or move after the fact) the stuff and things partitions so they are logically located under a OU under the initial partition, ending up with something like : cn=stuff,ou=applications,dc=enterprise,dc=example,dc=com cn=things,ou=applications,dc=enterprise,dc=example,dc=com

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