need your help with the
code, please. I am trying to display an album from the database, but i just get some strange signs having no idea why... the signs are Albums
Help me out if you know how to solve this problem. how can i maKe the
code to display name of the album and amount of images in it? i am sure all is fine with the db.
this is the function:
function get_albums()
{
$albums = array();
// not always have got to put brackets
$albums_query = "SELECT albums.album_id, albums.timestamp, albums.name, LEFT(albums.description, 50) as description, COUNT(images.image_id) as image_count
FROM albums
LEFT JOIN images ON albums.album_id = images.album_id
WHERE albums.user_id = '{$_SESSION['user_id']}'
GROUP BY albums.album_id";
$res = mysql_query($albums_query) or die(mysql_error().'<br>'.$albums_query);
while($albums_row = mysql_fetch_assoc($res)){
$albums = array (
'id' => $albums_row['album_id'],
'timestamp'=> $albums_row['timestamp'],
'name' => $albums_row['name'],
'description' => $albums_row['description'],
'count' =>$albums_row['image_count']
);
}
return $albums;
}
and the other half of the code:
<?php
$albums = get_albums();
if(empty($albums)) {
echo'<p>You don\'t have any albums</p>';
}else{
foreach($albums as $album){
echo'<p><a href="view_album.php?album_id=',$album['id'],'">',$album['name'],'</a>(',$album['count'],'images)<br /></p>';
}
}
?>
