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  • Mysql help with view more button.

    - by WAC0020
    I am working on a widget that is a lot like twitters widget where there is a list of postings and a view more button. I can get it to work with using ID variables but I would like to sort by popular posts. Here is my mysq code: $sql = "SELECT id, title, category, icon_normal, status, description, views_monthly FROM posts WHERE views_monthly<=".$lastPost." AND status='1' ORDER BY views_monthly DESC LIMIT 9" So the problem that I am having is it shows the first 9 just fine. When it gets to the point where views_monthly = 0 then it just loads the same 9 post over again. How do it get it to switch to using ID when it reaches Views_monthly = 0 and load fresh posts?

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  • mysql count(*) left join group by - the number of files in a folder

    - by Flavius
    Hi I have the following tables CREATE TABLE `files` ( `fileid` int(11) NOT NULL AUTO_INCREMENT, `filename` varchar(255) NOT NULL, `filesize` int(11) NOT NULL, `folder` int(11) NOT NULL, PRIMARY KEY (`fileid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; CREATE TABLE `folders` ( `directoryid` int(11) NOT NULL AUTO_INCREMENT, `directoryname` varchar(255) NOT NULL, PRIMARY KEY (`directoryid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; How to get a list of all folders and the number of files they hold, including folders who have no (zero) files? Recursion must not be taken into account. Found it select folders.directoryid, folders.directoryname, count(files.fileid) as no_files from folders left join files on files.folder = folders.directoryid group by folders.directoryid, folders.directoryname I hope it will help someone.

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  • Odd PHP Error Message

    - by John
    When I run some php code I've written, I get the following message: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'condition, price, name, email) VALUES('Fake Title', 'Fake Subhead', 'Fake Author' at line 1 I do not see anything wrong with my syntax, however, which is like: mysql_query("INSERT INTO table (x1, x2, x3) VALUES('$y1', '$y2', '$y3')"); Any ideas?

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  • MySQL: Insert into multiple tables in same query with BEGIN&COMMIT

    - by strc
    I want to insert into multiple tables in same query by using BEGIN and COMMIT. It seems the error occur at begin. here is my SQL command BEGIN INSERT INTO Product (pName, pBrand, pCategory, pSize, pQuantity, pPrice, pDetail) VALUES('$name', '$brand', '$category', '$size', '$quantity', '$price', '$detail') INSERT INTO Image (iName, iExt, iSize, pID) VALUES('$img_name', '$img_ext', '$img_size', LAST_INSERT_ID()); COMMIT;

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  • MySQL, how to use returned data?

    - by aejo
    Well, I know there is a funciton mysql_fetch_array() and we can use it like this: while ($row = mysql_fetch_array($result)) { echo $row['name'] . "<br />"; } But is there any other way? For example, if there is only one element that can be returned, and not an array. Thanks)

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  • MySQL AND alternative for each table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • MySQL: List rows who have one but not another many-to-many relationship

    - by Svish
    Not quite sure how to ask or define this, but can't figure it out. I have three tables like this: persons person_id, first_name, last_name hobbies hobby_id, name persons_hobbies person_id, hobby_id I need to make two lists. Persons that have both hobby A and B, and persons that have hobby A but not B. How can I write these two queries? Can't figure out how to do this with joining and all...

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  • PHP MYSQL SIMPLE SEARCH ISSUE

    - by Kunal
    Hi I have a table with the following structure: id int(11), name varchar(250) I have lots of records in the table but when I am trying to find a particluar record which has the following value on the name field: Lorem ipsum d\'olor sit amet The query is simply returning a blank recordset. I am not being able to figure out this weird behaviour, when my query is as simple as follows: SELECT * FROM slot_games WHERE name='Lorem ipsum d\'olor sit amet' Would appreciate your help please! Thanks in advance.

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  • Getting id of row just inserted into MySQL database

    - by James P
    I have my table columns set like this: likes(id, like_message, timestamp) id is the primary key that is auto incrementing. This is the SQL that I use to add a row: $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; Everything works, but now I need to throw back the id attribute of the newly inserted row. For example, if I insert a row and the id of that row is 13, I need to echo out 13 so my AJAX request can pick that up and use it. Any help would be appreciated, as well as related code samples. Thanks :)

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • Creating an array from a MySQL table

    - by Rob
    I'm trying to create an array to use for a curl_multi_exec, but I can't seem to create the array properly. Here is my code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the shell table while($resultSet = mysql_fetch_array($SQL)){ $urls[]=$resultSet; } echo $urls; //Test that the array works But when I run this script, all it does is echo "Array" I have no idea what I'm doing wrong, I've checked around google a bit, but can't figure it out. Any insight would be appreciated.

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  • PHP & MySQL Problem

    - by Fincha
    I Have a script, getting text from DB and post it on other DB. Problem is, if I have a Text lngen then 840 Words, I can't call this page. Get an error about "Not Found" or "Connection brocken" or what ever. In FF i get no error, only blank page. I found out the Problem is in lenght of the query i send... but how can i fix it??? My it be the Problem, if a query is longer then 6000 Characters?

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  • How to search mulitple value seperated by commas in mysql

    - by Fero
    Hi all, How to search multiple values separated by commas. ex: table name : searchTest id name keyword 1 trophy1 test1,test2,test3 2 trophy2 test2,test5 Points: If i search for test2 both results trophy1 and trophy2 should be display. If i search for trophy1 then trophy1 should be as result. How to solve this issue. thanks in advance

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  • MySql Union not getting executed in a view

    - by aLL0i
    Hi, I am trying to create a view for a UNION of 2 select statements that I have created. The UNION is working fine when executed individually But the problem is only the 1st part of the UNION is getting executed when I am executing it as a view. The query I am using is as below SELECT DISTINCT products.pid AS id, products.pname AS name, products.p_desc AS description, products.p_loc AS location, products.p_uid AS userid, products.isaproduct AS whatisit FROM products UNION SELECT DISTINCT services.s_id AS id, services.s_name AS name, services.s_desc AS description, services.s_uid AS userid, services.s_location AS location, services.isaservice AS whatisit FROM services WHERE services.s_name The above works fine when i execute it separately. But when I use it as a view, it does not give me the results of the services part. Could someone please help me with this?

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  • Mysql SELECT and INSERT Error

    - by nepaliking
    I am using sort field in order to sort records. My code is this $query = "SELECT max(sort) FROM $this->table LIMIT 1;"; $result = mysql_query($query); $row = mysql_fetch_row($result); $sort = $row[0]+1; $query = "INSERT INTO "$this->table." VALUES ( '', '$ini', '$time', '$ip', '0', '$type', '$sort', '$title', '$image', '0' );"; $result = mysql_query($query) or die(mysql_error()); What is the error here?

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  • php: parse error on mysql query

    - by dwstein
    I'm getting the following error: Parse error: syntax error, unexpected T_VARIABLE in /home/a4999406/public_html/willingLog.html on line 48 on the following code (line 48 is first row of this code): $rows = mysql_num_rows($result); for ($j=0; $j<$rows: ++$j) { echo 'ID: ' . mysql_result($result, $j, 'id') . '<br />'; echo 'First: ' . mysql_result($result, $j, 'first') . '<br />'; echo 'Last: ' . mysql_result($result, $j, 'last') . '<br />'; echo 'Email: ' . mysql_result($result, $j, 'email') . '<br />'; } Anyone know what i'm doing wrong?

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  • selecting more than 1 table to get content from [php/Mysql]

    - by SAFSOF
    Hi There i want to get the latest threads/messages i made my code then i made function that calls the code to show last messages in specific board it works great now i want to get latest messages from 2 boards or more in the same function this is the part that chooses the board AND b.id_board = t.id_board' . (empty($vars) ? '' : ' AND b.id_board = ' . $vars . ''). ' i tried to use functionname(1.2.3); but he says no board with id 1.2.3 i tried ("1,2,3") same i wish i made it clear for you i apreciate your help

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  • MySQL database populated dropdown box and PHP search

    - by Sanel Bajric
    I have question regarding search on webpage with textbox and dropdown box. I have table with fields: ID First name Last name Company name Occupation Description Now i need to make search form which will be populated from database (field Occupation) and textbox where I can put whatever I want, and then get results from database based on those on web page. I am really sorry but i am totally begginer and only need some examples of such kind of code and much help :) Thank you

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  • Bulk Update in MYSQl

    - by user351806
    I have a site which has client side and admin side. There is a table called account History. which contains fields like uid | accountBalance | PaymentStatus | Date. Now this table has to be updated every month for all the paid users and the table is bulk. So what is the best way to update the table every month.Do i need to select all the uid's and update.

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  • MySQL, PHP, How Many in GROUP

    - by 0Neji
    I'm trying to create a table which outputs a list of users and how many times they've logged in. A new row in the table is created every time that someone logs in so there is multiple rows for one user. Now, I'm trying using the following statement to pull the data out: SELECT * FROM logins GROUP BY user ORDER BY timestamp DESC Which is working fine but now there is a column in my HTML table which should show how many times the user has logged in. How do I go about counting the amount of rows in each group?

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  • Installing PHP extensions on Linux

    - by EmmyS
    Please bear with me; I'm a developer, not a server admin. My company wants to explore using Magento. They've handed me a pre-configured Linux server with apache and PHP installed, but when I try to run the Magento setup, it tells me that there are PHP extensions that need to be loaded. I can edit the php.ini file, but have no idea where to get the extensions or how to install them, and there's no one here who knows, either. Can anyone give me a hand? I need the PDO_MySQL, mcrypt, and GD extensions. I've searched and found sites that talk about downloading from the terminal and compiling code, but it's all way over my head. Is there an easy way to do this?

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