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  • MySQL::Eliminating redundant elements from a table?

    - by Legend
    I have a table like this: +-------+---------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+---------+------+-----+---------+-------+ | v1 | int(11) | YES | MUL | NULL | | | v2 | int(11) | YES | MUL | NULL | | +-------+---------+------+-----+---------+-------+ There is a tremendous amount of duplication in this table. For instance, elements like the following: +------+------+ | v1 | v2 | +------+------+ | 1 | 2 | | 1 | 3 | | 1 | 4 | | 1 | 5 | | 1 | 6 | | 1 | 7 | | 1 | 8 | | 1 | 9 | | 2 | 1 | | 4 | 1 | | 5 | 1 | | 6 | 1 | | 7 | 1 | | 8 | 1 | | 9 | 1 | +------+------+ The table is large with 1540000 entries. To remove the redundant entries (i.e. to get a table having only (1,9) and no (9,1) entries), I was thinking of doing it with a subquery but is there a better way of doing this?

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  • MySQL update query, how to skip empty values?

    - by Pawel
    I've got such query: $sql = "UPDATE test_accs SET acc_owner = '$owner_id', acc_policy_version = '$version', acc_policy_last_update = '$approved', acc_policy_next_update = '$renewed' WHERE acc_id = '1'"; Now, all of these values on the web folmular are optional, one can set one of these values, two, or so. Now, after I submit the form, it goes in the query like that: UPDATE test_accs SET acc_owner = '2', acc_policy_version = '1.2', acc_policy_last_update = '2012-12-19', acc_policy_next_update = '2012-12-18' WHERE acc_id = '1' It works only when I submit all values from the form. Can you please show me how could it work even if not all the values has been sent, just for example one of them? When I set one value (f.ex. policy version), it looks like that: UPDATE test_accs SET acc_owner = '', acc_policy_version = '1.2', acc_policy_last_update = '', acc_policy_next_update = '' WHERE acc_id = '1' and it isn't working. It might be possible cause of the acc_owner table values? #1366 - Incorrect integer value: '' for column 'acc_owner' at row 1 Thanks in advice.

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  • MySQL: Records inserted by hour, for the last 24 hours

    - by Andrew M
    I'm trying to list the number of records per hour inserted into a database for the last 24 hours. Each row displays the records inserted that hour, as well as how many hours ago it was. Here's my query now: SELECT COUNT(*), FLOOR( TIME_TO_SEC( TIMEDIFF( NOW(), time)) / 3600 ) FROM `records` WHERE time > DATE_SUB(NOW(), INTERVAL 24 HOUR) GROUP BY HOUR(time) ORDER BY time ASC right now it returns: 28 23 62 23 14 20 1 4 28 3 19 1 That shows two rows from 23 hours ago, when it should only show one per hour. I think it has something to do with using NOW() instead of getting the time at the start of the hour, which I'm unsure on how to get. There must be a simpler way of doing this.

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  • MySQL - Add Values In Query And Return As Single Value

    - by Sjwdavies
    I'm trying to query a database, and return a set of values. Part of the data i'm trying to return is an insurance premium breakdown. Is it possible to run a query, that selects multiple fields, then adds then and returns them as a single value? I've seen SUM() but the examples i've seen show it as adding up the results of an entire field - where as i need it to add specific fields for each row returned. Any help is much appreciated.

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  • Associating multiple MySQL queries w/ PHP?

    - by anon
    I am trying to create a simple inventory request system. A user can enter multiple SKU's that will query the inventory database. My problem is I am trying to do is associate these multiple queries into a type of list. This list can later be retrieved and contains all queries that were submitted simultaneously. When the list is filled it can then be deleted. Is this possible? I am just looking to be pointed in the right direction. Thanks

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  • MySQL: Use CASE/ELSE value as join parameter

    - by DRJ
    I'm trying to join the NAME and PHOTO from USERS table to the TRANSACTIONS table based on who is the payer or payee. It keeps telling me can't find the table this -- What am I doing wrong? SELECT name,photo,amount,comment, ( CASE payer_id WHEN 72823 THEN payee_id ELSE payer_id END ) AS this FROM transactions RIGHT JOIN users ON (users.id=this) WHERE payee_id=72823 OR payer_id=72823

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  • mysql join 3 tables and count

    - by air
    Please look at this image here is 3 tables , and out i want is uid from table1 industry from table 3 of same uid count of fid from table 2 of same uid like in the sample example output will be 2 records Thanks

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  • criticle join query mysql

    - by Bharanikumar
    i have table country and having country name and country code, i have customer table having countomer mobile number like customer_mobile field values like 0044-123456798 , 0024-582654753 , 012-52686145 , i want to populate my country oce into combo, that country name should in customer table which country code count is high that country name should come in the dropdown list top , How to write the join query... Thanks

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  • How to display mysql records as preselected checkboxes?

    - by Jennifer
    I have a table column called post_tags within a table called posts where assigned tags are stored separated by the @ symbol. I also have a table called tags where all tag names are stored. I would like to design my database in a more normalized way but for the purpose I am trying to achieve this is the easiest option. Anyway, I want to display on the screen all the entries from the tags table as checkboxes, so I do: $query = mysql_query("SELECT * FROM tags ORDER BY name"); while ($row = mysql_fetch_assoc($query)) { $tag = $row['name']; echo "<input type='checkbox' name='tags[]' value='$tag' />\n"; } Next I want to have the tags that are assigned to a particular post be preselected. For example, if I have a post with the following in it's post_tags column: party@beaches@dolphins@ I want the "party", "beaches" and "dolphin" checkboxes to be checked by default (while the checkboxes for the other options are unchecked). How can this be done?

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  • MySQL Query Where Column Like Column

    - by shmeeps
    I'm working on a small project that involves grabbing a list of contacts which are stored for each group. Essentially, the database is set up so that each group has a primary and secondary contact stored as, unsurprisingly, Group.Primary and Group.Secondary. The objective is to pull every Primary and Secondary contact for each Group and display them in a sortable table. I have the sortable table all worked out, but I have come across a small problem. Each primary and secondary field can have more than one contact separated by a comma. For instance, if Primary contained 123,256 , it would need to pull both Contacts with IDs 123 and 256. I had intended to use a query formatted like this: SELECT * FROM Group G, Contacts C WHERE G.Primary LIKE %C.ID% OR G.Secondary LIKE %C.ID% so that I could just skip the comma part, but I can't seem to find a working query for this. My question to you is, am I just overlooking something here? Is there a simple query that would let me do this? Or am I better off getting the groups and contacts separately, and combine the two later. I think the former is a little easier to understand when read, which is a plus as this is a shared project, but if that is not possible I will do the latter. This code is simplified, but it gets the point across.

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  • Mysql - GROUP BY Avoid using tempoary

    - by jwzk
    The goal of this query is to get a total of unique records (by IP) per ref ID. SELECT COUNT(DISTINCT ip), GROUP_CONCAT(ref.id) FROM `sess` sess JOIN `ref` USING(row_id) WHERE sess.time BETWEEN '2010-04-21 00:00:00' AND '2010-04-21 23:59:59' GROUP BY ref.id ORDER BY sess.time DESC The query works fine, but its using a temporary table. Any ideas?

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  • MySQL Query - WHERE and IF?

    - by Prash
    I'm not quite sure how to right this query. Basically, I'm going to have a table with two columns (OS and country_code) - more columns too, but those are the conditional ones. These will be either set to 0 for all, or specific ones, separated by commas. Now, what I'm trying achieve is pull data from the table if the OS and country_code = 0, or if they contain matching data (separated by commas). Then, I have a column for time. I want to select rows where the time is GREATER than the time column, unless the column time_t is set to false, in which case this shouldn't matter. I hope I explained it right? This is what I kind of have so far: $get = $db->prepare("SELECT * FROM commands WHERE country_code = 0 OR country_code LIKE :country_code AND OS = 0 OR OS LIKE :OS AND IF (time_t = 1, expiry > NOW()) "); $get->execute(array( ':country_code' => "%{$data['country_code']}%", ':OS' => "%{$data['OS']}%" ));

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  • PHP - MySQL - Select runs indefinitely

    - by John
    I have three tables listings: id, pid, beds, baths, etc, etc, etc, db locations: id, pid, zip, lat, lon, etc, etc, etc, db images id, pid, height, width, raw, etc, etc, db id, pid & db are indexed. db just references the mls provider a particular item came from. in images the raw column holds raw image data there are about 15k rows in listings/locations, and about 120k rows in images so there are multiple rows that have the same pid. when i do "select pid from listings" or "select pid from locations" the query completes successfully in about 100ms. when i do "select pid from images" it just hangs in sqlyog and never completes... i was thinking since the raw column contains alot of information that it might be trying to select that too, but my query doesn't try to select that so I can't imagine why it's taking so long... any idea why this is happening??

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  • Quality questionnaire php mysql graphipcs

    - by Marcelo
    Hi, i'm making a questionnaire about a service quality, its contains the options (poor, regular, good, very good). It's contains 6 questions (radio button) and a suggestion box (textbox). In the table of the database i created 6 rows for questions, 1 for suggestion and 1 for date (a friend of mine tole me to use this but i didn't get why). q1) I'm going to atribute a value form 1 to 4 to the radio buttons options, and i'd like to sum every answer for each question, and then divide by the numbers of user that answered that question and give the mean. how am i supposed to to that? I'd also like generate reports of the month, of the year. q2) not only about the questionnaire but for registration too. I need all the fields to be completed, no blank options, if he don't complete all of fields it'll not be submitted and there will be a warning message to the user. q3) about the field type, i'd like it to be the same class that is in the database, i'm having a "problem". Ex: Name(varchar) : 1234(int), in the field 'name' of the table of the database 1234 will be shown as name, and i don't want this, i want only the type that i declared in the construction of the table. q4) i'd also like to know if it's possible to create pizza graphics, about the percentage of each question, is this possible? q5) I'm using phpmyadmin and some of my id's are auto_increment, but 'cause of my tests they at a high number, i'd like to restart to 0 the ids number, is this possible? Thanks for the attention.

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  • Consecutive absences in MySQL

    - by pepersview
    Hi, I have 2 tables in my db: students and absences. In students: id_student, s_name; and in absences: id_student, date, day(the day of the week as number-it's not so important); I would like to get the students that were absent for more than 2 days consecutive and the dates. At the moment I have the next query: /*To control when the days are in the same week*/ SELECT id_student, date, dayname(date),date_add(date, INTERVAL 1 DAY) AS a, dayname(date_add(date, INTERVAL 1 DAY)) AS an, date_add(date, INTERVAL 2 DAY) AS b, dayname(date_add(date, INTERVAL 2 DAY)) AS bn FROM absences AS a WHERE id_student IN (SELECT id_student FROM absences WHERE id_student = a.id_student AND date = date_add(a.date, INTERVAL 1 DAY) ) AND id_student IN (SELECT id_student FROM absences WHERE id_student = a.id_student AND date = date_add(a.date,INTERVAL 2 DAY) ) UNION /*To control when the days jump to the next week*/ SELECT id_student, date, dayname(date),date_add(date, INTERVAL 3 DAY) AS a, dayname(date_add(date, INTERVAL 3 DAY)) AS an, date_add(date, INTERVAL 4 DAY) AS b, dayname(date_add(date, INTERVAL 4 DAY)) AS bn FROM absences AS a WHERE id_student IN (SELECT id_student FROM absences WHERE id_student = a.id_student AND date = date_add(a.date, INTERVAL 3 DAY) ) AND id_student IN (SELECT id_student FROM absences WHERE id_student = a.id_student AND date = date_add(a.date,INTERVAL 4 DAY) ) /* To avoid the case (Monday-Thursday-Friday) to be consider as consecutive days*/ AND WEEKDAY(date) !=0 Thanks

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  • rake db:create not working for legacy rails app (2.3.5) using MySQL (5.5.28)

    - by ridicter
    I'm a new Rails Developer, and I'm working on a legacy Rails app. Whenever I run the rake db:create command, I get an error that the database couldn't be created. I have found many StackOverflow questions related to this, but in troubleshooting nearly all permutations of solutions, I couldn't resolve the issue. I created the three Dbs (dev, prod, test), created the user with all access privileges to these dbs, and ran rake db:create. I'm running Mac OS X Lion, MySQL 5.5.28, Rails 2.3.5, Ruby 1.8.7. Here are my settings development: adapter: mysql encoding: utf8 database: adva_development username: adva password: **** host: localhost socket: /tmp/mysql.sock Here's the error: Couldn't create database for {"adapter"=>"mysql", "username"=>"adva", "host"=>"localhost", "encoding"=>"utf8", "database"=>"adva_development", "socket"=>"/tmp/mysql.sock", "password"=>"****"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) I have done the following troubleshooting: Verified user and password are correct, and the user has access to the DB. (Double checked user access with SELECT * FROM mysql.db WHERE Db = 'adva_development' \G; User has all privileges.) Verify the socket is correct. I don't really understand sockets, but I can plainly see it at /tmp/mysql.sock. Checked collation and character set. I found out I had created the DB in latin charset and collation, so I recreated them. I ran show variables like "collation_database"; and show variables like "character_set_database"; and came back with utf8 and utf8_unicode_ci respectively. I followed the instructions in this question. After uninstalling mysql gem, I ran the following but came up with the same error: gem install --no-rdoc --no-ri mysql -- --with-mysql-dir=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin --with-mysql-config=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin/mysql_config Following Matt's suggestion, here's what a rake --trace db:create reveals: ** Invoke db:create (first_time) ** Invoke db:load_config (first_time) ** Invoke rails_env (first_time) ** Execute rails_env ** Execute db:load_config ** Execute db:create Couldn't create database for {"database"=>"adva_development", "adapter"=>"mysql", "host"=>"127.0.0.1", "password"=>"woof2adva", "username"=>"adva", "encoding"=>"utf8"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) After 3 days and six or seven hours, I have pretty much run out of options. I tried various random things, like replacing localhost with 127.0.0.1 to no avail. Could there be something wrong related to my specific environment? Mac OS X Lion + MySQL 5.5.28? I plan on trying on setting up everything in a Linux environment. Thanks!

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  • MySQL Query, Date Range From "Blacklist"

    - by erbaker
    I have 2 databases. One is properties and the other is dates. In dates I have associated the land_id and a date (In YYYYMMDD format) which means that the date is not available. I need to formulate a query that a user can specify a start and end date, and then choose a property for which dates are available (not in the date database). How do airline and hotel websites do this kind of logic? I was thinking about taking the date range and picking all days in between and doing a query where the dates do not match and ordering it by number of results, but I can see how that could easily turn into an intense query. CREATE TABLE IF NOT EXISTS `dates` ( `id` int(11) NOT NULL AUTO_INCREMENT, `land_id` int(11) NOT NULL, `date` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=44 ; -- -- Dumping data for table `dates` -- INSERT INTO `dates` (`id`, `land_id`, `date`) VALUES (43, 1, '20100526'), (39, 1, '20100522'), (40, 1, '20100523'), (41, 1, '20100521'), (42, 1, '20100525');

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  • Input html tag not parsing properly in php

    - by Akaash
    I have a database with names that I would like displayed in the form of a table with checkboxes. Everything works until I try to place the html tag into my php code. When I put the input tag in it gives me the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' I can't see where I would put a comma or semi colon. <form> <?php $name = $_POST['name']; $host = "mysql16.000webhost.com"; $user_name = "a1611480_akaash"; $pwd = "****"; $database_name = "a1611480_akaash"; $db = mysql_connect($host, $user_name, $pwd); mysql_select_db($database_name); $result = mysql_query("SELECT name FROM Sort"); $var = array(); while ($row = mysql_fetch_array($result)) { $var[] = $row['name']; } $unique = array_unique($var); foreach ($unique as $value) { echo "<p class = Body_text><label>$value</label> <input type="checkbox" name="name" value="$value" /> </p>\n"; } ?> </form>

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  • MySQL "NULL" questions

    - by Camran
    I have a table with several columns. Sometimes some of these column fields may be empty (ie. I won't use them in some cases). My questions: Would it be smart to set them to NULL in phpmyadmin? What does the "NULL" property actually do? Would I gain anything at all by setting them to NULL? Is it possible to use a NULL field the same way even though it is set to null?

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