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  • can I get .class from generic type argument?

    - by Mike S
    I have the following class: public abstract class MyClass<T extends Object> { protected T createNewFromData(Reader reader){ GSON.fromJSON(reader,T.class); // T.class isn't allowed :( } } How do I pass a Class<T instance into there? Is there some wierd and wacky work around? Is there a way to get a Class<T reference other than from a pre-instantiated Object of type T? It won't let me do this either: T t = new T(); Class<T> klass = t.class; ANSWER BELOW Thanks to the accepted answer, here is the solution: Type type = new TypeToken<T>(){}.getType(); return gson.fromJson(reader, type);

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  • Format String become xxx1, xx10 or 1****, 10*** etc

    - by trycatch4j
    Hi all, I have following numbers : 1, 2, 3, 4, 10 But I want to print those numbers like this: 0001 0002 0003 0004 0010 I have searched in Google. the keyword is number format. But I've got nothing, I just get, format decimal such ass 1,000,000.00. I hope you can suggest me a reference or give me something to solve this problem. Thanks Edit, we can use NumberFormat, or String.format("%4d", somevalue); but it just for adding 0 character before integer. How If I wanna use character such as x, # or maybe whitespace. So the character become: xxxx1 xxx10 or ####1 ###10 or 1#### 10###

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  • Criteria: search for two different entity classes...

    - by RoCMe
    Hi! I have a "super entity" SuperEntity and three entities ChildEntity1, ..., ChildEntity3 which extends the super class. It's easy to search for all entities in the database, i.e. we could use session.createCriteria(SuperEntity.class); It's no problem to search for one specific entity type, too, just replace the SuperEntity with any of the children to look for entities of that type. But I have a problem when allowing 'multiple choice' for the types. I.e., it could be neccessary to search all entities of type 1 and 2, but not of type 3. A first idea was to create two independent queries and join the results in a final list - but that would destroy the paging which uses offset and limit functionality of the database... Is there a possibility in Criteria to join two different queries in one single result list? Kind regards, RoCMe

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  • MediaType of REST

    - by user357243
    Hi, I am beginner in REST web services. I wrote a program of REST to display the HTML or XML. The @Path annotation's value is @Path("{typeDocument}"). There are two methods for GET : @GET @Produces(MediaType.TEXT_XML) public String getXml(@PathParam("typeDocument") String typeDocument) to display XML file, and @GET @Produces(MediaType.TEXT_HTML) public String getHtml(@PathParam("typeDocument") String typeDocument) to display HTML. The browser Firefox always excutes getHtml() when URL is either http://localhost:8080/sources/html or localhost:8080/sources/xml But IE always excutes getXml(). How to excute the correct method, as defined by URL, in different browser ? Thanks a lot.

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  • hashmap and list compare

    - by sarah
    Hi, I have a hashmap having four values a,b,c,d and list having only a i want to see if the hashmap has the value a and print it. hashmap.get('data') results a,b,c,d list l is having a how will i print only the value a

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  • the variable only have it value inside while loop?

    - by user1834467
    static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); **System.out.println(h);** } } static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); } **System.out.println(h);** } when I try the second part of the code, it print out nothing. how can I get the whole h String outside of the while loop? Is it I have to declare the variable h as instance variable instead of local variable?

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  • which delimeter to use while spliting String

    - by London
    I need to split this line string in each line, I need to get the third word(film name) but as you see the delimeter is one big blank character in some cases its small like before the numbers at the end or its big as in front of numbers at front. I tried using string split with(" ") regex, and also \t but get the out of the bounds error. 400115305 Lionel_Atwill The_Song_of_Songs_(1933_film) 7587 400115309 Brian_Aherne A_Night_to_Remember_(1943_film) 7952 Did anyone have the same problem?

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  • Is this possible?

    - by Stud33
    I want to incorporate some Accelerometer code into a Android application im working and want to see if this is possible. Basically what I need is for the code to detect car acceleration motion. I am not wanting to determine speed with the code but just distinguish if the phone is in a car and has accelerated motion (Hence the car is moving for the first time). I have gone through many different accelerometer applications to see if this motion produces a viable profile to go off of and it appears it does. Just looking for something that popups a "Hello World" dialog when it detects your in the car and its moving for the first time down the street. Any help would be appreciated and a simple yes or no its possible would work. I would also be interested in compensating anyone that is capable of doing this as well. I need this done like yesterday so please let me know. Thank You, JTW

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  • Hibernate and mssql inner join rowcount

    - by ez2sarang
    I am struggling with Hibernate Criteria. My aim is to create the following request using Hibernate Criteria : select count(*) as y0_ from PInterface this_ inner join Product product2_ on this_.product_id=product2_.id where this_.product_interface_type_id=? Here is my code: @Entity @Table(name = "PInterface") public class PInterface { @Id @GeneratedValue @Column(name = "id", nullable = false, insertable = false, updatable = false) private int id; @Column(name = "product_id") private int productId; @Column(name = "product_interface_type_id") private int type; @ManyToOne(optional=false) @JoinColumn(name = "product_id", referencedColumnName = "id", insertable=false, updatable=false) private Product product; } @Entity @Table(name = "Product") public class Product { @Id @GeneratedValue @Column(name = "id", nullable = false, insertable = false, updatable = false) private int id; private String name; } //Criteria is : Object criteria = sessionFactory.getCurrentSession() .createCriteria(PInterface.class) .add(Restrictions.eq("type", 1)) .setProjection(Projections.rowCount()) .uniqueResult() ; However, the results ... select count(*) as y0_ from PInterface this_ where this_.product_interface_type_id=? Where Inner join? Thank you for help!

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  • help with google android

    - by hero
    how powerfull is google android bluetooth programming? is it considered a low level programming langauge/emulator that enables me to have full control over bluetooth? ie protocols,encryption,layers....

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  • Non-empty list with null elements returned from Hibernate query

    - by John
    Hi, I'm new to hibernate so not sure if this is an expected behaviour, anyway: Session session = (Session)entityManager.getDelegate(); Criteria criteria = session.createCriteria(myRequest.class); criteria.add(Restrictions.eq("username", username)); criteria.setProjection(Projections.max("accesscount")); List<myRequest> results = criteria.list(); The returned results is a non-empty list with a single null element. I can't think of any reason why it should behave this way, any idea if this is the expected behaviour or have I done something wrong? System is on hibernate/Syabse. Thanks.

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  • @Path and regular expression (Jersey/REST)

    - by Castanho
    Hi there! I'm using Jersey in a REST project and I'm needing to use regular expression. Digging about it is simple like: @Path("/resources) public class MyResource { @GET @Path("{subResources:.*}/bar") public String get() {...} } But, I'm only capable of using regex if in my @Path contains a variable or text value, example: @Path("{SubResource1}/{subResources:.*}/bar") Or @Path("hardCodeString/{subResources:.*}/bar") Today I could run with this solution of a variable, but is not oK for my perspective. Question Does anyone have worked with something related? I'm doing something wrong? I think that this could be a bug, when working with more then one @Path, one in the Class and other in the Method. Any tips is appreciated! Regards

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  • Quickest and most efficient method to search top 3 numbers?

    - by Donal Rafferty
    I currently have an array of around 8 - 10 numbers that changes on a periodic basis. So around every 5 - 10 seconds the numbers get updated. I need to get the top 3 numbers in the array every 10 seconds. This is all done on a mobile device. At the minute I iterate through the array 3 times and each time I take out the three highest numbers and place them in three previously declared variables. My question is what should I look to do to increase speed and efficiency in this instance?

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  • How the clients (client sockets) are identified?

    - by Roman
    To my understanding by serverSocket = new ServerSocket(portNumber) we create an object which potentially can "listen" to the indicated port. By clientSocket = serverSocket.accept() we force the server socket to "listen" to its port and to "accept" a connection from any client which tries to connect to the server through the port associated with the server. When I say "client tries to connect to the server" I mean that client program executes "nameSocket = new Socket(serverIP,serverPort)". If client is trying to connect to the server, the server "accepts" this client (i.e. creates a "client socket" associated with this client). If a new client tries to connect to the server, the server creates another client socket (associated with the new client). But how the server knows if it is a "new" client or an "old" one which has already its socket? Or, in other words, how the clients are identified? By their IP? By their IP and port? By some "signatures"? What happens if an "old" client tries to use Socket(serverIP,serverIP) again? Will server create the second socket associated with this client?

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