Search Results

Search found 5007 results on 201 pages for 'django inheritance'.

Page 106/201 | < Previous Page | 102 103 104 105 106 107 108 109 110 111 112 113  | Next Page >

  • Fixtures and inheritance in Symfony

    - by Tere
    Hi! I have a database schema in Symfony like this: Persona: actAs: { Timestampable: ~ } columns: primer_nombre: { type: string(255), notnull: true } segundo_nombre: { type: string(255) } apellido: { type: string(255), notnull: true } rut: { type: string(255) } email: { type: string(255) } email2: { type: string(255) } direccion: { type: string(400) } ciudad: { type: string(255) } region: { type: string(255) } pais: { type: string(255) } telefono: { type: string(255) } telefono2: { type: string(255) } fecha_nacimiento: { type: date } Alumno: inheritance: type: concrete extends: Persona columns: comentario: { type: string(255) } estado_pago: { type: string(255) } Alumno_Beca: columns: persona_id: { type: integer, primary: true } beca_id: { type: integer, primary: true } relations: Alumno: { onDelete: CASCADE, local: persona_id, foreign: id } Beca: { onDelete: CASCADE, local: beca_id, foreign: id } Beca: columns: nombre: { type: string(255) } monto: { type: double } porcentaje: { type: double } descripcion: { type: string(5000) } As you see, "alumno" has a concrete inheritance from "persona". Now I'm trying to create fixtures for this two tables, and I can't make Doctrine to load them. It gives me this error: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (eat/alumno__beca, CONSTRAINT alumno__beca_persona_id_alumno_id FOREIGN KEY (persona_id) REFERENCES alumno (id) ON DELETE CASCADE) Does someone know how to write a fixture for a table inherited from another? Thanks!

    Read the article

  • GetProperties() to return all properties for an interface inheritance hierarchy

    - by sduplooy
    Assuming the following hypothetical inheritance hierarchy: public interface IA { int ID { get; set; } } public interface IB : IA { string Name { get; set; } } Using reflection and making the following call: typeof(IB).GetProperties(BindingFlags.Public | BindingFlags.Instance) will only yield the properties of interface IB, which is "Name". If we were to do a similar test on the following code, public abstract class A { public int ID { get; set; } } public class B : A { public string Name { get; set; } } the call typeof(B).GetProperties(BindingFlags.Public | BindingFlags.Instance) will return an array of PropertyInfo objects for "ID" and "Name". Is there an easy way to find all the properties in the inheritance hierarchy for interfaces as in the first example?

    Read the article

  • JavaScript inheritance

    - by Tower
    Hi, Douglas Crockford seems to like the following inheritance approach: if (typeof Object.create !== 'function') { Object.create = function (o) { function F() {} F.prototype = o; return new F(); }; } newObject = Object.create(oldObject); It looks OK to me, but how does it differ from John Resig's simple inheritance approach? Basically it goes down to newObject = Object.create(oldObject); versus newObject = Object.extend(); And I am interested in theories. Implementation wise there does not seem to be much difference.

    Read the article

  • Dynamic dispatch and inheritance in python

    - by Bill Zimmerman
    Hi, I'm trying to modify Guido's multimethod (dynamic dispatch code): http://www.artima.com/weblogs/viewpost.jsp?thread=101605 to handle inheritance and possibly out of order arguments. e.g. (inheritance problem) class A(object): pass class B(A): pass @multimethod(A,A) def foo(arg1,arg2): print 'works' foo(A(),A()) #works foo(A(),B()) #fails Is there a better way than iteratively checking for the super() of each item until one is found? e.g. (argument ordering problem) I was thinking of this from a collision detection standpoint. e.g. foo(Car(),Truck()) and foo(Truck(), Car()) and should both trigger foo(Car,Truck) # Note: @multimethod(Truck,Car) will throw an exception if @multimethod(Car,Truck) was registered first? I'm looking specifically for an 'elegant' solution. I know that I could just brute force my way through all the possibilities, but I'm trying to avoid that. I just wanted to get some input/ideas before sitting down and pounding out a solution. Thanks

    Read the article

  • How to specify a different column for a @Inheritance JPA annotation

    - by Cue
    @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Foo @Entity @Inheritance(strategy = InheritanceType.JOINED) public class BarFoo extends Foo mysql> desc foo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ mysql> desc barfoo; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | | foo_id | int | | bar_id | int | +---------------+-------------+ mysql> desc bar; +---------------+-------------+ | Field | Type | +---------------+-------------+ | id | int | +---------------+-------------+ Is it possible to specify column barfo.foo_id as the joined column? Are you allowed to specify barfoo.id as BarFoo's @Id since you are overriding the getter/seeter of class Foo? I understand the schematics behind this relationship (or at least I think I do) and I'm ok with them. The reason I want an explicit id field for BarFoo is exactly because I want to avoid using a joined key (foo _id, bar _id) when querying for BarFoo(s) or when used in a "stronger" constraint. (as Ruben put it)

    Read the article

  • Unexplained Django error. Diagnosis anyone?

    - by colorfulgrayscale
    I have a django project I keep on github. It worked perfectly fine on my laptop. I downloaded it on my desktop and tried to "python manage.py runserver" or even "python manage.py shell" I get a Error: No module named messages No other messages, no stack trace, nothing..Anyone have any idea whats going on? Thanks.

    Read the article

  • Why is mod_wsgi not able to write data? IOError: failed to write data

    - by BryanWheelock
    What could be causing this error: $ sudo tail -n 100 /var/log/apache2/error.log' [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] mod_wsgi (pid=20343): Exception occurred processing WSGI script '/home/username/public_html/idm.wsgi'. [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] IOError: failed to write data Here is the WSGI script: $ cat public_html/idm.wsgi import os import sys sys.path.append('/home/username/public_html/IDM_app/') os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Why would Django not be able to write data? I'm running Django 1.2.4

    Read the article

  • running python script with cron

    - by paulo
    hey guys, im trying to run a python script after every 5 minutes using cron, inside the script is a django import import django when running the crontab i get mailed the following error ImportError: No module named django this is what the crontab file looks like: [email protected] */5 * * * * /usr/bin/python /Users/paulo/Desktop/ashtanga/ping/sender.py do anyone of you know whats causing this ? btw i do have django insalled version 1.2, python 2.6, and MacOX 10.6

    Read the article

  • why my code error,about serve the static file using django..

    - by zjm1126
    my settings.py: DIRNAME = os.path.dirname(__file__) STATIC_DOC_ROOT = os.path.join(DIRNAME, 'media') MEDIA_URL = '/media/' my urls.py: def google(request): return render_to_response('a.html',context_instance=RequestContext(request)) urlpatterns = patterns('', (r'^$',google), (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root':settings.STATIC_DOC_ROOT,'show_indexes': True}), ) and my a.html is: <script type="text/javascript" src="/media/jquery-1.4.2.js"></script> <script type="text/javascript"> alert($) </script> but,it can't defiend the '$' why ? thanks

    Read the article

  • Django-imagekit: how to reduce image quality with a preprocessor_spec ?

    - by pierre-guillaume-degans
    Hi, please excuse me for my ugly english :p I've created this simple model class, with a Preprocessor to reduce my photos'quality (the photos'extension is .JPG): from django.db import models from imagekit.models import ImageModel from imagekit.specs import ImageSpec from imagekit import processors class Preprocessor(ImageSpec): quality = 50 processors = [processors.Format] class Picture(ImageModel): image = models.ImageField(upload_to='pictures') class IKOptions: preprocessor_spec = Preprocessor The problem : pictures'quality are not reduced. :( Any idea to fix it ? Thank you very much ;)

    Read the article

  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

    Read the article

  • What should a Django user know when moving from MySQL to PostgreSQL?

    - by tmitchell
    Most of my experience with Django thus far has been with MySQL and mysqldb. For a new app I'm writing, I'm dipping my toe in the PostgreSQL water, now that I have seen the light. While writing a data import script, I stumbled upon an issue with the default autocommit behavior. I would guess there are other "gotchas" that might crop up. What else should I be on the lookout for?

    Read the article

  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

    Read the article

  • How to update the filename of a Django's FileField instance ?

    - by pierre-guillaume-degans
    Hello, Here a simple django model: class SomeModel(models.Model): title = models.CharField(max_length=100) video = models.FileField(upload_to='video') I would like to save any instance so that the video's file name would be a valid file name of the title. For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi"). Thank you :)

    Read the article

  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

    Read the article

< Previous Page | 102 103 104 105 106 107 108 109 110 111 112 113  | Next Page >