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  • How to get number of delete using NHibernate IStatistics

    - by epitka
    I am trying to get the number of delete statements issued during the session, so I enabled statistics generation and I got a reference to it through SessionFactory.Statistics. But I don't see a way to get the global number of deletes. I can get the statistics for the entity, but I have one many-to-many mapped relationship that does not materialize in an entity, everything is done through a table that is not mapped to an entity. Is there a way to get this number?

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  • Building a structure/object in a place other than the constructor

    - by Vishal Naidu
    I have different types of objects representing the same business entity. UIObject, PowershellObject, DevCodeModelObject, WMIObject all are different representation to the same entity. So say if the entity is Animal then I have AnimalUIObject, AnimalPSObject, AnimalModelObject, AnimalWMIObject, etc. Now the implementations of AnimalUIObject, AnimalPSObject, AnimalModelObject are all in separate assemblies. Now my scenario is I want to verify the contents of business entity Animal irrespective of the assembly it came from. So I created a GenericAnimal class to represent the Animal entity. Now in GenericAnimal I added the following constructors: GenericAnimal(AnimalUIObject) GenericAnimal(AnimalPSObject) GenericAnimal(AnimalModelObject) Basically I made GenericAnimal depend on all the underlying assemblies so that while verifying I deal with this abstraction. Now the other approach to do this is have GenericAnimal with an empty constructor an allow these underlying assemblies to have a Transform() method which would build the GenericAnimal. Both approaches have some pros and cons: The 1st approach: Pros: All construction logic is in one place in one class GenericAnimal Cons: GenericAnimal class must be touched every-time there is a new representation form. The 2nd approach: Pros: construction responsibility is delegated to the underlying assembly. Cons: As construction logic is spread accross assemblies, tomorrow if I need to add a property X in GenericAnimal then I have to touch all the assemblies to change the Transform method. Which approach looks better ? or Which would you consider a lesser evil ? Is there any alternative way better than the above two ?

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  • Solr - DeltaImport doenst run the parentDeltaQuery

    - by rails
    I have 1:n relation between my main entity(PackageVersion) and its tag in my DB. I add a new tag with this date to the db at the timestamp and I run delta import command. the select retrieves the line but i dont see any other sql. Here are my data-config.xml configurations: <entity name="PackageVersion" pk="PackageVersionId" query= "select ... from [dbo].[Package] Package inner join [dbo].[PackageVersion] PackageVersion on Package.Id = PackageVersion.PackageId" deltaQuery = "select PackageVersion.Id PackageVersionId from [dbo].[Package] Package inner join [dbo].[PackageVersion] PackageVersion on Package.Id = PackageVersion.PackageId where Package.LastModificationTime > '${dataimporter.last_index_time}' OR PackageVersion.Timestamp > '${dataimporter.last_index_time}'" deltaImportQuery="select ... from [dbo].[Package] Package inner join [dbo].[PackageVersion] PackageVersion on Package.Id = PackageVersion.PackageId Where PackageVersionId=='${dih.delta.id}'" > <entity name="PackageTag" pk="ResourceId" processor="CachedSqlEntityProcessor" cacheKey="ResourceId" cacheLookup="PackageVersion.PackageId" query= "SELECT ResourceId,[Text] PackageTag from [dbo].[Tag] Tag" deltaQuery="SELECT ResourceId,[Text] PackageTag from [dbo].[Tag] Tag Where Tag.TimeStamp > '${dataimporter.last_index_time}'" parentDeltaQuery="select PackageVersion.PackageVersionId from [dbo].[Package] where Package.Id=${PackageTag.ResourceId}"> </entity> </entity>

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  • Force update in Hibernate

    - by gubrutz
    How can I force Hibernate to update an entity instance even if the entity is not dirty? I'm using Hibernate 3.3.2 GA, Hibernate Annotations and Hibernate EntityManager btw. I really want Hibernate to execute the generic UPDATE statement even if no property on the entity has changed. I need this because some event listeners need to get invoked to do some additional work when the application runs for the first time. Thanks!

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  • What to do with lookup entities selected from drop down select ? How to send them to the service lay

    - by arrages
    I am developing a spring mvc based application. I have a simple pojo form object, the problem is that many properties will be taked from drop down lists that are populated from lookup entities, so I return the entity ID to the form object. public NewCarRequestForm { private makeId; // this are selected from a drop down. private modelId; } Should I just send this lookup entity ID to the service layer? or should I validated that this ID is correct (Somebody can send any random ID through the request) before and how? Now there is a problem if I want to validated something based on some property of the lookup entity. Do I perform a database lookup of the entity just to perform the validation? thanks.

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  • Doctrine: Mixing YAML markup and db manager (navicat) editing?

    - by ropstah
    I think the answer to this question should be: No. However I hope to be corrected. I'd like to edit our database using a mixture of YAML markup + Doctrine createTables() and Navicat editing. Can I maintain the inheritance which is marked up? Example (4 steps, at step 4, Doctrine is in no way able to re-create the inheritance schema... or is it?): Step 1: Create YAML with inheritance --- Entity: columns: username: string(20) password: string(16) created_at: timestamp updated_at: timestamp User: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 1 Group: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 2 Step 2: Create tables using Doctrine (and drop/create db if nessecary) Created sql: CREATE TABLE entity (id BIGINT AUTO_INCREMENT, username VARCHAR(20), password VARCHAR(16), created_at DATETIME, updated_at DATETIME, type VARCHAR(255), PRIMARY KEY(id)) ENGINE = INNODB Step 3: Edit table using Navicat Step 4: Refresh YAML file because of 'external' edits...

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  • STI and accepts_nested_attributes_for in rails

    - by ryanshackintosh
    I have models as follows: class Entity < ActiveRecord::Base has_many :addresses accepts_nested_attributes_for :addresses, :reject_if => lambda { |a| a[:label].blank?} , :allow_destroy => true end class Client < Entity before_save :set_type private def set_type self.type = "Client" end end class Address < ActiveRecord::Base belongs_to :entity end I have recently implemented accepts_nested_attributes_for on the /clients/new form, as follows: <% form_for(@client, :html => {:class => 'form'}) do |f| -%> <%= f.label :name %> <%= f.text_field :name -%> <%= f.label :phone %> <%= f.text_field :phone %> <% f.fields_for :addresses do |a| %> <%= a.label :street %> <%= a.text_field :street%> <%= a.label :city %> <%= a.text_field :city %> <% end %> <% end %> And my controller as follows: class ClientsController < ApplicationController before_filter :load_client , :except => [:index, :new, :create, :render_clients] def new @client = Client.new @client.addresses.build end def create @client = Client.new(params[:client]) if @client.save flash[:notice] = 'Client has been successfully added' redirect_to @client else render :action => 'new' end end The issue is that when the record is saved it gives an error stating: "Entity can't be blank" I assume it is something to do with the fact that a 'Client' and not an 'Entity' is being added. Can anyone point me in the right direction?

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  • Project Naming Convention Feedback Please

    - by Sam Striano
    I am creating a ASP.NET MVC 3 application using Entity Framework 4. I am using the Repository/Service Pattern and was looking for feedback. I currently have the following: MVC Application (GTG.dll) GTG GTG.Controllers GTG.ViewModels Business POCO's (GTG.Business.dll) This contains all business objects (Customer, Order, Invoice, etc...) EF Model/Repositories (GTG.Data.dll) GTG.Business (GTG.Context.tt) I used the Entity POCO Generator Templates. GTG.Data.Repositories Service Layer (GTG.Data.Services.dll) GTG.Data.Services - Contains all of the service objects, one per aggregate root. The following is a little sample code: Controller Namespace Controllers Public Class HomeController Inherits System.Web.Mvc.Controller Function Index() As ActionResult Return View(New Models.HomeViewModel) End Function End Class End Namespace Model Namespace Models Public Class HomeViewModel Private _Service As CustomerService Public Property Customers As List(Of Customer) Public Sub New() _Service = New CustomerService _Customers = _Service.GetCustomersByBusinessName("Striano") End Sub End Class End Namespace Service Public Class CustomerService Private _Repository As ICustomerRepository Public Sub New() _Repository = New CustomerRepository End Sub Function GetCustomerByID(ByVal ID As Integer) As Customer Return _Repository.GetByID(ID) End Function Function GetCustomersByBusinessName(ByVal Name As String) As List(Of Customer) Return _Repository.Query(Function(x) x.CompanyName.StartsWith(Name)).ToList End Function End Class Repository Namespace Data.Repositories Public Class CustomerRepository Implements ICustomerRepository Public Sub Add(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Add End Sub Public Sub Delete(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Delete End Sub Public Function GetByID(ByVal ID As Integer) As Business.Customer Implements IRepository(Of Business.Customer).GetByID Using db As New GTGContainer Return db.Customers.FirstOrDefault(Function(x) x.ID = ID) End Using End Function Public Function Query(ByVal Predicate As System.Linq.Expressions.Expression(Of System.Func(Of Business.Customer, Boolean))) As System.Linq.IQueryable(Of Business.Customer) Implements IRepository(Of Business.Customer).Query Using db As New GTGContainer Return db.Customers.Where(Predicate) End Using End Function Public Sub Save(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Save End Sub End Class End Namespace

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  • Symfony2 same form, different entities NOT related

    - by user1381537
    I'm trying to write one form for submitting against MySQL DB, but I can't get it working, I've tried a lot of things (separate forms, create an ->add('foo', new foo()) to a field, and trying to parse plain SQL with a normal HTML form is my only solution, which is obviously not the best. This is my DB structure: As you can see I need to insert the comments textarea to ticketcomments among the user who wrote it, etc. On crmentity the description field. Then on ticketcf the fields that I need to submit from form, are this (because you wont know if I don't tell you because of the field names): tcf.cf594 AS Type, tcf.cf675 AS Suscription, tcf.cf770 AS ID_PRODUCT, tcf.cf746 AS NotificationDate, tcf.cf747 AS ResponseDate, tcf.cf748 AS ResolutionDate, And, of course, every table needs to have the same ticketid id for the submitted form, so we can retrieve it with one simple query. It will be easy to do with plain SQL instead of using DQL and Symfony2 forms, but is not a good way to do it. Also, here's my "Ticket list" query, if you need it to have it more clear... SELECT t.ticketNo AS Ticket, t.title AS Asunto, t.status AS Estado, t.updateLog AS LOG, t.hours AS Horas, t.solution AS Solucion, t.priority AS Prioridad, tcf.cf594 AS Tipo, tcf.cf675 AS Suscripcion, tcf.cf770 AS IDPROD, tcf.cf746 AS F_Noti, tcf.cf747 AS F_Resp, tcf.cf748 AS F_Reso, CONCAT (cd.firstname, cd.lastname) AS Contacto, crm.description AS Descripcion, crm.crmid AS id FROM WbsGoclientsBundle:VtigerTroubletickets t INNER JOIN WbsGoclientsBundle:VtigerTicketcf tcf WITH t.ticketid = tcf.ticketid INNER JOIN WbsGoclientsBundle:VtigerContactdetails cd WITH t.parentId = cd.contactid INNER JOIN WbsGoclientsBundle:VtigerCrmentity crm WITH t.ticketid = crm.crmid WHERE t.parentId IN ( SELECT cd1.contactid FROM WbsGoclientsBundle:VtigerContactdetails cd1 WHERE cd1.accountid = ( SELECT cd2.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd2 WHERE cd2.contactid = :contactid)) AND t.status <> \'Closed\' And also "Ticket details" query (which is not in DQL format yet, only SQL) is so simple, it only retrieve the comments field and createdtime from ticketcomments appended to this query so we have all the fields... Thank you. This is a test form, using troubletickets and ticketcomments, it's returning errores because I can't set a comments field because troubletickets doesn't has it, but I need that field to be submitted to ticketcomments ... VtigerTicketcommentsType <?php namespace WbsGo\clientsBundle\Form\Type; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class VtigerTicketcommentsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('ticketid') ->add('comments') ->add('ownerid') ->add('ownertype') ->add('createdtype') ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTicketcomments' )); } public function getName() { return 'comments'; } } OpenTicketType.php <?php namespace WbsGo\clientsBundle\Form; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface ; use WbsGo\clientsBundle\Form\Type\VtigerTicketcommentsType; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class OpenTicketType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('title') ->add('priority') ->add('solution') ->add('comments', 'collection', array( 'type' => new VtigerTicketcommentsType() )) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTroubletickets' )); } public function getName() { return 'ticket'; } } TicketController.php <?php namespace WbsGo\clientsBundle\Controller; use Symfony\Bundle\FrameworkBundle\Controller\Controller; use WbsGo\clientsBundle\Entity\VtigerTroubletickets; use WbsGo\clientsBundle\Entity\VtigerTicketcomments; use WbsGo\clientsBundle\Form\OpenTicketType; use Symfony\Component\HttpFoundation\Request; class TicketController extends Controller { public function indexAction() { $em = $this->getDoctrine()->getManager(); $tickets = $em ->getRepository('WbsGoclientsBundle:VtigerTroubletickets') ->findAllOpenByCustomerId($this->getUser()->getId()); $userdata = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerContactdetails') ->findContact($this->getUser()->getId()); return $this ->render('WbsGoclientsBundle:Ticket:index.html.twig', array('tickets' => $tickets, 'userdata' => $userdata)); } public function addAction() { $assets = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerAssets') ->findAssetByAccountId($this->getUser()->getId()); $assetlist = array(); foreach ($assets as $key => $v) { $assetlist[$key] = $key; } $form = $this->createForm(new OpenTicketType(), new VtigerTroubletickets()); return $this ->render('WbsGoclientsBundle:Ticket:add.html.twig', array('form' => $form->createView(), 'assets' => $assets,)); } } This is the error Symfony2 is returning Neither the property "comments" nor one of the methods "getComments()", "isComments()", "hasComments()", "_get()" or "_call()" exist and have public access in class "WbsGo\clientsBundle\Entity\VtigerTroubletickets". EDIT 2 This code is actually rendering my forms, but I need help in order to submit each XXXType form to its corresponding table. public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('descripcion') ->add('prioridad') ->add('solucion') ->add('comment', new VtigerTicketcommentsType() ) ->add('contacto') ->add('suscripcion') ->add('producto', 'entity', array( 'class' => 'WbsGo\clientsBundle\Entity\VtigerAssets', 'property' => 'assetname', 'empty_value' => '--SELECT--', 'query_builder' => function(\WbsGo\clientsBundle\Entity\VtigerAssetsRepository $repository) { //return $repository->findAssetByAccountId($this->customerId); return $repository->createQueryBuilder('a') ->select('a') ->where('a.account = (SELECT cd.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd WHERE cd.contactid = ?1)') ->setParameter(1, $this->customerId); } ) ) ->add('hardware') ->add('backup') ->add('web') ->add('restore') ->add('customerId') ; } I also removed ->add('ticketid') from VtigerTicketcommentsType.php because it has relationship and is not needed. it's auto_incremental and must be generated once everything is submitted.

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  • Question on jpa joined table inheritance

    - by soontobeared
    Hi, The 'DiscriminatorColumn' annotation isn't creating any column in my parent entity. Where am I going wrong ? Here's my code @Entity @Inheritance(strategy=InheritanceType.JOINED) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING,length=20) public class WorkUnit extends BaseEntityClass implements Serializable{ @Entity @DiscriminatorValue(value="G") @Table(name="Group_") @PrimaryKeyJoinColumn public class Group extends WorkUnit implements Serializable{

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  • JPA Native Query (SQL View)

    - by Uchenna
    I have two Entities Customer and Account. @Entity @Table(name="customer") public class Customer { private Long id; private String name; private String accountType; private String accountName; ... } @Entity @Table(name="account") public class Account { private Long id; private String accountName; private String accountType; ... } i have a an sql query select a.id as account_id, a.account_name, a.account_type, d.id, d.name from account a, customer d Assumption account and customer tables are created during application startup. accountType and accountName fields of Customer entity should not be created. That is, only id and name columns will be created. Question How do i run the above sql query and return a Customer Entity Object with the accountType and accountName properties populated with sql query's account_name and account_type values. Thanks

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  • What is the best way to restore(rollback) data in an application to a specified state(date) ?

    - by panzerschreck
    Hello, An example would set the context right, the example below captures the various states of the entity, which needs to be reverted(rolled back) . State 1 - Recorded on 01-Mar-2010 Column1 Column2 Data1 0.56 State 2 - Recorded on 02-Mar-2010 Column1 Column2 Data1 0.57 State 3 - Recorded on 03-Mar-2010 Column1 Column2 Data1 0.58 User notices that state3 is not what he intended to be in, decides to revert back to state2. One approach that I can think of, without modifying the entity is via "auditing" all the inserts/updates, as below, the rollback information captures the data just before the updates/modifications on the entity, so that it can be applied in an order when you need to revert.Please note that changing the entity's schema, is not an option. Rollback - R1 recorded on 01-Mar-2010 Column1 Column2 Data1 0.56 Rollback - R2 Recorded on 02-Mar-2010 Column1 Column2 Data1 0.56 Rollback - R3 Recorded on 03-Mar-2010 Column1 Column2 Data1 0.57 So, to get to state2 , we would start with rollback information R1,apply R2 onto it. Is there a better approach to achieve this ? Thanks for your time.

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  • How to set up default value in symfony2 select box with data from database

    - by user172409255
    I have this code ->add('user', 'entity', array( 'class' => 'Acme\Entity\User', 'query_builder' => function(EntityRepository $er) use ($options) { return $er->createQueryBuilder('u') ->orderBy('u.name', 'ASC'); }, 'data' => $option['id'] )) Its not working public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('description') ->add('user', 'entity', array( 'class' => 'Acme\Entity\User', 'query_builder' => function(EntityRepository $er) use ($options) { return $er->createQueryBuilder('u'); }, 'preferred_choices' => array('2') )) ; }

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  • NSManagedObjectID into NSData

    - by papr
    I found this wonderful NSManagedObjectID. This would be very good for referencing an Entity/NSManagedObject/NSEntityDescription, right? Let's get an ID from an entity: NSEntityDescription *entity = [self newEntity]; NSManagedObjectID *objID = [entity objectID]; So... any idea how to get this objID into a string? Or better: NSData. Actually something to be able to save it to the NSUserDefaults. ;-) Btw: NSFetchRequest doesn't want to work in my case. I use an modified version of this example: answer of an old question.

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  • Updating the collections of entities with NHibernate the correct way

    - by karel_evzen
    A simple question regarding how NHibernate works: I have a parent entity that has a collection of other child entities. Those child entities have a reference to the parent entity they belong to. Now I want to implement an Add method to the parent entity that would add a child to it. Should that Add method only add the child to its new parents collection, or should it also update the parent reference of the child or should it also remove the added entity from its previous parents collection? Do I have to do all these things in that method or will NHibernate do something for me? Thanks.

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  • how to use JSF 1.2 and JPA in Netbeans ?

    - by user364746
    Hello... I'm trying to use JPA to connect my JSF components to database but the problem is that I can't figure out how to get this all combination works.I have done entity classes from database, also create persistence.xml file and now I don't know where to go!! I don't know how to use entity manager and entity manager factory. Is there any tutorial helps me how to use Java EE 5,JSF 1.2 and JPA in netbeans? any help appreciated Thanks

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  • Problem with inherited classes in C#

    - by Unniloct
    I have a class called "Entity," with two child classes: "Creature" and "Item." (I'm making a game.) Creature has two functions called "Attack," one for attacking Creatures, and one for attacking Items. So far, everything works well. Now I'm working on the shooting bit, so I have a function called SelectTarget(). It takes all of the Entities (both Creatures and Items) in the player's view that the player can shoot and lets the player choose one. So here lies the problem: SelectTarget() returns an Entity, but I need some code to figure out whether that Entity is a Creature or an Item, and process it appropriately. Since this question looks kind of empty without any code, and I'm not 100% sure my explanation is good enough, here's where I'm at: if (Input.Check(Key.Fire)) { Entity target = Game.State.SelectTarget.Run(); this.Draw(); if (target != null) { //Player.Attack(target); // This won't work, because I have: // Player.Attack((Creature)Target) // Player.Attack((Item)Target) // but nothing for Entity, the parent class to Creature and Item. return true; } } (If the way the game is laid out seems weird, it's a roguelike.)

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  • Difference between methods with and without generics

    - by isakavis
    Can someone help me understand advantages and disadvantages (if any) between the following methods which do the same function of storing away the entity to azure (in my case)? public bool Save<T>(string tableName, T entity) where T : TableEntityBase, new() { throw new NotImplementedException(); } vs public bool Save(string tableName, TableEntityBase entity) { throw new NotImplementedException(); }

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  • spring mvc 3.0 small web application not quite working

    - by lurscher
    Hi, i'm creating a very simple (hello World quality) web application using spring mvc 3.0. when deploying the application on tomcat 6.0.26 and i try to open http://localhost:8080/protoweb/helloWorld.html i get 404, resource /protoweb/WEB-INF/jsp/helloWorld.jsp is not available. The funny thing is that there IS a helloWorld.jsp in there. any idea what i'm doing wrong? here is my web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> <display-name>hello-spring3-RC1</display-name> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/yummy-servlet.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>yummy</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>yummy</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> </web-app> my yummy-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:component-scan base-package="com.mine.web.controllers"/> <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </beans> my very simple controller: package com.mine.web.controllers; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class BasicController { @RequestMapping(value = "/helloWorld") public ModelAndView helloWorld() { ModelAndView mav = new ModelAndView(); mav.setViewName("helloWorld"); mav.addObject("message", "Hello some basic message for u"); return mav; } } and my webapp/jsp/helloWorld.jsp <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Hello</title> </head> <body> ${message} </body> </html> also, it might be helpful to post my pom.xml <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mine</groupId> <artifactId>protoweb</artifactId> <packaging>war</packaging> <version>1.0-SNAPSHOT</version> <name>protoweb Maven Webapp</name> <url>http://maven.apache.org</url> <repositories> <repository> <id>springsource maven repo</id> <url>http://maven.springframework.org/milestone</url> </repository> </repositories> <dependencies> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-webmvc</artifactId> <version>3.0.0.RC1</version> </dependency> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> <dependency> <groupId>javax.servlet</groupId> <artifactId>jstl</artifactId> <version>1.1.2</version> <scope>compile</scope> </dependency> </dependencies> <build> <finalName>protoweb</finalName> <plugins> <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>tomcat-maven-plugin</artifactId> <configuration> <configurationDir>tomcat</configurationDir> <url>http://localhost:8080/manager</url> <username>test</username> <password>test</password> </configuration> </plugin> </plugins> </build> </project>

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  • How to load a springframework ApplicationContext from Jython

    - by staticman
    I have a class that loads a springframework application context like so: package com.offlinesupport; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class OfflineScriptSupport { private static ApplicationContext appCtx; public static final void initialize() { appCtx = new ClassPathXmlApplicationContext( new String[] { "mycontext.spring.xml" } ); } public static final ApplicationContext getApplicationContext() { return appCtx; } public static final void main( String[] args ) { System.out.println( "Starting..." ); initialize(); System.out.println( "loaded" ); } } The class OfflineScriptSupport, and the file mycontext.spring.xml are each deployed into separate jars (along with other classes and resources in their respective modules). Lets say the jar files are OfflineScriptSupport.jar and *MyContext.jar". mycontext.spring.xml is put at the root of the jar. In a Jython script (*myscript.jy"), I try to call the initialize method to create the application context: from com.offlinesupport import OfflineScriptSupport OfflineScriptSupport.initialize(); I execute the Jython script with the following command (from Linux): jython -Dpython.path=spring.jar:OfflineScriptSupport.jar:MyContext.jar myscript.jy The Springframework application context cannot find the mycontext.spring.xml file. It displays the following error: java.io.FileNotFoundException: class path resource [mycontext.spring.xml] cannot be opened because it does not exist at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:137) at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:167) at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:148) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:126) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:142) at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:113) at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:81) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:89) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:269) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:87) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:72) at com.offlinesupport.OfflineScriptSupport.initialize(OfflineScriptSupport.java:27) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) If I run the jar directly from Java (using the main entry point in OfflineScriptSupport) it works and there is no error thrown. Is there something special about the way Jython handles classpaths making the Springframework's ClassPathXmlApplicationContext not work (i.e. not be able to find resource files in the classpath)?

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  • spring mvc, css and javascript is not working properly

    - by user2788424
    the css and javascript is not take effect on my page. I google online, people saying this is the magic, but not happening on my page. <mvc:resources mapping="/resources/**" location="/resources/" /> this is the error: Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/css/styles.css] in DispatcherServlet with name 'dispatcher' Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/script.js] in DispatcherServlet with name 'dispatcher' Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/js/jquery-1.10.2.min.js] in DispatcherServlet with name 'dispatcher' here is the applicationContext.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd"> <context:component-scan base-package="org.peterhuang.myweb" /> <mvc:resources mapping="/resources/**" location="/resources/" /> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> </bean> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"> </bean> <!-- Hibernate Transaction Manager --> <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> <mvc:annotation-driven /> <!-- Activates annotation based transaction management --> <tx:annotation-driven /> <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location" value="classpath:jdbc.properties" /> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/"></property> <property name="suffix" value=".jsp"></property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="packagesToScan" value="org.peterhuang.myweb" /> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect"> ${jdbc.dialect} </prop> <prop key="hibernate.show_sql"> ${hibernate.show_sql} </prop> <prop key="hibernate.format_sql"> ${hibernate.format_sql} </prop> </props> </property> </bean> here is the web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>my web</display-name> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/applicationContext.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <welcome-file-list> <welcome-file>/WEB-INF/jsp/welcome.jsp</welcome-file> </welcome-file-list> this is the page got displaied: <%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%> <%@ taglib uri="http://www.springframework.org/tags" prefix="spring"%> <link type="text/css" rel="stylesheet" href="<spring:url value='resources/css/styles.css' />" /> <script type="text/javascript" src="<spring:url value='resources/js/jquery-1.10.2.min.js' />"></script> <script type="text/javascript" src="<spring:url value='resources/script.js'/>"</script> <ul id="button"> <c:forEach var="category" items="${categoryList}"> <li><a href="#">${category.categoryName}</a></li> </c:forEach> </ul> the folder structure in eclipse: myweb | | | |----Java Resources | | | | | |-----src/main/resources | | | | | | | | |------js | | | | | | | |-----jquery-1.10.2.min.js | | | | | | | | | | | |-----script.js | | | | | | | | |-----css | | | | | | | |-----style.css | | | | | | | | any tips would be appreciated!! thanks in advanced!

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  • Spring Framework 3.0.5 MVC Issue

    - by user578923
    I know that this may be absolutely dumb but for the life of me I cannot figure out why I'm getting these errors in my Spring Project, it is basically from the MVC tutorial with a few modifications. This is the error I get when running my tomcat server. `Caused by: java.lang.NoClassDefFoundError: org/springframework/web/servlet/mvc/SimpleFormController at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:634) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142) at java.net.URLClassLoader.defineClass(URLClassLoader.java:277) at java.net.URLClassLoader.access$000(URLClassLoader.java:73) at java.net.URLClassLoader$1.run(URLClassLoader.java:212) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1581) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1511) at org.springframework.util.ClassUtils.forName(ClassUtils.java:257) at org.springframework.beans.factory.support.AbstractBeanDefinition.resolveBeanClass(AbstractBeanDefinition.java:408) at org.springframework.beans.factory.support.AbstractBeanFactory.doResolveBeanClass(AbstractBeanFactory.java:1271) at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1242) ... 54 more Caused by: java.lang.ClassNotFoundException: org.springframework.web.servlet.mvc.SimpleFormController at java.net.URLClassLoader$1.run(URLClassLoader.java:217) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) ... 71 more` I just cannot figure out the issue with my classpath...I would appreciate any help. Here are all the jars in my classpath. I know that the class is inside the web-servlet jar but it's not seeing it. Is there a conflict? aopalliance.jar aspectjweaver.jar commons-codec.jar commons-dbcp.jar commons-logging.jar commons-pool.jar jstl.jar org.springframework.aop-3.0.5.RELEASE.jar org.springframework.asm-3.0.5.RELEASE.jar org.springframework.aspects-3.0.5.RELEASE.jar org.springframework.beans-3.0.5.RELEASE.jar org.springframework.context.support-3.0.5.RELEASE.jar org.springframework.context-3.0.5.RELEASE.jar org.springframework.core-3.0.5.RELEASE.jar org.springframework.expression-3.0.5.RELEASE.jar org.springframework.instrument.tomcat-3.0.5.RELEASE.jar org.springframework.instrument-3.0.5.RELEASE.jar org.springframework.jdbc-3.0.5.RELEASE.jar org.springframework.jms-3.0.5.RELEASE.jar org.springframework.orm-3.0.5.RELEASE.jar org.springframework.oxm-3.0.5.RELEASE.jar org.springframework.test-3.0.5.RELEASE.jar org.springframework.transaction-3.0.5.RELEASE.jar org.springframework.web.portlet-3.0.5.RELEASE.jar org.springframework.web.servlet-3.0.5.RELEASE.jar org.springframework.web.struts-3.0.5.RELEASE.jar org.springframework.web-3.0.5.RELEASE.jar postgresql-9.0-801.jdbc3.jar servlet-api.jar spring-security-config-3.0.5.RELEASE.jar spring-security-core-3.0.5.RELEASE.jar spring-security-web-3.0.5.RELEASE.jar standard.jar

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  • Using jQuery and OData to Insert a Database Record

    - by Stephen Walther
    In my previous blog entry, I explored two ways of inserting a database record using jQuery. We added a new Movie to the Movie database table by using a generic handler and by using a WCF service. In this blog entry, I want to take a brief look at how you can insert a database record using OData. Introduction to OData The Open Data Protocol (OData) was developed by Microsoft to be an open standard for communicating data across the Internet. Because the protocol is compatible with standards such as REST and JSON, the protocol is particularly well suited for Ajax. OData has undergone several name changes. It was previously referred to as Astoria and ADO.NET Data Services. OData is used by Sharepoint Server 2010, Azure Storage Services, Excel 2010, SQL Server 2008, and project code name “Dallas.” Because OData is being adopted as the public interface of so many important Microsoft technologies, it is a good protocol to learn. You can learn more about OData by visiting the following websites: http://www.odata.org http://msdn.microsoft.com/en-us/data/bb931106.aspx When using the .NET framework, you can easily expose database data through the OData protocol by creating a WCF Data Service. In this blog entry, I will create a WCF Data Service that exposes the Movie database table. Create the Database and Data Model The MoviesDB database is a simple database that contains the following Movies table: You need to create a data model to represent the MoviesDB database. In this blog entry, I use the ADO.NET Entity Framework to create my data model. However, WCF Data Services and OData are not tied to any particular OR/M framework such as the ADO.NET Entity Framework. For details on creating the Entity Framework data model for the MoviesDB database, see the previous blog entry. Create a WCF Data Service You create a new WCF Service by selecting the menu option Project, Add New Item and selecting the WCF Data Service item template (see Figure 1). Name the new WCF Data Service MovieService.svc. Figure 1 – Adding a WCF Data Service Listing 1 contains the default code that you get when you create a new WCF Data Service. There are two things that you need to modify. Listing 1 – New WCF Data Service File using System; using System.Collections.Generic; using System.Data.Services; using System.Data.Services.Common; using System.Linq; using System.ServiceModel.Web; using System.Web; namespace WebApplication1 { public class MovieService : DataService< /* TODO: put your data source class name here */ > { // This method is called only once to initialize service-wide policies. public static void InitializeService(DataServiceConfiguration config) { // TODO: set rules to indicate which entity sets and service operations are visible, updatable, etc. // Examples: // config.SetEntitySetAccessRule("MyEntityset", EntitySetRights.AllRead); // config.SetServiceOperationAccessRule("MyServiceOperation", ServiceOperationRights.All); config.DataServiceBehavior.MaxProtocolVersion = DataServiceProtocolVersion.V2; } } } First, you need to replace the comment /* TODO: put your data source class name here */ with a class that represents the data that you want to expose from the service. In our case, we need to replace the comment with a reference to the MoviesDBEntities class generated by the Entity Framework. Next, you need to configure the security for the WCF Data Service. By default, you cannot query or modify the movie data. We need to update the Entity Set Access Rule to enable us to insert a new database record. The updated MovieService.svc is contained in Listing 2: Listing 2 – MovieService.svc using System.Data.Services; using System.Data.Services.Common; namespace WebApplication1 { public class MovieService : DataService<MoviesDBEntities> { public static void InitializeService(DataServiceConfiguration config) { config.SetEntitySetAccessRule("Movies", EntitySetRights.AllWrite); config.DataServiceBehavior.MaxProtocolVersion = DataServiceProtocolVersion.V2; } } } That’s all we have to do. We can now insert a new Movie into the Movies database table by posting a new Movie to the following URL: /MovieService.svc/Movies The request must be a POST request. The Movie must be represented as JSON. Using jQuery with OData The HTML page in Listing 3 illustrates how you can use jQuery to insert a new Movie into the Movies database table using the OData protocol. Listing 3 – Default.htm <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>jQuery OData Insert</title> <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> <script src="Scripts/json2.js" type="text/javascript"></script> </head> <body> <form> <label>Title:</label> <input id="title" /> <br /> <label>Director:</label> <input id="director" /> </form> <button id="btnAdd">Add Movie</button> <script type="text/javascript"> $("#btnAdd").click(function () { // Convert the form into an object var data = { Title: $("#title").val(), Director: $("#director").val() }; // JSONify the data var data = JSON.stringify(data); // Post it $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "MovieService.svc/Movies", data: data, dataType: "json", success: insertCallback }); }); function insertCallback(result) { // unwrap result var newMovie = result["d"]; // Show primary key alert("Movie added with primary key " + newMovie.Id); } </script> </body> </html> jQuery does not include a JSON serializer. Therefore, we need to include the JSON2 library to serialize the new Movie that we wish to create. The Movie is serialized by calling the JSON.stringify() method: var data = JSON.stringify(data); You can download the JSON2 library from the following website: http://www.json.org/js.html The jQuery ajax() method is called to insert the new Movie. Notice that both the contentType and dataType are set to use JSON. The jQuery ajax() method is used to perform a POST operation against the URL MovieService.svc/Movies. Because the POST payload contains a JSON representation of a new Movie, a new Movie is added to the database table of Movies. When the POST completes successfully, the insertCallback() method is called. The new Movie is passed to this method. The method simply displays the primary key of the new Movie: Summary The OData protocol (and its enabling technology named WCF Data Services) works very nicely with Ajax. By creating a WCF Data Service, you can quickly expose your database data to an Ajax application by taking advantage of open standards such as REST, JSON, and OData. In the next blog entry, I want to take a closer look at how the OData protocol supports different methods of querying data.

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  • finite state machine used in mario like platform game

    - by juakob
    I dont understand how to use a finite state machine with the entity controlled by the player. For example i have a mario(2d platform) i can jump,run,walk,take damage,swim,etc so my first thought was to use this actions as states. But what happen when you are running when you take damage? or jumping taking damage and shooting at the same time? I just want to add functionalities(actions) to the player in a clean way(not using ifs for all the actions in the entity update)

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