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• Configuring Hadoop logging to avoid too many log files

  - by Eric Wendelin

  I'm having a problem with Hadoop producing too many log files in $HADOOP_LOG_DIR/userlogs (the Ext3 filesystem allows only 32000 subdirectories) which looks like the same problem in this question: http://stackoverflow.com/questions/2091287/error-in-hadoop-mapreduce My question is: does anyone know how to configure Hadoop to roll the log dir or otherwise prevent this? I'm trying to avoid just setting the "mapred.userlog.retain.hours" and/or "mapred.userlog.limit.kb" properties because I want to actually keep the log files. I was also hoping to configure this in log4j.properties, but looking at the Hadoop 0.20.2 source, it writes directly to logfiles instead of actually using log4j. Perhaps I don't understand how it's using log4j fully. Any suggestions or clarifications would be greatly appreciated.

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• Recursive wildcards in Rake?

  - by Roger Lipscombe

  Follow up to this question about GNU make: I've got a directory, flac, containing .FLAC files. I've got a corresponding directory, mp3 containing MP3 files. If a FLAC file is newer than the corresponding MP3 file (or the corresponding MP3 file doesn't exist), then I want to run a bunch of commands to convert the FLAC file to an MP3 file, and copy the tags across. The kicker: I need to search the flac directory recursively, and create corresponding subdirectories in the mp3 directory. The directories and files can have spaces in the names, and are named in UTF-8. It turns out that this won't work in make, because of the spaces in the directories and filenames, so I'm wondering how to do it in rake instead...

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• Reason for monolithic data files

  - by Ali Lown

  Primarily this seems to be a technique used by games, where they have all the sounds in one file, textures in another etc. With these files commonly reaching the GB size. What is the reason behind doing this over maintaining it all in subdirectories as small files - one per texture which many small games use this, with the monolithic system being favoured by larger companies? Is there some file system overhead with lots of small files? Are they trying to protect their property - although most just seem to be a compressed file with a new extension?

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• Recursive compilation using gcc

  - by curiousexplorer

  I am using the gcc compiler. My project source tree looks like somewhat like this test$~: tree . . |-- folder | |-- hello.cpp | `-- hello.h `-- main.cpp 1 directory, 3 files test$~: The file main.cpp contains the main() function and all the functions invoked by main.cpp lie in the directory named folder So far in all my little projects I never had to put some source code under a sub-directory. What I am looking for, in short, is some gcc command for recursive compilation in sub-directories and their subdirectories and so on... This command should be invoked from the home directory of the code project.

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• .classpath and .project - check into version control or not?

  - by amarillion

  I'm running an open source java project that consists of multiple modules in a tree of dependencies. All those modules are subdirectories in a subversion repository. For newcomers to our project, it's a lot of work to set all that up manually in eclipse. Not all our developers use eclipse. Nevertheless, we're considering to just check in the .classpath and .project files to help newcomers to get started. Is this a good idea? Or would that lead to constant conflicts in those files? Is there an alternative way to make the project easy to set up on eclipse?

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• Why does File::Find finished short of completely traversing a large directory?

  - by Stan

  A directory exists with a total of 2,153,425 items (according to Windows folder Properties). It contains .jpg and .gif image files located within a few subdirectories. The task was to move the images into a different location while querying each file's name to retrieve some relevant info and store it elsewhere. The script that used File::Find finished at 20462 files. Out of curiosity I wrote a tiny recursive function to count the items which returned a count of 1,734,802. I suppose the difference can be accounted for by the fact that it didn't count folders, only files that passed the -f test. The problem itself can be solved differently by querying for file names first instead of traversing the directory. I'm just wondering what could've caused File::Find to finish at a small fraction of all files. The data is stored on an NTFS file system.

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• Perl: Fastest way to get directory (and subdirs) size on unix - using stat() at the moment

  - by ivicas

  I am using Perl stat() function to get the size of directory and it's subdirectories. I have a list of about 20 parent directories which have few thousand recursive subdirs and every subdir has few hundred records. Main computing part of script looks like this: sub getDirSize { my $dirSize = 0; my @dirContent = <*>; my $sizeOfFilesInDir = 0; foreach my $dirContent (@dirContent) { if (-f $dirContent) { my $size = (stat($dirContent))[7]; $dirSize += $size; } elsif (-d $dirContent) { $dirSize += getDirSize($dirContent); } } return $dirSize; } The script is executing for more than one hour and I want to make it faster. I was trying with the shell du command, but the output of du (transfered to bytes) is not accurate. And it is also quite time consuming. I am working on HP-UNIX 11i v1.

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• Bash: any command to replace strings in text files?

  - by mikez302

  I have a hierarchy of directories containing many text files. I would like to search for a particular text string every time it comes up in one of the files, and replace it with another string. For example, I may want to replace every occurrence of the string "Coke" with "Pepsi". Does anyone know how to do this? I am wondering if there is some sort of Bash command that can do this without having to load all these files in an editor, or come up with a more complex script to do it. I found this page explaining a trick using sed, but it doesn't seem to work in files in subdirectories.

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• How to avoid the Windows (XP) Security Warning when launching a "DOS" command line within C#?

  - by Will Marcouiller

  This question is related to this initial question asked a little while ago. Now, that I have chosen the extracting tool, I'm iterating through a given in command line parameter directory and subdirectories to extract the compressed .zip files. private static void ExtractAll(DirectoryInfo _workingFolder) { if(_workingFolder == null) { Console.WriteLine("Répertoire inexistant."); return; } foreach (DirectoryInfo subFolder in _workingFolder.GetDirectories("*", SearchOption.AllDirectories)) foreach(FileInfo zippedFile in subFolder.GetFiles("*.zip", SearchOption.AllDirectories)) { if(zippedFile.Exists) { ProcessStartInfo task = new ProcessStartInfo(@".\Tools\7za.exe", string.Format("x {0}", zippedFile.FullName)); Process.Start(task); } } } But everytime I start a 7za process, the Windows Security Warning prompts. I would like to avoid such annoying behaviour, so here's my question: How to avoid the Windows (XP) Security Warning when launching a "DOS" command line within C#?

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• How to use git to download a particular tag?

  - by Jack BeNimble

  I'm trying to figure out how do download a particular tag of a git repository - it's one version behind the current version. I saw there was a tag for the previous version on the git web page, with object name of something long hex number. But the version name is "Tagged release 1.1.5" according the site. I tried a command like this (with names changed): git clone http://git.abc.net/git/abc.git my_abc And I did get something - a directory, a bunch of subdirectories, etc. If it's the whole repository, how do I get at the version I'm seeking? If not, how do I download that particular version?

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• How can I map URLs to filenames with perl?

  - by eugene y

  In a simple webapp I need to map URLs to filenames or filepaths. This app has a requirement that it can depend only on modules in the core Perl ditribution (5.6.0 and later). The problem is that filename length on most filesystems is limited to 255. Another limit is about 32k subdirectories in a single folder. My solution: my $filename = $url; if (length($filename) > $MAXPATHLEN) { # if filename longer than 255 my $part1 = substr($filename, 0, $MAXPATHLEN - 13); # first 242 chars my $part2 = crypt(0, substr($filename, $MAXPATHLEN - 13)); # 13 chars hash $filename = $part1.$part2; } $filename =~ s!/!_!g; # escape directory separator Is it reliable ? How can it be improved ?

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• What's the fastest way to get directory and subdirs size on unix using Perl?

  - by ivicas

  I am using Perl stat() function to get the size of directory and its subdirectories. I have a list of about 20 parent directories which have few thousand recursive subdirs and every subdir has few hundred records. Main computing part of script looks like this: sub getDirSize { my $dirSize = 0; my @dirContent = <*>; my $sizeOfFilesInDir = 0; foreach my $dirContent (@dirContent) { if (-f $dirContent) { my $size = (stat($dirContent))[7]; $dirSize += $size; } elsif (-d $dirContent) { $dirSize += getDirSize($dirContent); } } return $dirSize; } The script is executing for more than one hour and I want to make it faster. I was trying with the shell du command, but the output of du (transfered to bytes) is not accurate. And it is also quite time consuming. I am working on HP-UNIX 11i v1.

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• find string from the file in somewhere

  - by lightmanhk

  I want to find a string from some file in subdirectory. Like we are in bundle/. and in bundle/ there are multiple subdirectories and multiple txt files I want to do something like find . -type f -exec grep "\<F8\>" {} \; want to get the file where it contain string < F8 this command does work, find the string, but never return filename I hope anyone can give me a better solution to this, like display filename along with the line containing that string

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• Why can't I view a directory in Linux?

  - by Thread7

  I am setting up a Linux web server running apache. I uploaded and untared my web sites files. The files in the main directory are all visible when I am SSH'd into the system. However, I am blocked from all subdirectories. If I write: # cd images Then I get the error: -bash: cd: images: Permission denied I am signed in as ec2-user. I untarred the stuff as ec2-user and I doubt there was any permissions in the tar file since I created the archive on a Windows system. The weird thing is that I am the owner of this directory. Here is a snippet of the command: ls -l drw-rw-r-- 19 ec2-user ec2-user 4096 May 4 04:09 images When I do "sudo su" and then type the command cd images everything is fine. Why do I get "Permission denied" as ec2-user if I am the owner and have rw permission?

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• Correct permissions for /var/www and wordpress

  - by dpbklyn

  Hello and thank you in advance! I am relatively new to ubuntu, so please excuse the newbie-ness of this question... I have set up a LAMP server (ubuntu server 11.10) and I have access via SSH and to the "it works" page from a web browser from inside my network (via ip address) and from outside using dyndns. I have a couple of projects in development with some outside developers and I want to use this server as a development server for testing and for client approvals. We have some Wordpress projects that sit in subdirectories in /var/www/wordpress1 /var/www/wordpress2, etc. I cannot access these sub directories from a browser in order to set up WP--or (I assume) to see the content on a browser. I get a 403 Forbidden error on my browser. I assume that this is a permissions problem. Can you please tell me the proper settings for the permissions to: 1) Allow the developers and me to read/write. 2) to allow WP set up and do its thing 3) Allow visitors to access the site(s) via the web. I should also mention that the subfolder are actually simlinks to folder on another internal hdd--I don't think this will make a difference, but I thought I should disclose. Since I am a newbie to ubuntu, step-by-step directions are greatly appreciated! Thank you for taking the time! dp total 12 drwxr-xr-x 2 root root 4096 2012-07-12 10:55 . drwxr-xr-x 13 root root 4096 2012-07-11 20:02 .. lrwxrwxrwx 1 root root 43 2012-07-11 20:45 admin_media -> /root/django_src/django/contrib/admin/media -rw-r--r-- 1 root root 177 2012-07-11 17:50 index.html lrwxrwxrwx 1 root root 14 2012-07-11 20:42 media -> /hdd/web/media lrwxrwxrwx 1 root root 18 2012-07-12 10:55 wordpress -> /hdd/web/wordpress Here is the result of using chown -R www-data:www-data /var/www total 12 drwxr-xr-x 2 www-data www-data 4096 2012-07-12 10:55 . drwxr-xr-x 13 root root 4096 2012-07-11 20:02 .. lrwxrwxrwx 1 www-data www-data 43 2012-07-11 20:45 admin_media -> /root/django_src/django/contrib/admin/media -rw-r--r-- 1 www-data www-data 177 2012-07-11 17:50 index.html lrwxrwxrwx 1 www-data www-data 14 2012-07-11 20:42 media -> /hdd/web/media lrwxrwxrwx 1 www-data www-data 18 2012-07-12 10:55 wordpress -> /hdd/web/wordpress I am still unable to access via browser...

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• Get user profile size in vbscript

  - by Cameron

  Hello, I am trying to get the size of a user's local profile using VBScript. I know the directory of the profile (typically "C:\Users\blah"). The following code does not work for most profiles (Permission Denied error 800A0046): Dim folder Dim fso Set fso = WScript.CreateObject("Scripting.FileSystemObject") Set folder = fso.GetFolder("C:\Users\blah") MsgBox folder.Size ' Error occurs here Is there another way to do this? UPDATE: I did some deeper digging and it turns out that the Permission Denied error occurs if permission is denied to some subfolders or files of the directory whose size I wish to get. In the case of user profiles, there's always a few system files that even the Administrator group does not have permission to access. To get around this, I wrote a function that tries to get the folder size the normal way (above), then, if the error occurs, it recurses into the subdirectories of the folder, ignoring folder sizes that are permission denied (but not the rest of the folders). Dim fso Set fso = WScript.CreateObject("Scripting.FileSystemObject") Function getFolderSize(folderName) On Error Resume Next Dim folder Dim subfolder Dim size Dim hasSubfolders size = 0 hasSubfolders = False Set folder = fso.GetFolder(folderName) ' Try the non-recursive way first (potentially faster?) Err.Clear size = folder.Size If Err.Number <> 0 then ' Did not work; do recursive way: For Each subfolder in folder.SubFolders size = size + getFolderSize(subfolder.Path) hasSubfolders = True Next If not hasSubfolders then size = folder.Size End If End If getFolderSize = size Set folder = Nothing ' Just in case End Function

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• Trying to run an ASP.NET MVC application using Mono on Apache with FastCGI.

  - by Arda Xi

  I have a hosting account with DreamHost, and I would like to use the same account to run ASP.NET applications. I have an application deployed in a subdomain, a .htaccess with a handler like this: # Define the FastCGI Mono launcher as an Apache handler and let # it manage this web-application (its files and subdirectories) SetHandler monoWrapper Action monoWrapper /home/arienh4/<domain>/cgi-bin/mono.fcgi virtual My mono.fcgi is set up as such: #!/bin/sh #umask 0077 exec >>/home/arienh4/tmp/mono-fcgi.log exec 2>>/home/arienh4/tmp/mono-fcgi.err echo $(date +"[%F %T]") Starting fastcgi-mono-server2 cd / chmod 0700 /home/arienh4/tmp/mono-fcgi.sock echo $$>/home/arienh4/tmp/mono-fcgi.pid # stdin is the socket handle export PATH="/home/arienh4/mono/bin:$PATH" export LD_LIBRARY_PATH="/home/arienh4/mono/lib:$LD_LIBRARY_PATH" export TMP="/home/arienh4/tmp" export MONO_SHARED_DIR="/home/arienh4/tmp" exec /home/arienh4/mono/bin/mono /home/arienh4/mono/lib/mono/2.0/fastcgi-mono-server2.exe \ /logfile=/home/arienh4/logs/fastcgi-mono-web.log /loglevels=All \ /applications=/:/home/arienh4/<domain> I took this from the Mono site for CGI, I'm not sure if I'm doing it correctly though. This code is resulting in this error: Request exceeded the limit of 10 internal redirects due to probable configuration error. Use 'LimitInternalRecursion' to increase the limit if necessary. Use 'LogLevel debug' to get a backtrace. I have no idea what's causing this. As far as I can see, Mono isn't even hit (no log files are created).

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• Using %v in Apache LogFormat definition matches ServerName instead of specific vhost requested

  - by Graeme Donaldson

  We have an application which uses a DNS wildcard, i.e. *.app.example.com. We're using Apache 2.2 on Ubuntu Hardy. The relevant parts of the Apache config are as follows. In /etc/apache2/httpd.conf: LogFormat "%v %h %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" vlog In /etc/apache2/sites-enabled/app.example.com: ServerName app.example.com ServerAlias *.app.example.com ... CustomLog "|/usr/sbin/vlogger -s access.log /var/log/apache2/vlogger" vlog Clients access this application using their own URL, e.g. company1.app.example.com, company2.app.example.com, etc. Previously, the %v in the LogFormat directive would match the hostname of the client request, and we'd get several subdirectories under /var/log/apache2/vlogger corresponding to the various client URLs in use. Now, %v appears to be matching the ServerName value, so we only get one log under /var/log/apache2/vlogger/app.example.com. This breaks our logfile analysis because the log file has no indication of which client the log relates to. I can fix this easily by changing the LogFormat to this: LogFormat "%{Host}i %h %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" vlog This will use the HTTP Host: header to tell vlogger which subdirectory to create the logs in and everything will be fine. The only concern I have is that this has worked in the past and I can't find any indication that this has changed recently. Is anyone else using a similar config, i.e. wildcard + vlogger and using %v? Is it working fine?

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• CopSSH SFTP -- limit users access to their home directory only

  - by bradvido

  Let me preface this by saying I've read and followed these instructions at the FAQ many times: http://www.itefix.no/i2/node/37 It does not do what the title claims... It allows every user access to every other user's home directory, as well as access to all subfolders below the copssh installation path. I'm only using this for SFTP access and I need my users to be sandboxed into only their home directory. If you know a fool-proof way to lock users down so they can see only their home directory and its subfolders, stop reading now and reply with the solution. The details: Here is exactly what i tried as I followed the FAQ. My copSSH installation directory is: C:\Program Files\CopSSH net localgroup sftp_users /ADD **Create a user group to hold all my SFTP users cacls c:\ /c /e /t /d sftp_users **For that group, deny access at the top level and all levels below cacls "C:\Program Files\CopSSH" /c /e /t /r sftp_users **Allow my user group access to the copSSH installation directory and its subdirectories For each sftp user, I create a new windows user account, then I: net localgroup sftp_users sftp_user_1 /add **Add my user to the group I've created Open the activate user wizard for CopSSH, choosing the user, "/bin/sftponly" and Remove copssh home directory if it exists **Remains checked Create keys for public key authentication **Remains checked Create link to user's real home directory **Remains checked This works, however, every user has access to every other user's home directory as well as the CopSSH root directory.... So I tried denying access for all users to the user home directory: cacls "C:\Program Files\CopSSH\home" /c /e /t /d sftp_users **Deny access for users to the user home directory Then I tried adding permissions on a user-by-user basis for each users home\username folder. However,these permission were not allowed by windows because of the above deny rule i created at the home directory was being inherited and over-riding my allow rule. The next step for me would be to remove the deny rule at the home directory and for each user folder, add a deny rule for every user it doesn't belong to, and add an allow rule for the one user it does belong to. However, as my user list gets long, this will become very cumbersome. Thanks for the help!

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• Trying to run an ASP.NET MVC application using Mono on Apache with FastCGI

  - by Arda Xi

  I have a hosting account with DreamHost and I would like to use the same account to run ASP.NET applications. I have an application deployed in a subdomain, a .htaccess with a handler like this: # Define the FastCGI Mono launcher as an Apache handler and let # it manage this web-application (its files and subdirectories) SetHandler monoWrapper Action monoWrapper /home/arienh4/<domain>/cgi-bin/mono.fcgi virtual My mono.fcgi is set up as such: #!/bin/sh #umask 0077 exec >>/home/arienh4/tmp/mono-fcgi.log exec 2>>/home/arienh4/tmp/mono-fcgi.err echo $(date +"[%F %T]") Starting fastcgi-mono-server2 cd / chmod 0700 /home/arienh4/tmp/mono-fcgi.sock echo $$>/home/arienh4/tmp/mono-fcgi.pid # stdin is the socket handle export PATH="/home/arienh4/mono/bin:$PATH" export LD_LIBRARY_PATH="/home/arienh4/mono/lib:$LD_LIBRARY_PATH" export TMP="/home/arienh4/tmp" export MONO_SHARED_DIR="/home/arienh4/tmp" exec /home/arienh4/mono/bin/mono /home/arienh4/mono/lib/mono/2.0/fastcgi-mono-server2.exe \ /logfile=/home/arienh4/logs/fastcgi-mono-web.log /loglevels=All \ /applications=/:/home/arienh4/<domain> I took this from the Mono site for CGI. I'm not sure if I'm doing it correctly though. This code is resulting in this error: Request exceeded the limit of 10 internal redirects due to probable configuration error. Use 'LimitInternalRecursion' to increase the limit if necessary. Use 'LogLevel debug' to get a backtrace. I have no idea what's causing this. As far as I can see, Mono isn't even hit (no log files are created).

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• alias gcc='gcc -fpermissive' or modifying ./configure script

  - by robo

  I am compiling quite big project from source. The compilation always ends with: error: invalid conversion from ‘const char*’ to ‘char*’ [-fpermissive] I have already compiled this project one year ago. So I know a solution to this. Actualy I found more solutions: Adding a typecast to appropriate line of cpp code (It went to endless number of changes in each file. So I found next solution.) Modifying a makefile to compile that file with -fpermissive option. (I had to modify a lot of lines in each makefile. So I find even better solution.) "g++" or "gcc" was stored in a variable so I added -fpermissive to these variables. This is the best solution I have. It is sufficient to add this option to each makefile once. Unfortunately this software has big number of subdirectories. So I need to modify more than 100 makefiles. It took me whole day one year ago. Is there a way how to do this faster. What about this? alias gcc='gcc -fpermissive' I am not familiar with aliases. But it should be easy to try this. Is the syntax correct? And is this one correct? alias g++='g++ -fpermissive' ? And do I need to export the alias somehow? Will the make program respect the alias? Should I maybe change ./configure script? Or the ./configure.in? Or other file?

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• Upgrading Visio 2000 to Visio 2007

  - by dirtside

  I have Microsoft Visio 2000 SR 1, and recently purchased Microsoft Office Visio Standard 2007 with the understanding (supported by the product info and some other research) that I'd be able to upgrade. However, when I install 2007, it tells me it can't find a previous install of Visio, but... it's right there! Here's the exact message: "Setup can't find a version of Microsoft Office on your computer. If Office is installed on a disk or network share, click the browse button to select the appropriate disk or share... (etc.)" No matter which directory or drive I pick (various Office installs, the old Visio install, various subdirectories) it gives the following message: "The path you have chosen does not point at a qualifying upgradeable product. Click 'Retry' to try again or 'Cancel' to quit setup." Any ideas? This is a legit copy of Visio 2007 (purchased from Amazon) and the copy of Visio 2000 is legit as well. I'm not sure what exactly the installer is looking for that it would consider a "qualifying upgradeable product". A specific file?

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• CopSSH SFTP -- limit users access to their home directory only

  - by bradvido

  Let me preface this by saying I've read and followed these instructions at the FAQ many times: http://www.itefix.no/i2/node/37 It does not do what the title claims... It allows every user access to every other user's home directory, as well as access to all subfolders below the copssh installation path. I'm only using this for SFTP access and I need my users to be sandboxed into only their home directory. If you know a fool-proof way to lock users down so they can see only their home directory and its subfolders, stop reading now and reply with the solution. The details: Here is exactly what i tried as I followed the FAQ. My copSSH installation directory is: C:\Program Files\CopSSH net localgroup sftp_users /ADD **Create a user group to hold all my SFTP users cacls c:\ /c /e /t /d sftp_users **For that group, deny access at the top level and all levels below cacls "C:\Program Files\CopSSH" /c /e /t /r sftp_users **Allow my user group access to the copSSH installation directory and its subdirectories For each sftp user, I create a new windows user account, then I: net localgroup sftp_users sftp_user_1 /add **Add my user to the group I've created Open the activate user wizard for CopSSH, choosing the user, "/bin/sftponly" and Remove copssh home directory if it exists **Remains checked Create keys for public key authentication **Remains checked Create link to user's real home directory **Remains checked This works, however, every user has access to every other user's home directory as well as the CopSSH root directory.... So I tried denying access for all users to the user home directory: cacls "C:\Program Files\CopSSH\home" /c /e /t /d sftp_users **Deny access for users to the user home directory Then I tried adding permissions on a user-by-user basis for each users home\username folder. However,these permission were not allowed by windows because of the above deny rule i created at the home directory was being inherited and over-riding my allow rule. The next step for me would be to remove the deny rule at the home directory and for each user folder, add a deny rule for every user it doesn't belong to, and add an allow rule for the one user it does belong to. However, as my user list gets long, this will become very cumbersome. Thanks for the help!

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• Unix Permissions issue with users belonging to the same group accessing a folder

  - by TK Kocheran

  I have a folder I'd really like to allow another user on this machine access to. I'm using mt-daapd to serve music to the network, so I'd like to enable the mt-daapd user to access my Music directory, /home/rfkrocktk/Music. The master user is rfkrocktk obviously. I've tried to set all of my permissions properly on the directory, but the mt-daapd user can't acces the files. I created a group called media-users and added both rfkrocktk and mt-daapd to it in order to give mt-daapd permission to simply read all of the files in that directory and subdirectories. If I run id on each of my users, here's what's displayed: $ id rfkrocktk > uid=1000(rfkrocktk) gid=1000(rfkrocktk) groups=1000(rfkrocktk),4(adm),20(dialout),24(cdrom),29(audio),46(plugdev),104(lpadmin),115(admin),120(sambashare),124(vboxusers),1001(jupiter),2002(media-users) $ id mt-daapd > uid=123(mt-daapd) gid=65534(nogroup) groups=65534(nogroup),2002(media-users) It definitely seems that both users are a part of the media-users group, so what could be going wrong? If I run ls -l on the actual Music directory to see its permissions, here's the output: drwxr-Sr-- 201 rfkrocktk media-users 12288 2011-01-13 12:26 Music If I run ls -l on the Music directory to get its children, here's the output: drwxr-Sr-- 3 rfkrocktk media-users 4096 2010-12-20 15:31 2DBoy drwxr-Sr-- 3 rfkrocktk media-users 4096 2010-05-25 12:50 ABBA drwxr-Sr-- 3 rfkrocktk media-users 4096 2009-12-28 15:19 Access Denied drwxr-Sr-- 10 rfkrocktk media-users 4096 2009-12-28 15:19 AC-DC drwxr-Sr-- 3 rfkrocktk media-users 4096 2009-12-28 15:19 Aerosmith drwxr-Sr-- 3 rfkrocktk media-users 4096 2010-06-04 10:45 A Flock of Seagulls drwxr-Sr-- 4 rfkrocktk media-users 4096 2010-05-28 18:13 Alestorm drwxr-Sr-- 3 rfkrocktk media-users 4096 2010-06-22 23:29 Amon Amarth drwxr-Sr-- 5 rfkrocktk media-users 4096 2009-12-28 15:19 Anberlin ... From this, it would seem that I should be able to access the folders from mt-daapd, but I can't. Running sudo -i -u mt-daapd ls -l /home/rfkrocktk/Music displays nothing, indicating to me that for whatever reason, mt-daapd doesn't have access to read the folder. What am I doing wrong?

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• Question about Displaying Documents and the CQWP in MOSS 2007

  - by Psycho Bob

  My organization is in the process of converting our intranet over to a SharePoint solution. Part of this intranet will be the movement and organization of all our internal documents. Currently, we have 11 pages of document links, each with its own subheadings. So far I have it set where each document has a custom field called "Page" with a check box list of all the document pages on the intranet site. On each individual page, I have setup a Content Query Web Part that displays the documents that have the corresponding Page value set (i.e. if a document Page value has been checked for "HR" it will appear on the HR page). The goal of this setup is to allow the nontechnical personal who will be responsible for the maintenance of the documents to be able to upload new documents to the documents list and note on which pages they should appear on without having to manually update the pages themselves. The problem that I am having is that I cannot seem to find a good way to sort the documents into their subheadings once they are on the appropriate page. I could create individual check boxes for each page/subheading combination, but this would create a list of approximately 50-75 items. Does anyone have any ideas as to how I could accomplish this, either via CQWP or by different means? Goals/Requirements of Installation Allow Intranet documents to be maintained by nontechnical personnel Display documents on the appropriate pages without user having to edit actual page or web part Denote document page location using user settable document attributes (if possible) Maintain current intranet organization and workflow Use only one document list without subdirectories NOTE: I am aware that this is not the most efficient or elegant way to do things, but these are the requirements I have been given for the project.

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