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  • Hosting solution for images for website written in PHP

    - by tomaszs
    I've written a website in PHP and it will have ability for users to upload images. My website will have more than 100.000 users. Aprox. 1k users will upload image about 50 KB. And every image will be displayed on this website 5k times so it's transfer of: 1k x 50 KB x 5k = 250 GB per month. So my question is: Do you know any good solution (hosting or CDN network or else) that: will be payed for transfer not space used and no entrance fee will have API to upload images easily with PHP is extremely easy to use will be good for low budget will not require any special, complicated registration and formal things will allow commercial use will allow using this images in website layout ?

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  • How can I create my own form designer?

    - by Carson Myers
    I'm starting my first C# project, and I want to make a "form designer" (like the one in VS). The idea is, there will be a visual form designer with a limited toolbox, which will generate Python code (later more) to create the same form. Problem is, I have no idea how to even get started. First of all, I have the form designer in VS: how do I make a "form-within-a-form?" Next... I have no idea how complicated this is going to be. I suppose I could just make little boxes appear beside each control created on the form when it is clicked, for resizing, and make a textbox appear on it when double clicked or something, to change the text in it... Things like this. So another thing I would like to know is this: I do have programming experience in C and C++, I've done PHP for a number of years and am starting with Python as of recently. I've generated forms dynamically in VB6. Given this experience, am I in way over my head with this project?

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  • website session not set

    - by Matt
    Hello, I'm kind of a website development nub so bear with me. My problem is that the website php session doesn't seem to be set when I log in to my website. After ensuring that the username and password are correct, I have the following simple code: $_SESSION['username'] = $myusername; $_SESSION['password'] = $mypassword; session_start(); Content that should display after logging in is not displayed. Thanks in advance, Matt

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  • How can I load a Class contained in a website from a DLL referenced by that website???

    - by Morgeh
    Ok so this is alittle bit obscure and I'm not sure its the best way of doing what I'm trying to do but here goes. Basically I have a Presentation Layer Dll in my web site which handles the Model View Presenter classes. The presentation layer also handles login for my website and then calls off to a web service. Currently whenever the presentation layer calls to a model it verifies the users details and if they are invalid it calls to a loginHandler which redirects the user to the login page. However I cannot dynamically load a new istance of the Login Page in my website from within my Presentation layer. I've tried to use reflection to dynamically load the class but Since the method call is in the presentation assembly it is only looking within that assembly while the page I want to load is in the website. heres the reflection code that loads the View: public ILoginView LoadView() { string viewName = ConfigurationManager.AppSettings["LoginView"].ToString(); Type type = Type.GetType(viewName, true); object newInstance = Activator.CreateInstance(type); return newInstance as ILoginView; } Anyone got any suggestions on how to search within the website assembly? Ideal I don't want to tie this implementation into the website specifically as the presentation layer is also used in a WPF application.

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  • How to submit the form using JQuery UI?

    - by Vafello
    I have a form in html with a default submit button. After the form is submitted, a php file is run (with action = homelocation). I decided to use JQuery UI dialog to display the form. I have 2 default buttons there - one to save and one to close the dialog. Can anyone tell me how to assign the form submit button action to the JQuery dialog button(i.e. replace the submit button from the form with the one in the dialog)? Here's my code: <div id="userdialog" title="Add"> <form id="add" action="engine.php" method="POST"> <input type="hidden" name="action" value="homelocation" id="action"> <button type="submit">Save this location</button> </form></div> Dialog: $('#userdialog').dialog({ width: 260, position: [250,100], buttons: { "Save": function() { HERE GOES THE REQUIRED FUNCTION $(this).dialog('close'); }, "Don't Save": function() { $(this).dialog("close"); } } });

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  • how to pass values from one page to another on jquery form submit

    - by andy787899
    I'm trying to build a form using php & jquery, but I'm a little confused as to what to do with the jquery portion of it... Basically, when the user submits the first form, I want to direct them to the "next step" form, but I want to retain the values submitted from the first one in a hidden input field... If someone can either show me how or point me to a good tutorial, I'd appreciate it... I don't have any of the php or jquery yet, and this is just a simplified version of the html markup... //first.php <form name="form1" method="post" action="second.php"> <input type="text" name="name" value="" />Name <input type="submit" name="step1" value="Next" /> </form> //second.php <form name="form2" method="post" action="process.php"> <input type="hidden" name="name" value="{$_POST['name']}" /> <input type="text" name="message" value="" />message <input type="submit" name="step2" value="Finish" /> </form>

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  • how to pass values from one page to another on jquery form submit

    - by andy787899
    I'm trying to build a form using php & jquery, but I'm a little confused as to what to do with the jquery portion of it... Basically, when the user submits the first form, I want to direct them to the "next step" form, but I want to retain the values submitted from the first one in a hidden input field... If someone can either show me how or point me to a good tutorial, I'd appreciate it... I don't have any of the php or jquery yet, and this is just a simplified version of the html markup... //first.php <form name="form1" method="post" action="second.php"> <input type="text" name="name" value="" />Name <input type="submit" name="step1" value="Next" /> </form> //second.php <form name="form2" method="post" action="process.php"> <input type="hidden" name="name" value="{$_POST['name']}" /> <input type="text" name="message" value="" />message <input type="submit" name="step2" value="Finish" /> </form>

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  • jQuery capture all changes to named inpt on a form

    - by Brian M. Hunt
    I'm trying to determine when any of a set of named input/select/radio/checked/hidden fields in a form change. In particular, I'd like to capture when any changes are made to fields matching jQuery's selector $("form :input"), and where that input is has a name attribute. However, the form isn't static i.e. some of the fields are dynamically added later. My initial thought is to keep track of when new named elements matching :input are added, and then add an event handler, like this: function on_change() { alert("The form element with name " + $(this).attr("name") + " has changed"); } function reg_new_e_handler(input_element) { input_element.change(on_change); } However, I'm quite hopeful I can avoid this with some jQuery magic. In particular, is there a way to register an event handler in jQuery that would handle input elements that match the following: $("form :input").filter( function () { $(this).attr("name") } ).change(on_change); However, have this event set update whenever new input elements are added. I've thought that it may be possible to capture keyup event on the form node with $("form").keyup(on_change), but I'm not so sure how one could capture change events. I'd also like this to capture keyup events. Thank you for reading. Brian

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  • Django m2m form appearing fields

    - by dana
    I have a classroom application,and a follow relation. Users can follow each other and can create classrooms.When a user creates a classroom, he can invite only the people that are following him. The Classroom model is a m2m to User table. i have in models. py: class Classroom(models.Model): creator = models.ForeignKey(User) classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members") and in models.py of the follow application: class Relations(models.Model): initiated_by = models.ForeignKey(User, editable=False) date_initiated = models.DateTimeField(auto_now=True, editable = False) follow = models.ForeignKey(User, editable = False, related_name = "follow") date_follow = models.DateTimeField(auto_now=True, editable = False) and in views.py of the classroom app: def save_classroom(request, username): if request.method == 'POST': u = User.objects.get(username=username) form = ClassroomForm(request.POST, request.FILES) if form.is_valid(): new_obj = form.save(commit=False) new_obj.creator = request.user r = Relations.objects.filter(initiated_by = request.user) # new_obj.members = new_obj.save() return HttpResponseRedirect('.') else: form = ClassroomForm() return render_to_response('classroom/classroom_form.html', { 'form': form, }, context_instance=RequestContext(request)) i'm using a ModelForm for the classroom form, and the default view, taking in consideration my many to many relation with User table, in the field Members, is a list of all Users in my database. But i only want in that list the users that are in a follow relationship with the logged in user - the one who creates the classroom. How can i do that? Thanks!

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  • form layout in drupal from a module

    - by EricP
    I created my own module called "cssswitch". I'm trying to create my own html layout to display the admin form portion of the module. I understand how to use the hook_form_alter() to modify form elements, but I need to create the entire form layout to make some fields appear next to each other. It seems I need something like the way I have the frontend view of the node displayed with theme_cssswitch_display(), but for the admin part of the node. function cssswitch_form_alter(&$form, $form_state, $form_id) { switch($form_id) { case 'cssswitch_node_form': $form['hour_start']['#prefix'] = '<div class="start-box">'; $form['ampm_start']['#suffix'] = '</div>'; $form['ampm_start']['#attributes'] = array("style" => "border-width:2px;"); break; } } function cssswitch_theme() { return array( 'cssswitch_display' => array( 'arguments' => array('node'), ), ); } // to display the view of the node function theme_cssswitch_display($node) { $output = '<div class="cssswitch-cssfilename">Filename: '. check_plain($node->cssfilename). '</div>'; $output .= '<div class="cssswitch-time_start">Start: '. check_plain($node->hour_start). ':'.check_plain($node->minute_start).' '.check_plain($node->ampm_start).'</div>'; $output .= '<div class="cssswitch-time_end">End: '. check_plain($node->hour_end). ':'.check_plain($node->minute_end).' '.check_plain($node->ampm_end).'</div>'; return $output; } thanks for any help

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  • php, user-uploaded files, version control, and website deployment

    - by user151841
    I have a website that I regularly update the code to. I keep it in version control. When I want to deploy a new version of the site, I do an export and then symlink the served directory name to the directory of the deployment. There is a place where users can upload files, and I noticed once that, after I had deployed a new version, the user files were gone! Of course, I hadn't added them to the repository, and since the served site was from an export, they weren't uploaded into a version-controlled directory anyways. PHP doesn't yet have integrated svn functionality, so I couldn't do much programmatically to user uploaded files. My solution was to create an additional website, files.website.com, which sits in a parallel directory to the served website, and is served out of a directory that is under version control. That way they don't get obliterated when I do an upgrade to the website. From time to time, I manually add uploaded files to the svn project, deleted user-deleted ones, and commit the new version. I'm working on a shell script to run from cron to do this, but it isn't my forte, so it's on the backburner as it's not a pressing need. Is there a better way to do this?

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  • Data Synchronization between Enterprise DataStore and External WebSite DataStore

    - by Yoann. B
    Hi, I've an enterprise database store used by some rich applications and a website with it own database store. Enterprise application work with local data and some of these data (like orders,prices ...) have to be "synchronized" to the web site datastore. On the other side, internet customers are able to edit their profile which have to be "synchronized" to the enterprise datastore too. Basically i need this architecture : WebSite = WebSite Database <= || Internet || <= Enterprise Database <= Rich Applications

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  • Windows Forms: Unable to Click to Focus a MaskedTextBox in a Non TopLevel Form

    - by Overhed
    Like the title says, I've got a Child form being shown with it's TopLevel property set to False and I am unable to click a MaskedTextBox control that it contains (in order to bring focus to it). I can bring focus to it by using TAB on the keyboard though. The child form contains other regular TextBox controls and these I can click to focus with no problems, although they also exhibit some odd behavior: for example if I've got a value in the Textbox and I try to drag-click from the end of the string to the beginning, nothing happens. In fact I can't use my mouse to move the cursor inside the TextBox's text at all (although they keyboard arrow keys work). I'm not too worried about the odd TextBox behavior, but why can't I activate my MaskedTextBox by clicking on it? Below is the code that shows the form: Dim newReportForm As New Form Dim formName As String Dim FullTypeName As String Dim FormInstanceType As Type formName = TreeView1.SelectedNode.Name FullTypeName = Application.ProductName & "." & formName FormInstanceType = Type.GetType(FullTypeName, True, True) newReportForm = CType(Activator.CreateInstance(FormInstanceType), Form) Try newReportForm.Top = CType(SplitContainer1.Panel2.Controls(0), Form).Top + 25 newReportForm.Left = CType(SplitContainer1.Panel2.Controls(0), Form).Left + 25 Catch End Try newReportForm.TopLevel = False newReportForm.Parent = SplitContainer1.Panel2 newReportForm.BringToFront() newReportForm.Show()

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  • Error on opening ASP website

    - by user288604
    Dear all We changed the server of our ASP website and in new setting browsing the website returns this error: msxml3.dll error '80072ee2' The operation timed out /error404.asp, line 41 This is lines that I think returns error: Set XML=Server.CreateObject("Msxml2.ServerXMLHTTP.3.0") XML.SetOption 2,13056 XML.SetTimeouts 90000, 90000, 90000, 90000 XML.Open "POST", website &"/catalog/page.asp?id="& R("CTLMtree_id") &"&rnd="& rnd(), False XML.Send(Request.Form) Response.Write XML.ResponseTExt Set XML=Nothing

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  • Processing XML form input in ASP

    - by Omar Kooheji
    I'm maintaining a legacy application which consists of some ASP.Net pages with c# code behinds and some asp pages. I need to change the way the application accepts it's input from reading a set of parameters from some form fields to reading in one form field which contains contains some XML and parsing to get the parameters out. I've written a C# class that takes an The NameValueCollection from the C# HttpRequest's Form Element. Like so NameValueCollection form = Request.Form; Dictionary<string, string> fieldDictionary = RequestDataExtractor.BuildFieldDictionary(form); The code in the class looks for a particular parameter and if it's there processes the XML and outputs a Dictionary, if its not there it just cycles through the Form parameters and puts them all into the dictionary (Allowing the old method to still work) How would I do this in ASP? Can I use my same class, or a modified version of it? or do I have to write some new code to get this working? If I have to write ASP code Whats the best way to process the XML in ASP? Sorry if this seems like a stupid question but I know next to nothing about ASP and VB.

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  • Submit form with JS

    - by Thomas
    Im working with a shopping cart plugin and that uses a basic form on the product page to submit values like price, product name, etc.. The problem is that the plugin uses a standard submit button to send the values and I would like to replace said button with a prettier custom jquery rollover. In order to make this happen I used some JS and tossed a link around my custom submit button: <a href="#" onclick="document.forms[0].submit()" value="Add to Cart" onsubmit="return ReadForm(this, true);"> <img class="fade" src="style/img/add_btn.jpg" style="background: url(style/img/add_ro.png);" alt=""/> </a> The form submits and the user is redirected to the homepage but the data in the form doesn't seem to get submitted and the product never gets added to the 'cart' page. I suspect that the form is getting submitted but I am failing to fire some additional JS function that submits the data. The plugin adds some JS to the top of the page: <!-- // function ReadForm (obj1, tst) { // Read the user form var i,j,pos; val_total="";val_combo=""; for (i=0; i<obj1.length; i++) { // run entire form obj = obj1.elements[i]; // a form element if (obj.type == "select-one") { // just selects if (obj.name == "quantity" || obj.name == "amount") continue; pos = obj.selectedIndex; // which option selected val = obj.options[pos].value; // selected value val_combo = val_combo + "(" + val + ")"; } } // Now summarize everything we have processed above val_total = obj1.product_tmp.value + val_combo; obj1.product.value = val_total; } //--> If you want to check out the the site in question, take a look here and click 'add to cart button': http://hardtopdepot.com/?p=34 You can see the cart at the top: http://hardtopdepot.com/?page_id=50 Any help would be super appreciated- thanks!

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  • sharepoint website error 403

    - by sinisana
    I just created a web application on Sharepoint and followed all the instructions as given. When i created web app, it created the Database on SQL and the new website on IIS. But when i goto browse that website, It gives me the following error - The website declined to show this webpage HTTP 403 Most likely causes: •This website requires you to log in. I dont have anywhere login required. What am i doing wrong? Anyone have this problem please help me. Thanks

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  • reply to a comment via email and directly post it on the website commenting system

    - by Gaurav Sharma
    Hello Everybody, I have developed a website using PHP and MYSQL. The website has a commenting system through which registered users of the website can post comments on the feedback posted by different users. When a comment is posted for a feedback an email is sent to the user who posted that feedback notifying him of new comments on his feedback. Now what I want is that a feedback owner should be able to post a new comment in response to that comment by simply replying to the email that has been sent by the website. I hope I was able to explain my query properly. If it needs any improvement in explanation, I would be glad to know and make changes accordingly Thanks

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  • host MVC app inside a website

    - by Nishant
    I have a website (not a web application- in visual studio you get two options-create a website/project) running on IIS 6.0. Now I want to develop few features in MVC architecture. So I created one MVC application in visual studio and everything is working fine on localhost as a separate application. Now I want to host this MVC app also inside the website I have already deployed. I created a virtual directory(MVCDir) inside the default website in IIS 6.0. The global.asax file which was in root folder I added the routing function- Shared Sub RegisterRoutes(ByVal routes As RouteCollection) routes.Ignore("{resource}.axd/{*pathInfo}") routes.Ignore("{resource}.aspx/{*pathInfo}") routes.MapPageRoute("Default4", "{controller}/{action}/{id}", "~/MVCDir", False, New RouteValueDictionary(New With {.controller = "Home", .action = "Index", .id = Mvc.UrlParameter.Optional})) End Sub * NOTE- If I write routes.ignoreRoute instead of routes,ignore it says- IgnoreRoute is not a member of System.Web.RoutingCollection* I called this routing function inside application_start function now when I run domain.com/home/index How to solve this problem? it says resource not found

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  • Working with extra fields in an Inline form - save_model, save_formset, can't make sense of the diff

    - by magicrebirth
    Suppose I am in the usual situation where there're extra fields in the many2many relationship: class Person(models.Model): name = models.CharField(max_length=128) class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(Person, through='Membership') class Membership(models.Model): person = models.ForeignKey(Person) group = models.ForeignKey(Group) date_joined = models.DateField() invite_reason = models.CharField(max_length=64) # other models which are unrelated to the ones above.. class Trip(models.Model): placeVisited = models.ForeignKey(Place) visitor = models.ForeignKey(Person) pleasuretrip = models.Boolean() class Place(models.Model): name = models.CharField(max_length=128) I want to add some extra fields in the Membership form that gets displayed through the Inline. These fields basically are a shortcut to the instantiation of another model (Trip). Trip can have its own admin views, but these shortcuts are needed because when my project partners are entering 'Membership' data in the system they happen to have also the 'Trip' information handy (and also because some of the info in Membership can just be copied over to Trip etc. etc.). So all I want to have is two extra fields in the Membership Inline - placeVisited and pleasuretrip - which together with the Person instance will let me instantiate the Trip model in the background... I found out I can easily add extra fields to the inline view by defining my own form. But once the data have been entered, how and when to reference to them in order to perform the save operations I need to do? class MyForm(forms.ModelForm): place = forms.ModelChoiceField(required=False, queryset=Place.objects.all(), label="place",) pleasuretrip = forms.BooleanField(required=False, label="...") class MembershipInline(admin.TabularInline): model = Membership form = MyForm def save_model(self, request, obj, form, change): place = form.place pleasuretrip = form.pleasuretrip person = form.person .... # now I can create Trip instances with those data .... obj.save() class GroupAdmin(admin.ModelAdmin): model = Group .... inlines = (MembershipInline,) This doesn't seem to work... I'm also a bit puzzled by the save_formset method... maybe is that the one I should be using? Many thanks in advance for the help!!!!

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  • Need help on how to begin learning website development

    - by Golfy
    OK for the past 10 days I have been trying to figure out where to begin learning website development a dynamic one, So far everyone told me you should start with computer science and I am like What the @#$% how am I suppose to learn computer science without going to school and get a degree but I don't want a degree I just want to learn how to devlope websites. So now I am here and confused about how to put together a website. I get HTML and CSS but still have some problems designing the site now on the other had I am having trouble trying to figure out how php and database mysql is used to put together a website. I have seen videos from lynda.com and still have no Idea after I have watched the video the basic one, one that teach you the Variables, Loops, Strings ext... ok than what happens, how do you build the website with it, that is the question I am real not understand the answer to. Any help will be appreciated.

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  • I am not able to update form data to MySQL using PHP and jQuery

    - by Jimson Jose
    My problem is that I am unable to update the values entered in the form. I have attached all the files. I'm using MYSQL database to fetch data. What happens is that I'm able to add and delete records from form using jQuery and PHP scripts to MYSQL database, but I am not able to update data which was retrieved from the database. The file structure is as follows: index.php is a file with jQuery functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refreshing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form) - Delete is an function called from index.php to delete record from MySQL database (function calling delete.php works fine) - Update is an function called from index.php to update data using update-form.php by retriving specific record from MySQL table, (works fine) Problem lies in updating data from update-form.php to update.php (in which update query is written for MySQL) I have tried in many ways - at last I had figured out that data is not being transferred from update-form.php to update.php; there is a small problem in jQuery AJAX function where it is not transferring data to update.php page. Something is missing in calling update.php page it is not entering into that page. I am new bee in programming. I had collected this script from many forums and made this one. So I was limited in solving this problem. I came to know that this is good platform for me and many where we get a help to create new things. Please find the link below to download all files which is of 35kb (virus free assurance): download mysmallform files in ZIPped format, including mysql query

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  • website to be displayed in browser

    - by hardik
    i have a button called "Visit Website" If Visit Website is clicked then the website supplied will be opened in the browser. My requirement is, when closing the browser the user will be brought back to the same screen i want to do it in this way please guide me how i can do that

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