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  • iPhone/Objective-C struct question my own CGRectZero

    - by Mark
    I am designing a Padding struct as follows: /* Padding. */ struct CGPadding { CGFloat left; CGFloat top; CGFloat right; CGFloat bottom; }; typedef struct CGPadding CGPadding; CG_INLINE CGPadding CGPaddingMake(CGFloat left, CGFloat top, CGFloat right, CGFloat bottom) { CGPadding p; p.left = left; p.top = top; p.right = right; p.bottom = bottom; return p; } This all works perfectly well, the problem is how can I create a const CGPadding CGPaddingZero? If I do like this: const CGPadding CGPaddingZero = (CGPadding){0.0, 0.0, 0.0, 0.0}; It doesnt work. So what am I doing wrong?

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  • What Is the Experience Revolution – and Why Does it Matter?

    - by Charles Knapp
    Customer experience is how your customer perceives the sum of their interactions with your organization throughout their buying, service delivery, and ownership experiences. In our highly connected online, phone, social, and mobile interactions, it’s easy to lose a dissatisfied customer – who can readily dissuade future customers. Nevertheless, great brand experiences still deliver top margins and low-cost repeat business. The Experience Revolution seamlessly connects customer-facing interactions with employee-facing CRM transactions. While your organization has invested in some of these capabilities, how well do the pieces work for your customers? Is it time for your organization to join the Experience Revolution? We invite you to join Oracle President Mark Hurd for an incredible, educational evening on June 25, from 6:00 – 9:00 p.m. in New York City.  Attend to see and learn: What leading brands do to win over customers How to unlock the value of customer experiences The bottom-line effect of great experiences Why doing nothing is not an option

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  • Webcast on using live upgrade

    - by Owen Allen
    Leon Shaner is doing a webcast next week, on Thursday Nov. 6 at 11 am EST, about updating Oracle Solaris in Ops Center using Live Upgrade. He's also written a blog post over on the Enterprise Manager blog about using Live Upgrade and and Oracle Solaris 11 Boot Environments, which goes into a lot of detail about the benefits, requirements, setup, and use of these features. To join the webconference, when it rolls around: Go to https://oracleconferencing.webex.com/oracleconferencing/j.php?ED=209834092&UID=1512097467&PW=NMTJjY2NkZjg0&RT=MiMxMQ%3D%3D If requested, enter your name and email address. If a password is required, enter the meeting password: oracle123 Click Join. To dial into the conference, dial 1-866-682-4770 (US/Canada) or go here for the numbers in other countries. The conference code is 7629343# and the security code is 7777#.

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  • CSS Position:Absolute with relative adjustment

    - by Gidiyo
    I am trying to do a vertical dropdown menu. This is my code .menu li:hover>ul{ position:absolute; display:inline; left:120px; top:100px;} I use position: Absolute to remove the sub-menu from the table, once the menu gets hovered. It appears that, if I do not indicate top or left property. The sub-menu will displayed relatively. Now I need to adjust the position relatively but seems that only the left property works. So my sub-menu left position is 120px relatively away from its original position. But the top is 100px away from the top of the window, rather then to the original position. How do I move the list up relative to it original position? I cant use position:relative because I need the sub-menu to be remove from the table.

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  • CSS Positioning

    - by Davey
    Trying to mess with this wordpress theme and can't figure out why the sidebar is stacking underneath the content block. Any help would be very appreciated. http://www.buffalostreetbooks.com/events CSS: body { font-family: Arial, Helvetica, Verdana, Sans-serif; font-size: 10pt; background-color: #692022; background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/repeatflower.png"); } body,h1#blog-title { margin: 0; padding: 0; } a { color: blue; } a:hover { color: #FF8C00; } a img { border: 0 none; } #wrapper { width: 960px; margin: 0 auto; background-color: #F4FBF4; border-left: 1px solid #ccc; border-right: 1px solid #ccc; } #header { background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/headertime.png"); width:768px; height: 200px; } #inner-header { padding: 125px 1em 0; } h1#blog-title { font-size: 2em; } h1#blog-title a { color: #800000; } .entry-title a { color: #CD853F; } h1#blog-title a, .entry-title a, #footer a { text-decoration: none; } h1#blog-title a:hover, .entry-title a:hover, #footer a:hover { text-decoration: underline; } div.skip-link { display: none; } #menu { border-bottom: 1px solid #ccc; } #menu a { color: #000; } #menu a:hover { text-decoration: underline; } #menu li.current_page_item a, #menu li.current_page_item a:hover { background-color: #DFC28B; text-decoration: none; } #content { padding: 1em; width:600px; } .entry-title { font-size: 1.5em; margin: 1em 0 0 0; } abbr.published { color: #666; border: 0 none; } .entry-meta, .entry-date { color: #666; } #comments-list .avatar { float: left; margin-right: 1em; } #comments-list .n { font-weight: bold; } .entry-meta, .comment-meta { font-style: italic; } #comments-list p { clear: left; } #primary { padding-left: 1em; font-size: 0.9em; border-left: 1px solid #ccc; border-bottom: 1px solid #ccc; background-color: #FFFACD; } #footer { text-align: center; font-size: 0.8em; border-top: 1px solid #ccc; border-bottom: 1px solid #ccc; margin-bottom: 1em; } #inner-footer { padding: 1em 0; } .entry-meta, .entry-meta a, .comment-meta, .comment-meta a, .sidebar, .sidebar a, #footer, #footer a { color: #666; } /* LAYOUT: Two-Column (Right) DESCRIPTION: Two-column fluid layout with one sidebars right of content */ div#container { margin:0 0 0 0; width:960px; height:100%; } div#content { margin:0 0 0 0; } div.sidebar { overflow:hidden; width:280px; min-height:500px; clear:both; } div#secondary { clear:right; } div#footer { clear:both; width:100%; } /* Just some example content */ div#menu { height:2em; width:100%; } div#menu ul,div#menu ul ul { line-height:2em; list-style:none; margin:0; padding:0; } div#menu ul a { display:block; margin-right:1em; padding:0 0.5em; text-decoration:none; } div#menu ul ul ul a { font-style:italic; } div#menu ul li ul { left:-999em; position:absolute; } div#menu ul li:hover ul { left:auto; } .entry-title,.entry-meta { clear:both; } div#primary { } form#commentform .form-label { margin:1em 0 0; } form#commentform span.required { background:#fff; color:#c30; } form#commentform,form#commentform p { padding:0; } input#author,input#email,input#url,textarea#comme nt { padding:0.2em; } div.comments ol li { margin:0 0 3.5em; } textarea#comment { height:13em; margin:0 0 0.5em; overflow:auto; width:66%; } .alignright,img.alignright{ float:right; margin:1em 0 0 1em; } .alignleft,img.alignleft{ float:left; margin:1em 1em 0 0; } .aligncenter,img.aligncenter{ display:block; margin:1em auto; text-align:center; } div.gallery { clear:both; height:180px; margin:1em 0; width:100%; } p.wp-caption-text{ font-style:italic; } div.gallery dl{ margin:1em auto; overflow:hidden; text-align:center; } div.gallery dl.gallery-columns-1 { width:100%; } div.gallery dl.gallery-columns-2 { width:49%; } div.gallery dl.gallery-columns-3 { width:33%; } div.gallery dl.gallery-columns-4 { width:24%; } div.gallery dl.gallery-columns-5 { width:19%; } div#nav-above { margin-bottom:1em; } div#nav-below { margin-top:1em; } div#nav-images { height:150px; margin:1em 0; } div.navigation { height:1.25em; } div.navigation div.nav-next { float:right; text-align:right; } div.sidebar h3 { font-size:1.2em; } div.sidebar input#s { width:7em; } div.sidebar li { list-style:none; margin:0 0 2em; } div.sidebar li form { margin:0.2em 0 0; padding:0; } div.sidebar ul ul { margin:0 0 0 2em; } div.sidebar ul ul li { list-style:disc; margin:0; } div.sidebar ul ul ul { margin:0 0 0 0.5em; } div.sidebar ul ul ul li { list-style:circle; } div#menu ul li,div.gallery dl,div.navigation div.nav-previous { float:left; } input#author,input#email,input#url,div.navigation div { width:50%; } div.gallery *,div.sidebar div,div.sidebar h3,div.sidebar ul { margin:0; padding:0; }

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  • Blackberry (Java) - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • problem in below table:i had table inside table .my inner table contains some text.

    - by Ayyappan.Anbalagan
    Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

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  • Giving 'TemplateError' can't convert String into Integer

    - by Gagan
    Hi, I recently transfered my app from Rails2 to Rails3. The code in 'app/views/distribution/index.html.erb' is like :- <div style="padding-bottom:10px; padding-left:0px;float:left;display:<%= (!session[:album][@artist.id.to_s].empty? && !session[:album][@artist.id.to_s].nil?)?'block' : 'none' %>" id = "make_payment_enabled"> <%= link_to 'Make Payments',{:action => 'pay', :album=>@album.id}, :class => "button" %> </div> It's giving me TemplateError on line :- <div style="padding-bottom:10px; padding-left:0px;float:left;display:<%= (!session[:album][@artist.id.to_s].empty? && !session[:album][@artist.id.to_s].nil?)?'block' : 'none' %>" id = "make_payment_enabled"> How to resolve the problem ?

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  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

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  • Container div ignores height of floated elements

    - by Thomas
    Ok, so this seems like a really silly problem but I can't get my container div to inherit the height of the floated elements inside of it. Since I need to center the container div, I can't use float to fix this problem. Here is my css: #container { margin: 0 auto; width: 1000px; border-left: 1px solid #f1f1f1; border-right: 1px solid #f1f1f1; border-bottom: 1px solid #f1f1f1; } #focus { padding-left: 23px; width: 977px; padding-top: 20px; padding-bottom: 23px; border-bottom: 1px solid #f1f1f1; float: left; } .rslider { float: left; width: 600px; margin-left: 15px; } .welcome { float: left; width: 300px; } Html: <div id="container"> <div id="logo_block"> <a href="#"><img src="img/logo.jpg" alt="" /></a> </div> <div id="focus"> <div class="welcome"> <h1>All About This Page</h1> <p>Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem. Nulla consequat massa quis enim. Donec pede justo, fringilla vel, liquet nec, vulputate eget, arcu. In enim justo, rhoncus ut, imperdiet a, venenatis vitae, justo. Nullam dictum felis eu pede mollis pretium.</p> </div> <div class="rslider"> <img src="img/slider_image.jpg"> </div> </div> </div> Any ideas?

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  • convert following string into array using explode()

    - by Deepali
    HI, I have a string: NEW ALPINESTAR?S SMX PLUS WHITE MOTORCYCLE BOOTS! 44/9.5$349.95 Time Left 1h 2m NEW AGV BLADE FLAT MATTE WHITE LARGE/LG HELMET$75.53Time Left 1h 2m I want result in array like this: Productname Price time NEW ALPINESTAR?S SMX PLUS WHITE MOTORCYCLE BOOTS! 44/9.5 $349.95 Time Left 1h 2m

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • OSCON: Java and a Nice Discount

    - by Tori Wieldt
    Now in its 14th year, OSCON, O'Reilly's annual open source conference, will once again be in Portland, OR on July 16-20, 2012.  Join the world’s open source pioneers, builders, and innovators at the Oregon Convention Center for five intense days to learn about open development, challenge your assumptions, and fire up your brain.With 200+ speakers, 18 tracks, hundreds of technologies, and over 3,000 hackers in attendance, it's a place to learn and network. You’ll find practical tutorials, inspirational keynotes, and a wealth of information on open source languages, platforms, and development. OSCON includes whole track devoted to Java & the JVM, and the list of speakers is impressive. OSCON is where the serious thinkers and doers—and their favorite technologies—converge. And when the day’s sessions are over, join people just like you for some serious fun. Thanks to Java Magazine (you have subscribed to Java Magazine, right? If not, get your free digital subscription now!), you can register for OSCON and save 20% with code JAVAMAG.

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  • CSS Horizontal sub menu - IE 6,7 both dont working, tried with whatever hover.

    - by SHAKTI
    I'm not expert about css menus. But I know basic system to make css menu. I used this system before and works, but this time it is not working. The site is http://www.uniethos.com. Please check this site This menu works with all other latest Browsers. But not with IE 6 & 7. I know IE6 don't support hover except anchor. So before I was using Whatever Hover. But this time it is not working and even with IE7. I don't know why its happening. May be there could be some problem with my css. Please check the css. If you don't have IE 6 or 7 installed you can run one from http://spoon.net/browsers/. Require to install one plugin. The CSS I'm using for the menu is .glossymenu{ background: #B4B3B3; height: 30px; width: 100%; padding: 0; margin: 0; display:inline-block; position:relative; } .glossymenu ul { list-style: none; padding: 0px; margin: 0; padding-left: 0px; } .glossymenu li ul { display:none; position:absolute; width: 80%; top:30px; left:0px; background-color:#5B0C10; border:0px; z-index: 99; } .glossymenu li li a { padding: 0px 10px 0px 10px; } .glossymenu li li a:hover { background : #871016; } .glossymenu li{ float:left; padding: 0; } .glossymenu li a{ float: left; display:block; position:relative; color:#FFF; text-decoration: none; font-family: sans-serif; font-size: 13px; font-weight: bold; padding:0 0 0 16px; /*Padding to accomodate left tab image. Do not change*/ height: 30px; line-height: 30px; text-align: center; cursor: pointer; } .glossymenu li a b{ float: left; display: block; padding: 0 24px 0 8px; /*Padding of menu items*/ } .glossymenu li.current a, .glossymenu li a:hover{ color: #FFF; background: #5B0C10; background-position: left; text-decoration: none; } .glossymenu li a:visited{ text-decoration: none; } .glossymenu ul li:hover ul { display: block; }

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  • More useful Sql Server Serivce Broker Queries

    - by ChrisD
    SELECT 'Checking Broker Service Status...' IF (select Top 1 is_broker_enabled from sys.databases where name = 'NWMESSAGE')=1     SELECT ' Broker Service IS Enabled'  -- Should return a 1. ELSE     SELECT '** Broker Service IS DISABLED ***' /* If Is_Broker_enabled returns 0, uncomment and run this code ALTER DATABASE NWMESSAGE SET SINGLE_USER WITH ROLLBACK IMMEDIATE GO Alter Database NWMESSAGE Set enable_broker GO ALTER DATABASE NWDataChannel SET MULTI_USER GO */ SELECT 'Checking For Disabled Queues....' -- ensure the queues are enabled --  0 indicates the queue is disabled. Select '** Receive Queue Disabled: '+name from sys.service_queues where is_receive_enabled = 0 --select [name], is_receive_enabled from sys.service_queues; /*If the queue is disabled, to enable it alter queue QUEUENAME with status=on; – replace QUEUENAME with the name of your queue */ -- Get General information about the queues --select * from sys.service_queues -- Get the message counts in each queue SELECT 'Checking Message Count for each Queue...' select q.name, p.rows from sys.objects as o join sys.partitions as p on p.object_id = o.object_id join sys.objects as q on o.parent_object_id = q.object_id join sys.service_queues sq on sq.name = q.name where p.index_id = 1 -- Ensure all the queue activiation sprocs are present SELECT 'Checking for Activation Stored Procedures....' SELECT  '** Missing Procedure:  '+q.name  From sys.service_queues q Where NOT Exists(Select * from sysobjects where xtype='p' and name='activation_'+q.name) and q.activation_procedure is not null DECLARE @sprocs Table (Name Varchar(2000)) Insert into @sprocs Values ('Echo') Insert into @sprocs Values ('HTTP_POST') Insert into @sprocs Values ('InitializeRecipients') Insert into @sprocs Values ('sp_EnableRecipient') Insert into @sprocs Values ('sp_ProcessReceivedMessage') Insert into @sprocs Values ('sp_SendXmlMessage') SELECT 'Checking for required stored procedures...' SELECT  '** Missing Procedure:  '+s.name  From @sprocs s Where NOT Exists(Select * from sysobjects where xtype='p' and name=s.name) GO -- Check the services Select 'Checking Recipient Message Services...' Select '** Missing Message Service:' + r.RecipientName +'MessageService' From Recipient r Where not exists (Select * from sys.services s where  s.name  COLLATE SQL_Latin1_General_CP1_CI_AS= r.RecipientName+'MessageService') DECLARE @svcs Table (Name Varchar(2000)) Insert into @svcs Values ('XmlMessageSendingService') SELECT  '** Missing Service:  '+s.name  From @svcs s Where NOT Exists(Select * from sys.services where name=s.name COLLATE SQL_Latin1_General_CP1_CI_AS) GO /*** To Test a message send Run: sp_SendXmlMessage  'TSQLTEST', 'CommerceEngine','<Root><Text>Test</Text></Root>' */ Select CAST(message_body as XML) as xml, * From XmlMessageSendingQueue /*** clean out all queues declare @handle uniqueidentifier declare conv cursor for   select conversation_handle from sys.conversation_endpoints open conv fetch next from conv into @handle while @@FETCH_STATUS = 0 Begin    END Conversation @handle with cleanup    fetch next from conv into @handle End close conv deallocate conv ***********************

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  • Reconciling a new BindingList into a master BindingList using LINQ

    - by Neo
    I have a seemingly simple problem whereby I wish to reconcile two lists so that an 'old' master list is updated by a 'new' list containing updated elements. Elements are denoted by a key property. These are my requirements: All elements in either list that have the same key results in an assignment of that element from the 'new' list over the original element in the 'old' list only if any properties have changed. Any elements in the 'new' list that have keys not in the 'old' list will be added to the 'old' list. Any elements in the 'old' list that have keys not in the 'new' list will be removed from the 'old' list. I found an equivalent problem here - http://stackoverflow.com/questions/161432/ - but it hasn't really been answered properly. So, I came up with an algorithm to iterate through the old and new lists and perform the reconciliation as per the above. Before anyone asks why I'm not just replacing the old list object with the new list object in its entirety, it's for presentation purposes - this is a BindingList bound to a grid on a GUI and I need to prevent refresh artifacts such as blinking, scrollbars moving, etc. So the list object must remain the same, only its updated elements changed. Another thing to note is that the objects in the 'new' list, even if the key is the same and all the properties are the same, are completely different instances to the equivalent objects in the 'old' list, so copying references is not an option. Below is what I've come up with so far - it's a generic extension method for a BindingList. I've put comments in to demonstrate what I'm trying to do. public static class BindingListExtension { public static void Reconcile<T>(this BindingList<T> left, BindingList<T> right, string key) { PropertyInfo piKey = typeof(T).GetProperty(key); // Go through each item in the new list in order to find all updated and new elements foreach (T newObj in right) { // First, find an object in the new list that shares its key with an object in the old list T oldObj = left.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(newObj, null))); if (oldObj != null) { // An object in each list was found with the same key, so now check to see if any properties have changed and // if any have, then assign the object from the new list over the top of the equivalent element in the old list foreach (PropertyInfo pi in typeof(T).GetProperties()) { if (!pi.GetValue(oldObj, null).Equals(pi.GetValue(newObj, null))) { left[left.IndexOf(oldObj)] = newObj; break; } } } else { // The object in the new list is brand new (has a new key), so add it to the old list left.Add(newObj); } } // Now, go through each item in the old list to find all elements with keys no longer in the new list foreach (T oldObj in left) { // Look for an element in the new list with a key matching an element in the old list if (right.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(oldObj, null))) == null) { // A matching element cannot be found in the new list, so remove the item from the old list left.Remove(oldObj); } } } } It can be called like this: _oldBindingList.Reconcile(newBindingList, "MyKey") However, I'm looking for perhaps a method of doing the same using LINQ type methods such as GroupJoin<, Join<, Select<, SelectMany<, Intersect<, etc. So far, the problem I've had is that each of these LINQ type methods result in brand new intermediary lists (as a return value) and really, I only want to modify the existing list for all the above reasons. If anyone can help with this, would be most appreciated. If not, no worries, the above method (as it were) will suffice for now. Thanks, Jason

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  • Blackberry app development - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • How to bring the parent element with floated child elements to the center of the document?

    - by Starx
    I have organized a menu. Its HTML is as follows: <ul class="topmenu"> <li><a href="sample.html">Text 1</a></li> <li><a href="sample.html">Text 2</a></li> <li><a href="sample.html">Text 3</a></li> <li><a href="sample.html">Text 4</a></li> <ul> This is a horizontal menu, so I have floated the list items to left to appear them in a horizontal line. I could have used display:inline to appear them in a single line, but since IE does not support it and I don't know any other way to do so, I used float:left;. It's css is: .topmenu { list-style:none; margin:0; padding:0; } .topmenu li { float:left; } This brings the menu in a perfect horizontal line, but the entire list is floated to the left. I want to bring the .topmenu to appear in the center of the document and keep the listitem inside it floated towards the left. I found that this is achievable by defining width property of the .topmenu, but I dont want to fix its width as the list-items are dynamically generated and thus could increase and decrease. Any one know of any solution?

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  • How do I set command line mode vga=788 permanently?

    - by George
    I have a problem that is not of easy resolution, happen to tell... I have Installed Ubuntu 10.10 Server. I want to join to the system way vga=788, into the grub it changes without any problem editing the file grub.cfg, the problem is that editing the above mentioned file I join to the system way vga=788 (800x600) and then command line puts itself in way vga=792 (1280x1024). Is there any way of changing this configuration so that it is always vga=788? tanks. sorry for my english :D

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  • Reading JSON with Javascript/jQuery

    - by Josephine
    I'm building a game in javascript/html5 and I'm trying to build a database of locked doors in a maze that can be loaded from and overwritten to throughout gameplay. I've found a large number of tutorials online, but nothing is working. I was wondering if someone could look at what I'm trying and let me know what I'm doing wrong. My JSON file looks like this: { "doors": [ {"left":true, "right":false, "bottom":false}, {"left":false, "right":false, "bottom":false}, {"right":false, "bottom":false, "top":false}, {"left":false, "right":false, "top":false} ] } I want to build the HTML page so that when a player collides with a door it checks if its locked or not like: if (player.x < leftDoor.x + leftDoor.width && player.x + player.width > leftDoor.x && player.y < leftDoor.y + leftDoor.height && player.y + player.height > leftDoor.y) { if(doors[0].left == true) alert("door is locked"); else window.location = ( "2.html?p1="); } However I'm having trouble reading from the JSON file itself. I've tried things like: function loadJson() { $(document).ready(function() { $.getJSON('info.json', function(doors) { alert(doors[0].left); }); }); } But nothing happens, and I need to be able to access the information in the HTML as well. I'd rather use jQuery, but I'm not opposed to straight JS if it works. I've been trying to do this for ages and I'm getting absolutely no where. If someone could help that would be amazing. Thanks!

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  • How do I remove the leaves of a binary tree?

    - by flopex
    I'm trying to remove all of the leaves. I know that leaves have no children, this is what I have so far. public void removeLeaves(BinaryTree n){ if (n.left == null && n.right == null){ n = null; } if (n.left != null) removeLeaves(n.left); if (n.right != null) removeLeaves(n.right); }

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  • Return parent of node in Binary Tree

    - by user188995
    I'm writing a code to return the parent of any node, but I'm getting stuck. I don't want to use any predefined ADTs. //Assume that nodes are represented by numbers from 1...n where 1=root and even //nos.=left child and odd nos=right child. public int parent(Node node){ if (node % 2 == 0){ if (root.left==node) return root; else return parent(root.left); } //same case for right } But this program is not working and giving wrong results. My basic algorithm is that the program starts from the root checks if it is on left or on the right. If it's the child or if the node that was queried else, recurses it with the child.

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  • Please help fix and optimize this query

    - by user607217
    I am working on a system to find potential duplicates in our customers table (SQL 2005). I am using the built-in SOUNDEX value that our software computes when customers are added/updated, but I also implemented the double metaphone algorithm for better matching. This is the most-nested query I have created, and I can't help but think there is a better way to do it and I'd like to learn. In the inner-most query I am joining the customer table to the metaphone table I created, then finding customers that have identical pKey (primary phonetic key). I take that, union that with customers that have matching soundex values, and then proceed to score those matches with various text similarity functions. This is currently working, but I would also like to add a union of customers whose aKey (alternate phonetic key) match. This would be identical to "QUERY A" except to substitute on (c1Akey = c2Akey) for the join. However, when I attempt to include that, I get errors when I try to execute my query. Here is the code: --Create aggregate ranking select c1Name, c2Name, nDiff, c1Addr, c2Addr, aDiff, c1SSN, c2SSN, sDiff, c1DOB, c2DOB, dDiff, nDiff+aDiff+dDiff+sDiff as Score ,(sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 as [Rank] FROM ( --Create match scores for different fields SELECT c1Name, c2Name, c1Addr, c2Addr, c1SSN, c2SSN, c1LTD, c2LTD, c1DOB, c2DOB, dbo.Jaro(c1name, c2name) AS nDiff, dbo.JaroWinkler(c1addr, c2addr) AS aDiff, CASE WHEN c1dob = '1901-01-01' OR c2dob = '1901-01-01' OR c1dob = '1800-01-01' OR c2dob = '1800-01-01' THEN .5 ELSE dbo.SmithWaterman(c1dob, c2dob) END AS dDiff, CASE WHEN c1ssn = '000-00-0000' OR c2ssn = '000-00-0000' THEN .5 ELSE dbo.Jaro(c1ssn, c2ssn) END AS sDiff FROM -- Generate list of possible matches based on multiple phonetic matching fields ( select * from -- List of similar names from pKey field of ##Metaphone table --QUERY A BEGIN (select customers.custno as c1Custno, name as c1Name, haddr as c1Addr, ssn as c1SSN, lasttripdate as c1LTD, dob as c1DOB, soundex as c1Soundex, pkey as c1Pkey, akey as c1Akey from Customers WITH (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c1 JOIN (select customers.custno as c2Custno, name as c2Name, haddr as c2Addr, ssn as c2SSN, lasttripdate as c2LTD, dob as c2DOB, soundex as c2Soundex, pkey as c2Pkey, akey as c2Akey from Customers with (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c2 on (c1Pkey = c2Pkey) and (c1Custno < c2Custno) WHERE (c1Name <> 'PARENT, GUARDIAN') and c1soundex != c2soundex --QUERY A END union --List of similar names from pregenerated SOUNDEX field (select t1.custno, t1.name, t1.haddr, t1.ssn, t1.lasttripdate, t1.dob, t1.[soundex], 0, 0, t2.custno, t2.name, t2.haddr, t2.ssn, t2.lasttripdate, t2.dob, t2.[soundex], 0, 0 from Customers t1 WITH (nolock) join customers t2 with (nolock) on t1.[soundex] = t2.[soundex] and t1.custno < t2.custno where (t1.name <> 'PARENT, GUARDIAN')) ) as a ) as b where (sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 >= 7.5 order by [rank] desc, score desc Previously, I was using joins such as on c1.pkey = c2.pkey or c1.akey = c2.akey or c1.soundex = c2.soundex but the performance was horrendous, and using unions seems to be working a lot better. Out of 103K customers, tt is currently generating a list of 8.5M potential matches (based on the phonetic codes) in 2.25 minutes, and then taking another 2 to score, rank and filter those down to about 3000. So I am happy with the performance, I just can't help but think there is a better way to structure this, and I need help adding the extra union condition. Thanks!

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  • How to do word wrapping.

    - by Talha Bin Shakir
    Hi, I have created a table in PHP but the cells size is not fixed it expends when the input is long. Here is the Code. echo "<div style=\"overflow-y: scroll; white-space: nowrap; height: 190px;\">\n"; echo "<table cellspacing=\"1\" cellpadding=\"1\" align=\"center\" width=\"100%\" id=\"clients\">\n"; echo "<tr bgcolor=\"2b2d5d\">\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">&nbsp;</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Name</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Address</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Phone</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Fax</th>\n"; I want to fixed the cells width please need help. Thanks

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  • WCF service is not getting called

    - by Cheranga
    I have a web solution and I have a WCF service project inside it. We need to support "cookieless". so in the web.config, it's set as <sessionState mode="SQLServer" sqlConnectionString="Data Source=ds;Initial Catalog=db;User Id=uid;Password=pwd" allowCustomSqlDatabase="true" cookieless="true" timeout="720" regenerateExpiredSessionId="false"/> The WCF service will be supporting sessions, so we have also set "aspNetCompatibilityEnabled" to true in web.config. <serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true"/> The service and interfaces are as follows, [ServiceContract(SessionMode=SessionMode.Allowed)] public interface ICDOCService { } [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class CDOCService : ICDOCService { } The problem we are facing is we cannot access the service from any client application. (web app, WCF test client) The following error is showing, when we access it via WCF Test client, Failed to invoke the service. Possible causes: The service is offline or inaccessible; the client-side configuration does not match the proxy; the existing proxy is invalid. Refer to the stack trace for more detail. You can try to recover by starting a new proxy, restoring to default configuration, or refreshing the service. The content type text/html; charset=UTF-8 of the response message does not match the content type of the binding (multipart/related; type="application/xop+xml"). If using a custom encoder, be sure that the IsContentTypeSupported method is implemented properly. The first 1024 bytes of the response were: <HTML> <HEAD> <link rel="alternate" type="text/xml" href="http://localhost:53721/Services/CDOCService.svc?disco"/> <STYLE type="text/css">#content{ FONT-SIZE: 0.7em; PADDING-BOTTOM: 2em; MARGIN-LEFT: 30px}BODY{MARGIN-TOP: 0px; MARGIN-LEFT: 0px; COLOR: #000000; FONT-FAMILY: Verdana; BACKGROUND-COLOR: white}P{MARGIN-TOP: 0px; MARGIN-BOTTOM: 12px; COLOR: #000000; FONT-FAMILY: Verdana}PRE{BORDER-RIGHT: #f0f0e0 1px solid; PADDING-RIGHT: 5px; BORDER-TOP: #f0f0e0 1px solid; MARGIN-TOP: -5px; PADDING-LEFT: 5px; FONT-SIZE: 1.2em; PADDING-BOTTOM: 5px; BORDER-LEFT: #f0f0e0 1px solid; PADDING-TOP: 5px; BORDER-BOTTOM: #f0f0e0 1px solid; FONT-FAMILY: Courier New; BACKGROUND-COLOR: #e5e5cc}.heading1{MARGIN-TOP: 0px; PADDING-LEFT: 15px; FONT-WEIGHT: normal; FONT-SIZE: 26px; MARGIN-BOTTOM: 0px; PADDING-BOTTOM: 3px; MARGIN-LEFT: -30px; WIDTH: 100%; COLOR: #ffffff; PADDING-TOP: 10px; FONT-FAMILY: Tahoma; BACKGROUND-COLOR: #003366}.intro{MARGIN-LEFT: -15px} </STYLE> <TITLE>CDOCService Service</TITLE></HEAD><BODY><DIV id="content"><P '. Server stack trace: at System.ServiceModel.Channels.HttpChannelUtilities.ValidateRequestReplyResponse(HttpWebRequest request, HttpWebResponse response, HttpChannelFactory factory, WebException responseException, ChannelBinding channelBinding) at System.ServiceModel.Channels.HttpChannelFactory.HttpRequestChannel.HttpChannelRequest.WaitForReply(TimeSpan timeout) at System.ServiceModel.Channels.RequestChannel.Request(Message message, TimeSpan timeout) at System.ServiceModel.Dispatcher.RequestChannelBinder.Request(Message message, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannel.Call(String action, Boolean oneway, ProxyOperationRuntime operation, Object[] ins, Object[] outs, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannel.Call(String action, Boolean oneway, ProxyOperationRuntime operation, Object[] ins, Object[] outs) at System.ServiceModel.Channels.ServiceChannelProxy.InvokeService(IMethodCallMessage methodCall, ProxyOperationRuntime operation) at System.ServiceModel.Channels.ServiceChannelProxy.Invoke(IMessage message) Exception rethrown at [0]: at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg) at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type) at ICDOCService.GetCDOCCount(String institutionID, String mrnID, String userID, String callingSystemID, String securityToken) at CDOCServiceClient.GetCDOCCount(String institutionID, String mrnID, String userID, String callingSystemID, String securityToken)

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