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  • Container div ignores height of floated elements

    - by Thomas
    Ok, so this seems like a really silly problem but I can't get my container div to inherit the height of the floated elements inside of it. Since I need to center the container div, I can't use float to fix this problem. Here is my css: #container { margin: 0 auto; width: 1000px; border-left: 1px solid #f1f1f1; border-right: 1px solid #f1f1f1; border-bottom: 1px solid #f1f1f1; } #focus { padding-left: 23px; width: 977px; padding-top: 20px; padding-bottom: 23px; border-bottom: 1px solid #f1f1f1; float: left; } .rslider { float: left; width: 600px; margin-left: 15px; } .welcome { float: left; width: 300px; } Html: <div id="container"> <div id="logo_block"> <a href="#"><img src="img/logo.jpg" alt="" /></a> </div> <div id="focus"> <div class="welcome"> <h1>All About This Page</h1> <p>Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem. Nulla consequat massa quis enim. Donec pede justo, fringilla vel, liquet nec, vulputate eget, arcu. In enim justo, rhoncus ut, imperdiet a, venenatis vitae, justo. Nullam dictum felis eu pede mollis pretium.</p> </div> <div class="rslider"> <img src="img/slider_image.jpg"> </div> </div> </div> Any ideas?

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  • What data type should I use for my texture coordinates in OpenGL ES?

    - by Matthew Chen
    I notice that the default data type for texture coordinates in the OpenGL docs is GLfloat, but much of the sample code I see written by experienced iphone developers uses GLshort or GLbyte. Is this an optimization? GLfloat vertices[] = { // Upper left x1, y2, // Lower left x1, y1, // Lower right x2, y1, // Upper right x2, y2, }; glTexCoordPointer(2, GL_FLOAT, 0, iconSTs); vs. GLbyte vertices[] = { // Upper left x1, y2, // Lower left x1, y1, // Lower right x2, y1, // Upper right x2, y2, }; glTexCoordPointer(2, GL_BYTE, 0, iconSTs);

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  • How could I evaluate this in code?

    - by WM
    There is a medieval puzzle about an old woman and a basket of eggs. On her way to market, a horseman knocks down the old woman and all the eggs are broken. The horseman will pay for the eggs, but the woman does not remember the exact number she had, only that when she took the eggs in pair, there was one left over; similarly, there was one left over when she took them three or five at a time. When she took them seven at a time, however, none were left. Write an application that can determine the smallest number of eggs the woman could have had. It might be a multiple of seven because there are no eggs left when it's seven at a time. But I have a problem. 49 eggs -1=2*24 49 eggs -1=3*16 49 eggs-4=5*9 49 eggs-0=7*7

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  • Trying to fadein divs in a sequence, over time, using JQuery

    - by user346602
    Hi, I'm trying to figure out how to make 4 images fade in sequentially when the page loads. The following is my (amateurish) code: Here is the HTML: <div id="outercorners"> <img id="corner1" src="images/corner1.gif" width="6" height="6" alt=""/> <img id="corner2" src="images/corner2.gif" width="6" height="6" alt=""/> <img id="corner3" src="images/corner3.gif" width="6" height="6" alt=""/> <img id="corner4" src="images/corner4.gif" width="6" height="6" alt=""/> </div><!-- end #outercorners--> Here is the JQuery: $(document).ready(function() { $("#corner1").fadeIn("2000", function(){ $("#corner3").fadeIn("4000", function(){ $("#corner2").fadeIn("6000", function(){ $("#corner4").fadeIn("8000", function(){ }); }); }); }); Here is the css: #outercorners { position: fixed; top:186px; left:186px; width:558px; height:372px; } #corner1 { position: fixed; top:186px; left:186px; display: none; } #corner2 { position: fixed; top:186px; left:744px; display: none; } #corner3 { position: fixed; top:558px; left:744px; display: none; } #corner4 { position: fixed; top:558px; left:186px; display: none; } They seem to just wink at me, rather than fade in in the order I've ascribed to them. Should I be using the queue() function? And, if so, how would I implement it in this case? Thank you for any assistance.

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  • 2-col layout, one col scrolls vertical, other is fixed. Both scroll horizontal.

    - by Victor P
    Im trying to do a 2 column layout where the left column is very long vertically, and the right column is very long horizontally. When I scroll vertically, I want to move up and down the left column while the right one stays fixed. When I scroll horizontally, both columns move left-right (normal behaviour) I hope this drawing explain it more (sorry for the bad quality): Is this possible to do using only css? If not, how can I do it with javascript? Thanks

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  • CSS Positioning

    - by Davey
    Trying to mess with this wordpress theme and can't figure out why the sidebar is stacking underneath the content block. Any help would be very appreciated. http://www.buffalostreetbooks.com/events CSS: body { font-family: Arial, Helvetica, Verdana, Sans-serif; font-size: 10pt; background-color: #692022; background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/repeatflower.png"); } body,h1#blog-title { margin: 0; padding: 0; } a { color: blue; } a:hover { color: #FF8C00; } a img { border: 0 none; } #wrapper { width: 960px; margin: 0 auto; background-color: #F4FBF4; border-left: 1px solid #ccc; border-right: 1px solid #ccc; } #header { background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/headertime.png"); width:768px; height: 200px; } #inner-header { padding: 125px 1em 0; } h1#blog-title { font-size: 2em; } h1#blog-title a { color: #800000; } .entry-title a { color: #CD853F; } h1#blog-title a, .entry-title a, #footer a { text-decoration: none; } h1#blog-title a:hover, .entry-title a:hover, #footer a:hover { text-decoration: underline; } div.skip-link { display: none; } #menu { border-bottom: 1px solid #ccc; } #menu a { color: #000; } #menu a:hover { text-decoration: underline; } #menu li.current_page_item a, #menu li.current_page_item a:hover { background-color: #DFC28B; text-decoration: none; } #content { padding: 1em; width:600px; } .entry-title { font-size: 1.5em; margin: 1em 0 0 0; } abbr.published { color: #666; border: 0 none; } .entry-meta, .entry-date { color: #666; } #comments-list .avatar { float: left; margin-right: 1em; } #comments-list .n { font-weight: bold; } .entry-meta, .comment-meta { font-style: italic; } #comments-list p { clear: left; } #primary { padding-left: 1em; font-size: 0.9em; border-left: 1px solid #ccc; border-bottom: 1px solid #ccc; background-color: #FFFACD; } #footer { text-align: center; font-size: 0.8em; border-top: 1px solid #ccc; border-bottom: 1px solid #ccc; margin-bottom: 1em; } #inner-footer { padding: 1em 0; } .entry-meta, .entry-meta a, .comment-meta, .comment-meta a, .sidebar, .sidebar a, #footer, #footer a { color: #666; } /* LAYOUT: Two-Column (Right) DESCRIPTION: Two-column fluid layout with one sidebars right of content */ div#container { margin:0 0 0 0; width:960px; height:100%; } div#content { margin:0 0 0 0; } div.sidebar { overflow:hidden; width:280px; min-height:500px; clear:both; } div#secondary { clear:right; } div#footer { clear:both; width:100%; } /* Just some example content */ div#menu { height:2em; width:100%; } div#menu ul,div#menu ul ul { line-height:2em; list-style:none; margin:0; padding:0; } div#menu ul a { display:block; margin-right:1em; padding:0 0.5em; text-decoration:none; } div#menu ul ul ul a { font-style:italic; } div#menu ul li ul { left:-999em; position:absolute; } div#menu ul li:hover ul { left:auto; } .entry-title,.entry-meta { clear:both; } div#primary { } form#commentform .form-label { margin:1em 0 0; } form#commentform span.required { background:#fff; color:#c30; } form#commentform,form#commentform p { padding:0; } input#author,input#email,input#url,textarea#comme nt { padding:0.2em; } div.comments ol li { margin:0 0 3.5em; } textarea#comment { height:13em; margin:0 0 0.5em; overflow:auto; width:66%; } .alignright,img.alignright{ float:right; margin:1em 0 0 1em; } .alignleft,img.alignleft{ float:left; margin:1em 1em 0 0; } .aligncenter,img.aligncenter{ display:block; margin:1em auto; text-align:center; } div.gallery { clear:both; height:180px; margin:1em 0; width:100%; } p.wp-caption-text{ font-style:italic; } div.gallery dl{ margin:1em auto; overflow:hidden; text-align:center; } div.gallery dl.gallery-columns-1 { width:100%; } div.gallery dl.gallery-columns-2 { width:49%; } div.gallery dl.gallery-columns-3 { width:33%; } div.gallery dl.gallery-columns-4 { width:24%; } div.gallery dl.gallery-columns-5 { width:19%; } div#nav-above { margin-bottom:1em; } div#nav-below { margin-top:1em; } div#nav-images { height:150px; margin:1em 0; } div.navigation { height:1.25em; } div.navigation div.nav-next { float:right; text-align:right; } div.sidebar h3 { font-size:1.2em; } div.sidebar input#s { width:7em; } div.sidebar li { list-style:none; margin:0 0 2em; } div.sidebar li form { margin:0.2em 0 0; padding:0; } div.sidebar ul ul { margin:0 0 0 2em; } div.sidebar ul ul li { list-style:disc; margin:0; } div.sidebar ul ul ul { margin:0 0 0 0.5em; } div.sidebar ul ul ul li { list-style:circle; } div#menu ul li,div.gallery dl,div.navigation div.nav-previous { float:left; } input#author,input#email,input#url,div.navigation div { width:50%; } div.gallery *,div.sidebar div,div.sidebar h3,div.sidebar ul { margin:0; padding:0; }

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  • More efficient comparison of numbers

    - by Pez Cuckow
    I have an array which is part of a small JS game I am working on I need to check (as often as reasonable) that each of the elements in the array haven't left the "stage" or "playground", so I can remove them and save the script load I have coded the below and was wondering if anyone knew a faster/more efficient way to calculate this. This is run every 50ms (it deals with the movement). Where bots[i][1] is movement in X and bots[i][2] is movement in Y (mutually exclusive). for (var i in bots) { var left = parseInt($("#" + i).css("left")); var top = parseInt($("#" + i).css("top")); var nextleft = left + bots[i][1]; var nexttop = top + bots[i][2]; if(bots[i][1]>0&&nextleft>=PLAYGROUND_WIDTH) { remove_bot(i); } else if(bots[i][1]<0&&nextleft<=-GRID_SIZE) { remove_bot(i); } else if(bots[i][2]>0&&nexttop>=PLAYGROUND_HEIGHT) { remove_bot(i); } else if(bots[i][2]<0&&nexttop<=-GRID_SIZE) { remove_bot(i); } else { //alert(nextleft + ":" + nexttop); $("#" + i).css("left", ""+(nextleft)+"px"); $("#" + i).css("top", ""+(nexttop)+"px"); } } On a similar note the remove_bot(i); function is as below, is this correct (I can't splice as it changes all the ID's of the elements in the array. function remove_bot(i) { $("#" + i).remove(); bots[i] = false; } Many thanks for any advice given!

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

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  • How do I set command line mode vga=788 permanently?

    - by George
    I have a problem that is not of easy resolution, happen to tell... I have Installed Ubuntu 10.10 Server. I want to join to the system way vga=788, into the grub it changes without any problem editing the file grub.cfg, the problem is that editing the above mentioned file I join to the system way vga=788 (800x600) and then command line puts itself in way vga=792 (1280x1024). Is there any way of changing this configuration so that it is always vga=788? tanks. sorry for my english :D

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  • Reconciling a new BindingList into a master BindingList using LINQ

    - by Neo
    I have a seemingly simple problem whereby I wish to reconcile two lists so that an 'old' master list is updated by a 'new' list containing updated elements. Elements are denoted by a key property. These are my requirements: All elements in either list that have the same key results in an assignment of that element from the 'new' list over the original element in the 'old' list only if any properties have changed. Any elements in the 'new' list that have keys not in the 'old' list will be added to the 'old' list. Any elements in the 'old' list that have keys not in the 'new' list will be removed from the 'old' list. I found an equivalent problem here - http://stackoverflow.com/questions/161432/ - but it hasn't really been answered properly. So, I came up with an algorithm to iterate through the old and new lists and perform the reconciliation as per the above. Before anyone asks why I'm not just replacing the old list object with the new list object in its entirety, it's for presentation purposes - this is a BindingList bound to a grid on a GUI and I need to prevent refresh artifacts such as blinking, scrollbars moving, etc. So the list object must remain the same, only its updated elements changed. Another thing to note is that the objects in the 'new' list, even if the key is the same and all the properties are the same, are completely different instances to the equivalent objects in the 'old' list, so copying references is not an option. Below is what I've come up with so far - it's a generic extension method for a BindingList. I've put comments in to demonstrate what I'm trying to do. public static class BindingListExtension { public static void Reconcile<T>(this BindingList<T> left, BindingList<T> right, string key) { PropertyInfo piKey = typeof(T).GetProperty(key); // Go through each item in the new list in order to find all updated and new elements foreach (T newObj in right) { // First, find an object in the new list that shares its key with an object in the old list T oldObj = left.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(newObj, null))); if (oldObj != null) { // An object in each list was found with the same key, so now check to see if any properties have changed and // if any have, then assign the object from the new list over the top of the equivalent element in the old list foreach (PropertyInfo pi in typeof(T).GetProperties()) { if (!pi.GetValue(oldObj, null).Equals(pi.GetValue(newObj, null))) { left[left.IndexOf(oldObj)] = newObj; break; } } } else { // The object in the new list is brand new (has a new key), so add it to the old list left.Add(newObj); } } // Now, go through each item in the old list to find all elements with keys no longer in the new list foreach (T oldObj in left) { // Look for an element in the new list with a key matching an element in the old list if (right.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(oldObj, null))) == null) { // A matching element cannot be found in the new list, so remove the item from the old list left.Remove(oldObj); } } } } It can be called like this: _oldBindingList.Reconcile(newBindingList, "MyKey") However, I'm looking for perhaps a method of doing the same using LINQ type methods such as GroupJoin<, Join<, Select<, SelectMany<, Intersect<, etc. So far, the problem I've had is that each of these LINQ type methods result in brand new intermediary lists (as a return value) and really, I only want to modify the existing list for all the above reasons. If anyone can help with this, would be most appreciated. If not, no worries, the above method (as it were) will suffice for now. Thanks, Jason

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  • appendTo() inside $.each in jquery seems to cause flicker....

    - by Pandiya Chendur
    appendTo() causes flicker when it is inside $.each.... $.each(jsob.Table, function(i, employee) { $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').appendTo('#ResultsDiv'); }); Right now i am appending every new div to #ResultsDiv inside$.each is it good/bad to do so... If it is bad What can be done to make my divs appendTo() after the loop so that i it wont flicker.... EDIT:(based on answer) var divs = ''; $.each(jsob.Table, function(i, employee) { divs += '<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>'; }); $("#ResultsDiv").append(divs); But that too doesn't stop the flicker...

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  • Reading JSON with Javascript/jQuery

    - by Josephine
    I'm building a game in javascript/html5 and I'm trying to build a database of locked doors in a maze that can be loaded from and overwritten to throughout gameplay. I've found a large number of tutorials online, but nothing is working. I was wondering if someone could look at what I'm trying and let me know what I'm doing wrong. My JSON file looks like this: { "doors": [ {"left":true, "right":false, "bottom":false}, {"left":false, "right":false, "bottom":false}, {"right":false, "bottom":false, "top":false}, {"left":false, "right":false, "top":false} ] } I want to build the HTML page so that when a player collides with a door it checks if its locked or not like: if (player.x < leftDoor.x + leftDoor.width && player.x + player.width > leftDoor.x && player.y < leftDoor.y + leftDoor.height && player.y + player.height > leftDoor.y) { if(doors[0].left == true) alert("door is locked"); else window.location = ( "2.html?p1="); } However I'm having trouble reading from the JSON file itself. I've tried things like: function loadJson() { $(document).ready(function() { $.getJSON('info.json', function(doors) { alert(doors[0].left); }); }); } But nothing happens, and I need to be able to access the information in the HTML as well. I'd rather use jQuery, but I'm not opposed to straight JS if it works. I've been trying to do this for ages and I'm getting absolutely no where. If someone could help that would be amazing. Thanks!

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  • iPhone/Objective-C struct question my own CGRectZero

    - by Mark
    I am designing a Padding struct as follows: /* Padding. */ struct CGPadding { CGFloat left; CGFloat top; CGFloat right; CGFloat bottom; }; typedef struct CGPadding CGPadding; CG_INLINE CGPadding CGPaddingMake(CGFloat left, CGFloat top, CGFloat right, CGFloat bottom) { CGPadding p; p.left = left; p.top = top; p.right = right; p.bottom = bottom; return p; } This all works perfectly well, the problem is how can I create a const CGPadding CGPaddingZero? If I do like this: const CGPadding CGPaddingZero = (CGPadding){0.0, 0.0, 0.0, 0.0}; It doesnt work. So what am I doing wrong?

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  • Return parent of node in Binary Tree

    - by user188995
    I'm writing a code to return the parent of any node, but I'm getting stuck. I don't want to use any predefined ADTs. //Assume that nodes are represented by numbers from 1...n where 1=root and even //nos.=left child and odd nos=right child. public int parent(Node node){ if (node % 2 == 0){ if (root.left==node) return root; else return parent(root.left); } //same case for right } But this program is not working and giving wrong results. My basic algorithm is that the program starts from the root checks if it is on left or on the right. If it's the child or if the node that was queried else, recurses it with the child.

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  • problem in below table:i had table inside table .my inner table contains some text.

    - by Ayyappan.Anbalagan
    Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

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  • Blackberry app development - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • Blackberry (Java) - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • I want to write a program to control the square moving by using WINAPI

    - by code_new
    This is the code as attempted so far: #include <windows.h> LRESULT CALLBACK WndProc (HWND, UINT, WPARAM, LPARAM) ; int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine, int iCmdShow) { static TCHAR szAppname[] = TEXT ("win0") ; WNDCLASS wndclass ; MSG msg ; HWND hwnd ; wndclass.style = CS_HREDRAW | CS_VREDRAW ; wndclass.cbWndExtra = 0 ; wndclass.cbClsExtra = 0 ; wndclass.lpfnWndProc = WndProc ; wndclass.lpszClassName = szAppname ; wndclass.lpszMenuName = NULL ; wndclass.hbrBackground = (HBRUSH) GetStockObject (WHITE_BRUSH) ; wndclass.hCursor = LoadCursor (NULL, IDC_ARROW) ; wndclass.hIcon = LoadIcon (NULL, IDI_APPLICATION) ; wndclass.hInstance = hInstance ; if (!RegisterClass (&wndclass)) { MessageBox (NULL, TEXT ("Register fail"), szAppname, 0) ; return 0 ; } hwnd = CreateWindow ( szAppname, TEXT ("mywin"), WS_OVERLAPPEDWINDOW, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, NULL, NULL, hInstance, NULL) ; ShowWindow (hwnd, iCmdShow) ; UpdateWindow (hwnd) ; while (GetMessage (&msg, NULL, 0, 0)) { TranslateMessage (&msg) ; DispatchMessage (&msg) ; } return msg.wParam ; } LRESULT CALLBACK WndProc (HWND hwnd, UINT message, WPARAM wParam, LPARAM lParam) { static int cxClient, cyClient, Left, Top, Right, Down ; PAINTSTRUCT ps ; HDC hdc ; RECT rect ; Right = 20 ; Down = 20 ; switch (message) { case WM_SIZE : cxClient = LOWORD (lParam) ; cyClient = HIWORD (lParam) ; return 0 ; case WM_PAINT : hdc = BeginPaint (hwnd, &ps) ; SetRect (&rect, Left, Top, Right, Down) ; FillRect (hdc, &rect, CreateSolidBrush (RGB (100, 100, 100))) ; EndPaint (hwnd, &ps) ; return 0 ; case WM_KEYDOWN : InvalidateRect (hwnd, &rect, TRUE) ; switch (wParam) { case VK_UP : if (Top - 20 < 0) { Top = 0 ; Down = 20 ; } else { Top -= 20 ; Down -= 20 ; } SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_DOWN : if (Down + 20 > cyClient) { Down = cyClient ; Top = Down - 20 ; } else { Down += 20 ; Top += 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_LEFT : if (Left - 20 < 0) { Left = 0 ; Right = 20 ; } else { Left -= 20 ; Right -= 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_RIGHT : if (Right + 20 > cxClient) { Right = cxClient ; Left = Right - 20 ; } else { Right += 20 ; Left += 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; default : break ; } return 0 ; case WM_DESTROY : PostQuitMessage (0) ; return 0 ; } return DefWindowProc (hwnd, message, wParam, lParam); } I considered that I didn't deal the message well, so I can't control it.

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  • Please help fix and optimize this query

    - by user607217
    I am working on a system to find potential duplicates in our customers table (SQL 2005). I am using the built-in SOUNDEX value that our software computes when customers are added/updated, but I also implemented the double metaphone algorithm for better matching. This is the most-nested query I have created, and I can't help but think there is a better way to do it and I'd like to learn. In the inner-most query I am joining the customer table to the metaphone table I created, then finding customers that have identical pKey (primary phonetic key). I take that, union that with customers that have matching soundex values, and then proceed to score those matches with various text similarity functions. This is currently working, but I would also like to add a union of customers whose aKey (alternate phonetic key) match. This would be identical to "QUERY A" except to substitute on (c1Akey = c2Akey) for the join. However, when I attempt to include that, I get errors when I try to execute my query. Here is the code: --Create aggregate ranking select c1Name, c2Name, nDiff, c1Addr, c2Addr, aDiff, c1SSN, c2SSN, sDiff, c1DOB, c2DOB, dDiff, nDiff+aDiff+dDiff+sDiff as Score ,(sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 as [Rank] FROM ( --Create match scores for different fields SELECT c1Name, c2Name, c1Addr, c2Addr, c1SSN, c2SSN, c1LTD, c2LTD, c1DOB, c2DOB, dbo.Jaro(c1name, c2name) AS nDiff, dbo.JaroWinkler(c1addr, c2addr) AS aDiff, CASE WHEN c1dob = '1901-01-01' OR c2dob = '1901-01-01' OR c1dob = '1800-01-01' OR c2dob = '1800-01-01' THEN .5 ELSE dbo.SmithWaterman(c1dob, c2dob) END AS dDiff, CASE WHEN c1ssn = '000-00-0000' OR c2ssn = '000-00-0000' THEN .5 ELSE dbo.Jaro(c1ssn, c2ssn) END AS sDiff FROM -- Generate list of possible matches based on multiple phonetic matching fields ( select * from -- List of similar names from pKey field of ##Metaphone table --QUERY A BEGIN (select customers.custno as c1Custno, name as c1Name, haddr as c1Addr, ssn as c1SSN, lasttripdate as c1LTD, dob as c1DOB, soundex as c1Soundex, pkey as c1Pkey, akey as c1Akey from Customers WITH (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c1 JOIN (select customers.custno as c2Custno, name as c2Name, haddr as c2Addr, ssn as c2SSN, lasttripdate as c2LTD, dob as c2DOB, soundex as c2Soundex, pkey as c2Pkey, akey as c2Akey from Customers with (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c2 on (c1Pkey = c2Pkey) and (c1Custno < c2Custno) WHERE (c1Name <> 'PARENT, GUARDIAN') and c1soundex != c2soundex --QUERY A END union --List of similar names from pregenerated SOUNDEX field (select t1.custno, t1.name, t1.haddr, t1.ssn, t1.lasttripdate, t1.dob, t1.[soundex], 0, 0, t2.custno, t2.name, t2.haddr, t2.ssn, t2.lasttripdate, t2.dob, t2.[soundex], 0, 0 from Customers t1 WITH (nolock) join customers t2 with (nolock) on t1.[soundex] = t2.[soundex] and t1.custno < t2.custno where (t1.name <> 'PARENT, GUARDIAN')) ) as a ) as b where (sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 >= 7.5 order by [rank] desc, score desc Previously, I was using joins such as on c1.pkey = c2.pkey or c1.akey = c2.akey or c1.soundex = c2.soundex but the performance was horrendous, and using unions seems to be working a lot better. Out of 103K customers, tt is currently generating a list of 8.5M potential matches (based on the phonetic codes) in 2.25 minutes, and then taking another 2 to score, rank and filter those down to about 3000. So I am happy with the performance, I just can't help but think there is a better way to structure this, and I need help adding the extra union condition. Thanks!

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  • CSS Horizontal sub menu - IE 6,7 both dont working, tried with whatever hover.

    - by SHAKTI
    I'm not expert about css menus. But I know basic system to make css menu. I used this system before and works, but this time it is not working. The site is http://www.uniethos.com. Please check this site This menu works with all other latest Browsers. But not with IE 6 & 7. I know IE6 don't support hover except anchor. So before I was using Whatever Hover. But this time it is not working and even with IE7. I don't know why its happening. May be there could be some problem with my css. Please check the css. If you don't have IE 6 or 7 installed you can run one from http://spoon.net/browsers/. Require to install one plugin. The CSS I'm using for the menu is .glossymenu{ background: #B4B3B3; height: 30px; width: 100%; padding: 0; margin: 0; display:inline-block; position:relative; } .glossymenu ul { list-style: none; padding: 0px; margin: 0; padding-left: 0px; } .glossymenu li ul { display:none; position:absolute; width: 80%; top:30px; left:0px; background-color:#5B0C10; border:0px; z-index: 99; } .glossymenu li li a { padding: 0px 10px 0px 10px; } .glossymenu li li a:hover { background : #871016; } .glossymenu li{ float:left; padding: 0; } .glossymenu li a{ float: left; display:block; position:relative; color:#FFF; text-decoration: none; font-family: sans-serif; font-size: 13px; font-weight: bold; padding:0 0 0 16px; /*Padding to accomodate left tab image. Do not change*/ height: 30px; line-height: 30px; text-align: center; cursor: pointer; } .glossymenu li a b{ float: left; display: block; padding: 0 24px 0 8px; /*Padding of menu items*/ } .glossymenu li.current a, .glossymenu li a:hover{ color: #FFF; background: #5B0C10; background-position: left; text-decoration: none; } .glossymenu li a:visited{ text-decoration: none; } .glossymenu ul li:hover ul { display: block; }

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  • How to bring the parent element with floated child elements to the center of the document?

    - by Starx
    I have organized a menu. Its HTML is as follows: <ul class="topmenu"> <li><a href="sample.html">Text 1</a></li> <li><a href="sample.html">Text 2</a></li> <li><a href="sample.html">Text 3</a></li> <li><a href="sample.html">Text 4</a></li> <ul> This is a horizontal menu, so I have floated the list items to left to appear them in a horizontal line. I could have used display:inline to appear them in a single line, but since IE does not support it and I don't know any other way to do so, I used float:left;. It's css is: .topmenu { list-style:none; margin:0; padding:0; } .topmenu li { float:left; } This brings the menu in a perfect horizontal line, but the entire list is floated to the left. I want to bring the .topmenu to appear in the center of the document and keep the listitem inside it floated towards the left. I found that this is achievable by defining width property of the .topmenu, but I dont want to fix its width as the list-items are dynamically generated and thus could increase and decrease. Any one know of any solution?

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  • Javascript game with css position

    - by newb125505
    I am trying to make a very simple helicopter game in javascript and I'm currently using css positions to move the objects. but I wanted to know if there was a better/other method for moving objects (divs) when a user is pressing a button here's a code i've got so far.. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Game 2 helicopter</title> <script type="text/javascript"> function num(x){ return parseInt(x.replace(/([^0-9]+)/g,'')); } function getPos(x, y){ var inum=Math.floor(Math.random()*(y+1-x)) + x; inum=inum; return inum; } function setTop(x,y){ x.style.top = y+'px'; } function setBot(x,y){ x.style.bottom = y+'px'; } function setLeft(x,y){ x.style.left = y+'px'; } function setRight(x,y){ x.style.right = y+'px'; } function getTop(x){ return num(x.style.top); } function getBot(x){ return num(x.style.bottom); } function getLeft(x){ return num(x.style.left); } function getRight(x){ return num(x.style.right); } function moveLeft(x,y){ var heli = document.getElementById('heli'); var obj = document.getElementById('obj'); var poss = [20,120,350,400]; var r_pos = getPos(1,4); var rand_pos = poss[r_pos]; xleft = getLeft(x)-y; if(xleft>0){ xleft=xleft; } else{ xleft=800; setTop(x,rand_pos); } setLeft(x,xleft); setTimeout(function(){moveLeft(x,y)},10); checkGame(heli,obj); } var heli; var obj; function checkGame(x,y){ var obj_right = getLeft(x) + 100; var yt = getTop(y); var yb = (getTop(y)+100); if(getTop(x) >= yt && getTop(x) <= yb && obj_right==getLeft(y)){ endGame(); } } function func(){ var x = document.getElementById('heli'); var y = document.getElementById('obj'); alert(getTop(x)+' '+getTop(y)+' '+(getTop(y)+200)); } function startGame(e){ document.getElementById('park').style.display='block'; document.getElementById('newgame').style.display='none'; heli = document.getElementById('heli'); obj = document.getElementById('obj'); hp = heli.style.top; op = obj.style.top; setTop(heli,20); setLeft(heli,20); setLeft(obj,800); setTop(obj,20); moveLeft(obj,5); } function newGameLoad(){ document.getElementById('park').style.display='none'; document.getElementById('newgame').style.display='block'; } function gamePos(e){ heli = document.getElementById('heli'); obj = document.getElementById('obj'); var keynum; var keychar; var numcheck; if(window.event){ // IE keynum = e.keyCode; } else if(e.which){ // Netscape/Firefox/Opera keynum = e.which; } keychar = String.fromCharCode(keynum); // up=38 down=40 left=37 right=39 /*if(keynum==37){ //left tl=tl-20; db.style.left = tl + 'px'; } if(keynum==39){ //right //stopPos(); tl=tl+20; db.style.left = tl + 'px'; }*/ curb = getTop(heli); if(keynum==38){ //top setTop(heli,curb-10); //alert(curb+10); } if(keynum==40){ //bottom setTop(heli,curb+10); //alert(curb-10); } } function endGame(){ clearTimeout(); newGameLoad(); } </script> <style type="text/css"> .play{position:absolute;color:#fff;} #heli{background:url(http://classroomclipart.com/images/gallery/Clipart/Transportation/Helicopter/TN_00-helicopter2.jpg);width:150px;height:59px;} #obj{background:red;width:20px;height:200px;} .park{height:550px;border:5px solid brown;border-left:none;border-right:none;} #newgame{display:none;} </style> </head> <body onload="startGame();" onkeydown="gamePos(event);"> <div class="park" id="park"> <div id="heli" class="play"></div> <div id="obj" class="play"></div> </div> <input type="button" id="newgame" style="position:absolute;top:25%;left:25%;" onclick="startGame();" value="New Game" /> </body> </html>

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  • How to do word wrapping.

    - by Talha Bin Shakir
    Hi, I have created a table in PHP but the cells size is not fixed it expends when the input is long. Here is the Code. echo "<div style=\"overflow-y: scroll; white-space: nowrap; height: 190px;\">\n"; echo "<table cellspacing=\"1\" cellpadding=\"1\" align=\"center\" width=\"100%\" id=\"clients\">\n"; echo "<tr bgcolor=\"2b2d5d\">\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">&nbsp;</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Name</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Address</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Phone</th>\n"; echo "<th align=\"left\" style=\"color: FFFFFF; font-size: 12px; font-weight: normal; font-family: Arial; padding: 5\">Fax</th>\n"; I want to fixed the cells width please need help. Thanks

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