Search Results

Search found 18648 results on 746 pages for 'left join'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 112/746 | < Previous Page | 108 109 110 111 112 113 114 115 116 117 118 119  | Next Page >

  • Generated HTML word document not displaying image correctly

    - by spiderdijon
    I'm trying to add an image to a generated html word document that is embedded in a classic ASP page. The code looks something like this: <% Response.ContentType = "application/msword" %> <html xmlns:v="urn:schemas-microsoft-com:vml" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:w="urn:schemas-microsoft-com:office:word"> ... <v:shape id="_x0000_s1030" type="#_x0000_t75" style='position:absolute; left:0;text-align:left;margin-left:0;margin-top:17.95pt;width:7in;height:116.85pt; z-index:2;mso-position-horizontal:center;mso-position-horizontal-relative:page; mso-position-vertical-relative:page'> <v:imagedata src="http://xxx/image001.gif" o:title="image001"/> <w:wrap anchorx="page" anchory="page"/> <w:anchorlock/> </v:shape><![endif]--><![if !vml]><span style='mso-ignore:vglayout;position: absolute;z-index:0;left:0px;margin-left:0px;margin-top:24px;width:672px; height:156px'><img width=672 height=156 src="http://xxx/image001.gif" v:shapes="_x0000_s1030"></span><![endif]> The image URL is correct and can be viewed through a browser, however when the word document opens, the image has a red x, with the error message: The image cannot be displayed. Your computer may not have enough memory to open the image, or the image may be corrupted. Restart your computer, and then open the file again. If the red x still appears, you may have to delete the image and then insert it again. If i copy the html code and try to open the word document on my local machine, it displays the image correctly. It just doesn't work when retrieving the document from the server. This happens for any images I try to add. Is there another way to add images to html-generated word documents that can be output from an asp page? Thanks.

    Read the article

  • are these css classes names good?

    - by metal-gear-solid
    See section /* Common Classes */ of this page. http://webdesign.about.com/od/css/a/master_stylesht_2.htm are these css classes good, to use in any project? in terms of semantic? /* Common Classes */ .clear { clear: both; } .floatLeft { float: left; } .floatRight { float: right; } .textLeft { text-align: left; } .textRight { text-align: right; } .textCenter { text-align: center; } .textJustify { text-align: justify; } .blockCenter { display: block; margin-left: auto; margin-right: auto; } /* remember to set width */ .bold { font-weight: bold; } .italic { font-style: italic; } .underline { text-decoration: underline; } .noindent { margin-left: 0; padding-left: 0; } .nomargin { margin: 0; } .nopadding { padding: 0; } .nobullet { list-style: none; list-style-image: none; }

    Read the article

  • problem with converting simple code to silverlight app.

    - by Sara
    Hi. I have this code for window form application and I have been attempting to convert it to a Silverlight application but it does not work!. There is a Textbox and I attached KeyDown event handler to it. when the user press the arrow key ( left or right) while the focus on the textbox, it will write . or -. When it is window form i used e.KeyCode and Keys.Right and its works great but when it is silverlight I used e.Key and key.Right and the program doesn't work good because the arrows do the 2 functions moving and write ./-. How I can work this out in Silverlight? (My English not good) The code ( window form): private void textBox1_KeyDown(object sender, KeyEventArgs e) { if (sender is TextBox) { TextBox textBox = (TextBox)sender; if (e.KeyCode == Keys.Left || e.KeyCode == Keys.Right) { e.Handled = true; char insert; if (e.KeyCode == Keys.Left) { insert = '.'; } else { insert = '-'; } int i = textBox.SelectionStart; textBox.Text = textBox.Text.Insert(i, insert.ToString()); textBox.Select(i + 1, 0); } } } (and Silverlight): private void textBox1_KeyDown(object sender, KeyEventArgs e) { if (sender is TextBox) { TextBox textBox = (TextBox)sender; if (e.Key == Key.Left || e.Key == Key.Right) { e.Handled = true; char insert; if (e.Key == Key.Left) { insert = '.'; } else { insert = '-'; } int i = textBox.SelectionStart; textBox.Text = textBox.Text.Insert(i, insert.ToString()); textBox.Select(i + 1, 0); } } } I don't understand, is there huge different effect between using Keycode/Keys and Key/Key or because something else?

    Read the article

  • More efficient comparison of numbers

    - by Pez Cuckow
    I have an array which is part of a small JS game I am working on I need to check (as often as reasonable) that each of the elements in the array haven't left the "stage" or "playground", so I can remove them and save the script load I have coded the below and was wondering if anyone knew a faster/more efficient way to calculate this. This is run every 50ms (it deals with the movement). Where bots[i][1] is movement in X and bots[i][2] is movement in Y (mutually exclusive). for (var i in bots) { var left = parseInt($("#" + i).css("left")); var top = parseInt($("#" + i).css("top")); var nextleft = left + bots[i][1]; var nexttop = top + bots[i][2]; if(bots[i][1]>0&&nextleft>=PLAYGROUND_WIDTH) { remove_bot(i); } else if(bots[i][1]<0&&nextleft<=-GRID_SIZE) { remove_bot(i); } else if(bots[i][2]>0&&nexttop>=PLAYGROUND_HEIGHT) { remove_bot(i); } else if(bots[i][2]<0&&nexttop<=-GRID_SIZE) { remove_bot(i); } else { //alert(nextleft + ":" + nexttop); $("#" + i).css("left", ""+(nextleft)+"px"); $("#" + i).css("top", ""+(nexttop)+"px"); } } On a similar note the remove_bot(i); function is as below, is this correct (I can't splice as it changes all the ID's of the elements in the array. function remove_bot(i) { $("#" + i).remove(); bots[i] = false; } Many thanks for any advice given!

    Read the article

  • Return parent of node in Binary Tree

    - by user188995
    I'm writing a code to return the parent of any node, but I'm getting stuck. I don't want to use any predefined ADTs. //Assume that nodes are represented by numbers from 1...n where 1=root and even //nos.=left child and odd nos=right child. public int parent(Node node){ if (node % 2 == 0){ if (root.left==node) return root; else return parent(root.left); } //same case for right } But this program is not working and giving wrong results. My basic algorithm is that the program starts from the root checks if it is on left or on the right. If it's the child or if the node that was queried else, recurses it with the child.

    Read the article

  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

    Read the article

  • Container div ignores height of floated elements

    - by Thomas
    Ok, so this seems like a really silly problem but I can't get my container div to inherit the height of the floated elements inside of it. Since I need to center the container div, I can't use float to fix this problem. Here is my css: #container { margin: 0 auto; width: 1000px; border-left: 1px solid #f1f1f1; border-right: 1px solid #f1f1f1; border-bottom: 1px solid #f1f1f1; } #focus { padding-left: 23px; width: 977px; padding-top: 20px; padding-bottom: 23px; border-bottom: 1px solid #f1f1f1; float: left; } .rslider { float: left; width: 600px; margin-left: 15px; } .welcome { float: left; width: 300px; } Html: <div id="container"> <div id="logo_block"> <a href="#"><img src="img/logo.jpg" alt="" /></a> </div> <div id="focus"> <div class="welcome"> <h1>All About This Page</h1> <p>Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem. Nulla consequat massa quis enim. Donec pede justo, fringilla vel, liquet nec, vulputate eget, arcu. In enim justo, rhoncus ut, imperdiet a, venenatis vitae, justo. Nullam dictum felis eu pede mollis pretium.</p> </div> <div class="rslider"> <img src="img/slider_image.jpg"> </div> </div> </div> Any ideas?

    Read the article

  • Reconciling a new BindingList into a master BindingList using LINQ

    - by Neo
    I have a seemingly simple problem whereby I wish to reconcile two lists so that an 'old' master list is updated by a 'new' list containing updated elements. Elements are denoted by a key property. These are my requirements: All elements in either list that have the same key results in an assignment of that element from the 'new' list over the original element in the 'old' list only if any properties have changed. Any elements in the 'new' list that have keys not in the 'old' list will be added to the 'old' list. Any elements in the 'old' list that have keys not in the 'new' list will be removed from the 'old' list. I found an equivalent problem here - http://stackoverflow.com/questions/161432/ - but it hasn't really been answered properly. So, I came up with an algorithm to iterate through the old and new lists and perform the reconciliation as per the above. Before anyone asks why I'm not just replacing the old list object with the new list object in its entirety, it's for presentation purposes - this is a BindingList bound to a grid on a GUI and I need to prevent refresh artifacts such as blinking, scrollbars moving, etc. So the list object must remain the same, only its updated elements changed. Another thing to note is that the objects in the 'new' list, even if the key is the same and all the properties are the same, are completely different instances to the equivalent objects in the 'old' list, so copying references is not an option. Below is what I've come up with so far - it's a generic extension method for a BindingList. I've put comments in to demonstrate what I'm trying to do. public static class BindingListExtension { public static void Reconcile<T>(this BindingList<T> left, BindingList<T> right, string key) { PropertyInfo piKey = typeof(T).GetProperty(key); // Go through each item in the new list in order to find all updated and new elements foreach (T newObj in right) { // First, find an object in the new list that shares its key with an object in the old list T oldObj = left.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(newObj, null))); if (oldObj != null) { // An object in each list was found with the same key, so now check to see if any properties have changed and // if any have, then assign the object from the new list over the top of the equivalent element in the old list foreach (PropertyInfo pi in typeof(T).GetProperties()) { if (!pi.GetValue(oldObj, null).Equals(pi.GetValue(newObj, null))) { left[left.IndexOf(oldObj)] = newObj; break; } } } else { // The object in the new list is brand new (has a new key), so add it to the old list left.Add(newObj); } } // Now, go through each item in the old list to find all elements with keys no longer in the new list foreach (T oldObj in left) { // Look for an element in the new list with a key matching an element in the old list if (right.First(call => piKey.GetValue(call, null).Equals(piKey.GetValue(oldObj, null))) == null) { // A matching element cannot be found in the new list, so remove the item from the old list left.Remove(oldObj); } } } } It can be called like this: _oldBindingList.Reconcile(newBindingList, "MyKey") However, I'm looking for perhaps a method of doing the same using LINQ type methods such as GroupJoin<, Join<, Select<, SelectMany<, Intersect<, etc. So far, the problem I've had is that each of these LINQ type methods result in brand new intermediary lists (as a return value) and really, I only want to modify the existing list for all the above reasons. If anyone can help with this, would be most appreciated. If not, no worries, the above method (as it were) will suffice for now. Thanks, Jason

    Read the article

  • CSS Position:Absolute with relative adjustment

    - by Gidiyo
    I am trying to do a vertical dropdown menu. This is my code .menu li:hover>ul{ position:absolute; display:inline; left:120px; top:100px;} I use position: Absolute to remove the sub-menu from the table, once the menu gets hovered. It appears that, if I do not indicate top or left property. The sub-menu will displayed relatively. Now I need to adjust the position relatively but seems that only the left property works. So my sub-menu left position is 120px relatively away from its original position. But the top is 100px away from the top of the window, rather then to the original position. How do I move the list up relative to it original position? I cant use position:relative because I need the sub-menu to be remove from the table.

    Read the article

  • I want to write a program to control the square moving by using WINAPI

    - by code_new
    This is the code as attempted so far: #include <windows.h> LRESULT CALLBACK WndProc (HWND, UINT, WPARAM, LPARAM) ; int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine, int iCmdShow) { static TCHAR szAppname[] = TEXT ("win0") ; WNDCLASS wndclass ; MSG msg ; HWND hwnd ; wndclass.style = CS_HREDRAW | CS_VREDRAW ; wndclass.cbWndExtra = 0 ; wndclass.cbClsExtra = 0 ; wndclass.lpfnWndProc = WndProc ; wndclass.lpszClassName = szAppname ; wndclass.lpszMenuName = NULL ; wndclass.hbrBackground = (HBRUSH) GetStockObject (WHITE_BRUSH) ; wndclass.hCursor = LoadCursor (NULL, IDC_ARROW) ; wndclass.hIcon = LoadIcon (NULL, IDI_APPLICATION) ; wndclass.hInstance = hInstance ; if (!RegisterClass (&wndclass)) { MessageBox (NULL, TEXT ("Register fail"), szAppname, 0) ; return 0 ; } hwnd = CreateWindow ( szAppname, TEXT ("mywin"), WS_OVERLAPPEDWINDOW, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, NULL, NULL, hInstance, NULL) ; ShowWindow (hwnd, iCmdShow) ; UpdateWindow (hwnd) ; while (GetMessage (&msg, NULL, 0, 0)) { TranslateMessage (&msg) ; DispatchMessage (&msg) ; } return msg.wParam ; } LRESULT CALLBACK WndProc (HWND hwnd, UINT message, WPARAM wParam, LPARAM lParam) { static int cxClient, cyClient, Left, Top, Right, Down ; PAINTSTRUCT ps ; HDC hdc ; RECT rect ; Right = 20 ; Down = 20 ; switch (message) { case WM_SIZE : cxClient = LOWORD (lParam) ; cyClient = HIWORD (lParam) ; return 0 ; case WM_PAINT : hdc = BeginPaint (hwnd, &ps) ; SetRect (&rect, Left, Top, Right, Down) ; FillRect (hdc, &rect, CreateSolidBrush (RGB (100, 100, 100))) ; EndPaint (hwnd, &ps) ; return 0 ; case WM_KEYDOWN : InvalidateRect (hwnd, &rect, TRUE) ; switch (wParam) { case VK_UP : if (Top - 20 < 0) { Top = 0 ; Down = 20 ; } else { Top -= 20 ; Down -= 20 ; } SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_DOWN : if (Down + 20 > cyClient) { Down = cyClient ; Top = Down - 20 ; } else { Down += 20 ; Top += 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_LEFT : if (Left - 20 < 0) { Left = 0 ; Right = 20 ; } else { Left -= 20 ; Right -= 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; case VK_RIGHT : if (Right + 20 > cxClient) { Right = cxClient ; Left = Right - 20 ; } else { Right += 20 ; Left += 20 ; }SendMessage (hwnd, WM_PAINT, wParam, lParam) ; break ; default : break ; } return 0 ; case WM_DESTROY : PostQuitMessage (0) ; return 0 ; } return DefWindowProc (hwnd, message, wParam, lParam); } I considered that I didn't deal the message well, so I can't control it.

    Read the article

  • CSS Horizontal sub menu - IE 6,7 both dont working, tried with whatever hover.

    - by SHAKTI
    I'm not expert about css menus. But I know basic system to make css menu. I used this system before and works, but this time it is not working. The site is http://www.uniethos.com. Please check this site This menu works with all other latest Browsers. But not with IE 6 & 7. I know IE6 don't support hover except anchor. So before I was using Whatever Hover. But this time it is not working and even with IE7. I don't know why its happening. May be there could be some problem with my css. Please check the css. If you don't have IE 6 or 7 installed you can run one from http://spoon.net/browsers/. Require to install one plugin. The CSS I'm using for the menu is .glossymenu{ background: #B4B3B3; height: 30px; width: 100%; padding: 0; margin: 0; display:inline-block; position:relative; } .glossymenu ul { list-style: none; padding: 0px; margin: 0; padding-left: 0px; } .glossymenu li ul { display:none; position:absolute; width: 80%; top:30px; left:0px; background-color:#5B0C10; border:0px; z-index: 99; } .glossymenu li li a { padding: 0px 10px 0px 10px; } .glossymenu li li a:hover { background : #871016; } .glossymenu li{ float:left; padding: 0; } .glossymenu li a{ float: left; display:block; position:relative; color:#FFF; text-decoration: none; font-family: sans-serif; font-size: 13px; font-weight: bold; padding:0 0 0 16px; /*Padding to accomodate left tab image. Do not change*/ height: 30px; line-height: 30px; text-align: center; cursor: pointer; } .glossymenu li a b{ float: left; display: block; padding: 0 24px 0 8px; /*Padding of menu items*/ } .glossymenu li.current a, .glossymenu li a:hover{ color: #FFF; background: #5B0C10; background-position: left; text-decoration: none; } .glossymenu li a:visited{ text-decoration: none; } .glossymenu ul li:hover ul { display: block; }

    Read the article

  • 2-col layout, one col scrolls vertical, other is fixed. Both scroll horizontal.

    - by Victor P
    Im trying to do a 2 column layout where the left column is very long vertically, and the right column is very long horizontally. When I scroll vertically, I want to move up and down the left column while the right one stays fixed. When I scroll horizontally, both columns move left-right (normal behaviour) I hope this drawing explain it more (sorry for the bad quality): Is this possible to do using only css? If not, how can I do it with javascript? Thanks

    Read the article

  • Please help fix and optimize this query

    - by user607217
    I am working on a system to find potential duplicates in our customers table (SQL 2005). I am using the built-in SOUNDEX value that our software computes when customers are added/updated, but I also implemented the double metaphone algorithm for better matching. This is the most-nested query I have created, and I can't help but think there is a better way to do it and I'd like to learn. In the inner-most query I am joining the customer table to the metaphone table I created, then finding customers that have identical pKey (primary phonetic key). I take that, union that with customers that have matching soundex values, and then proceed to score those matches with various text similarity functions. This is currently working, but I would also like to add a union of customers whose aKey (alternate phonetic key) match. This would be identical to "QUERY A" except to substitute on (c1Akey = c2Akey) for the join. However, when I attempt to include that, I get errors when I try to execute my query. Here is the code: --Create aggregate ranking select c1Name, c2Name, nDiff, c1Addr, c2Addr, aDiff, c1SSN, c2SSN, sDiff, c1DOB, c2DOB, dDiff, nDiff+aDiff+dDiff+sDiff as Score ,(sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 as [Rank] FROM ( --Create match scores for different fields SELECT c1Name, c2Name, c1Addr, c2Addr, c1SSN, c2SSN, c1LTD, c2LTD, c1DOB, c2DOB, dbo.Jaro(c1name, c2name) AS nDiff, dbo.JaroWinkler(c1addr, c2addr) AS aDiff, CASE WHEN c1dob = '1901-01-01' OR c2dob = '1901-01-01' OR c1dob = '1800-01-01' OR c2dob = '1800-01-01' THEN .5 ELSE dbo.SmithWaterman(c1dob, c2dob) END AS dDiff, CASE WHEN c1ssn = '000-00-0000' OR c2ssn = '000-00-0000' THEN .5 ELSE dbo.Jaro(c1ssn, c2ssn) END AS sDiff FROM -- Generate list of possible matches based on multiple phonetic matching fields ( select * from -- List of similar names from pKey field of ##Metaphone table --QUERY A BEGIN (select customers.custno as c1Custno, name as c1Name, haddr as c1Addr, ssn as c1SSN, lasttripdate as c1LTD, dob as c1DOB, soundex as c1Soundex, pkey as c1Pkey, akey as c1Akey from Customers WITH (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c1 JOIN (select customers.custno as c2Custno, name as c2Name, haddr as c2Addr, ssn as c2SSN, lasttripdate as c2LTD, dob as c2DOB, soundex as c2Soundex, pkey as c2Pkey, akey as c2Akey from Customers with (nolock) join ##Metaphone on customers.custno = ##Metaphone.custno) as c2 on (c1Pkey = c2Pkey) and (c1Custno < c2Custno) WHERE (c1Name <> 'PARENT, GUARDIAN') and c1soundex != c2soundex --QUERY A END union --List of similar names from pregenerated SOUNDEX field (select t1.custno, t1.name, t1.haddr, t1.ssn, t1.lasttripdate, t1.dob, t1.[soundex], 0, 0, t2.custno, t2.name, t2.haddr, t2.ssn, t2.lasttripdate, t2.dob, t2.[soundex], 0, 0 from Customers t1 WITH (nolock) join customers t2 with (nolock) on t1.[soundex] = t2.[soundex] and t1.custno < t2.custno where (t1.name <> 'PARENT, GUARDIAN')) ) as a ) as b where (sDiff+dDiff)*1.5 + (nDiff+dDiff)*1.5 + (nDiff+sDiff)*1.5 + aDiff *.5 + nDiff *.5 >= 7.5 order by [rank] desc, score desc Previously, I was using joins such as on c1.pkey = c2.pkey or c1.akey = c2.akey or c1.soundex = c2.soundex but the performance was horrendous, and using unions seems to be working a lot better. Out of 103K customers, tt is currently generating a list of 8.5M potential matches (based on the phonetic codes) in 2.25 minutes, and then taking another 2 to score, rank and filter those down to about 3000. So I am happy with the performance, I just can't help but think there is a better way to structure this, and I need help adding the extra union condition. Thanks!

    Read the article

  • problem in below table:i had table inside table .my inner table contains some text.

    - by Ayyappan.Anbalagan
    Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

    Read the article

  • 2012 EC Election Ballot open; Meet the Candidates Call tomorrow

    - by heathervc
    The JCP Executive Committee (EC) Election ballot is now open and all of the candidates' nominations materials are now available on JCP.org -- note that two new candidates were nominated late last week:  Liferay and North Sixty-One. It is shaping up to be an exciting election this year! The ratified candidates are:  Cinterion, Credit Suisse, Fujitsu and HP.The elected candidates are (9 candidates, 2 open seats):  Cisco Systems, CloudBees, Giuseppe Dell'Abate, Liferay, London Java Community, MoroccoJUG, North Sixty-One, Software AG, and Zero Turnaround. Tomorrow, 18 October, we will hold an open teleconference for the Java Community to meet the candidates and ask questions regarding their nomination.  We hope you will be able to participate in the call.  Should the time be inconvenient, a recording will be made available for download, and candidate questions may be posted on this blog entry or sent to [email protected]. Topic: Meet the EC Candidates Date: Thursday, October 18, 2012 Time: 9:30 am, Pacific Daylight Time (San Francisco, GMT-07:00) Meeting Number: 807 818 225 Meeting Password: MeetEC ------------------------------------------------------- To join the online meeting (Now from mobile devices) ------------------------------------------------------- 1. Go to https://jcp.webex.com/jcp/j.php?ED=186721592&UID=0&PW=NMmUzNjY5ZTMw&RT=MiM0 2. If requested, enter your name and email address. 3. If a password is required, enter the meeting password: MeetEC 4. Click "Join". To view in other time zones or languages, please click the link: https://jcp.webex.com/jcp/j.php?ED=186721592&UID=0&PW=NMmUzNjY5ZTMw&ORT=MiM0 ------------------------------------------------------- To join the audio conference only -------------------------------------------------------     +1 (866) 682-4770     Outside the US: global access numbers  https://www.intercallonline.com/portlets/scheduling/viewNumbers/listNumbersByCode.do?confCode=6279803 or +1 (408) 774-4073     Conference code: 9454597     Security code: JCPEC (52732)------------------------------------------------------- For assistance ------------------------------------------------------- 1. Go to https://jcp.webex.com/jcp/mc 2. On the left navigation bar, click "Support".

    Read the article

  • How could I evaluate this in code?

    - by WM
    There is a medieval puzzle about an old woman and a basket of eggs. On her way to market, a horseman knocks down the old woman and all the eggs are broken. The horseman will pay for the eggs, but the woman does not remember the exact number she had, only that when she took the eggs in pair, there was one left over; similarly, there was one left over when she took them three or five at a time. When she took them seven at a time, however, none were left. Write an application that can determine the smallest number of eggs the woman could have had. It might be a multiple of seven because there are no eggs left when it's seven at a time. But I have a problem. 49 eggs -1=2*24 49 eggs -1=3*16 49 eggs-4=5*9 49 eggs-0=7*7

    Read the article

  • appendTo() inside $.each in jquery seems to cause flicker....

    - by Pandiya Chendur
    appendTo() causes flicker when it is inside $.each.... $.each(jsob.Table, function(i, employee) { $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').appendTo('#ResultsDiv'); }); Right now i am appending every new div to #ResultsDiv inside$.each is it good/bad to do so... If it is bad What can be done to make my divs appendTo() after the loop so that i it wont flicker.... EDIT:(based on answer) var divs = ''; $.each(jsob.Table, function(i, employee) { divs += '<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>'; }); $("#ResultsDiv").append(divs); But that too doesn't stop the flicker...

    Read the article

  • How do I set command line mode vga=788 permanently?

    - by George
    I have a problem that is not of easy resolution, happen to tell... I have Installed Ubuntu 10.10 Server. I want to join to the system way vga=788, into the grub it changes without any problem editing the file grub.cfg, the problem is that editing the above mentioned file I join to the system way vga=788 (800x600) and then command line puts itself in way vga=792 (1280x1024). Is there any way of changing this configuration so that it is always vga=788? tanks. sorry for my english :D

    Read the article

  • CSS Positioning

    - by Davey
    Trying to mess with this wordpress theme and can't figure out why the sidebar is stacking underneath the content block. Any help would be very appreciated. http://www.buffalostreetbooks.com/events CSS: body { font-family: Arial, Helvetica, Verdana, Sans-serif; font-size: 10pt; background-color: #692022; background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/repeatflower.png"); } body,h1#blog-title { margin: 0; padding: 0; } a { color: blue; } a:hover { color: #FF8C00; } a img { border: 0 none; } #wrapper { width: 960px; margin: 0 auto; background-color: #F4FBF4; border-left: 1px solid #ccc; border-right: 1px solid #ccc; } #header { background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/headertime.png"); width:768px; height: 200px; } #inner-header { padding: 125px 1em 0; } h1#blog-title { font-size: 2em; } h1#blog-title a { color: #800000; } .entry-title a { color: #CD853F; } h1#blog-title a, .entry-title a, #footer a { text-decoration: none; } h1#blog-title a:hover, .entry-title a:hover, #footer a:hover { text-decoration: underline; } div.skip-link { display: none; } #menu { border-bottom: 1px solid #ccc; } #menu a { color: #000; } #menu a:hover { text-decoration: underline; } #menu li.current_page_item a, #menu li.current_page_item a:hover { background-color: #DFC28B; text-decoration: none; } #content { padding: 1em; width:600px; } .entry-title { font-size: 1.5em; margin: 1em 0 0 0; } abbr.published { color: #666; border: 0 none; } .entry-meta, .entry-date { color: #666; } #comments-list .avatar { float: left; margin-right: 1em; } #comments-list .n { font-weight: bold; } .entry-meta, .comment-meta { font-style: italic; } #comments-list p { clear: left; } #primary { padding-left: 1em; font-size: 0.9em; border-left: 1px solid #ccc; border-bottom: 1px solid #ccc; background-color: #FFFACD; } #footer { text-align: center; font-size: 0.8em; border-top: 1px solid #ccc; border-bottom: 1px solid #ccc; margin-bottom: 1em; } #inner-footer { padding: 1em 0; } .entry-meta, .entry-meta a, .comment-meta, .comment-meta a, .sidebar, .sidebar a, #footer, #footer a { color: #666; } /* LAYOUT: Two-Column (Right) DESCRIPTION: Two-column fluid layout with one sidebars right of content */ div#container { margin:0 0 0 0; width:960px; height:100%; } div#content { margin:0 0 0 0; } div.sidebar { overflow:hidden; width:280px; min-height:500px; clear:both; } div#secondary { clear:right; } div#footer { clear:both; width:100%; } /* Just some example content */ div#menu { height:2em; width:100%; } div#menu ul,div#menu ul ul { line-height:2em; list-style:none; margin:0; padding:0; } div#menu ul a { display:block; margin-right:1em; padding:0 0.5em; text-decoration:none; } div#menu ul ul ul a { font-style:italic; } div#menu ul li ul { left:-999em; position:absolute; } div#menu ul li:hover ul { left:auto; } .entry-title,.entry-meta { clear:both; } div#primary { } form#commentform .form-label { margin:1em 0 0; } form#commentform span.required { background:#fff; color:#c30; } form#commentform,form#commentform p { padding:0; } input#author,input#email,input#url,textarea#comme nt { padding:0.2em; } div.comments ol li { margin:0 0 3.5em; } textarea#comment { height:13em; margin:0 0 0.5em; overflow:auto; width:66%; } .alignright,img.alignright{ float:right; margin:1em 0 0 1em; } .alignleft,img.alignleft{ float:left; margin:1em 1em 0 0; } .aligncenter,img.aligncenter{ display:block; margin:1em auto; text-align:center; } div.gallery { clear:both; height:180px; margin:1em 0; width:100%; } p.wp-caption-text{ font-style:italic; } div.gallery dl{ margin:1em auto; overflow:hidden; text-align:center; } div.gallery dl.gallery-columns-1 { width:100%; } div.gallery dl.gallery-columns-2 { width:49%; } div.gallery dl.gallery-columns-3 { width:33%; } div.gallery dl.gallery-columns-4 { width:24%; } div.gallery dl.gallery-columns-5 { width:19%; } div#nav-above { margin-bottom:1em; } div#nav-below { margin-top:1em; } div#nav-images { height:150px; margin:1em 0; } div.navigation { height:1.25em; } div.navigation div.nav-next { float:right; text-align:right; } div.sidebar h3 { font-size:1.2em; } div.sidebar input#s { width:7em; } div.sidebar li { list-style:none; margin:0 0 2em; } div.sidebar li form { margin:0.2em 0 0; padding:0; } div.sidebar ul ul { margin:0 0 0 2em; } div.sidebar ul ul li { list-style:disc; margin:0; } div.sidebar ul ul ul { margin:0 0 0 0.5em; } div.sidebar ul ul ul li { list-style:circle; } div#menu ul li,div.gallery dl,div.navigation div.nav-previous { float:left; } input#author,input#email,input#url,div.navigation div { width:50%; } div.gallery *,div.sidebar div,div.sidebar h3,div.sidebar ul { margin:0; padding:0; }

    Read the article

  • iPhone/Objective-C struct question my own CGRectZero

    - by Mark
    I am designing a Padding struct as follows: /* Padding. */ struct CGPadding { CGFloat left; CGFloat top; CGFloat right; CGFloat bottom; }; typedef struct CGPadding CGPadding; CG_INLINE CGPadding CGPaddingMake(CGFloat left, CGFloat top, CGFloat right, CGFloat bottom) { CGPadding p; p.left = left; p.top = top; p.right = right; p.bottom = bottom; return p; } This all works perfectly well, the problem is how can I create a const CGPadding CGPaddingZero? If I do like this: const CGPadding CGPaddingZero = (CGPadding){0.0, 0.0, 0.0, 0.0}; It doesnt work. So what am I doing wrong?

    Read the article

  • Blackberry (Java) - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

    Read the article

  • Center big image in smaller div

    - by larin555
    I'm trying to align images in the center of a slider div. I'm adjusting FlexSlider css by the way. Here's my CSS code : .flexslider {margin: 0; padding: 0; width: 600px; height:480px; overflow:hidden;margin-left:auto;margin-right:auto;} .flexslider .slides > li {display: none; -webkit-backface-visibility: hidden;} /* Hide the slides before the JS is loaded. Avoids image jumping */ .flexslider .slides img {width:auto;height:100%; display: inline-block; text-align:center;} Everything is working like I want, except that I want wider image to be centered in the div. Right now it is left-aligned. I cannot use background-image by the way. Any ideas? I also tried applying to the .flexslider .slides img : margin-left:-50%...not working margin-left:auto and margin-right:auto...not working left:50% and right:50%...not working either

    Read the article

  • Rogue PropertyChanged notifications from ViewModel

    - by user1886323
    The following simple program is causing me a Databinding headache. I'm new to this which is why I suspect it has a simple answer. Basically, I have two text boxes bound to the same property myString. I have not set up the ViewModel (simply a class with one property, myString) to provide any notifications to the View for when myString is changed, so even although both text boxes operate a two way binding there should be no way that the text boxes update when myString is changed, am I right? Except... In most circumstances this is true - I use the 'change value' button at the bottom of the window to change the value of myString to whatever the user types into the adjacent text box, and the two text boxes at the top, even although they are bound to myString, do not change. Fine. However, if I edit the text in TextBox1, thus changing the value of myString (although only when the text box loses focus due to the default UpdateSourceTrigger property, see reference), TextBox2 should NOT update as it shouldn't receive any updates that myString has changed. However, as soon as TextBox1 loses focus (say click inside TextBox2) TextBox2 is updated with the new value of myString. My best guess so far is that because the TextBoxes are bound to the same property, something to do with TextBox1 updating myString gives TextBox2 a notification that it has changed. Very confusing as I haven't used INotifyPropertyChanged or anything like that. To clarify, I am not asking how to fix this. I know I could just change the binding mode to a oneway option. I am wondering if anyone can come up with an explanation for this strange behaviour? ViewModel: namespace WpfApplication1 { class ViewModel { public ViewModel() { _myString = "initial message"; } private string _myString; public string myString { get { return _myString; } set { if (_myString != value) { _myString = value; } } } } } View: <Window x:Class="WpfApplication1.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:local="clr-namespace:WpfApplication1" Title="MainWindow" Height="350" Width="525"> <Window.DataContext> <local:ViewModel /> </Window.DataContext> <Grid> <!-- The culprit text boxes --> <TextBox Height="23" HorizontalAlignment="Left" Margin="166,70,0,0" Name="textBox1" VerticalAlignment="Top" Width="120" Text="{Binding Path=myString, Mode=TwoWay}" /> <TextBox Height="23" HorizontalAlignment="Left" Margin="166,120,0,0" Name="textBox2" VerticalAlignment="Top" Width="120" Text="{Binding Path=myString, Mode=TwoWay}"/> <!--The buttons allowing manual change of myString--> <Button Name="changevaluebutton" Content="change value" Click="ButtonUpdateArtist_Click" Margin="12,245,416,43" Width="75" /> <Button Content="Show value" Height="23" HorizontalAlignment="Left" Margin="12,216,0,0" Name="showvaluebutton" VerticalAlignment="Top" Width="75" Click="showvaluebutton_Click" /> <Label Content="" Height="23" HorizontalAlignment="Left" Margin="116,216,0,0" Name="showvaluebox" VerticalAlignment="Top" Width="128" /> <TextBox Height="23" HorizontalAlignment="Left" Margin="116,245,0,0" Name="changevaluebox" VerticalAlignment="Top" Width="128" /> <!--simply some text--> <Label Content="TexBox1" Height="23" HorizontalAlignment="Left" Margin="99,70,0,0" Name="label1" VerticalAlignment="Top" Width="61" /> <Label Content="TexBox2" Height="23" HorizontalAlignment="Left" Margin="99,118,0,0" Name="label2" VerticalAlignment="Top" Width="61" /> </Grid> </Window> Code behind for view: namespace WpfApplication1 { /// <summary> /// Interaction logic for MainWindow.xaml /// </summary> public partial class MainWindow : Window { ViewModel viewModel; public MainWindow() { InitializeComponent(); viewModel = (ViewModel)this.DataContext; } private void showvaluebutton_Click(object sender, RoutedEventArgs e) { showvaluebox.Content = viewModel.myString; } private void ButtonUpdateArtist_Click(object sender, RoutedEventArgs e) { viewModel.myString = changevaluebox.Text; } } }

    Read the article

  • How do I remove the leaves of a binary tree?

    - by flopex
    I'm trying to remove all of the leaves. I know that leaves have no children, this is what I have so far. public void removeLeaves(BinaryTree n){ if (n.left == null && n.right == null){ n = null; } if (n.left != null) removeLeaves(n.left); if (n.right != null) removeLeaves(n.right); }

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 108 109 110 111 112 113 114 115 116 117 118 119  | Next Page >