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  • Jquery Text Slide in Effect

    - by user3718016
    I want to make text animation like this slide in from left. There are three text fields Sports Cargo Bag $14 Sale $25 I want these text to be set from jquery and slide in from the left like this link. This is my code JsFiddle html <div id="mainContainer"> <div id="logdo"> <img src="http://i.share.pho.to/7346a9ca_o.gif"/> </div> <div id="images"> <img id="introImg" src="http://i.share.pho.to/9064dfe4_o.jpeg"/></div> <div id="headlineText"> <p id="headline1Txt" ></p> <p id="headline2Txt" ></p> <p id="headline3Txt" ></p> </div> <button class="btn btn-primary" id="ctaBtn" type="button">SHOP NOW</button> </div> css * { margin:0; padding:0; } #mainContainer{ text-align: center; width:160px; height:600px; box-sizing:border-box; -moz-box-sizing:border-box; -webkit-box-sizing:border-box; border:5px solid #BACAE4; overflow: hidden; position: fixed; } #images{ position:absolute; top:200px; left:3px; right:1286px; Width:130px; height:152px; } #introImg{ position:absolute; top:40px; left:7px; right:11px; } #headlineText p { text-align: center; position: absolute; top:60px; left:-120px; Width:120px; height:269px; line-height:1.0; overflow:hidden; } #ctaBtn{ position:absolute; top:540px; left:26px; right:0px; Width:106px; height:28px; }

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  • CSS Not Centering Container

    - by user269799
    I have a container div. Width: 80%, margin-left: 10% and margin-right 10%. The problem is, the container is displaying to the left in all the browsers I check. If I change the value of margin-left to 20%, it looks ok. I will supply code if necessary but is there anything obviously wrong here? Isn't 80 with a margin of 10 on each side correct to center a div? GF

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  • Shift Operators in C++

    - by Codeguru
    If the value after the shift operator is greater than the number of bits in the left-hand operand, the result is undefined. If the left-hand operand is unsigned, the right shift is a logical shift so the upper bits will be filled with zeros. If the left-hand operand is signed, the right shift may or may not be a logical shift (that is, the behavior is undefined). Can somebody explain me what the above lines mean??

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  • CSS 3 columns, why is the third column taking over the other 2?

    - by Matt Dawdy
    Here is the smallest amount of code that clearly illustrates my problem: <html> <body> <div style="float: left; width: 200px;">One</div> <div style="float: left; width: 200px;">Two</div> <div style="background-color: #f0f;">Three</div> </body> </html> The first 2 divs are supposed to be 2 left columns. The 3rd should take up the rest of the page. Eventually, I'm going to add options to hide and show the 2 columns on the left. But, why is the color purple extending all the way to the browser's left edge? I am trying to get it to start at the word "Three".

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  • Swap function for a char*

    - by Martin
    I have the simple function below which swap two characters of an array of characters (s). However, I am getting a "Unhandled exception at 0x01151cd7 in Bla.exe: 0xC0000005: Access violation writing location 0x011557a4." error. The two indexes (left and right) are within the limit of the array. What am I doing wrong? void swap(char* s, int left, int right) { char tmp = s[left]; s[left] = s[right]; s[right] = tmp; } swap("ABC", 0, 1); I am using VS2010 with unmanaged C/C++. Thanks!

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  • Click event for dynamically added li element?

    - by user1774460
    I am having totally 20 links.First 10 links directly visible to user and remaining 10 links shown when user hover the down arrow image(used for hover). When user click any one hover link, the link till the currently clicked are moved to left side(another down arrow used for add the right side links to left side dynamically by creating li). This one working fine.But this is not working as vice versa. (i.e)When i click left side link it should navigate to right side.Click event not working for li element that i created dynamically. Please Can any one help for me?????? My sample Code: //To append the line from right hover to looplink div $('#loop_link').append(''+$('#pagelinkli_'+val3).html()+''); //To hide the link in right hover div once it selected and appended in loop link div $('#pagelink_a #pagelinkli_'+val3).css('display','none'); //This line to move the link from loop link to left hover div $('#pagelink_a_left ul').prepend((''+$('#pagelinkli_'+val6).html()+'')); //This line to hide the link in looplink div $('#loop_link #pagelinkli_'+val6).css('display','none'); This code is like navigating link from right hover to tab and from tab to left hover and vice versa.....

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  • Insertion into BST without header Node JAVA

    - by Petiatil
    I am working on a recursive insertion method for a BST. This function is suppose to be a recursive helper method and is in a private class called Node. The Node class is in a class called BinarySearchTree which contains an instance variable for the root. When I am trying to insert an element, I get a NullPointerException at : this.left = insert(((Node)left).element); I am unsure about why this occurs. If I understand correctly, in a BST, I am suppose to insert the item at the last spot on the path transversed. Any help is appreciated! private class Node implements BinaryNode<E> { E item; BinaryNode<E> left, right; public BinaryNode<E> insert(E item) { int compare = item.compareTo(((Node)root).item); if(root == null) { root = new Node(); ((Node)root).item = item; } else if(compare < 0) { this.left = insert(((Node)left).item); } else if(compare > 0) { this.right = insert(((Node)right).item); } return root; } }

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  • How to get the xy coordinate of an image=(0,0) from in the Big box(div)

    - by Farah fathiah
    I have a problem..I'm using visual studio 2008... I want to ask, how to get the xy coordinate of an image=(0,0) from in the Big box(div)??? because when the image is drag to the end of the box it will give me x=8 and y=8...instead of x=0 and y=0... Please help me!!! Tq... Here is the code: $('#dragThis').draggable({ cursor: 'move', // sets the cursor apperance containment: '#box', drag: function() { var offset = $(this).offset(); var xPos = Math.abs(offset.left); var yPos = Math.abs(offset.top); $('#posX').text('x: ' + xPos); $('#posY').text('y: ' + yPos); }, stop: function(event, ui) { // Show dropped position. var Stoppos = $(this).position(); var left = Math.abs(Stoppos.left); var top = Math.abs(Stoppos.top); $('#posX').text('left: ' + left); $('#posY').text('top: ' + top); } }); http://jsfiddle.net/qx5K7/

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  • two div boxes [1st float, 2nd clear], margin on 2nd doesn't seem to push off first

    - by mach77
    In the code below I have two div boxes. The first is float:left, the second has clear:left so that it sits below the first. My question is why does margin-top:20px not push off the first div? <head> <style> div { width:100px; height:100px; background-color:green; } #box1 { float:left; } #box2 { background-color:red; clear:left; margin-top:20px; } </style> </head> <body> <div id="box1"></div> <div id="box2"></div> </body>

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  • Extended URL php

    - by web.ask
    I have a problem with the extended url here in php. I'm not even sure if it's called extended url. I was wondering if someone can help me since i'm no good with PHP. I have a php page the careers.php it shows the career listing but when I click on Learn more link it goes to http(dot)localhost/houseofpatel/jobs/4/Career-4 but it outputs an "Object not found". Does xampplite have something to do with this? or is it just the codes? I also have the breadcrumb.php in here. Please see code below: session_start(); include("Breadcrumb.php"); $trail = new Breadcrumb(); $trail->add('Careers', $_SERVER['PHP_SELF'], 1); $trail -> output(); # REMOVE SPECIAL CHARACTERS $sPattern = array('/[^a-zA-Z0-9 -]/', '/[ -]+/', '/^-|-$/'); $sReplace = array('', '-', ''); mysql_query("SET CHARACTER_SET utf8"); //$query = "SELECT * FROM careers_mst WHERE status = 1 ORDER BY dateposted DESC LIMIT 0, 4"; if(!$_GET['jobs']){ $jobsPerPage = 4; }else{ $jobsPerPage = $_GET['jobs']; } if(!$_GET['page']){ $currPage = 1; $showMoreJobs = true; }else{ $currPage = $_GET['page']; $showMoreJobs = false; } $offset = ($currPage - 1 )* $jobsPerPage; $query = "SELECT * FROM careers_mst WHERE status = 1 ORDER BY dateposted"; $process = mysql_query($query); if(@mysql_num_rows($process) > 0){ $totalRows = @mysql_num_rows($process); $query2 = "SELECT * FROM careers_mst WHERE status = 1 ORDER BY dateposted DESC LIMIT $offset, $jobsPerPage"; $process2 = mysql_query($query2); if(@mysql_num_rows($process2) > 0){ $pagNav = pageNavigator($totalRows,$jobsPerPage,$currPage,''); while($row = @mysql_fetch_array($process2)){ $id = $row[0]; $title = stripslashes($row['title']); $title1 = preg_replace($sPattern, $sReplace, $title); $description = stripslashes($row['description']); $description1 = substr($description, 0, 200); $careers_list .= ' <div class="left" style="width:340px; padding-left:10px;"> <p><span class="blue"><strong>'.$title.'</strong></span></p> '.$description1.'... <p><a href="jobs/'.$id.'/'.$title1.'" title="Learn more">[ Learn More ]</a></p> </div>'; } /*$careers_list .= ' <div class="left" style="width: 100%; margin-top:15px;"> <p><a href="more-jobs" title="More Job Opennings">MORE JOB OPENNINGS >> </a></p> <div class="divider left"></div> </div>'; */ if($showMoreJobs){ if($totalRows > $jobsPerPage){ $currPage++; } $jobNav = "<a href=careers.php?page=$currPage title='More Job Opennings'>MORE JOB OPENNINGS >> </a>"; }else{ $jobNav = "$pagNav"; } $careers_list .= "<div class='left' style='width: 100%; margin-top:15px;'> <p>$jobNav</p> <div class='divider left'></div> </div>"; } }

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  • Cannot bind OSX to AD

    - by erotsppa
    I'm trying to get an mac mini running snow leopard server to join a windows domain here. The windows domain server is running Windows server 2008. When I go to "Accounts" in my System Preferences, and lick on "Join", I get this error: "Unable to add server. Node name wasn't found. (2000)" In my console messages I find this: 10-04-06 11:42:25 AM System Preferences1452 -[ODCAddServerSheetController handleOtherActionError: gotError: Error Domain=com.apple.OpenDirectory Code=2000 UserInfo=0x2004f2f80 "Custom call 82 to Active Directory failed.", Node name wasn't found. I specified a FQDN for the domain server, so I am totally confused as to why it would list "domain = com.apple...." in that error. I've tried firing up the Directory Utility and trying to join a domain via the Active Directory option there. Again I fill in the FQDN, and the proper administrator/password acount info. Now I get a different error: "Invalid Domain An invalid Domain and Forest combination was specified. You should enter a fully qualified DNS name for the domain and forest (e.g., ads.company.com)." If anyone has any pointers or suggestions this would be appreciated.

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  • Changing subnet-mask of class-c network host to 255.255.0.0

    - by Prashant Mandhare
    We have a existing class-c network with IP address range 11.22.33.44/24 (just for example). My domain controller has been configured within this subnet. So all servers within this subnet have subnet mask configured to 255.255.255.0. Now we have got a new subnet with IP address 11.22.88.99/24 (note that only last 2 octets have changed). I want all new hosts in this new subnet to join my existing DC. For this we have configured firewall properly so allow this. (so there is no issue with firewall). But initially I was not able to join hosts in new subnet in existing domain. Later I doubted on subnet mask used in domain controller (255.255.255.0) and for testing purpose I changed it to 255.255.0.0, it worked like charm, i was able to join subnet-2 hosts in subnet-1 domain. Now i am wondering whether it will be good practice to change subnet mask of a class-c network to 255.255.0.0? Can any issues arise due to this? Experts please provide your opinion.

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  • Linking to a chat room via XMPP: URI

    - by Coderer
    I found out how to link directly to a chat room on a Jabber conference server -- it took a bit of digging, and I wound up actually looking at the spec before I was sure I was doing it right. I confirmed here, so I'm pretty sure I've got it. The results, though, are puzzling. If I click a link of the style xmpp:[email protected] I get a new chat session with user "dude" at example.com, as expected. If I tack on a nonsense query (xmpp:[email protected]?foobar), it's ignored, which is what the spec says should happen. However, if I use xmpp:[email protected]?join, as in the link above, nothing happens. I dug a little deeper, and found out that on my (Linux) system, xmpp URIs are handled via purple-url-handler, so I dropped to a terminal and ran it manually. The result was that any xmpp URI ran fine except one that includes a ?join query. The ?join query results in a dbus crash, pointing specifically to line 2356 of dbus-message.c -- a little Googling suggests this probably is dbus's less-than-elegant way of telling me that somebody is using dbus incorrectly. Am I crafting my link correctly? Is this an OS or maybe application issue? Does this work on other platforms / browsers / etc? More importantly, is there any easy way to fix it?

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  • Talk on multiple IRC channels at once?

    - by TwoPixelGrid
    I seem to remember, back in '91 or so, that the console-based IRCII implemention on the Solaris box that first got me on the net would let me /Join multiple channels on a given network such that, as new channels were joined, they would start scrolling to the single console view. Let's call it the 'interleaved conversation' chat paradigm. Am I rembering this correctly? More importantly, is there a modern way of doing this in any of the GUI-based clients? I'm surprised this isn't a common desire/feature because I think it would greatly improve the experience, especially on channels with high SNR. For example, If I'm working on a project I may connect to Freenode and join : #Qt,#OpenGL,#C++. As it is now, with mIRC,Xchat, I have to manually flip between pages just to see whats being said and to reply. What I envision would go more like this (using only 2 channels for simplicity) /join #QT #OpenGL < [QT] QtChannelUser: Hello TwoPixelGrid. < [OpenGL] OpenGLChannelUser: Hi there TwoPixelGrid. @QT: Hi QtChannelUser @OpenGL: Hello againOpenGLChannelUser And this message is going out to all my channels. Do I have to write a new client or is this already out there?

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  • Cannot access domain from windows 2003 client

    - by Peuge
    Hey all, First off I am a novice at AD and DNS so please bear with me. This is my current situation: I have one server which is a DC and DNS server (win2k3) - Machine 1. I have another machine which is trying to join this domain - Machine2. This machine is also a win2k3 server. This is what I have done so far: I have setup DNS on the DC and its tcp/ip dns is pointing to itself. On machine2 I have set its dns to point to the dc. The DNS has been setup with a forward lookup zone with the same name as the domain (accdirect.com). I can ping machine1 from the machine2 by its FQDN and ip. I have set up forwarders on the DC for our ISP dns and can browse the internet on both machines. In the DNS mmc on the DC I can see a host (A) has been created for machine2. The problem is I still cannot join the domain. When I try join the domain via my computer - properties then it brings up the username/password box and after I go "ok" it says cannot find domain accdirect.com If I run this from machine2 dcdiag /s:accdirect.com /u:accdirect.com\admin /p: then I get the following: Performing initial setup: ** Warning: could not confirm the identity of this server in the directory versus the names returned by DNS servers. If there are problems accessing this directory server then you may need to check that this server is correctly registered with DNS [accdirect.com] Directory Binding Error 1722: Win32 Error 1722 This may limit some of the tests that can be performed. Done gathering initial info. On the dc all dcdiag and netdiag results pass. If anyone could help me I would really appreciate this! Sorry if any of my terminology is a bit off, I have only been doing this for two days. thanks Peuge

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  • Creating Active Directory on an EC2 box

    - by Chiggins
    So I have Active Directory set up on a Windows Server 2008 Amazon EC2 server. Its set up correctly I think, I never got any errors with it. Just to test that I got it all set up correctly, I have a Windows 7 Professional virtual machine set up on my network to join to AD. I set the VM to use the Active Directory box as its DNS server. I type in my domain to join it, but I get the following error: DNS was successfully queried for the service location (SRV) resource record used to locate a domain controller for domain "ad.win.chigs.me": The query was for the SRV record for _ldap._tcp.dc._msdcs.ad.win.chigs.me The following domain controllers were identified by the query: ip-0af92ac4.ad.win.chigs.me However no domain controllers could be contacted. Common causes of this error include: - Host (A) or (AAAA) records that map the names of the domain controllers to their IP addresses are missing or contain incorrect addresses. - Domain controllers registered in DNS are not connected to the network or are not running. It seems that I can talk to Active Directory, but when I'm trying to contact the Domain Controller, its giving a private IP to connect to, at least thats what I can make out of it. Here are some nslookup results. > win.chigs.me Server: ec2-184-73-35-150.compute-1.amazonaws.com Address: 184.73.35.150 Non-authoritative answer: Name: ec2-184-73-35-150.compute-1.amazonaws.com Address: 10.249.42.196 Aliases: win.chigs.me > ad.win.chigs.me Server: ec2-184-73-35-150.compute-1.amazonaws.com Address: 184.73.35.150 Name: ad.win.chigs.me Address: 10.249.42.196 win.chigs.me and ad.win.chigs.me are CNAME's pointing to my EC2 box. Any idea what I need to do so that I can join my virtual machine to the EC2 Active Directory set up I have? Thanks!

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  • Safe use of Update-FormatData?

    - by Steve B
    In a custom PowerShell module, I have at the top of my module definition this code: Update-FormatData -AppendPath (Join-Path $psscriptroot "*.ps1xml") This is working fine as all .ps1xml files are loaded. However, the module is sometimes loaded using Import-Module MyModule -Force (actually, this is in the install script of the module). In this case, the call to Update-FormatData fails with this error : Update-FormatData : There were errors in loading the format data file: Microsoft.PowerShell, c:\pathto\myfile.Types.ext.ps1xml : File skipped because it was already present from "Microsoft.PowerShell". At line:1 char:18 + Update-FormatData <<<< -AppendPath "c:\pathto\myfile.Types.ext.ps1xml" + CategoryInfo : InvalidOperation: (:) [Update-FormatData], RuntimeException + FullyQualifiedErrorId : FormatXmlUpateException,Microsoft.PowerShell.Commands.UpdateFormatDataCommand Is there a way to safely call this command? I know I can call Update-FormatData with no parameters, and it will update any known .ps1xml file, but this would work only if the file has already been loaded. Can I list somewhere the loaded format data files? Here is a bit of background: I'm building a custom module that is installed using a script. The install script looks like : [CmdletBinding(SupportsShouldProcess=$true,ConfirmImpact="High")] param() process { $target = Join-Path $PSHOME "Modules\MyModule" if ($pscmdlet.ShouldProcess("$target","Deploying MyModule module")) { if(!(Test-Path $target)) { new-Item -ItemType Directory -Path $target | Out-Null } get-ChildItem -Path (Split-Path ((Get-Variable MyInvocation -Scope 0).Value).MyCommand.Path) | copy-Item -Destination $target -Force Write-Host -ForegroundColorWhite @" The module has been installed. You can import it using : Import-Module MyModule Or you can add it in your profile ($profile) "@ Write-Warning "To refresh any open PowerShell session, you should run ""Import-Module MyModule -Force"" to reload the module" Import-Module MyModule -Force Write-Warning "This session has been refreshed." } } MyModule defines, as first statement, this line : Update-FormatData -AppendPath (Join-Path $psscriptroot "*.ps1xml") As I updated my $profile to always load this module, the Update-Path command has been called when I run the install script. In the install script, I force import the module, which be fire again the module, and then, the Update-Path call

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  • How to resume XMPP groupchat window in Irssi (using bitlbee)?

    - by mcnesium
    I use Bitlbee to chat in XMPP-networks within my IRC-client Irssi. This works great so far, and recently I started using XMPP Multi User Chats as an alternative to IRC-channels. I set up a channel using chat add <account> <[email protected]> in the &bitlbee control window, set chan <room> set autojoin true and entered /join #room in the &bitlbee window to join that groupchat. It then appears as a unique Irssi window in the status bar. This seems to work ok too, but with one exception: Since I idle in the channels 24/7 my irssi has to cope with the every-night-24h-DSL-disconnection by the ISP. After it automatically reconnects, it does kind of rejoin that XMPP-groupchat, but the traffic of the groupchat does not go back to the unique irssi window, but keeps flooding &bitlbee with messages from root telling me about a Groupchat Message from unknown JID <jid>: <message> - which is the traffic of the groupchat. The unique groupchat window is gone after the reconnect, and I will again have to go /join #room in &bitlbee to get it back. Even worse, the window number is unused before I rejoin the groupchat, and if I get a query from any network, the window nests in that unused window spot, so I will first have to remove that query from the spot, and then move the rejoined groupchat to that window number. I want my groupchat window to resume after the reconnect just like every other IRC channel too. How can I get this done? Any ideas?

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  • Getting Started with Boxee

    - by DigitalGeekery
    Boxee is a free Media PC application that runs on Windows, Mac, and Ubuntu Linux. With Boxee, you can integrate online video, music and pictures, with your own local media and social networking. Today we are going to take a closer look at Boxee and some of it’s features. Note: We used Windows 7 for this tutorial. Your experience on a Mac or Ubuntu Linux build may vary slightly. Hardware Requirements x86 (Intel/AMD processor) based system running at 1.0GHz or greater 512MB system memory (RAM) or more Video card capable of OpenGL 1.4, Direct X 9.0 Software Requirements Mac OS X 10.4+ (Intel based processor) Ubuntu Linux 9.04+ x86 only Windows XP / Vista / 7 (64 bit in Vista or 7) Installing Boxee Before downloading and installing Boxee, you’ll need to register for a free account. (See link below) Once your account is registered and verified, you’ll be able to log in and download the application. Installation is pretty straightforward…just take the defaults. Boxee will open in full screen mode and you’ll be prompted to login with your username and password. Before you login, you may want to take a moment to click on the “Guide” icon and learn a bit about navigating in Boxee. Some basic keyboard navigation is as follows. Move right, left, up, & down with the arrow keys. Hit “Enter” to make a selection, the forward slash key “\” to toggle between full screen and windowed mode, and “Esc” to go back to the previous screen. For Playback, the volume is controlled by plus & minus (+/-) keys, you can Play / Pause using the spacebar, and skip using the arrow keys. Boxee will also work with any infrared remote. If you have an iPhone or iPod Touch you can download software to enable them as a Boxee remote. If you’re using a mouse and keyboard, hover over the username and password boxes to enter your login credentials. If using a a remote, click your OK button and enter credentials with the on screen keyboard. Click “Done” when finished.   When you are ready to login, enter your credentials and click “Login.” On first login, you’ll be prompted to calibrate your screen. If you choose “Skip” you can always calibrate your screen later under Settings > Appearance > Screen. When Boxee opens, you’ll be greeted by the Home screen. To the left will be your Feeds. This will be any recommended content from friends on Boxee, and social networks such as Facebook and Twitter. Although, when you first login, it will mainly be info from the Boxee staff. You’ll have “Featured” content in the center and your Queue on the right. You’ll also have the Menu along the top.   Pop Up Menu The Pop Menu can be accessed by hitting the “Esc” key, or back on your remote. Depending on where you are located in Boxee, you may have to hit it a few time to “back out” to the Pop Up menu. From the Pop Up Menu, you can easily access any of the resources, settings, and favorites. Queue The Queue is your playlist of TV shows, movies, or Internet videos you wish to watch. When you find an offering you’d like to watch, select it and then click “Add to Queue.” The selected item will be added to your Queue and can be accessed at any time from the Menu. TV Show Library The TV Show library can contain files from your local hard drive or streaming content from the Web. Boxee pulls content from a variety of online locations such as Hulu and TV network sites. Click on the show to see which specific episodes are currently available. To search for your favorite shows, click on the yellow arrow to the left, or navigate to the left with your keyboard or remote. Enter your selection into the search box. My Apps By default, the “My Apps” section includes a list of the most popular apps, such as Netflix, Pandora, YouTube, and others. You can remove Apps from “My Apps,” or add new Apps from the Apps Library.   To access all the available Apps, click on the left arrow button, or click on the yellow arrow at the left, then select “App Library.” Choose an App from the Library and click it to open… … and then select “Add to My Apps.” Or, you can click start to play the App if you don’t wish to Add it to your “My Apps.”   Music, Pictures, and Movies Boxee will scan your PC for movies, pictures, and music. You can choose to scan specific folders by clicking on “Scan Media Folders…” … or from the Pop Up Menu, selecting Settings > Media, and then browsing for your media.   Conclusion Boxee to be a great way to integrate your local media with online streaming content. It can be run as an application on your home PC, or as a stand alone media PC. It should also be noted, however, that your access to online content will vary depending on your country. If you are a Windows Media Center user and and want to add the additional features of Boxee, check out our article on integrating Boxee with Windows 7 Media Center. Download Boxee Similar Articles Productive Geek Tips Integrate Boxee with Media Center in Windows 7Disable Fast User Switching on Windows XPOops! Sorry About the Feed ErrorsDisplay a list of Started Services from the Command Line (Windows)Feedburner to Google: Worst Transition Ever. TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Discover New Bundled Feeds in Google Reader Play Music in Chrome by Simply Dragging a File 15 Great Illustrations by Chow Hon Lam Easily Sync Files & Folders with Friends & Family Amazon Free Kindle for PC Download Stretch popurls.com with a Stylish Script (Firefox)

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  • UV texture mapping with perspective correct interpolation

    - by Twodordan
    I am working on a software rasterizer for educational purposes and I am having issues with the texturing. The problem is, only one face of the cube gets correctly textured. The rest are stretched edges: You can see the running program online here. I have used cartesian coordinates, and all I do is interpolate the uv values along the scanlines. The general formula I use for interpolating the uv coordinates is pretty much the one I use for the z-buffering interpolation and looks like this (in this case for horizontal scanlines): u_Slope = (right.u - left.u) / (triangleRight_x - triangleLeft_x); v_Slope = (right.v - left.v) / (triangleRight_x - triangleLeft_x); //[...] new_u = left.u + ((currentX_onScanLine - triangleLeft_x) * u_Slope); new_v = left.v + ((currentX_onScanLine - triangleLeft_x) * v_Slope); Then, when I add each point to the pixel buffer, I restore z and uv: z = (1/z); uv.u = Math.round(uv.u * z *100);//*100 because my texture is 100x100px uv.v = Math.round(uv.v * z *100); Then I turn the u v indexes into one index in order to fetch the correct pixel from the image data (which is a 1 dimensional px array): var index = texture.width * uv.u + uv.v; //and the rest is unimportant imagedata[index].RGBA bla bla The interpolation formula is correct considering the consistency of the texture (including the straight stripes). However, I seem to get quite a lot of 0 values for either u or v. Which is probably why I only get one face right. Furthermore, why is the texture flipped horizontally? (the "1" is flipped) I must get some sleep now, but before I get into further dissecting of every single value to see what goes wrong, Can someone more experienced guess why might this be happening, just by looking at the cube? "I have no idea what I'm doing" (it's my first time implementing a rasterizer). Did I miss an important stage? Thanks for any insight. PS: My UV values are as follows: { u:0, v:0 }, { u:0, v:0.5 }, { u:0.5, v:0.5 }, { u:0.5, v:0 }, { u:0, v:0 }, { u:0, v:0.5 }, { u:0.5, v:0.5 }, { u:0.5, v:0 }

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  • Setting up OpenGL camera with off-center perspective

    - by user5484
    Hi, I'm using OpenGL ES (in iOS) and am struggling with setting up a viewport with an off-center distance point. Consider a game where you have a character in the left hand side of the screen, and some controls alpha'd over the left-hand side. The "main" part of the screen is on the right, but you still want to show whats in the view on the left. However when the character moves "forward" you want the character to appear to be going "straight", or "up" on the device, and not heading on an angle to the point that is geographically at the mid-x position in the screen. Here's the jist of how i set my viewport up where it is centered in the middle: // setup the camera // glMatrixMode(GL_PROJECTION); glLoadIdentity(); const GLfloat zNear = 0.1; const GLfloat zFar = 1000.0; const GLfloat fieldOfView = 90.0; // can definitely adjust this to see more/less of the scene GLfloat size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect; rect.origin = CGPointMake(0.0, 0.0); rect.size = CGSizeMake(backingWidth, backingHeight); glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glMatrixMode(GL_MODELVIEW); // rotate the whole scene by the tilt to face down on the dude const float tilt = 0.3f; const float yscale = 0.8f; const float zscale = -4.0f; glTranslatef(0.0, yscale, zscale); const int rotationMinDegree = 0; const int rotationMaxDegree = 180; glRotatef(tilt * (rotationMaxDegree - rotationMinDegree) / 2, 1.0f, 0.0f, 0.0f); glTranslatef(0, -yscale, -zscale); static float b = -25; //0; static float c = 0; // rotate by to face in the direction of the dude float a = RADIANS_TO_DEGREES(-atan2f(-gCamera.orientation.x, -gCamera.orientation.z)); glRotatef(a, 0.0, 1.0, 0.0); // and move to where it is glTranslatef(-gCamera.pos.x, -gCamera.pos.y, -gCamera.pos.z); // draw the rest of the scene ... I've tried a variety of things to make it appear as though "the dude" is off to the right: - do a translate after the frustrum to the x direction - do a rotation after the frustrum about the up/y-axis - move the camera with a biased lean to the left of the dude Nothing i do seems to produce good results, the dude will either look like he's stuck on an angle, or the whole scene will appear tilted. I'm no OpenGL expert, so i'm hoping someone can suggest some ideas or tricks on how to "off-center" these model views in OpenGL. Thanks!

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  • Leaving a SQL Server DBA Job Gracefully

    You’re leaving your current employer for a new opportunity and want to make the move as smooth as possible. You don’t want to burn your bridges and want to make sure that everything you’ve left behind can be managed by the people you’ve left behind or the DBA who is replacing you. So, you’ve done your handover documentation and trained up the new guy. You definitely don’t want to be that DBA who is cursed the week after they leave when their network account is disabled and a bunch of stuff ‘breaks’.

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  • Move Window Buttons Back to the Right in Ubuntu 10.04

    - by Trevor Bekolay
    One of the more controversial changes in the Ubuntu 10.04 beta is the Mac OS-inspired change to have window buttons on the left side. We’ll show you how to move the buttons back to the right. Before While the change may or may not persist through to the April 29 release of Ubuntu 10.04, in the beta version the maximize, minimize, and close buttons appear in the top left of a window. How to move the window buttons The window button locations are dictated by a configuration file. We’ll use the graphical program gconf-editor to change this configuration file. Press Alt+F2 to bring up the Run Application dialog box, enter “gconf-editor” in the text field, and click on Run. The Configuration Editor should pop up. The key that we want to edit is in apps/metacity/general. Click on the + button next to the “apps” folder, then beside “metacity” in the list of folders expanded for apps, and then click on the “general” folder. The button layout can be changed by changing the “button_layout” key. Double-click button_layout to edit it. Change the text in the Value text field to: menu:maximize,minimize,close Click OK and the change will occur immediately, changing the location of the window buttons in the Configuration Editor. Note that this ordering of the window buttons is slightly different than the typical order; in previous versions of Ubuntu and in Windows, the minimize button is to the left of the maximize button. You can change the button_layout string to reflect that ordering, but using the default Ubuntu 10.04 theme, it looks a bit strange. If you plan to change the theme, or even just the graphics used for the window buttons, then this ordering may be more natural to you. After After this change, all of your windows will have the maximize, minimize, and close buttons on the right. What do you think of Ubuntu 10.04’s visual change? Let us know in the comments! Similar Articles Productive Geek Tips Move a Window Without Clicking the Titlebar in UbuntuBring Misplaced Off-Screen Windows Back to Your Desktop (Keyboard Trick)Keep the Display From Turning Off on UbuntuPut Close/Maximize/Minimize Buttons on the Left in UbuntuAllow Remote Control To Your Desktop On Ubuntu TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional SpeedyFox Claims to Speed up your Firefox Beware Hover Kitties Test Drive Mobile Phones Online With TryPhone Ben & Jerry’s Free Cone Day, 3/23/10 New Stinger from McAfee Helps Remove ‘FakeAlert’ Threats Google Apps Marketplace: Tools & Services For Google Apps Users

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  • SQL SERVER – Order By Numeric Values Formatted as String

    - by pinaldave
    When I was writing this blog post I had a hard time to come up with the title of the blog post so I did my best to come up with one. Here is the reason why? I wrote a blog post earlier SQL SERVER – Find First Non-Numeric Character from String. One of the questions was that how that blog can be useful in real life scenario. This blog post is the answer to that question. Let us first see a problem. We have a table which has a column containing alphanumeric data. The data always has first as an integer and later part as a string. The business need is to order the data based on the first part of the alphanumeric data which is an integer. Now the problem is that no matter how we use ORDER BY the result is not produced as expected. Let us understand this with example. Prepare a sample data: -- How to find first non numberic character USE tempdb GO CREATE TABLE MyTable (ID INT, Col1 VARCHAR(100)) GO INSERT INTO MyTable (ID, Col1) SELECT 1, '1one' UNION ALL SELECT 2, '11eleven' UNION ALL SELECT 3, '2two' UNION ALL SELECT 4, '22twentytwo' UNION ALL SELECT 5, '111oneeleven' GO -- Select Data SELECT * FROM MyTable GO The above query will give following result set. Now let us use ORDER BY COL1 and observe the result along with Original SELECT. -- Select Data SELECT * FROM MyTable GO -- Select Data SELECT * FROM MyTable ORDER BY Col1 GO The result of the table is not as per expected. We need the result in following format. Here is the good example of how we can use PATINDEX. -- Use of PATINDEX SELECT ID, LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) 'Numeric Character', Col1 'Original Character' FROM MyTable ORDER BY LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) GO We can use PATINDEX to identify the length of the digit part in the alphanumeric string (Remember: Our string has a first part as an int always. It will not work in any other scenario). Now you can use the LEFT function to extract the INT portion from the alphanumeric string and order the data according to it. You can easily clean up the script by dropping following table. DROP TABLE MyTable GO Here is the complete script so you can easily refer it. -- How to find first non numberic character USE tempdb GO CREATE TABLE MyTable (ID INT, Col1 VARCHAR(100)) GO INSERT INTO MyTable (ID, Col1) SELECT 1, '1one' UNION ALL SELECT 2, '11eleven' UNION ALL SELECT 3, '2two' UNION ALL SELECT 4, '22twentytwo' UNION ALL SELECT 5, '111oneeleven' GO -- Select Data SELECT * FROM MyTable GO -- Select Data SELECT * FROM MyTable ORDER BY Col1 GO -- Use of PATINDEX SELECT ID, Col1 'Original Character' FROM MyTable ORDER BY LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) GO DROP TABLE MyTable GO Well, isn’t it an interesting solution. Any suggestion for better solution? Additionally any suggestion for changing the title of this blog post? Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL String, SQL Tips and Tricks, T SQL, Technology

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