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  • Find all substrings between two strings

    - by Orsol
    I need to get all substrings from string. For ex: StringParser.GetSubstrings("[start]aaaaaa[end] wwwww [start]cccccc[end]", "[start]", "[end]"); that returns 2 string "aaaaaa" and "cccccc" Suppose we have only one level of nesting. Not sure about regexp, but I think it will be userful.

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  • In Vim, how to swap 2 non adjacent patterns?

    - by ThG
    I have lines of text, all with the same structure, and would like to make a permutation of 2 elements on all lines: 1257654 some text (which may be long) #Foo 1543098 some other text #Barbar 1238769 whatever #Baz 2456874 something else #Quux I want to obtain : #Foo some text (which may be long) 1257654 #Barbar some other text 1543098 #Baz whatever 1238769 #Quux something else 2456874 This is where I am stuck : :%s/\(\d\{7\}\)\(#.\{-}\)/\2\1/ Where did I go wrong ?

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  • How to move many files in multiple different directories (on Linux)

    - by user1335982
    My problem is that I have too many files in single directory. I cannot "ls" the directory, cos is too large. I need to move all files in better directory structure. I'm using the last 3 digits from ID as folders in reverse way. For example ID 2018972 will gotta go in /2/7/9/img_2018972.jpg. I've created the directories, but now I need help with bash script. I know the IDs, there are in range 1,300,000 - 2,000,000. But I can't handle regular expressions. I wan't to move all files like this: /images/folder/img_2018972.jpg -> /images/2/7/9/img_2018972.jpg I will appreciate any help on this subject. Thanks!

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  • Replace strings differently depending if is enclosed in braces or not.

    - by peroyomas
    I want to replace all instances of an specific words between braces with something else, unless it is written between double braces, while it should show as is it was written with single braces without the filter. I have tried a code but only works for the first match. The rest are shown depending of the first one: $foo = 'a {bar} b {{bar}} c {bar} d'; $baz = 'Chile'; preg_match_all( '/(\{?)\{(tin)\}(\}?)/i', $foo, $matches, PREG_SET_ORDER ); if ( !empty($matches) ) { foreach ( (array) $matches as $match ) { if( empty($match[1]) && empty($match[3])) { $tull = str_replace( $match[0], $baz, $foo ); } else { $tull = str_replace( $match[0], substr($match[0], 1, -1), $foo ) ; } } } echo $tull;

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  • mod_rewrite per-dir redirection returning a 400

    - by Eaterrust
    I moved my images directory to a different folder, and now I want to redirect all images requests from that folder to the new one. I do not have access to the main configuraion file, so I'm doing this in a .htaccess. I tried this, and it works:     RewriteCond %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT] But since they have permanently moved, I want to do a proper redirect, so I added the [R] flag, like this:      %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT,R] But the server gets confused, and returns a 400, so I looked at the log file, and this is what happens:     strip per-dir prefix: C:/wamp/www/natrazyle/old_dir/images/banner.jpg - old_dir/images/banner.jpg     applying pattern 'old_dir/(.+[^/]+..+)$' to uri 'old_dir/images/banner.jpg'     rewrite 'old_dir/images/banner.jpg' - 'images/banner.jpg'     add per-dir prefix: images/banner.jpg - C:/wamp/www/natrazyle/images/banner.jpg     explicitly forcing redirect with http://localhost/C:/wamp/www/natrazyle/images/banner.jpg As you can see, the full local path gets added after localhost I know I'm doing something wrong, I just can't figure it out myself. Any help would be greatly appreciated...

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • How to check that a regular expression fall into infty loop or not?

    - by Sorush Rabiee
    I'm trying to learn and hopefully use regular expression with Qt. I found that some patterns cause handler to fall into loop. for example searching \b\b in a text, never will terminate. and number of these expressions is infinite (\b\b\b,\b\b\b\b and so on). I'd like to determine and control all invalid expressions. Is there an algorithm to distinguish valid and invalid expressions? If not, how can I prevent my program from falling into an infinite loop?

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  • PHP preg_match Math Function

    - by Matt
    I'm writing a script that will allow a user to input a string that is a math statement, to then be evaluated. I however have hit a roadblock. I cannot figure out how, using preg_match, to dissallow statements that have variables in them. Using this, $calc = create_function("", "return (" . $string . ");" ); $calc();, allows users to input a string that will be evaluated, but it crashes whenever something like echo 'foo'; is put in place of the variable $string.

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  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

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  • Simple Search and Replace use of Regular Expression

    - by nunos
    So, I am adapting some code I found online to suit my needs. However, my set_pixel function has two more parameters. Since there are lots of calls to this function even doing a quick paste over would be very tedious. So, I thought this would be a good time for me to learn some simple regular expressions. So, I have calls of this type: set_pixel(arg1, arg2); which I want to change to something like: set_pixel(arg1, arg2, arg3, arg4); Note: arg1 and and 2 should be preserved, whereas arg3 and arg4 are most of the time the same. How can I achieve this?

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  • negative look ahead to exclude html tags

    - by Remoh
    I'm trying to come up with a validation expression to prevent users from entering html or javascript tags into a comment box on a web page. The following works fine for a single line of text: ^(?!.(<|)).$ ..but it won't allow any newline characters because of the dot(.). If I go with something like this: ^(?!.(<|))(.|\s)$ it will allow multiple lines but the expression only matches '<' and '' on the first line. I need it to match any line. This works fine: ^[-_\s\d\w"'.,:;#/&\$\%\?!@+*\()]{0,4000}$ but it's ugly and I'm concerned that it's going to break for some users because it's a multi-lingual application. Any ideas? Thanks!

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • Function of: if(/(file|http).*/.test(url)) { }

    - by WmasterJ
    I am wondering what this technique is called and what it does. It seems to be validating some regular expression on the variable url. I am customizing another persons code: var url = document.getElementById("editorURL").value; if(/(file|http).*/.test(url)) { } Maybe someone has a link to an article that explains this a bit more in-depth?

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  • How to pull the file name from a url using javascript/jquery?

    - by jim23
    A certain variable might contain a relative path or an absolute path. Either way, I need to be able to pull the filename from the variable: http://www.somesite.com/dir1/dir2/filename.gif /dir1/dir2/filename.gif The directory structure is also arbitrary. So basically given either of the url's above (with arbirtrary directory structure) I need to pull 'filename.gif'. Thanks in advance

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • mod_rewrite rule for all urls except ones with some words

    - by zlog
    How do I write a mod_rewrite regulare expression rule that is the opposite of this: ^(.+)/path/(page1|page2)+$ ie, I want all pages except blah/path/page1 and blah/path/page2 to redirect to another path, where the x in blah/path/x is used in the new path. For example, I'd like write a rewrite rule like: RewriteRule some_regex /index.php?path/show/$1 [L] where some_regex would pull out the last component of a url in the format: /something/path/some_param to redirect to /index.php/path/show/some_param I'm trying to use ! and [^] syntax, but I don't quite understand how these work, especially when they involve words not single characters.

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  • How to use Regular Expression to extract information from a HTML webpage?

    - by user569248
    How to use Regular Expression to extract the answer "Here is the answer" from a HTML webpage like this? <b>Last Question:</b> <b>Here is the answer</b> ..:: Update ::.. Thanks everybody! Here is my solution by using BeautifulSoup since I'm using Python framework: response = opener.open(url) the_page = response.read() soup = BeautifulSoup(''.join(the_page)) paraText1 = soup.body.find('div', 'div_id', text = u'Last Question:') if paraText1: answer = paraText1.next

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