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  • Run word on server for COM to work??

    - by chupinette
    I got this from php.net website. This is related to the problem I am having with tho code below. Can anyone explain me what the following does. I am using Vista. What does running Word on server implies? In order to get the Word example running, do the following on the server side. Worked for me... 1. Click START--RUN and enter "dcomcnfg" 2. In the "Applications" tab, go down to "Microsoft Word Document" 3. Click PROPERTIES button 4. Go to the "Security" Tab 5. Click "Use custom access permissions", and then click EDIT 6. Click ADD and then click SHOW USERS 7. Highlight the IIS anonymous user account (usually IUSR_), click ADD 8. Go back to the "Security" tab by hitting OK 9. Click "Use custom launch permissions", and the click EDIT 10. Click ADD and then click SHOW USERS 11. Highlight the IIS anonymous user account (usually IUSR_), click ADD 12. Hit OK, and then hit APPLY. Also, you should look at the "Identity" tab in the Microsoft Word Document PROPERTIES and see that it is set to "Interactive User" ALSO, log into the machine AS the IUSR_ account, start word, and make sure to click through the dialog boxes that Word shows the first time it is run for a certain user. In other words, make sure Word opens cleanly for the IUSR_ user. <?php // starting word $word = new COM("word.application") or die("Unable to instantiate Word"); echo "Loaded Word, version {$word->Version}\n"; //bring it to front $word->Visible = 1; //open an empty document $word->Documents->Add(); //do some weird stuff $word->Selection->TypeText("This is a test..."); $word->Documents[1]->SaveAs("Useless test.doc"); //closing word $word->Quit(); //free the object $word = null; ?>

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  • Debugging in XCode as root

    - by Anton
    In my program I need to create sockets and bind them to listen HTTP port (80). The program works fine when I launch it from command line with sudo, escalating permissions to root. Running under XCode gives a 'permission denied' error on the call to binding function (asio::ip::tcp::acceptor::bind()). How can I do debugging under XCode? All done in C++ and boost.asio on Mac OS X 10.5 with XCode 3.1.2.

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  • JPA @ManyToOne and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @ManyToOne mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • Maven:install jar file during build process

    - by Venkata
    I have got a requirement as follows. I need to run ant build file during maven build process. I need to invoke the build.xml from my pom.xml file. I have done that using maven-antrun-plugin. Now I need to install the ant build generated jar file automatically into my local repository before maven compiles my project source. I tried using build-helper-maven-plugin but it did not help. Either I am doing something wrong, or i am not doing right. Please help. Update Thank you. ant maven tasks worked for me as well. However I am runing into the following exception at the end of the build process. Any help is highly appreciated. org.apache.tools.ant.ExitException: Permission (java.lang.RuntimePermission exitVM) was not granted. at org.apache.tools.ant.types.Permissions$MySM.checkExit(Permissions.java:196) at java.lang.Runtime.exit(Runtime.java:99) at java.lang.System.exit(System.java:275) at org.codehaus.classworlds.Launcher.main(Launcher.java:376) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37) at java.lang.reflect.Method.invoke(Method.java:599) at org.apache.tools.ant.taskdefs.ExecuteJava.run(ExecuteJava.java:217) at org.apache.tools.ant.taskdefs.ExecuteJava.execute(ExecuteJava.java:152) at org.apache.tools.ant.taskdefs.Java.run(Java.java:771) at org.apache.tools.ant.taskdefs.Java.executeJava(Java.java:221) at org.apache.tools.ant.taskdefs.Java.executeJava(Java.java:135) at org.apache.tools.ant.taskdefs.Java.execute(Java.java:108) at org.apache.maven.artifact.ant.Mvn.execute(Mvn.java:81) at org.apache.tools.ant.UnknownElement.execute(UnknownElement.java:291) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37) at java.lang.reflect.Method.invoke(Method.java:599) at org.apache.tools.ant.dispatch.DispatchUtils.execute(DispatchUtils.java:106) at org.apache.tools.ant.Task.perform(Task.java:348) at org.apache.tools.ant.Target.execute(Target.java:390) at org.apache.tools.ant.Target.performTasks(Target.java:411) at org.apache.tools.ant.Project.executeSortedTargets(Project.java:1399) at org.apache.tools.ant.Project.executeTarget(Project.java:1368) at org.apache.tools.ant.helper.DefaultExecutor.executeTargets(DefaultExecutor.java:41) at org.apache.tools.ant.Project.executeTargets(Project.java:1251) at org.apache.tools.ant.Main.runBuild(Main.java:809) at org.apache.tools.ant.Main.startAnt(Main.java:217) at org.apache.tools.ant.launch.Launcher.run(Launcher.java:280) at org.apache.tools.ant.launch.Launcher.main(Launcher.java:109)

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  • Installing Rails 3 - /usr/local/bin/rails: No such file or directory

    - by viatropos
    I just ran these two commands: sudo gem install rails --pre sudo gem install railties --pre Now when I run rails myapp, I get this: -bash: /usr/local/bin/rails: No such file or directory Here's some system info: $ ruby -v ruby 1.8.7 (2009-06-12 patchlevel 174) [i686-darwin9.7.0] $ sudo gem update --system Updating RubyGems Nothing to update I tried copy/pasting the bin/rails file into /usr/local/bin/rails, and changing permissions to sudo chmod 755 /usr/local/bin/rails, but that doesn't work. Any ideas how to get up and running?

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  • KSH shell script won't execute and returns 127 (not found)

    - by Chris Knight
    Can anyone enlighten me why the following won't work? $ groups staff btgroup $ ls -l total 64 -rw-rw---- 1 sld248 btgroup 26840 Apr 02 13:39 padaddwip.jks -rwxrwx--- 1 sld248 btgroup 1324 Apr 02 13:39 padaddwip.ksh $ ./padaddwip.ksh ksh: ./padaddwip.ksh: not found. $ echo $? 127 This is nearly identical to another script which works just fine. I can't see any differences between the two in terms of permissions or ownership. thanks in advance!

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  • Simplest Way to Test ODBC on WIndows

    - by Rescommunes
    With unixODBC you can use a simple command line utility called "isql" to test your connection permissions etc. Without having to write extra code or install libs is there a simple way to open up X data source send some sql commands and be done with it?

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  • Facebook dialogs keep popping up in Firefox

    - by Pierre Olivier Martel
    I have a facebook application running in a FBML canvas and I have a problem with dialogs (either extended permissions or stream publish dialogs). Once they popup, they keep popping up for every subsequent requests. I've tested it in Chrome and everything works fine. It seems that the URL is chained in Firefox, which gives cryptic long urls like : http://apps.facebook.com/webdweller-po/discover?_fb_q=1&_fb_qsub=apps.facebook.com#!/webdweller-dev/?_fb_q=1&_fb_qsub=apps.facebook.com Did anybody experienced such a bug?

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  • Open Source Alternative to ASP.NET membership

    - by Tony Lenzi
    I'm currently supporting a Python web app with increasingly complicated user/role/permission management requirements. Currently, we are rolling our own user, groups, permissions, etc. code and supporting database. I'd like to find something like ASP.NET membership that can help manage user authentication and authorization, rather than risk security issues in continuing to create an increasingly complicated custom solution. Are there any similar projects out there worth taking a look at?

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  • Crystal reports .net visual studio 2008 bundled edition

    - by DeveloperChris
    I have a serious issue with crystal reports. when run in my development environment or debugged on my local machine it works fine. but when the application is published to a windows server 2003 it has the dreaded "The report you requested requires further information" Message I have had no luck trying to get rid of this message Anybody know what I can try? DC Here is a bunch more info. I use a placeholder in the aspx page and then set the user/password and database in the codebehind I could not get it to work with a dataset and found that I had to assign odbc connection in the cr designer. and then in the code behind change the above details as required. This is done because the same report can get the data from 3 different databases (live development and training) protected override void Page_Load(object sender, EventArgs e) { base.Page_Load(sender, e); CrystalReportSource1.ReportDocument.Load(Server.MapPath(@"~/Reports/Report5asp.rpt")); CrystalReportViewer1.ReportSource = ConfigureCrystalReports(CrystalReportSource1.ReportDocument,CrystalReportViewer1); // parameters CrystalReportViewer1.ParameterFieldInfo.Clear(); AddParameter("DIid", _app.Data["DIid"], CrystalReportViewer1.ParameterFieldInfo); AddParameter("EEid", _app.Data["EEid"], CrystalReportViewer1.ParameterFieldInfo); AddParameter("CTid", _app.Data["CTid"], CrystalReportViewer1.ParameterFieldInfo); } public ReportDocument ConfigureCrystalReports(ReportDocument report, CrystalReportViewer viewer) { String _connectionString = _app.ConnectionString(); String dsn = _app.DSN(); SqlConnectionStringBuilder SConn = new SqlConnectionStringBuilder(_connectionString); TableLogOnInfos crtableLogoninfos = new TableLogOnInfos(); TableLogOnInfo crtableLogoninfo = new TableLogOnInfo(); ConnectionInfo crConnectionInfo = new ConnectionInfo(); crConnectionInfo.ServerName = dsn;// SConn.DataSource; crConnectionInfo.DatabaseName = SConn.InitialCatalog; crConnectionInfo.UserID = SConn.UserID; crConnectionInfo.Password = SConn.Password; crConnectionInfo.Type = ConnectionInfoType.SQL; crConnectionInfo.IntegratedSecurity = false; foreach (CrystalDecisions.CrystalReports.Engine.Table CrTable in report.Database.Tables) { crtableLogoninfo = CrTable.LogOnInfo; crtableLogoninfo.ConnectionInfo = crConnectionInfo; CrTable.ApplyLogOnInfo(crtableLogoninfo); } return report; } As stated this works fine on my XP machine used for development when deployed on winserver 2003 I get the error DC Some interesting additional information I moved the development to my home machine so I could work on the problem this weekend. So now I am developing debugging and testing on the same machine! In VS2008 I can edit and preview the reports with no problems If I fire up the debugger I can view the reports in the browser with no problems But if I publish the website to another folder on the same machine and fire up IIS and try to browse to a report I get the aforementioned error. All else works as expected. IIS runs under different permissions than VS2008 so perhaps its something to do with that, but I have tried lots of different permissions and cannot get it to run. DC

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  • Installing jdk without sudo?

    - by Legend
    Currently, I have a machine on which I am working in Eclipse, it says that the JRE System Library version is sun-jdk-1.5.0.11 but on my active development machine, it is java-6-sun-1.6.0.16. What is the difference between these two (of course, besides the versioning)? Is there any way I can make the first machine to use the same "java-6-sun-1.6.0.16" version without having sudo permissions on the machine?

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  • HTTPS connection in BlackBerry Java Midlet

    - by Casebash
    My Java ME Midlet works fine on Java phones and the BlackBerry simulator, but I can't receive a connection on a BlackBerry. I see a message that asks for permissions to connect, but when I select yes, it doesn't connect. I even checked on the server, but no connection was provided. My application isn't signed. Does anyone know why this might be failing?

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  • How do I get ELMAH to work with SQL Server (permission problems)

    - by Gary McGill
    I've got ELMAH working on my (Cassini) development server, and was quite happy with it, but now that I'm trying to move everything to my production server (IIS7), the honeymoon looks like being over. I've got past the "gotcha" with IIS7, which frankly could have been better highlighted in the documentation, and if I just use the in-memory log then it works. However, I'm trying to get it to use the SQL Server log (as I do on my development system), and I'm getting an error along the lines of: The EXECUTE permission was denied on the object ELMAH_GetErrorsXml Well, fine. I know how to grant database permissions, but I'm really struggling to understand which user and which stored procs/tables I need to grant access to. The thing that's really confusing me is that I didn't have to do anything like this to get it to work on my development server. The only difference I can see is that on my development server it seems to connect as NT AUTHORITY\IUSR, whereas on my production server it seems to connect as NT AUTHORITY\NETWORK SERVICE. (It's just using a trusted connection so I've not explicitly configured it to do that - I presume it's to do with the web server). UPDATE: I've since established that because I'm using Cassini, it was actually logging in as me (an admin) and not IUSR, which explains why I didn't get any permission problems. On my development server, the IUSR account is a member of the public database role, and has access to the required database (again as "public"). There's no explicit granting of object-level permissions. [See update above - this is irrelevant]. On my production server, I've added NETWORK SERVICE in exactly the same way (public database role, explicit access to the database as "public"). Yet, I get this permission error. Why?!! [See update above - the only reason I don't get a permission error is because I'm running as an admin]. And, of course, if the fact that it works locally is just "luck", I will need to know which SPs/tables to grant access to. My guess would be all 3 SPs and not the table, but it would be good (again) to see some documentation that makes this explicit.

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  • Godaddy security exception

    - by stighy
    Hi at all. I can't resolve this issue. My web hoster, GoDaddy , return this error: Exception Details: System.Security.SecurityException: Request for the permission of type 'System.Security.Permissions.SecurityPermission, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed. And i really don't know how to solve it. Are there Anyone with similar experience ? Thanks

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  • Checkbox has the wrong values

    - by Praesagus
    I have a page with several checkboxes on it, along with a dropdownlist of users. The checkboxes correlate to the user's permissions so each user is different. When a different user is chosen, the check boxes should change to match that user's permissions. The codebehind is correct, I stepped through it and the checkbox.checked value is being assigned to the box with the correct value to match the user. chk.Checked = viewable; No matter what I assign to the checked property the value stays the same as the very first submittal. I tried chk.EnableViewState = false; but that did not help. I am sure it is dot net trying to be helpful (grrr). Thank you for your help. There is no databinding per se. I will be saving the values from the textboxes via xmlhttp when the user clicks on them. I never want the check boxes to fill with values other than what I give them. Here is the essence of the code. foreach (DataRow dRow in dTable.Rows) { viewable = Convert.ToBoolean(dRow["Viewable"]); table.Rows.Add(CreatePageRow(Convert.ToString(dRow["SitePageViewName"]), Convert.ToString(dRow["SitePageName"]), folderDepth, maxFolderDepth, viewable)); } FileTree.Controls.Add(table); private TableRow CreatePageRow(String ViewName, String FileName, Int32 folderDepth, Int32 maxFolderDepth, Boolean viewable) { TableRow tr = new TableRow(); tr.Cells.Add(CreateCheckboxCell(viewable, folderDepth+3)); tr.Cells.Add(CreateImageCell("/images/icon/sm/report_graph.gif", "Page: " + ViewName)); tr.Cells.Add(CreateTitleCell(ViewName, maxFolderDepth - (folderDepth+1), FileName)); return tr; } private TableCell CreateCheckboxCell(Boolean viewable, Int32 colSpan) { TableCell td = new TableCell(); if (colSpan > 1) td.ColumnSpan = colSpan; CheckBox chk = new CheckBox(); chk.Checked = viewable; chk.EnableViewState = false; td.Controls.Add(chk); td.CssClass = "right"; return td; }

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  • silverlight Socket: Unhandled Error in Silverlight Application An attempt was made to access a sock

    - by Yang
    I basically try to reproduce the Socket example from here: http://www.silverlightshow.net/items/Sockets-and-their-implementation-in-SL2-Beta-1-including-a-chat-like-example.aspx I only made a small change in the client side, i.e., String safeHost = "127.0.0.1"; int port = 4509; Then I got this permission error? Any idea why? Unhandled Error in Silverlight Application An attempt was made to access a socket in a way forbidden by its access permissions.

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  • What are the causes and solutions to a CS0122 error when sending onto an MSMQ queue from C#?

    - by Erick
    Having created a System.Messaging.MessageQueue using the MessageQueue(string queuePath) constructor, attempting to use MessageQueue.Send(obj) results in a 'Unable to generate a temporary class (result=1)' exception with the additional text: 'error CS0122: 'System.__ComObject' is inaccessible due to its protection level'. The queue itself has full control given to EVERYONE. When querying the MessageQueue object for it's read write permissions, it returns SendAndReceive. What causes this error and how do you resolve it?

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  • ASP SQL Error Handling

    - by J Harley
    Hello, I am using Classic asp and SQL Server 2005. This is code that works (Provided by another member of Stack Overflow): sqlStr = "USE "&databaseNameRecordSet.Fields.Item("name")&";SELECT permission_name FROM fn_my_permissions(null, 'database')" This code checks what permissions I have on a given database - the problem being - if I dont have permission it throws an error and doesn't continue to draw the rest of my page. Anyone got any ideas on remedying this? Many Thanks, Joel

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  • How to do REST securely and with sensitive data?

    - by Earlz
    Hello, we are implementing a new web service. The web service will be a store of sensitive data and there are multiple users types with different permissions. So some user types can't access(and some can't change, and so on) certain types of data. How would this work in REST? I'm very new to REST, so sorry if this sounds noobish.

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  • Detailed error on fopen

    - by Roland
    I'm using fopen to read from a file $fh = fopen($path, 'r') or die('Could not open file'); Now I contantly get error Could not open file. I checked the file path and even changed the permissions of the file to 777. Is there a way I can get a detailed error report as why the file can't be opened similar to mysql_error()?

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