If I want to open binary file (in Python 2.6), that doesn't exists, program exits with an error and prints this:
Traceback (most recent call last):
File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 4, in <module>
pkl_file = open('monitor.dat', 'rb')
IOError: [Errno 2] No such file or directory: 'monitor.dat'
I can handle this with 'try-except', like:
try:
pkl_file = open('monitor.dat', 'rb')
monitoring_pickle = pickle.load(pkl_file)
pkl_file.close()
except Exception:
print 'No such file or directory'
Does anybody know, how could I, in caught Exception, print the following line?
File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 11, in <module>
pkl_file = open('monitor.dat', 'rb')
So, program would not exits, and I would have useful information.
