Search Results

Search found 15301 results on 613 pages for 'global assembly cache'.

Page 116/613 | < Previous Page | 112 113 114 115 116 117 118 119 120 121 122 123  | Next Page >

  • Error in Print Function in Bubble Sort MIPS?

    - by m00nbeam360
    Sorry that this is such a long block of code, but do you see any obvious syntax errors in this? I feel like the problem is that the code isn't printing correctly since the sort and swap methods were from my textbook. Please help if you can! .data save: .word 1,2,4,2,5,6 size: .word 6 .text swap: sll $t1, $a1, 2 #shift bits by 2 add $t1, $a1, $t1 #set $t1 address to v[k] lw $t0, 0($t1) #load v[k] into t1 lw $t2, 4($t1) #load v[k+1] into t1 sw $t2, 0($t1) #swap addresses sw $t0, 4($t1) #swap addresses jr $ra #return sort: addi $sp, $sp, -20 #make enough room on the stack for five registers sw $ra, 16($sp) #save the return address on the stack sw $s3, 12($sp) #save $s3 on the stack sw $s2, 8($sp) #save Ss2 on the stack sw $s1, 4($sp) #save $s1 on the stack sw $s0, 0($sp) #save $s0 on the stack move $s2, $a0 #copy the parameter $a0 into $s2 (save $a0) move $s3, $a1 #copy the parameter $a1 into $s3 (save $a1) move $s0, $zero #start of for loop, i = 0 for1tst: slt $t0, $s0, $s3 #$t0 = 0 if $s0 S $s3 (i S n) beq $t0, $zero, exit1 #go to exit1 if $s0 S $s3 (i S n) addi $s1, $s0, -1 #j - i - 1 for2tst: slti $t0, $s1, 0 #$t0 = 1 if $s1 < 0 (j < 0) bne $t0, $zero, exit2 #$t0 = 1 if $s1 < 0 (j < 0) sll $t1, $s1, 2 #$t1 = j * 4 (shift by 2 bits) add $t2, $s2, $t1 #$t2 = v + (j*4) lw $t3, 0($t2) #$t3 = v[j] lw $t4, 4($t2) #$t4 = v[j+1] slt $t0, $t4, $t3 #$t0 = 0 if $t4 S $t3 beq $t0, $zero, exit2 #go to exit2 if $t4 S $t3 move $a0, $s2 #1st parameter of swap is v(old $a0) move $a1, $s1 #2nd parameter of swap is j jal swap #swap addi $s1, $s1, -1 j for2tst #jump to test of inner loop j print exit2: addi $s0, $s0, 1 #i = i + 1 j for1tst #jump to test of outer loop exit1: lw $s0, 0($sp) #restore $s0 from stack lw $s1, 4($sp) #resture $s1 from stack lw $s2, 8($sp) #restore $s2 from stack lw $s3, 12($sp) #restore $s3 from stack lw $ra, 16($sp) #restore $ra from stack addi $sp, $sp, 20 #restore stack pointer jr $ra #return to calling routine .data space:.asciiz " " # space to insert between numbers head: .asciiz "The sorted numbers are:\n" .text print:add $t0, $zero, $a0 # starting address of array add $t1, $zero, $a1 # initialize loop counter to array size la $a0, head # load address of print heading li $v0, 4 # specify Print String service syscall # print heading out: lw $a0, 0($t0) # load fibonacci number for syscall li $v0, 1 # specify Print Integer service syscall # print fibonacci number la $a0, space # load address of spacer for syscall li $v0, 4 # specify Print String service syscall # output string addi $t0, $t0, 4 # increment address addi $t1, $t1, -1 # decrement loop counter bgtz $t1, out # repeat if not finished jr $ra # return

    Read the article

  • delete a file in protected mode env(like windows xp)

    - by JGC
    hi I write a program to delete a file from somewhere of my harddisk in 8086 but when i use int 21h (ah=41h) an error happens and carry set to 1.and I cannot delete that. does anyone know what can I do? I think it should be from protected mode which does not allow my program to delete another file.I want the answer and language is not matter.

    Read the article

  • Problem with asm program (nasm)

    - by GLeBaTi
    org 0x100 SEGMENT .CODE mov ah,0x9 mov dx, Msg1 int 0x21 ;string input mov ah,0xA mov dx,buff int 0x21 mov ax,0 mov al,[buff+1]; length ;string UPPERCASE mov cl, al mov si, buff cld loop1: lodsb; cmp al, 'a' jnb upper loop loop1 ;output mov ah,0x9 mov dx, buff int 0x21 exit: mov ah, 0x8 int 0x21 int 0x20 upper: sub al,32 jmp loop1 SEGMENT .DATA Msg1 db 'Press string: $' buff db 254,0 this code perform poorly. I think that problem in "jnb upper". This program make small symbols into big symbols.

    Read the article

  • Database caching on a shared host

    - by tau
    Anyone have any ideas how to increase MySQL performance on a shared host? My question has less to do with overall database performance and more to do with simply retrieving user-submitted data. Currently my database will create caches at timed intervals, and then the PHP will selectively access the static files it needs. This has given me a noticeable performance boost, but I am worried about a time in which I have so much data that having to read in big files in PHP will actually be slower. I am just looking for ideas for shared hosting solutions; I am not going to get my own server anytime soon. Thanks!

    Read the article

  • stripping default.aspx and //www from the url

    - by b0x0rz
    the code to strip /Default.aspx and //www is not working (as expected): protected void Application_BeginRequest(object sender, EventArgs e) { HttpContext context = HttpContext.Current; string url = context.Request.RawUrl.ToString(); bool doRedirect = false; // remove > default.aspx if (url.EndsWith("/default.aspx", StringComparison.OrdinalIgnoreCase)) { url = url.Substring(0, url.Length - 12); doRedirect = true; } // remove > www if (url.Contains("//www")) { url = url.Replace("//www", "//"); doRedirect = true; } // redirect if necessary if (doRedirect) { context.Response.Redirect(url); } } it works usually, but when submitting a form (sign in for example) the code above INTERCEPTS the request and then does a redirect to the same page. example: try to arrive at page: ~/SignIn/Default.aspx the requests gets intercepted and fixed to: ~/SignIn/ fill the form, click sign in the current page url goes from: ~/SignIn/ to ~/SignIn/Default.aspx and gets fixed again, thus voiding the processing of the method SignIn (which would have redirected the browser to /SignIn/Success/) and the page is reloaded as ~/SignIn/ and no sign in was done. please help. not sure what / how to fix here. the main REQUIREMENT here is: remove /Default.aspx and //www from url's thnx

    Read the article

  • Why would I need a using statement to Libary B extn methods, if they're used in Library A & it's Li

    - by Greg
    Hi, I have: Main Program Class - uses Library A Library A - has partial classes which mix in methods from Library B Library B - mix in methods & interfaces Why would I need a using statement to LibaryB just to get their extension methods working in the main class? That is given that it's Library B that defines the classes that will be extended. EDIT - Except from code // *** PROGRAM *** using TopologyDAL; using Topology; // *** THIS WAS NEEDED TO GET EXTN METHODS APPEARING *** class Program { static void Main(string[] args) { var context = new Model1Container(); Node myNode; // ** trying to get myNode mixin methods to appear seems to need using line to point to Library B *** } } // ** LIBRARY A namespace TopologyDAL { public partial class Node { // Auto generated from EF } public partial class Node : INode<int> // to add extension methods from Library B { public int Key } } // ** LIBRARY B namespace ToplogyLibrary { public static class NodeExtns { public static void FromNodeMixin<T>(this INode<T> node) { // XXXX } } public interface INode<T> { // Properties T Key { get; } // Methods } }

    Read the article

  • Outputting variable values in x86?

    - by Airjoe
    Hello All- I'm working on a homework assignment in x86 and it isn't working as I expect (surprise surprise!). I'd like to be able to output values of variables in x86 functions to ensure that the values are what I expect them to be. Is there a simple way to do this, or is it very complex? For what it's worth, the x86 functions are being used by a C file and compiled with gcc, so if that makes it simpler that is how I'm going about it. Thanks for the help.

    Read the article

  • Setting processor to 32-bit mode

    - by dboarman-FissureStudios
    It seems that the following is a common method given in many tutorials on switching a processor from 16-bit to 32-bit: mov eax, cr0 ; set bit 0 in CR0-go to pmode or eax, 1 mov cr0, eax Why wouldn't I simply do the following: or cr0, 1 Is there something I'm missing? Possibly the only thing I can think of is that I cannot perform an operation like this on the cr0 register.

    Read the article

  • Dynamic Variables Within Functions

    - by Ryan
    Why does this work: function myfunction($v) { $query = $v['host'] == '1'; return ( $query ); } $output = array_filter($recordset,myfunction); print_r($output); Whereas this script, which tries to accomplish the same thing with variables, does not? $column1 = 'host'; $value1 = 1; $query1 = '$v[\''.$column1.'\'] == '.$value1; function myfunction($v) { $query = $GLOBALS['query1']; return ( $query ); } $output = array_filter($recordset,myfunction); print_r($output); Any help would be great. Thanks!

    Read the article

  • Python - question regarding the concurrent use of `multiprocess`.

    - by orokusaki
    I want to use Python's multiprocessing to do concurrent processing without using locks (locks to me are the opposite of multiprocessing) because I want to build up multiple reports from different resources at the exact same time during a web request (normally takes about 3 seconds but with multiprocessing I can do it in .5 seconds). My problem is that, if I expose such a feature to the web and get 10 users pulling the same report at the same time, I suddenly have 60 interpreters open at the same time (which would crash the system). Is this just the common sense result of using multiprocessing, or is there a trick to get around this potential nightmare? Thanks

    Read the article

  • Is asp.net caching my sql results?

    - by Christian W
    I have the following method in an App_Code/Globals.cs file: public static XmlDataSource getXmlSourceFromOrgid(int orgid) { XmlDataSource xds = new XmlDataSource(); var ctx = new SensusDataContext(); SqlConnection c = new SqlConnection(ctx.Connection.ConnectionString); c.Open(); SqlCommand cmd = new SqlCommand(String.Format("select orgid, tekst, dbo.GetOrgTreeXML({0}) as Subtree from tblOrg where OrgID = {0}", orgid), c); var rdr = cmd.ExecuteReader(); rdr.Read(); StringBuilder sb = new StringBuilder(); sb.AppendFormat("&lt;node orgid=\"{0}\" tekst=\"{1}\"&gt;",rdr.GetInt32(0),rdr.GetString(1)); sb.Append(rdr.GetString(2)); sb.Append("&lt;/node&gt;"); xds.Data = sb.ToString(); xds.ID = "treedata"; rdr.Close(); c.Close(); return xds; } This gives me an XML-structure to use with the asp.net treeview control (I also use the CssFriendly extender to get nicer code) My problem is that if I logon on my pc with a code that gives me access on a lower level in the tree hierarchy (it's an orgianization hierarchy), it somehow "remembers" what level i logon at. So when my coworker tests from her computer with another code, giving access to another place in the tree, she get's the same tree as me. (The tree is supposed to show your own level and down.) I have added a html-comment to show what orgid it passes to the function, and the orgid passed is correct. So either the treeview caches something serverside, or the sqlquery caches it's result somehow... Any ideas? Sql function: ALTER function [dbo].[GetOrgTreeXML](@orgid int) returns XML begin RETURN (select org.orgid as '@orgid', org.tekst as '@tekst', [dbo].GetOrgTreeXML(org.orgid) from tblOrg org where (@orgid is null and Eier is null) or Eier=@orgid for XML PATH('NODE'), TYPE) end Extra code as requested: int orgid = int.Parse(Session["org"].ToString()); string orgname = context.Orgs.Where(q => q.OrgID == orgid).First().Tekst; debuglit.Text = String.Format("<!-- Id: {0} \n name: {1} -->", orgid, orgname); var orgxml = Globals.getXmlSourceFromOrgid(orgid); tvNavtree.DataSource = orgxml; tvNavtree.DataBind(); Where "debuglit" is a asp:Literal in the aspx file. EDIT: I have narrowed it down. All functions returns correct values. It just doesn't bind to it. I suspect the CssFriendly adapter to have something to do with it. I disabled the CssFriendly adapter and the problem persists... Stepping through it in debug it's correct all the way, with the stepper standing on "tvNavtree.DataBind();" I can hover the pointer over the tvNavtree.Datasource and see that it actually has the correct data. So something must be faulting in the binding process...

    Read the article

  • Is there any kind of standard for 8086 multiprocessing?

    - by Earlz
    Back when I made an 8086 emulator I noticed that there was the LOCK prefix intended for synchonization in a multiprocessor environment. Yet the only multitasking I know of for the x86 arch. involves use of the APIC which didn't come around until either the Pentiums or 486s. Was there any kind of standard for 8086 multitasking or was it done by some manufacturer specific extensions to the instruction set and/or special ports? By standard, I mean things like: How do you separate the 2 processors if they both use the same memory? This is impossible without some kind of way to make each processor execute a different piece of code. (or cause an interrupt on only one processor)

    Read the article

  • Are programming languages and methods inefficient? (assembler and C knowledge needed)

    - by b-gen-jack-o-neill
    Hi, for a long time, I am thinking and studying output of C language compiler in assembler form, as well as CPU architecture. I know this may be silly to you, but it seems to me that something is very ineffective. Please, don´t be angry if I am wrong, and there is some reason I do not see for all these principles. I will be very glad if you tell me why is it designed this way. I actually truly believe I am wrong, I know the genius minds of people which get PCs together knew a reason to do so. What exactly, do you ask? I´ll tell you right away, I use C as a example: 1: Stack local scope memory allocation: So, typical local memory allocation uses stack. Just copy esp to ebp and than allocate all the memory via ebp. OK, I would understand this if you explicitly need allocate RAM by default stack values, but if I do understand it correctly, modern OS use paging as a translation layer between application and physical RAM, when address you desire is further translated before reaching actual RAM byte. So why don´t just say 0x00000000 is int a,0x00000004 is int b and so? And access them just by mov 0x00000000,#10? Because you wont actually access memory blocks 0x00000000 and 0x00000004 but those your OS set the paging tables to. Actually, since memory allocation by ebp and esp use indirect addressing, "my" way would be even faster. 2: Variable allocation duplicity: When you run application, Loader load its code into RAM. When you create variable, or string, compiler generates code that pushes these values on the top o stack when created in main. So there is actual instruction for do so, and that actual number in memory. So, there are 2 entries of the same value in RAM. One in form of instruction, second in form of actual bytes in the RAM. But why? Why not to just when declaring variable count at which memory block it would be, than when used, just insert this memory location?

    Read the article

  • How to benchmark on multi-core processors

    - by Pascal Cuoq
    I am looking for ways to perform micro-benchmarks on multi-core processors. Context: At about the same time desktop processors introduced out-of-order execution that made performance hard to predict, they, perhaps not coincidentally, also introduced special instructions to get very precise timings. Example of these instructions are rdtsc on x86 and rftb on PowerPC. These instructions gave timings that were more precise than could ever be allowed by a system call, allowed programmers to micro-benchmark their hearts out, for better or for worse. On a yet more modern processor with several cores, some of which sleep some of the time, the counters are not synchronized between cores. We are told that rdtsc is no longer safe to use for benchmarking, but I must have been dozing off when we were explained the alternative solutions. Question: Some systems may save and restore the performance counter and provide an API call to read the proper sum. If you know what this call is for any operating system, please let us know in an answer. Some systems may allow to turn off cores, leaving only one running. I know Mac OS X Leopard does when the right Preference Pane is installed from the Developers Tools. Do you think that this make rdtsc safe to use again? More context: Please assume I know what I am doing when trying to do a micro-benchmark. If you are of the opinion that if an optimization's gains cannot be measured by timing the whole application, it's not worth optimizing, I agree with you, but I cannot time the whole application until the alternative data structure is finished, which will take a long time. In fact, if the micro-benchmark were not promising, I could decide to give up on the implementation now; I need figures to provide in a publication whose deadline I have no control over.

    Read the article

  • Electronic resources for learning Z/OS assembler?

    - by Jared
    This is a follow up to this question. I'm totally blind so printed books aren't an option. All the recommended books appear to have been published before electronic publishing got started. I've been able to learn the very basics but would like something between here's what a register is, and the IBM reference material. Searching the normal places like Safari Books Online has come up dry.

    Read the article

  • Why increased pipeline depth does not always mean increased throughput?

    - by worlds-apart89
    This is perhaps more of a discussion question, but I thought stackoverflow could be the right place to ask it. I am studying the concept of instruction pipelining. I have been taught that a pipeline's instruction throughput is increased once the number of pipeline stages is increased, but in some cases, throughput might not change. Under what conditions, does this happen? I am thinking stalling and branching could be the answer to the question, but I wonder if I am missing something crucial.

    Read the article

  • translate ia32 into C

    - by David Lee
    I am trying to translate the following: Action: push %ebp #function prolog mov %esp, %ebp sub $0x10, %esp mov 0x8(%ebp), %eax #first line compiles to these 4 lines imul 0x8(%ebp), %eax sub $0x7, %eax mov %eax, -0x4(%ebp) addl $0x8, 0xc(%ebp) #second line mov -0x4(%ebp), %eax #third line mov 0xc(%ebp), %edx mov (%edx, %eax, 4), %eax add $0x3, %eax movb $0x41, (%eax) leave ret So far I have the following: //What am I missing? void Action(int x, char **y) { int z = x * x - 7; y+=8; //missing third line } What is the best way to translate this?

    Read the article

  • easy asm program(nasm)

    - by GLeBaTi
    org 0x100 SEGMENT .CODE mov ah,0x9 mov dx, Msg1 int 0x21 ;string input mov ah,0xA mov dx,buff int 0x21 mov ax,0 mov al,[buff+1]; length ;string UPPERCASE mov cl, al mov si, buff cld loop1: lodsb; cmp al, 'a' jnb upper loop loop1 ;output mov ah,0x9 mov dx, buff int 0x21 exit: mov ah, 0x8 int 0x21 int 0x20 upper: sub al,32 jmp loop1 SEGMENT .DATA Msg1 db 'Press string: $' buff db 254,0 this code perform poorly. I think that problem in "jnb upper". This program make small symbols into big symbols.

    Read the article

  • ARM Simulator on Windows

    - by Betamoo
    I am studying ARM Processors from a textbook... I thought it will be more useful if I could apply what I learn on an ARM simulator... writing code then watching results and different execution stages would be more fun... I have searched for it, but all I could find was either a freeware on linux or a demo on windows Is there a simulator that allow me to see execution steps and different changes for ARM processor (any version!) that runs on windows?? Thanks

    Read the article

  • Why does it NOT give a segmentation violation?

    - by user198729
    The code below is said to give a segmentation violation: #include <stdio.h> #include <string.h> void function(char *str) { char buffer[16]; strcpy(buffer,str); } int main() { char large_string[256]; int i; for( i = 0; i < 255; i++) large_string[i] = 'A'; function(large_string); return 1; } It's compiled and run like this: gcc -Wall -Wextra hw.cpp && a.exe But there is nothing output. NOTE The above code indeed overwrites the ret address and so on if you really understand what's going underneath.

    Read the article

  • "C variable type sizes are machine dependent." Is it really true? signed & unsigned numbers ;

    - by claws
    Hello, I've been told that C types are machine dependent. Today I wanted to verify it. void legacyTypes() { /* character types */ char k_char = 'a'; //Signedness --> signed & unsigned signed char k_char_s = 'a'; unsigned char k_char_u = 'a'; /* integer types */ int k_int = 1; /* Same as "signed int" */ //Signedness --> signed & unsigned signed int k_int_s = -2; unsigned int k_int_u = 3; //Size --> short, _____, long, long long short int k_s_int = 4; long int k_l_int = 5; long long int k_ll_int = 6; /* real number types */ float k_float = 7; double k_double = 8; } I compiled it on a 32-Bit machine using minGW C compiler _legacyTypes: pushl %ebp movl %esp, %ebp subl $48, %esp movb $97, -1(%ebp) # char movb $97, -2(%ebp) # signed char movb $97, -3(%ebp) # unsigned char movl $1, -8(%ebp) # int movl $-2, -12(%ebp)# signed int movl $3, -16(%ebp) # unsigned int movw $4, -18(%ebp) # short int movl $5, -24(%ebp) # long int movl $6, -32(%ebp) # long long int movl $0, -28(%ebp) movl $0x40e00000, %eax movl %eax, -36(%ebp) fldl LC2 fstpl -48(%ebp) leave ret I compiled the same code on 64-Bit processor (Intel Core 2 Duo) on GCC (linux) legacyTypes: .LFB2: .cfi_startproc pushq %rbp .cfi_def_cfa_offset 16 movq %rsp, %rbp .cfi_offset 6, -16 .cfi_def_cfa_register 6 movb $97, -1(%rbp) # char movb $97, -2(%rbp) # signed char movb $97, -3(%rbp) # unsigned char movl $1, -12(%rbp) # int movl $-2, -16(%rbp)# signed int movl $3, -20(%rbp) # unsigned int movw $4, -6(%rbp) # short int movq $5, -32(%rbp) # long int movq $6, -40(%rbp) # long long int movl $0x40e00000, %eax movl %eax, -24(%rbp) movabsq $4620693217682128896, %rax movq %rax, -48(%rbp) leave ret Observations char, signed char, unsigned char, int, unsigned int, signed int, short int, unsigned short int, signed short int all occupy same no. of bytes on both 32-Bit & 64-Bit Processor. The only change is in long int & long long int both of these occupy 32-bit on 32-bit machine & 64-bit on 64-bit machine. And also the pointers, which take 32-bit on 32-bit CPU & 64-bit on 64-bit CPU. Questions: I cannot say, what the books say is wrong. But I'm missing something here. What exactly does "Variable types are machine dependent mean?" As you can see, There is no difference between instructions for unsigned & signed numbers. Then how come the range of numbers that can be addressed using both is different? I was reading http://stackoverflow.com/questions/2511246/how-to-maintain-fixed-size-of-c-variable-types-over-different-machines I didn't get the purpose of the question or their answers. What maintaining fixed size? They all are the same. I didn't understand how those answers are going to ensure the same size.

    Read the article

  • Software Protection: Shuffeling my application?

    - by Martijn Courteaux
    Hi, I want to continue on my previous question: http://stackoverflow.com/questions/3007168/torrents-can-i-protect-my-software-by-sending-wrong-bytes Developer Art suggested to add a unique key to the application, to identifier the cracker. But JAB said that crackers can search where my unique key is located by checking for binary differences, if the cracker has multiple copies of my software. Then crackers change that key to make them self anonymous. That is true. Now comes the question: If I want to add a unique key, are there tools to shuffle (a kind of obfuscation) the program modules? So, that a binary compare would say that the two files are completely different. So they can't locate the identifier key. I'm pretty sure it is possible (maybe by replacing assembler blocks and make some jumps). I think it would be enough to make 30 to 40 shuffles of my software. Thanks

    Read the article

< Previous Page | 112 113 114 115 116 117 118 119 120 121 122 123  | Next Page >