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  • CLR JIT Bugs Found During IKVM.NET Development

    "It is actually fairly common that people notice that things fail under retail but not debug and tend to blame code generation. While a code generation bug is possible, as a matter of statistics, it is not likely." -- Vance MorrisonDateCLRArchTypeDescription2010-06-12 v4 x64 Incorrect code Optimizer incorrectly propagates invariants.2010-06-04 v2, v4 x86 Crash ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Thanks for Stopping by at Oracle Open World

    - by Etienne Remillon
    Thanks to hundreds of our customers and more specifically to our directory friends that came to Oracle Open World and meet with us at: One of our two OUD booth: Next Generation Directory in the Middleware demo-ground Optimized Solution for Oracle Unified Directory in the Hardware demo-ground Our well attended session on Next Generation Directory: Oracle Unified Directory One of our other gathering evens Was always a good opportunity to discuss your directory usages, expansion plan, expected evolutions and enhancements. Big thanks for making Oracle Open World 2012 a big event!

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  • What is meant by 4 GL?

    - by Geek
    I came across the term 4GL(generation language) in reading about Oracle ADF Busniess components . I want to know what exactly is 4GL ? This is the actual quote from the book Oracle Fusion Guide: Oracle ADF Business Components is the business services layer of choice in Oracle Fusion application development. Compared to other persistence layers, ADF Business Components provides exceptional built-in business application functionality and maximally declarative experience that makes it a perfect match for those who seek an end-to-end fourth generation language (4GL) Java EE development architecture.

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  • Multiple vulnerabilities in Wireshark

    - by RitwikGhoshal
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2012-4048 Improper Control of Generation of Code ('Code Injection') vulnerability 3.3 Wireshark Solaris 11 11/11 SRU 11.4 CVE-2012-4049 Improper Control of Generation of Code ('Code Injection') vulnerability 2.9 This notification describes vulnerabilities fixed in third-party components that are included in Oracle's product distributions.Information about vulnerabilities affecting Oracle products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • Testez Windows Server 2012 avec Ikoula, l'hébergeur basé à Reims met à jour sa gamme de serveurs dédiés avec les Ivy Bridge d'Intel

    Testez Windows Server 2012 avec Ikoula L'hébergeur basé à Reims met à jour sa gamme de serveurs dédiés avec des processeurs Intel de dernière génération L'hébergeur Ikoula vient d'annoncer qu'il avait mis à jour ses serveurs dédiés avec des processeurs Ivy Bridge d'Intel de dernière génération, des mémoires RAM allant de 4 à 32 Go et des disques pouvant supporter jusqu'à 2 To de données. Cette rentrée est également celle de Windows Server, avec l'arrivée de la version 2012 de la déclinaison pour serveurs...

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  • Trying to configure HWIC-3G-HSPA

    - by user1174838
    I'm trying to configure a couple of Cisco 1941 routes. The are both identical routers. Each as a HWIC-1T (Smart Serial interface) and a HWIC-3G-HSPA 3G interface. These routers are to be sent to remote sites. We have connectivity to one of the sites but if remote site A gors down we lose connectivity to remote site B. The HWIC-1T is the primary WAN interface using frame relay joining the two remote sites We want the HWIC-3G-HSPA to be usable for direct connectivity from head office to remote site B, and also the HWIC-3G-HSPA is do be used for comms between the remote sites when the frame relay is down (happens quite a bit). I initialy tried to do dynamic routing using EIGRP however in my lab setup of laptop - 1941 - 1941 - laptop, I was unable to get end to end connectivity. I later settled on static routing and have got end to end connectivity but only over frame relay, not the HWIC-3G-HSPA. The sanitized running config for remote site A: version 15.1 service tcp-keepalives-in service tcp-keepalives-out service timestamps debug datetime msec service timestamps log datetime msec service password-encryption service udp-small-servers service tcp-small-servers ! hostname remoteA ! boot-start-marker boot-end-marker ! ! logging buffered 51200 warnings enable secret 5 censored ! no aaa new-model clock timezone wst 8 0 ! no ipv6 cef ip source-route ip cef ! ip domain name yourdomain.com multilink bundle-name authenticated ! chat-script gsm "" "ATDT*98*1#" TIMEOUT 30 "CONNECT" ! username admin privilege 15 secret 5 censored ! controller Cellular 0/1 ! interface Embedded-Service-Engine0/0 no ip address shutdown ! interface GigabitEthernet0/0 ip address 192.168.2.5 255.255.255.0 duplex auto speed auto ! interface GigabitEthernet0/1 no ip address shutdown duplex auto speed auto ! interface Serial0/0/0 ip address 10.1.1.2 255.255.255.252 encapsulation frame-relay cdp enable frame-relay interface-dlci 16 frame-relay lmi-type ansi ! interface Cellular0/1/0 ip address negotiated encapsulation ppp dialer in-band dialer idle-timeout 2147483 dialer string gsm dialer-group 1 async mode interactive ppp chap hostname censored ppp chap password 7 censored cdp enable ! interface Cellular0/1/1 no ip address encapsulation ppp ! interface Dialer0 no ip address ! ip forward-protocol nd ! no ip http server no ip http secure-server ! ip route 0.0.0.0 0.0.0.0 Serial0/0/0 210 permanent ip route 0.0.0.0 0.0.0.0 Cellular0/1/0 220 permanent ip route 172.31.2.0 255.255.255.0 Cellular0/1/0 permanent ip route 192.168.3.0 255.255.255.0 10.1.1.1 permanent ip route 192.168.3.0 255.255.255.0 Cellular0/1/0 210 permanent ! access-list 1 permit any dialer-list 1 protocol ip list 1 ! control-plane ! line con 0 logging synchronous login local line aux 0 line 2 no activation-character no exec transport preferred none transport input all transport output pad telnet rlogin lapb-ta mop udptn v120 ssh stopbits 1 line 0/1/0 exec-timeout 0 0 script dialer gsm login modem InOut no exec transport input all rxspeed 7200000 txspeed 5760000 line 0/1/1 no exec rxspeed 7200000 txspeed 5760000 line vty 0 4 access-class 23 in privilege level 15 password 7 censored login local transport input all line vty 5 15 access-class 23 in privilege level 15 password 7 censored login local transport input all line vty 16 1370 password 7 censored login transport input all ! scheduler allocate 20000 1000 end The sanitized running config for remote site B: version 15.1 service tcp-keepalives-in service tcp-keepalives-out service timestamps debug datetime msec service timestamps log datetime msec service password-encryption service udp-small-servers service tcp-small-servers ! hostname remoteB ! boot-start-marker boot-end-marker ! logging buffered 51200 warnings enable secret 5 censored ! no aaa new-model clock timezone wst 8 0 ! no ipv6 cef ip source-route ip cef ! no ip domain lookup ip domain name yourdomain.com multilink bundle-name authenticated ! chat-script gsm "" "ATDT*98*1#" TIMEOUT 30 "CONNECT" username admin privilege 15 secret 5 censored ! controller Cellular 0/1 ! interface Embedded-Service-Engine0/0 no ip address shutdown ! interface GigabitEthernet0/0 ip address 192.168.3.1 255.255.255.0 duplex auto speed auto ! interface GigabitEthernet0/1 no ip address shutdown duplex auto speed auto ! interface Serial0/0/0 ip address 10.1.1.1 255.255.255.252 encapsulation frame-relay clock rate 2000000 cdp enable frame-relay interface-dlci 16 frame-relay lmi-type ansi frame-relay intf-type dce ! interface Cellular0/1/0 ip address negotiated encapsulation ppp dialer in-band dialer idle-timeout 2147483 dialer string gsm dialer-group 1 async mode interactive ppp chap hostname censored ppp chap password 7 censored ppp ipcp dns request cdp enable ! interface Cellular0/1/1 no ip address encapsulation ppp ! interface Dialer0 no ip address ! ip forward-protocol nd ! no ip http server no ip http secure-server ! ip route 0.0.0.0 0.0.0.0 Serial0/0/0 210 permanent ip route 0.0.0.0 0.0.0.0 Cellular0/1/0 220 permanent ip route 172.31.2.0 255.255.255.0 Cellular0/1/0 permanent ip route 192.168.2.0 255.255.255.0 10.1.1.2 permanent ip route 192.168.2.0 255.255.255.0 Cellular0/1/0 210 permanent ! kron occurrence PING in 1 recurring policy-list ICMP ! access-list 1 permit any dialer-list 1 protocol ip list 1 ! control-plane ! line con 0 logging synchronous login local line aux 0 line 2 no activation-character no exec transport preferred none transport input all transport output pad telnet rlogin lapb-ta mop udptn v120 ssh stopbits 1 line 0/1/0 exec-timeout 0 0 script dialer gsm login modem InOut no exec transport input all rxspeed 7200000 txspeed 5760000 line 0/1/1 no exec rxspeed 7200000 txspeed 5760000 line vty 0 4 access-class 23 in privilege level 15 password 7 censored login transport input all line vty 5 15 access-class 23 in privilege level 15 password 7 censored login transport input all line vty 16 1370 password 7 censored login transport input all ! scheduler allocate 20000 1000 end The last problem I'm having is the 3G interfaces go down after only a few minutes of inactivity. I've tried using kron to ping the local HWIC-3G-HSPA interface (cellular 0/1/0) every minute but that hasn't been successful. Manually pinging the IP assigned (by the telco) to ce0/1/0 does bring the interface up. Any ideas? Thanks

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  • call a class method from inside an instance method from a module mixin (rails)

    - by sean
    Curious how one would go about calling a class method from inside an instance method of a module which is included by an active record class. For example I want both user and client models to share the nuts and bolts of password encryption. # app/models class User < ActiveRecord::Base include Encrypt end class Client < ActiveRecord::Base include Encrypt end # app/models/shared/encrypt.rb module Encrypt def authenticate # I want to call the ClassMethods#encrypt_password method when @user.authenticate is run self.password_crypted == self.encrypt_password(self.password) end def self.included(base) base.extend ClassMethods end module ClassMethods def encrypt_password(password) Digest::SHA1.hexdigest(password) end end end However, this fails. Says that the class method cannot be found when the instance method calls it. I can call User.encrypt_password('password') but User.new.encrypt_password fails Any thoughts?

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  • Cannot add margin to Legend element in Safari & Chrome

    - by Graham
    I have some pretty straightforward markup: <form action=""> <fieldset class="compact"> <legend>Member Tools</legend> <label for="username">Username</label> <input name="username" id="username" type="text"/> <label for="password">Password</label> <input name="password" id="password" type="password" /> </fieldset> </form> I am attempting to add a small margin to the bottom of the Legend element, this works just fine in Firefox 2 and 3 as well as IE 5-8, however in Safari and Chrome adding a margin does nothing. As far as I know legend is just another block level element and Webkit should have no issue adding a margin to it, or am I incorrect?

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  • iPhone: Issue disabling Auto-Cap/autocorrect on a UITextField

    - by phil swenson
    For some reason, even though I disable the auto-cap and auto-correct of my UITextField, it's still capitalizing the first letter of my input. Here is the code: UITextField* textField = [[[UITextField alloc] initWithFrame:CGRectMake(90.0, 10.0, 213.0, 25.0)] autorelease]; [textField setClearButtonMode:UITextFieldViewModeWhileEditing]; textField.returnKeyType = UIReturnKeyGo; textField.autocorrectionType = FALSE; textField.autocapitalizationType = UITextAutocapitalizationTypeNone; textField.delegate = self; if (inputFieldType == Email) { label.text = @"Email:"; textField.keyboardType = UIKeyboardTypeEmailAddress; emailTextField = textField; textField.placeholder = @"Email Address"; } else { // password textField.secureTextEntry = TRUE; label.text = @"Password:"; if (inputFieldType == Password){ textField.placeholder = @"Password"; passwordTextField = textField; } if (inputFieldType == ConfirmPassword){ textField.placeholder = @"Confirm Password"; confirmPasswordTextField = textField; } } See screenshot:

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  • Unable to compare valuesfrom mysql in a prepared statement

    - by Cortopasta
    I can't seem to get this to connect to the database so that I can run my prepared statement. Does anybody have an idea what I've forgotten? private function check_credentials($plain_username, $password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $password); $userid->execute(); $id = $userid->fetch(); Return $id; } EDIT: I changed the SQL query from a SELECT FROM query, to an INSERT INTO query and it worked. WHat the heck is going on?

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  • Invalid character in a Base-64 string

    - by swetha
    I am getting this error when I am validating the user with sql membership provider this.provider.ValidateUser(userName, password); the password i have used is "freetrial". I tried trimming the spaces but still no luck!!! and the call stack is as follows: [FormatException: Invalid character in a Base-64 string.] System.Convert.FromBase64String(String s) +0 System.Web.Security.MembershipProvider.EncodePassword(String pass, Int32 passwordFormat, String salt) +54 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved, String& salt, Int32& passwordFormat) +169 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved) +42 System.Web.Security.SqlMembershipProvider.ValidateUser(String username, String password) +78

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  • PDO prepared statement not working for login system

    - by Cortopasta
    Anybody no what I'm doing wrong here? I have a username and password hashed in my database, but i can't seem to get it to match the one I submit through the script. $res = $dbcon->prepare('SELECT id FROM users WHERE name = :name AND password = MD5(:password)'); $res->bindParam(':name', $user); $res->bindParam(':password', $password); $res->execute(); $row = $res->fetch(); for ($i=0; $i<7; $i++) { $row[$i]; }

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  • Stop browser from filling textboxes with details

    - by TenaciousImpy
    Hi, I've run into a really annoying problem, and I'm hoping it's just a setting I've missed. I've got an ASP.NET application which allows users to enter their username/password in various places (e.g. login, change password, change username etc..). When I logged in, the browser asked if I would like to store the user details. Usually, I click 'no', but this time I decided to click 'yes'. Now, certain textboxes in my form are prefilled with the username or password. Is it possible to remove these, as they sometimes appear in textboxes which shouldn't be prefilled. I tried setting AutoCompleteType=none and Text='' but it still gets prefilled. The textboxes don't have much in common, except the same CssClass and, for password boxes, TextMode=password. The names are different, although sometimes they include the word name (e.g. fullName, userName). Is there a way to stop the browser from filling certain textboxes? Thanks

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  • How can I set controls for a web page ??

    - by Rami Jarrar
    I have this login page with https, and i reach to this approach:: import ClientForm import urllib2 request = urllib2.Request("http://ritaj.birzeit.edu") response = urllib2.urlopen(request) forms = ClientForms.ParseResponseEx(response) response.close() f = forms[0] username = str(raw_input("Username: ")) password = str(raw_input("Password: ")) ## Here What To Do request2 = form.click() i get the controls of that page >>> f = forms[0] >>> [c.name for c in f.controls] ['q', 'sitesearch', 'sa', 'domains', 'form:mode', 'form:id', '__confirmed_p', '__refreshing_p', 'return_url', 'time', 'token_id', 'hash', 'username', 'password', 'persistent_p', 'formbutton:ok'] so how can i set the username and password controls of the "non-form form" f ??? and i have another problem,, how to know if its the right username and password ??

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  • Cookbook: SES and UCM setup

    - by George Maggessy
    The purpose of this post is to guide you setting up the integration between UCM and SES. On my next post I’ll show different approaches to integrate WebCenter Portal, UCM and SES based on some common scenarios. Let’s get started. WebCenter Content Configuration WebCenter Content has a component that adds functionality to the content server to allow it to be searched via the Oracle SES. To enable the component installation, go to Administration -&gt; Admin Server and select SESCrawlerExport. Click the update button and restart UCM_server1 managed server. Once the managed server is back, we’ll configure the component. In the menu, under Administration you should see SESCrawlerExport. Click on the link. You’ll see the window below. Click on Configure SESCrawlerExport. Configure the values below: Hostname: SES hostname. Feed Location: Directory where data feeds will be saved. Metadata List: List of metadata that will be searchable by SES. After updating the values click on the Update button. Come back to the SESCrawlerExport Administration UI and click on Take Snapshot button. It will create the data feeds in the specified Feed Location. To check if the correct configuration was done, please access the following URL http://&lt;ucm_server&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWLOAD_CONFIG&amp;source=default. It should download config file in the format below: &lt;?xml version="1.0" encoding="UTF-8"?&gt; &lt;rsscrawler xmlns="http://xmlns.oracle.com/search/rsscrawlerconfig"&gt; &lt;feedLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONTROL&amp;source=default]]&gt;&lt;/feedLocation&gt; &lt;errorFileLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_STATUS&amp;IsJava=1&amp;source=default&amp;StatusFeed=]]&gt;&lt;/errorFileLocation&gt; &lt;feedType&gt;controlFeed&lt;/feedType&gt; &lt;sourceName&gt;default&lt;/sourceName&gt; &lt;securityType&gt;attributeBased&lt;/securityType&gt; &lt;securityAttribute name="Account" grant="true"/&gt; &lt;securityAttribute name="DocSecurityGroup" grant="true"/&gt; &lt;securityAttribute name="Collab" grant="true"/&gt; &lt;/rsscrawler&gt; Make sure Account and DocSecurityGroup values are true. SES Configuration Let’s start by configuring the Identity Plug-ins in SES. Go to Global Settings -&gt; System -&gt; Identity Management Setup. Select Oracle Content Server and click the Activate button. We’ll populate the following values: HTTP endpoint for authentication: URL to WebCenter Content. Notice that /cs/idcplg was added at the end of the URL. Admin User: UCM Admin user. This user must have access to all CPOE content. Password: Password to Admin user. Authentication Type: NATIVE. Go back to the Home tab and click on Sources on the top left. Select Oracle Content Server on the right and click the Create button. Configuration URL: URL that point to the configuration file. Example: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONFIG&amp;source=default. User ID: UCM Admin user. Password: Password to Admin user. Click on the Authorization tab and add the appropriate values to the fields below. Make sure you see the ACCOUNT and DOCSECURITYGROUP security attributes at the end of the page. HTTP endpoint for authorization: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg. Display URL prefix: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs. Administrator user: UCM Admin user. Administrator password. On the Document Types tab, add the documents that should be indexed by SES. As our last step, we’ll configure the Federation Trusted Entities under Global Settings. Entity Name: The user must be present in both the identity management server configured for your WebCenter application and the identity management server configured for Oracle SES. For instance, I used weblogic in my sample. Password: Entity user password.\ Now you are ready to test the integration on the SES UI: http://&lt;ses hostname&gt;:&lt;port&gt;/search/query/.

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  • Encryption using rijndael

    - by user363295
    Hi all. I'm quite new in programming .I wrote the below code in order to prompt the user for a password to encrypting a file, But it just work when the length of password is 8, What can I do on order to accepting any number of characters for the password? string pass = textBox2.Text.ToString(); string password = @"" + pass + ""; UnicodeEncoding UE = new UnicodeEncoding(); byte[] key = UE.GetBytes(password); FileStream fsCrypt = new FileStream(@"c:\\users\\new", FileMode.Create); name = fsCrypt.Name; RijndaelManaged RMCrypto = new RijndaelManaged(); CryptoStream cs = new CryptoStream(fsCrypt, RMCrypto.CreateEncryptor(key, key), CryptoStreamMode.Write); FileStream fsIn = new FileStream(filename, FileMode.Open); int data; while ((data = fsIn.ReadByte()) != -1) cs.WriteByte((byte)data);

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  • SQL Encryption - Asymmetric Key - 2nd Server

    - by Jason Heine
    Hello, I created an asymmetric key on one of my SQL servers (2008). I encrypted a password field and I am able to retrieve that password just fine on my development server. The issue comes into play where I need to move this data to a production server. Here is the code for the key that was created: CREATE MASTER KEY ENCRYPTION BY PASSWORD='#########' CREATE ASYMMETRIC KEY UserEncryptionKey WITH ALGORITHM = RSA_2048 Now, when I run this on the production server, it creates the key just fine. However, when I run my sproc to get the password, it returns NULL. SQL: SELECT EncryptByAsymKey(AsymKey_ID('UserEncryptionKey'), Password ) FROM Users WHERE UserName = '######' Any thoughts on what I need to do to get the encrypted field to work on multiple SQL Servers? Please let me know if I need to clarify something. Thanks

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  • How can I login in a website with Pyhon?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log. I have this source from the site <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> It's possible?

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  • Why does this regular expression fail?

    - by Stephen
    I have a password validation script in PHP that checks a few different regular expressions, and throws a unique error message depending on which one fails. Here is an array of the regular expressions and the error messages that are thrown if the match fails: array( 'rule1' => array( '/^.*[\d].*$/i', 'Password must contain at least one number.' ), 'rule2' => array( '/^.*[a-z].*$/i', 'Password must contain at least one lowercase letter' ), 'rule3' => array( '/^.*[A-Z].*$/i', 'Password must contain at least one uppercase letter' ), 'rule4' => array( '/^.*[~!@#$%^&*()_+=].*$/i', 'Password must contain at least one special character [~!@#$%^&*()_+=]' ) ); For some reason, no matter what I pass through the validation, the "Special Characters" rule fails. I'm guessing it's a problem with the expression. If there's a better (or correct) way to write these expressions, I'm all ears!

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  • How secure is a PostgreSQL database if my server is stolen?

    - by orokusaki
    If I have a server with a database if top secret data in PostgreSQL and my password is practically impossible to crack (128 character string of all sorts of weird chars, generated by hand). The server password is also uncrackable in theory (basically, ignore the possibility of a password crack on the DB). Aside from a password crack, how easy is it to get the data out of this database? Assumptions: Only the DB exists on the server. There is no password in a PHP script or anything like that The person who has the server is a computer / DB / hard-drive recovery expert I'm not using any hard-drive encryption or anything out of the norm for protection I'm trying to understand the risks involved with somebody gaining physical access to my server's hard-drives.

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  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

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  • How do I get phpMyAdmin to connect to a local mysql server?

    - by bryan
    Hi everyone, I have my config.inc.php file, and have set my host name to localhost. Unfortunately, I have no idea what my username/password should be. Is that something I need to configure on the MySql side? I tried creating an arbitrary username/password (admin/password), but when I try to log into phpMyAdmin with those credentials, I get an error: (#1045 - Access denied for user 'admin'@'localhost' (using password: YES)) Can anyone point me in the right direction? (Sorry for the dumb question; I just haven't had to install mysql before. I've always had a host name / username / password given to me.) Thanks!

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  • I want to design a html form in python

    - by VaIbHaV-JaIn
    when user will enter details in the text box on the html from <h1>Please enter new password</h1> <form method="POST" enctype="application/json action="uid"> Password<input name="passwd"type="password" /><br> Retype Password<input name="repasswd" type="password" /><br> <input type="Submit" /> </form> </body> i want to post the data in json format through http post request and also i want to set content-type = application/json

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  • Encryption-Decryption in Rails

    - by Salil
    Hi All, I am using require 'digest/sha1' to encrypt my password and save into database. During login I authenticate by matching the encrypted password saved in database and again encrypted the one use enter in password field. As of now everything works fine but now I want to do 'Forgot Password' functionality. To do this I need to decrypt the password which is saved in database to find original one. How to decrypt using digest/sha1? Or does anyone know any algorithm which supports encryption & decryption as well? I am using ruby on rails so I need Ruby way to accomplish it.

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  • How to manually verify a user against the asp.net memberhip database

    - by Ekk
    I would like to know how I can verify a user's credential against an existing asp.net membership database. The short story is that we want provide single sign on access. So what I've done is to connect directly to the membership database and tried to run a sql query against the aspnet_Membership table: private bool CanLogin(string userName, string password) { // Check DB to see if the credential is correct try { string passwordHash = FormsAuthentication.HashPasswordForStoringInConfigFile(password, "SHA1"); string sql = string.Format("select 1 from aspnet_Users a inner join aspnet_Membership b on a.UserId = b.UserId and a.applicationid = b.applicationid where a.username = '{0}' and b.password='{1}'", userName.ToLowerInvariant(), passwordHash); using (SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString)) using (SqlCommand sqlCmd = new SqlCommand(sql, sqlConn)) { sqlConn.Open(); int count = sqlCmd.ExecuteNonQuery(); sqlConn.Close(); return count == 1; } } catch (Exception ex) { return false; } } The problem is the password value, does anyone know how the password it is hashed?

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