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  • how to concatinate a link with <select> <option> value on "onchange" event

    - by atif
    <?php echo $this->getUrl(); ?> = this gives me my index page url .i.e. www.domain.com/index.php/ but now wat i want is when any particular option is selected, it should add to this url. .e.g. www.domain.com/index.php/wordpress/ i write this code for it but now don know how to get it done :( <select onchange="setLocation('<?php echo $this->getUrl(); ?>')"> <option value="">&nbsp;</option> <option value="wordpress">Wordpress</option> <option value="drupal">drupal</option> <option value="magento">Megento</option> </select> also i had searched this link but couldn't take help from it. As it didnt work for me. <select name="forma" ONCHANGE="location = this.options[this.selectedIndex].value;"> <option value="Home">Home</option> <option value="Contact">Contact</option> <option value="Sitemap">Sitemap</option> </select>

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  • Understanding REST: is GET fundamentally incompatible with any "number of views" counter?

    - by cocotwo
    I'm trying to understand REST. Under REST a GET must not trigger something transactional on the server (this is a definition everybody agrees upon, it is fundamental to REST). So imagine you've got a website like stackoverflow.com (I say like so if I got the underlying details of SO wrong it doesn't change anything to my question), where everytime someone reads a question, using a GET, there's also some display showing "This question has been read 256 times". Now someone else reads that question. The counter now is at 257. The GET is transactional because the number of views got incremented and is now incremented again. The "number of views" is incremented in the DB, there's no arguing about that (for example on SO the number of time any question has been viewed is always displayed). So, is a REST GET fundamentally incompatible with any kind of "number of views" like functionality in a website? So should it want to be "RESTFUL", should the SO main page either stop display plain HTML links that are accessed using GETs or stop displaying the "this question has been viewed x times"? Because incrementing a counter in a DB is transactional and hence "unrestful"? EDIT just so that people Googling this can get some pointers: From http://www.xfront.com/REST-Web-Services.html : 4. All resources accessible via HTTP GET should be side-effect free. That is, the request should just return a representation of the resource. Invoking the resource should not result in modifying the resource. Now to me if the representation contains the "number of views", it is part of the resource [and in SO the "number of views" a question has is a very important information] and accessing it definitely modifies the resource. This is in sharp contrast with, say, a true RESTFUL HTTP GET like the one you can make on an Amazon S3 resource, where your GET is guaranteed not to modify the resource you get back. But then I'm still very confused.

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  • flex 4 release changes to application are not showing up.

    - by guacamoly
    I just took over a clients flex project and I can't get the app to reflect even a simple trace statement. Before I took over, the project was last successfully built using the Flash Builder Beta 2 environment/sdk. I have the latest release version of Flash Builder 4. Upon importing the project into FB4, I got a ton of errors. Most of them mostly because of the changes made to the sdk from beta2 to release. Some of the things I corrected: - mx namespace from library://ns.adobe.com/flex/halo to library://ns.adobe.com/flex/mx - video player skinning: a lot of the state names for the video player component had been changed, more required states had been added. also there were other video related component and property names that had to be updated. But I fixed all that and the application was finally able to compile (although with some warnings mostly of the duplicate variable type) The only thing now is that whatever change I make to the project doesn't get reflected in the build (debug or release). I changed existing traces, added additional traces. Nothing shows up. I even removed the applicationComplete property in the main.mxml. Everything still ran like nothing changed. Also I can't seem to debug the app. Whenever I try to debug.. flash builder says.. "Swf Application doesn't contain the required debugging information ... " Anyone have any idea how I need to even begin tackling all this? Any help or pointers would be greatly appreciated.

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  • GWT with JPA - no persistence provider...

    - by meliniak
    GWT with JPA There are two projects in my eclipse workspace, let's name them: -JPAProject -GWTProject JPAProject contains JPA configuration stuff (persistence.xml, entity classes and so on). GWTProject is an examplary GWT project (taken from official GWT tutorial). Both projects work fine alone. That is, I can create EMF (EntityManagerFactory) in JPAProject and get entities from the database. GWTProject works fine too, I can run it, fill the field text in the browser and get the response. My goal is to call JPAProject from GWTProject to get entities. But the problem is that when calling DAO, I get the following exception: [WARN] Server class 'com.emergit.service.dao.profile.ProfileDaoService' could not be found in the web app, but was found on the system classpath [WARN] Adding classpath entry 'file:/home/maliniak/workspace/emergit/build/classes/' to the web app classpath for this session [WARN] /gwttest/greet javax.persistence.PersistenceException: No Persistence provider for EntityManager named emergitPU at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at com.emergit.service.dao.profile.JpaProfileDaoService.<init>(JpaProfileDaoService.java:19) at pl.maliniak.server.GreetingServiceImpl.<init>(GreetingServiceImpl.java:21) . . . at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488) [ERROR] 500 - POST /gwttest/greet (127.0.0.1) 3812 bytes I guess that the warnings at the beginning can be omitted for now. Do you have any ideas? I guess I am missing some basic point. All hints are highly apprecieable.

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  • Spring validation has error in XML document from ServletContext resource

    - by user1441404
    I applied spring validation in my registration page .but the follwing error are shown in my server log of my app engine server. javax.servlet.UnavailableException: org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 22 in XML document from ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 22; columnNumber: 30; cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'property'. My code is given below : <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd > <beans:bean name="/register" class="com.my.registration.NewUserRegistration"> <property name="validator"> <bean class="com.my.validation.UserValidator" /> </property> <beans:property name="formView" value="newuser"></beans:property> <beans:property name="successView" value="home"></beans:property> </beans:bean> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> </beans:beans>

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  • I need help on this data file to be edited in SOM_PAK format

    - by Mola
    Hi Experts, I am working on Self Organizing Map (SOM) Implementation and i have a microarray dataset which i am trying to read in using some_read_data function, but i keep having an errors when i edit it to have it in SOM_PAK form which is recognise by SOM for reading such as ??? Error using == somtoolbox\som_read_data.m Only 69 vector components on input file data line 1 (dimension is 70) Error in == SomMainFunction at 3 sD = som_read_data('B_r2.txt'); but when i try to read the data without editing which is the original file as shown here: http://rapidshare.com/files/376239367/DLBCL.txt.html It indicates "Data read OK", but i have the following error ??? Error using == unknown Out of memory. Type HELP MEMORY for your options. Error in == somtoolbox\som_bmus.m at 189 Bmus = zeros(dlen,length(which_bmus)); Error in == somvis\somvis_p_matrix.m at 41 [dummy dists] = som_bmus (dat, dat, 2:datlen); Error in == SomMainFunction at 16 [pheight rad_real perc] = somvis_p_matrix(sM,sD); You can get the datafile from here:http://rapidshare.com/files/376239367/DLBCL.txt.html I need someone to help me correct this data for me and put it in SOM_PAK format. I have tried getting it in SOM_PAK format, but it still giving me errors:

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  • Recursion through a directory tree in PHP

    - by phphelpplz
    I have a set of folders that has a depth of at least 4 or 5 levels. I'm looking to recurse through the directory tree as deep as it goes, and iterate over every file. I've gotten the code to go down into the first sets of subdirectories, but no deeper, and I'm not sure why. Any ideas? $count = 0; $dir = "/Applications/MAMP/htdocs/idahohotsprings.com"; function recurseDirs($main, $count){ $dir = "/Applications/MAMP/htdocs/idahohotsprings.com"; $dirHandle = opendir($main); echo "here"; while($file = readdir($dirHandle)){ if(is_dir($file) && $file != '.' && $file != '..'){ echo "isdir"; recurseDirs($file); } else{ $count++; echo "$count: filename: $file in $dir/$main \n<br />"; } } } recurseDirs($dir, $count); ?

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  • NoClassDefFoundError when trying to reference external jar files

    - by opike
    I have some 3rd party jar files that I want to reference in my tomcat web application. I added this line to catalina.properties: shared.loader=/home/ollie/dev/java/googleapi_samples/gdata/java/lib/*.jar but I'm still getting this error: org.apache.jasper.JasperException: javax.servlet.ServletException: java.lang.NoClassDefFoundError: com/google/gdata/util/ServiceException org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:491) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:401) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) I verified that the com.google.gdata.util.ServiceException is in the gdata-core-1.0.jar file which is in the directory: /home/ollie/dev/java/googleapi_samples/gdata/java/lib I did bounce tomcat after I modified catalina.properties. Update 1: I tried copying the gdata-core-1.0.jar file into /var/lib/tomcat6/webapp/examples/WEB-INF/lib as a test but that didn't fix the problem either. Update 2: It actually does work when I copy the jar file directly into the WEB-INF/lib directory. There was a permissions issue that I had to resolve. But it's still not working when I use the shared.loader setting. I reconfirmed that the path is correct.

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  • xsl defining in xml

    - by aditya parikh
    My first few lines in movies.xml are as follows : <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="movies_style.xsl"?> <movies xmlns="http://www.w3schools.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.w3schools.com file:///B:/USC/Academic/DBMS/HWS/no3/movie_sch.xsd"> and first few lines in movies_style.xsl are as follows : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format"> Problem is if remove schema file linking from movies.xml file and keep tag only as <movies> then proper styled table is shown as output else nothing is displayed in browser and error is displayed in console as: "Unsafe attempt to load URL file:///B:/USC/Academic/DBMS/HWS/no3/movies_style.xsl from frame with URL file:///B:/USC/Academic/DBMS/HWS/no3/movies.xml. Domains, protocols and ports must match." Looks like some namespace mistake. Can anyone point out exactly what ?

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  • Heroku: Postgres type operator error after migrating DB from MySQL

    - by sevennineteen
    This is a follow-up to a question I'd asked earlier which phrased this as more of a programming problem than a database problem. http://stackoverflow.com/questions/2935985/postgres-error-with-sinatra-haml-datamapper-on-heroku I believe the problem has been isolated to the storage of the ID column in Heroku's Postgres database after running db:push. In short, my app runs properly on my original MySQL database, but throws Postgres errors on Heroku when executing any query on the ID column, which seems to have been stored in Postgres as TEXT even though it is stored as INT in MySQL. My question is why the ID column is being created as INT in Postgres on the data transfer to Heroku, and whether there's any way for me to prevent this. Here's the output from a heroku console session which demonstrates the issue: Ruby console for myapp.heroku.com >> Post.first.title => "Welcome to First!" >> Post.first.title.class => String >> Post.first.id => 1 >> Post.first.id.class => Fixnum >> Post[1] PostgresError: ERROR: operator does not exist: text = integer LINE 1: ...", "title", "created_at" FROM "posts" WHERE ("id" = 1) ORDER... ^ HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. Query: SELECT "id", "name", "email", "url", "title", "created_at" FROM "posts" WHERE ("id" = 1) ORDER BY "id" LIMIT 1 Thanks!

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  • Inconsistent GWT behavior in IE 8

    - by Don Branson
    All, I have a web site that's built with GWT at https://penwag.com/penwag/. If you just hit the site and see the main page, there's supposed to be a login/registration area that displays, along with a teaser for the site. I've tried the site with most of the main browsers - FF 3 & 3.5, IE 6 & 8, Safari, and Chrome, and all appears well to me. However, I have a non-geek user that has visited the site from both work and home. The work computer can see the intro page fine, but the home computer shows only the static content, and non of the javascript-based portion, that is the login/registration and teaser. Both computers are using IE 8. He checked the computer where the site fails, and scripting is enabled. Can anyone else see the problem? (You don't have to register to see the problem, just hit the main page.) Anything else I should check or have him try? Thanks! Edit: The site is implemented using GWT 1.7.0. I'll have to find out about the OS versions. Edit: The one that works is running Windows XT, the failing one is running Windows Vista. (There's a shocker!) I myself have viewed it successfully with both OSs. Edit: I've since completely re-structured the site, and documented the changes here: http://penwag.blogspot.com/2010/04/april-penwag-update.html So, the site is no longer the same as when I asked this question.

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  • Login to website and use cookie to get source for another page

    - by Stu
    I am trying to login to the TV Rage website and get the source code of the My Shows page. I am successfully logging in (I have checked the response from my post request) but then when I try to perform a get request on the My Shows page, I am re-directed to the login page. This is the code I am using to login: private string LoginToTvRage() { string loginUrl = "http://www.tvrage.com/login.php"; string formParams = string.Format("login_name={0}&login_pass={1}", "xxx", "xxxx"); string cookieHeader; WebRequest req = WebRequest.Create(loginUrl); req.ContentType = "application/x-www-form-urlencoded"; req.Method = "POST"; byte[] bytes = Encoding.ASCII.GetBytes(formParams); req.ContentLength = bytes.Length; using (Stream os = req.GetRequestStream()) { os.Write(bytes, 0, bytes.Length); } WebResponse resp = req.GetResponse(); cookieHeader = resp.Headers["Set-cookie"]; String responseStream; using (StreamReader sr = new StreamReader(resp.GetResponseStream())) { responseStream = sr.ReadToEnd(); } return cookieHeader; } I then pass the cookieHeader into this method which should be getting the source of the My Shows page: private string GetSourceForMyShowsPage(string cookieHeader) { string pageSource; string getUrl = "http://www.tvrage.com/mytvrage.php?page=myshows"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookieHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); } return pageSource; } I have been using this previous question as a guide but I'm at a loss as to why my code isn't working.

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  • Werid onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

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  • iframe created dynamically with javascript not reloading parent URL

    - by Lauren
    I can't seem to reload the parent page from within an iframe even though the domain for my iframe and the parent page appear to be the same. The IFRAME was created dynamically, rather than in the HTML page source, so could that be the problem? The iframe I'm working with is here http://www.avaline.com/ R3000_3 once you log in. You may use user:test2@gmail.com pass: test03 Once logged in, hit the "order sample" button, and then hit "here" where it says "Your Third Party Shipper Numbers (To enter one, click here.)". I tried using javascript statements window.top.location.reload(),window.parent.location.reload(),window.parent.location.href=window.parent.location.href but none of those worked in FF 3.6 so I didn't move on to the other browsers although I am shooting for a cross-browser solution. I put the one-line javascript statements inside setTimeout("statement",2000) so people could read the content of the iframe before the redirect happens, but that shouldn't affect the execution of the statements... I wish I could test and debug the statements with the Firebug console from within the Iframe.

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  • linq to xml enumerating over descendants

    - by gh9
    Hi trying to write a simple linq query from a tutorial I read. But i cannot seem to get it to work. I am trying to display both the address in the attached xml document, but can only display the first one. Can someone help me figure out why both aren't being printed. Thank you very much <?xml version="1.0" encoding="utf-8" ?> <Emails> <Email group="FooBar"> <Subject>Test subject</Subject> <Content>Test Content</Content> <EmailTo> <Address>[email protected]</Address> <Address>[email protected]</Address> </EmailTo> </Email> </Emails> Dim steve = (From email In emailList.Descendants("Email") _ Where (email.Attribute("group").Value.Equals("FooBar")) _ Select content = email.Element("EmailTo").Descendants("Address")).ToList() If Not steve Is Nothing Then For Each addr In steve Console.WriteLine(addr.Value) Next Console.ReadLine() End If

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  • Google Analytics, Install Tracking android

    - by vvieux
    Hi, I want track install referer for my application using google analytics. I don't want use the Tracking Pageviews and Events feature, only install. So I added the sdk jar in my app, add these lines to the manifest : <receiver android:name="com.google.android.apps.analytics.AnalyticsReceiver" android:exported="true"> <intent-filter> <action android:name="com.android.vending.INSTALL_REFERRER" /> </intent-filter> </receiver> And publish the app. But how can see the stats ? I never entered my UA-xxxxxxx id. For the Pageviews and Events tracking it's here : tracker.start("UA-YOUR-ACCOUNT-HERE", this); But as thew readme says : (NOTE: do not start the GoogleAnalyticsTracker in your Application onCreate() method if using referral tracking). But with referer where do I put my id ? And what is the url to watch in the google analytics console ? Thx

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  • How to run an async task afor every x mins in android?

    - by Shan
    how to run the async task at specific time? (I want to run it every 2 mins) I tried using post delayed but it's not working? tvData.postDelayed(new Runnable(){ @Override public void run() { readWebpage(); }}, 100); In the above code readwebpage is function which calls the async task for me.. Right now below is the method which I am using public void onCreate(Bundle savedInstanceState) { readwebapage(); } public void readWebpage() { DownloadWebPageTask task = new DownloadWebPageTask(); task.execute("http://www.google.com"); } private class DownloadWebPageTask extends AsyncTask<String, Void, String> { @Override protected String doInBackground(String... urls) { String response1 = ""; response1=read(); //read is my another function which does the real work response1=read(); super.onPostExecute(response1); return response1; } protected void onPostExecute(String result) { try { Thread.sleep(100); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } TextView tvData = (TextView) findViewById(R.id.TextView01); tvData.setText(result); DownloadWebPageTask task = new DownloadWebPageTask(); task.execute(new String[] { "http://www.google.com" }); } } This is what I my code is and it works perfectly fine but the big problem I drains my battery?

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  • Font alignment problem in webkit based browsers

    - by Mike
    Here is the code: <style type="text/css"> html, body {font:0.9em/1.2em arial, verdana, helvetica, sans-serif;} #todayOn {background-color:#efefef; repeat-x top left;border-bottom:1px solid #ddd;border-top:1px solid #ddd;height:52px;margin:15px 0;} #todayOn #pageTitle {float:left;padding-left:3px;} #todayOn #pageTitle h2 {color:#feb425;font-size:32px;margin:10px 0 0 0;padding:0;} #todayOn #pageTitle h2 em {color:#7498c0;display:block;font-size:14px;font-style:italic;font-weight:normal;line-height:20px;padding:5px 0 0 0;} </style> <div id="todayOn"> <div id="pageTitle"> <h2>TODAY <em>on this page.com</em></h2> </div> </div> In Firefox, IE (6+), Opera, etc. the subheader "on this page.com" displays vertically how I want it to. In Webkit browsers like Chrome and Safari, it's pushed down a couple more pixels. What's the prob? Thanks.

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  • Reading XML or objects from a Web service

    - by Shawn
    This is my first time working with webservices and I am a bit lost. I successfully called the functions, but I only can get one value from the service. I read that the easiest way is to read xml or create objects and then call their values. Currently I use functions that return the desired value but I need to call them 3 times to get all the data witch is a waste of time and resources. I tried to call the service with the URL and use it as a website or getting the service to work the same way without importing into the program. The thing is that i cant find a way to pass the values into the url, because of that i get only blank pages. What is the fastest way to get my data from the services? I need city name, temperature and a flag if the city is valid. I need to pass the zip code to the service. Thank you. My current code wetther.Weather wether = new wetther.Weather(); string farenhait = wether.GetCityWeatherByZIP(zip).Temperature; string city = wether.GetCityWeatherByZIP(zip).City; bool correct = wether.GetCityWeatherByZIP(zip).Success; I tried it that way // Retrieve XML document XmlTextReader reader = new XmlTextReader("http://xml.weather.yahoo.com/forecastrss?p=94704"); // Skip non-significant whitespace reader.WhitespaceHandling = WhitespaceHandling.Significant; // Read nodes one at a time while (reader.Read()) { // Print out info on node Console.WriteLine("{0}: {1}", reader.NodeType.ToString(), reader.Name); } This one works for the yahoo page but not for mine. I need to use this webservice - http://wsf.cdyne.com/WeatherWS/Weather.asmx

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  • PHP mail may be filtered out by spam?

    - by Derek
    I am creating a small company, and would like to send out emails to my clients once they have signed up for my service to activate their accounts. I am currently using PHP's mail() function, however I am worried that my emails are being filtered out by spam filters. Is there a better way to go about this? $email = 'XZY Client Email address @ somedomain.com'; $emailSubject = "Welcome to XYZ Service!"; $to = $email; $subject .= "".$emailSubject.""; $headers .= "From: [email protected]\r\n" . "X-Mailer: php"; $headers .= "MIME-Version: 1.0\r\n"; $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; $message = "<html><body>"; $message .= "Welcome to XYZ Service! \n Activate your account by clicking the following link: link..."; mail($to, $subject, $message, $headers); Is there a way to authenticate these emails so that my clients know that they are from my actual service? Thank you in advance!

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  • document.getElementById returns null for my drop-down select menu

    - by tucson
    I am trying to create a drop-down select menu with custom css (similar to the drop-down selection of language at http://translate.google.com/#). I have current html code: <ul id="Select"> <li> <select id="myId" onmouseover="mopen('options')" onmouseout="mclosetime()"> <div id="options" onmouseover="mcancelclosetime()" onmouseout="mclosetime()"> <option value="1" selected="selected">One</option> <option value="2">Two</option> <option value="3">Three</option> </div> </select> </li> </ul> and the Javascript: function mopen(id) { // cancel close timer mcancelclosetime(); // close old layer if(ddmenuitem) ddmenuitem.style.visibility = 'hidden'; // get new layer and show it ddmenuitem = document.getElementById(id); ddmenuitem.style.visibility = 'visible'; } But document.getElementById returns null. Though if I use the code with a div element that does not contain a select list the document.getElementById(id) returns proper div value. How do I fix this? or is there a better way to create drop-down select menu like http://translate.google.com ?

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  • Getting document.getElementsByName from another page PHP/javascript

    - by DarkN3ss
    so i have been looking around on how to do this but with no success. Im trying to get the value of the name test from an external website <input type="hidden" name="test" value="ThisIsAValue" /> But so far i have only found how to get the value of that with an ID <input type="hidden" id="test" name="test" value="ThisIsAValue" autocomplete="off" /> but I need to try find it without a ID is my problem. And this is an example on how to get it from the ID <?php $doc = new DomDocument; $doc->validateOnParse = true; $doc->loadHtml(file_get_contents('http://example.com/bla.php')); var_dump($doc->getElementById('test')); ?> And i have found how to get it from name and NOT ID on the same page <script> function getElements() { var test = document.getElementsByName("test")[0].value; alert(test); } </script> But again I dont know how to get the value of it by name from an external page eg "http://example.com/bla.php", any help? Thanks

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  • If attacker has original data, and encrypted data, can they determine the passphrase?

    - by Brad Cupit
    If an attacker has several distinct items (for example: e-mail addresses) and knows the encrypted value of each item, can the attacker more easily determine the secret passphrase used to encrypt those items? Meaning, can they determine the passphrase without resorting to brute force? This question may sound strange, so let me provide a use-case: User signs up to a site with their e-mail address Server sends that e-mail address a confirmation URL (for example: https://my.app.com/confirmEmailAddress/bill%40yahoo.com) Attacker can guess the confirmation URL and therefore can sign up with someone else's e-mail address, and 'confirm' it without ever having to sign in to that person's e-mail account and see the confirmation URL. This is a problem. Instead of sending the e-mail address plain text in the URL, we'll send it encrypted by a secret passphrase. (I know the attacker could still intercept the e-mail sent by the server, since e-mail are plain text, but bear with me here.) If an attacker then signs up with multiple free e-mail accounts and sees multiple URLs, each with the corresponding encrypted e-mail address, could the attacker more easily determine the passphrase used for encryption? Alternative Solution I could instead send a random number or one-way hash of their e-mail address (plus random salt). This eliminates storing the secret passphrase, but it means I need to store that random number/hash in the database. The original approach above does not require this extra table. I'm leaning towards the the one-way hash + extra table solution, but I still would like to know the answer: does having multiple unencrypted e-mail addresses and their encrypted counterparts make it easier to determine the passphrase used?

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  • Filtering string in Python

    - by Ecce_Homo
    I am making algorithm for checking the string (e-mail) - like "E-mail addres is valid" but their are rules. First part of e-mail has to be string that has 1-8 characters (can contain alphabet, numbers, underscore [ _ ]...all the parts that e-mail contains) and after @ the second part of e-mail has to have string that has 1-12 characters (also containing all legal expressions) and it has to end with top level domain .com EDIT email = raw_input ("Enter the e-mail address:") length = len (email) if length > 20 print "Address is too long" elif lenght < 5: print "Address is too short" if not email.endswith (".com"): print "Address doesn't contain correct domain ending" first_part = len (splitting[0]) second_part = len(splitting[1]) account = splitting[0] domain = splitting[1] for c in account: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in account name of e-mail" for c in domain: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in domain of e-mail" if first_part == 0: print "You need at least 1 character before the @" elif first_part> 8: print "The first part is too long" if second_part == 4: print "You need at least 1 character after the @" elif second_part> 16: print "The second part is too long" else: # if everything is fine return this print "E-mail addres is valid" EDIT: After reproting what is wrong with our input, now I need to make Python recognize valid address and return ("E-mail adress is valid") This is the best i can do with my knowledge....and we cant use regular expressions, teacher said we are going to learn them later.

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  • Get Mail with PHP and IMAP in Gmail just loading

    - by Oscar Godson
    I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = 'xxxxxxxx@gmail.com'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

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