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• Exclude a string from wildcard search in a shell

  - by steigers

  Hello everybody I am trying to exclude a certain string from a file search. Suppose I have a list of files: file_Michael.txt, file_Thomas.txt, file_Anne.txt. I want to be able and write something like ls *<and not Thomas>.txt to give me file_Michael.txt and file_Anne.txt, but not file_Thomas.txt. The reverse is easy: ls *Thomas.txt Doing it with a single character is also easy: ls *[^s].txt But how to do it with a string? Sebastian

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• Proper way to set PYTHONPATH (including precedence)

  - by Wells

  In .bashrc I have: export PYTHONPATH=/home/wells/py-mlb I've verified this is actually being set. so, in this directory is another directory called 'py_mlb'- the actual module. So I go python -v and then import py_mlb but it does: >>> import py_mlb import py_mlb # directory /usr/local/lib/python2.6/dist-packages/py_mlb Then I do import sys and print sys.path and I see: >>> print sys.path ['', '/usr/local/lib/python2.6/dist-packages/python_memcached-1.44-py2.6.egg', '/usr/local/lib/python2.6/dist-packages/pymc-2.1alpha-py2.6-linux-i686.egg', '/usr/local/lib/python2.6/dist-packages/nose-0.11.1-py2.6.egg', '/home/wells/py-mlb', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/local/lib/python2.6/dev-packages', '/usr/lib/pymodules/python2.6', '/usr/lib/pymodules/python2.6/gtk-2.0', '/usr/local/lib/python2.6/dist-packages'] So my path from .bashrc IS in there, and from the look of it it's even before dist-packages but it's importing the module from dist-packages. How can I finagle this so the PYTHONPATH as defined by .bashrc takes precedence? Thanks!

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• How to use a variable in an awk expression

  - by lugte098

  I'm trying to make this command: sed bla bla filename | awk '{printf "%s %s_entry_%.3f %.3f %.3f %.3f",$1,$3,$4,$5,$6,$7}' But the thing is, i want the %.3f part to be variable. So in one case it could be %.3f and in another it could be %.3f %.3f %.3f. So i'll just use a static one in my example code for clarity. So if i want 4 of these %.3f and put them in variable $values like so: values="%.3f %.3f %.3f %.3f" Then how can i put this string in the awk expression, without making awk to just put literally "${values}" in there. The following is my non-working-attempt: sed bla bla filename | awk '{printf "%s %s_entry_${values}",$1,$3,$4,$5,$6,$7}'

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• Linux: Merging multiple files, each on a new line

  - by Marco

  I am using cat *.txt to merge multiple txt files into one, but I need each file to be on a separate line. What is the best way to merge files with each file appearing on a new line?

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• matching files with regular expressions

  - by Javier

  Dear all, I have an input file with a list of movies (Note that there might be some repeated entries): American_beauty__1h56mn38s_ As_Good_As_It_Gets As_Good_As_It_Gets _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ Capote_EN_DVDRiP_XViD-GeT-AW _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ I would to find the corresponding match (line number) from another reference file for each of the entries in the first file: American beauty.(1h56mn38s) As Good As It Gets Capote.EN.DVDRiP.XViD-GeT-AW [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) Quills (2000)(7.4) The desired output would be something like (Reference Movie + Line number from the Reference File): American beauty.(1h56mn38s) 1 As Good As It Gets 2 As Good As It Gets 2 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Capote.EN.DVDRiP.XViD-GeT-AW 3 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Basically, the difference between the entries in both files is that some characters such as: blank spaces, parenthesis, points, etc. have been replaced by underscores. Does anybody could shed some light on it? Best wishes, Javier

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• sed to insert on first match only

  - by SS.

  UPDATED: Using sed, how can I insert (NOT SUBSTITUTE) a new line on only the first match of keyword for each file. Currently I have the following but this inserts for every line containing Matched Keyword and I want it to only insert the New Inserted Line for only the first match found in the file: sed -ie '/Matched Keyword/ i\New Inserted Line' *.* For example: Myfile.txt: Line 1 Line 2 Line 3 This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6 changed to: Line 1 Line 2 Line 3 New Inserted Line This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6

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• How to do a join of 3 files with awk by first Column?

  - by noinflection

  i have three similar files, they are all like this: ID1 Value1a ID2 Value2a . . . IDN Value2n and i want an output like this ID1 Value1a Value1b Value1c ID2 Value2a Value2b Value2c ..... IDN ValueNa ValueNb ValueNc Looking to the first line i want value1A to be the value of id1 in fileA, value1B the value of id1 in fileB, etc, i think of it like a nice sql join. I've tried several things but none of them where even close.

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• Uninstall Git completely on Ubuntu?

  - by Millisami

  I installed Git on Ubuntu Lucid (latest) manually as following. cd ~/tmp wget http://kernel.org/pub/software/scm/git/git-1.7.0.6.tar.gz tar -xzvf git-1.7.0.6.tar.gz cd git-1.7.0.6.tar.gz ./configure sudo make sudo make install Now, how can I completely uninstall it?

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• How to create program that can be run by: #service myservice start

  - by Saif Bechan

  I am new to Linux and want to know what kind of programs can be run by using. #service myservice start And the programs stays on until stopped. Are they normal c++ programs or are they different. In some tutorials i have seen that they use ./myprogram to start a program. Another thing I have seen is the usage of .sh files. One last type of program i see is executed by the command: #/usr/bin/myprogramm Can someone explain the difference between these or point me to a basic tutorial/guide.

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• Using a dictionary file with sed

  - by Winston

  I have a blacklist.txt file that contains keywords I want to remove using sed. Here's what the blacklist.txt file contain winston@linux ] $ cat blacklist.txt obscure keywords here ... And here's what I have so far, but currently doesn't work. blacklist=$(cat blacklist.txt); output="filtered_file.txt" for i in $blacklist; do cat $input | sed 's/$i//g' >> $output done

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• Dymanic if statement evaluation problem with string comparison

  - by Mani

  I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

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• select fields with sed

  - by Samantha

  Hey, Using only grep and sed, is there a way I can tranform the output of ls -l * into this : -rw-r--r-- agenda.txt -rw-r--r-- annuaire.txt Thanks!

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• Parsing the first column of a csv file to a new file.

  - by S1syphus

  Operating System: OSX Method: From the command line, so using sed, cut, gawk, although preferably no installing modules. Essentially I am trying to take the first column of a csv file and parse it to a new file. Example input file EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 Desire output EXAMPLEfoo EXAMPLEbar EXAMPLE1 EXAMPLE2 EXAMPLE3 EXAMPLE4 So I want the first column. Here is what I have tried so far: awk -F"," '{print $1}' in.csv > out.txt awk -F"," '{for (i=2;i<=NF;i++)}' in.csv > out.txt awk -F"," 'BEGIN { OFS="," }' '{print $1}' in.csv > out.txt cat in.csv | cut -d \, -f 1 > out.txt None seem to work, either they just print the first line or nothing at all, so I would assume it's failing to read line by line.

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• Invoking shell from java, it complaints "stty: standard input: Invalid argument"

  - by solotim

  Hi, everybody. I invoked shell command by Process class of java and it gave "stty: standard input: Invalid argument" no matter the command is right or wrong (normal output of shell command is shown too). If I run the shell command in shell, no such error message shows. I can't figure out why. Thanks

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• How can I prevent default_environment variables from getting set by Capistrano's sudo action?

  - by Logan Koester

  My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

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• Trouble with piping through sed

  - by Joel

  I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

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• How can I detect dos line breaks in a file?

  - by chiggsy

  I have a bunch of files. Some are unix line endings, many are dos. I'd like to test each file to see if if is dos formatted, before I switch the line endings. How would I do this? Is there a flag I can test for? Something similar?

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• cmake source and out-of-source navigation

  - by idimba

  Hi, cmake advises to use out-of-source builds. While in general I like the idea I find it not comfortable to navigate from out-of-source sub directory to the corresponding source directory. I frequently need the code to perform some actions with code (e.g. grep, svn command etc.). Is there an easy way in shell to navigate from out-of-source sub directory to the corresponding source directory? Thanks Dima

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• How to replace the nth column/field in a comma-separated string using sed/awk?

  - by Peter Meier

  assume I have a string "1,2,3,4" Now I want to replace, e.g. the 3rd field of the string by some different value. "1,2,NEW,4" I managed to do this with the following command: echo "1,2,3,4" | awk -F, -v OFS=, '{$3="NEW"; print }' Now the index for the column to be replaced should be passed as a variable. So in this case index=3 How can I pass this to awk? Because this won't work: echo "1,2,3,4" | awk -F, -v OFS=, '{$index="NEW"; print }' echo "1,2,3,4" | awk -F, -v OFS=, '{$($index)="NEW"; print }' echo "1,2,3,4" | awk -F, -v OFS=, '{\$$index="NEW"; print }' Thanks for your help!

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• Want to set 'src' of script to my IP-Won't load in Safari or Chrome. Relative link asp.netmvc

  - by Ozaki

  I have a script that links to the server I am hosting (IP can change) usually I would just use for links: var url ='http://' + window.location.hostname + 'end of url'; But in this case it isnt appearing to be so easy. I have tried: (1) $('#scriptid').attr('src', url); as well as: (2) var script = document.createElement( 'script' ); script.type = 'text/javascript'; script.src = url; $("#insert").append( script ); Now case (2) works loads the script runs the script. But when at the end of my script it hits the 'write data' it decides to replace the entire page with just the data. Any idea on how I can do this? Note: I am using plain html not ASP. With ASP backend that is just the way it has to be. Ok it now is <script src="myscript.js"></script> C# router.AddAsyncRoute("myscript.js"...... It workes in IE & FF. But I get blank pages in Chrome & Safari. I am using document.write to write a script onto my page. Any ideas why Chrome & Safari don't like this? I am so far assuming that in Crhome & Safari it takes longer to run the script therefore launching the document.write after the DOM has loaded therefore replacing the page with a blank one. edit the script im trying to run is a modification of: d = new dTree('d'); d.add(0,-1,'My example tree'); d.add(1,0,'Node 1','default.html'); d.add(2,0,'Node 2','default.html'); d.add(3,1,'Node 1.1','default.html'); d.add(4,0,'Node 3','default.html'); d.add(5,3,'Node 1.1.1','default.html') document.write(d); Any ideas how I can get around this? I am not to sure how to implement an appenChild in this case as the script is changing constantly with live data. So every refresh it will generally have changed some...

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• What happened to the TMP environment variable?

  - by Mark0978

  I always heard that the proper way to find the temporary folder on a UNIX machine was to look at the TMP environment variable. When writing code that worked on Windows as well as Linux, I would check for TEMP and TMP. Today, I discovered that my Ubuntu install does not have that environment variable at all. I know it seems you can always count on /tmp being there to put your temporary files in, but I understood that TMP was the way the user could tell you to put the temporary files someplace else. Is that still the case?

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• How do I write an alias for grep -R?

  - by numerodix

  I end up typing grep -Rni pattern . and awful lot. How do I make this into an alias like alias gr='grep -Rni $@ .' Running that gives: $ gr pattern grep: pattern: No such file or directory Even though the alias looks fine: $ type gr gr is aliased to `grep -R $@ .' It seems that the $@ and the . get swapped when it's actually executed.

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• Sorting tab delimited text file based on multiple columns in natural way [duplicate]

  - by Vignesh

  This question already has an answer here: Sorting a column of CSV file resulting in 1123 appearing before 232 1 answer I am trying to sort a file based on all two columns Eg: chr19 1070019 1070020 chr16 869712 869713 chr1 1378131 1378132 chr12 189386 189387 chr4 254941 254942 chr16 1476500 1476501 chr2 1476810 1476811 chr19 313283 313284 chr17 595817 595818 chr18 656897 656898 chr19 1061829 1061830 I Tried sort -t $\t -k1,1 2,2 <filename> but doesn't work. I want the output to be sorted by first column and second column based on first column. I want to do a natural sort. Not lexical sorting. Eg: chr1 1378131 1378132 chr2 1476810 1476811 chr4 254941 254942 chr12 189386 189387 chr16 869712 869713 chr16 1476500 1476501 chr17 595817 595818 chr18 656897 656898 chr19 313283 313284 chr19 1061829 1061830 chr19 1070019 1070020 Anyone any idea?

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• Specify private SSH-key to use when executing shell command with or without Ruby?

  - by Christoffer

  A rather unusual situation perhaps, but I want to specify a private SSH-key to use when executing a shell (git) command from the local computer. Basically like this: git clone [email protected]:TheUser/TheProject.git -key "/home/christoffer/ssh_keys/theuser" Or even better (in Ruby): with_key("/home/christoffer/ssh_keys/theuser") do sh("git clone [email protected]:TheUser/TheProject.git") end I have seen examples of connecting to a remote server with Net::SSH that uses a specified private key, but this is a local command. Is it possible? Thanks

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• Add xcode-select to PATH vs. Install Xcode Command Line Tools?

  - by MattDiPasquale

  Now with Xcode 4.5, is it OK to just add the following line to my ~/.bash_profile rather than installing the Xcode Command Line Tools? export PATH="$PATH:`xcode-select -print-path`/usr/bin:`xcode-select -print-path`/Toolchains/XcodeDefault.xctoolchain/usr/bin" Note: Xcode says the following about Command Line Tools: Before installing, note that from within Terminal you can use the XCRUN tool to launch compilers and other tools embedded within the Xcode application. Use the XCODE-SELECT tool to define which version of Xcode is active. Type "man xcrun" from within Terminal to find out more.

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