Search Results

Search found 1898 results on 76 pages for 'dd dent'.

Page 12/76 | < Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >

  • Styling definition lists - IE clear:both bug

    - by Andrea
    Hi guys, I'm trying to style a definition list properly. So far I've got the style that I wanted in Firefox 3.5 and IE 8 but I couldn't get IE6 and IE7 to behave properly... I've already tried any kind of hack and trickery I could possibly think of. It seems like the "clear:both" on the dt doesn't work in IE<=7... Below is the "test page" that I'm using. The markup of the definition list is built on purpose: I wanna test different scenarios such as multiple definitions or empty one. Check it in Firefox 3.5 to see how it should look like. Cheers!!! <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> <style type="text/css"> body { font-family: Arial; font-size: 62.5%; } * { margin: 0; padding: 0; } #main { font-size: 1.4em; } dt { font-weight: bold; } hr { clear: both; } dl.aligned { width: 300px; } .aligned dt { clear: both; float: left; margin: 0 0 0.5em 0; width: 100px; } .aligned dd { clear: right; float: right; margin: 0 0 0.5em 10px; width: 190px; } </style> </head> <body> <div id="main"> <dl class="aligned"> <dt>First title</dt> <dd>1.1 definition</dd> <dd>1.2 definition - very long to test wrapping</dd> <dd>1.3 definition</dd> <dt>Second title</dt> <dd></dd> <dd></dd> <dt>Third title</dt> <dd>3.0 definition</dd> <dt>Fourth title - very long to test wrapping</dt> <dt>Fifth title</dt> <dt>Sixth title</dt> <dd>6.0 definition</dd> </dl> </div> </body> </html>

    Read the article

  • Partitioned Repository for WebCenter Content using Oracle Database 11g

    - by Adao Junior
    One of the biggest challenges for content management solutions is related to the storage management due the high volumes of the unstoppable growing of information. Even if you have storage appliances and a lot of terabytes, thinks like backup, compression, deduplication, storage relocation, encryption, availability could be a nightmare. One standard option that you have with the Oracle WebCenter Content is to store data to the database. And the Oracle Database allows you leverage features like compression, deduplication, encryption and seamless backup. But with a huge volume, the challenge is passed to the DBA to keep the WebCenter Content Database up and running. One solution is the use of DB partitions for your content repository, but what are the implications of this? Can I fit this with my business requirements? Well, yes. It’s up to you how you will manage that, you just need a good plan. During you “storage brainstorm plan” take in your mind what you need, such as storage petabytes of documents? You need everything on-line? There’s a way to logically separate the “good content” from the “legacy content”? The first thing that comes to my mind is to use the creation date of the document, but you need to remember that this document could receive a lot of revisions and maybe you can consider the revision creation date. Your plan can have also complex rules like per Document Type or per a custom metadata like department or an hybrid per date, per DocType and an specific virtual folder. Extrapolation the use, you can have your repository distributed in different servers, different disks, different disk types (Such as ssds, sas, sata, tape,…), separated accordingly your business requirements, separating the “hot” content from the legacy and easily matching your compliance requirements. If you think to use by revision, the simple way is to consider the dId, that is the sequential unique id for every content created using the WebCenter Content or the dLastModified that is the date field of the FileStorage table that contains the date of inclusion of the content to the DB Table using SecureFiles. Using the scenario of partitioned repository using an hierarchical separation by date, we will transform the FileStorage table in an partitioned table using  “Partition by Range” of the dLastModified column (You can use the dId or a join with other tables for other metadata such as dDocType, Security, etc…). The test scenario bellow covers: Previous existent data on the JDBC Storage to be migrated to the new partitioned JDBC Storage Partition by Date Automatically generation of new partitions based on a pre-defined interval (Available only with Oracle Database 11g+) Deduplication and Compression for legacy data Oracle WebCenter Content 11g PS5 (Could present some customizations that do not affect the test scenario) For the test case you need some data stored using JDBC Storage to be the “legacy” data. If you do not have done before, just create an Storage rule pointed to the JDBC Storage: Enable the metadata StorageRule in the UI and upload some documents using this rule. For this test case you can run using the schema owner or an dba user. We will use the schema owner TESTS_OCS. I can’t forgot to tell that this is just a test and you should do a proper backup of your environment. When you use the schema owner, you need some privileges, using the dba user grant the privileges needed: REM Grant privileges required for online redefinition. GRANT EXECUTE ON DBMS_REDEFINITION TO TESTS_OCS; GRANT ALTER ANY TABLE TO TESTS_OCS; GRANT DROP ANY TABLE TO TESTS_OCS; GRANT LOCK ANY TABLE TO TESTS_OCS; GRANT CREATE ANY TABLE TO TESTS_OCS; GRANT SELECT ANY TABLE TO TESTS_OCS; REM Privileges required to perform cloning of dependent objects. GRANT CREATE ANY TRIGGER TO TESTS_OCS; GRANT CREATE ANY INDEX TO TESTS_OCS; In our test scenario we will separate the content as Legacy, Day1, Day2, Day3 and Future. This last one will partitioned automatically using 3 tablespaces in a round robin mode. In a real scenario the partition rule could be per month, per year or any rule that you choose. Table spaces for the test scenario: CREATE TABLESPACE TESTS_OCS_PART_LEGACY DATAFILE 'tests_ocs_part_legacy.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY1 DATAFILE 'tests_ocs_part_day1.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY2 DATAFILE 'tests_ocs_part_day2.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY3 DATAFILE 'tests_ocs_part_day3.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_A 'tests_ocs_part_round_robin_a.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_B 'tests_ocs_part_round_robin_b.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_C 'tests_ocs_part_round_robin_c.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; Before start, gather optimizer statistics on the actual FileStorage table: EXEC DBMS_STATS.GATHER_TABLE_STATS(USER, 'FileStorage', cascade => TRUE); Now check if is possible execute the redefinition process: EXEC DBMS_REDEFINITION.CAN_REDEF_TABLE('TESTS_OCS', 'FileStorage',DBMS_REDEFINITION.CONS_USE_PK); If no errors messages, you are good to go. Create a Partitioned Interim FileStorage table. You need to create a new table with the partition information to act as an interim table: CREATE TABLE FILESTORAGE_Part ( DID NUMBER(*,0) NOT NULL ENABLE, DRENDITIONID VARCHAR2(30 CHAR) NOT NULL ENABLE, DLASTMODIFIED TIMESTAMP (6), DFILESIZE NUMBER(*,0), DISDELETED VARCHAR2(1 CHAR), BFILEDATA BLOB ) LOB (BFILEDATA) STORE AS SECUREFILE ( ENABLE STORAGE IN ROW NOCACHE LOGGING KEEP_DUPLICATES NOCOMPRESS ) PARTITION BY RANGE (DLASTMODIFIED) INTERVAL (NUMTODSINTERVAL(1,'DAY')) STORE IN (TESTS_OCS_PART_ROUND_ROBIN_A, TESTS_OCS_PART_ROUND_ROBIN_B, TESTS_OCS_PART_ROUND_ROBIN_C) ( PARTITION FILESTORAGE_PART_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_LEGACY LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_LEGACY RETENTION NONE DEDUPLICATE COMPRESS HIGH ), PARTITION FILESTORAGE_PART_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY1 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY1 RETENTION AUTO KEEP_DUPLICATES COMPRESS ), PARTITION FILESTORAGE_PART_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY2 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY2 RETENTION AUTO KEEP_DUPLICATES NOCOMPRESS ), PARTITION FILESTORAGE_PART_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY3 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY3 RETENTION AUTO KEEP_DUPLICATES NOCOMPRESS ) ); After the creation you should see your partitions defined. Note that only the fixed range partitions have been created, none of the interval partition have been created. Start the redefinition process: BEGIN DBMS_REDEFINITION.START_REDEF_TABLE( uname => 'TESTS_OCS' ,orig_table => 'FileStorage' ,int_table => 'FileStorage_PART' ,col_mapping => NULL ,options_flag => DBMS_REDEFINITION.CONS_USE_PK ); END; This operation can take some time to complete, depending how many contents that you have and on the size of the table. Using the DBA user you can check the progress with this command: SELECT * FROM v$sesstat WHERE sid = 1; Copy dependent objects: DECLARE redefinition_errors PLS_INTEGER := 0; BEGIN DBMS_REDEFINITION.COPY_TABLE_DEPENDENTS( uname => 'TESTS_OCS' ,orig_table => 'FileStorage' ,int_table => 'FileStorage_PART' ,copy_indexes => DBMS_REDEFINITION.CONS_ORIG_PARAMS ,copy_triggers => TRUE ,copy_constraints => TRUE ,copy_privileges => TRUE ,ignore_errors => TRUE ,num_errors => redefinition_errors ,copy_statistics => FALSE ,copy_mvlog => FALSE ); IF (redefinition_errors > 0) THEN DBMS_OUTPUT.PUT_LINE('>>> FileStorage to FileStorage_PART temp copy Errors: ' || TO_CHAR(redefinition_errors)); END IF; END; With the DBA user, verify that there's no errors: SELECT object_name, base_table_name, ddl_txt FROM DBA_REDEFINITION_ERRORS; *Note that will show 2 lines related to the constrains, this is expected. Synchronize the interim table FileStorage_PART: BEGIN DBMS_REDEFINITION.SYNC_INTERIM_TABLE( uname => 'TESTS_OCS', orig_table => 'FileStorage', int_table => 'FileStorage_PART'); END; Gather statistics on the new table: EXEC DBMS_STATS.GATHER_TABLE_STATS(USER, 'FileStorage_PART', cascade => TRUE); Complete the redefinition: BEGIN DBMS_REDEFINITION.FINISH_REDEF_TABLE( uname => 'TESTS_OCS', orig_table => 'FileStorage', int_table => 'FileStorage_PART'); END; During the execution the FileStorage table is locked in exclusive mode until finish the operation. After the last command the FileStorage table is partitioned. If you have contents out of the range partition, you should see the new partitions created automatically, not generating an error if you “forgot” to create all the future ranges. You will see something like: You now can drop the FileStorage_PART table: border-bottom-width: 1px; border-bottom-style: solid; text-align: left; border-left-color: silver; border-left-width: 1px; border-left-style: solid; padding-bottom: 4px; line-height: 12pt; background-color: #f4f4f4; margin-top: 20px; margin-right: 0px; margin-bottom: 10px; margin-left: 0px; padding-left: 4px; width: 97.5%; padding-right: 4px; font-family: 'Courier New', Courier, monospace; direction: ltr; max-height: 200px; font-size: 8pt; overflow-x: auto; overflow-y: auto; border-top-color: silver; border-top-width: 1px; border-top-style: solid; cursor: text; border-right-color: silver; border-right-width: 1px; border-right-style: solid; padding-top: 4px; " id="codeSnippetWrapper"> DROP TABLE FileStorage_PART PURGE; To check the FileStorage table is valid and is partitioned, use the command: SELECT num_rows,partitioned FROM user_tables WHERE table_name = 'FILESTORAGE'; You can list the contents of the FileStorage table in a specific partition, per example: SELECT * FROM FileStorage PARTITION (FILESTORAGE_PART_LEGACY) Some useful commands that you can use to check the partitions, note that you need to run using a DBA user: SELECT * FROM DBA_TAB_PARTITIONS WHERE table_name = 'FILESTORAGE';   SELECT * FROM DBA_TABLESPACES WHERE tablespace_name like 'TESTS_OCS%'; After the redefinition process complete you have a new FileStorage table storing all content that has the Storage rule pointed to the JDBC Storage and partitioned using the rule set during the creation of the temporary interim FileStorage_PART table. At this point you can test the WebCenter Content downloading the documents (Original and Renditions). Note that the content could be already in the cache area, take a look in the weblayout directory to see if a file with the same id is there, then click on the web rendition of your test file and see if have created the file and you can open, this means that is all working. The redefinition process can be repeated many times, this allow you test what the better layout, over and over again. Now some interesting maintenance actions related to the partitions: Make an tablespace read only. No issues viewing, the WebCenter Content do not alter the revisions When try to delete an content that is part of an read only tablespace, an error will occurs and the document will not be deleted The only way to prevent errors today is creating an custom component that checks the partitions and if you have an document in an “Read Only” repository, execute the deletion process of the metadata and mark the document to be deleted on the next db maintenance, like a new redefinition. Take an tablespace off-line for archiving purposes or any other reason. When you try open an document that is included in this tablespace will receive an error that was unable to retrieve the content, but the others online tablespaces are not affected. Same behavior when deleting documents. Again, an custom component is the solution. If you have an document “out of range”, the component can show an message that the repository for that document is offline. This can be extended to a option to the user to request to put online again. Moving some legacy content to an offline repository (table) using the Exchange option to move the content from one partition to a empty nonpartitioned table like FileStorage_LEGACY. Note that this option will remove the registers from the FileStorage and will not be able to open the stored content. You always need to keep in mind the indexes and constrains. An redefinition separating the original content (vault) from the renditions and separate by date ate the same time. This could be an option for DAM environments that want to have an special place for the renditions and put the original files in a storage with less performance. The process will be the same, you just need to change the script of the interim table to use composite partitioning. Will be something like: CREATE TABLE FILESTORAGE_RenditionPart ( DID NUMBER(*,0) NOT NULL ENABLE, DRENDITIONID VARCHAR2(30 CHAR) NOT NULL ENABLE, DLASTMODIFIED TIMESTAMP (6), DFILESIZE NUMBER(*,0), DISDELETED VARCHAR2(1 CHAR), BFILEDATA BLOB ) LOB (BFILEDATA) STORE AS SECUREFILE ( ENABLE STORAGE IN ROW NOCACHE LOGGING KEEP_DUPLICATES NOCOMPRESS ) PARTITION BY LIST (DRENDITIONID) SUBPARTITION BY RANGE (DLASTMODIFIED) ( PARTITION Vault VALUES ('primaryFile') ( SUBPARTITION FILESTORAGE_VAULT_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_FUTURE VALUES LESS THAN (MAXVALUE) ) ,PARTITION WebLayout VALUES ('webViewableFile') ( SUBPARTITION FILESTORAGE_WEBLAYOUT_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_FUTURE VALUES LESS THAN (MAXVALUE) ) ,PARTITION Special VALUES ('Special') ( SUBPARTITION FILESTORAGE_SPECIAL_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_FUTURE VALUES LESS THAN (MAXVALUE) ) )ENABLE ROW MOVEMENT; The next post related to partitioned repository will come with an sample component to handle the possible exceptions when you need to take off line an tablespace/partition or move to another place. Also, we can include some integration to the Retention Management and Records Management. Another subject related to partitioning is the ability to create an FileStore Provider pointed to a different database, raising the level of the distributed storage vs. performance. Let us know if this is important to you or you have an use case not listed, leave a comment. Cross-posted on the blog.ContentrA.com

    Read the article

  • How can I optimize the SELECT statement running on an Oracle database?

    - by Elvis Lou
    I have a SELECT statement in ORACLE: SELECT COUNT(DISTINCT ds1.endpoint_msisdn) multiple30, dss1.service, dss1.endpoint_provisioning_id, dss1.company_scope, Nvl(x.subscription_status, dss1.subscription_status) subscription_status FROM daily_summary ds1 join daily_summary ds2 ON ds1.endpoint_msisdn = ds2.endpoint_msisdn, daily_summary_static dss1, daily_summary_static dss2, (SELECT NULL subscription_status FROM dual UNION ALL SELECT -2 subscription_status FROM dual) x WHERE ds1.summary_ts >= To_date('10-04-2012', 'dd-mm-yyyy') - 30 AND ds1.summary_ts <= To_date('10-04-2012', 'dd-mm-yyyy') AND dss1.last_active >= To_date('10-04-2012', 'dd-mm-yyyy') - 30 AND dss1.last_active <= To_date('10-04-2012', 'dd-mm-yyyy') AND dss2.last_active >= To_date('10-04-2012', 'dd-mm-yyyy') - 30 AND dss2.last_active <= To_date('10-04-2012', 'dd-mm-yyyy') AND dss1.service <> dss2.service AND ( dss1.company_scope = 2 OR dss1.company_scope = 5 ) AND ( dss2.company_scope = 2 OR dss2.company_scope = 5 ) AND dss1.company_scope = dss2.company_scope AND ds1.endpoint_noc_id = dss1.endpoint_noc_id AND ds1.endpoint_host_id = dss1.endpoint_host_id AND ds1.endpoint_instance_id = dss1.endpoint_instance_id AND ds2.endpoint_noc_id = dss2.endpoint_noc_id AND ds2.endpoint_host_id = dss2.endpoint_host_id AND ds2.endpoint_instance_id = dss2.endpoint_instance_id AND dss1.endpoint_provisioning_id = dss2.endpoint_provisioning_id AND Least(1, ds1.total_actions) = 1 AND Least(1, ds2.total_actions) = 1 GROUP BY dss1.service, dss1.endpoint_provisioning_id, dss1.company_scope, Nvl(x.subscription_status, dss1.subscription_status); This query took about 26 minutes to return in my environment, but if I remove the section: dss1.last_active >= to_date('10-04-2012','dd-mm-yyyy') - 30 AND dss1.last_active <= to_date('10-04-2012','dd-mm-yyyy') AND dss2.last_active >= to_date('10-04-2012','dd-mm-yyyy') - 30 AND dss2.last_active <= to_date('10-04-2012','dd-mm-yyyy') AND it only took 20 seconds to run. We have index on the column last_active, I don't know why the section slow down the performance so much? any ideas?

    Read the article

  • How to split this string in c#?

    - by melaos
    hi i'm really not used to the split string method in c# and i was wondering how come there's no split by more than one char function? and my attempt to try to split this string below using regex has just ended up in frustration. anybody can help me? basically i want to split the string below down to aa**aa**bb**dd^__^a2a**a2a**b2b**dd^__^ into aa**aa**bb**dd a2a**a2a**b2b**dd and then later into aa aa bb dd a2a a2a b2b dd thanks!

    Read the article

  • converting a csv into text

    - by user349418
    I have a csv (large) file of ip addresses, and wish to covert into single line ip address in bash. aa.bb.cc.dd,aa.bb.cc.dd,aa.bb.cc.dd,.. into aa.bb.cc.dd aa.bb.cc.dd aa.bb.cc.dd [..] The list of ips in question, http://www.stopforumspam.com/downloads/bannedips.zip

    Read the article

  • is it possible to set up a wireless bridge with dd-wrt?

    - by user398314
    I have a standard router (dlink) and a secondary linksys running wrt. Currently i have it set up according to this guide. (using the Instruction for dd-wrt v24 sp1 settings) It works great however it seems as though i can only connect via the actually ports in the router meaning it has to be hard wired. Is it possible to set it up so that I can connect to the secondary router and still use it as a bridge? Seems like it doesn't work as a wireless AP anymore when its running in bridged mode.

    Read the article

  • Make a Drive Image Using an Ubuntu Live CD

    - by Trevor Bekolay
    Cloning a hard drive is useful, but what if you have to make several copies, or you just want to make a complete backup of a hard drive? Drive images let you put everything, and we mean everything, from your hard drive in one big file. With an Ubuntu Live CD, this is a simple process – the versatile tool dd can do this for us right out of the box. We’ve used dd to clone a hard drive before. Making a drive image is very similar, except instead of copying data from one hard drive to another, we copy from a hard drive to a file. Drive images are more flexible, as you can do what you please with the data once you’ve pulled it off the source drive. Your drive image is going to be a big file, depending on the size of your source drive – dd will copy every bit of it, even if there’s only one tiny file stored on the whole hard drive. So, to start, make sure you have a device connected to your computer that will be large enough to hold the drive image. Some ideas for places to store the drive image, and how to connect to them in an Ubuntu Live CD, can be found at this previous Live CD article. In this article, we’re going to make an image of a 1GB drive, and store it on another hard drive in the same PC. Note: always be cautious when using dd, as it’s very easy to completely wipe out a drive, as we will show later in this article. Creating a Drive Image Boot up into the Ubuntu Live CD environment. Since we’re going to store the drive image on a local hard drive, we first have to mount it. Click on Places and then the location that you want to store the image on – in our case, a 136GB internal drive. Open a terminal window (Applications > Accessories > Terminal) and navigate to the newly mounted drive. All mounted drives should be in /media, so we’ll use the command cd /media and then type the first few letters of our difficult-to-type drive, press tab to auto-complete the name, and switch to that directory. If you wish to place the drive image in a specific folder, then navigate to it now. We’ll just place our drive image in the root of our mounted drive. The next step is to determine the identifier for the drive you want to make an image of. In the terminal window, type in the command sudo fdisk -l Our 1GB drive is /dev/sda, so we make a note of that. Now we’ll use dd to make the image. The invocation is sudo dd if=/dev/sda of=./OldHD.img This means that we want to copy from the input file (“if”) /dev/sda (our source drive) to the output file (“of”) OldHD.img, which is located in the current working directory (that’s the “.” portion of the “of” string). It takes some time, but our image has been created…Let’s test to make sure it works. Drive Image Testing: Wiping the Drive Another interesting thing that dd can do is totally wipe out the data on a drive (a process we’ve covered before). The command for that is sudo dd if=/dev/urandom of=/dev/sda This takes some random data as input, and outputs it to our drive, /dev/sda. If we examine the drive now using sudo fdisk –l, we can see that the drive is, indeed, wiped. Drive Image Testing: Restoring the Drive Image We can restore our drive image with a call to dd that’s very similar to how we created the image. The only difference is that the image is going to be out input file, and the drive now our output file. The exact invocation is sudo dd if=./OldHD.img of=/dev/sda It takes a while, but when it’s finished, we can confirm with sudo fdisk –l that our drive is back to the way it used to be! Conclusion There are a lots of reasons to create a drive image, with backup being the most obvious. Fortunately, with dd creating a drive image only takes one line in a terminal window – if you’ve got an Ubuntu Live CD handy! Similar Articles Productive Geek Tips Reset Your Ubuntu Password Easily from the Live CDCreate a Bootable Ubuntu USB Flash Drive the Easy WayHow to Browse Without a Trace with an Ubuntu Live CDWipe, Delete, and Securely Destroy Your Hard Drive’s Data the Easy WayClone a Hard Drive Using an Ubuntu Live CD TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips HippoRemote Pro 2.2 Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Microsoft Office Web Apps Guide Know if Someone Accessed Your Facebook Account Shop for Music with Windows Media Player 12 Access Free Documentaries at BBC Documentaries Rent Cameras In Bulk At CameraRenter Download Songs From MySpace

    Read the article

  • Burn bootable iso image to USB stick using dd: Won't boot (despite USB first in boot sequence)

    - by Nicolas Raoul
    I have installed Ubuntu on a Lenovo Thinkpad R500 2732, and I must update the BIOS. On the Lenovo website, I am offered this: BIOS Update Bootable CD for Windows 7 (32-bit, 64-bit), Vista (32-bit, 64-bit), XP - ThinkPad R500 I guess a bootable CD that would do a BIOS update is indeed what I need. (still wondering why it says "Windows" though... if it is bootable should not it be OS-agnostic?) Not wanting to waste a CD, I copied the image to my USB stick: sudo dd if=/home/nico/7yuj40uc.iso of=/dev/sdb1 bs=1M And rebooted, after making sure USB is first in the boot sequence. PROBLEM: It does not boot. Did I forget one step? Details about the iso image (readme): ls -lh 7yuj40uc.iso 25M file 7yuj40uc.iso /home/nico/7yuj40uc.iso: # ISO 9660 CD-ROM filesystem data '7YUJ40US ' (bootable) (Scroll to the right: it says "bootable") UNetbootin does not work because it is not a Linux image. Some people on the Internet advise to copy the content of the ISO and do other steps. This ISO has zero ISO content so it would not work. If I mount the ISO, I can see it contains zero files.

    Read the article

  • Physical Debian to VMWare: vmware-converter, dd-image or otherwise?

    - by Dabu
    we have two debian Lenny production machines, both running larger commercial websites. Now these machines need to be moved, and in the process, they need to be virtualized to VMWare ESX. If you believe the internet information, there are several ways to accomplish this. The easiest for us would be to use our weekly dd backup where the whole disk, however, I have no experience with this kind of technology and if it is really possible. The second best way would be via an application on the source machine virtualizing it and generating an ESX compatible VM. However, the software is beta and unsupported, and after installation, nothing really works (the /etc/init.d/vmware-converter script doesn't actually do anything, start and stop reply with success messages, yet ps shows that there are no new processes). The worst way with the most work would be to install a new machine and set it up manually, copying files and databases as needed. This part is clear in it's execution, and my question(s) do not touch this. Is my 1st way possible? Has anyone done this yet, or better, has a page with instructions? Or is there a help page that explains how to correctly install, run and use the vmware-converter tool using a Debian installation (it's possible that I dod something wrong during installation already)? Thank you.

    Read the article

  • Why is domU faster than dom0 on IO?

    - by Paco
    I have installed debian 7 on a physical machine. This is the configuration of the machine: 3 hard drives using RAID 5 Strip element size: 1M Read policy: Adaptive read ahead Write policy: Write Through /boot 200 MB ext2 / 15 GB ext3 SWAP 10GB LVM rest (~500GB) emphasized text I installed postgresql, created a big database (over 1GB). I have an SQL request that takes a lot of time to run (a SELECT statement, so it only reads data from the database). This request takes approximately 5.5 seconds to run. Then, I installed XEN, created a domU, with another debian distro. On this OS, I also installed postgresql, with the same database. The same SQL request takes only 2.5 seconds to run. I checked the kernel on both dom0 and domU. uname-a returns "Linux debian 3.2.0-4-amd64 #1 SMP Debian 3.2.41-2+deb7u2 x86_64 GNU/Linux" on both systems. I checked the kernel parameters, which are approximately the same. For those that are relevant, I changed their values to make them match on both systems using sysctl. I saw no changes (the requests still take the same amount of time). After this, I checked the file systems. I used ext3 on domU. Still no changes. I installed hdparm, and ran hdparm -Tt on both systems, on all my partitions on both systems, and I get similar results. Now, I am stuck, I don't know what is different, and what could be the cause of such a big difference. Additional Info: Debian runs on a Dell server PowerEdge 2950 postgresql: 9.1.9 (both dom0 and domU) xen-linux-system: 3.2.0 xen-hypervisor: 4.1 Thanks EDIT: As Krzysztof Ksiezyk suggested, it might be due to some file caching system. I ran the dd command to test both the read and write speed. Here is domU: root@test1:~# dd if=/dev/zero of=/root/dd count=5MB bs=1MB ^C2020+0 records in 2020+0 records out 2020000000 bytes (2.0 GB) copied, 18.8289 s, 107 MB/s root@test1:~# dd if=/root/dd of=/dev/null count=5MB bs=1MB 2020+0 records in 2020+0 records out 2020000000 bytes (2.0 GB) copied, 15.0549 s, 134 MB/s And here is dom0: root@debian:~# dd if=/dev/zero of=/root/dd count=5MB bs=1MB ^C1693+0 records in 1693+0 records out 1693000000 bytes (1.7 GB) copied, 8.87281 s, 191 MB/s root@debian:~# dd if=/root/dd of=/dev/null count=5MB bs=1MB 1693+0 records in 1693+0 records out 1693000000 bytes (1.7 GB) copied, 0.501509 s, 3.4 GB/s What can be the cause of this caching system? And how can we "fix" it? Can we apply it to dom0? EDIT 2: I switched my virtual disk type. To do so I followed this article. I did a dd if=/dev/vg0/test1-disk of=/mnt/test1-disk.img bs=16M Then in /etc/xen/test1.cfg, I changed the disk parameter to use file: instead of phy: it should have removed the file caching, but I still get the same numbers (domU being much faster for Postgres)

    Read the article

  • How to get the users set of date format pattern strings? (3 replies)

    I would like to get the current user's set of date format pattern strings as listed in the Control Panel regional settings applet. For my UK English system I see the following patterns listed: Short Date: dd/MM/yyyy dd/MM/yy d/M/yy d.M.yy yyyy MM dd Long Date: dd MMMM yyyy d MMMM yyyy If I use GetDateTimeFormats (d and D) the results match the expected patterns above, but of course they're the for...

    Read the article

  • How to get the users set of date format pattern strings? (3 replies)

    I would like to get the current user's set of date format pattern strings as listed in the Control Panel regional settings applet. For my UK English system I see the following patterns listed: Short Date: dd/MM/yyyy dd/MM/yy d/M/yy d.M.yy yyyy MM dd Long Date: dd MMMM yyyy d MMMM yyyy If I use GetDateTimeFormats (d and D) the results match the expected patterns above, but of course they're the for...

    Read the article

  • Clone a Hard Drive Using an Ubuntu Live CD

    - by Trevor Bekolay
    Whether you’re setting up multiple computers or doing a full backup, cloning hard drives is a common maintenance task. Don’t bother burning a new boot CD or paying for new software – you can do it easily with your Ubuntu Live CD. Not only can you do this with your Ubuntu Live CD, you can do it right out of the box – no additional software needed! The program we’ll use is called dd, and it’s included with pretty much all Linux distributions. dd is a utility used to do low-level copying – rather than working with files, it works directly on the raw data on a storage device. Note: dd gets a bad rap, because like many other Linux utilities, if misused it can be very destructive. If you’re not sure what you’re doing, you can easily wipe out an entire hard drive, in an unrecoverable way. Of course, the flip side of that is that dd is extremely powerful, and can do very complex tasks with little user effort. If you’re careful, and follow these instructions closely, you can clone your hard drive with one command. We’re going to take a small hard drive that we’ve been using and copy it to a new hard drive, which hasn’t been formatted yet. To make sure that we’re working with the right drives, we’ll open up a terminal (Applications > Accessories > Terminal) and enter in the following command sudo fdisk –l We have two small drives, /dev/sda, which has two partitions, and /dev/sdc, which is completely unformatted. We want to copy the data from /dev/sda to /dev/sdc. Note: while you can copy a smaller drive to a larger one, you can’t copy a larger drive to a smaller one with the method described below. Now the fun part: using dd. The invocation we’ll use is: sudo dd if=/dev/sda of=/dev/sdc In this case, we’re telling dd that the input file (“if”) is /dev/sda, and the output file (“of”) is /dev/sdc. If your drives are quite large, this can take some time, but in our case it took just less than a minute. If we do sudo fdisk –l again, we can see that, despite not formatting /dev/sdc at all, it now has the same partitions as /dev/sda.  Additionally, if we mount all of the partitions, we can see that all of the data on /dev/sdc is now the same as on /dev/sda. Note: you may have to restart your computer to be able to mount the newly cloned drive. And that’s it…If you exercise caution and make sure that you’re using the right drives as the input file and output file, dd isn’t anything to be scared of. Unlike other utilities, dd copies absolutely everything from one drive to another – that means that you can even recover files deleted from the original drive in the clone! Similar Articles Productive Geek Tips Reset Your Ubuntu Password Easily from the Live CDHow to Browse Without a Trace with an Ubuntu Live CDRecover Deleted Files on an NTFS Hard Drive from a Ubuntu Live CDCreate a Bootable Ubuntu 9.10 USB Flash DriveWipe, Delete, and Securely Destroy Your Hard Drive’s Data the Easy Way TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Windows Media Player Glass Icons (icons we like) How to Forecast Weather, without Gadgets Outlook Tools, one stop tweaking for any Outlook version Zoofs, find the most popular tweeted YouTube videos Video preview of new Windows Live Essentials 21 Cursor Packs for XP, Vista & 7

    Read the article

  • Using a parser to locate faulty code

    - by ryan.riverside
    Lately I've been working a lot in PHP and have run into an abnormally large number of parsing errors. I realize these are my own fault and a result of sloppy initial coding on my part, but it's getting to the point that I'm spending more time resolving tags than developing. In the interest of not slamming my productivity, are there any tricks to locating the problem in the code? What I'd really be looking for would be a line to put in the code which would output the entire faulty tag in the parsing error, or something similar. Purely for reference sake, my current error is Parse error: syntax error, unexpected '}' in /home/content/80/9480880/html/cache/tpl_prosilver_viewtopic_body.html.php on line 50 (which refers to this): </dd><dd><?php if ($_poll_option_val['POLL_OPTION_RESULT'] == 0) { echo ((isset($this->_rootref['L_NO_VOTES'])) ? $this->_rootref['L_NO_VOTES'] : ((isset($user->lang['NO_VOTES'])) ? $user->lang['NO_VOTES'] : '{ NO_VOTES }')); } else { echo $_poll_option_val['POLL_OPTION_PERCENT']; } ?></dd> </dl> <?php }} if ($this->_rootref['S_DISPLAY_RESULTS']) { ?> <dl> <dt>&nbsp;</dt> <dd class="resultbar"><?php echo ((isset($this->_rootref['L_TOTAL_VOTES'])) ? $this->_rootref['L_TOTAL_VOTES'] : ((isset($user->lang['TOTAL_VOTES'])) ? $user->lang['TOTAL_VOTES'] : '{ TOTAL_VOTES }')); ?> : <?php echo (isset($this->_rootref['TOTAL_VOTES'])) ? $this->_rootref['TOTAL_VOTES'] : ''; ?></dd> </dl> <?php } if ($this->_rootref['S_CAN_VOTE']) { ?> <dl style="border-top: none;"> <dt>&nbsp;</dt> <dd class="resultbar"><input type="submit" name="update" value="<?php echo ((isset($this->_rootref['L_SUBMIT_VOTE'])) ? $this->_rootref['L_SUBMIT_VOTE'] : ((isset($user->lang['SUBMIT_VOTE'])) ? $user->lang['SUBMIT_VOTE'] : '{ SUBMIT_VOTE }')); ?>" class="button1" /></dd> </dl> <?php } if (! $this->_rootref['S_DISPLAY_RESULTS']) { ?> <dl style="border-top: none;"> <dt>&nbsp;</dt> <dd class="resultbar"><a href="<?php echo (isset($this->_rootref['U_VIEW_RESULTS'])) ? $this->_rootref['U_VIEW_RESULTS'] : ''; ?>"><?php echo ((isset($this->_rootref['L_VIEW_RESULTS'])) ? $this->_rootref['L_VIEW_RESULTS'] : ((isset($user->lang['VIEW_RESULTS'])) ? $user->lang['VIEW_RESULTS'] : '{ VIEW_RESULTS }')); ?></a></dd> </dl> <?php } ?> </fieldset></div>

    Read the article

  • Dijkstras Algorithm exaplination java

    - by alchemey89
    Hi, I have found an implementation for dijkstras algorithm on the internet and was wondering if someone could help me understand how the code works. Many thanks private int nr_points=0; private int[][]Cost; private int []mask; private void dijkstraTSP() { if(nr_points==0)return; //algorithm=new String("Dijkstra"); nod1=new Vector(); nod2=new Vector(); weight=new Vector(); mask=new int[nr_points]; //initialise mask with zeros (mask[x]=1 means the vertex is marked as used) for(int i=0;i<nr_points;i++)mask[i]=0; //Dijkstra: int []dd=new int[nr_points]; int []pre=new int[nr_points]; int []path=new int[nr_points+1]; int init_vert=0,pos_in_path=0,new_vert=0; //initialise the vectors for(int i=0;i<nr_points;i++) { dd[i]=Cost[init_vert][i]; pre[i]=init_vert; path[i]=-1; } pre[init_vert]=0; path[0]=init_vert; pos_in_path++; mask[init_vert]=1; for(int k=0;k<nr_points-1;k++) { //find min. cost in dd for(int j=0;j<nr_points;j++) if(dd[j]!=0 && mask[j]==0){new_vert=j; break;} for(int j=0;j<nr_points;j++) if(dd[j]<dd[new_vert] && mask[j]==0 && dd[j]!=0)new_vert=j; mask[new_vert]=1; path[pos_in_path]=new_vert; pos_in_path++; for(int j=0;j<nr_points;j++) { if(mask[j]==0) { if(dd[j]>dd[new_vert]+Cost[new_vert][j]) { dd[j]=dd[new_vert]+Cost[new_vert][j]; } } } } //Close the cycle path[nr_points]=init_vert; //Save the solution in 3 vectors (for graphical purposes) for(int i=0;i<nr_points;i++) { nod1.addElement(path[i]); nod2.addElement(path[i+1]); weight.addElement(Cost[path[i]][path[i+1]]); } }

    Read the article

  • Dijkstra's Algorithm explanation java

    - by alchemey89
    Hi, I have found an implementation for dijkstras algorithm on the internet and was wondering if someone could help me understand how the code works. Many thanks private int nr_points=0; private int[][]Cost; private int []mask; private void dijkstraTSP() { if(nr_points==0)return; //algorithm=new String("Dijkstra"); nod1=new Vector(); nod2=new Vector(); weight=new Vector(); mask=new int[nr_points]; //initialise mask with zeros (mask[x]=1 means the vertex is marked as used) for(int i=0;i<nr_points;i++)mask[i]=0; //Dijkstra: int []dd=new int[nr_points]; int []pre=new int[nr_points]; int []path=new int[nr_points+1]; int init_vert=0,pos_in_path=0,new_vert=0; //initialise the vectors for(int i=0;i<nr_points;i++) { dd[i]=Cost[init_vert][i]; pre[i]=init_vert; path[i]=-1; } pre[init_vert]=0; path[0]=init_vert; pos_in_path++; mask[init_vert]=1; for(int k=0;k<nr_points-1;k++) { //find min. cost in dd for(int j=0;j<nr_points;j++) if(dd[j]!=0 && mask[j]==0){new_vert=j; break;} for(int j=0;j<nr_points;j++) if(dd[j]<dd[new_vert] && mask[j]==0 && dd[j]!=0)new_vert=j; mask[new_vert]=1; path[pos_in_path]=new_vert; pos_in_path++; for(int j=0;j<nr_points;j++) { if(mask[j]==0) { if(dd[j]>dd[new_vert]+Cost[new_vert][j]) { dd[j]=dd[new_vert]+Cost[new_vert][j]; } } } } //Close the cycle path[nr_points]=init_vert; //Save the solution in 3 vectors (for graphical purposes) for(int i=0;i<nr_points;i++) { nod1.addElement(path[i]); nod2.addElement(path[i+1]); weight.addElement(Cost[path[i]][path[i+1]]); } }

    Read the article

  • Sun Solaris - Find out number of processors and cores

    - by Adrian
    Our SPARC server is running Sun Solaris 10; I would like to find out the actual number of processors and the number of cores for each processor. The output of psrinfo and prtdiag is ambiguous: $psrinfo -v Status of virtual processor 0 as of: dd/mm/yyyy hh:mm:ss on-line since dd/mm/yyyy hh:mm:ss. The sparcv9 processor operates at 1592 MHz, and has a sparcv9 floating point processor. Status of virtual processor 1 as of: dd/mm/yyyy hh:mm:ss on-line since dd/mm/yyyy hh:mm:ss. The sparcv9 processor operates at 1592 MHz, and has a sparcv9 floating point processor. Status of virtual processor 2 as of: dd/mm/yyyy hh:mm:ss on-line since dd/mm/yyyy hh:mm:ss. The sparcv9 processor operates at 1592 MHz, and has a sparcv9 floating point processor. Status of virtual processor 3 as of: dd/mm/yyyy hh:mm:ss on-line since dd/mm/yyyy hh:mm:ss. The sparcv9 processor operates at 1592 MHz, and has a sparcv9 floating point processor. _ $prtdiag -v System Configuration: Sun Microsystems sun4u Sun Fire V445 System clock frequency: 199 MHZ Memory size: 32GB ==================================== CPUs ==================================== E$ CPU CPU CPU Freq Size Implementation Mask Status Location --- -------- ---------- --------------------- ----- ------ -------- 0 1592 MHz 1MB SUNW,UltraSPARC-IIIi 3.4 on-line MB/C0/P0 1 1592 MHz 1MB SUNW,UltraSPARC-IIIi 3.4 on-line MB/C1/P0 2 1592 MHz 1MB SUNW,UltraSPARC-IIIi 3.4 on-line MB/C2/P0 3 1592 MHz 1MB SUNW,UltraSPARC-IIIi 3.4 on-line MB/C3/P0 _ $more /etc/release Solaris 10 8/07 s10s_u4wos_12b SPARC Copyright 2007 Sun Microsystems, Inc. All Rights Reserved. Use is subject to license terms. Assembled 16 August 2007 Patch Cluster - EIS 29/01/08(v3.1.5) What other methods can I use? EDITED: It looks like we have a 4 processor system with one core each: $psrinfo -p 4 _ $psrinfo -pv The physical processor has 1 virtual processor (0) UltraSPARC-IIIi (portid 0 impl 0x16 ver 0x34 clock 1592 MHz) The physical processor has 1 virtual processor (1) UltraSPARC-IIIi (portid 1 impl 0x16 ver 0x34 clock 1592 MHz) The physical processor has 1 virtual processor (2) UltraSPARC-IIIi (portid 2 impl 0x16 ver 0x34 clock 1592 MHz) The physical processor has 1 virtual processor (3) UltraSPARC-IIIi (portid 3 impl 0x16 ver 0x34 clock 1592 MHz)

    Read the article

  • Jquery Slidetoggle open 1 div and close another

    - by Stephen
    I'm trying to close one div when clicking on another div . Currently, it opens multiple divs at one time. JQUERY: $(document).ready(function() { $(".dropdown dt a").click(function() { var dropID = $(this).closest("dl").attr("id"); $("#"+dropID+" dd ul").slideToggle(200); return false; }); $(".dropdown dd ul li a").click(function() { var dropID = $(this).closest("dl").attr("id"); var text = $(this).html(); var selVal = $(this).find(".dropdown_value").html(); $("#"+dropID+" dt a").html(text); $("#"+dropID+" dd ul").hide(); return false; }); $("dl[class!=dropdown]").click(function() { $(".dropdown dd ul").hide(); return false; }); $("id!=quotetoolContainer").click(function() { $(".dropdown dd ul").hide(); return false; }); $('body').click(function() { $(".dropdown dd ul").hide(); return false; }); $('.productSelection').children().hover(function() { $(this).siblings().stop().fadeTo(200,0.5); }, function() { $(this).siblings().stop().fadeTo(200,1); }); }); HTML: <div id="quotetoolContainer"> <div class="top"></div> <div id="quotetool"> <h2>Instant Price Calculator</h2> <p>Document Type</p> <dl id="docType" class="dropdown"> <dt><a href="#"><span>Select a Document Type</span></a></dt> <dd> <ul> <li><a href="#" id="1">Datasheets<span class="value">Datasheets</span></a></li> <li><a href="#">Manuals<span class="value">Manuals</span></a></li> <li><a href="#">Brochures<span class="value">Brochures</span></a></li> <li><a href="#">Newsletters<span class="value">Newsletters</span></a></li> <li><a href="#">Booklets<span class="value">Booklets</span></a></li> </ul> </dd> </dl> <p>Flat Size</p> <dl id="flatSize" class="dropdown"> <dt><a href="#">8.5" x 11"<span class="value">8.5" x 11"</span></a></dt> <dd> <ul> <li><a href="#">8.5" x 11"<span class="value">8.5" x 11"</span></a></li> <li><a href="#">11" x 17"<span class="value">11" x 17"</span></a></li> </ul> </dd> </dl> <p>Full Color or Black &amp; White?</p> <dl id="color" class="dropdown"> <dt><a href="#">Full Color<span class="value">Full Color</span></a></dt> <dd> <ul> <li><a href="#">Full Color<span class="value">Full Color</span></a></li> <li><a href="#">Black &amp; White<span class="value">Black &amp; White</span></a></li> </ul> </dd> </dl> <p>Paper</p> <dl id="paper" class="dropdown"> <dt><a href="#">Value White Paper (20 lb.)<span class="value">Value White Paper (20 lb.)</span></a></dt> <dd> <ul> <li><a href="#">Value White Paper (20 lb.)<span class="value">Value White Paper (20 lb.)</span></a></li> <li><a href="#">Premium White Paper (28 lb.)<span class="value">Premium White Paper (28 lb.)</span></a></li> <li><a href="#">Glossy White Text (80 lb.) - Recycled<span class="value">Glossy White Text (80 lb.) - Recycled</span></a></li> <li><a href="#">Glossy White Cover (80 lb.) - Recycled<span class="value">Glossy White Cover (80 lb.) - Recycled</span></a></li> </ul> </dd> </dl> <p>Folding</p> <dl id="folding" class="dropdown"> <dt><a href="#">Fold in Half<span class="value">Fold in Half</span></a></dt> <dd> <ul> <li><a href="#">Fold in Half<span class="value">Fold in Half</span></a></li> <li><a href="#">Tri-Fold<span class="value">Tri-Fold</span></a></li> <li><a href="#">Z-Fold<span class="value">Z-Fold</span></a></li> <li><a href="#">Double-Parallel Fold<span class="value">Double-Parallel Fold</span></a></li> </ul> </dd> </dl> <p>Three-Hole Drill</p> <dl id="drill" class="dropdown"> <dt><a href="#">No<span class="value">No</span></a></dt> <dd> <ul> <li><a href="#">No<span class="value">No</span></a></li> <li><a href="#">Yes<span class="value">Yes</span></a></li> </ul> </dd> </dl> <p>Qty</p> <dl id="quantity" class="dropdown"> <dt><a href="#">50<span class="value">50</span></a></dt> <dd> <ul> <li><a href="#">50<span class="value">50</span></a></li> <li><a href="#">100<span class="value">100</span></a></li> <li><a href="#">150<span class="value">150</span></a></li> <li><a href="#">200<span class="value">200</span></a></li> <li><a href="#">250<span class="value">250</span></a></li> <li><a href="#">500<span class="value">500</span></a></li> <li><a href="#">750<span class="value">750</span></a></li> <li><a href="#">1,000<span class="value">1,000</span></a></li> <li><a href="#">1,500<span class="value">1,500</span></a></li> <li><a href="#">2,000<span class="value">2,000</span></a></li> <li><a href="#">2,500<span class="value">2,500</span></a></li> <li><a href="#">3,000<span class="value">3,000</span></a></li> <li><a href="#">3,500<span class="value">3,500</span></a></li> <li><a href="#">4,000<span class="value">4,000</span></a></li> <li><a href="#">4,500<span class="value">4,500</span></a></li> <li><a href="#">5,000<span class="value">5,000</span></a></li> <li><a href="#">5,500<span class="value">5,500</span></a></li> <li><a href="#">6,000<span class="value">6,000</span></a></li> <li><a href="#">6,500<span class="value">6,500</span></a></li> <li><a href="#">7,000<span class="value">7,000</span></a></li> <li><a href="#">7,500<span class="value">7,500</span></a></li> <li><a href="#">8,000<span class="value">8,000</span></a></li> <li><a href="#">8,500<span class="value">8,500</span></a></li> <li><a href="#">9,000<span class="value">9,000</span></a></li> <li><a href="#">9,500<span class="value">9,500</span></a></li> <li><a href="#">10,000<span class="value">10,000</span></a></li> <li><a href="#">12,500<span class="value">12,500</span></a></li> <li><a href="#">15,000<span class="value">15,000</span></a></li> <li><a href="#">17,500<span class="value">17,500</span></a></li> <li><a href="#">20,000<span class="value">20,000</span></a></li> </ul> </dd> </dl> <div id="priceTotal"> <div class="priceText">Your Price:</div> <div class="price">$29.00</div> <div class="clear"></div> </div> <div id="buttonQuoteStart"><a href="#" title="Start Printing">Start Printing</a></div> </div> <div class="bottom"></div> </div>

    Read the article

  • Parent CSS (jQuery)

    - by Glister
    There is <dl> with padding-top <dl style="padding-top: 150px;"> <dt>text</dt> <dd><img width="150" height="150" src="..." /></dd> <dt>text 2</dt> <dd><img width="150" height="250" src="..." /></dd> <dt>text 3</dt> <dd><img width="150" height="350" src="..." /></dd> </dl> The difference between images - height. Trying to write a script, which will change a height of the <dl>, when <dd> is clicked. Height should be taken from the height attribute of the dd img. Tryed this, but it doesn't work: $("#posters dd").click(function(){ var parent_padding = $(this).find("img").attr("height"); $(this).parent().css({"padding-top":parent_padding}); }); Thanks.

    Read the article

< Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >