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  • Alert show when extension of FileUpLoads are not allowed

    - by Vy Clarks
    I have a asp FileUpload control in my aspx page. And the code behind to check file's extension and then insert them into database: private string Write(HttpPostedFile file, string table) { string fileNameMain = Path.GetFileName(file.FileName); // check for the valid file extension string fileExtension = Path.GetExtension(fileNameMain).ToLower(); if (fileExtension.Equals(".pdf") || fileExtension.Equals(".doc")) { ...insert fileupload into database } else { LabelError.Text = "Extension of files are not allowed."; return null; } } With the code above, it checks the extension and then show the message "Extension of files are not allowed." in a LabelError if the fileupload is not allowed. Now, I'm required to do the "check-extension" in the other way: at the moment the client click and choose FileUpload, an alert show "Extension of files are not allowed.". I need a way to make an alert show at the momment the FileUpload choosed in browser. Help!!!!

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  • Why is the ASP Repeater.Items collection empty, when controls are on the screen?

    - by Ryan
    I have an ASP page with the following repeater: <asp:Repeater runat="server" ID="RegionRepeater" DataSourceID="SqlDataSourceRegions" EnableViewState="true"> <ItemTemplate> <tr> <td valign="top"> <b><%#Eval("description")%></b> <asp:HiddenField runat="server" ID="RegionID" Value='<%#Eval("region_id")%>'/> </td> <td> <asp:FileUpload ID="FileUpload" runat="server" Width="368px" /> </td> </tr> </ItemTemplate> </asp:Repeater> (The repeater is inside a Wizard, inside a content pane). The code behind is connected to the protected void Wizard1_NextButtonClick(object sender, WizardNavigationEventArgs e) event. There are two items on the screen (two rows inside the table). However, when the code tries to read those items, the Items collection is empty! foreach(RepeaterItem region in RegionRepeater.Items) { // Never runs - the RegionRepeater.Items.Count = 0 FileUpload fileUpload = (FileUpload) region.FindControl("FileUpload"); String regionID = ((HiddenField)region.FindControl("RegionID")).Value; ... Why is the collection empty, when there are controls drawn on the screen? Thanks a lot for any help; this is starting to drive me nuts. (BTW: I tried adding/removing the EnableViewState="true" tag)

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  • Why is the ASP.NET Repeater.Items collection empty, when controls are on the screen?

    - by Ryan
    I have an ASP page with the following repeater: <asp:Repeater runat="server" ID="RegionRepeater" DataSourceID="SqlDataSourceRegions" EnableViewState="true"> <ItemTemplate> <tr> <td valign="top"> <b><%#Eval("description")%></b> <asp:HiddenField runat="server" ID="RegionID" Value='<%#Eval("region_id")%>'/> </td> <td> <asp:FileUpload ID="FileUpload" runat="server" Width="368px" /> </td> </tr> </ItemTemplate> </asp:Repeater> (The repeater is inside a Wizard, inside a content pane). The code behind is connected to the protected void Wizard1_NextButtonClick(object sender, WizardNavigationEventArgs e) event. There are two items on the screen (two rows inside the table). However, when the code tries to read those items, the Items collection is empty! foreach(RepeaterItem region in RegionRepeater.Items) { // Never runs - the RegionRepeater.Items.Count = 0 FileUpload fileUpload = (FileUpload) region.FindControl("FileUpload"); String regionID = ((HiddenField)region.FindControl("RegionID")).Value; ... Why is the collection empty, when there are controls drawn on the screen? Thanks a lot for any help; this is starting to drive me nuts. (BTW: I tried adding/removing the EnableViewState="true" tag)

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  • Is it possible to remember the filename from a fileupload field and then later launch that file via

    - by Pieter Breed
    I have a HTML file upload field from which I'm reading the file name of the file that the user specifies. The actual contents of the file is never uploaded. At a later stage, is it possible to construct a link using this file name information so that if the user clicks on this link, the original file is launched into a new browser window? If not, what are the reason for disallowing this behaviour? The purpose of such a feature is to store links to documents that are available on a mapped local drive or a network share.

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  • how can we apply client side validation on fileupload control in ASP.NET to check filename contain s

    - by subodh
    I am working on ASP.NET3.5 platform. I have used a file upload control and a asp button to upload a file. Whenever i try to upload a file which contain special characterlike (file#&%.txt) it show crash and give the messeage Server Error in 'myapplication' Application. A potentially dangerous Request.Files value was detected from the client (filename="...\New Text &#.txt"). Description: Request Validation has detected a potentially dangerous client input value, and processing of the request has been aborted. This value may indicate an attempt to compromise the security of your application, such as a cross-site scripting attack. You can disable request validation by setting validateRequest=false in the Page directive or in the configuration section. However, it is strongly recommended that your application explicitly check all inputs in this case. Exception Details: System.Web.HttpRequestValidationException: A potentially dangerous Request.Files value was detected from the client (filename="...\New Text &#.txt"). Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. how can i prevent this crash using javascript at client side?

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  • HTML/Javascript: Is it possible to remember the filename from a fileupload field ONLY and then later

    - by Pieter Breed
    I have a HTML file upload field from which I'm reading the file name of the file that the user specifies. The actual contents of the file is never uploaded. At a later stage, is it possible to construct a link using this file name information so that if the user clicks on this link, the original file is launched into a new browser window? If not, what are the reason for disallowing this behaviour? The purpose of such a feature is to store links to documents that are available on a mapped local drive or a network share.

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  • problem with dll file linked with masterpage

    - by sumit
    i have recently find the solution that how i can retrieve the fileupload id when page is linked with masterpage in codebehind as ContentPlaceHolder content = Page.Master.FindControl("ContentPlaceHolder1") as ContentPlaceHolder; Fileupload f=content.FindControl("FileUpload1") as FileUpload; in my contentplaceholeder1 i have a dropdownlist with id dropdownlist1 now i m trying to use it in one of the cs file of dll file as if (previousFields.ContainsKey("dropdownlist1")) { prefix = previousFields["dropdownlist1"]; } where dropdownload list is the previos field of fileupload so it checks the previos field and assign the prefix to the corresponding value.nw i want to know how can i access the dropdownlist id within contentplaceholder1 id

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  • Passing PHP variables trough functions?

    - by Mateus Nunes
    I'm facing some troubles to pass php variables value trough functions,every time i try to use a variable inside one of my functions its value becomes nil,let me be more specific.I have the following code in my php file: $myvar = $Session['username']; function updateuserinformation(){ if(trim($_FILES["fileUpload"]["tmp_name"]) != ""){ $images = $_FILES["fileUpload"]["tmp_name"]; $new_images = "thumbnails_".$_FILES["fileUpload"]["name"]; copy($_FILES["fileUpload"]["tmp_name"],"Photos/".$_FILES["fileUpload"]["name"]); $width=200; //*** Fix Width & Heigh (Autu caculate) ***// $size=GetimageSize($images); $height=round($width*$size[1]/$size[0]); $images_orig = ImageCreateFromJPEG($images); $photoX = ImagesX($images_orig); $photoY = ImagesY($images_orig); $images_fin = ImageCreateTrueColor($width, $height); ImageCopyResampled($images_fin, $images_orig, 0, 0, 0, 0, $width+1, $height+1, $photoX, $photoY); ImageJPEG($images_fin,"Photos/".$new_images); ImageDestroy($images_orig); ImageDestroy($images_fin); print $data["foo"]; echo"$myvar"; mysql_query("UPDATE users SET userpictureaddress = 'http://www.litsdevelopment.com/litsapplication/userimages/MATEUS' WHERE username = 'Mateus' "); } } I trying to use the $myvar value in my function but every time i run the code it just doesn't work,i've already tried global,globals,arrays and session for nothing worked.Of corse i'm making a little mistake in some part of it,but anyone know what is the correct way to do this?

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  • ASP.NET Hosting :: ASP.NET File Upload Control

    - by mbridge
    The asp.net FileUpload control allows a user to browse and upload files to the web server. From developers perspective, it is as simple as dragging and dropping the FileUpload control to the aspx page. An extra control, like a Button control, or some other control is needed, to actually save the file. <asp:FileUploadID="FileUpload1"runat="server"/> <asp:ButtonID="B1"runat="server"Text="Save"OnClick="B1_Click"/> By default, the FileUpload control allows a maximum of 4MB file to be uploaded and the execution timeout is 110 seconds. These properties can be changed from within the web.config file’s httpRuntime section. The maxRequestLength property determines the maximum file size that can be uploaded. The executionTimeout property determines the maximum time for execution. <httpRuntimemaxRequestLength="8192"executionTimeout="220"/> From code behind, the mime type, size of the file, file name and the extension of the file can be obtained. The maximum file size that can be uploaded can be obtained and modified using the System.Web.Configuration.HttpRuntimeSection class. Files can be alternatively saved using the System.IO.HttpFileCollection class. This collection class can be populated using the Request.Files property. The collection contains HttpPostedFile class which contains a reference to the class. using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.IO; using System.Configuration; using System.Web.Configuration;   namespace WebApplication1 {     public partial class WebControls : System.Web.UI.Page     {         protected void Page_Load(object sender, EventArgs e)         {         }           //Using FileUpload control to upload and save files         protected void B1_Click(object sender, EventArgs e)         {             if (FileUpload1.HasFile && FileUpload1.PostedFile.ContentLength > 0)             {                 //mime type of the uploaded file                 string mimeType = FileUpload1.PostedFile.ContentType;                   //size of the uploaded file                 int size = FileUpload1.PostedFile.ContentLength; // bytes                   //extension of the uploaded file                 string extension = System.IO.Path.GetExtension(FileUpload1.FileName);                                  //save file                 string path = Server.MapPath("path");                                 FileUpload1.SaveAs(path + FileUpload1.FileName);                              }             //maximum file size allowed             HttpRuntimeSection rt = new HttpRuntimeSection();             rt.MaxRequestLength = rt.MaxRequestLength * 2;             int length = rt.MaxRequestLength;                     //execution timeout             TimeSpan ts = rt.ExecutionTimeout;             double secomds = ts.TotalSeconds;           }           //Using Request.Files to save files         private void AltSaveFile()         {             HttpFileCollection coll = Request.Files;             for (int i = 0; i < coll.Count; i++)             {                 HttpPostedFile file = coll[i];                   if (file.ContentLength > 0)                     ;//do something             }         }     } }

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  • JQuery uploadify plugin not working

    - by Nitesh Panchal
    Hello, I first used primefaces FileUpload component and it didn't work. Always gave "HTTP Error". So i thought there is some bug with this component and went to plain old JQuery and tried using uploadify. But still i get the same error. I am using Container Managed Security. Is this the reason for not working properly? This is my script :- $(document).ready(function(){ $('#photoInput').uploadify({ 'script' : '/Blogger/fileUploadServlet', 'uploader' : './uploadify/uploadify.swf', 'cancelImg' : './uploadify/cancel.png', 'auto' : true }); And this is my servlet which is never executed :- package Servlets; import java.io.IOException; import java.io.PrintWriter; import java.util.Iterator; import java.util.List; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItemFactory; import org.apache.commons.fileupload.FileUploadException; import org.apache.commons.fileupload.disk.DiskFileItemFactory; import org.apache.commons.fileupload.servlet.ServletFileUpload; @WebServlet(name = "fileUploadServlet", urlPatterns = {"/fileUploadServlet"}) public class fileUploadServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, FileUploadException { PrintWriter out = response.getWriter(); try { System.out.println("Executed!!"); boolean isMultipart = ServletFileUpload.isMultipartContent(request); // Create a factory for disk-based file items FileItemFactory factory = new DiskFileItemFactory(); // Create a new file upload handler ServletFileUpload upload = new ServletFileUpload(factory); // Parse the request List /* FileItem */ items = upload.parseRequest(request); Iterator e = items.iterator(); while(e.hasNext()){ System.out.println(e.next().toString()); } } finally { out.close(); } } } }); Please help me. I am stuck on this since 3 hours.

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  • Restricting Directory access from web application context

    - by Yogi
    i have a web application which stores users file in directory which is under webroot directory.. Suppose web application is under 'fileupload' and all files are getting stored in 'xyz' folder under 'fileupload' so now if user points to url say like www.xyzpqr.com/fileupload/xyz/abc.doc, he gets that file. How do i restirct this from happening.. i have thought of putting xyz folder in WeB-inf folder but as my application is very big i have to made changes at too many places.. so is there any way so that without moving the folder to web-inf (restricted folders) i can achieve wat i want..

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  • Uploading Files Using ASP.NET Web Forms, Generic Handler and jQuery

    - by bipinjoshi
    In order to upload files from the client machine to the server ASP.NET developers use FileUpload server control. The FileUpload server control essentially renders an INPUT element with its type set to file and allows you to select one or more files. The actual upload operation is performed only when the form is posted to the server. Instead of making a full page postback you can use jQuery to make an Ajax call to the server and POST the selected files to a generic handler (.ashx). The generic handler can then save the files to a specified folder. The remainder of this post shows how this can be accomplished.http://www.bipinjoshi.net/articles/f2a2f1ee-e18a-416b-893e-883c800f83f4.aspx      

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  • WCF MaxReceivedMessageSize property not taking

    - by Steve Syfuhs
    Searched with no luck... I keep getting The maximum message size quota for incoming messages (65536) has been exceeded. To increase the quota, use the MaxReceivedMessageSize property on the appropriate binding element. It makes sense, so I go into both Server and client config and make the change: Client <system.serviceModel> <bindings> <basicHttpBinding> <binding name="BasicHttpBinding_IFileUpload" closeTimeout="00:01:00" openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00" transferMode="Streamed" messageEncoding="Text" maxBufferSize="65536" maxReceivedMessageSize="67108864"> </binding> </basicHttpBinding> </bindings> <client> <endpoint address="http://localhost/services/FileUpload.svc" binding="basicHttpBinding" bindingConfiguration="BasicHttpBinding_IFileUpload" contract="CFTW.FileUpload.IFileUpload" name="BasicHttpBinding_IFileUpload" /> </client> </system.serviceModel> Server <system.serviceModel> <behaviors> <serviceBehaviors> <behavior name=""> <serviceMetadata httpGetEnabled="true" /> <serviceDebug includeExceptionDetailInFaults="false" /> </behavior> </serviceBehaviors> </behaviors> <bindings> <basicHttpBinding> <binding name="BasicHttpBinding_IFileUpload" transferMode="Streamed" messageEncoding="Text" maxBufferSize="67108864" maxBufferPoolSize="67108864" maxReceivedMessageSize="67108864"> </binding> </basicHttpBinding> </bindings> <services> <service name="BasicHttpBinding_IFileUpload"> <endpoint address="~/services/FileUpload.svc" binding="basicHttpBinding" bindingConfiguration="BasicHttpBinding_IFileUpload" contract="CFTW.FileUpload.IFileUpload"></endpoint> </service> </services> <serviceHostingEnvironment multipleSiteBindingsEnabled="true" /> </system.serviceModel> I'm not sure why it's not working (otherwise I'd fix it:)). It's running on .NET 4.0 RC.

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  • Why is this simple file upload not working? JSF

    - by Nitesh Panchal
    Hello, Why is this code not working? I always get size() = 0, whenever i upload file. xhtml file :- <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>Abc</title> </h:head> <h:body> <center> <form method="post" enctype="multipart/form-data" id="form" action="/upload/uploadFile"> <input type="file"/> <br/> <input type="Submit" value="upload"/> </form> </center> </h:body> </html> This is my servlet :- package servlets; import java.io.IOException; import java.util.List; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItem; import org.apache.commons.fileupload.FileUploadException; import org.apache.commons.fileupload.disk.DiskFileItemFactory; import org.apache.commons.fileupload.servlet.ServletFileUpload; @WebServlet(name="uploadFile", urlPatterns={"/uploadFile"}) public class uploadFile extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, FileUploadException { System.out.println("executed!"); List<FileItem> items = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request); System.out.println(items.size()); for (FileItem item : items) { if (!item.isFormField()) { System.out.println("Name: " + item.getName()); System.out.println("Size: " + item.getSize()); System.out.println("Type: " + item.getContentType()); } } } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; } }

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  • scriptdata not working in uploadify

    - by Vinoth13
    Hi Friends i am using uploadify for my project.. in that i need to pass some data to upload.php to insert it in database. i am using the below code for sending data and getting it using $_POST in that upload.php file but its not getting those values. $("#fileupload").fileUpload({ 'uploader': 'uploadify/uploader.swf', 'cancelImg': 'uploadify/cancel.png', 'script': 'uploadify/upload.php', 'scriptData' : {'name':'name','status':1} Can anyone help me on this ..

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  • Spring upload file

    - by benaissa
    hi every one, I'm a novice in Spring, i started to develop an application to upload files,i used the official spring documentation but, i have this error: Handler processing failed; nested exception is java.lang.NoClassDefFoundError: org/apache/commons/io/output/DeferredFileOutputStream at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:823) at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:719) at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644) at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:560) at javax.servlet.http.HttpServlet.service(HttpServlet.java:637) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:143) at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:237) at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:619) Caused by: java.lang.NoClassDefFoundError: org/apache/commons/io/output/DeferredFileOutputStream at org.apache.commons.fileupload.disk.DiskFileItemFactory.createItem(DiskFileItemFactory.java:191) at org.apache.commons.fileupload.FileUploadBase.parseRequest(FileUploadBase.java:350) at org.apache.commons.fileupload.servlet.ServletFileUpload.parseRequest(ServletFileUpload.java:126) at org.springframework.web.multipart.commons.CommonsMultipartResolver.parseRequest(CommonsMultipartResolver.java:155) at org.springframework.web.multipart.commons.CommonsMultipartResolver.resolveMultipart(CommonsMultipartResolver.java:138) at org.springframework.web.servlet.DispatcherServlet.checkMultipart(DispatcherServlet.java:907) at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:750)

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  • Error while uploading file method in Client Object Model Sharepoint 2010

    - by user1481570
    Error while uploading file method in Client Object Model + Sharepoint 2010. Once the file got uploaded. After that though the code compiles with no error I get the error while executing "{"Value does not fall within the expected range."} {System.Collections.Generic.SynchronizedReadOnlyCollection} I have a method which takes care of functionality to upload files /////////////////////////////////////////////////////////////////////////////////////////// public void Upload_Click(string documentPath, byte[] documentStream) { String sharePointSite = "http://cvgwinbasd003:28838/sites/test04"; String documentLibraryUrl = sharePointSite +"/"+ documentPath.Replace('\\','/'); //////////////////////////////////////////////////////////////////// //Get Document List List documentsList = clientContext.Web.Lists.GetByTitle("Doc1"); var fileCreationInformation = new FileCreationInformation(); //Assign to content byte[] i.e. documentStream fileCreationInformation.Content = documentStream; //Allow owerwrite of document fileCreationInformation.Overwrite = true; //Upload URL fileCreationInformation.Url = documentLibraryUrl; Microsoft.SharePoint.Client.File uploadFile = documentsList.RootFolder.Files.Add( fileCreationInformation); //uploadFile.ListItemAllFields.Update(); clientContext.ExecuteQuery(); } ///////////////////////////////////////////////////////////////////////////////////////////////// In the MVC 3.0 application in the controller I have defined the following method to invoke the upload method. ////////////////////////////////////////////////////////////////////////////////////////////////// public ActionResult ProcessSubmit(IEnumerable<HttpPostedFileBase> attachments) { System.IO.Stream uploadFileStream=null; byte[] uploadFileBytes; int fileLength=0; foreach (HttpPostedFileBase fileUpload in attachments) { uploadFileStream = fileUpload.InputStream; fileLength=fileUpload.ContentLength; } uploadFileBytes= new byte[fileLength]; uploadFileStream.Read(uploadFileBytes, 0, fileLength); using (DocManagementService.DocMgmtClient doc = new DocMgmtClient()) { doc.Upload_Click("Doc1/Doc2/Doc2.1/", uploadFileBytes); } return RedirectToAction("SyncUploadResult"); } ////////////////////////////////////////////////////////////////////////////////////////////////// Please help me to locate the error

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  • Sharepoint NewForm adding attachments programatically

    - by CodeSpeaker
    I have a list with a custom form which contains a custom file upload control. As soon as the user selects a file and clicks upload, i want this file to go directly to the attachments list within that listitem. However, when adding the file to SPContext.Current.ListItem.Attachments on a new item, the attachment wont show up in the list after saving. If i instead use item.Update() on the new item after adding the attachment i get an error in Sharepoint, but when i then go back to the list, the item is there with its attachment. It seems like its trying to create 2 new entries at once when i save (item.Update) which results in the second of those crashing. What would be the correct way to add attachments this way? oSPWeb.AllowUnsafeUpdates = true; // Get the List item SPListItem listItem = SPContext.Current.ListItem; // Get the Attachment collection SPAttachmentCollection attachmentCollection = listItem.Attachments; Stream attachmentStream; Byte[] attachmentContent; // Get the file from the file upload control if (fileUpload.HasFile) { attachmentStream = fileUpload.PostedFile.InputStream; attachmentContent = new Byte[attachmentStream.Length]; attachmentStream.Read(attachmentContent, 0, (int)attachmentStream.Length); attachmentStream.Close(); attachmentStream.Dispose(); // Add the file to the attachment collection attachmentCollection.Add(fileUpload.FileName, attachmentContent); } // Update th list item listItem.Update();

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  • Getting a Specified Cast is not valid while importing data from Excel using Linq to SQL

    - by niceoneishere
    This is my second post. After learning from my first post how fantastic is to use Linq to SQL, I wanted to try to import data from a Excel sheet into my SQL database. First My Excel Sheet: it contains 4 columns namely ItemNo ItemSize ItemPrice UnitsSold I have a created a database table with the following fields table name ProductsSold Id int not null identity --with auto increment set to true ItemNo VarChar(10) not null ItemSize VarChar(4) not null ItemPrice Decimal(18,2) not null UnitsSold int not null Now I created a dal.dbml file based on my database and I am trying to import the data from excel sheet to db table using the code below. Everything is happening on click of a button. private const string forecast_query = "SELECT ItemNo, ItemSize, ItemPrice, UnitsSold FROM [Sheet1$]"; protected void btnUpload_Click(object sender, EventArgs e) { var importer = new LinqSqlModelImporter(); if (fileUpload.HasFile) { var uploadFile = new UploadFile(fileUpload.FileName); try { fileUpload.SaveAs(uploadFile.SavePath); if(File.Exists(uploadFile.SavePath)) { importer.SourceConnectionString = uploadFile.GetOleDbConnectionString(); importer.Import(forecast_query); gvDisplay.DataBind(); pnDisplay.Visible = true; } } catch (Exception ex) { Response.Write(ex.Source.ToString()); lblInfo.Text = ex.Message; } finally { uploadFile.DeleteFileNoException(); } } } // Now here is the code for LinqSqlModelImporter public class LinqSqlModelImporter : SqlImporter { public override void Import(string query) { // importing data using oledb command and inserting into db using LINQ to SQL using (var context = new WSDALDataContext()) { using (var myConnection = new OleDbConnection(base.SourceConnectionString)) using (var myCommand = new OleDbCommand(query, myConnection)) { myConnection.Open(); var myReader = myCommand.ExecuteReader(); while (myReader.Read()) { context.ProductsSolds.InsertOnSubmit(new ProductsSold() { ItemNo = myReader.GetString(0), ItemSize = myReader.GetString(1), ItemPrice = myReader.GetDecimal(2), UnitsSold = myReader.GetInt32(3) }); } } context.SubmitChanges(); } } } can someone please tell me where am I making the error or if I am missing something, but this is driving me nuts. When I debugged I am getting this error when casting from a number the value must be a number less than infinity I really appreciate it

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  • ASP.NET Send Image Attachment With Email Without Saving To Filesystem

    - by KGO
    I'm trying to create a form that will send an email with an attached image and am running into some problems. The form I am creating is rather large so I have created a small test form for the purpose of this question. The email will send and the attachment will exist on the email, but the image is corrupt or something as it is not viewable. Also.. I do not want to save the image to the filesystem. You may think it is convoluted to take the image file from the fileupload to a stream, but this is due to the fact that the real form I am working on will allow multiple files to be added through a single fileupload and will be saved in session, thus the images will not be coming from the fileupload control directly on submit. File: TestAttachSend.aspx <%@ Page Language="C#" AutoEventWireup="true" CodeFile="TestAttachSend.aspx.cs" Inherits="TestAttachSend" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <h1>Send Email with Image Attachment</h1> Email Address TO: <asp:TextBox ID="txtEmail" runat="server"></asp:TextBox><br /> Attach JPEG Image: <asp:FileUpload ID="fuImage" runat="server" /><br /> <br /> <asp:Button ID="btnSend" runat="server" Text="Send" onclick="btnSend_Click" /><br /> <br /> <asp:label ID="lblSent" runat="server" text="Image Sent!" Visible="false" EnableViewState="false"></asp:label> </div> </form> </body> </html> File: TestAttachSend.aspx.cs using System; using System.Collections.Generic; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Net.Mail; using System.IO; public partial class TestAttachSend : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void btnSend_Click(object sender, EventArgs e) { if (fuImage.HasFile && fuImage.PostedFile.ContentType == System.Net.Mime.MediaTypeNames.Image.Jpeg) { SmtpClient emailClient = new SmtpClient(); MailMessage EmailMsg = new MailMessage(); EmailMsg.To.Add(txtEmail.Text.Trim()); EmailMsg.From = new MailAddress(txtEmail.Text.Trim()); EmailMsg.Subject = "Attached Image"; EmailMsg.Body = "Image is attached!"; MemoryStream imgStream = new MemoryStream(); System.Drawing.Image img = System.Drawing.Image.FromStream(fuImage.PostedFile.InputStream); string filename = fuImage.PostedFile.FileName; img.Save(imgStream, System.Drawing.Imaging.ImageFormat.Jpeg); EmailMsg..Attachments.Add(new Attachment(imgStream, filename, System.Net.Mime.MediaTypeNames.Image.Jpeg)); emailClient.Send(EmailMsg); lblSent.Visible = true; } } }

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  • jquey ajax upload file in asp.net mvc

    - by CoffeeCode
    i have a file in my view <form id="upload" enctype="multipart/form-data"> <input type="file" name="fileUpload" id="fileUpload" size="23" /><br /> </form> and an ajax request $.ajax({ url: '<%=Url.Action("JsonSave","Survey") %>', dataType: 'json', processData: false, contentType: "multipart/mixed", data: { Id: selectedRow.Id, Value: 'some date was added by the user here :))' }, cache: false, success: function(data) { } }); but there is no file in the Request.Files. Whats wrong with the ajax request?

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  • Auto populate input based on file name with AngularJS

    - by LouieV
    I am playing around with AngularJS and have not been able to solve this problem. I have a view that has a form to upload a file to a node server. So far I have manage to do this using some directives and a service. I allow the user to send a custom name to the POST data if they desire. What I wan to accomplish is that when the user selects a file the filename models auto populates. My view looks like: <div> <input file-model="phpFile" type="file"> <input name="filename" type="text" ng-model="filename"> <button ng-click="send()">send</button> </div> file-model is my directive that allows the file to be assigned to a scope. myApp.directive('fileModel', ['$parse', function($parse) { return { restrict: 'A', link: function(scope, element, attrs) { var model = $parse.(attrs.fileModel); var modelSetter = model.assign; element.bind('change', function() { scope.$apply(function() { modelSetter(scope, element[0].files[0]); }); }); } }]); The service: myApp.service('fileUpload', ['$http', function($http){ this.uploadFileToUrl = function(file, uploadUrl, optionals) { var fd = new FormData(); fd.append('file', file); for (var key in file) { fd.append(key, file[key]); } for(var i = 0; i < optionals.length; i++){ fd.append(optionals[i].name, optionals[i].data); } }); }]); Here as you can see I pass the file, append its properties, and append any optional properties. In the controller is where I am having the troubles. I have tried $watch and using the file-model but I get the same error either way. myApp.controller('AddCtrl', function($scope, $location, PEberry, fileUpload){ //$scope.$watch(function() { // return $scope.phpFile; //},function(newValue, oldValue) { // $scope.filename = $scope.phpFile.name; //}, true); // if ($scope.phpFiles) { // $scope.filename = $scope.phpFiles.name; // } $scope.send = function() { var uploadUrl = "/files"; var file = $scope.phpFile; //var opts = [{ name: "uname", data: file.name }] fileUpload.uploadFileToUrl(file, uploadUrl); }; }); Thank you for your help!

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  • Is php fileinfo sufficient to prevent upload of malicious files?

    - by Scarface
    Hey guys, I have searched around a bit, and have not really found a professional type response to how to have secure fileupload capability so I wanted to get the opinion of some of the experts on this site. I am currently allowing upload of mp3s and images, and while I am pretty confident in preventing xss and injection attacks on my site, I am not really familiar with fileupload security. I basically just use php fileinfo and check an array of accepted filetypes against the filetype. For images, there is the getimagesize function and some additional checks. As far as storing them, I just have a folder within my directory, because I want the users to be able to use the files. If anyone could give me some tips I would really appreciate it.

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