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  • Wildcards!

    - by Tim Dexter
    Yes, its been a while, Im sorry, mumble, mumble ... no excuses. Well other than its been, as my son would say 'hecka busy.' On a brighter note I see Kan has been posting some cool stuff in my absence, long may he continue! I received a question today asking about using a wildcard in a template, something like: <?if:INVOICE = 'MLP*'?> where * is the wildcard Well that particular try does not work but you can do it without building your own wildcard function. XSL, the underpinning language of the RTF templates, has some useful string functions - you can find them listed here. I used the starts-with function to achieve a simple wildcard scenario but the contains can be used in conjunction with some of the others to build something more sophisticated. Assume I have a a list of friends and the amounts of money they owe me ... Im very generous and my interest rates a pretty competitive :0) <ROWSET> <ROW> <NAME>Andy</NAME> <AMT>100</AMT> </ROW> <ROW> <NAME>Andrew</NAME> <AMT>60</AMT> </ROW> <ROW> <NAME>Aaron</NAME> <AMT>50</AMT> </ROW> <ROW> <NAME>Alice</NAME> <AMT>40</AMT> </ROW> <ROW> <NAME>Bob</NAME> <AMT>10</AMT> </ROW> <ROW> <NAME>Bill</NAME> <AMT>100</AMT> </ROW> Now, listing my friends is easy enough <for-each:ROW> <NAME> <AMT> <end for-each> but lets say I just want to see all my friends beginning with 'A'. To do that I can use an XPATH expression to filter the data and tack it on to the for-each expression. This is more efficient that using an 'if' statement just inside the for-each. <?for-each:ROW[starts-with(NAME,'A')]?> will find me all the A's. The square braces denote the start of the XPATH expression. starts-with is the function Im calling and Im passing the value I want to check i.e. NAME and the string Im looking for. Just substitute in the characters you are looking for. You can of course use the function in a if statement too. <?if:starts-with(NAME,'A')?><?attribute@incontext:color;'red'?><?end if?> Notice I removed the square braces, this will highlight text red if the name begins with an 'A' You can even use the function to do conditional calculations: <?sum (AMT[starts-with(../NAME,'A')])?> Sum only the amounts where the name begins with an 'A' Notice the square braces are back, its a function we want to apply to the AMT field. Also notice that we need to use ../NAME. The AMT and NAME elements are at the same level in the tree, so when we are at the AMT level we need the ../ to go up a level to then come back down to test the NAME value. I have built out the above functions in a sample template here. Huge prizes for the first person to come up with a 'true' wildcard solution i.e. if NAME like '*im*exter* demand cash now!

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  • How do I ADD an Attribute to the Root Element in XML using XSLT?

    - by kunjaan
    I want to match a root Element “FOO” and perform the transformation (add a version attribute) to it leaving the rest as it is. The Transformation I have so far looks like this: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://schemas.foo.com/fooNameSpace"> <xsl:template match="//FOO"> <xsl:choose> <xsl:when test="@version"> <xsl:apply-templates select="node()|@*" /> </xsl:when> <xsl:otherwise> <FOO> <xsl:attribute name="version">1</xsl:attribute> <xsl:apply-templates select="node()|@*" /> </FOO> </xsl:otherwise> </xsl:choose> </xsl:template> However this does not perform any transformation. It doesn't even detect the element. So I need to do add the namespace in order to make it work: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fd="http://schemas.foo.com/fooNameSpace"> <xsl:template match="//fd:FOO"> … But this attaches a namespace attribute to the FOO element as well as other elements: <FOO xmlns:fd="http://schemas.foo.com/fooNameSpace" version="1" id="fooid"> <BAR xmlns="http://schemas.foo.com/fooNameSpace" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> Is there a way to say that the element is using the default namespace? Can we match and add elements in the default name space? Here is the original XML: <?xml version="1.0" encoding="UTF-8"?> <FOO xmlns="http://schemas.foo.com/fooNameSpace" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <BAR> <Attribute name="HEIGHT">2067</Attribute> </BAR> </FOO>

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  • How to apply or chain multiple matching templates in XSLT?

    - by Ignatius
    I am working on a stylesheet employing many templates with match attributes: <xsl:template match="//one" priority="0.7"> <xsl:param name="input" select="."/> <xsl:value-of select="util:uppercase($input)"/> <xsl:next-match /> </xsl:template> <xsl:template match="/stuff/one"> <xsl:param name="input" select="."/> <xsl:value-of select="util:add-period($input)"/> </xsl:template> <xsl:function name="util:uppercase"> <xsl:param name="input"/> <xsl:value-of select="upper-case($input)"/> </xsl:function> <xsl:function name="util:add-period"> <xsl:param name="input"/> <xsl:value-of select="concat($input,'.')"/> </xsl:function> What I would like to do is be able to 'chain' the two functions above, so that an input of 'string' would be rendered in the output as 'STRING.' (with the period.) I would like to do this in such a way that doesn't require knowledge of other templates in any other template. So, for instance, I would like to be able to add a "util:add-colon" method without having to open up the hood and monkey with the existing templates. I was playing around with the <xsl:next-match/> instruction to accomplish this. Adding it to the first template above does of course invoke both util:uppercase and util:add-period, but the output is an aggregation of each template output (i.e. 'STRINGstring.') It seems like there should be an elegant way to chain any number of templates together using something like <xsl:next-match/>, but have the output of each template feed the input of the next one in the chain. Am I overlooking something obvious?

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  • Twitter Feeds in Umbraco using XSLT

    - by Vizioz Limited
    There are currently two packages tagged on the Umbraco forum that can be used to add a twitter feed to your website. I was playing around with "Twitter for Umbraco" by Warren Buckley and noticed a bug in the way it converted twitter @names to links, so I thought I would try and solve this using XSLT.It may also be useful for those of you using Darren Ferguson's "Feed Cache" package as the demo on Darren's site does not add links to the tweets.To use this XSLT you simple call the XSLT Template passing in your Twitter message:<xsl:call-template name="formaturl"> <xsl:with-param name="url" select="text"/></xsl:call-template>Then add the XSLT template to your XSLT macro (outside of the main template)<xsl:template name="formaturl"> <xsl:param name="twitterfeed"/> <xsl:variable name="transform-http" select="Exslt.ExsltRegularExpressions:replace($twitterfeed, '(http\:\/\/\S+)',ig,'<a href="$1">$1</a>')"/> <xsl:variable name="transform-https" select="Exslt.ExsltRegularExpressions:replace($transform-http, '(HTTps\:\/\/\S+)',ig,'<a href="$1">$1</a>')"/> <xsl:variable name="transform-AT" select="Exslt.ExsltRegularExpressions:replace($transform-https, '(^|\s)@(\w+)',ig,' <a href="http://www.twitter.com/$2">@$2</a>')"/> <xsl:variable name="transform-HASH" select="Exslt.ExsltRegularExpressions:replace($transform-AT, '(^|\s)#(\w+)',ig,' <a href="http://www.twitter.com/search?q=$2">#$2</a>')"/> <xsl:value-of select="$transform-HASH" disable-output-escaping="yes"/> </xsl:template>You should find that this now replaces all the @names, #names and URL's with links!

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  • XSL Transformations in .NET 2.0

    Having realized the need for efficient built-in support for XSLT processing, Microsoft has included in the .NET Framework 2.0 a set of classes that are highly optimized, robust, and scalable. This article will explore the rich XSLT support provided by the .NET Framework 2.0 by providing examples on how to use the XSLT related classes to create rich ASP.NET Web applications.

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  • The Power Of XSL Compared To CSS

    CSS or Cascading Style Sheets is one of the most popular style sheet language used in the market today. This is mainly because of its ease of use as well as with its simplicity which is why CSS was o... [Author: Margarette Mcbride - Web Design and Development - May 17, 2010]

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  • XSLT ... I can'f find a (working) find minimum value in XML and set variable

    - by Bob
    I've search for hours and not found an example that allows for the very first position to be the lowest. I'm getting 'False' instead of the value returned .... EDIT: Oddly enough if I run a 2nd instance as MAX_Landed with ascending it returns a value just fine. If I switch the order in the XSLT the first instance will return 'False' and the 2nd will work. Hope I'm making sense ..... Example XML which I can't get formatted to show correctly and in a hurry so you get the gist I hope: <?xml version="1.0"?> <GetLowestOfferListingsForASINResponse xmlns="http://mws.amazonservices.com/schema/Products/2011-10-01"> <GetLowestOfferListingsForASINResult ASIN="0470067802" status="Success"> <AllOfferListingsConsidered>false</AllOfferListingsConsidered> <Product xmlns="http://mws.amazonservices.com/schema/Products/2011-10-01" xmlns:ns2="http://mws.amazonservices.com/schema/Products/2011-10-01/default.xsd"> <LowestOfferListings> <LowestOfferListing> <Qualifiers> <ItemCondition>Used</ItemCondition> <ItemSubcondition>Good</ItemSubcondition> </Qualifiers> <Price> <LandedPrice> <Amount>15.71</Amount> </LandedPrice> </Price> </LowestOfferListing> <LowestOfferListing> <Qualifiers> <ItemCondition>Used</ItemCondition> <ItemSubcondition>Good</ItemSubcondition> </Qualifiers> <Price> <LandedPrice> <Amount>16.71</Amount> </LandedPrice> </Price> </LowestOfferListing> <LowestOfferListing> <Qualifiers> <ItemCondition>Used</ItemCondition> <ItemSubcondition>Good</ItemSubcondition> </Qualifiers> <Price> <LandedPrice> <Amount>18.71</Amount> </LandedPrice> </Price> </LowestOfferListing> </LowestOfferListings> </Product> </GetLowestOfferListingsForASINResult> </GetLowestOfferListingsForASINResponse> Example XSLT : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:amz="http://mws.amazonservices.com/schema/Products/2011-10-01" exclude-result-prefixes="amz"> <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/> <xsl:template match="/"> <xsl:variable name="MIN_Landed"> <xsl:for-each select="//Amount"> <xsl:sort data-type="number" order="ascending"/> <xsl:if test="position()=1"><xsl:value-of select="."/></xsl:if> </xsl:for-each> </xsl:variable> <FMPXMLRESULT xmlns="http://www.filemaker.com/fmpxmlresult"> <ERRORCODE>0</ERRORCODE> <PRODUCT BUILD="" NAME="" VERSION=""/> <DATABASE DATEFORMAT="M/d/yyyy" LAYOUT="" NAME="" RECORDS="1" TIMEFORMAT="h:mm:ss a"/> <METADATA> <FIELD EMPTYOK="YES" MAXREPEAT="1" NAME="DATA" TYPE="TEXT"/> <FIELD EMPTYOK="YES" MAXREPEAT="1" NAME="Min_Landed" TYPE="TEXT"/> </METADATA> <RESULTSET> <xsl:attribute name="FOUND">1</xsl:attribute> <xsl:for-each select="amz:GetLowestOfferListingsForASINResponse/amz:GetLowestOfferListingsForASINResult/amz:Product/amz:LowestOfferListings/amz:LowestOfferListing"> <ROW> <xsl:attribute name="MODID">0</xsl:attribute> <xsl:attribute name="RECORDID">1</xsl:attribute> <COL> <DATA> <xsl:value-of select="amz:Qualifiers/amz:ItemCondition"/> </DATA> </COL> <COL> <DATA> <xsl:value-of select="$MIN_Landed"/> </DATA> </COL> </ROW> </xsl:for-each> </RESULTSET> </FMPXMLRESULT> </xsl:template> </xsl:stylesheet> HELP PLEASE! I really didn't want to post so much Amazon code but here it is stripped down to a bare bones response

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  • Using EXSLT dates-and-times module in XSLT 1.0 yields unknown error

    - by danielle
    I added the EXSLT dates-and-times module in my XSLT 1.0 file by declaring: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" ... xmlns:date="http://exslt.org/dates-and-times" extension-element-prefixes="date"> This doesn't affect my resulting page, but when I try to call the actual date with: <xsl:value-of select="date:date-time()"/> I receive an "Error loading stylesheet: An unknown error has occurred ()" message when loading my page. Does anyone have a suggestion as to what I might be missing? Thanks in advance!

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  • Can anyone help me out in writing a xslt-fo for this xml file?

    - by atrueguy
    Currencies By Country Australia Australian Dollar Austria Schilling Belgium Belgium Franc Canada Canadian Dollar England Pound Fiji Fijian Dollar France Franc Germany DMark Hong Kong Hong Kong Dollar Italy Lira Japan Yen Netherlands Guilder Switzerland SFranc USA Dollar I started to write a xsl-fo to format the above xml in to a table, but I am really struggling with the flow of the tags, can any one help me out in writing a xsl-fo for this xml file? Is it possible for anyone to suggest me material for staring with xsl-fo, so that I can code my own xsl-fo., because the tags and syntax are very difficult to understand.

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  • Easily (as in WYSIWYG) customize the docbook output

    - by Sukima
    I've used DocBook in the past and I love the idea behind the separation of content from presentation. I am very comfortable editing XML directly. In my extensive search to find the best documenting solution for my needs I am always coming back to this one solution: DocBook - Build system (ant, make, etc.) - Output I have seen lots of information concerning the best WYSIWYG, XML, Text editors for writing DocBook including alternative markup languages like asciidoc. All these solutions focus on the creation of DocBook or the nightmare of the DocBook tool chain. No one ever addresses the Output side other then to say "Just use XSL" or "Custom scripts" When tasked to make a document or manual I don't want to worry about spending countless hours attempting to reprogram, customize, and modify the XSL, CSS, and shell scripts (i.e. O'Riely books). That is a very arduous task. My query: is there a tool that makes the customizing easier? And is there anything that could be similar to say Pages or Word in that the user creates a template and the tool chain does the rest? Attempting to do a visual task like pretty logos and fixing all the broken layouts that the default XSL comes up with (pagination is a mess) is very difficult from a text editor. Content is easy. Editing DocBook XSL was truly a nightmare when I did it in the past. I've searched and I find lots of info on XML editors but nothing on XSL editors. Or am I lacking a key understanding of the process. Thanks.

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  • Replace text in XSL using wildcards

    - by JosephThomas
    This is similar to an earlier problem I was having which you guys solved in less than a day. I am working with XML files that are generated by a digital video camera. The camera allows the user to save all of the camera's settngs to an SD card so that the settings can be recalled or loaded into another camera. The XSL stylesheet I am writing will allow users to view the camera's settings, as saved to the SD card in a web browser. While most of the values in the XML file -- as formatted by my stylesheet -- make sense to humans, some do not. What I would like to do is have the stylesheet display text that is based on the value in the XML file but more easily understood by humans. A typical value that can be written to the XML file is "_23_970" which represents the camera's frame rate. This would be better displayed as 23.970 (or 023.970). The first underscore is a sort of place holder to make a space for values over 099.999. The second underscore, obviously represents the decimal. My previous (similar) question involved replacing predictable text, and the solution was matching templates. In this case, however, the camera can be set at any one of 119,999 frame rates (I think I did that math correctly). The approach, I would guess, is to pass a value to the displayed webpage that keeps the numeric values (each digit), replaces the second underscore with a decimal, and replaces the first underscore with either an nbsp or a zero (whichever is easier). If the first character in the string is a "1" (the camera can run at frame rates up to 120.000) then the one should be passed on to the page displayed by the stylesheet. I have read other posts here regarding wildcards, but couldn't find one that answered this question. EDIT: Sorry for leaving out important info. I fared better on my first try at asking a question! I guess I got complacent. Anyhow . . . I should have shown you the code that displays the text in the XSL file as is: <tr> <xsl:for-each select="Settings/Groups/Recording"> <tr><td class="title_column">Frame Rate</td><td><xsl:value-of select="RecOutLinkSpeed"/></td></tr> </xsl:for-each> </tr> I should also have given you the URL for the sample file I have been working with: http://josephthomas.info/Alexa/Setup_120511_140322.xml

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  • RSS feed generated by SharePoint has a stylesheet tag and how to remove that

    - by iHeartDucks
    The feed which SharePoint Generates is here (I copied it to pastie because I thought it would be clear there) However, the xml file comes with a style sheet tag. How do I remove that? Does SharePoint always generate that? Due to the presence of that tag, I am unable to apply another style sheet of my own using the XML WebPart. EDIT: I don't think the issue is related to the style sheet. If I copy the xml and paste it in the "Xml Editor" of the Web Part everything works just fine. If I provide the URL, that is when I do not see any data. This is my XSL file <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" exclude-result-prefixes="x d ddwrt xsl msxsl" xmlns:x="http://www.w3.org/2001/XMLSchema" xmlns:d="http://schemas.microsoft.com/sharepoint/dsp" xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"> <xsl:output method="html" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="/"> <xsl:value-of select="count(rss)" /> <xsl:value-of select="count(rss/channel)" /> <xsl:value-of select="count(rss/channel/item)" /> <xsl:for-each select="rss/channel/item"> <xsl:value-of select="title" /> </xsl:for-each> </xsl:template> </xsl:stylesheet> Pastie link

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  • Flatten XML using XSLT but based on nesting level

    - by user2532750
    I'm new to XSLT and I'm trying to write some XSLT that will flatten any given XML such that a new line occurs whenever the nesting level changes. My input can be any XML document, with any number of nested levels so the structure isn't known to the XSLT. Due to the tools available to me, my solution has to use XSLT version 1.0. For example. <?xml version="1.0"?> <ROWSET> <ROW> <CUSTOMER_ID>0</CUSTOMER_ID> <NAME>Default Company</NAME> <BONUSES> <BONUSES_ROW> <BONUS_ID>21</BONUS_ID> <DESCRIPTION>Performance Bonus</DESCRIPTION> </BONUSES_ROW> <BONUSES_ROW> <BONUS_ID>26</BONUS_ID> <DESCRIPTION>Special Bonus</DESCRIPTION> </BONUSES_ROW> </BONUSES> </ROW> <ROW> <CUSTOMER_ID>1</CUSTOMER_ID> <NAME>Dealer 1</NAME> <BONUSES> <BONUSES_ROW> <BONUS_ID>27</BONUS_ID> <DESCRIPTION>June Bonus</DESCRIPTION> <BONUS_VALUES> <BONUS_VALUES_ROW> <VALUE>10</VALUE> <PERCENT>N</PERCENT> </BONUS_VALUES_ROW> <BONUS_VALUES_ROW> <VALUE>11</VALUE> <PERCENT>Y</PERCENT> </BONUS_VALUES_ROW> </BONUS_VALUES> </BONUSES_ROW> </BONUSES> </ROW> <ROWSET> needs to becomes.... 0, Default Company 21, Performance Bonus 26, Special Bonus 1, Dealer 1 27, June Bonus 10, N 11, Y The XSLT I've written so far is... <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text" encoding="iso-8859-1"/> <xsl:strip-space elements="*" /> <xsl:template match="/*/child::*"> <xsl:apply-templates select="*"/> </xsl:template> <xsl:template match="*"> <xsl:value-of select="text()" /> <xsl:if test="position()!= last()"><xsl:text>,</xsl:text></xsl:if> <xsl:if test="position()= last()"><xsl:text>&#xD;</xsl:text></xsl:if> <xsl:apply-templates select="./child::*"/> </xsl:template> </xsl:stylesheet> but my output just isn't correct, with gaps and unnecessary data. 0,Default Company, ,21,Performance Bonus 26,Special Bonus 1,Dealer 1, 27,June Bonus, ,10,N 11,Y It seems there needs to be a check as whether or not a node can contain text, but I'm stuck and could do with an XSLT expert's help.

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  • How do I create Variables in XSLT that are not document fragments?

    - by chiborg
    Consider the following XSLT template <xsl:template match="/"> <xsl:variable name="var1"> <elem>1</elem> <elem>2</elem> <elem>3</elem> </xsl:variable> <xsl:text>var1 has </xsl:text> <xsl:value-of select="count($var1)"/> <xsl:text>elements. </xsl:text> <xsl:variable name="var2" select="$var1/elem[. != '2']"/> <xsl:text>var2 has </xsl:text> <xsl:value-of select="count($var2)"/> <xsl:text>elements. </xsl:text> </xsl:template> The output of this template is var1 has 1 elements var2 has 2 elements The first line outputs 1 (and not, as I first expected 3) because var1 is a document fragment that contains the <elem> elements as childen. Now for my questions: How can I create a variable that does not contain a document fragment? I could do it like I did with var2, only leaving out the predicate. But maybe there is a way without using a second variable. Or, as an alternative: How can I preserve the document fragment in a variable while filtering out some elements?

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  • XSLT: replace an integer by a string

    - by binogure
    I have a little problem. A node in my XML may contains and integer, and i have to replace this integer by a string. Each number match with a string. For example i have: Integer - String 1 - TODO 2 - IN PROGRESS 3 - DONE 4 - ERROR 5 - ABORTED Original XML: <root> <status>1</status> </root> Converted XML: <root> <status>TODO</status> </root> So i want replace 1 by "TODO", 2 by "IN PROGRESS" ... <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/root/status"> <root> <status> <xsl:variable name="text" select="." /> <xsl:choose> <xsl:when test="contains($text, '1')"> <xsl:value-of select="'TODO'"/> </xsl:when> <xsl:otherwise> <xsl:value-of select="$text"/> </xsl:otherwise> </xsl:choose> </status></root> </xsl:template> </xsl:stylesheet> I'am asking if there is another way to do that.

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  • Using xsl:key to store result of boolean expression

    - by hielsnoppe
    In my transformation there is an expression some elements are repeatedly tested against. To reduce redundancy I'd like to encapsulate this in an xsl:key like this (not working): <xsl:key name="td-is-empty" match="td" use="not(./node()[normalize-space(.) or ./node()])" /> The expected behaviour is the key to yield a boolean value of true in case the expression is evaluated successfully and otherwise false. Then I'd like to use it as follows: <xsl:template match="td[not(key('td-is-empty', .))]" /> Is this possible and in case yes, how?

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  • XSL: Dead or not dead

    - by Seattle Leonard
    I'm currently taking on a new project at home. In this project I'm going to be generating HTML emails. For this purpose, I believe XSL to be a good candidate. However, I have heard people say that XSL is a dead language, and if it's not that it is on it's way out. In fact, MS has been very leary to support XSL 2.0. Personally I feel that any time you are going from text to text, it is a great tool. Such as: Generating HTML e-mails Creating Open Office Docs Generating another XML doc What are your thoughts? Is it dead, or is it still a viable, usefull tool?

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  • Using a variable name in XMLHttpRequest

    - by Paul
    Hi All, I am using jQuery and trying to load a variable in place of a named xml file. My Code: $(document).ready(function() { // bind 'myForm' and provide a simple callback function $('#theForm').ajaxForm(function(responseXML2) { var myxml = responseXML2; alert(responseXML2); displayResult(); }); }); function loadXMLDoc(dname) { if (window.XMLHttpRequest) { alert("loading xmlhttprequest"); xhttp=new XMLHttpRequest(); } else { alert("loading activeX"); xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } alert("bottom load"); xhttp.open("GET",dname,false); xhttp.send(); return xhttp.responseXML; } function displayResult() { alert("setting vars"); alert("displayResult called"); //xml=loadXMLDoc(responseXML2); //tried this and the line below, among others xml=responseXML2; alert("xmlDocLoaded"); xsl=loadXMLDoc("xslt-test.xsl"); alert("XSLloaded"); // code for IE if (window.ActiveXObject) { alert("IE"); ex=xml.transformNode(xsl); document.getElementById("ieiresponse").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { alert("notIE"); xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("ieiresponse").appendChild(resultDocument); } } In the code above I want to have: //xml=loadXMLDoc(responseXML2); //tried this and the line below, among others xml=responseXML2; instead of a named file: xsl=loadXMLDoc("example.xml"); When I run through the code, it works if I name the file, but when I use the variable, (which does show up in alerts, so is being pulled), it stops the code at the above line (placing the variable as the xml file) Any help would be much appreciated! Thank you in advance.

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  • XSL - Unknown Error in FF media:content/@url

    - by danit
    I keep getting "Unknow Error occurred" when i try this in my XSLT: <table class="TEDtalks"> <xsl:for-each select="/rss/channel/item"> <tr> <td><xsl:value-of select="title"/></td> <td> <xsl:value-of select="media:content/@url" /> </td> </tr> </xsl:for-each> </table> The XML <rss> <channel> <item> <title>TEDTalks : Karen Armstrong: Let's revive the Golden Rule - Karen Armstrong (2009)</title> <itunes:author>Karen Armstrong</itunes:author> <description>Weeks from the Charter for Compassion launch, Karen Armstrong looks at religion's role in the 21st century: Will its dogmas divide us? Or will it unite us for common good? She reviews the catalysts that can drive the world's faiths to rediscover the Golden Rule.&lt;img src="http://feeds.feedburner.com/~r/TEDTalks_video/~4/th6FBgvV22o" height="1" width="1"/&gt;</description> <itunes:subtitle>Karen Armstrong: Let's revive the Golden Rule</itunes:subtitle> <itunes:summary><![CDATA[Weeks from the Charter for Compassion launch, Karen Armstrong looks at religion's role in the 21st century: Will its dogmas divide us? Or will it unite us for common good? She reviews the catalysts that can drive the world's faiths to rediscover the Golden Rule.]]></itunes:summary> <link>http://feedproxy.google.com/~r/TEDTalks_video/~3/th6FBgvV22o/647</link> <guid isPermaLink="false">http://video.ted.com/talks/podcast/KarenArmstrong_2009G.mp4</guid> <pubDate>Tue, 29 Sep 2009 12:46:00 -0500</pubDate> <category>Higher Education</category> <itunes:explicit>no</itunes:explicit> <itunes:duration>00:09:54</itunes:duration> <itunes:keywords>TED</itunes:keywords> <media:content url="http://feedproxy.google.com/~r/TEDTalks_video/~5/XT8k_DqlzGc/KarenArmstrong_2009G.mp4" fileSize="33726021" type="video/mp4" />

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  • Mapping Repeating Sequence Groups in BizTalk

    - by Paul Petrov
    Repeating sequence groups can often be seen in real life XML documents. It happens when certain sequence of elements repeats in the instance document. Here’s fairly abstract example of schema definition that contains sequence group: <xs:schemaxmlns:b="http://schemas.microsoft.com/BizTalk/2003"            xmlns:xs="http://www.w3.org/2001/XMLSchema"            xmlns="NS-Schema1"            targetNamespace="NS-Schema1" >  <xs:elementname="RepeatingSequenceGroups">     <xs:complexType>       <xs:sequencemaxOccurs="1"minOccurs="0">         <xs:sequencemaxOccurs="unbounded">           <xs:elementname="A"type="xs:string" />           <xs:elementname="B"type="xs:string" />           <xs:elementname="C"type="xs:string"minOccurs="0" />         </xs:sequence>       </xs:sequence>     </xs:complexType>  </xs:element> </xs:schema> And here’s corresponding XML instance document: <ns0:RepeatingSequenceGroupsxmlns:ns0="NS-Schema1">  <A>A1</A>  <B>B1</B>  <C>C1</C>  <A>A2</A>  <B>B2</B>  <A>A3</A>  <B>B3</B>  <C>C3</C> </ns0:RepeatingSequenceGroups> As you can see elements A, B, and C are children of anonymous xs:sequence element which in turn can be repeated N times. Let’s say we need do simple mapping to the schema with similar structure but with different element names: <ns0:Destinationxmlns:ns0="NS-Schema2">  <Alpha>A1</Alpha>  <Beta>B1</Beta>  <Gamma>C1</Gamma>  <Alpha>A2</Alpha>  <Beta>B2</Beta>  <Gamma>C2</Gamma> </ns0:Destination> The basic map for such typical task would look pretty straightforward: If we test this map without any modification it will produce following result: <ns0:Destinationxmlns:ns0="NS-Schema2">  <Alpha>A1</Alpha>  <Alpha>A2</Alpha>  <Alpha>A3</Alpha>  <Beta>B1</Beta>  <Beta>B2</Beta>  <Beta>B3</Beta>  <Gamma>C1</Gamma>  <Gamma>C3</Gamma> </ns0:Destination> The original order of the elements inside sequence is lost and that’s not what we want. Default behavior of the BizTalk 2009 and 2010 Map Editor is to generate compatible map with older versions that did not have ability to preserve sequence order. To enable this feature simply open map file (*.btm) in text/xml editor and find attribute PreserveSequenceOrder of the root <mapsource> element. Set its value to Yes and re-test the map: <ns0:Destinationxmlns:ns0="NS-Schema2">  <Alpha>A1</Alpha>  <Beta>B1</Beta>  <Gamma>C1</Gamma>  <Alpha>A2</Alpha>  <Beta>B2</Beta>  <Alpha>A3</Alpha>  <Beta>B3</Beta>  <Gamma>C3</Gamma> </ns0:Destination> The result is as expected – all corresponding elements are in the same order as in the source document. Under the hood it is achieved by using one common xsl:for-each statement that pulls all elements in original order (rather than using individual for-each statement per element name in default mode) and xsl:if statements to test current element in the loop:  <xsl:templatematch="/s0:RepeatingSequenceGroups">     <ns0:Destination>       <xsl:for-eachselect="A|B|C">         <xsl:iftest="local-name()='A'">           <Alpha>             <xsl:value-ofselect="./text()" />           </Alpha>         </xsl:if>         <xsl:iftest="local-name()='B'">           <Beta>             <xsl:value-ofselect="./text()" />           </Beta>         </xsl:if>         <xsl:iftest="local-name()='C'">           <Gamma>             <xsl:value-ofselect="./text()" />           </Gamma>         </xsl:if>       </xsl:for-each>     </ns0:Destination>  </xsl:template> BizTalk Map editor became smarter so learn and use this lesser known feature of XSLT 2.0 in your maps and XSL stylesheets.

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  • Recursive XML through XSLT to XML

    - by Patrick
    Essentially, I have XML structured like this: <A> <B> <1>data</1> <2>data</2> <C> <1>data</1> <2>data</2> <B> <1>data</1> <2>data</2> <C> <B> <1>data</1> <2>data</2> </B> </C> </B> <B> <1>data</1> <2>data</2> </B> </C> </B> </A> I am trying to get the output to look like this: <A> <B 1="data" 2="data"> <C 1="data" 2="data"> <B 1="data" 2="data"> <C> <B 1="data" 2="data" > </B> </C> </B> <B 1="data" 2="data" > </B> </C> </B> </A> I have figured out how to put everything as attributes and start looping through the elements. The issue I am facing is that when trying to get below the first C, nothing happens. Here is my code: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="xml" indent="yes"/> <xsl:template match="/"> <MenuDataResult> <B> <xsl:apply-templates /> </B> </MenuDataResult> </xsl:template> <xsl:template match="B"> <xsl:for-each select="B"> <B ItemID="{B/ItemID/text()}" ItemType="{ItemType/text()}" ItemSubType="{ItemSubType/text()}" ItemTitle="{ItemTitle/text()}" ItemImage="{ItemImage/text()}" ItemImageOverride="{ItemImageOverride/text()}" ItemLink="{ItemLink/text()}" ItemTarget="{ItemTarget/text()}>"> <xsl:for-each select="C"> <xsl:apply-templates select="C"/> </xsl:for-each> </B> </xsl:for-each> </xsl:template> <xsl:template match="C"> <C ID="{ID/text()}" Title="{Title/text()}" Template="{Template/text()}" Type="{Type/text()}" Link="{Link/text()}" ParentID="{ParentID/text()}" AncestorID="{AncestorID/text()}" FolderID="{FolderID/text()}" Description="{Description/text()}" Image="{Image/text()}" ImageOverride="{ImageOverride/text()}"> <xsl:for-each select="B"> <xsl:apply-templates select=".//B"/> </xsl:for-each> </C> </xsl:template> </xsl:stylesheet>

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  • Issue with undefined namespace

    - by SoBeK
    "xmlns="VL01" Seems to be causing the style-sheet to fail(works fine if removed), do no know how to address it the style-sheet. I feel like this is basic XLST 101 but I am having a hard time wrapping my brain around it. Any assisting would be greatly appreciated. Cheers XML <?xml version="1.0" encoding="utf-8"?> <Report xsi:schemaLocation="VL01 http://site.com/ReportServer?%2FVMS%20Reports%2FVL01&amp;rs%3ACommand=Render&amp;rs%3AFormat=XML&amp;rs%3ASessionID=lk44ff55z5q3ck3b5pfuxo45&amp;rc%3ASchema=True" Name="VL01" textbox41="VL01 - Checklist Report&#xD;&#xA;" textbox1946=" 2) Target Element&#xD;&#xA;     Target Element List&#xD;&#xA;        Windows 7&#xD;&#xA;3) Report Options&#xD;&#xA; xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="VL01"> <list2> <Item_Collection> <Item /> </Item_Collection> </list2> <list1> <list1_Details_Group_Collection> <list1_Details_Group Key="V0001070" EffectiveDate="04 Mar 1998 16:03:47:000" LongName2="Name..."/> </list1_Details_Group_Collection> </list1> </Report> XSL <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <xsl:output method="xml" version="4.0" indent="yes"/> <xsl:variable name="var-checklist_name"> <xsl:value-of select="substring-after(substring-before(translate(Report/@textbox1946, '&#xD;&#xA;', ''),'3)'),'Target&#x00A0;Element&#x00A0;List')"/> </xsl:variable><xsl:template match="/"> <html> <body> <table> <xsl:apply-templates select="Report/list1/list1_Details_Group_Collection"/> </table> </body> </html> </xsl:template> <xsl:template match="Report/list1/list1_Details_Group_Collection"> <xsl:for-each select="list1_Details_Group"> <Import_List> <Checklist_Name> <xsl:value-of select="normalize-space(translate($var-checklist_name, '&#x00A0;', ' '))"/> </Checklist_Name> <Vuln_ID><xsl:value-of select="number(substring-after(@VulKey,'V'))"/></Vuln_ID> <Short_Name><xsl:value-of select="substring(@LongName2,1,255)"/></Short_Name> <Release_Date><xsl:value-of select="substring(@EffectiveDate,1,11)"/></Release_Date> </Import_List> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • NFOP performance problem

    - by Jay Stevens
    We're using NFOP in a project (C#, ASP.NET 2.0) to ultimately return PDF files to the user. The process currently goes like this: Stored Procedure - XML XML - XSLT - XSL-FO XSL-FO - NFOP - PDF This works fine, the PDF is generated BEAUTIFULLY. The problem is that it takes 300+ seconds to do it. The ANTS profiler indicates that the problem is sitting in the driver.run() method inside of NFOP. It's not like this is a gargantuan amount of data, the size of the xsl-fo source going into the nfop driver object is ~980k. What's the most likely source and resolution of this problem? ANY hints or tips or answers are most appreciated, we were supposed to head to VA scan at 11 am. :|

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  • Dynamically generate XPath expression using XML data

    - by iHeartGreek
    Hi! I would like to dynamically create XPath expressions in an XSL determined by data in an XML file. (i.e. the XML data is "concatenated" to create an XPath expression). Example of XML data: AAA BBB CCC Example of how I would like the XPath expression to look like: //AAA | //BBB | //CCC And this dynamic generation needs to be done in an XSL file. I am fairly new to XSL (and family) and would appreciate some general direction on how to tackle this problem. Thanks!

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