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  • How to import classes into other classes within the same file in Python

    - by Chris
    I have the file below and it is part of a django project called projectmanager, this file is projectmanager/projects/models.py . Whenever I use the python interpreter to import a Project just to test the functionality i get a name error for line 8 that FileRepo() cannot be found. How Can I import these classes correctly? Ideally what I am looking for is each Project to contain multiple FileRepos which each contain and unknown number of files. Thanks for any assistance in advance. #imports from django.db import models from django.contrib import admin #Project is responsible for ensuring that each project contains all of the folders and file storage #mechanisms a project needs, as well as a unique CCL# class Project(models.Model): ccl = models.CharField(max_length=30) Techpacks = FileRepo() COAS = FileRepo() Shippingdocs = FileRepo() POchemspecs = FileRepo() Internalpos = FileRepo() Finalreports = FileRepo() Batchrecords = FileRepo() RFPS = FileRepo() Businessdev = FileRepo() QA = FileRepo() Updates = FileRepo() def __unicode__(self): return self.ccl #ProjectFile is the file object used by each FileRepo component class ProjectFile(models.Model): file = models.FileField(uploadto='ProjectFiles') def __unicode__(self): return self.file #FileRepo is the model for the "folders" to be used in a Project class FileRepo(models.Model): typeOf = models.CharField(max_length=30) files = models.ManyToManyField(ProjectFile) def __unicode__(self): return self.typeOf

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  • FCGI htaccess handler

    - by sharvey
    I'm trying to setup django on a shared hosting provider. I followed the instructions on http://helpdesk.bluehost.com/index.php/kb/article/000531 and almost have it working. The problem I'm facing now is that the traffic is properly routed throught the fcgi file, but the file itself shows up as plain text in the browser. If I run ./mysite.fcgi in the ssh shell, I do get the default django welcome page. my .htaccess is: AddHandler fastcgi-script .fcgi RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ mysite.fcgi/$1 [QSA,L] and mysite.fcgi: #!/usr/bin/python2.6 import sys, os os.environ['DJANGO_SETTINGS_MODULE'] = "icm.settings" from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") thanks.

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  • Is it bad practice to extend the MongoEngine User document?

    - by Soviut
    I'm integrating MongoDB using MongoEngine. It provides auth and session support that a standard pymongo setup would lack. In regular django auth, it's considered bad practice to extend the User model since there's no guarantee it will be used correctly everywhere. Is this the case with mongoengine.django.auth? If it is considered bad practice, what is the best way to attach a separate user profile? Django has mechanisms for specifying an AUTH_PROFILE_MODULE. Is this supported in MongoEngine as well, or should I be manually doing the lookup?

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  • Decorator for determining HTTP response from a view

    - by polera
    I want to create a decorator that will allow me to return a raw or "string" representation of a view if a GET parameter "raw" equals "1". The concept works, but I'm stuck on how to pass context to my renderer. Here's what I have so far: from django.shortcuts import render_to_response from django.http import HttpResponse from django.template.loader import render_to_string def raw_response(template): def wrap(view): def response(request,*args,**kwargs): if request.method == "GET": try: if request.GET['raw'] == "1": render = HttpResponse(render_to_string(template,{}),content_type="text/plain") return render except Exception: render = render_to_response(template,{}) return render return response return wrap Currently, the {} is there just as a place holder. Ultimately, I'd like to be able to pass a dict like this: @raw_response('my_template_name.html') def view_name(request): render({"x":42}) Any assistance is appreciated.

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  • Encoding gives "'ascii' codec can't encode character … ordinal not in range(128)"

    - by user140314
    I am working through the Django RSS reader project here. The RSS feed will read something like "OKLAHOMA CITY (AP) — James Harden let". The RSS feed's encoding reads encoding="UTF-8" so I believe I am passing utf-8 to markdown in the code snippet below. The em dash is where it chokes. I get the Django error of "'ascii' codec can't encode character u'\u2014' in position 109: ordinal not in range(128)" which is an UnicodeEncodeError. In the variables being passed I see "OKLAHOMA CITY (AP) \u2014 James Harden". The code line that is not working is: content = content.encode(parsed_feed.encoding, "xmlcharrefreplace") I am using markdown 2.0, django 1.1, and python 2.4. What is the magic sequence of encoding and decoding that I need to do to make this work? Thanks.

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  • How can I tell Phusion Passenger which python to use?

    - by Mike
    I'm using Phusion Passenger with a ruby app and I'd also like to set it up to work with an django appengine app I'm working on. Googling for "passenger_wsgi.py" I was able to get the following very simple non-django app working on passenger: passenger_wsgi.py: def application(environ, start_response): response_headers = [('Content-type','text/plain')] start_response('200 OK', response_headers) return ['Hello World!\n'] However, if I add the line import django.core.handlers.wsgi into the mix, I get 'An error occurred importing your passenger_wsgi.py'. By printing out the sys.path I've discovered that at least part of the reason is because Passenger is using the wrong python installation on my machine. How can I configure Passenger (on apache) to use /opt/local/bin/python2.5 instead of the system default python?

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  • How to pass json via a form element

    - by becomingGuru
    I have this swf (flash) file that provides the json that needs to be sent to the server. I wrote a very simple jQuery: function submitForm(swf_json) { $('#swfjson').val(swf_json); #swfjson is an input of type hidden $('#titleForm').submit(); } and the swf will call the submitForm above and I receive the request.POST in django as usual. But, django is interpreting the swf_json as a string "Object object" >>>type(request.POST['swfjson']) <type 'unicode'> Of course I can pass the json as a string to the view function. Doesn't seem good to me. Any other way of passing the json object to the django view?

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  • How to make Dajax callback into scoped object

    - by BozoJoe
    I cant seem to find a way to make django-dajaxice have its callback inside same scoped object from which made the initial call. MyViewport = Ext.extend(MyViewportUi, { initComponent: function() { MyViewport.superclass.initComponent.call(this); }, LoadRecordsCallback: function(data){ if(data!='DAJAXICE_EXCEPTION') { alert(data); } else { alert('DAJAXICE_EXCEPTION'); } }, LoadRecords: function(){ Dajaxice.Console.GetUserRecords(this.LoadRecordsCallback); } }); var blah = new MyViewport(); blah.LoadRecords(); I'm on django, and like the calling syntax to django-dajaxice. I'm using Extjs 3.2 and tried passing a Ext.createCallback but Dajax's returning eval seems to only want a string for the callback.

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  • Error 1005 when adding a foreign key constraint on mysql table

    - by luc
    Hello, I have a problem when upgrading a django and mysql app with south. I've tried to make a sql-based upgrade with the code generated by the django sqlall command and I have a similar problem. Here is the sql code: CREATE TABLE `programmations_basissupport` ( `id` integer AUTO_INCREMENT NOT NULL PRIMARY KEY, `value` numeric(6, 0) NOT NULL ) ALTER TABLE `programmations_concert` ADD `basis_support_id` integer AFTER program_status_id; ALTER TABLE `programmations_concert` ADD CONSTRAINT `basis_support_id_refs_id_1e4ed8d7` FOREIGN KEY (`basis_support_id`) REFERENCES `programmations_basissupport` (`id`); An error is raised when adding the FK constraint: ERROR 1005 (HY000): Can't create table 'apidev_mnl.#sql-106e_632b00a' (errno: 150) Does anybody have an idea? Update: DEFAULT values where missing but even if I add the default='' in the django model, the creation of foreign keys fails. Thanks for your help

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  • Aptana Studio is opening but not ever closing a python.exe process

    - by SC Ghost
    I am developing a small testing website using Django 1.2 in Aptana Studio build 2.0.4.1268158907. I have a Django project that I test by running the command "runserver 8001" on my project. This command runs the project on a small server that comes with Django. However the problem arises that every time I run this command Aptana opens two instances of the process "python.exe". Upon terminating the command only one of these instances is ended. The other process continues to run and use memory. My server is not online, and the process doesn't seem to do anything that I can find. This happens every time i run the runserver command on my project and therefore more and more python.exe instances will open up through my development period. Any help discovering either the purpose of this extra python.exe or a way to prevent it from opening would be much appreciated.

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  • Presentation software requires admin rights to install - any way to remove this requirement?

    - by James F
    I have some wireless presentation software which I use in a meeting room in order to allow end users to hold presentations here and wirelessly have their laptop screens showing on the TV on the wall. Unfortunately the .exe file requires admin rights to install therefore requiring that either the user requests temporary admin rights beforehand, I install it using my admin account or that we use a VGA/HDMI cable. Is there a way to remove the admin right requirement from a .exe or a .msi file so that it can be installed freely by any user? We are using XP for now but will be moving to 7 soon. Thanks James

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  • How do I access admin shares on windows 2008 r2?

    - by Jim Geurts
    I am not able to access admin file shares on a Windows 2008 R2 box, if I'm logged in as a user who is part of the Administrators group. The only way I can access those shares is if I use the built in Administrator account. How can I configure the server to allow any administrator to access the file system via admin shares? Btw, this works with Windows 2003. By admin shares, I refer to: \192.168.1.4\c$ or \192.168.1.4\e$

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  • Utility to grant admin rights to a user in Windows XP for few hours/days?

    - by user15660
    I have two accounts on my windows xp home desktop. The default regular user is used for everything and the 2nd user which has admin rights is used only for installations. I do this to avoid malware infestations during web browsing and limited user account is guarding against online threats to a good extend but many programs refuse to run under limited rights like revo uninstaller. many installs i run from limited user by selectin "run as" from right click context menu of the .exe file. but some apps need admin rights for certain. I use "switch user" to go to admin mode and do the install/uninstall. but the admin user has none of my preferences bookmarks setup nor has my locate32 indexing done and ready for fast search Is there a utility which I can use "run as" login in administration login and use that to grant my limited user admin rights for a limited amount of period like few hours or days? Please help. I guess MS might have closed many doors of it for fear of exploitation of the API. are there any?

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  • Does admin=true and root has the same privileges on AIX?

    - by Boaz Tirosh
    Does a user in /etc/security/user with the parameter admin set to true (admin = true) has the same privileges as the root user? According to IBM (full information here): admin Defines the administrative status of the user. Possible values are: true The user is an administrator. Only the root user can change the attributes of users defined as administrators. false The user is not an administrator. This is the default value. Is there another type of user, or are admin and root the same?

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  • What do the "ALL"s in the line " %admin ALL=(ALL) ALL " in Ubuntu's /etc/sudoers file stand for?

    - by sri
    What does each ALL mean? I understand that the whole line indicates that the admin group members get admininstartive privileges, but would like to know more info about the position of the ALLS and if they each refer to a different set of permissions or something like that? $sudo cat /etc/sudoers ... # User privilege Information root ALL=(ALL) ALL #... %sudo ALL=(ALL) ALL # #includedir /etc/sudoers.d #Members of the admin group may gain root privileges %admin ALL=(ALL) ALL # If it matters: OS: Ubuntu : 10.4

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  • Is it normal that Software installs in Admin user folder?

    - by RoToRa
    I've got a new computer with Windows 7, which I'm using for the first time. For security I decided to create a standard user for everyday work instead of using an admin account. However when I install programs logged in as the standard user (such as Aptana right now) they always try to install in the admin's user folder (C:\Users\Admin\AppData...). I'd expect the programs to install to the standard user's folder or Progran Files as in XP. This also leads to that I need to grant admin rights whenever I start such a program. Of course I could just change the installation path every time, but I find this behavior strange. Ist it normal, or did I somehow mess up the Windows 7 installation?

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  • What is the equivalent of domain admin on Sharepoint 2010?

    - by user54266
    I have to support Sharepoint on a daily basis but do not have the equivalent of domain access so I'm constantly having to ask the guy in charge of Sharepoint to add me to a new security group to complete my task. Rather than having to bug him all the time (he is only somewhat technical) it would be easier to simply have the equivalent of domain admin access for Sharepoint (I'm a sys admin and have domain admin access already but this doesn't seem to carry over to FOSS). What is the equivalent of domain admin access on Sharepoint 2010? Thanks in advance.

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  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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  • Servlet 3.1, Expression Language 3.0, Bean Validation 1.1, Admin Console Replay: Java EE 7 Launch Webinar Technical Breakouts on YouTube

    - by arungupta
    As stated previously (here, here, here, and here), the On-Demand Replay of Java EE 7 Launch Webinar is already available. You can watch the entire Strategy and Technical Keynote there, and all other Technical Breakout sessions as well. We are releasing the final set of Technical Breakout sessions on GlassFishVideos YouTube channel as well. In this series, we are releasing Servlet 3.1, Expression Language 3.0, Bean Validation 1.1, and Admin Console. Here's the Servlet 3.1 session: Here's the Expression Language 3.0 session: Here's the Bean Validation 1.1 session: And finally the Admin Console session: Enjoy watching all of them together in a consolidated playlist: And don't forget to download Java EE 7 SDK and try the numerous bundled samples.

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  • How to prevent the google users found my index of admin page?

    - by krish
    I am running a website but for some days i stopped it and put the under-construction page because the Index of admin page is visible to the outside world through the Google search. One of my friend told me that your websites index is visible and its one step away to access the password file and he shows me that very simply using the Google search. How can i prevent this and i am hosting my site with a hosting company and i report about this to them but they simply replied to me still its secure so you no need to worry... am i really don need to worry and continue my site with the visible index of admin page?

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  • How to prevent Google from finding my admin index page?

    - by krish
    I am running a website but for some days i stopped it and put the under-construction page because the Index of admin page is visible to the outside world through the Google search. One of my friend told me that your websites index is visible and its one step away to access the password file and he shows me that very simply using the Google search. How can i prevent this and i am hosting my site with a hosting company and i report about this to them but they simply replied to me still its secure so you no need to worry... am i really don need to worry and continue my site with the visible index of admin page?

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  • How to layer if statements when order of logic is irrelevant?

    - by jimmyjimmy
    Basically I have a series of logic in my website that can lead to 5 total outcomes. Basically two different if tests and then a catch all else statement. For example: if cond1: if mod1: #do things elif mod2: #do things elif cond2: if mod1: #do things elif mod2 #do things else: #do things I was thinking about rewriting it like this: if cond1 and mod1: #do things elif cond1 and mod2: #do things elif cond2 and mod1: #do things elif cond2 and mod2: #do things else: #do things Is there any real difference in these two coding options/a better choice for this kind of logic testing?

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  • How do I install OSQA with limited access to the server?

    - by Noir
    I would very much like to install OSQA on my host (provided/owned by my friend), but I can not make heads or tails of how I would go about doing it; a lot of the dependancies and such can't be installed with the current level of access (or most probably just knowledge) that I have. I can provide any further information required, and attempt to contact (friend) to see if he can do any of it for me, but I'm unsure as to how often I will be able to contact him. exec and shell_exec are not disabled on the server. If there are any other alternatives that I could use, please let me know! I tried Qwench but that was pretty buggy. I can usually deal with these kind of things, but this is my first foray into Python stuff!

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  • SugarCRM - how to make users see only child users?

    - by John
    Hello, I want to change the behaviour of Sugar CRM community version. Here's what sugar currently does: 1) Admin logs into Sugar. 2) Admin clicks on Admin tab. 3) Admin creates a new user named George with admin access 4) Under user information section, Admin makes George report to Admin (in the database, it will show users.report_to_id is the admin's user_id) 5) Admin saves and logs out 6) George logs in with his password 7) George goes to admin tab. 8) George goes to list users page and sees all users, including Admin, the person he is supposed to report to. I want to change step 8 such that George is not allowed to see the user he reports to. Additionally, he is not allowed to see his grand parent user, great grand parent user, great great grand parent user etc... George should only be able to see users that he creates. How can I achieve this? Is this even possible?

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