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  • php Dollar amount Regular Expression

    - by Thildemar
    I am have completed javascript validation of a form using Regular Expressions and am now working on redundant verification server-side using PHP. I have copied this regular expression from my jscript code that finds dollar values, and reformed it to a PHP friendly format: /\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/ Specifically: if (preg_match("/\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/", $_POST["cost"])){} While the expression works great in javascript I get : Warning: preg_match() [function.preg-match]: Compilation failed: nothing to repeat at offset 1 when I run it in PHP. Anyone have a clue why this error is coming up?

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  • will php/apache ever support multi threading?

    - by fayer
    i mainly focus on the web, i think i will never create desktop applications. so i think it's better for me to focus on typical web languages like php. i know an advantage java has over php is multi threading though. will php ever support this feature in the future? thanks

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  • How should I architect JasperReports with a PHP front+backend system

    - by Itay Moav
    Our system is written completely in PHP. For various business reasons (which are a given) I need to build the reports of the system using JasperReports. What architecture should I use? Should I put the Jasper as a stand alone server (if possible) and let the php query against it, should I have it generate the reports with a cron, and then let the PHP scoop up the files and send them to the web client/browser...

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  • Create function in python to find the highest of all function arguments, and return the "tag" of the value.

    - by gatechgrad
    Consider the following: p1=1; p2=5; p3=7; highest=max(p1,p2,p3). The max function would return 7. I am looking to create a similar function, which would return "p3". I have created a small function (by simple comparisons) for the above example, shown below. however I am having trouble when the number of arguments go up. def highest(p1,p2,p3) if (p1p2) and (p1p3): return "p1" if (p2p1) and (p2p3): return "p2" if (p3p1) and (p3p1): return "p3". Is there a simpler way to do this

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  • INSERT DELAYED on locked tables blocks PHP processes to continue

    - by sw0x2A
    Our webservers write some tracking information into a MySQL database (using INSERT DELAYED into MyISAM table). When a huge SELECT query is executed on this table or when it is locked for another reason, the webserver processes (with INSERT DELAYED) are waiting for the database and in some cases the MaxServer limit is reached in Apaches, so they will stop serving requests. We use INSERT DELAYED because The DELAYED option for the INSERT statement is a MySQL extension to standard SQL that is very useful if you have clients that cannot or need not wait for the INSERT to complete. This is a common situation when you use MySQL for logging and you also periodically run SELECT and UPDATE statements that take a long time to complete. Quote from MySQL documentation. I am wondering why the Apache processes are waiting for the INSERT DELAYED to finish. And what can I do to just send the data and forget about it. (Since this is logging data, I do not care if we lose some entries.) Even when the table is locked the PHP script should just go on and should not wait for an answer of MySQL. (We do not want to setup Master-slave for this table but we are thinking about move this data to some NoSQL database. But for now I would like to know why INSERT DELAYED is not working as expected.)

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  • Jquery Javascript function, simple error, can't find it!

    - by CodingIsAwesome
    When my page loads it calls the function like below: <body onLoad='changeTDNodes()'> And the code it calls is below: enter code here <script src='jquery-1.4.2.min.js' type='text/javascript'></script> <script> function changeTDNodes() { var threshValue = 10; $(".threshold").each(function(elem) { if($("b",elem).innerText > threshValue) { elem.addClass("overThreshold"); } }); }); } I have the class setup correctly in CSS .overThreshold { td{font-size:72px;} th{font-size:72px;} } But no classes are being changed, whats going on? Thanks for all your help!

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  • PHP echo query result in Class??

    - by Jerry
    Hi all I have a question about PHP Class. I am trying to get the result from Mysql via PHP. I would like to know if the best practice is to display the result inside the Class or store the result and handle it in html. For example, display result inside the Class class Schedule { public $currentWeek; function teamQuery($currentWeek){ $this->currentWeek=$currentWeek; } function getSchedule(){ $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } $scheduleQuery=mysql_query("SELECT guest, home, time, winner, pickEnable FROM $this->currentWeek ORDER BY time", $connection); if (!$scheduleQuery){ die("database has errors: ".mysql_error()); } while($row=mysql_fetch_array($scheduleQuery, MYSQL_NUMS)){ //display the result..ex: echo $row['winner']; } mysql_close($scheduleQuery); //no returns } } Or return the query result as a variable and handle in php class Schedule { public $currentWeek; function teamQuery($currentWeek){ $this->currentWeek=$currentWeek; } function getSchedule(){ $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } $scheduleQuery=mysql_query("SELECT guest, home, time, winner, pickEnable FROM $this->currentWeek ORDER BY time", $connection); if (!$scheduleQuery){ die("database has errors: ".mysql_error()); // create an array } $ret = array(); while($row=mysql_fetch_array($scheduleQuery, MYSQL_NUMS)){ $ret[]=$row; } mysql_close($scheduleQuery); return $ret; // and handle the return value in php } } Two things here: I found that returned variable in php is a little bit complex to play with since it is two dimension array. I am not sure what the best practice is and would like to ask you experts opinions. Every time I create a new method, I have to recreate the $connection variable: see below $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } It seems like redundant to me. Can I only do it once instead of calling it anytime I need a query? I am new to php class. hope you guys can help me. thanks.

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  • Hide URL of PHP page

    - by manoj singhal
    I want to hide the URL of my PHP page; that is, I don't want to write /register.php directly in the href tag, I want to write /register/ and have it open the register.php page directly. I want to do that for all the webpages.

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  • PHP if statement - select two different get variables?

    - by arsoneffect
    Below is my example script: <li><a <?php if ($_GET['page']=='photos' && $_GET['view']!=="projects"||!=="forsale") { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos\""); } ?>>Photos</a></li> <li><a <?php if ($_GET['view']=='projects') { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos&view=projects\""); } ?>>Projects</a></li> <li><a <?php if ($_GET['view']=='forsale') { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos&view=forsale\""); } ?>>For Sale</a></li> I want the PHP to echo the "href="#" class="active" only when it is not on the two pages: ?page=photos&view=forsale or ?page=photos&view=projects

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  • PHP language specification ?

    - by Rolf
    Hi, as I know there is an official document for Java (JLS), I'd like to know if it's also the case of PHP language. I found the "Language Reference" section on the PHP manual, but it doesn't look as detailed as the JLS. The thing is I have a good practical knowledge of PHP but I'm miserably clueless about what REALLY happens under the hood. If there isn't any official document, could you recommend me some good books to read ? Thanks in advance ! Rolf

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  • jQuery ajax request to php, how to return plain text only

    - by jyoseph
    I am making an ajax request to a php page and I cannot for the life of me get it to just return plain text. $.ajax({ type: 'GET', url: '/shipping/test.php', cache: false, dataType: 'text', data: myData, success: function(data){ console.log(data) } }); in test.php I am including this script to get UPS rates. I am then calling the function with $rate = ups($dest_zip,$service,$weight,$length,$width,$height); I am doing echo $rate; at the bottom of test.php. When viewed in a browser shows the rate, that's great. But when I request the page via ajax I get a bunch of XML. Pastie here: http://pastie.org/1416142 My question is, how do I get it so I can just return the plain text string from the ajax call, where the result data will be a number? Edit, here's what I see in Firebug- Response tab: HTML tab:

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  • How to overload shutdown function?

    - by Michal M
    I am using Kohana (v3) framework but I believe it's not tied to a particular framework. What I have is basically an app with a front-end, where I want to use Kohana's native Kohana::shutdown_handler(), but I also have a part of the - RESTful API - where I don't want colourful and html-encoded exception reporting. I want a plain text reporting. The way I thought it might work is to register another shutdown function in API's controller abstract class constructor, but then I realised register_shutdown_function() works differently to set_exception_handler() and instead of replacing it adds another function to the shutdown procedure. What's worse PHP doesn't allow "unregistering" shutdown functions and that's where my problem lies. What to do, if you want to use another shutdown function instead of one already registered?

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  • PHP post programmatically

    - by Tural Teyyuboglu
    After user registration, website send activation code to email. something like that. www.domain.com/?activate=<code> I'm creating 2 variants of activation: 1.manual 2.auto Lets say we have index.php. 1.Manual method. When someone wants to activate user manually all things are obvious: User opens page www.domain.com/?activate Index.php checks with following script and includes div file (which contains activation form) if (isset($_GET['activate'])) { $page='activate'; $divfile = 'path to div.php'; } include $divfile; Then page sends form data via ajax to activation.php file. 2.Auto method. Lets say user clicked directly to www.domain.com/?activate=<code>. What I wanna do is, to check if(!empty($_GET['activate'])), if all right ... I can't figure out how to act?! Programmatically send something like POST to activation.php or what? Please help. Thx in advance

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  • PHP & WP: Render Certain Markup Based on True False Condition

    - by rob
    So, I'm working on a site where on the top of certain pages I'd like to display a static graphic and on some pages I would like to display an scrolling banner. So far I set up the condition as follows: <?php $regBanner = true; $regBannerURL = get_bloginfo('stylesheet_directory'); //grabbing WP site URL ?> and in my markup: <div id="banner"> <?php if ($regBanner) { echo "<img src='" . $regBannerURL . "/style/images/main_site/home_page/mock_banner.jpg' />"; } else { echo 'Slider!'; } ?> </div><!-- end banner --> In my else statement, where I'm echoing 'Slider!' I would like to output the markup for my slider: <div id="slider"> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/1.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/2.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/3.jpg" alt="" /> ............. </div> My question is how can I throw the div and all those images into my else echo statement? I'm having trouble escaping the quotes and my slider markup isn't rendering.

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  • template function roundTo int, float -> truncation

    - by Oops
    Hi, according to this question: http://stackoverflow.com/questions/2833730/calling-template-function-without-type-inference the round function I will use in the future now looks like: template < typename TOut, typename TIn > TOut roundTo( TIn value ) { return static_cast<TOut>( value + 0.5 ); } double d = 1.54; int i = rountTo<int>(d); However it makes sense only if it will be used to round to integral datatypes like char, short, int, long, long long int, and it's unsigned counterparts. If it ever will be used with a TOut As float or long double it will deliver s***. double d = 1.54; float f = roundTo<float>(d); // aarrrgh now float is 2.04; I was thinking of a specified overload of the function but ... that's not possible... How would you solve this problem? many thanks in advance Oops

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  • Will php code exit after echo for ajax?

    - by Steve
    I am running a typical php-engined ajax webpage. I use echo to return a html string from the php code. My question is, if I have some other code after the echo, will those code get executed? Or echo behaves similar to exit, which immediately return and stop running the php code? Thanks.

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  • Never getting a JSON response when running server-side PHP proxy script but I do with others

    - by Dohk
    I'm on PHP 5.3.4 and Apache 2.2 btw So I'm using (or trying to use) Simple PHP Proxy (Simple PHP Proxy) I enter a URL at his example page at SPP Example Page and it works fine, I see the JSON response and all the headers. However, when I copy the exact URL, only changing the URL to now have localhost, I get both empty headers and no JSON. Assuming that the script on his site is the same I downloaded, could this be due to a multitude of things or a setting in Apache and/or the PHP ini? So for example: benalman.com/code/projects/php-simple-proxy/ba-simple-proxy.php?url=http://github.com/&full_headers=1&full_status=1 That will get me a ton of info back Now changing to localhost http://localhost/ba-simple-proxy.php?url=http://github.com/&full_headers=1&full_status=1 {"headers":[],"status":{"url":"https:\/\/github.com\/","content_type":"text\/html","http_code":301,"header_size":194,"request_size":182,"filetime":-1,"ssl_verify_result":0,"redirect_count":1,"total_time":0.094,"namelookup_time":0,"connect_time":0.047,"pretransfer_time":0,"size_upload":0,"size_download":185,"speed_download":1968,"speed_upload":0,"download_content_length":185,"upload_content_length":0,"starttransfer_time":0,"redirect_time":0.047,"certinfo":[]},"contents":null} I even went basic and just used some curl and of course, empty objects being returned other than false for my content and the url I set in my JSON. Any help is deeply appreciated or any ideas.

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  • Getting search results from Twitter in php

    - by Mark Mayo
    I'm attempting to put together a little mashup with some twitter APIs. However, the whole area is new to me (I'm more of an embedded developer dabbling). And frustratingly, every tutorial I am trying in Php is either out of date, not doing what it claims to do, it or is broken. Essentially, I just want a nice bit of example code - say, an HTML file, a connection.js for the JQuery magic, and a php file - 'getsearch' which contains the relevant Curl calls to the API to just return the results for a given search term. Followed the tutorial to the letter at http://www.reynoldsftw.com/2009/02/using-jquery-php-ajax-with-the-twitter-api/ and even downloaded the guy's code and chucked it on my webserver, but it just seems to sit there. I'm relatively competent at php and html, but it's the Curl and the JQuery side of things which is new to me, and would appreciate any thoughts, links, or code suggestions. I've attempted reading the API - but even that seems sparse - and several links are broken to their own tutorials, so that's put me off a bit for now.

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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • Success function not being called when form is submitted

    - by Tom Hartman
    Hi, I've been trying to figure out why the following script's success function isn't running. Everything in my form works perfectly, and the form contents are being emailed correctly, but the success function isn't being called. If anyone could review my code and let me know why my success function isn't being called I would very much appreciate it! Here is the HTML form with notification divs, which are hidden via css: <div id="success" class="notification"> <p>Thank you! Your message has been sent.</p> </div> <div id="failure" class="notification"> <p>Sorry, your message could not be sent.</p> </div> <form id="contact-form" method="post" action="" class="jqtransform"> <label for="name">Name:</label> <input name="name" id="name" type="text" class="validate[required] input" /> <label for="company">Company:</label> <input name="company" id="company" type="text" class="input" /> <label for="phone">Phone:</label> <input name="phone" id="phone" type="text" class="input" /> <label for="email">Email:</label> <input name="email" id="email" type="text" class="validate[required,email] input" /> <div class="sep"></div> <label for="subject">Subject:</label> <input name="subject" id="subject" type="text" class="validate[required] input" /> <div class="clear"></div> <label for="message">Message:</label> <textarea name="message" id="message" class="validate[required]"></textarea> <div id="check-services"> <input type="checkbox" name="services[]" value="Contractor Recommendation" /> <div>Contractor Recommendation</div> <input type="checkbox" name="services[]" value="Proposal Review" /> <div>Proposal Review</div> <input type="checkbox" name="services[]" value="Existing Website Review" /> <div>Existing Website Review</div> <input type="checkbox" name="services[]" value="Work Evaluation" /> <div>Work Evaluation</div> <input type="checkbox" name="services[]" value="Layman Translation" /> <div>Layman Translation</div> <input type="checkbox" name="services[]" value="Project Management" /> <div>Project Management</div> </div> <div class="sep"></div> <input name="submit" id="submit" type="submit" class="button" value="Send" /> <input name="reset" id="reset" type="reset" class="button" value="Clear" onclick="$.validationEngine.closePrompt('.formError',true)" /> </form> Here is the javascript: // CONTACT FORM VALIDATION AND SUBMISSION $(document).ready(function(){ $('#contact-form').validationEngine({ ajaxSubmit: true, ajaxSubmitFile: 'lib/mail.php', scroll: false, success: function(){ $('#success').slideDown(); }, failure: function(){ $('#failure').slideDown(); $('.formError').animate({ marginTop: '+30px' }); } }); }); And here is my PHP mailer script: <?php $name = $_POST['name']; $company = $_POST['company']; $phone = $_POST['phone']; $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; $services = $_POST['services']; $to = '[email protected]'; $subject = 'THC - Contact'; $content .= "You received a message from ".$name.".\r\n\n"; if ($company): $content .= "They work for ".$company.".\r\n\n"; endif; $content .= "Here's the message:\r\n\n".$message."\r\n\n"; $content .= "And they are interested in the services below:\r\n\n"; $content .= implode("\r\n",$services); if ($phone): $content .= "\r\n\nYou can reach them at ".$phone."."; else: $content .= "\r\n\nNo phone number was provided."; endif; $headers = "From: ".$name."\r\n"; $headers .= "Reply-To: ".$email."\r\n"; if (mail($to,$subject,$content,$headers)): return true; else: return false; endif; ?>

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