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  • Getting mysql syntax error and cant find source

    - by eGGzy
    I have function that updates log table. function wslog($userID, $log, $where) { safe_query("INSERT INTO ".PREFIX."log ( time, userID, log, where ) values( '".time()."', '".$userID."', '".$log."', '".$where."' ) "); } And I have this php code: wslog($userID, 'server|'.mysql_insert_id().'', 'servers'); But I keep getting syntax error: Query failed: errorno=1064 error=You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where ) values( '1269208030', '1', 'server|14', 'servers' )' at line 1 query=INSERT INTO ws_DII_log ( time, userID, log, where ) values( '1269208030', '1', 'server|14', 'servers' )

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  • header problem in php refresh

    - by basma
    hello i have this code : <?php session_start(); echo "".$_SESSION['eventnum'].""; $urlRefresh = "testremot.php"; header("Refresh: 5; URL=\"" . $urlRefresh . "\""); ?> but the header doesnt work and this warning appear when i try to run this code : Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\remot\testremot.php:3) in C:\xampp\htdocs\remot\testremot.php on line 5 can you please help me ?

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  • Absolute URL Path for PHP Website

    - by kakaajee
    Hi friends, I am working on a website in a CMS site. I have provided a link in my footer file e.g blogs.php. This page is at the root like "http://www.example.com/new_cms/blogs.php" When I moves to other files link like "http://www.example.com/new_cms/forums" the footer link is changed to "http://www.example.com/new_cms/forums/blogs.php" but the blogs.php page resides at path "http://www.example.com/new_cms/" . I tried different $_SERVER[] variables but got no luck to get the above path "http://www.example.com/new_cms/" means the server name with the directory where the project is currently running from. Any one have idea how to get it done will be a great help. Thanks

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  • PHP - Can you help change this function slightly?

    - by Joe
    I have the following function I modified based off someone elses function: function showCombinations($string, $nameString, $linkParts, $i){ $wordDivider = "/"; //the divider between the words/values if ($i >= count($linkParts)){ echo "<a href='".trim($string)."'>".trim($nameString)."</a>, "; } else { foreach ($linkParts[$i] as $currentTrait){ if ($currentTrait['name']=="urltext"){ $currentNameStringName=""; //ignore } else { $currentNameStringName=$currentTrait['name']; } if ($nameString!=""){ $currentNameString=$nameString." - ".$currentNameStringName; } else { $currentNameString=$nameString.$currentNameStringName; } showCombinations($string.$currentTrait['value'].$wordDivider, $currentNameString, $linkParts, $i + 1); } } } showCombinations('', '', $linkParts, 0); All I need to change this to do is, instead of "ECHO", I want it to build up the combination and so I can do: $result = showCombinations('', '', $linkParts, 0); echo $result; I need it this way because I have to modify that $result, not just echo it.

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  • How to transition from PHP to Python Django?

    - by ggfan
    Here's my background: Decent experience with PHP/MySql. Beginner's experience with OOP Why I want to learn Python Django? I gave in, based on many searches on SO and reading over some of the answers, Python is a great, clean, and structured language to learn. And with the framework Django, it's easier to write codes that are shorter than with PHP Questions Can i do everything in Django as in PHP? Is Django a "big" hit in web development as PHP? I know Python is a great general-purpose language but I'm focused on web development and would like to know how Django ranks in terms of web development.

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  • javascript function object's inheritFrom method

    - by gawpertron
    I've come across this.inheritFrom that enables you to inherit from a super class. var superClass = function() { this.foo = 'foo'; this.bar = 'bar'; } var subClass = function() { this.inheritFrom = superClass; this.inheritFrom(); this.myFunction = function() { return this.foo; }; } I've looked in Mozilla and MSDN, but I can't seem to find it documented any where. As far as I can see it works in IE6 and Firefox 3. Any reason why it wouldn't be documented?

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  • PHP+MYSQL Server Config

    - by Matias
    Hi guys, I am parsing an XML file with PHP and inserting the rows in a MYSQL database. I am using PHP simplexml_load_files to load the XML and a foreach to loop through the array and insert the rows into my database. It works perfectly fine with small files i am testing, but it comes to reality I need to parse a large 500mb XML file and nothing happens. I was wondering what was the right Php.ini config for this case ? I have a VPS Linux Cent OS, with 256 mb of dedicated Memory and MYSQL 5.0.5. I have also set php memory_limit = 256M (maximum of my server) Any suggestions, similar experiences will be greatly appreciated Thanks

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  • php include not working on IE?

    - by janoChen
    This include is not working in IE: <?php include_once 'localization.php'; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <title>Global Colleague</title> <link href="css/style.css" rel="stylesheet" type="text/css"/><!--Start Kampyle Exit-Popup Code--> <script type="text/javascript"> Calling an array inside localization.php <?php echo l('content_p3'); ?>

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  • Access PHP var from external javascript file

    - by FFish
    I can access a PHP var with Javascript like this: <?php $fruit = "apple"; $color = "red"; ?> <script type="text/javascript"> alert("fruit: " + "<?php echo $fruit; ?>"); // or shortcut "<?= $fruit ?>" </script> But what if I want to use an external JS file: <script type="text/javascript" src="externaljs.js"></script> externaljs.js: alert("color: " + "<?php echo $color; ?>");

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  • Access control of page in php

    - by garcon1986
    Hello, I want to control the access in php website. I have a solution right now with switch case. <?php $obj = $_GET['obj']; switch ($obj) { case a: include ('a.php'); break; default: include ('f.php'); } ?> But when i have so many pages, it becomes difficult to manage them. Do you have better solutions? Right now, i develop the application using php4. And i want to use php5. Do you have any suggestions when i develop it using php5? Thanks

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  • got undefined variable in php code

    - by Newbie New
    I got a error message when I run my php however the result is come out this is my code function cart() { foreach($_SESSION as $name => $value) { if ($value>0) { if (substr($name, 0, 5) == 'cart_'){ $id = substr($name, 5, (strlen($name)-5)); $get = mysql_query('SELECT id, name, price FROM products WHERE id=' .mysql_real_escape_string((int)$id)); while ($get_row = mysql_fetch_assoc($get)){ $sub = $get_row['price'] * $value; echo $get_row['name'].' x '.$value.' @ &pound'.number_format($get_row['price'], 2).' = &pound'.number_format($sub, 2).' <a href="cart.php?remove='.$id.'">[-]</a> <a href="cart.php?add='.$id.'">[+]</a> <a href="cart.php?delete='.$id.'">[Delete]</a><br />' ; } } $total += $sub; } } echo $total; } ?> I got a error message Notice: Undefined variable: total in C:\xampp\htdocs\shoppingcart\cart.php on line 54 which line 54 is echo $total; what's wrong with my code?? I think I have defined the code in $total += $sub; thanks for helping me :)

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  • Echo html+php from database

    - by pg-robban
    I am working on a site which deals with a lot of texts in HTML, so recently I learned PHP and moved them into a MySQL database and echo the contents given a specific chapter and section. Now this works relatively fine, the HTML shows up properly. However, in some parts I have included PHP function calls, and these doesn't seem to be evaluated - rather, they get just inserted into the source code (and thus invisible for the page viewer), never doing anything. They did work when they were simple .html files. How can I solve this? For example, a text can look like this: <?php printChapterName(); ?> <p>Some text</p> ... <?php showImage($name, $alt-text); ?> ... This just shows the text on the page. Edit: The functions are echo:ing some HTML.

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  • Possible to view PHP code of a website?

    - by Camran
    Is it possible to somehow view another websites php files/codes? Or to rephrase the question, Can my php codes be viewed by anybody except for those who have access to the file? If so, how cant I best prevent this? Thanks Ps: Server OS is Ubuntu 9.10 and PHP version is 5+ (Apache2)

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  • generate PHP classes from XSD?

    - by Qwerty
    Is there in the world analogues of JavaBeans or JAXB for PHP? Is it possible to generate PHP classes from XML schema? It's common practice to publish API's as XSD schemas. Java and C# guys can get advantage of this by generating classes right from XSD. Is there same tool for PHP?

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  • Disable globbing in PHP exec()

    - by wxs
    I have a PHP script which calls another script in order to add IP addresses to a whitelist. I sometimes want to whitelist all addresses, in which case I have it call exec("otherscript *.*.*.*", output, retval); This worked fine, adding the string "*.*.*.*" to the whitelist until I happened to have another file in the directory of the php script that matched that pattern ("foo.1.tar.gz"), at which point the wildcards were expanded, and I ended up with the filename in my whitelist. Is there some way to disable globbing in php's exec? It isn't mentioned in the PHP docs as far as I can tell.

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  • html-embedded php code not executing when hosted on iis

    - by Jack
    <HTML> <HEAD> <META NAME="GENERATOR" Content="Microsoft Visual Studio .NET 7.1"> <TITLE></TITLE> </HEAD> <BODY> <?php echo '<p>Hello World</p>'; ?> </BODY> </HTML> When I run the above code in a browser, firefox renders it like this: Hello World '; ?> I am doing my coding in Windows XP/IIS 5.1. I have PHP set up correctly because I have no problem running .php files. The problem, it seems to me, is that IIS can't render php code embedded inside html. Does anyone know how to fix this problem or should i switch to Apache?

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  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

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  • Function naming: sendCharacter or receiveCharacter?

    - by bobobobo
    I'm trying to name a function that runs when a character is received by the object. For the caller, it should be named sendCharacter, so that it can call: object->sendCharacter( character ) ; That looks nice for the caller.. but for the receiver, it implements a method /// Called when this object is do something /// with a character /// from the caller void sendCharacter( char c ) ; So for the recipient class, it looks like this method will actually send a character out, not receive one. So then, I could call the function receiveCharacter /// Called when this object is do something /// with a character /// from the caller void receiveCharacter( char c ) ; But now the caller does this: object->receiveCharacter( character ) ; Which just looks odd. How can I better name this function?

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  • html embeded php code not executing when hosted on iis

    - by Jack
    <HTML> <HEAD> <META NAME="GENERATOR" Content="Microsoft Visual Studio .NET 7.1"> <TITLE></TITLE> </HEAD> <BODY> <?php echo '<p>Hello World</p>'; ?> </BODY> When I run the above code in browser, firefox render it like this Hello World '; ? I am doing my coding in Windows XP/IIS 5.1. I have PHP setup correctly because i have no problem running .php file. The problem seem to me that IIS can't render php code embedded inside html. Does anyone know how to fix this problem or should i switch to Apache?

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • Broken php/localhost/something

    - by ghego1
    I was trying to install the mcrypt libraries following this tutorial (http://www.glenscott.co.uk/blog/2011/08/29/install-mcrypt-php-extension-on-mac-os-x-lion/), but something must have gone wrong and now when I load a php page on my localhost I see this: query="SELECT DISTINCT ".$field." as a,".$field2." as b FROM ".$tab." ".$where. " Group by ".$field." order By ".$orderBy; return $this->query; } And all the remaining code of the php page that should get loaded. I've retrieved the previous versions of the private/etc folder and usr/lib/php folder with time machine but it didn't help. And now if I execute sudo pachectl restart it gives me this error: sudo: no valid sudoers sources found, quitting (while before it worked. PS I'm on a mac with Mountain Lion

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  • Debugging PHP in Aptana 2.0

    - by Nick Lowman
    I'm a real newbie when it comes to PHP debugging so forgive my stupidity. I have a simple html form that submits to a PHP script and I want to debug that script and see what's being sent from the form. My Aptana has two two PHP interpreters installed; Zend Debugger on port 10001 and XDebug on 9000 I have the Firefox Aptana Addon installed I have my HTML page on the following url, running locally; http://3i/latest.html In the IDE I open the PHP script and add some breakpoints, I then open the latest.html and I click on the debug button. It launches the HTML page in a local webserver running at; http://127.0.0.1:8000/3i/latest.html I then fill out the form and submit at which point the debugger tells me the JS Debugger has terminated but it doesn't stop at my break points. I've had a good read around and I can't find anything which helps me, which makes me think it's something pretty easy and I'm being a bit dumb.

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  • php class crash course

    - by rabidmachine9
    Hello people, I'm sorry for this question but I'm getting crazy trying to write my first php clash, it is supposed to connect me to server and to a database but I'm always getting this error: Parse error: syntax error, unexpected ',', expecting T_PAAMAYIM_NEKUDOTAYIM in /Applications/XAMPP/xamppfiles/htdocs/classTest/test.php on line 9 thanks in advance, here is the code: <?php // include 'DBConnect.php'; class DBConnect { function connection($hostname = "localhost", $myname = "root", $pass = ''){ mysql_connect(&hostname, &myname, &pass) or die("Could not connect!"); //Connect to mysql } function choose($dbnam){ mysql_select_db(&dbnam) or die("Couldn't find database!"); //fnd specific db } } $a = new DBConnect(); $connect = $a->connection("localhost", "root"); $a->choose('mydb'); ?>

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