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  • Load PHP function with jQuery Ajax

    - by brandon14_99
    I have a file which is loaded at the top of my document, which is called Videos.php. Inside that file are several functions, such as getYoutubeVideos. On some pages, I need to call upon that function several times (up to 50), and it of course creates major lag on load times. So I have been trying to figure out how to call that function in, only when it is need (when someone clicks the show videos button). I have very little experience with jQuery's ajax abilities. I would like the ajax call to be made inside of something like this: jQuery('a[rel=VideoPreview1).click(function(){ jQuery ("a[rel=VideoPreview1]").hide(); jQuery ("a[rel=HideVideoPreview1]").show(); jQuery ("#VideoPreview1").show(); //AJAX STUFF HERE preventDefault(); }); Ok I have created this based on the responses, but it is still not working: jQuery Code: jQuery(document).ready(function(){ jQuery("a[rel=VideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").hide(); jQuery("a[rel=HideVideoPreview5]").show(); jQuery.post("/Classes/Video.php", {action: "getYoutubeVideos", artist: "Train", track: "Hey, Soul Sister"}, function(data){ jQuery("#VideoPreview5").html(data); }, 'json'); jQuery("#VideoPreview5").show(); preventDefault(); }); jQuery("a[rel=HideVideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").show(); jQuery("a[rel=HideVideoPreview5]").hide(); jQuery("#VideoPreview5").hide(); preventDefault(); }); }); And the PHP code: $Action = isset($_POST['action']); $Artist = isset($_POST['artist']); $Track = isset($_POST['track']); if($Action == 'getYoutubeVideos') { echo 'where are the videos'; echo json_encode(getYoutubeVideos($Artist.' '.$Track, 1, 5, 'relevance')); }

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  • Problem with Xpath PHP

    - by user294597
    Im tring to access some links through Google using xpath. The below does works fine and all the links are shown. $query = $xpath->evaluate("/html/body//a"); for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('href'); echo $url."<br>"; } But when i try the below xpath nothing is shown..Im sure that the xpath is correct coz its evaluated and the result is shown in xpather.. /html/body[@id='gsr']/div[@id='cnt']/div[@id='res']/div[1]/ol/li/div//cite for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('cite'); echo $url."<br>"; } can some one please tell me what i am doin wrong? any help will be much appreciated

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  • Executing system command in php, differs in using broswer and in using command line

    - by Amit
    Hi, I have to execute a Linux "more" command in php from a particular offset, format the result and display the result in Browser. My Code for the above is : <html> <head> <META HTTP-EQUIV=REFRESH CONTENT=10> <META HTTP-EQUIV=PRAGMA CONTENT=NO-CACHE> <title>Runtime Access log</title> </head> <body> <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "<br/>No of lines are : $accessDisplay[0] <br/>"; ?> The output at the browser is :: No of lines are : 3428 (This is wrong) While executing the same command using command line gives a different output. My code snippet for the same is : <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "No of lines are : $accessDisplay[0] \n"; ? The output at the command line is :: No of lines are : 279 (This is correct) While executing the same command directly in command line, gives me output as 279. I am unable to understand why the output of the same command is wrong in the browser. Its actually giving the word count of lines, ignoring the offset parameter. Please help !! Thanks, Amit

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  • PHP what is faster to use

    - by user1631500
    What is faster / better to use? To put html into variables and print them later, or to just html print / echo print the content based on condition? EXAMPLE 1:(html into variables) if(!isset($_SESSION['daddy'])) { $var = "<span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span>" } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = You are cool enough to view the content; } echo $var; EXAMPLE 2:(print based on condition) if(!isset($_SESSION['daddy'])) { $var = 1; } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = 0; } if ($var==1) { ?> <span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span <?php } else { ?> You are cool enough to view the content. <?php } ?>

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  • How do I use curl to display a table on a page?

    - by user272899
    I want to use curl to retrieve a table from an external page. So far my code retrieves all data from the page. I have read that using preg_match or preg_replace is the way to go about it. This is my code so far: <?php $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL,"http://www.megaupload.com/?d=XE30L1GA&w=631&h=392"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1=curl_exec($ch) or die(curl_error()); echo "<font color=black face=verdana size=3>".$data1."</font>"; echo curl_error($ch); curl_close($ch); ?> This is the data I want to retrieve from the page: <FORM method="POST" id="captchaform"> <INPUT type="hidden" name="captchacode" value="1a589e0a53c54f937eb8"> <INPUT type="hidden" name="megavar" value="bed55b1a7a26e4bb0aa11df4188f58bda6958d72856a637ca55cbda4c24c89b97d52e39e3a2d1d26082273dec61e68416bd929d566cf63cd8441e9f6166d667618060608c5d63c9341e72fc036ea4ed1ec8d099bc488fa1f3c5df7228e10a0f79c4e5fb78fe41f0d9873194c56f94dfbcc008e4a7c8ebc58c8169d42cb98a9a86d8cb6dfbae8791b9dfcf5a3119f7941cc07e9ba48934ad9b5f865cd32e71bf6d3a3954ddc4e75925aaf2c0ec6d1dd884ccc4d299be3e41957a967e68a143af49d6b7ff7b36dac725f20214e58feb32662e09f5840ac76cff67f7d99e67ffb485d72382dd20cece80e4307dfef720a51734d7f9a4a363de0950d3d0e927423642a79b2e68ed177d2ad2d877c1c2052969ec61737749b05864b3a74d241981d6b89"> <TR> <TD>Enter this </TD> <TD width="100" align="center" height="40"><img src="http://wwwq32.megaupload.com/gencap.php?23243f17c2404dd4.gif" border="0" alt=""></TD> <TD> here:</TD> <TD><input type="text" name="captcha" id="captchafield" maxlength="4" style="border:solid 1px; border-color:#C4C4C4; background-color:#F9F9F9; width:50px; height:25px;"></TD> </TR> </FORM>

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  • PHP unlink OR rewrite own/current file by itself

    - by Email
    Hi Task: Cut or erase a file after first walk-through. i have an install file called "index.php" which creates another php file. <? /* here some code*/ $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = "<?php \n echo 'hallo, *very very long text*'; \n ?>"; fwrite($fh, $stringData); /*herecut"/ /*here some code */ after the creation of the new file this file is called and i intent to erase the filecreation call since it is very long and only needed on first install. i therefor add to the above code echo 'hallo, *very very long text*'; \n ***$new= file_get_contents('index.php'); \n $findme = 'habanot'; $pos = strpos($new, $findme); if ($pos === false) { $marker='herecut';\n $new=strstr($new,$marker);\n $new='<?php \n /*habanot*/\n'.$new;\n $fh = fopen('index.php', 'w') or die 'cant open file'); $stringData = $new; fwrite($fh, $stringData); fclose($fh);*** ?>"; fwrite($fh, $stringData);]} Isnt there an easier way or a function to modify the current file or even "self destroy" a file after first call? Regards

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  • PHP mail() function not delivering mail

    - by Ryan Jones
    Hi there, I have a slight problem. I am using a working script (works on my testing account - shared server) to send a mail through PHP using the mail() function. I just got a dedicated server, and I haven't been able to get the function to work. I've spent the last 10 or so hours reading various documentations on BIND (for the SPF record), dovecot, sendmail and postfix trying various things to get this to work. There is clearly something that I am missing. So we know the PHP code works fine. All the headers are fine everything. We know this as it's a direct copy from my testing account. So the problem must arise somewhere in the server config. The path to sendmail is correct, and sendmail is (apparently) working fine. I've set up the script to now deliver "Sent" or "Error" based on the boolean result from the PHP mail() function. That is: if(mail($blah,$blah,$blah,$blah,$blah)) { echo "Sent"; } else { echo "Error";} And the result ALWAYS comes up as "Sent" - however, the email never arrives. Can someone suggest things to check, as I'm completely new to this (24 hours or so!). Thanks in advance. Ryan

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  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

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  • INSERT INTO table doesn't work???

    - by Joann
    I found a tutorial from nettuts and it has a source code in it so tried implementing it in my site.. It is working now. However, it doesn't have a Registration system so I am making one. The thing is, as I have expected, my code is not working... It doesn't seem to know how to INSERT into the database. Here's the function that inserts data into the db. function register_User($un, $email, $pwd) { $query = "INSERT INTO users( username, password, email ) VALUES(:uname, :pwd, :email) LIMIT 1"; if($stmt = $this->conn->prepare($query)) { $stmt->bind_param(':uname', $un); $stmt->bind_param(':pwd', $pwd); $stmt->bind_param(':email', $email); $stmt->execute(); if($stmt->fetch()) { $stmt->close(); return true; } else return "The username or email you entered is already in use..."; } } I have debugged the connection to the database from within the class, it says it's connected. I tried using this method instead: function register($un, $email, $pwd) { $registerquery = $this->conn->query( "INSERT INTO users(uername, password, email) VALUES('".$un."', '".$pwd."', '".$email."')"); if($registerquery) { echo "<h4>Success</h4>"; } else { echo "<h4>Error</h4>"; } } And it echos "Error"... Can you please help me pen point the error in this??? :(

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  • How to disable a checkbox based on date using php?

    - by udaya
    I have iterated a table based on my query result... I have a column lastDate it contains a date value like 01/24/2010... Now i have to check the date value with the current date if currentdate is less than or equal to lastDate i have to enable the checkbox else disable it..... Any suggestion how it can be done in php... Here is my code <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <td align="center" class="table_label" id="txtsubdat"> <? $dd=$row['dDate']; if($dd=='') { } else { $str = $dd; $dd = strtotime ( $str ); echo date ( 'm/d/Y' , $dd ); } ?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['dAssignment_id']?>" onclick="checkdisplay(this);"> </td> <? } ?>

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  • Problem with checkboxes, sql select statements & php

    - by smokey20
    I am trying to display some rows from a database table based on choices submitted by the user. Here is my form code <form action="choice.php" method="POST" > <input type="checkbox" name="variable[]" value="Apple">Apple <input type="checkbox" name="variable[]" value="Banana">Banana <input type="checkbox" name="variable[]" value="Orange">Orange <input type="checkbox" name="variable[]" value="Melon">Melon <input type="checkbox" name="variable[]" value="Blackberry">Blackberry From what I understand I am placing the values of these into an array called variable. Two of my columns are called receipe name and ingredients(each field under ingredients can store a number of fruits). What I would like to do is, if a number of checkboxes are selected then the receipe name/s is displayed. Here is my php code. <?php // Make a MySQL Connection mysql_connect("localhost", "*****", "*****") or die(mysql_error()); mysql_select_db("****") or die(mysql_error()); $variable=$_POST['variable']; foreach ($variable as $variablename) { echo "$variablename is checked"; } $query = "SELECT receipename FROM fruit WHERE $variable like ingredients"; $row = mysql_fetch_assoc($result); foreach ($_POST['variabble'] as $ingredients) echo $row[$ingredients] . '<br/>'; ?> I am very new to php and just wish to display the data, I do not need to perform any actions on it. I have tried many select statements but I cannot get any results to display. My db connection is fine and it does print out what variables are checked. Many thanks in advance.

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  • Preserving Tabs in POST Data

    - by byronh
    I need to preserve tab characters from a textarea through POST Data. It seems that there's no way to differentiate tabs from spaces in the $_POST array, and this is really frustrating me. I'm using a jQuery plugin from here to allow for tab and shift+tab usage within a textarea. http://teddevito.com/demos/textarea.html The JavaScript is using this as its TAB character: $.fn.tabby.defaults = {tabString : String.fromCharCode(9)}; For some reason, it shows an individual space instead of each tab character, so all my code formatting is lost: <textarea name="field0" rows="26" cols="123"><?php echo $_POST['field0']; ?></textarea> Neither does this. Apparently the tabs disappear before the data even reaches the str_replace function (the four spaces in the first double quotes is when I press TAB in my text editor). <textarea name="field0" rows="26" cols="123"><?php echo str_replace(" ", "\t", $_POST['field0']); ?></textarea> The reason I need tabs and not multiple spaces is because my application features and on-line code editor. Anyone have any ideas? I'm guessing the solution would involve modifying the data with javascript before it's sent through POST, but I haven't the slightest idea how to start.

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  • How to send a future email using AT command.

    - by BHare
    I just need to send one email into the future, so I figured i'd be best at using at rather than using cron. This is what I have so far, its messy and ugly and not that great at escaping: <pre> <?php $out = array(); // Where is the email going? $email = "[email protected]"; // What is the body of the email (make sure to escape any double-quotes) $body = "This is what is actually emailed to me"; $body = escapeshellcmd($body); $body = str_replace('!', '\!', $body); // What is the subject of the email (make sure to escape any double-quotes) $subject = "It's alive!"; $subject = escapeshellcmd($subject); $subject = str_replace('!', '\!', $subject); // How long from now should this email be sent? IE: 1 minute, 32 days, 1 month 2 days. $when = "1 minute"; $command= <<<END echo " echo \"$body\" > /tmp/email; mail -s \"$subject\" $email < /tmp/email; rm /tmp/email; " | at now + $when; END; $ret = exec($command, $out); print_r($out); ?> </pre> The output should be something like warning: commands will be executed using /bin/sh job 60 at Thu Dec 30 19:39:00 2010 However I am doing something wrong with exec and not getting the result? The main thing is this seem very messy. Is there any alternative better methods for doing this? PS: I had to add apache's user (www-data for me) to /etc/at.allow ...Which I don't like, but I can live with it.

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  • Yii Framework Tutorial - file not found

    - by Heshan Perera
    I am in the process of learning the Yii Framework. I have been following this Tutorial. I have followed all the steps and have by index page loading. In my index.php page I point to two other pages located in protected/views/message The following is the code in my index.php located in the message folder mentioned above. <html> <body> <h1>Welcome</h1> <p> To view our message go to... <?php echo CHtml::link('Here', '/message/show')?> </p> <p> To edit our message go to... <?php echo CHtml::link('Here', '/message/edit')?> </p> </body> </html> "message" is the ID I gave when generating the model and controller through the yii shell application. The problem is, after the above page loads, and I click on any one of the above URLs, it points to "localhost:8080/message/show" and "localhost:8080/message/edit" , whereas the real location of these files is "localhost:8080/test/protected/views/message/..." What could I be doing wrong ?

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  • how to concatinate a link with <select> <option> value on "onchange" event

    - by atif
    <?php echo $this->getUrl(); ?> = this gives me my index page url .i.e. www.domain.com/index.php/ but now wat i want is when any particular option is selected, it should add to this url. .e.g. www.domain.com/index.php/wordpress/ i write this code for it but now don know how to get it done :( <select onchange="setLocation('<?php echo $this->getUrl(); ?>')"> <option value="">&nbsp;</option> <option value="wordpress">Wordpress</option> <option value="drupal">drupal</option> <option value="magento">Megento</option> </select> also i had searched this link but couldn't take help from it. As it didnt work for me. <select name="forma" ONCHANGE="location = this.options[this.selectedIndex].value;"> <option value="Home">Home</option> <option value="Contact">Contact</option> <option value="Sitemap">Sitemap</option> </select>

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  • How to populate html combo box with mysql data

    - by user225269
    Please help, I'm having trouble loading mysql data on the combo box. The data that I'm loading is 1 column from a table. Here is my current code, and it crashed firefox for some reason: <td colspan=”2?>Religion</TD> <td> <select name="REL" onClick="submitCboSemester();"> <?php $query_disp="SELECT * FROM Religion ORDER BY RID"; $result_disp = mysql_query($query_disp, $conn); while($query_data = mysql_fetch_array($result_disp)) { ?> <option value="<? echo $query_data["RID"]; ?>"<?php if ($query_data["RID"]==$_POST['REL']) {?>selected<? } ?>><? echo $query_data["RELIGION"]; ?></option> <? } ?> </select> </td> The column is RELIGION and it ID is RID How do I populate the combo box with all the data in the column RELIGION

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  • Not able to insert data in the database from a form in php

    - by Prashant Baid
    I am not able to insert data into my data, i dont know what the problem is. Here is the code: mysql_select_db("mitestore", $con); */ if ((isset($_POST['product_name'])) && (strlen(trim($_POST['product_name'])) 0)) { $product_name = stripslashes(strip_tags($_POST['product_name'])); $sql="INSERT INTO sell (product_name) VALUE ('$_POST[product_name]')"; } else {$product_name = 'Please enter the product name.';} if ((isset($_POST[''])) && (strlen(trim($_POST['how_old'])) 0)) { $how_old = stripslashes(strip_tags($_POST['how_old'])); $sql="INSERT INTO sell (how_old) VALUE ('$_POST[how_old]')"; } else {$how_old = 'Please enter how old your product is';} if ((isset($_POST['which_block'])) && (strlen(trim($_POST['which_block'])) 0)) { $which_block = stripslashes(strip_tags($_POST['which_block'])); $sql="INSERT INTO sell (which_block) VALUE ('$_POST[which_block]')"; } else {$which_block = 'Please enter which block are you from';} if ((isset($_POST['room_no'])) && (strlen(trim($_POST['room_no'])) 0)) { $room_no = stripslashes(strip_tags($_POST['room_no'])); $sql="INSERT INTO sell (room_no) VALUE ('$_POST[room_no]')"; } else {$room_no = 'Please enter the room no:';} if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Success!"; mysql_close($con) ? Initially i had this code and it worked for me. mysql_select_db("database", $con); $sql="INSERT INTO sell ( product_name, how_old , selling_price, negotiable, which_block, room_no) VALUES ('$_POST[product_name]','$_POST[how_old]','$_POST[selling_price]','$_POST[negotiable]','$_POST[which_block]','$_POST[room_no]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your product is added."; mysql_close($con) ? But i don't know how to validate each field individually.

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  • minifying final html output using regex with codeigniter

    - by Aman
    Google pages suggest you to minify html i.e. remove all the un-necessary spaces. Codeigniter does have feature of giziping output or it can be done via .htaccess. But still I also would like to remove un-necessary spaces from final html output as well. I played a bit with this peace of code to do it, and it seem to work. This does indeed result in html that is without excess spaces and removes other tab formatting. class Welcome extends CI_Controller { function _output() { echo preg_replace('!\s+!', ' ', $output); } function index(){ ... } } Now the problem with this is there may be tag like <pre>,<textarea>, etc.. which may have space in it and regx should remove them. So, how do I remove excess space from final html, without effecting spaces or formatting for these certain tags using regx? Thanks to @Alan Moore got the answer, this worked for me echo preg_replace('#(?ix)(?>[^\S ]\s*|\s{2,})(?=(?:(?:[^<]++|<(?!/?(?:textarea|pre)\b))*+)(?:<(?>textarea|pre)\b|\z))#', ' ', $output); @ridgerunner here did very good job of analyzing this regx, ended up using his solution. Cheers to ridgerunner.

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  • jquery draggable/droppable issue

    - by Scarface
    Hey guys I have a drag and drop function that does not fully work. What I want to do is be able to drag and drop a picture into a div and have that picture pop up in the div. I have a list of 2 pictures right now, so I have the following function echoed for each picture. Both pictures are draggable and droppable, but the first one is the only one that appears in the div, regardless of which picture gets dragged in. I am not sure what is wrong because the jquery function seems to be unique to each picture. If any one has any suggestions I would appreciate it greatly. while ($row = mysql_fetch_assoc($query)) { $image=htmlentities($row['image']); //image name $uniqid=uniqid(); //unique id for jquery functions $dirname = "usercontent/$user/images/$image"; echo "<img id=\"$uniqid\" src=\"$dirname\" width=\"75\" height=\"75\"/>"; echo "<script> $(function() { $(\"#$uniqid\").draggable({ scroll: true, scrollSensitivity: 10, scrollSpeed: 10, revert: true, helper: 'clone', cursorAt: { cursor: 'move', top: 27, left: 27 } }); $(\"#droppable2, #droppable-background , #droppable2-innerer\").droppable({ greedy: true, activeClass: 'ui-state-hover', hoverClass: 'ui-state-active', drop: function(event, ui) { $(this).addClass('ui-state-highlight').find('> p').html('Dropped!'); $('#droppable-background').css(\"background-image\",\"url($dirname)\"); } }); }); </script>"; }

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  • Check if date is allowed weekday in php?

    - by moogeek
    Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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  • Is there a way to access Joomla 1.5 user variables (like user id) from a Flex 4 application using a PHP Data Service?

    - by Zachary G. Schroeder
    I have written a script (in two files) that correctly displays a Joomla user id, like this: //this is testy.php define( '_JEXEC', 1 ); define('JPATH_BASE', dirname(FILE)); define( 'DS', DIRECTORY_SEPARATOR ); require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' ); require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' ); $mainframe =& JFactory::getApplication('site'); $id = JFactory::getUser()-id; The above file is located in the Joomla root folder. The other file is in a different directory and is as follows: //this is testid.php include '../../joomla/testy.php'; echo $id; However, and here is the rub, when I change the "echo" to a "return" and put the second code snippet inside my Flex 4 Data Service script file, like this... function getUserId() { include '../../joomla/testy.php'; return $id; } ...I get a Flex error that says this: Fatal error: Class 'JRequest' not found in /var/www/html/joomla/libraries/joomla/import.php on line 33 I am extremely confused by this error and would appreciate any suggestions that the stackoverflow community may have. Thanks so much! Zach

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  • PHP strtotime without leap-years

    - by Christian Sciberras
    With regards to this thread, I've developed a partial solution: function strtosecs($time,$now=null){ static $LEAPDIFF=86400; $time=strtotime($time,$now); return $time-((date('Y',$time)-1968)/4*$LEAPDIFF); } The function is supposed to get the number of seconds given a string without checking leap-years. It does this calculating the number of leap-years 1970 [(year-1986)/4], multiplying it by the difference in seconds between a leap-year and a normal year (which in the end, it's just the number of seconds in a day). Finally, I simply remove all those excess leap-year seconds from the calculated time. Here's some examples of the inputs/outputs: // test code echo strtosecs('+20 years',0).'=>'.(strtosecs('+20 years',0)/31536000); echo strtosecs('+1 years',0).'=>'.(strtosecs('+1 years',0)/31536000); // test output 630676800 => 19.998630136986 31471200 => 0.99794520547945 You will probably ask why am I doing a division on the output? It's to test it out; 31536000 is the number of seconds in a year, so that 19.99... should be 20 and 0.99... should be a 1. Sure, I could round it all and get "correct" answer, but I'm worried about the inaccuracies.

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  • CodeIgniter: problem using foreach in view

    - by krike
    I have a model and controller who gets some data from my database and returns the following array Array ( [2010] => Array ( [year] => 2010 [months] => Array ( [0] => stdClass Object ( [sales] => 2 [month] => Apr ) [1] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) [2011] => Array ( [year] => 2011 [months] => Array ( [0] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) ) It shows exactly what it should show but the key's have different names so I have no idea on how to loop through the years using foreach in my view. Arrays is something I'm not that good at yet :( this is the controller if you need to know: function analytics() { $this->load->model('admin_model'); $analytics = $this->admin_model->Analytics(); foreach ($analytics as $a): $data[$a->year]['year'] = $a->year; $data[$a->year]['months'] = $this->admin_model->AnalyticsMonth($a->year); endforeach; echo"<pre style='text-align:left;'>"; print_r($data); echo"</pre>"; $data['main_content'] = 'analytics'; $this->load->view('template_admin', $data); }//end of function categories()

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  • merge my code with Ajax code>>> problem

    - by sandy
    I want to help me In the following link i found nice code in Ajax http://www.w3schools.com/php/php_ajax_livesearch.asp I want to link my code with the code you see in the link above and replace dropdown list How can I do it for I could not where is it change in code even my code work as Ajax ?? I wish .... I wish .... I wish any somebody can help me <?php include ("connect.php"); print_r($_POST['sector_list']); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="POST" action=<?php echo $_SERVER["PHP_SELF"]; ?> > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list[]" class="inputstandard" multiple="multiple"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberName'] . '">' . $row['MemberName']. '</option>'; } ?> <input type ="submit" name ="go" value = "go" > </select> </form>

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  • KO3: How to deal with stylesheets and scriptfiles

    - by Svish
    I'm using Kohana 3 and it's template controller. My main site template controller currently looks something like this: <?php defined('SYSPATH') or die('No direct script access.'); abstract class Controller_SiteTemplate extends Controller_Template { public function before() { parent::before(); // Initialize default template variables $this->template->styles = Kohana::config('site.styles'); $this->template->scripts = Kohana::config('site.scripts'); $this->template->title = ''; $this->template->content = ''; } } And then in my template view I do: <?php # Styles foreach($styles as $file => $media) echo HTML::style($file, array('media' => $media)).PHP_EOL ?> <?php # Scripts foreach($scripts as $file) echo HTML::script($file).PHP_EOL ?> This works alright. The problem is that it requires the style- and script files to be added in the controller, which shouldn't really have to care about those. It also makes it a hassle if the views are done by someone else than me since they would have to fool around with the controller just to add a new stylesheet or a new script file. How can this be done in a better way? Just to clearify, what I am wondering is how to deal with page specific stylesheets and scripts. The default and site-wide ones I have no problem with fetching from a config file or just put directly in the template view. My issue is how to add custom ones for specific pages in a good way.

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