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  • PDO using singleton stored as class properity

    - by Misiur
    Hi again. OOP drives me crazy. I can't move PDO to work. Here's my DB class: class DB extends PDO { public function &instance($dsn, $username = null, $password = null, $driver_options = array()) { static $instance = null; if($instance === null) { try { $instance = new self($dsn, $username, $password, $driver_options); } catch(PDOException $e) { throw new DBException($e->getMessage()); } } return $instance; } } It's okay when i do something like this: try { $db = new DB(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } But this: try { $db = DB::instance(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } Does nothing. I mean, even when I use wrong password/username, I don't get any exception. Second thing - I have class which is "heart" of my site: class Core { static private $instance; public $db; public function __construct() { if(!self::$instance) { $this->db = DB::instance(DB_TYPE.':hpost='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } return self::$instance; } private function __clone() { } } I've tried to use "new DB" inside class, but this: $r = $core->db->query("SELECT * FROM me_config"); print_r($r->fetch()); Return nothing. $sql = "SELECT * FROM me_config"; print_r($core->db->query($sql)); I get: PDOStatement Object ( [queryString] => SELECT * FROM me_config ) I'm really confused, what am I doing wrong?

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  • SQL wont work? It doesn't come up with errors either

    - by Stefan
    Hey there, I have php function which checks to see if variables are set and then adds them onto my sql query. However I am don't seem to be getting any results back!? $where_array = array(); if (array_key_exists("location", $_GET)) { $location = addslashes($_GET['location']); $where_array[] = "`mainID` = '".$location."'"; } if (array_key_exists("gender", $_GET)) { $gender = addslashes($_GET["gender"]); $where_array[] = "`gender` = '".$gender."'"; } if (array_key_exists("hair", $_GET)) { $hair = addslashes($_GET["hair"]); $where_array[] = "`hair` = '".$hair."'"; } if (array_key_exists("area", $_GET)) { $area = addslashes($_GET["area"]); $where_array[] = "`locationID` = '".$area."'"; } $where_expr = ''; if ($where_array) { $where_expr = "WHERE " . implode(" AND ", $where_array); } $sql = "SELECT `postID` FROM `posts` ". $where_expr; $dbi = new db(); $result = $dbi->query($sql); $r = mysql_fetch_row($result); I'm trying to call the data after in a list like so: $dbi = new db(); $offset = ($currentpage - 1) * $rowsperpage; // get the info from the db $sql .= " ORDER BY `time` DESC LIMIT $offset, $rowsperpage"; $result = $dbi->query($sql); // while there are rows to be fetched... while ($row = mysql_fetch_object($result)){ // echo data echo $row['text']; } // end while Anyone got any ideas why I am not retrieving any data? -Stefan

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  • $_POST in php 5.3.5 does not work

    - by naji
    dear all iam working in php 5.3.5 this is the html file <html> <body> <form action="welcome.php" method="post"> Name: <input type="text" name="fname" /> Age: <input type="text" name="age" /> <input type="submit" /> </form> </body> </html> and this is the php file <html> <body> Welcome <?php echo $_POST["fname"]; ?>!<br /> You are <?php echo $_POST["age"]; ?> years old. </body> </html> the problem the values are not passed and the output like Welcome ! You are years old. But it has to be like this Welcome John! You are 28 years old. can any one help me please?? naji

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  • php: autoload exception handling.

    - by YuriKolovsky
    Hello again, I'm extending my previous question (Handling exceptions within exception handle) to address my bad coding practice. I'm trying to delegate autoload errors to a exception handler. <?php function __autoload($class_name) { $file = $class_name.'.php'; try { if (file_exists($file)) { include $file; }else{ throw new loadException("File $file is missing"); } if(!class_exists($class_name,false)){ throw new loadException("Class $class_name missing in $file"); } }catch(loadException $e){ header("HTTP/1.0 500 Internal Server Error"); $e->loadErrorPage('500'); exit; } return true; } class loadException extends Exception { public function __toString() { return get_class($this) . " in {$this->file}({$this->line})".PHP_EOL ."'{$this->message}'".PHP_EOL . "{$this->getTraceAsString()}"; } public function loadErrorPage($code){ try { $page = new pageClass(); echo $page->showPage($code); }catch(Exception $e){ echo 'fatal error: ', $code; } } } $test = new testClass(); ?> the above script is supposed to load a 404 page if the testClass.php file is missing, and it works fine, UNLESS the pageClass.php file is missing as well, in which case I see a "Fatal error: Class 'pageClass' not found in D:\xampp\htdocs\Test\PHP\errorhandle\index.php on line 29" instead of the "fatal error: 500" message I do not want to add a try/catch block to each and every class autoload (object creation), so i tried this. What is the proper way of handling this?

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  • Add kilometers to a map point

    - by proveyourselfthom
    Good morning. I would like to know how do I add kilometers to a map point (latitude / longitude). For example: The city Jaraguá do Sul is in latitude -26.462049, longitude -49.059448. I want to add 100 kilometers up, down, and on the sides. I want to do a square and get the new points. How do I do that? I tried it: <?php $distance = 100; $earthRadius = 6371; $lat1 = -26.4853239150483; $lon1 = -49.075927734375; $bearing = 0; $lat2 = asin(sin($lat1) * cos($distance / $earthRadius) + cos($lat1) * sin($distance / $earthRadius) * cos($bearing)); $lon2 = $lon1 + atan2(sin($bearing) * sin($distance / $earthRadius) * cos($lat1), cos($distance / $earthRadius) - sin($lat1) * sin($lat2)); echo 'LAT: ' . $lat2 . '<br >'; echo 'LNG: ' . $lon2; ?> But it's returning wrong cordinates. Thank you! Thank you very much.

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  • Need help with PHP URL encoding/decoding

    - by Kenan
    On one page I'm "masking"/encoding URL which is passed to another page, there I decode URL and start file delivering to user. I found some function for encoding/decoding URL's, but sometime encoded URL contains "+" or "/" and decoded link is broken. I must use "folder structure" for link, can not use QueryString! Here is encoding function: $urll = 'SomeUrl.zip'; $key = '123'; $result = ''; for($i=0; $i<strlen($urll); $i++) { $char = substr($urll, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)+ord($keychar)); $result.=$char; } $result = urlencode(base64_encode($result)); echo '<a href="/user/download/'.$result.'/">PC</a>'; Here is decoding: $urll = 'segment_3'; //Don't worry for this one its CMS retrieving 3rd "folder" $key = '123'; $resultt = ''; $string = ''; $string = base64_decode(urldecode($urll)); for($i=0; $i<strlen($string); $i++) { $char = substr($string, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)-ord($keychar)); $resultt.=$char; } echo '<br />DEC: '. $resultt; So how to encode and decode url. Thanks

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  • Weird character at start of json content type

    - by Nek
    Hi, I'm trying to return json content read from MySQL server. This is supposed to be easy but, there is a 'weird' character that keeps appearing at start of the content. I have two pages for returning content: kcb433.sytes.net/as/test.php?json=true&limit=6&input=d this test.php is from a script written by Timothy Groves, which converts an array to json output http://kcb433.sytes.net/k.php?k=4 this one is supposed to do the same I tried to validate it here jsonformatter.curiousconcept.com but just page 1 gets validated, page 2 says that it does not contain JSON data. If accessed directly both pages has no problems. Then what is the difference, why both don't get validated? Then I found this page jsonformat.com and tried the same thing. Page 1 was ok and page 2 wasn't but, surprisingly the data could be read. At a glance, {"a":"b"} may look good but there is a character in front. According to a hex editor online, this is the value of the string above (instead of 9 values, there are 10): -- 7B 22 61 22 3A 22 62 22 7D The code to echo json in page 2 is: header("Content-Type: application/json"); echo "{\"a\":\"b\"}";

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  • How to change the attribute value of svg file

    - by rafiq7s
    Hello, In samplexml.svg there is a node <image width="744" height="1052" xlink:href="image1.png"/> I need to replace "image1.png" with another value like "image2.png". Please guide me with sample code how to to that. I could get the attribute value "image1.png". Here is the code: > <?php $xdoc = new DomDocument; > $xdoc->Load('samplexml.svg'); $tagName > = $xdoc->getElementsByTagName('image')->item(0); > $attribNode = > $tagName->getAttributeNode('xlink:href'); > > echo "Attribute Name : > ".$attribNode->name; echo "<br > />Attribute Value : > ".$attribNode->value; ?> Here is samplexml.svg: > <svg> <g> <title>Test title</title> > <image x="0" y="0" width="744" > height="1052" > xlink:href="image1.png"/> </g> </svg> Please help me, how to change this attribute value. Regards, rafiq7s

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  • PHP - print content from file after manipulation

    - by ludicco
    Hello there, I'm struggling trying to read a php file inside a php and do some manipulation..after that have the content as a string, but when I try to output that with echo or print all the php tags are literally included on the file. so here is my code: function compilePage($page,$path){ $contents = array(); $menu = getMenuFor($page); $file = file_get_contents($path); array_push($contents,$menu); array_push($contents,$file); return implode("\n",$contents); } and this will return a string like <div id="content> <h2>Here is my title</h2> <p><? echo "my body text"; ?></p> </div> but this will print exactly the content above not compiling the php on it. So, how can I render this "compilePage" making sure it returns a compiled php result and not just a plain text? Thanks in advance

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  • Run a command as cron would but from the command line.

    - by BCS
    I have a script that I'm trying to run from cron. When I run it from bash, it work just fine. However when I let cron do it's thing, I get a: myscript.sh: line 122: syntax error: unexpected end of file What I want is a way to run a command as if it was a cron job, but do it in my shell. As a side note: does anyone know what would be differnt under cron? (the script already has a #!/bin/sh line) To answer my own question: I added this to my crontab: * * * * * bcs for ((i=1; i <= 55; i++)) ; do find ~/.crontemp/ -name '*.run' -exec "{}" ";" ; sleep 1; done` and created this script: #!/bin/sh tmp=$(mktemp ~/.crontemp/cron.XXXXX) mknod $tmp.pipe p mv $tmp $tmp.pre echo $* '>' $tmp.pipe '1>&2' >> $tmp.pre echo rm $tmp.run >> $tmp.pre chmod 700 $tmp.pre mv $tmp.pre $tmp.run cat $tmp.pipe rm $tmp.pipe With that, I can run an arbitrary command with a delay of not more than one second. (And yes, I know there are all kinds of security issue involved in that)

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  • Getting the last User ID in Zend Framework

    - by Ryan Murphy
    Using MySQL query browser, I manually made a table called users and input some date in the fields. I set the primary key to id and set it to auto increment. There are 3 rows, the highest id is 3. I then made the following class in the method directory to call upon the data in the table etc. class Application_Model_DbTable_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; public function getLatestUserId() { $id = $this->getAdapter()->lastInsertId(); return $id; } } In the controller I do the following which gets the value generated by the method and lets the view access it: $usersDbModel = new Application_Model_DbTable_User(); $lastUserId = $usersDbModel->getLatestUserId(); $this->view->lastUserId = $lastUserId; In the view I then echo it to display it to the user: echo $this->lastUserId; However, even though my last id in the users table is 3. It displays 0. I have also tried: public function getLatestUserId() { $sql = 'SELECT max(id) FROM user'; $query = $this->query($sql); $result = $query->fetchAll(); return $result; } But this just throws out a server error. What have I done wrong? Am I missing something? Is there another way of doing this?

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  • How could I cache images that I'm pulling from a magento database through ajax?

    - by wes
    Here's script being called through ajax: <?php require_once '../app/Mage.php'; umask(0); /* not Mage::run(); */ Mage::app('default'); $cat_id = ($_POST['cat_id']) ? $_POST['cat_id'] : NULL; try { $category = new Mage_Catalog_Model_Category(); $category->load($cat_id); $collection = $category->getProductCollection(); $output = '<ul>'; foreach ($collection as $product) { $cProduct = Mage::getModel('catalog/product'); $cProduct->load($product->getId()); $output .= '<li><img id="'.$product->getId().'" src="' . (string)Mage::helper('catalog/image')->init($cProduct, 'small_image')->resize(75) . '" class="thumb" /></li>'; } $output .= '</ul>'; echo $output; } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } I'm just passing in the Category ID, which I've tacked onto the navigation links, then doing some work to eventually just pass back all product images in that category. I'm using this on a drag and drop build-a-bracelet type of application, and the amount of images returned is sometimes in the 500s. So it get's pretty held up during transmission, sometimes 10 seconds or so. I know I'd do good by caching them some way, just not sure how to go about it. Any help is much appreciated. Thanks. -Wes

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  • Trying to match variables in a PHP array

    - by Nick B
    I'm stuck with a php array problem. I've to a webpage that takes values from a URL, and I need to cross reference those values against some values on the page and if they match output a 'yes'. It's an expression engine bodge job. The URL is something like domain.com/page/C12&C14 The C12 and C14 represent different categories. I've taken the last bit of the url, removed the 'C' from the values and then exploded the 12&14 into an array. I print_r the array on the page and it shows: Array ( [0] = 12 [1] = 14 ) So, the values are in the array. Lovely. Now on the page I have an html list which looks like 10 12 14 15 I want to output a YES next to the variables that are current in the array so the ideal output would be: 10 12 - YES 14 - YES 15 I was trying this but it keeps just saying No next to all of them. $currentnumber = 12; foreach ($tharray as $element) { if ($element == $currentnumber) { echo "Yes"; } else { echo "No"; } } I thought that should work, but it's not. I checked and the array and the variable are both stings. I did a strlen() on both to see if they are the same, but $currentnumber outputs '13' and the array variable outputs '2'. Any ideas as to why it's saying 13? Is the variable the wrong type of string - and if so how would I convert it?

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  • Upload file onto Server from the IPhone using ASIHTTPRequest

    - by Nick
    I've been trying to upload a file (login.zip) using the ASIHTTPRequest libraries from the IPhone onto the inbuilt Apache Server in Mac OS X Snow Leopard. My code is: NSString *urlAddress = [[[NSString alloc] initWithString:self.uploadField.text]autorelease]; NSURL *url = [NSURL URLWithString:urlAddress]; ASIFormDataRequest *request; NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *dataPath = [documentsDirectory stringByAppendingPathComponent:@"login.zip"]; NSData *data = [[[NSData alloc] initWithContentsOfFile:dataPath] autorelease]; request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease]; [request setPostValue:@"login.zip" forKey:@"file"]; [request setData:data forKey:@"file"]; [request setUploadProgressDelegate:uploadProgress]; [request setShowAccurateProgress:YES]; [request setDelegate:self]; [request startAsynchronous]; The php code is : <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> I don't quite understand why the file is not uploading. If anyone could help me. I've stuck on this for 5 days straight. Thanks in advance Nik

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • jquery autocomplete: works for first value, how to enable it for next?

    - by Toni Michel Caubet
    hello there! I'm using autocomplete so user can easly enter data on inputs, like this: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> $a = $b its an array with a result like: 'help','please',i','need','to,'be able to', 'select next item',' with autocomplete'; and i checked the ui documentation, but it doesn't fith with my source method.. any idea? I'm trying like this (edited with Bugai13 aportation): <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>], multiple: true, multipleSeparator: ", ", matchContains: true }); } </script> but i don't know how to do it.. any idea? are .push and .pop functions from the autocomplete? or shall i define, them? thanks again! PS: i'm getting adicted to this site! PS: come on dudes, i think the answer will be very usefull for many people PS: is it allowed to offer paypal reward?

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  • Passing jquery JSON from Codeigniter controller to view

    - by dede
    I've been struggling to make it work, but cannot pass the inserted data from the controler to the view in CI using JSON. The input value from the form is successfully inserted into the database, but cannot make it appear in the view. This is my view file ajax_view.php: <script type="text/javascript" src="<?php echo base_url(); ?>js/jquery-1.4.2.min.js"></script> $(document).ready(function(){ $("#submit").click(function(){ var inp = $('#inp').val(); $.post("ajax/ajax_input", { 'send' : inp }, function(data){ alert(data.input_text); }, "json"); }); }); </script> </head> <body> <form id="form1" method="post" action=""> <label for="inp">Text</label> <input type="text" name="inp" id="inp" /> <label for="submit"></label> <input type="submit" name="submit" id="submit" value="Submit" /> And this is the ajax_input method of the ajax.php controller: <?php // Initializing controller ..... // ............................. //ajax method function ajax_input(){ $var_1 = trim($this->input->post('send')); $array = array('input_text' => $var_1); echo json_encode($array); $this->db->insert('ajax',$array); } Trying to debug it with Firebug, it gives me that data.input_text is empty. What am I doing wrong? EDIT: I'm using XAMPP on Win, so is it posible that json configuration is the problem?

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  • The youtube API sometimes throws error: Call to a member function children() on a non-object

    - by Anna Lica
    When i launch the php script, sometime works fine, but many other times it retrieve me this errror Fatal error: Call to a member function children() on a non-object in /membri/americanhorizon/ytvideo/rilevametadatadaurlyoutube.php on line 21 This is the first part of the code // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/dZec2Lbr_r8'; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); $video = parseVideoEntry($entry); function parseVideoEntry($entry) { $obj= new stdClass; // get nodes in media: namespace for media information $media = $entry->children('http://search.yahoo.com/mrss/'); //<----this is the doomed line 21 UPDATE: solution adopted for ($i=0 ; $i< count($fileArray); $i++) { // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/'.$fileArray[$i]; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); if ( is_object($entry)) { $video = parseVideoEntry($entry); echo ($video->description."|".$video->length); echo "<br>"; } else { $i--; } } In this mode i force the script to re-check the file that caused the error

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  • How to use a string as a delimiter shell script

    - by Dan
    I am reading a line and am using regex to match it in my script. (/bin/bash) echo $line | grep -E '[Ss][Uu][Bb][Jj][Ee][Cc][Tt]: [Hh][Ee][Ll][Pp]' > /dev/null 2>&1 if [[ $? = "0" && -z $subject ]]; then subject=`echo $line | cut -d: -f2` > /dev/null echo "Was able to grab a SUBJECT $line and the actual subject is -> $subject" >> $logfile fi now my problem is that i use the colon as the delimiter. but sometimes the email will have multiple colons in the subject and so I am not able to grab the whole subject because of that. I am looking for a way to grab everything after the colon following subject. even is there is a way to loop through and check for a colon or what. maybe cut allows you to cut with a string as delimiter? Not sure...any ideas? Thanks!

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  • HTML relative links with URL Rewrite

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • Find numbers that equals a sum in an array

    - by valli-R
    I want to find the first set of integers in an array X that the sum equals a given number N. For example: X = {5, 13, 24, 9, 3, 3} N = 28 Solution = {13, 9, 3, 3} Here what I have so far : WARNING, I know it uses global and it is bad,that's not the point of the question. <?php function s($index = 0, $total = 0, $solution = '') { global $numbers; global $sum; echo $index; if($total == 28) { echo '<br/>'.$solution.' = '.$sum.'<br/>'; } elseif($index < count($numbers) && $total != 28) { s($index + 1, $total, $solution); s($index + 1, $total + $numbers[$index], $solution.' '.$numbers[$index]); } } $numbers = array(5, 13, 24, 9, 3, 3); $sum = 28; s(); ?> I don't get how I can stop the process when it finds the solution.. I know I am not far from good solution.. Thanks in advance

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  • PHP classes totally forgotten something today - sorry

    - by russp
    Hi guys, really sorry about being "totally thick today" but I have forgotten how to do something simple - too much time not in php recently. Want to use the OS phpapi How do I print out the individual rows - see told you I was being thick today // The fields we will be fetching. if (isset($_GET['test']) && $_GET['test'] == 'plaxo') { // plaxo is a PortableContacts end-point so doesn't know about the OpenSocial specific fields $profile_fields = array(); } else { $profile_fields = array( 'aboutMe', 'displayName', 'bodyType', 'currentLocation', 'drinker', 'happiestWhen', 'lookingFor' ); } // The number of friends to fetch. $friend_count = 2; $batch = $osapi->newBatch(); // Fetch the current user. $self_request_params = array( 'userId' => $userId, // Person we are fetching. 'groupId' => '@self', // @self for one person. 'fields' => $profile_fields // Which profile fields to request. ); $batch->add($osapi->people->get($self_request_params), 'self'); // Fetch the friends of the user $friends_request_params = array( 'userId' => $userId, // Person whose friends we are fetching. 'groupId' => '@friends', // @friends for the Friends group. 'fields' => $profile_fields, // Which profile fields to request. 'count' => $friend_count // Max friends to fetch. ); $batch->add($osapi->people->get($friends_request_params), 'friends'); // Get supportedFields Request $batch->add($osapi->people->getSupportedFields(), 'supportedFields'); // Send the batch request. $result = $batch->execute(); Say I wanted to print out "aboutMe", whats the echo? cos echo $result['aboutMe'] doesn't work.

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  • execute a string of PHP code on the command line

    - by Matthew J Morrison
    I'd like to be able to run a line of PHP code on the command line similar to how the following options work: :~> perl -e "print 'hi';" :~> python -c "print 'hi'" :~> ruby -e "puts 'hi'" I'd like to be able to do: :~> php "echo 'hi';" I've read that there is a -r option that can do what I need for php, however it doesn't appear to be available when I try to use it. I've tried using PHP 5.2.13 and PHP 4.4.9 and neither have an -r option available. I wrote this script (that I called run_php.php) - which works, but I'm not a huge fan of it just because I feel like there should be a more "correct" way to do it. #!/usr/bin/php5 -q <?php echo eval($argv[1]); ?> My question is: is there a -r option? If so, why is it not available when I run --help? If there is no -r option, what is the best way to do this (without writing an intermediary script if possible)? Thanks!

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  • gevent urllib is slow

    - by djay
    I've created a set of demos of a TCP server however my gevent examples are noticely slower. I'm sure must be how I compiled gevent but can't work out the problem. I'm using OSX leopard using fink compiled python 2.6 and 2.7. I've tried both the stable gevent and gevent 1.0b1 and it acts the same. The echo takes 5 seconds to respond, where the other examples take <1sec. If I remove the urllib call then the problem goes away. I put all the code in https://github.com/djay/geventechodemo To run the examples I'm using zc.buildout so to build $ python2.7 bootstrap.py $ bin/buildout To run the gevent example: $ bin/py geventecho3.py & [1] 80790 waiting for connection... $ telnet localhost 8080 Trying 127.0.0.1... ...connected from: ('127.0.0.1', 56588) Connected to localhost. Escape character is '^]'. hello echo: avast This will take 3-4 seconds to respond on my system. However the twisted example $ bin/py threadecho2.py or the twisted example $ bin/py twistedecho2.py Is less than 1s. Any idea what I'm doing wrong?

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  • HTML relative links on various domains

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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