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  • Why isn't this simple MySQL statement working?

    - by Clark
    I am trying to match a user inputted search term against two tables: posts and galleries. The problem is the union all clause isn't working. Is there something wrong with my code? $query = mysql_query(" SELECT * FROM posts WHERE title LIKE '%$searchTerm%' OR author LIKE '%$searchTerm%' OR location LIKE '%$searchTerm%' OR excerpt LIKE '%$searchTerm%' OR content LIKE '%$searchTerm%' UNION ALL SELECT * FROM galleries WHERE title LIKE '%$searchTerm%' ");

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  • Which mysql construct is faster?

    - by Olaseni
    SELECT ..WHERE COL IN(A,B) or SELECT ... WHERE (COL = A or COL = B) I'm trying to find out what are the differences between the two constructs? Would there be significant performance gains either way if utilized on resultsets that are nearing the 1 million mark?

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  • Update all table rows but top N in Mysql

    - by arthurprs
    I was trying to run the following query UPDATE blog_post SET `thumbnail_present`=0, `thumbnail_size`=0, `thumbnail_data`='' WHERE `blog_post` NOT IN ( SELECT `blog_post` FROM blog_post ORDER BY `blog_post` DESC LIMIT 10) But Mysql doesn't allow 'LIMIT' in an 'IN' subquery. I think I can make a select to count the table rows and then make an ordered update limited by 'COUNT - 10', but I was wondering if there is a better way. Thanks in advance.

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  • seperated mysql statement query in php

    - by stone
    So, I can run the following statements from within mysql itself successfully. SET @fname = 'point1'; SELECT * FROM country WHERE name=@fname;` But when I try to pass the query through php like this and run it, I get an error on the second line $query = "SET @fname = 'point1';"; $query .= "SELECT * FROM country WHERE name=@fname;";

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  • MySql: How to know if an entry is compressed or not

    - by Guy
    I'm working with python and mysql and I want to verify that a certain entry is compressed in the db. Ie: cur = db.getCursor() cur.execute('''select compressed_column from table where id=12345''') res = cur.fetchall() at this point I would like to verify that the entry is compressed (ie in order to work with the data you would have to use select uncompress(compressed_column)..). Ideas?

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  • PHP and MySQL search with extra counts along the way

    - by Barry Connolly
    I am building a PHP and MySQL search as so SELECT * FROM Properties WHERE Locaion = 'Liverpool' I want to count how many of each property type there are and display them at the side of the page to use as filters (like Rightmove.co.uk). This is what I am have come up with but can't get it to work SELECT *, count(PropertyType = 'house') AS HouesTotal, count(PropertyType = 'Apartment') AS ApartmentTotal FROM Properties WHERE Location = 'Liverpool' Can anyone help?

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  • What data actually gets cached in InnoDB/MySQL?

    - by ming yeow
    Hi folks, i am trying to optimize performance for my database. My question is - what get cached in the db memory? For example: (table with 2 columns: key (indexed), data (not indexed) updated (not indexed) Select * where updated=20100202 (the db will do a scan - will the scanned rows be kept in memory?) Select * where key = 20 (the db will refer to the index - will the identified rows be kept in memory?)

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  • Question about Benchmark function in Mysql ( Incredible results ).

    - by xRobot
    I have 2 tables: author with 3 millions of rows. book with 20 miles rows. . So I have benchmarked this query with a join: SELECT BENCHMARK(100000000, 'SELECT book.title, author.name FROM `book` , `author` WHERE book.id = author.book_id ') And this is the result: Query took 0.7438 sec ONLY 0.7438 seconds for 100 millions of query with a join ??? Do I make some mistakes or this is the right result ?

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  • MySQL: Digits (1.75) to Friendly Time (1 hour and 45 minutes)

    - by Nick
    In my MySQL database, I have a float field named "HoursSpent" with values like "0.25", "1.75", "2.5", etc. Is there a way that I can have my SELECT statement format those values in a friendly format like this?: 0.25 = 15 minutes 1.75 = 1 hour and 45 minutes 2.5 = 2 hours and 30 minutes The "HoursSpent" field is supposed to only have values in 0.25 increments, but if somebody were to put something random like 0.16, it would be nice if the SELECT statement handled that by rounding it up to the nearest 0.25 (so in this case 0.16 would become 0.25, or 15 minutes).

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  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • mySQL JOIN wont return results with 0 count

    - by MPC
    SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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  • how to number the datas from mysql

    - by udaya
    Hi This is a doubt on mysql select query let me axplain my doubt with a simple example consider this is my query SELECT dbCountry from tableCountry tableCountry has fields dbCuntryId dbCountry and dbState I have the result as dbCountry india america england kenya pakisthan I need the result as 1 india 2 america 3 england 4 kenya 5 pakisthan the numbers 12345 must be generated with the increase in data and itis not a autoincrement id How can i get it is it something like loop

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  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

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  • mysql like issue on partial match

    - by ubercooluk
    Im having a mysql query like this SELECT group_name FROM t_groups WHERE group_name LIKE '%PCB%'; The results are group_name ------------ PCB Full size PCB Another query, SELECT group_name FROM t_groups WHERE group_name LIKE '%PCB-123%'; group_name ----------- PCB-123 How can i use a query that will show all the three results ?,I mean i need to get all the results that starts or contains PCB

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  • Codeigniter active record select, left join, count

    - by sea_1987
    Hi There, I have a form that shows results from a database query, these results can have many other assets ajoined to them and I wanting to find a way of showing how many assets each elemement has. For example my table is of areas of england an other table has where the users live I current have this code, $this->db->select('*'); $this->db->from('places'); $this->db->join('users, places.place_id = user.place_id, left'); $this->db->get(); The issue I am having is getting the query to return the place name and the number of users living in that place, it is possible?

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  • PHP mysql select results

    - by Jordan Pagaduan
    <?php $sql = " SELECT e.*, l.counts AS l_counts, l.date AS l_date, lo.counts AS lo_counts, lo.date AS lo_date FROM employee e LEFT JOIN logs l ON l.employee_id = e.employee_id LEFT JOIN logout lo ON lo.employee_id = e.employee_id WHERE e.employee_id =" .(int)$_GET['salary']; $query = mysql_query($sql); $rows = mysql_fetch_array($query); while($countlog = $rows['l_counts']) { echo $countlog; } echo $rows['first_name']; echo $rows['last_name_name']; ?> I got what I want to my first_name and last_name(get only 1 results). The l_counts I wanted to loop that thing but the result is not stop counting until my pc needs to restart. LoL. How can I get the exact result of that? I only need to get the exact results of l_counts. Thank you Jordan Pagaduan

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  • Using * in SELECT Query

    - by libregeek
    I am currently porting an application written in MySQL3 and PHP4 to MySQL5 and PHP5. On analysis I found several SQL queries which uses "select * from tablename" even if only one column(field) is processed in PHP. The table has almost 60 columns and it has a primary key. In most cases, the only column used is id which is the primary key. Will there be any performance boost if I use queries in which the column names are explicitly mentioned instead of * ? (In this application there is only one method which we need all the columns and all other methods return only a subset of the columns)

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  • Jquery/Javascript gmail style stuff for message inbox, such as select all message using checkbox etc

    - by Psychonetics
    I am enjoying the fact that I'm here building a private message inbox for my website after building a full user signup/login and activation system when a few months ago I thought I wouldn't have enough patience to learn this stuff. Anyway to my question. I am currently building the private message inbox for my users and wondering if there are any jquery/javascript stuff I can use to make my inbox more like the gmail inbox. E.G. Gmail allows you to select all read messages or unread or starred or unstarred or none of the messages using a checkbox. I would like to add this kind of feature to my website and I'm sure the easiest way to achieve this would be using a jquery/javascript script. I would appreciate if someone could provide some links or info to where I can find several of these types of scripts to use with my inbox page. Thanks EDIT: Would also like to note that I would like the checkbox to be in a dropdown just like gmails.

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  • php / mysql - select id from one table excepting ids which are in second table

    - by John
    hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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  • sql select with exact outcome

    - by Shiro
    Asking a simple question, just want everyone have fun to solve it. I got 2 tables. 1. Student 2. Course Student +----+--------+ | id | name | +----+--------+ | 1 | User1 | | 2 | User2 | +----+--------+ Course +----+------------+------------+ | id | student_id | course_name| +----+------------+------------+ | 1 | 1 | English | | 2 | 1 | Chinese | | 3 | 2 | English | | 4 | 2 | Japanese | +----+------------+------------+ I would like to get the result all student, who have taken English and Chinese, NOT English or Chinese. Expected result: +----+------------+------------+ | id | student_id | course_name| +----+------------+------------+ | 1 | 1 | English | | 2 | 1 | Chinese | +----+------------+------------+ What we normally do is select * from student join course on (student.id = course.student_id) WHERE course_name = 'English' OR course_name = 'Chinese' but in this result I can get User2 record which is not my expected result. I want the record only display the User take the course English+Chinese only.

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  • Help with a MySQL SELECT WHERE Clause

    - by Dr. DOT
    A column in my table contains email addresses. I have a text string that contains the a few usernames of email addresses separated by commas. I can make text sting into an array if necessary to get my SELECT WHERE clause to work correctly. Text string search argument is 'bob,sally,steve' I want to produce a WHERE clause that only returns rows where the username portion of the email address in the table matches one of the usernames in my text string search argument. Thus a row with [email protected] would not be returned but [email protected] would be. Does anyone have a WHERE clause sample that produces this result? Thanks.

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  • Zend Framework Relations vs. Table Select

    - by rtmilker
    Hey! I just want to know your guys opinion on using join tables within the zend framework. Of course you can use relations by defining a referenceMap and dependentTables and stuff, or using setIntegrityCheck(false) within a db select(). The setIntegrityCheck version seems a little bit dirty to me, but the other version is not very suitable for big querys and joining many tables... I'm a PHP developer for 5 years now and new to the zend framework and just want get a direction for my first project. Thanks!!!

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