Search Results

Search found 33911 results on 1357 pages for 'mysql select'.

Page 123/1357 | < Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >

  • select mysql data using MAX

    - by JPro
    I have a testdata like this: DROP TABLE SELECT_PASS; CREATE TABLE SELECT_PASS(ID INT(20),TESTCASE VARCHAR(20),RESULT VARCHAR(20)); INSERT INTO SELECT_PASS VALUES(1,"TC1","PASS"); INSERT INTO SELECT_PASS VALUES(2,"TC2","PASS"); INSERT INTO SELECT_PASS VALUES(3,"TC3","INCONC"); INSERT INTO SELECT_PASS VALUES(4,"TC1","FAIL"); INSERT INTO SELECT_PASS VALUES(5,"TC21","FAIL"); INSERT INTO SELECT_PASS VALUES(6,"TC4","PASS"); INSERT INTO SELECT_PASS VALUES(7,"TC3","PASS"); INSERT INTO SELECT_PASS VALUES(8,"TC2","PASS"); INSERT INTO SELECT_PASS VALUES(9,"TC1","TIMEOUT"); SELECT TESTCASE, MAX(RESULT) FROM SELECT_PASS GROUP BY TESTCASE; The resultset I get is : TC1 TIMEOUT TC2 PASS TC21 FAIL TC3 PASS TC4 PASS Basically I want to see those testcases which never passed. Any way to do it? Thanks.

    Read the article

  • mysql select from multi tables problem

    - by moustafa
    this is the query SELECT members.memberID, members.salutation, members.firstName, members.middleName, members.lastName, members.suffix, members.company, addresses.address1, addresses.address2, addresses.city, addresses.state, addresses.postalCode, addresses.country, addresses.memberID, email.email, email.memberID, phonenumbers.phoneNumber, phonenumbers.memberId, subscriptions.year, subscriptions.memberID FROM members, addresses, email, phonenumbers, subscriptions WHERE subscriptions.year = '%s' AND subscriptions.memberID = members.memberID AND subscriptions.memberID = addresses.memberID AND subscriptions.memberID = email.memberID AND subscriptions.memberID = phonenumbers.memberID ORDER BY members.lastName, members.firstName, members.company LIMIT 0, 10 my problem is its a huge query so Im trying to limit it to so many at a time... its supposed to have over 5000 results... anyway the only limit that works is limit 0, 10 if you do anything else 5, 10 it doesnt work 0, 50 doesnt work... only 0, 10 works... and when I do 0, 10 the query returns blake firstName, middleName, lastName, and a few others... and when I do a print_r() on the $result it shows them blank as well and there is most def data in the database and there is also no typos for that...

    Read the article

  • Select one column from a row in hibernate

    - by ComfortablyNumb
    I am trying to do a simple query to get a unique result back in hibernate here is my code. public String getName(Integer id) { Session session = getSessionFactory().openSession(); String name = (String)session.createSQLQuery("SELECT name FROM users WHERE user_id = :userId").setParameter("userId", id).uniqueResult(); return name; } The name that is being returned is stored as HTML text that includes html syntacx language. I think this is what is causing the problem but it doesnt make sense I just want to return it as a string. It is only happening on this one field name, I can get every other field in the row but this one it gives me the error. I am getting an exception. The exception I am getting is No Dialect mapping for JDBC type: -1; nested exception is org.hibernate.HibernateException How do you query for a specific column on a row in hibernate?

    Read the article

  • MySQL SELECT WHERE returning empty with long numbers, although they are there

    - by brybam
    Alright, so basically the most simple query ever... I've done this a million times... SELECT * FROM purchased_items WHERE uid = '$uid' if $uid == 123 It works fine and returns all data in rows where uid is 123 if $uid == 351565051447743 It returns empty... I'm positive 351565051447743 is a possible uid in some rows, i literally copied and pasted it into the table. $uid is a string, and is being passed as a string. This is something i've done a million times, and i've never had this simple query not work. Any ideas why this is not working?

    Read the article

  • select similar value from MySQL and order the result

    - by mathew
    how do I order this result?? $range = 5; // you'll be selecting around this range. $min = $rank - $range; $max = $rank + $range; $limit = 10; // max number of results you want. $result = mysql_query("select * from table where rank between $min and $max limit $limit"); while($row = mysql_fetch_array($result)) { echo $row['name']."&nbsp;-&nbsp;".$row['rank']."<br>"; }

    Read the article

  • Select past date from database x days from now

    - by Pr0no
    Consider the following table daterange _date trading_day ------------------------ 2011-08-01 1 2011-07-31 0 2011-07-30 0 2011-07-29 1 2011-07-28 1 2011-07-27 1 2011-07-26 1 2011-07-25 1 2011-07-24 0 2011-07-23 0 2011-07-22 1 2011-07-21 1 2011-07-20 1 2011-07-19 1 2011-07-18 1 2011-07-17 0 I'm in need of a query that returns a _date, x days before a given _date. When counting back, _days with trading_day = 0 should be ignored. A few examples: input | output -------------------------+------------ 1 day before 2011-07-19 | 2011-07-18 2 days before 2011-08-01 | 2011-07-28 (trading_day = 0 don't count) 3 days before 2011-07-29 | 2001-07-26 The first one is easy: SELECT _date FROM daterange WHERE trading_day = 0 AND _date < '2011-07-19' LIMIT 1 But I don't know how to query for the other examples. Do you?

    Read the article

  • Insert into select and update in single query

    - by Ossi
    I have 4 tables: tempTBL, linksTBL and categoryTBL, extra on my tempTBL I have: ID, name, url, cat, isinserted columns on my linksTBL I have: ID, name, alias columns on my categoryTBL I have: cl_id, link_id,cat_id on my extraTBL I have: id, link_id, value How do I do a single query to select from tempTBL all items where isinsrted = 0 then insert them to linksTBL and for each record inserted, pickup ID (which is primary) and then insert that ID to categoryTBL with cat_id = 88. after that insert extraTBL ID for link_id and url for value. I know this is so confusing, put I'll post this anyhow... This is what I have so far: INSERT IGNORE INTO linksTBL (link_id,link_name,alias) VALUES(NULL,'tex2','hello'); # generate ID by inserting NULL INSERT INTO categoryTBL (link_id,cat_id) VALUES(LAST_INSERT_ID(),'88'); # use ID in second table I would like to add here somewhere that it only selects items where isinserted = 0 and iserts those records, and onse inserted, will change isinserted to 1, so when next time it runs, it will not add them again.

    Read the article

  • Check if the current date is between two dates + mysql select query

    - by kj7
    I have following table : id dateStart dateEnd active 1 2012-11-12 2012-12-31 0 2 2012-11-12 2012-12-31 0 I want to compare todays date in between dateStart and dateEnd. Following is my query for this : $todaysDate="2012-26-11"; $db = Zend_Registry::get("db"); $result = $db->fetchAll("SELECT * FROM `table` WHERE active=0 AND {$todaysDate} between dateStart and dateEnd"); return $result; But its not working. Any solution. Thanks in advance.

    Read the article

  • select distinct over specific columns

    - by Midhat
    A query in a system I maintain returns QID AID DATA 1 2 x 1 2 y 5 6 t As per a new requirement, I do not want the (QID, AID)=(1,2) pair to be repeated. We also dont care what value is selected from "data" column. either x or y will do. What I have done is to enclose the original query like this SELECT * FROM (<original query text>) Results group by QID,AID Is there a better way to go about this? The original query uses multiple joins and unions and what not, So I would prefer not to touch it unless its absolutely necesary

    Read the article

  • INSERT INTO othertbl SELECT * tbl

    - by Harry
    Current situation: INSERT INTO othertbl SELECT * FROM tbl WHERE id = '1' So i want to copy a record from tbl to othertbl. Both tables have an autoincremented unique index. Now the new record should have a new index, rather then the value of the index of the originating record else copying results in a index not unique error. A solution would be to not use the * but since these tables have quite some columns i really think it's getting ugly. So,.. is there a better way to copy a record which results in a new record in othertbl which has a new autoincremented index without having to write out all columns in the query and using a NULL value for the index. -hope it makes sense....-

    Read the article

  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

    Read the article

  • Mysql SELECT and INSERT Error

    - by nepaliking
    I am using sort field in order to sort records. My code is this $query = "SELECT max(sort) FROM $this->table LIMIT 1;"; $result = mysql_query($query); $row = mysql_fetch_row($result); $sort = $row[0]+1; $query = "INSERT INTO "$this->table." VALUES ( '', '$ini', '$time', '$ip', '0', '$type', '$sort', '$title', '$image', '0' );"; $result = mysql_query($query) or die(mysql_error()); What is the error here?

    Read the article

  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

    Read the article

  • how to define service runlevel order position?

    - by DmitrySemenov
    I setup bind-dlz and need mysql start prior NAMED when system starts here is what I have [root@semenov]# ./test.sh mysql 0:off 1:off 2:on 3:on 4:on 5:on 6:off named 0:off 1:off 2:off 3:on 4:on 5:on 6:off lrwxrwxrwx. 1 root root 15 Apr 15 18:57 /etc/rc3.d/S93mysql -> ../init.d/mysql lrwxrwxrwx. 1 root root 15 Apr 15 18:57 /etc/rc3.d/S90named -> ../init.d/named here is what I have in mysql init script # Comments to support chkconfig on RedHat Linux # chkconfig: 2345 84 16 # description: A very fast and reliable SQL database engine. # Comments to support LSB init script conventions ### BEGIN INIT INFO # Provides: mysql # Required-Start: $local_fs $network $remote_fs # Should-Start: ypbind nscd ldap ntpd xntpd # Required-Stop: $local_fs $network $remote_fs # Default-Start: 2 3 4 5 # Default-Stop: 0 1 6 # Short-Description: start and stop MySQL # Description: MySQL is a very fast and reliable SQL database engine. ### END INIT INFO so when I remove named from chkconfig and have there just mysql, it starts with order number 84: /etc/rc3.d/S84mysql - ../init.d/mysql but when I add named inside chkconfig it's order changes to 93: /etc/rc3.d/S93mysql - ../init.d/mysql as a result mysql will be starting after named and named will fail (no sql available) any ideas what I'm doing wrong? here is what I have in named init script # chkconfig: 345 90 16 # description: named (BIND) is a Domain Name Server (DNS) \ # that is used to resolve host names to IP addresses. # probe: true ### BEGIN INIT INFO # Provides: $named # Required-Start: $local_fs $network $syslog # Required-Stop: $local_fs $network $syslog # Default-Start:2 3 4 # Default-Stop: 0 1 2 3 4 5 6 # Short-Description: start|stop|status|restart|try-restart|reload|force-reload DNS server # Description: control ISC BIND implementation of DNS server ### END INIT INFO thanks, Dmitry

    Read the article

  • Wordpress SQL Select Multiple Meta Values / Meta Keys / Custom Fields

    - by Wes
    I am trying to modify a wordpress / MySQL function to display a little more information. I'm currently running the following query that selects the post, joins the 'postmeta' and gets the info where the meta_key = _liked function most_liked_posts($numberOf, $before, $after, $show_count) { global $wpdb; $request = "SELECT ID, post_title, meta_value FROM $wpdb->posts, $wpdb->postmeta"; $request .= " WHERE $wpdb->posts.ID = $wpdb->postmeta.post_id"; $request .= " AND post_status='publish' AND post_type='post' AND meta_key='_liked' "; $request .= " ORDER BY $wpdb->postmeta.meta_value+0 DESC LIMIT $numberOf"; $posts = $wpdb->get_results($request); foreach ($posts as $post) { $post_title = stripslashes($post->post_title); $permalink = get_permalink($post->ID); $post_count = $post->meta_value; echo $before.'<a href="' . $permalink . '" title="' . $post_title.'" rel="nofollow">' . $post_title . '</a>'; echo $show_count == '1' ? ' ('.$post_count.')' : ''; echo $after; } } The important part being: $post_count = $post->meta_value; But now I want to also grab a value that is attached to each post called wbphoto How do I specify that $post_count = _liked and $photo = wbphoto ? Here is a screen cap of my Phpmyadmin

    Read the article

  • Access denied error on select into outfile using Zend

    - by Peter
    Hi, I'm trying to make a dump of a MySQL table on the server and I'm trying to do this in Zend. I have a model/mapper/dbtable structure for all my connections to my tables and I'm adding the following code to the mappers: public function dumpTable() { $db = $this->getDbTable()->getAdapter(); $name = $this->getDbTable()->info('name'); $backupFile = APPLICATION_PATH . '/backup/' . date('U') . '_' . $name . '.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $name"; $db->query( $query ); } This should work peachy, I thought, but Message: Mysqli prepare error: Access denied for user 'someUser'@'localhost' (using password: YES) is what this results in. I checked the user rights for someUser and he has all the rights to the database and table in question. I've been looking around here and on the net in general and usually turning on "all" the rights for the user seems to be the solution, but not in my case (unless I'm overlooking something right now with my tired eyes + I don't want to turn on "all" on my production server). What am I doing wrong here? Or, does anybody know a more elegant way to get this done in Zend?

    Read the article

  • Algorithm To Select Most Popular Places from Database

    - by Russell C.
    We have a website that contains a database of places. For each place our users are able to take one of the follow actions which we record: VIEW - View it's profile RATING - Rate it on a scale of 1-5 stars REVIEW - Review it COMPLETED - Mark that they've been there WISH LIST - Mark that they want to go there FAVORITE - Mark that it's one of their favorites In our database table of places each place contains a count of the number of times each action above was taken as well as the average rating given by users. views ratings avg_rating completed wishlist favorite What we want to be able to do is generate lists of the top places using the above information. Ideally, we would want to be able to generate this list using a relatively simple SQL query without needing to do any legwork to calculate additional fields or stack rank places against one another. That being said, since we only have about 50,000 places we could run a nightly cron job to calculate some fields such as rankings on different categories if it would make a meaningful difference in the overall results of our top places. I'd appreciate if you could make some suggestions on how we should think about bubbling the best places to the top, which criteria we should weight more heavily, and given that information - suggest what the MySQL query would need to look like in order to select the top 10 places. One thing to note is that at this time we are less concerned with the recency of a place being popular - meaning that looking at the aggregate information is fine and that more recent data doesn't need to be weighted more heavily. Thanks in advance for your help & advice!

    Read the article

  • MYSQL - SELECT ALL FROM TABLE if...

    - by hornetbzz
    Hello I have a (nice) mysql table built like this : Fields Datas id (pk) 1 2 3 4 5 6 master_id 1000 1000 1000 2000 2000 2000 ... master_name home home home shop shop shop ... type_data value common client value common client ... param_a foo_a 1 0 bar_a 0 1 ... param_b foo_b 1 0 bar_b 1 0 ... param_c foo_c 0 1 bar_c 0 1 ... ... ... ... ... ... ... ... ... All these datas are embed in a single table. Each datas are dispatched on 3 "columns" set (1 for the values, 1 for identifying if these are common values and one for identifying client values). It's not the best I got but many other scripts depends on this structure. I'd need sthg like this: SELECT parameters name (eg param_a, param_b..) and their values (eg foo_a, foo_b..) WHEN master_id=? AND type_data=(common or client) (eg for values=1 on the 2nd column) . in order to get the parameters hash like param_a => foo_a param_b => foo_b param_c => foo_c ... I could not succeed in self joining on the same table till now but I guess it should be feasible. (I'd like to avoid to do several queries) Thx in advance

    Read the article

  • mySQL select and group by values

    - by Foo
    I'd like to count and group rows by specific values. This seems fairly simple, but I can't seem to do it. I have a table set up similar to this: Table: Ratings id pID uID rating 1 1 2 7 2 1 7 7 3 1 5 4 4 1 1 1 id is the primary key, piD and uID are foreign-keys. Rating contains values between 1 and 10, and only between 1 and 10. I want to run some statistics and count the number of ratings with a certain value. In the example above, two have left a rating of 7. So I wrote the following query: SELECT COUNT(*) AS 'count' , 'rating' FROM 'ratings' WHERE pID= '1' GROUP BY `rating` ORDER BY `rating` Which yields the nice result as: count ratings 1 1 1 4 2 7 I'd like to get the mySQL query to include values between 1 and 10 as well. For example: Desired Result count ratings 1 1 0 2 0 3 1 4 0 5 0 6 2 7 0 8 0 9 0 10 Unfortunately, I'm relatively new to SQL and I've been reading through everything I could get my hands on for the past hour, but I can't get it to work. I've been leaning along the lines of a some type of JOIN. If anyone can point me in the right direction, it'd be appreciated. Thanks.

    Read the article

  • Count Email Address Domains

    - by BRADINO
    A quick tidbit I came up with today to count email addresses in a mysql database table grouping them by domain. So say for example you have a large list of subscribers and you want to see the breakdown of people who use Hotmail, Yahoo, Gmail, etc. SELECT COUNT( SUBSTRING_INDEX( `email` , '@', -1 ) ) AS `count` , SUBSTRING_INDEX( `email` , '@', -1 ) AS `domain` FROM `subscribers` WHERE `email` != '' GROUP BY `domain` ORDER BY `count` DESC This sql statement assumes that the table is called 'subscribers' and the column containing the email addresses is 'email'. Change these two values to match your table name and email address column name. mysql count email mysql count domain mysql split email mysql split domain

    Read the article

  • Fatal error encountered during command execution with a mySQL INSERT

    - by Brian
    I am trying to execute a INSERT statement on a mySQL DB in C#: MySqlConnection connection = new MySqlConnection("SERVER=" + _dbConnection + ";" + "DATABASE=" + _dbName + ";" + "PORT=" + _dbPort + ";" + "UID=" + _dbUsername + ";" + "PASSWORD=" + _dbPassword + ";"); MySqlDataAdapter adapter; DataSet dataset = new DataSet(); command = new MySqlCommand(); command.Connection = connection; command.CommandText = "INSERT INTO plugins (pluginName, enabled) VALUES (@plugin,@enabled)"; command.Parameters.AddWithValue("@name", "pluginName"); command.Parameters.AddWithValue("@enabled", false); adapter = new MySqlDataAdapter(command); adapter.Fill(dataset); The plugin table consists of two columns: pluginName(varchar(50)) and enabled(boolean). This fails with the error: mysql Fatal error encountered during command execution. Any ideas on why this would fail?

    Read the article

  • mysqldump from a query

    - by Hulk
    How do we take a mysql dump from the results of a query I need something like this.. `mysqldump -uroot -pxxxx mydb "select * from table where name='1';" /tmp/a Thanks

    Read the article

  • Update to php5.3 breaks connecting to mysql db

    - by bobbyb
    I just updated php to 5.3 and can no longer connect to my remote mysql server. I get the following errors: mysqli_connect(): OK packet 6 bytes shorter than expected mysqli_connect(): (HY000/2000): mysqlnd cannot connect to MySQL 4.1+ using old authentication It seems this has to do with the new mysqlnd driver. Is there a way to force it to use the old libmysql driver. Also, reverting to php5.2.11 doesn't seem to fix the issue which seems to work for most people. Anyone have any suggestions? thanks!

    Read the article

  • Setup Padrino with DataMapper and MySQL database

    - by Ivo Sabev
    Hello I am trying to setup a Padrino project using DataMapper and MySQL on my Mac OSX Snow Leopard. I have the necessary gems: dm-core data_objects do_mysql mysql (linked to my original Mac OSX installation) But when I try to start the padrino with PADRINO START from the console, I get the following error: /Users/ivolution/.bundle/ruby/1.9.1/gems/dm-core-0.10.2/lib/dm-core/adapters/mysql_adapter.rb:3:in `require': no such file to load -- do_mysql (LoadError) But as I said I do have do_mysql gem installed so there shouldn't be such error, I did bundle install in my project folder before trying to start Padrino. Any ideas?

    Read the article

  • iPhone SDK mySQL

    - by Kevin
    Hello everybody, I'm starting on a new iPhone project, and this application mostly relies on mySQL. I have a mysql database running on my computer, and I need this application to send queries to the server to gain information. One example is creating and logging into an account. I have successfully done this on my windows vb.net application, but I know that objective c will be harder. This is basically getting text from the sql database and displaying it on the iPhone application. If someone could simply help me on that, I'll easily get started. So I hope that you guys help me out here :). Thanks Kevin

    Read the article

< Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >