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  • accessing SQL syntax reference in mysql workbench

    - by dcompiled
    Finding it a little bit tedious migrating to the new Mysql Workbench (5.2.22) even though it has many more features than the older GUI tools. Right now I'm confused why I can't find an SQL reference when I open the Doc Library. Is there a way to access this info within the workbench, I'd prefer not to have to open a browser to access reference info on the web.

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  • changing mysql password via java

    - by Osama Abukmail
    I'm trying to change a user's password on mysql using java, i successfully changed it on phpmyadmin but same command doesnt work on java SET PASSWORD = PASSWORD('12345') this command will change the current logged in user, i have tried it on java like this statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD = PASSWORD('12345')"); but nothing happened i also tried this with root logged in statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD FOR 'username'@'localhost' = PASSWORD('123456')"); and nothing work,, any help please

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  • Efficient way to build a MySQL update query in Python

    - by ensnare
    I have a class variable called attributes which lists the instance variables I want to update in a database: attributes = ['id', 'first_name', 'last_name', 'name', 'name_url', 'email', 'password', 'password_salt', 'picture_id'] Each of the class attributes are updated upon instantiation. I would like to loop through each of the attributes and build a MySQL update query in the form of: UPDATE members SET id = self._id, first_name = self._first name ... Thanks.

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  • Not able to create a datasource registration with WAMP MysQL 5.0 in DBArtisan

    - by Alf Christophersen
    I try in a test version of DBArtisan to set up a datasource and register both servere as localhost, database to use, my username and password, but, when testing the connection, I get message that connection failed. Hooking up from eg. Delphi and other utilities run nicely. But not DBArtisan, Is MySQL 5.0 not supported yet ?? Or is it WAMP that is the culprit naming the service wampmysqld insted of just mysqld ??

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  • mysql category tree search

    - by ffffff
    I have the following schema on MySQL 5.1 CREATE TABLE `mytest` ( `category` varchar(32) , `item_name` varchar(255) KEY `key1` (`category`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; category column is filled with like that [:parent_parent_cat_id][:parent_cat_id][:leaf_cat_id] "10000200003000" if you can search all of the under categories :parent_parent_category_id SELECT * FROM mytest WHERE category LIKE "10000%"; it's using index key1; but How to use index when I wanna search :parent_cat_id? SELECT * FROM mytest WHERE category LIKE "%20000%"; Do you have a better solutions?

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  • Table character encoding - exception in application

    - by zgnilec
    I have a code: CREATE TABLE IF NOT EXISTS Person ( name varchar(24) ... ) CHARACTER SET utf8 COLLATE utf8_polish_ci; This works OK in my application, but I read if someone put in name field a string that contains character wchich code is greater than 127, database will use 2 bytes (or more) to store this character. So i think, i will change character set to utf16: CHARACTER SET utf16 COLLATE utf16_polish_ci; But now when I run my application, exception apears: KeyNotFoundException. It apears exactly at these instructions: MySqlCommand komenda = baza.Polaczenie.CreateCommand (); komenda.CommandText = zapytanie; MySqlDataReader dr = komenda.ExecuteReader (); // HERE, at execute reader method if (dr.Read ()) ... 1) Anyone had similar problem? 2) Any idea how to use always 2 bytes/char in database field?

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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  • MYSQL and Array with PHP for create Tag Cloud

    - by asilloo
    Hi, I'm trying to make a Tag cloud for every user in own page, I'm using PHP5 and Mysql, My table named "tags" and I want to make a array but in short way. The table like below, The array can be like for user1 array={[car,1],[cat,null],[pen,1],[dvd,1],[cd,null]} Username totaltag tag1 tag2 tag3 tag4 tag5 admin 5 car cat pen dvd cd user1 1 1 1 user2 1 2 12 1 user3 3 2 10 1

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  • mysql get last auto increment value

    - by Mick
    Hi I have a field in mySql table called jobnumber which auto increments with each new entry. What I want to do is when a user views my form, get the value of the next 'jobnumber' . But I want to do this before any entry is made to the table. IE so when a user looks at a form it will display something like 'this is job number 6954' I have tried $rr = mysql_insert_id() but this only work after I have made an entry Can anyone help please thanks

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  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

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  • ORDERING A MYSQL QUERY WITH JOINS AND GROUPS

    - by Oliver
    I have this mysql query: SELECT * FROM Customer c JOIN eHRDemographic ehD ON ehD.CxID = c.CustomerID JOIN CustPrimaryWeight cpW ON cpW.CxID = c.CustomerID WHERE c.CustomerID =22703 GROUP BY c.CustomerID ORDER BY cpW.CustPrimaryWeightID DESC This doesn't really work correctly as the CustPrimaryWeight table has multiple enteries and it's simply joining the first entry and not the more recent one as the ORDER statement doesn't seem to do anything. Any ideas?

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  • Unique text field in MySQL and php

    - by Jonathan
    I've created a salt using; md5(rand(0,10000000)); (there is probably a better way?) There doesn't seem to be possible to make a text field unique in MYSQL. So how do I check if the salt has already been used for a previous user? Or should I generate the salt based on the current date/time? as it is impossible for 2 users to register at exactly the same time correct?

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  • Which MySql line is faster:

    - by Camran
    I have a classified_id variable which matches one document in a MySql table. I am currently fetching the information about that one record like this: SELECT * FROM table WHERE table.classified_id = $classified_id I wonder if there is a faster approach, for example like this: SELECT 1 FROM table WHERE table.classified_id = $classified_id Wont the last one only select 1 record, which is exactly what I need, so that it doesn't have to scan the entire table but instead stops searching for records after 1 is found? Or am I dreaming this? Thanks

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  • easy mysql query question

    - by Ahmet vardar
    Hi, here is the "msg" table on mysql sent_to customer msg read ------- -------- ------ ----- 45 3 bla 0 34 4 bla 1 34 6 bla 0 45 3 bla 0 56 7 bla 1 45 8 bla 0 for example user whose id number is 45 logs in, i want him to see this, you have 2 unread msg to your "number 3" customer you have 1 unread msg to your "number 8" customer like a news feed what query should i use for this ? thx

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  • mysql command for update

    - by Mac Taylor
    hey guys i need to add a special text to all rows in my mysql table , how to add some text to the end of all rows' content in a table just for one field i used this code : UPDATE `blogs` SET `title`= `title`+ 'mytext'; but didnt work for me

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