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  • SubSonic isn't generating MySql foreign key tables

    - by keith
    I two tables within a MySql 5.1.34 database. When using SubSonic to generate the DAL, the foreign-key relationship doesn't get scripted, ie; I have no Parent.ChildCollection object. Looking inside the generated DAL Parent class shows the following; //no foreign key tables defined (0) I have tried SubSonic 2.1 and 2.2, and various MySql 5 versions. I must be doing something wrong procedurally - any help would be greatly appreciated. This has always just worked 'out-the-box' when using MS-SQL. TABLE `parent` ( `ParentId` INT(11) NOT NULL AUTO_INCREMENT, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1; TABLE `child` ( `ChildId` INT(11) NOT NULL AUTO_INCREMENT, `ParentId` INT(11) NOT NULL, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ChildId`), KEY `FK_child` (`ParentId`), CONSTRAINT `FK_child` FOREIGN KEY (`ParentId`) REFERENCES `parent` (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1;

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  • Mysql query - problem with order by

    - by Sergio
    I'm using two tables for selecting messages between users. Table "messages" for recording the messages and table "members" for checking users data (are they activ or deleted). This query working fine. What I need to do is list the received messsages order by last received. I tried to do with "ORDER BY messages.id DESC" at the end of this query but it didn't work. All messages are listed from first received. This is the mysql join table query that I'm using: sql = "select distinct messages.fromid, messages.readed, messages.fromid, messages.toid, members.id as pid From messages Inner Join members on members.id = messages.fromid Where messages.toid = ".$mid." AND members.status = 7 AND messages.kreaded !='1' AND messages.subject != 'readed' GROUP BY fromid" Is there any way to do this?

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  • Splitting a MySQL DB in two may ease server from "Too many connetions"? I don't think so

    - by Petruza
    I was requested to split a MySQL in two, it's kind of a horizontal partition, in which some rows correspond to one site, and some other correspond to another site. But they want to split it in two DBs in the same MySQL server. I'm no DB expert but I guess keeping them in the same MySQL server with the same amount of memory and processor and the same platform won't improve things. What we're trying to avoid is the "Too many connections" problem.

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  • Unix timestamp and mysql date: birthdate

    - by Mikk
    Hi, I have a really basic question concerning unix timestamp and mysql date. I'm trying to build a small website where users can register and fill in their birthdate. Problem is that unix starts with Jan 01 1970. Now if i calculate age for users, form dates like date('m.d.Y', $unix_from_db) and so on it will fail with users older that 40 years, right? So what would be the rigth way for doing this. Sorry, for basic question like this, but I'm inexperienced with php and mysql.

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  • MySQL with Java: Open connection only if possible

    - by emempe
    I'm running a database-heavy Java application on a cluster, using Connector/J 5.1.14. Therefore, I have up to 150 concurrent tasks accessing the same MySQL database. I get the following error: Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Too many connections This happens because the server can't handle so many connections. I can't change anything on the database server. So my question is: Can I check if a connection is possible BEFORE I actually connect to the database? Something like this (pseudo code): check database for open connection slots if (slot is free) { Connection cn = DriverManager.getConnection(url, username, password); } else { wait ... } Cheers

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  • Select in a many-to-many relationship in MySQL

    - by Joff Williams
    I have two tables in a MySQL database, Locations and Tags, and a third table LocationsTagsAssoc which associates the two tables and treats them as a many-to-many relationship. Table structure is as follows: Locations --------- ID int (Primary Key) Name varchar(128) LocationsTagsAssoc ------------------ ID int (Primary Key) LocationID int (Foreign Key) TagID int (Foreign Key) Tags ---- ID int (Primary Key) Name varchar(128) So each location can be tagged with multiple tagwords, and each tagword can be tagged to multiple locations. What I want to do is select only Locations which are tagged with all of the tag names supplied. For example: I want all locations which are tagged with both "trees" and "swings". Location "Park" should be selected, but location "Forest" should not. Any insight would be appreciated. Thanks!

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  • Alternative to 'where col in (list)' for MySQL

    - by user210481
    Hi I have the following table T: id 1 2 3 4 col a b a c I want to do a select that returns the id,col when group by(col) having count(col)1 One way of doing it is SELECT id,col FROM T WHERE col IN (SELECT col FROM T GROUP BY(col) HAVING COUNT(col)>1); The intern select (from the right) returns 'a' and main one (left) will return 1,a and 3,a The problem is that the where in statement seems to be extremely slow. In my real case, the results from the internal select has many 'col's, something about 70000 and it's taking hours. Right now it's much faster to do the internal select and the main select getting all ids and upcs and do the intersection locally. MySQL should be able to handle this kind of query efficiently. Can I substitute the where in for a join or something faster? Thanks

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  • Question about Radio button/PHP/MySQL

    - by Marcelo
    Hi, I'm an engineering student and I'm developing a simple software based on HTML, PHP and mysql. I learned this topics on w3schools. I know only the basics. I tried to search about this in this website but I found questions about PHP, MySQL and HTML radio buttons which were much more complex than I need and that I could understand. Sorry for the English. (Q1) Ex: $email=$_REQUEST['email'] , in this case the input is text, if it where like a radio button for ex: sex: male or female, how would it be? (Q2) what would be the type of this field (for exemple sex in question 1) in the database: text, int, varchar ? Thanks for the attention

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  • MySQL different versions other results.

    - by kuba
    hey, i have 2 version of mysql on windows 5.1.39-community and on linux 5.1.39-log i execute a query: SELECT `o`.`idOffer`, `o`.`offer_date`, `p`.`factory`, `c`.`short` AS `company`, `s`.`name` AS `subcategory`, `ct`.`name` AS `category`, count( (select count(1) from product where idProduct=idOffer group by idOffer) ) as b FROM `Offer` AS `o` LEFT JOIN `Product` AS `p` ON o.idOffer = p.idOffer LEFT JOIN `company` AS `c` ON o.company = c.id LEFT JOIN `Subcategory` AS `s` ON s.idSubcategory = o.idSubcategory LEFT JOIN `Category` AS `ct` ON ct.idCategory = s.idCategory WHERE (o.idOffer = p.idOffer) GROUP BY `o`.`idOffer` on windows it works as it suppose, but on linux it says: ERROR 1242 (21000): Subquery returns more than 1 row is it any way to get it worked on linux without any mysql updates/downgrades ?

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  • MYSQL Query with 2 columns in Table A related to 1 column in Table B

    - by CYREX
    I have 2 Tables, User and Mail. In User Table i have 2 columns that i will use, the ID column which makes the relation with the Mail Table and it is the Index of User Table and the Name column. In Mail Table i have Receiver Column and Sender Column. Both columns, Receiver and Sender have a number that relates to the ID Column in the User Table. In the User Table is where the name columns resides and i want to make a query that shows me the Receiver and Sender Columns but with the name of the user, not the ID. Up to this point i have this: SELECT name AS Send, name AS Receive FROM mail,user WHERE sender=guid; I know there is still a part of the query missing but i can not figure out what else to put to tell it to show in the SEND output column the name of the sender and in the RECEIVE output column the name of the receiver.

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  • MySQL, join one item to multiple items in a single query

    - by bschaeffer
    Say I've got two tables. One contains a list of items, and one contains pictures of the items. Something like this: Items +----+---------+ | id | name | +----+---------+ | 1 | oranges | | 2 | apples | +----+---------+ Pictures +----+---------+ | id | item_id | +----+---------+ | 1 | 1 | | 2 | 2 | | 3 | 2 | +----+---------+ My question is this: is it possible in a single query to select item 2 from Items and join all the rows in the Pictures table whose item_id references that same id? I am sure I've tried almost everything I can think of, but nothing is coming to mind. I apologize if the answer to this is simple, but It's just escaping me right now.

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  • How to SET tiggers 0 in MySQL?

    - by Grijesh Chauhan
    In my MySQL database I have some Triggers ON DELETE and ON INSERT. Some time I need to switched-off my some Triggers, And I have to DROP e.g. DROP TRIGGER IF EXISTS hostgroup_before_insert // and reinstall. Is there any shortcut to SET triggers hostgroup_before_insert = 0 like we have for foreign keys mysql> SELECT version(); +-------------------------+ | version() | +-------------------------+ | 5.1.61-0ubuntu0.10.10.1 | +-------------------------+ 1 row in set (0.00 sec) I am new learner and I could not find regarding this on web.

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  • mysql_connect randomly hangs up

    - by sergdev
    I install php 5 (more precisely 5.3.1) as apache module. After this one of my application becomes randomly hang up on mysql_connect - sometimes works, sometimes no, sometimes reload of page helps. How can this be fixed? I use Windows Vista, Apache/2.2.14 (Win32) PHP/5.3.1 with php module, MySql 5.0.67-community-nt.

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  • mysql replace matching but not changing

    - by alex
    I've used mysql's update replace function before, but even though I think I'm following the same syntax, I can't get this to work-it matches the rows, but doesn't replace. Here's what I'm trying to do: mysql> update contained_widgets set preference_values = replace(preference_values, '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li>', '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li> <li> <a_href="/projects"><span class="not-tc">Projects</span></a></li>'); Query OK, 0 rows affected (0.00 sec) Rows matched: 77 Changed: 0 Warnings: 0 I don't see what I'm missing. Any help is appreciated. I edited "a " to "a_" because the site thinks I'm posting spam links otherwise.

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  • Finding shared list IDs in a MySQL table using bitwise operands

    - by landons
    I want to find items in common from the "following_list" column in a table of users: +----+--------------------+-------------------------------------+ | id | name | following_list | +----+--------------------+-------------------------------------+ | 9 | User 1 | 26,6,12,10,21,24,19,16 | | 10 | User 2 | 21,24 | | 12 | User 3 | 9,20,21,26,30 | | 16 | User 4 | 6,52,9,10 | | 19 | User 5 | 9,10,6,24 | | 21 | User 6 | 9,10,6,12 | | 24 | User 7 | 9,10,6 | | 46 | User 8 | 45 | | 52 | User 9 | 10,12,16,21,19,20,18,17,23,25,24,22 | +----+--------------------+-------------------------------------+ I was hoping to be able to sort by the number of matches for a given user id. For example, I want to match all users except #9 against #9 to see which of the IDs in the "following_list" column they have in common. I found a way of doing this through the "SET" datatype and some bit trickery: http://dev.mysql.com/tech-resources/articles/mysql-set-datatype.html#bits However, I need to do this on an arbitrary list of IDs. I was hoping this could be done entirely through the database, but this is a little out of my league. Any bit gurus out there? Thanks, Landon

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  • Selecting two field in MySQL with PHP

    - by Crays
    Hi guys, i'm relatively new to php and mysql and would like to know how to select two value in mysql with php. What i have is $query = sprintf("SELECT COUNT(id) FROM table WHERE UPPER(username) = UPPER('%s') AND password='%s'"... in this case, i'm only selecting and count if the id exist and i use list($count) = mysql_fetch_row($result); if($count == 1) and by using cookies, i would like to retrieve two value from the database, namely user (the user's name) and power (which has value of 1,2 or 3, indicating the menu they would be able to see) basically it is to differentiate if you're admin or normal user, but i wonder if i could do SELECT COUNT(id) AND power FROM table WHERE ... is this possible? or is there any other way? Please guide me, thanks.

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  • Why is this MySQL Join Statement not Working?

    - by Timmy
    Here is my code: $query2 = mysql_query("SELECT * FROM categories WHERE parent = $id JOIN SELECT * FROM posts WHERE main_nav_page = '$idTwo'"); while ($row2 = mysql_fetch_assoc($query2)) { $id = $row2['id']; $name = $row2['name']; $slug = $row2['slug']; $subMenuOrder = $row2['sub_menu_order']; echo "<tr>\n"; echo "<td>&nbsp; -- $name</td>\n"; echo "</tr>\n"; } Is my syntax wrong? EDIT: the error message is: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/studentw/public_html/new_nav.php on line 30

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  • Integrating Incoming Email Into a php/mysql App

    - by phirschybar
    I am looking to create an incoming email daemon switchboard that I can integrate with various remote php/mysql apps. Ideally I want to check the 'to' address to see if it is in a mysql database and if it is, have the email parsed and posted via CURL to a target destination as well as have attachments saved somewhere locally. I will likely set up a rackspace cloud server dedicated to this task (just accepting emails and posting to 3rd party APIs). However, I do not know where to start. Which server platform / distribution should I go with? Which software needs to be customized, etc?

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