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  • using union in a construct sparql query

    - by simon
    hello, i have such a sparql query: select ?s ?p ?o from <http://localhost:8890/DAV/ranking> where { {<http://seekda.com/providers/cdyne.com/PhoneNotify> so:hasEndpoint ?s. ?s ?p ?o} union {<http://seekda.com/providers/cdyne.com/PhoneNotify> ?p ?o} } but i need a graph query (construct ord describe). unfortunatly i have no clue about how to use unions in construct or describe queries. please help me best regards simon

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  • Find the % character in a LIKE query

    - by Jensen
    Hi, I've an SQL database and I would like to do a query who show all the datas containing the sign "%". Normally, to find a character (for example: "z") in a database I use a query like this : mysql_query("SELECT * FROM mytable WHERE tag LIKE '%z%'"); But here, I want to found the % character, but in SQL it's a joker so when I write: mysql_query("SELECT * FROM mytable WHERE tag LIKE '%%%'"); It show me all my datas. So how to found the % character in my SQL datas ? Thanks

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  • Date and time Query - problem

    - by Gold
    hi i try to run this query: select * from WorkTbl where ((Tdate = '20100414' AND Ttime = '06:00') and (Tdate <= '20100415' AND Ttime <= '06:00')) i have this date: 14/04/2010 and time: 14:00 i cant see hem, how to fix the query ? thank's in advance

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  • MySQL regexp on Indexes

    - by Vivek
    HI, I have query having multiple regexp in where clause. The coloumns contained in the where clause have already been indexed. But the query is not using the indexes. Does MySql regexp cause use of indexes ? If not, what could be the workaround for this ?

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  • Sanitizing MySQL user parameters.

    - by Tom
    What are the dangerous characters that should be replaced in user input when the users' input will be inserted in a MySQL query? I know about quotes, double quotes, \r and \n. Are there others?(I don't have the option of using a smart connector that accepts parameters so I have to build the query myself and this will be implemented in multiple programming languages, including some obscure ones so solutions such as mysql_real_escape_string in PHP are not valid)

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  • SQL Query with computed column

    - by plotnick
    help me please with a query. Assume that we have a table with columns: Transaction StartTime EndTime Now, I need a query with computed column of (value = EndTime-Startime). Actually I need to group Users(Transaction has a FK for Users) and sort them by average time spent for transaction.

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  • SQL query problem

    - by Pankaj
    Hello All I have 2 tables Project and ProjectList like this Project ProjectID Name ProjectListID - allow null In ProjectList ProjectListID ProjName Now what i need here, i want only those recoed from ProjectList table which ProjectListID not in Project table. I made a query but it is taking lot of time to execute. select * FROM projectslist pl where pl.ProjectsListID not in (SELECT p.ProjectsListID FROM project p where (p.ProjectsListID is not null and p.ProjectsListID <>0)) Please help me to create optimize query. I am using My SQL.

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  • Help with Query - Access

    - by yae
    Hi I have 4 tables: machines, categories, users and usersMAchines machines is linked to categories and usersMachines. Machines -------- idMachine machine idCat Categories -------- idCat category Users -------- idUser nameUser UsersMachines -------- idUserMachine idUser IdMachine To list machines, filtered for any field of 3 previous table, I have this query: select distinct machines.*,categories.category from( (machines left join UsersMachines on machines.idMachine=UsersMachines.idMachine) left join categories on machines.idcat=categories.idcat) Ok,runs fine. But Using the same query, how I can do to filter the machines that only have linked users ?

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  • MySQL won't use index for query?

    - by Jack Sleight
    I have this table: CREATE TABLE `point` ( `id` INT(11) NOT NULL AUTO_INCREMENT, `siteid` INT(11) NOT NULL, `lft` INT(11) DEFAULT NULL, `rgt` INT(11) DEFAULT NULL, `level` SMALLINT(6) DEFAULT NULL, PRIMARY KEY (`id`), KEY `point_siteid_site_id` (`siteid`), CONSTRAINT `point_siteid_site_id` FOREIGN KEY (`siteid`) REFERENCES `site` (`id`) ON DELETE CASCADE ) ENGINE=INNODB AUTO_INCREMENT=35 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci And this query: SELECT * FROM `point` WHERE siteid = 1; Which results in this EXPLAIN information: +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ | 1 | SIMPLE | point | ALL | point_siteid_site_id | NULL | NULL | NULL | 6 | Using where | +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ Question is, why isn't the query using the point_siteid_site_id index?

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  • SQL Server Query Question

    - by Lp1
    Running SQL Server 2008, and I am definitely a new SQL user. I have a table that has 4 columns: EmpNum, User, Action, Updatetime A user logs into, and out of a system, it is registered in the database. For example, if user1 logs into the system, then out 5 minutes later, a simple query (select * from update) would look like: EmpNum User Action Updatetime 1 User1 I 2010-01-01 23:00:00:000 1 User1 O 2010-01-01 23:05:00:000 I'm trying to query the Empnum, User, Action, I(in time), O(out time), and the total time.

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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • Difference of two series in MySQL

    - by Brian
    I have a table with the following fields in MySQL: date, Value, Type. Type can be either exports or imports. I want a query that returns the trade deficit (exports-imports) for each month. Is this possible with a single query?

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  • How to search multiple columns in MySQL?

    - by George
    I'm trying to make a search feature that will search multiple columns to find a keyword based match. This query: SELECT title FROM pages LIKE %$query%; works only for searching one column, I noticed separating column names with commas results in an error. So is it possible to search multiple columns in mysql?

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  • MySQL sub query

    - by Juddling
    UPDATE members SET money=money+100 WHERE username IN (SELECT username FROM forum); Lets say I wanted to give each of my members 100 money for each post in my forum. This query works but if one member has posted more than once, they only get 100. Could someone correct this query please?

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  • Convert sql query

    - by nisha
    I have used this query in sql,pls convert this query to use for access database. Table structure is UserID,Username,LogDate,LogTime WITH [TableWithRowId] as (SELECT ROW_NUMBER() OVER(ORDER BY UserId,LogDate,LogTime) RowId, * FROM @YourTable), [OddRows] as (SELECT * FROM [TableWithRowId] WHERE rowid % 2 = 1), [EvenRows] as (SELECT *, RowId-1 As OddRowId FROM [TableWithRowId] WHERE rowid % 2 = 0) SELECT [OddRows].UserId, [OddRows].UserName, [OddRows].LogDate, [OddRows].LogTime, [EvenRows].LogDate, [EvenRows].LogTime FROM [OddRows] LEFT JOIN [EvenRows] ON [OddRows].RowId = [EvenRows].OddRowId

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  • MySQL & PHP: auto connect to DB or to properly way to pass host/db to MySQL methods

    - by SODA
    Hi, does anyone know of a known method in PHP to auto connect to MySQL db/table in case an app is using multiple databases on multiple hosts? Question 1: are there scripts around that allow to auto connect to necessary host/DB based on query? Question 2: if above is not possible, is there a known approach to properly passing host/DB info to make sure app is properly connected before executing the query?

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • how to pass variables this in dynamic query

    - by Ranjana
    i using the dynamic query to pass the variables select a.TableName, COUNT(a.columnvalue) as '+'count'+' from Settings.ColumnMapping a where a.ColumnValue in ('+ @columnvalue +') and a.Value in (' + @value +') the @columnvalues = 'a','b','c' @value ='comm(,)','con(:)' how to pass this in dynamic query any idea???

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  • treat mysql longtext as integer in query

    - by InnateDev
    I have a set field in my db that is longtext. I have used prices in this field and cannot change the field type to integer. In my query however I need to sort by these fields and assume I should treat them as an integer. is there another way to query these results to sort by price as an integer and not longtext without having to change the field type? at the moment 3900000 is smaller than 4300 in my result set.

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  • Oracle Query for getting CURRENT CTC (Salary) of Each Employee

    - by reply2viveksshah
    i want current CTC of each employee following is the design of my table Ecode Implemented Date Salary 7654323 2010-05-20 350000 7654322 2010-05-17 250000 7654321 2003-04-01 350000 7654321 2004-04-01 450000 7654321 2005-04-01 750000 7654321 2007-04-01 650000 i want oracle query for following output Ecode Salary 7654321 650000 7654322 250000 7654323 350000 thanks in advance See also Oracle Query for getting MAximum CTC (Salary) of Each Employee

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  • MYSQL LIMIT not working as expected - Java

    - by Sirish
    I have this weird problem in java when trying to fetch records from MYSql database by using the limit function in the query. Not sure what went wrong or did wrong, this query is giving me a hard time. Issue - When I run this query through my java program it returns all the records and not limiting the records to 10 as given in the limit. The same query when ran in MYSql command line, it execute very well and fetches me only 10 recrods. Below is the java code and query. Any help or support is appreciated.! Java code - public UserVO getApplUserDetailsList(UserVO userVO) throws CAPDAOException { List<UserVO> returnList = null; String methodName = "getApplUserDetails()"; Session session = null; String queryString = null; Transaction transaction = null; PreparedStatement ps = null; ResultSet rs = null; if(userVO == null) { logger.writeToTivoliAlertLog(className, CAPConstants.ERROR, methodName, null, "userVO returned null. Busines validation error.!", null); throw new CAPDAOException("userVO returned null. Busines validation error.!",CAPException.BUSINESS_VALIDATION_ERROR_SECURITY); } try { returnList = new ArrayList<UserVO>(); System.out.println(""); String appusr = userVO.getAppUsrNm(); session = getSession(); transaction = session.beginTransaction(); if(userVO.getAppUsrRoleCd()!=null && !userVO.getAppUsrRoleCd().trim().equalsIgnoreCase(CAPConstants.DEFAULT_DROPDOWN_VALUE)){ queryString = "SELECT " + "APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, " + "APPL_USR_LST_NM,ACCESS_ROLE_CD " + "FROM APPL_USR " + "WHERE " + "APPL_USR_NM LIKE ?"+ " AND APPL_USR_FRST_NM LIKE ?"+ " AND APPL_USR_LST_NM LIKE ?"+ " AND ACCESS_ROLE_CD = ?"+ " AND APPL_USR_ID != ?"; ps = session.connection().prepareStatement(queryString); ps.setString(1,userVO.getAppUsrNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(2,userVO.getAppUsrFirstNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(3,userVO.getAppUsrLastNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(4,userVO.getAppUsrRoleCd()); ps.setInt(5, 1); } else { queryString = "SELECT " + "APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, " + "APPL_USR_LST_NM,ACCESS_ROLE_CD " + "FROM APPL_USR " + "WHERE " + "APPL_USR_NM LIKE ?"+ " AND APPL_USR_FRST_NM LIKE ?"+ " AND APPL_USR_LST_NM LIKE ?"+ " AND APPL_USR_ID != ?"; ps = session.connection().prepareStatement(queryString); ps.setString(1,userVO.getAppUsrNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(2,userVO.getAppUsrFirstNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(3,userVO.getAppUsrLastNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setInt(4, 1); } if(userVO.getQueryAction()!=null && userVO.getQueryAction().equals(CAPConstants.GET_DATA)) queryString += " ORDER BY APPL_USR_ID LIMIT " + userVO.getPAGE_MIN_LIMIT() + ", " + userVO.getPAGE_MAX_LIMIT(); else queryString += " ORDER BY APPL_USR_ID"; rs = ps.executeQuery(); if(userVO.getQueryAction()!=null && userVO.getQueryAction().equals(CAPConstants.GET_DATA)) { int tempCOunt = 0; while(rs!=null && rs.next()) { tempCOunt ++; UserVO returnVO = new UserVO(); returnVO.setAppUsrId(rs.getInt("APPL_USR_ID")); returnVO.setAppUsrNm(rs.getString("APPL_USR_NM")); returnVO.setAppUsrFirstNm(rs.getString("APPL_USR_FRST_NM")); returnVO.setAppUsrLastNm(rs.getString("APPL_USR_LST_NM")); if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.ADMINISTRATOR_ROLE_CD)) returnVO.setApplicationLevelRole("Administrator"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.MAINTAINER_ROLE_CD)) returnVO.setApplicationLevelRole("Maintainer"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.VIEWER_ROLE_CD)) returnVO.setApplicationLevelRole("Viewer"); else returnVO.setApplicationLevelRole("None"); returnList.add(returnVO); } System.out.println("Count >>>>>>>>>>>>>>>>>>> "+tempCOunt); userVO.setReturnListFromDB(returnList); } else { int rowcount = 0; if (rs.last()) { rowcount = rs.getRow(); rs.beforeFirst(); // not rs.first() because the rs.next() below will move on, missing the first element } userVO.setTotalRecordCount(rowcount); System.out.println("Total count of the records to be used for pagination >> "+rowcount); rowcount = 0; while(rs!=null && rs.next()) { rowcount ++; UserVO returnVO = new UserVO(); returnVO.setAppUsrId(rs.getInt("APPL_USR_ID")); returnVO.setAppUsrNm(rs.getString("APPL_USR_NM")); returnVO.setAppUsrFirstNm(rs.getString("APPL_USR_FRST_NM")); returnVO.setAppUsrLastNm(rs.getString("APPL_USR_LST_NM")); if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.ADMINISTRATOR_ROLE_CD)) returnVO.setApplicationLevelRole("Administrator"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.MAINTAINER_ROLE_CD)) returnVO.setApplicationLevelRole("Maintainer"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.VIEWER_ROLE_CD)) returnVO.setApplicationLevelRole("Viewer"); else returnVO.setApplicationLevelRole("None"); returnList.add(returnVO); System.out.println("Row count >>"+rowcount); if(rowcount == CAPConstants.PAGINATION_MAX_VALUE) break; } rowcount = 0; userVO.setReturnListFromDB(returnList); } System.out.println("returnList >>"+returnList); return userVO; } catch (Throwable e) { e.printStackTrace(); logger.writeToTivoliAlertLog(className, CAPConstants.ERROR, methodName, userVO.getAppUsrNm(), "Error occured while trying to fetch application user details. Printing stack trace to the log for analysis..", e); throw new CAPDAOException("Error occured while trying to fetch application user details.",CAPException.SPEXECUTION_ERROR_CODE); } finally{ closeTransactionAndSession(session,transaction); } } MYSQL Query - SELECT APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, APPL_USR_LST_NM,ACCESS_ROLE_CD FROM APPL_USR WHERE APPL_USR_NM LIKE '%' AND APPL_USR_FRST_NM LIKE '%' AND APPL_USR_LST_NM LIKE '%' AND APPL_USR_ID != 1 ORDER BY APPL_USR_ID LIMIT 10, 10

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  • data from few MySQL tables sorted by ASC

    - by Andrew
    In the dbase I 've few tables named as aaa_9xxx, aaa_9yyy, aaa_9zzz. I want to find all data with a specified DATE and show it with the TIME ASC. First, I must find a tables in the dbase: $STH_1a = $DBH->query("SELECT table_name FROM information_schema.tables WHERE table_name LIKE 'aaa\_9%' "); foreach($STH_1a as $row) { $table_name_s1[] = $row['table_name']; } Second, I must find a data wit a concrete date and show it with TIME ASC: foreach($table_name_s1 as $table_name_1) { $STH_1a2 = $DBH->query("SELECT * FROM `$table_name_1` WHERE date = '2011-11-11' ORDER BY time ASC "); while ($row = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$table_name_1."-".$row['time']."-".$row['ei_name']." <br>"; } } .. but it shows the data sorted by tables name, then by TIME ASC. I must to have all this data (from all tables) sorted by TIME ASC. Thank You dev-null-dweller, Andrew Stubbs and Jaison Erick for your help. I test the Erick solution : foreach($STH_1a as $row) { $stmts[] = sprintf('SELECT * FROM %s WHERE date="%s"', $row['table_name'], '2011-11-11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; } it's working but I've problem with 'table_name' - it's always the LAST table name. //---------------------------------------------------------------------- end the ending solution with all fixes, thanks all for your help, :)) foreach($STH_1a as $row) { $stmts[] = sprintf("SELECT *, '%s' AS table_name FROM %s WHERE date='%s'", $row['table_name'], $row['table_name'], '2011-11- 11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row_1a2['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; }

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  • MySQL: Question about SELECT WHERE AND/OR

    - by Andrew
    I'm trying to write a query that returns the same result from three different events, but I think I am doing it wrong. I can run my query against one event ID and it works. How can I select all three? Here's what I have so far: SELECT * FROM `Registrations` WHERE `Role` = "Attendee" AND `RegistrationStatus_ID` = "1" AND `DigSignature` IS NULL AND `Event_ID` = "147" OR `Event_ID` = "155" OR `Event_ID` = "160"

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  • JPA query many to one association

    - by Random Joe
    I want to build the following pseudo query Select a From APDU a where a.group.id= :id group is a field in APDU class of the type APDUGroup.class. I just want to get a list of APDUs based on APDUGroup's id. How do i do that using a standard JPA query?

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  • how to avoid deadlock in mysql

    - by noam
    I have the following query (all tables are innoDB) INSERT INTO busy_machines(machine) SELECT machine FROM all_machines WHERE machine NOT IN (SELECT machine FROM busy_machines) and machine_name!='Main' LIMIT 1 Which causes a deadlock when I run it in threads, obviously because of the inner select, right? The error I get is: (1213, 'Deadlock found when trying to get lock; try restarting transaction') How can I avoid the deadlock? Is there a way to change to query to make it work, or do I need to do something else?

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