Faster or more memory-efficient solution in Python for this Codejam problem.
- by jeroen.vangoey
I tried my hand at this Google Codejam Africa problem (the contest is already finished, I just did it to improve my programming skills).
  The Problem:
  
  You are hosting a party with G guests
  and notice that there is an odd number
  of guests! When planning the party you
  deliberately invited only couples and
  gave each couple a unique number C on
  their invitation. You would like to
  single out whoever came alone by
  asking all of the guests for their
  invitation numbers.
  
  The Input:
  
  The first line of input gives the number of cases, N.
  N test cases follow. For each test case there will be:
  
  
  One line containing the value G the
  number of guests. 
  One line containing
  a space-separated list of G integers.
  Each integer C indicates the
  invitation code of a guest. Output
  
  
  For each test case, output one line
  containing "Case #x: " followed by the
  number C of the guest who is alone.
  
  The Limits:
  
  
  1 = N = 50 
  0 < C = 2147483647 
  
  
  Small dataset
  
  3 = G < 100
  
  Large dataset
  
  3 = G < 1000
Sample Input:
3
3
1 2147483647 2147483647
5
3 4 7 4 3
5
2 10 2 10 5
Sample Output:
Case #1: 1
Case #2: 7
Case #3: 5
This is the solution that I came up with:
with open('A-large-practice.in') as f:
    lines = f.readlines()
with open('A-large-practice.out', 'w') as output:
    N = int(lines[0])
    for testcase, i in enumerate(range(1,2*N,2)):
        G = int(lines[i])
        for guest in range(G):
            codes = map(int, lines[i+1].split(' '))
            alone = (c for c in codes if codes.count(c)==1)
        output.write("Case #%d: %d\n" % (testcase+1, alone.next()))
It runs in 12 seconds on my machine with the large input.
Now, my question is, can this solution be improved in Python to run in a shorter time or use less memory? The analysis of the problem gives some pointers on how to do this in Java and C++ but I can't translate those solutions back to Python.