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  • Counting the number of objects that meets a certain criteria

    - by Candy Chiu
    The title doesn't tell the complete story. Please read the message. I have two objects: Adult and Child. Child has a boolean field isMale, and a reference to Adult. Adult doesn't reference Child. public class Adult { long id; } public class Child { long id; boolean isMale; Adult parent; } I want to create a query to list the number of sons each adult has including adults who don't have any sons. I tried: Query 1 SELECT adult, COUNT(child) FROM Child child RIGHT OUTER JOIN child.parent as adult WHERE child.isMale='true' GROUP BY adult which translates to sql select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id where child.isMale = 'true' group by adult.id Query 1 doesn't pick up adults that don't have any sons. Query 2: SELECT adult, COUNT(child.isMale) FROM Child child RIGHT OUTER JOIN child.parent as adult GROUP BY adult translates to sql: select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id group by adult.id Query 2 doesn't have the right count of sons. Basically COUNT doesn't evaluate isMale. The where clause in Query 1 filtered out Adults with no sons. How do I build a HQL or a Criteria query for this use case? Thanks.

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  • PHP - Counting matching arrays in array

    - by Sergio
    hi there, I have an array structure that looks like this: Array ( [0] => Array ( [type] => image [data] => Array ( [id] => 1 [alias] => test [caption] => no caption [width] => 200 [height] => 200 ) ) [1] => Array ( [type] => image [data] => Array ( [id] => 2 [alias] => test2 [caption] => hello there [width] => 150 [height] => 150 ) ) ) My question is, how can I get a count of the number of embedded arrays that have their type set as image (or anything else for that matter)? In practise this value can vary. So, the above array would give me an answer of 2. Thanks

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  • Groovy sorting string asc

    - by srinath
    How to sort string names in array on ascending order . I tried sort method but it fails to sort on name basis . def words = ["orange", "blue", "apple", "violet", "green"] I need to achieve like this : ["apple", "blue", "green", "orange", "violet" ] thanks in advance.

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  • PyQt: How to keep QTreeView nodes correctly expanded after a sort

    - by taynaron
    I'm writing a simple test program using QTreeModel and QTreeView for a more complex project later on. In this simple program, I have data in groups which may be contracted or expanded, as one would expect in a QTreeView. The data may also be sorted by the various data columns (QTreeView.setSortingEnabled is True). Each tree item is a list of data, so the sort function implemented in the TreeModel class uses the built-in python list sort: self.layoutAboutToBeChanged.emit() self.rootItem.childItems.sort(key=lambda x: x.itemData[col], reverse=order) for item in self.rootItem.childItems: item.childItems.sort(key=lambda x: x.itemData[col], reverse=order) self.layoutChanged.emit() The problem is that whenever I change the sorting of the root's child items (the tree is only 2 levels deep, so this is the only level with children) the nodes aren't necessarily expanded as they were before. If I change the sorting back without expanding or collapsing anything, the nodes are expanded as before the sorting change. Can anyone explain to me what I'm doing wrong? I suspect it's something with not properly reassigning QModelIndex with the sorted nodes, but I'm not sure.

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  • Discrete mathematics problem - Probability theory and counting

    - by Mohammad
    Hello All, I'm taking a discrete mathematics course, and I encountered a question and I need your help. I don't know if this is the right place for that though :) It says: Each user on a computer system has a password, which is six to eight characters long, where each character is an uppercase letter or a digit. Each password must contain at least one digit. How many possible passwords are there? The book solves this by adding the probabilities of having six,seven and eight characters long password. However, when he solves for probability of six characters he does this P6 = 36^6 - 26^6 and does P7 = 36^7 - 26^7 and P8 = 36^8 - 26^8 and then add them all I understand the solution, but my question is why doesn't calculating, P6 = 10*36^5 and the same for P7 and P8, work? 10 for the digit and 36 for the alphanumeric? Also, if anyone could give me another solution, other than the one in the book. Thank you very much :)

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  • Counting longest occurence of repeated sequence in Python

    - by user248237
    What's the easiest way to count the longest consecutive repeat of a certain character in a string? For example, the longest consecutive repeat of "b" in the following string: my_str = "abcdefgfaabbbffbbbbbbfgbb" would be 6, since other consecutive repeats are shorter (3 and 2, respectively.) How can I do this in Python? thanks.

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  • Counting number of children in hierarchical SQL data

    - by moontear
    for a simple data structure such as so: ID parentID Text Price 1 Root 2 1 Flowers 3 1 Electro 4 2 Rose 10 5 2 Violet 5 6 4 Red Rose 12 7 3 Television 100 8 3 Radio 70 9 8 Webradio 90 For reference, the hierarchy tree looks like this: ID Text Price 1 Root |2 Flowers |-4 Rose 10 | |-6 Red Rose 12 |-5 Violet 5 |3 Electro |-7 Television 100 |-8 Radio 70 |-9 Webradio 90 I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so: ID parentID Text Price NoOfChildren 1 Root 8 2 1 Flowers 3 3 1 Electro 3 4 2 Rose 10 1 5 2 Violet 5 0 6 4 Red Rose 12 0 7 3 Television 100 0 8 3 Radio 70 1 9 8 Webradio 90 0 I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here. moon

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  • Counting the number of words in a text area

    - by user1320483
    Hello everyone my first question on stack overflow import javax.swing.*; import java.util.*; import java.awt.event.*; public class TI extends JFrame implements ActionListener { static int count=0; String ct; JTextField word; JTextArea tohide; public static void main(String arg[]) { TI ti=new TI(); } public TI() { JPanel j=new JPanel(); JLabel def=new JLabel("Enter the text to be encrypted"); word=new JTextField("",20); tohide=new JTextArea("",5,20); JButton jb=new JButton("COUNT"); tohide.setBorder(BorderFactory.createLoweredBevelBorder()); j.add(def); j.add(tohide); j.add(word); j.add(jb); add(j); setSize(500,500); setVisible(true); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); setLocationRelativeTo(null); jb.addActionListener(this); } public void actionPerformed(ActionEvent ae) { String txt=tohide.getText(); StringTokenizer stk=new StringTokenizer(txt," "); while(stk.hasMoreTokens()) { String token=stk.nextToken(); count++; } ct=Integer.toString(count);; word.setText(ct); } } I want to count the number of words that are being typed in the textarea.There is a logical error.As I keep clicking the count button the word count increases.

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  • Counting the number of visitors for a web page - JavaScript and Struts

    - by Dj
    Hi i am Dhananjay, I need to keep track of the number of visitors to a web page. I have planned like this: on load of the home page, I will call a javascript callCounter(); From javascript, I need then to call an action and update a record in database. Please help me with this. How do i call the action? I should be in the same home jsp after updating database. Thanks in advance, Dhananjay

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  • Counting FLOPS/GFLOPS in program - CUDA

    - by msx
    Already finished my application which multiplies CRS matrix and vector (SpMV) and the only thing to do now is to count FLOPS my application did. In my opinion it's really hard to estimate number of floating point operation in case of sparse matrix - vector multiplication, because the number of multiplies in one row is really "jumpy" or fluent. I only tried to measure time using "cudaprof" ( available in ./CUDA/bin directory) - it works fine. Any sugestions and instruction pastes appreciated !

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  • ASP.NET GridView Sort?

    - by Curtis White
    I'm performing a query with a sort in the Selecting event of the LinqDataSource. I'm then casting my query to a list and assigning it to the result. I'm using this data source in an ASP.NET gridview. I can see the list is sorted but when the ASP.NET gridview does not seem to be respecting the sort order. How can I get the gridview to respect my default sort order?

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  • Need Help With Simple Counting Bug in iPhone SDK

    - by seanny94
    So I'm basically making an app that adds a count to a number and then displays it each time you tap the button. However, the first tap issued doesn't take any action but adds one (just as planned) on the second tap. I've searched to the ends of the earth looking for the solution with no luck, so I'll see what you guys can make of this. :) #import "MainView.h" @implementation MainView int count = 0; -(void)awakeFromNib { counter.text = @"0"; } - (IBAction)addUnit { if(count >= 999) return; NSString *numValue = [[NSString alloc] initWithFormat:@"%d", count++]; counter.text = numValue; [numValue release]; } - (IBAction)subtractUnit { if(count <= 0) return; NSString *numValue = [[NSString alloc] initWithFormat:@"%d", count--]; counter.text = numValue; [numValue release]; } @end

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  • How to sort in-place using the merge sort algorithm?

    - by eSKay
    I know the question is too open. All I want is someone to tell me how to convert a normal merge sort into an in-place merge sort (or a merge sort with constant extra space overhead). All I can find (on the net) is pages saying "it is too complex" or "out of scope of this text". "The only known ways to merge in-place (without any extra space) are too complex to be reduced to practical program." (from here) Even if it is too complex, can somebody outline the basic concept of how to make the merge sort in-place?

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  • JS sort works in Firefox but not IE - can't work out why

    - by Max Williams
    I have a line in a javascript function that sort an array of objects based on the order of another array of strings. This is working in firefox but not in IE and i don't know why. Here's what my data looks like going into the sort call. (I'm using an array of three items just to illustrate the point here). //cherry first then the rest in alphabetical order originalData = ['cherry','apple','banana','clementine','nectarine','plum'] //data before sorting - note how clementine is second item - we wan to to to be after apple and banana csub = [ {"value":"cherry","data":["cherry"],"result":"cherry"}, {"value":"clementine","data":["clementine"],"result":"clementine"}, {"value":"apple","data":["apple"],"result":"apple"}, {"value":"banana","data":["banana"],"result":"banana"}, {"value":"nectarine","data":["nectarine"],"result":"nectarine"}, {"value":"plum","data":["plum"],"result":"plum"} ] //after sorting, csub has been rearranged but still isn't right: clementine is before banana csubSorted = [ {"value":"cherry","data":["cherry"],"result":"cherry"}, {"value":"apple","data":["apple"],"result":"apple"}, {"value":"clementine","data":["clementine"],"result":"clementine"}, {"value":"banana","data":["banana"],"result":"banana"}, {"value":"nectarine","data":["nectarine"],"result":"nectarine"}, {"value":"plum","data":["plum"],"result":"plum"} ] Here's the actual sort code: csubSorted = csub.sort(function(a,b){ return (originalData.indexOf(a.value) > originalData.indexOf(b.value)); }); Can anyone see why this wouldn't work? Is the basic javascript sort function not cross-browser compatible? Can i do this a different way (eg with jquery) that would be cross-browser? grateful for any advice - max

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  • Counting multiple entries in a MySQL database?

    - by Aaron
    Hi all, I'm trying to count multiple entries in a MySQL database, I know how to use COUNT(), but the exact syntax I want to get the results I need eludes me. The problem: Table structure: ID, CODE, AUTHOR, COUNTRY, TIMESTAMP. Code, Author and Country overlap many times in the table. I am trying to discover if there is one simple query that can be ran to return (using WHERE clause on COUNTRY) the author field, the code field, and then a final field that counts the number of times the CODE was present in the query result. So, theoretically I could end up with an array like: array('author', 'code', 'codeAppearsNTimes'); Authors also have varying codes associated with them, so I don't want the results merged. I suppose the end result would be: 'This author is associated with this code this many times'. Is this possible with MySQL? Thanks in advance.

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  • SQL - Counting sets of Field-B values for each Field-A value

    - by potrnd
    Hello, First of all sorry that I could not think of a more descriptive title. What I want to do is the following using only SQL: I have some lists of strings, list1, list2 and list3. I have a dataset that contains two interesting columns, A and B. Column A contains a TransactionID and column B contains an ItemID. Naturally, there can be multiple rows that share the same TransactionIDs. I need to catch those transactions that have at least one ItemID in each and every list (list1 AND list2 AND list3). I also need to count how many times does that happen for each transaction. [EDIT] That is, count how many full sets of ItemIDs there are for each TransactionID", "Full Set" being any element of the list1 with any element of the list2 with any element of the list3 I hope that makes enough sense, perhaps I will be able to explain it better with a clear head. Thanks in advance

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  • Counting computers for each lab

    - by Irvin
    Alright I have a problem with having to count PCs, and Macs from different labs. In each lab I need to display how many PC and Macs there is available. The data is coming from a SQL server, right am trying sub queries and the use of union, this the closest I can get to what I need. The query below shows me the number of PCs, and Macs in two different columns, but of course, the PCs will be in one row and the Macs on another right below it. Having the lab come up twice. EX: LabName -- PC / MAC Lab1 -- 5 / 0 Lab1 -- 0 / 2 Query SELECT Labs.LabName, COUNT(*),0 AS Mac FROM HardWare INNER JOIN Labs ON HardWare.LabID = Labs.LabID WHERE ComputerStatus = 'AVAILABLE' GROUP BY Labs.LabName UNION SELECT Labs.LabName, COUNT(*), (SELECT COUNT(Manufacturer)) AS Mac FROM HardWare INNER JOIN Labs ON HardWare.LabID = Labs.LabID WHERE ComputerStatus = 'AVAILABLE' AND Manufacturer = 'Apple' GROUP BY Labs.LabName ORDER BY Labs.LabName So is there any way to get them together in one row as in Lab1 -- 5 / 2 or is there a different way to write the query? anything will be a big help, am pretty much stuck here. Cheers

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  • Counting Alphabetic Characters That Are Contained in an Array with C

    - by Craig
    Hello everyone, I am having trouble with a homework question that I've been working at for quite some time. I don't know exactly why the question is asking and need some clarification on that and also a push in the right direction. Here is the question: (2) Solve this problem using one single subscripted array of counters. The program uses an array of characters defined using the C initialization feature. The program counts the number of each of the alphabetic characters a to z (only lower case characters are counted) and prints a report (in a neat table) of the number of occurrences of each lower case character found. Only print the counts for the letters that occur at least once. That is do not print a count if it is zero. DO NOT use a switch statement in your solution. NOTE: if x is of type char, x-‘a’ is the difference between the ASCII codes for the character in x and the character ‘a’. For example if x holds the character ‘c’ then x-‘a’ has the value 2, while if x holds the character ‘d’, then x-‘a’ has the value 3. Provide test results using the following string: “This is an example of text for exercise (2).” And here is my source code so far: #include<stdio.h> int main() { char c[] = "This is an example of text for exercise (2)."; char d[26]; int i; int j = 0; int k; j = 0; //char s = 97; for(i = 0; i < sizeof(c); i++) { for(s = 'a'; s < 'z'; s++){ if( c[i] == s){ k++; printf("%c,%d\n", s, k); k = 0; } } } return 0; } As you can see, my current solution is a little anemic. Thanks for the help, and I know everyone on the net doesn't necessarily like helping with other people's homework. ;P

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  • R counting the occurance of similar rows of data frame

    - by Matt
    I have data in the following format called DF (this is just a made up simplified sample): eval.num, eval.count, fitness, fitness.mean, green.h.0, green.v.0, offset.0 random 1 1 1500 1500 100 120 40 232342 2 2 1000 1250 100 120 40 11843 3 3 1250 1250 100 120 40 981340234 4 4 1000 1187.5 100 120 40 4363453 5 1 2000 2000 200 100 40 345902 6 1 3000 3000 150 90 10 943 7 1 2000 2000 90 90 100 9304358 8 2 1800 1900 90 90 100 284333 However, the eval.count column is incorrect and I need to fix it. It should report the number of rows with the same values for (green.h.0, green.v.0, and offset.0) by only looking at the previous rows. The example above uses the expected values, but assume they are incorrect. How can I add a new column (say "count") which will count all previous rows which have the same values of the specified variables? I have gotten help on a similar problem of just selecting all rows with the same values for specified columns, so I supposed I could just write a loop around that, but it seems inefficient to me.

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  • counting fields based on group in crystal report

    - by hatem gamil
    hi all i wana ask a question about crystal reporting in vs 2008 lets say i have a report with these data customer_ID Customer_Name Order_amoont Order_Date (#group1 VipCustomer) 1 xyz 3 1/1/2010 2 abc 4 2/2/2010 5 sds 21 3/12/2009 (#Group2 NormalCustomer) 3 tyt 2 3/3/2010 4 ha 4 21/3/2009 i want only to display records where Order_Date year is in 2010 only so i went to the section expert and i added a condintion in suppress formula Year(order_Date)=2010 and i get the result ,,the question is how to count how many vip customers ordered in 2010 only and how many normal customer order in 2010 only ,,then i want the total number of both type of customers to be displayed to have a report like that:: customer_ID Customer_Name Order_amoont Order_Date (#group1 VipCustomer) 1 xyz 3 1/1/2010 2 abc 4 2/2/2010 subtotal 2 (#Group2 NormalCustomer) 3 tyt 2 3/3/2010 subtotal 1 total 3 thnx

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