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• Counting elements and reading attributes with .net2.0 ?

  - by Prix

  I have an application that is on .net 2.0 and I am having some difficult with it as I am more use to linq. The xml file look like this: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <updates> <files> <file url="files/filename.ext" checksum="06B9EEA618EEFF53D0E9B97C33C4D3DE3492E086" folder="bin" system="0" size="40448" /> <file url="files/filename.ext" checksum="CA8078D1FDCBD589D3769D293014154B8854D6A9" folder="" system="0" size="216" /> <file url="files/filename.ext" checksum="CA8078D1FDCBD589D3769D293014154B8854D6A9" folder="" system="0" size="216" /> </files> </updates> The file is downloaded and readed on the fly: XmlDocument readXML = new XmlDocument(); readXML.LoadXml(xmlData); Initially i was thinking it would go with something like this: XmlElement root = doc.DocumentElement; XmlNodeList nodes = root.SelectNodes("//files"); foreach (XmlNode node in nodes) { ... im reading it ... } But before reading them I need to know how many they are to use on my progress bar and I am also clueless on how to grab the attribute of the file element in this case. How could I count how many "file" ELEMENTS I have (count them before entering the foreach ofc) and read their attributes ? I need the count because it will be used to update the progress bar. Overall it is not reading my xml very well.

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• Counting leaf nodes in hierarchical tree

  - by timn

  This code fills a tree with values based their depths. But when traversing the tree, I cannot manage to determine the actual number of children. node-cnt is always 0. I've already tried node-parent-cnt but that gives me lots of warnings in Valgrind. Anyway, is the tree type I've chosen even appropriate for my purpose? #include <string.h> #include <stdio.h> #include <stdlib.h> #ifndef NULL #define NULL ((void *) 0) #endif // ---- typedef struct _Tree_Node { // data ptr void *p; // number of nodes int cnt; struct _Tree_Node *nodes; // parent nodes struct _Tree_Node *parent; } Tree_Node; typedef struct { Tree_Node root; } Tree; void Tree_Init(Tree *this) { this->root.p = NULL; this->root.cnt = 0; this->root.nodes = NULL; this->root.parent = NULL; } Tree_Node* Tree_AddNode(Tree_Node *node) { if (node->cnt == 0) { node->nodes = malloc(sizeof(Tree_Node)); } else { node->nodes = realloc( node->nodes, (node->cnt + 1) * sizeof(Tree_Node) ); } Tree_Node *res = &node->nodes[node->cnt]; res->p = NULL; res->cnt = 0; res->nodes = NULL; res->parent = node; node->cnt++; return res; } // ---- void handleNode(Tree_Node *node, int depth) { int j = depth; printf("\n"); while (j--) { printf(" "); } printf("depth=%d ", depth); if (node->p == NULL) { goto out; } printf("value=%s cnt=%d", node->p, node->cnt); out: for (int i = 0; i < node->cnt; i++) { handleNode(&node->nodes[i], depth + 1); } } Tree tree; int curdepth; Tree_Node *curnode; void add(int depth, char *s) { printf("%s: depth (%d) > curdepth (%d): %d\n", s, depth, curdepth, depth > curdepth); if (depth > curdepth) { curnode = Tree_AddNode(curnode); Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); curdepth++; } else { while (curdepth - depth > 0) { if (curnode->parent == NULL) { printf("Illegal nesting\n"); return; } curnode = curnode->parent; curdepth--; } Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); } } void main(void) { Tree_Init(&tree); curnode = &tree.root; curdepth = 0; add(0, "1"); add(1, "1.1"); add(2, "1.1.1"); add(3, "1.1.1.1"); add(4, "1.1.1.1.1"); add(2, "1.1.2"); add(0, "2"); handleNode(&tree.root, 0); }

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• Counting computers for each lab

  - by Irvin

  Alright I have a problem with having to count PCs, and Macs from different labs. In each lab I need to display how many PC and Macs there is available. The data is coming from a SQL server, right am trying sub queries and the use of union, this the closest I can get to what I need. The query below shows me the number of PCs, and Macs in two different columns, but of course, the PCs will be in one row and the Macs on another right below it. Having the lab come up twice. EX: LabName -- PC / MAC Lab1 -- 5 / 0 Lab1 -- 0 / 2 Query SELECT Labs.LabName, COUNT(*),0 AS Mac FROM HardWare INNER JOIN Labs ON HardWare.LabID = Labs.LabID WHERE ComputerStatus = 'AVAILABLE' GROUP BY Labs.LabName UNION SELECT Labs.LabName, COUNT(*), (SELECT COUNT(Manufacturer)) AS Mac FROM HardWare INNER JOIN Labs ON HardWare.LabID = Labs.LabID WHERE ComputerStatus = 'AVAILABLE' AND Manufacturer = 'Apple' GROUP BY Labs.LabName ORDER BY Labs.LabName So is there any way to get them together in one row as in Lab1 -- 5 / 2 or is there a different way to write the query? anything will be a big help, am pretty much stuck here. Cheers

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• postgres counting one record twice if it meets certain criteria

  - by Dashiell0415

  I thought that the query below would naturally do what I explain, but apparently not... My table looks like this: id | name | g | partner | g2 1 | John | M | Sam | M 2 | Devon | M | Mike | M 3 | Kurt | M | Susan | F 4 | Stacy | F | Bob | M 5 | Rosa | F | Rita | F I'm trying to get the id where either the g or g2 value equals 'M'... But, a record where both the g and g2 values are 'M' should return two lines, not 1. So, in the above sample data, I'm trying to return: $q = pg_query("SELECT id FROM mytable WHERE ( g = 'M' OR g2 = 'M' )"); 1 1 2 2 3 4 But, it always returns: 1 2 3 4

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• MapReduce for counting parameter values

  - by cnkt

  I have document like this: { "_id": ObjectId("4d17c7963ffcf60c1100002f"), "title": "Text", "params": { "brand": "BMW", "model": "i3" } } { "_id": ObjectId("4d17c7963ffcf60c1100002f"), "title": "Text", "params": { "brand": "BMW", "model": "i5" } } What i need is the count of every params values. like: brand --------- BMW (2) model --------- i3 (1) i5 (1) I think i have to write map/reduce functions. How can i do this? Thanks.

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• counting rows that date hasn't yet passed

  - by AdRock

  I am trying to count the number of rows whose date has not yet passed so i can get only the current records I get an error sayng MySQL error #111 Invalid use of group function SELECT COUNT(festivalid) FROM festivals WHERE min(datefrom) > now()

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• Counting viable sublist lengths from an array.

  - by Ben B.

  This is for a genetic algorithm fitness function, so it is important I can do this as efficiently as possible, as it will be repeated over and over. Lets say there is a function foo(int[] array) that returns true if the array is a "good" array and false if the array is a "bad" array. What makes it good or bad does not matter here. Given the full array [1,6,8,9,5,11,45,16,9], lets say that subarray [1,6,8] is a "good" array and [9,5,11,45] is a "good" array. Furthermore [5,11,45,16,9] is a "good" array, and also the longest "good" subarray. Notice that while [9,5,11,45] is a "good" array, and [5,11,45,16,9] is a "good" array, [9,5,11,45,16,9] is a "bad" array. We wants the length counts of all "good" arrays, but not subarrays of "good" arrays. Furthermore, as described above, a "good" array might begin in the middle of another "good" array, but the combination of the two might be a "bad" array.

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• R counting the occurrences of similar rows of data frame

  - by Matt

  I have data in the following format called DF (this is just a made up simplified sample): eval.num, eval.count, fitness, fitness.mean, green.h.0, green.v.0, offset.0 random 1 1 1500 1500 100 120 40 232342 2 2 1000 1250 100 120 40 11843 3 3 1250 1250 100 120 40 981340234 4 4 1000 1187.5 100 120 40 4363453 5 1 2000 2000 200 100 40 345902 6 1 3000 3000 150 90 10 943 7 1 2000 2000 90 90 100 9304358 8 2 1800 1900 90 90 100 284333 However, the eval.count column is incorrect and I need to fix it. It should report the number of rows with the same values for (green.h.0, green.v.0, and offset.0) by only looking at the previous rows. The example above uses the expected values, but assume they are incorrect. How can I add a new column (say "count") which will count all previous rows which have the same values of the specified variables? I have gotten help on a similar problem of just selecting all rows with the same values for specified columns, so I supposed I could just write a loop around that, but it seems inefficient to me.

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• Counting problem: possible sudoko tables?

  - by Sorush Rabiee

  Hi, I'm working on a sudoko solver. my method is using a game tree and explore possible permutations for each set of digits by DFS Algorithm. in order to analyzing problem, i want to know what is the count of possible valid and invalid sudoko tables? - a 9*9 table that have 9 one, 9 two, ... , 9 nine. (this isn't exact duplicate by this question) my solution is: 1- First select 9 cells for 1s: (*) 2- and like (1) for other digits (each time, 9 cells will be deleted from remaining available cells): C(81-9,9) , C(81-9*2,9) .... = 3- finally multiply the result by 9! (permutation of 123456789 in (*)) this is not equal to accepted answer of this question but problems are equivalent. what did i do wrong?

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• IN R counting hierarchical data

  - by Alison

  I have a list of counties in each state that received nonattainment status in years 1995-2005. I want to know how many counties in each state each year that received this status. If my data is formatted like this, State1 Country1 YR1 Yr2 Yr3 Yr4... State1 Country2 YR1 Yr2 Yr3 Yr4 State2 County1 Yr1 Yr2..... Each year variable could have a 1 or a zero, since a county may gain or loose this status in a time period. I need to count each year how many counties in each state have nonattainment status (YRx=1), but can't think of how to do it.

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• MySQl - update field by counting data in other table

  - by Qiao

  There are two tables. One is users info "users", one is comments info "comments". I need to create new field "comments" in users table, that contains number of comments of that user. Table "comments" has "user" field with user's id of that comment. What is optimal way to count number of comments by every user? With php you should write script that selects every user and than count number of his comments and then update "comments" field. It is not hard for me, but boring. Is it possible to do it without php, only in MySQL?

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• Counting common Bytes, Words and Double Words.

  - by Recursion

  I am scanning over a large amount of data and looking for common trends in it. Every time I meet a recurrence of a unit, I want to increment the count of it. What is the best data structure or way to hold this data. I need to be able to search it quickly, and also have a count with each unit of data.

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• Counting the number of select statements, connections per user in MySQL

  - by Michelangelo

  Hi guys, how can I count the number of connection and queries by user per day? I need a little list of users, previously registered in my MySQL Server, with the total of the queries and connections. For instance: users | Queries user01 | 120000 user02 | 340000 user03 | 1540000 user04 | 1244000 thanks

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• Counting the most tagged tag with MySQL

  - by Jack W-H

  Hi folks My problem is that I'm trying to count which tag has been used most in a table of user-submitted code. But the problem is with the database structure. The current query I'm using is this: SELECT tag1, COUNT(tag1) AS counttag FROM code GROUP BY tag1 ORDER BY counttag DESC LIMIT 1 This is fine, except, it only counts the most often occurence of tag1 - and my database has 5 tags per post - so there's columns tag1, tag2, tag3, tag4, tag5. How do I get the highest occurring tag value from all 5 columns in one query? Jack

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• problem in counting children category

  - by moustafa

  I have this table: fourn_category (id , sub) I am using this code to count: function CountSub($id){ $root = array($id); $query = mysql_query("SELECT id FROM fourn_category WHERE sub = '$id'"); while( $row = mysql_fetch_array( $query, MYSQL_ASSOC ) ){ array_push($root,$row['id']); CountSub($row['id']); } return implode(",",$root); } It returns the category id as 1,2,3,4,5 to using it to count the sub by IN() But the problem is that it counts this: category 1 category 2 category 3 category 4 category 5 Category 1 has 1 child not 4. Why? How can I get all children's trees?

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• Understanding ruby array sort

  - by user257797

  I am having a problem understanding how array.sort{|x,y| block} works exactly,hence how to use it? ruby-doc example: a = [ "d", "a", "e", "c", "b" ] a.sort #=> ["a", "b", "c", "d", "e"] a.sort {|x,y| y <=> x } #=> ["e", "d", "c", "b", "a"] thanks

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• Drupal - Counting data in nodes, creating custom statistics

  - by hfidgen

  Hiya, I'm building some custom content types to capture customer data on a website. Admins will enter the data, users will be able to view it, but I also need to be able to bolt on some statistics and infographics to the data. The problem I have is that I can't see any simple way of doing this within Drupal. Are there modules which can produce simple stats on selected node types or will I have to write a complete custom module using the data abstraction layer? Thanks for any insights!

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• Counting words in a collection using LINQ

  - by icemanind

  Guys, I have a StringCollection object with 5 words in them. 3 of them are duplicate words. I am trying to create a LINQ query that will count how many unique words are in the collection and output them to to the console. So, for example, if my StringCollection has 'House', 'Car,'House','Dog', 'Cat', then it should output like this: House -- 2 Car -- 1 Dog -- 1 Cat -- 1 any ideas on how to create a LINQ query to do this?

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• Counting HTML images with Python

  - by user2537246

  I need some feedback on how to count HTML images with Python 3.01 after extracting them, maybe my regular expression are used properly. Here is my code: import re, os import urllib.request def get_image(url): url = 'http://www.google.com' total = 0 try: f = urllib.request.urlopen(url) for line in f.readline(): line = re.compile('<img.*?src="(.*?)">') if total > 0: x = line.count(total) total += x print('Images total:', total) except: pass

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• counting twice in a query, once using restrictions

  - by Andrew Heath

  Given the following tables: Table1 [class] [child] math boy1 math boy2 math boy3 art boy1 Table2 [child] [glasses] boy1 yes boy2 yes boy3 no If I want to query for number of children per class, I'd do this: SELECT class, COUNT(child) FROM Table1 GROUP BY class and if I wanted to query for number of children per class wearing glasses, I'd do this: SELECT Table1.class, COUNT(table1.child) FROM Table1 LEFT JOIN Table2 ON Table1.child=Table2.child WHERE Table2.glasses='yes' GROUP BY Table1.class but what I really want to do is: SELECT class, COUNT(child), COUNT(child wearing glasses) and frankly I have no idea how to do that in only one query. help?

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• Counting through all binary numbers with equal 1's and 0's

  - by Stuart

  I'm implementing a binary representation of an equal-side bi-partitioning algorithm and I'm wondering what the best way to iterate through all combinations of N bits that have equal (N/2) 1's and 0's. I'm trying to find the quickest way, not the easiest to code. Thanks.

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• bubble sort on array of c structures not sorting properly

  - by xmpirate

  I have the following program for books record and I want to sort the records on name of book. the code isn't showing any error but it's not sorting all the records. #include "stdio.h" #include "string.h" #define SIZE 5 struct books{ //define struct char name[100],author[100]; int year,copies; }; struct books book1[SIZE],book2[SIZE],*pointer; //define struct vars void sort(struct books *,int); //define sort func main() { int i; char c; for(i=0;i<SIZE;i++) //scanning values { gets(book1[i].name); gets(book1[i].author); scanf("%d%d",&book1[i].year,&book1[i].copies); while((c = getchar()) != '\n' && c != EOF); } pointer=book1; sort(pointer,SIZE); //sort call i=0; //printing values while(i<SIZE) { printf("##########################################################################\n"); printf("Book: %s\nAuthor: %s\nYear of Publication: %d\nNo of Copies: %d\n",book1[i].name,book1[i].author,book1[i].year,book1[i].copies); printf("##########################################################################\n"); i++; } } void sort(struct books *pointer,int n) { int i,j,sorted=0; struct books temp; for(i=0;(i<n-1)&&(sorted==0);i++) //bubble sort on the book name { sorted=1; for(j=0;j<n-i-1;j++) { if(strcmp((*pointer).name,(*(pointer+1)).name)>0) { //copy to temp val strcpy(temp.name,(*pointer).name); strcpy(temp.author,(*pointer).author); temp.year=(*pointer).year; temp.copies=(*pointer).copies; //copy next val strcpy((*pointer).name,(*(pointer+1)).name); strcpy((*pointer).author,(*(pointer+1)).author); (*pointer).year=(*(pointer+1)).year; (*pointer).copies=(*(pointer+1)).copies; //copy back temp val strcpy((*(pointer+1)).name,temp.name); strcpy((*(pointer+1)).author,temp.author); (*(pointer+1)).year=temp.year; (*(pointer+1)).copies=temp.copies; sorted=0; } *pointer++; } } } My Imput The C Programming Language X Y Z 1934 56 Inferno Dan Brown 1993 453 harry Potter and the soccers stone J K Rowling 2012 150 Ruby On Rails jim aurther nil 2004 130 Learn Python Easy Way gmaps4rails 1967 100 And the output ########################################################################## Book: Inferno Author: Dan Brown Year of Publication: 1993 No of Copies: 453 ########################################################################## ########################################################################## Book: The C Programming Language Author: X Y Z Year of Publication: 1934 No of Copies: 56 ########################################################################## ########################################################################## Book: Ruby On Rails Author: jim aurther nil Year of Publication: 2004 No of Copies: 130 ########################################################################## ########################################################################## Book: Learn Python Easy Way Author: gmaps4rails Year of Publication: 1967 No of Copies: 100 ########################################################################## ########################################################################## Book: Author: Year of Publication: 0 No of Copies: 0 ########################################################################## We can see the above sorting is wrong? What I'm I doing wrong?

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• Counting divs for pagination in Jquery

  - by Craig Ward

  I want to create a nice pagination in Jquery for a number of divs I have. EG: <div class="container"> <div id="one">content</div> <div id="two">content</div> <div id="three">content</div> <div id="four">content</div> </div> The number will not always be the same so I need to count the divs, and display a pagination like the one below. 1|2|3|4 Clicking on the page number would display the relevant div. I know how to show and hide elements using Jquery and css and have figured out I can count the divs using var numPages = $('.container').size(); but I can't work out how I can display the pagination. Any pointers?

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• C++ assignment question [closed]

  - by Adam Joof

  (Bubble Sort) In the bubble sort algorithm, smaller values gradually "bubble" their way upward to the top of the array like air bubbles rising in water, while the larger values sink to the bottom. The bubble sort makes several passes through the array. On each pass, successive pairs of elements are compared. If a pair is in increasing order (or the values are identical), we leave the values as they are. If a pair is in decreasing order, their values are swapped in the array. Write a program that sorts an array of 10 integers using bubble sort.

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• How to sort a key of a map

  - by Tsuna Sawada

  How to sort (any kind of sorting) a key of a map(treemap or hashmap) i have a problem and it goes like this. i have a map that has a key of 27527-683, 27525-1179, 27525-1571, 27525-1813, 27525-4911, 27526-1303, 27526-3641, 27525-3989, 27525-4083, 27525-4670, 27526-4102, 27526-558, 27527-2411, 27527-4342 this is the list of keys and the value for each of the key is a list. now, how can i sort this key in ascending order by number. ex. if i want to sort : 1,2,11,20,31,3,10 i want to have as output is : 1,2,3,10,11,20,31 but when i use the autosort of treemap the output goes : 1,10,11,2,20,3,31 how can i sort it in ascending order by numeric? please help me. i can't think of anymore ways because this is my first time handling map and list

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