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  • MySQL on a laptop for remote workers - MyISAM keeps corrupting

    - by Jonathon
    We have an application that is used by remote, mobile workers. It intalls WAMP (Server2Go) on a laptop and uses MySQL to store data locally. All tables are MyISAM. Once a day, the workers sync the database to our central server via HTTP scripts that query the data and post it to our site. The problem is that many of these laptop database tables are corrupting continually. It appears that MySQL acts like it saves the information (I don't get any query errors), but the table gets corrupt. I have to repair the table constantly (which removes several rows of data in the process). Does anyone have any ideas about how to work around this problem? Would it be wise to switch to InnoDB on the laptops? How about a different database system altogether. I have looked at MySQL Embedded, but it appears to be the same engine as the regular MySQL.

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  • multiple file systems for mysql

    - by RainDoctor
    Does mysql support multiple file systems for a single database with most of the tables being on MyISAM? Context: we have a 1.5TB mysql database, which is increasing at the rate of 200GB per month. The storage is directly attached, whose slots are almost full. I can add another DAS, and increase the file system. But resizing volume, resizing file system, etc are getting messy. Is there a concept of "tablespace, datafile" (like in oracle) in MySql world? Or how you guys manage mysql db with these kind of constraints?

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  • (PHP vs Python vs Perl) vs Ruby [closed]

    - by Dr.Kameleon
    OK, here's what : I've programmed in over 20 different languages and now, because of a large project I'm currently working on for Mac OS X (in Objective-C/Cocoa), I need to make a final decision on which language to use for my background scripting + plugin functionality. Definitely, one factor that'll ultimately influence my decision is which one I'm most familiar with, which is PHP (one of the ugliest languages around, which I however adore... lol), then Python / Perl (the "proven values"... )... and then Ruby (which, to me, is almost confusing and I've only played with it for some time.) Now, here's my considerations : (As previously mentioned) Being familiar with it (anyway, if X is better in my case, I really don't mind studying it from scratch...) Speed Good interaction with the Shell + ease of integration with my Cocoa application Btw, some of the reasons that made me wonder if Ruby would be a good choice is : The hype around it (although, I still don't get why; but that's probably just me...) My major competitor (we're actually talking about the same type of software here) is using Ruby for its backend scripting almost exclusively (ok, along with some BASH). Isn't Ruby considered slower e.g. than Perl? Why did he choose that? Simply, a matter of personal taste? So... your thoughts?

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  • Fine-tuning a LNMP stack

    - by Norman
    I'm in the process of setting up a server with 4GB RAM and 2 CPUs. The stack will be CentOS + NGINX + MySQL + PHP (with APC) and spawn-fcgi. It will be used to serve 10 Wordpress blogs, 3 of which receive about 20,000 hits per day. Each Wordpress instance is equipped with the W3 TotalCache. I have a few variables to play with: NGINX (How many worker_processes, worker_connections, etc) PHP (What parameters in php.ini should I change? What about apc?) Spawn-fcgi (Right now I have 6 php-cgi spawned. How many of them should I have?) I realize it's hard to tell without testing, but if you could please provide me with some ballpark numbers, that would be helpful too.

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  • Load an html table from a mysql database when an onChange event is triggered from a select tag

    - by Crew Peace
    So, here's the deal. I have an html table that I want to populate. Specificaly the first row is the one that is filled with elements from a mysql database. To be exact, the table is a questionnaire about mobile phones. The first row is the header where the cellphone names are loaded from the database. There is also a select tag that has company names as options in it. I need to trigger an onChange event on the select tag to reload the page and refill the first row with the new names of mobiles from the company that is currently selected in the dropdown list. This is what my select almost looks like: <select name="select" class="companies" onChange="reloadPageWithNewElements()"> <?php $sql = "SELECT cname FROM companies;"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['cname']."\">".$row['cname']."</option>\n "; } ?> </select> So... is there a way to refresh this page with onChange and pass the selected value to the same page again and assign it in a new php variable so i can do the query i need to fill my table? <?php //$mobileCompanies = $_GET["selectedValue"]; $sql = "SELECT mname FROM ".$mobileCompanies.";"; $rs = mysql_query($sql); while ($row = mysql_fetch_array($rs)) { echo "<td><div class=\"q1\">".$row['mname']."</div></td>"; } ?> something like this. (The reloadPageWithNewElements() and selectedValue are just an idea for now)

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  • problems installing mysql and phpmyadmin to localhost

    - by Joel
    Hi guys, I know there have been many similar questions, but as far as I can tell, most of the other people have gotten further than I have... I'm trying to get a WAMP setup happening. I've got PHP and Apache running and talking to each other. PHP is in c:\PHP Apache is in it's default program files folder. mySQL is in it's default install location. I have localhost setup at D:\public_html\ I'm able to navigate to localhost and see html and php files. But I have a simple mySQL test file: <?php // hostname or ip of server (for local testing, localhost should work) $dbServer='localhost'; // username and password to log onto db server $dbUser='root'; $dbPass=''; // name of database $dbName='test'; $link = mysql_connect("$dbServer", "$dbUser", "$dbPass") or die("Could not connect"); print "Connected successfully<br>"; mysql_select_db("$dbName") or die("Could not select database"); print "Database selected successfully<br>"; // close connection mysql_close($link); ?> When I try and open this, I get "could not connect" Now, I haven't even created a database yet, because I can't log into mySQL with phpmyadmin-so I think I've done something wrong in my mySQL install because they aren't talking to each other. I guess my main question is how do I first create a database in mySQL to be sure I have even installed it correctly?

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  • PHP W3 Validator API, Is this good? [closed]

    - by Josh Purcell
    I was trying to find a way to see if my site's code was valid or not but I continuously going over to W3 Validator so I decided to make an "API" however it really isn't! I just wanted to know if anybody can find a better solution to the one I have made. This is what I currently use, with the usage of ?uri=http://www.mydomain.com : <?php if(!$_GET['uri']) { echo "No URI!"; } else { $CheckURI = "http://validator.w3.org/check?uri=".$_GET['uri']; $URL = file_get_contents($CheckURI); $Start = strpos($URL, "<title>") + 7; $End = strpos($URL, "</title>"); $Title = substr($URL, $Start, $End-$Start); if(preg_match('[Invalid]',$Title)) { //Code is INVALID echo "<a href='$CheckURI' title='This is not good!' target='_BLANK'>INVALID Source</a>"; } elseif(preg_match('[Valid]',$Title)) { //Code is VALID echo "<a href='$CheckURI' title='Check It Yourself!' target='_BLANK'>Valid Source</a>"; } else { //It Went WRONG echo ""; } }

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  • mysql.sock problem on Mac OS X, all Zend products

    - by Michael Stelly
    Hi folks. I posted this on the Zend forum, but I'm hoping I can get a speedier reply here. I've tried every solution provided on this forum with no luck. When I restart mysql, everything appears ok. sudo /usr/local/zend/bin/zendctl.sh restart Password: /usr/local/zend/bin/apachectl stop [OK] /usr/local/zend/bin/apachectl start [OK] Stopping Zend Server GUI [Lighttpd] [OK] spawn-fcgi: child spawned successfully: PID: 7943 Starting Zend Server GUI [Lighttpd] [OK] Stopping Java bridge [OK] Starting Java bridge [OK] Shutting down MySQL . SUCCESS! Starting MySQL . SUCCESS! Pinging locahost is also OK and resolve dns to IP. ping localhost PING localhost (127.0.0.1): 56 data bytes 64 bytes from 127.0.0.1: icmp_seq=0 ttl=64 time=0.048 ms 64 bytes from 127.0.0.1: icmp_seq=1 ttl=64 time=0.064 ms 64 bytes from 127.0.0.1: icmp_seq=2 ttl=64 time=0.066 ms 64 bytes from 127.0.0.1: icmp_seq=3 ttl=64 time=0.076 ms 64 bytes from 127.0.0.1: icmp_seq=4 ttl=64 time=0.064 ms But when I attempt to access the local url for my app, I get the dreaded: Message: SQLSTATE[HY000] [2002] Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2). This is a show-stopper for me. I appreciate any assistance. Thank you.

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  • Building PHP For MacOS

    - by Eray
    I was using XAMPP and decided to uninstall it and use MacOS' in-built apache and php modules. But while uninstalling XAMPP I deleted /usr/bin/php files and other PHP-CLI files accidentally. And I decided to install newest version of PHP (5.5.12) instead of rebuilding current version (5.4.24). Downloaded it and unzip. After this executed this command as mentioned at this guide. ./configure '--with-apxs2=/usr/sbin/apxs' '--enable-cli' '--with-config-file-path=/etc' '--with-zlib=/usr' '--enable-bcmath' '--with-bz2=/usr' '--enable-calendar' '--disable-cgi' '--with-curl=/usr' '--enable-dba' '--enable-ndbm=/usr' '--enable-exif' '--enable-fpm' '--enable-ftp' '--with-gd' '--enable-gd-native-ttf' '--enable-mbregex' '--with-mysql=mysqlnd' '--with-mysqli=mysqlnd' '--with-pear' '--with-pdo-mysql=mysqlnd' '--with-mysql-sock=/var/mysql/mysql.sock' '--with-tidy' '--enable-wddx' '--with-xmlrpc' '--enable-zip' make make install When i check phpinfo() , it's still version 5.4.24 . This line from my httpd.conf LoadModule php5_module libexec/apache2/libphp5.so /usr/libexec/apache2/libphp5.so coming from old version and i couldn't ind libphp5.so for new version. There is no libphp5.so file inside modules dir. How can i use new PHP build with Apache ? UPDATE Results of php -v command . PHP 5.5.12 (cli) (built: May 27 2014 05:17:21) Copyright (c) 1997-2014 The PHP GroupZend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies

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  • Mirroring MySQL server with diffrent configuration

    - by HTF
    I have to migrate MySQL server to a different data centre so I would like to create another MySQL slave server in new DC and then promote it to a master later on. I previously used LVM snapshots and Percona Xtrabackup for this purpose but this time I've optimized MySQL configuration file that prevents me from using these methods. Old server (backup): innodb_log_file_size = 256M innodb_log_files_in_group = 3 New server (restore): innodb_log_file_size = 512M innodb_log_files_in_group = 2 The Xtrabackup script and LVM snapshots copy the whole directory structure so the MySQL server won't start because there is a different size for InnoDB logs. Is there any solution to avoid a downtime in this case? I can't use mysqldumps as there is around 8000 databases so I would have to take the server down for a couple of hours. I was also thinking to use the old settings with Xtrabackup and then change it once the new server is promoted to a master - less downtime but I'm not sure if this will work? Thank you Regards

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  • MySQL wants a password but it's empty

    - by gAMBOOKa
    mysql -uroot ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES) mysql -uroot -p Enter password: <-- leave blank, hit enter without entering anything mysql> <-- i am logged in NOTE: This is a new mysql instance installation So if the password is blank, why won't it log me in without a -p flag? For a little clarification. I am running into this issue when attempting to change the password using a script: We're using a bash script to do that. mysqladmin -u root password abc wouldn't work (access denied) mysqladmin -u root -p password abc cannot be used because it prompts for a password and we need to automate this. mysqladmin -u root -p'' password abc is not working either

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  • Completely remove MySQL from macbook pro

    - by mike
    Im prety sure i completely removed mysql from my system, except for one thing. When i type mysql in the command line i get this bash: /opt/local/bin/mysql5: No such file or directory How is it still recognizing where it thinks mysql should be? I'm trying to build it myself in /usr/local, and when i do install it there, i still get that error message for it looking for it in opt/local.

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  • Coolstack MySQL Crash Unable to Restart

    - by rayblasdel
    Environment: Solaris 10 This mysql server has been up and running for 6 months now. Today all of a sudden it crashed. When typing 'mysql' as user it gives the error MYSQL" Error 2002 (HY000): Can't Connect to Local MySQL server though socket '/tmp/mysql.sock' The server try to open mysql, it stays open for 9-10 seconds and restarts the process. Below are the application logs. Application-database-mysql_mysql-csk.log [ May 30 22:37:52 Enabled. ] [ May 30 22:37:58 Rereading configuration. ] [ May 30 22:37:59 Executing start method ("/opt/coolstack/lib/svc/method/svc-cskmysql start") ] /opt/coolstack/mysql/bin/mysqld_safe --user=mysql --datadir=/dbpool1/data --pid-file=/dbpool1/data/database.soliaonline.com.pid [ May 30 22:37:59 Method "start" exited with status 0 ] [ May 30 22:38:13 Stopping because all processes in service exited. ] [ May 30 22:38:13 Executing stop method ("/opt/coolstack/lib/svc/method/svc-cskmysql stop") ] [ May 30 22:38:13 Method "stop" exited with status 0 ] [ May 30 22:38:13 Executing start method ("/opt/coolstack/lib/svc/method/svc-cskmysql start") ] /opt/coolstack/mysql/bin/mysqld_safe --user=mysql --datadir=/dbpool1/data --pid-file=/dbpool1/data/database.soliaonline.com.pid [ May 30 22:38:13 Method "start" exited with status 0 ] [ May 30 22:38:25 Stopping because all processes in service exited. ] [ May 30 22:38:25 Executing stop method ("/opt/coolstack/lib/svc/method/svc-cskmysql stop") ] [ May 30 22:38:25 Method "stop" exited with status 0 ] I am hoping someone might have run into this before and might know how to fix it. The following is an excerpt from the MySQL Error log 100530 22:44:03 mysqld_safe mysqld from pid file /dbpool1/data/database.soliaonline.com.pid ended 100530 22:44:04 mysqld_safe Starting mysqld daemon with databases from /dbpool1/data InnoDB: Log scan progressed past the checkpoint lsn 32 727170612 100530 22:44:13 InnoDB: Database was not shut down normally! InnoDB: Starting crash recovery. InnoDB: Reading tablespace information from the .ibd files... InnoDB: Restoring possible half-written data pages from the doublewrite InnoDB: buffer... InnoDB: Doing recovery: scanned up to log sequence number 32 727200901 100530 22:44:14 InnoDB: Starting an apply batch of log records to the database... InnoDB: Progress in percents: 100530 22:44:14 - mysqld got signal 11 ; This could be because you hit a bug. It is also possible that this binary or one of the libraries it was linked against is corrupt, improperly built, or misconfigured. This error can also be caused by malfunctioning hardware. We will try our best to scrape up some info that will hopefully help diagnose the problem, but since we have already crashed, something is definitely wrong and this may fail. key_buffer_size=209715200 read_buffer_size=1048576 max_used_connections=0 max_threads=10000 threads_connected=0 It is possible that mysqld could use up to key_buffer_size + (read_buffer_size + sort_buffer_size)*max_threads = 31024253 K bytes of memory Hope that's ok; if not, decrease some variables in the equation. enter code here

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  • Updated my WAMP Server and MySQL is eating up 580mB of memory

    - by Jon
    I updated my dev-box's WAMPSERVER, and along with updating PHP and Apache, MySQL updated to '5.6.12'. After doing that, I copied the data folder from my old (5.1.36) install to the new one and now MySQL takes up 580mB which is way too much, since I'm the only person using it (Locally) and there are only 20 or so databases on it, none of which have 'memory' tables. How can I get this down to a decent amount? My my.ini: # For advice on how to change settings please see # http://dev.mysql.com/doc/refman/5.6/en/server-configuration-defaults.html # *** DO NOT EDIT THIS FILE. It's a template which will be copied to the # *** default location during install, and will be replaced if you # *** upgrade to a newer version of MySQL. [mysqld] # Remove leading # and set to the amount of RAM for the most important data # cache in MySQL. Start at 70% of total RAM for dedicated server, else 10%. # innodb_buffer_pool_size = 128M # Remove leading # to turn on a very important data integrity option: logging # changes to the binary log between backups. # log_bin # These are commonly set, remove the # and set as required. # basedir = ..... # datadir = ..... # port = ..... # server_id = ..... # Remove leading # to set options mainly useful for reporting servers. # The server defaults are faster for transactions and fast SELECTs. # Adjust sizes as needed, experiment to find the optimal values. # join_buffer_size = 128M # sort_buffer_size = 2M # read_rnd_buffer_size = 2M sql_mode=NO_ENGINE_SUBSTITUTION,STRICT_TRANS_TABLES Database info: Storage Engine Data Size Index Size Total Size InnoDB 48.00 KB 0.00 B 48.00 KB MEMORY 0.00 B 0.00 B 0.00 B MyISAM 163.64 MB 122.49 MB 286.13 MB Total 163.69 MB 122.49 MB 286.18 MB

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • Virtual Hosting in RHEL5

    - by Kumar P
    We having RHEL5 linux server with few windows xp clients. We providing web development in php. Now my developers as for common local php server for keep their projects in same place. Currently proxy server and samba sharing are running in RHEL5 server. I installed httpd,php,MySQL in server. And i would like to configure virtual hosting too for LAN. What i want do for it ? In server we have 2 Ethernet ports, 1 for local connection and another one for Internet. Internet provided by ADSL provider. (192.168.0.0 series for ADSL modem connection and 10.1.1.0 for LAN connection. If i want to use virtual hosting , am i want to setup local DNS server ? My requirements are, setup php with mySQL server for Local clients with multiple hosting , without disturbing proxy and samba. Help me to solve it.

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  • Guide To Setting Accessing PhpMyAdmin On NGINX, Ubuntu 11.04, EC2 Remote MySQL Instance

    - by darkAsPitch
    I have setup a domain name to run on amazon ec2 running ubuntu 11.04, nginx and php5-fpm. The domain name works great, I have setup it's own sites-available configuration file and sym-linked it to sites-enabled. I installed phpmyadmin via sudo apt-get install phpmyadmin and followed the instructions. I then added this just above my /etc/nginx/nginx.conf file and restarted nginx. server { listen 80; server_name phpmyadmin.domain.com; location / { root /usr/share/phpmyadmin; index index.php; } #make sure all php files are processed by fast_cgi location ~ \.php { # try_files $uri =404; fastcgi_index index.php; fastcgi_pass 127.0.0.1:9000; include fastcgi_params; fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_param PATH_INFO $fastcgi_path_info; fastcgi_param PATH_TRANSLATED $document_root$fastcgi_path_info; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; } } I have also added the appropriate dns A records for phpmyadmin.domain.com phpmyadmin.domain.com just shows a 404 error code. All other subdomains do not respond at all so at least something is working here. FYI I have edited the /etc/phpmyadmin/config.inc.php file so that I can connect to a remote MySQL Database. What else do I need to do?

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  • MySQL Server Not Starting on Boot

    - by Brian
    I have installed MySQL on a RHEL 5 server and I'm wanting to set it up so that the server starts on boot. I've ran the "chkconfig --list mysqld" command and it's currently running on levels 3, 4 and 5. However, when I reboot the server, no mysqld process is started. I've also tried manually starting the server by executing "/usr/bin/mysqld_safe" and I get the following output: Starting mysqld daemon with databases from /var/lib/mysql STOPPING server from pid file /var/run/mysqld/mysqld.pid 100319 10:31:30 mysqld ended I looked in /var/log/mysqld.log and I found the following: 100319 10:29:01 mysqld started 100319 10:29:02 InnoDB: Started; log sequence number 0 29752204 100319 10:29:02 [ERROR] Can't start server : Bind on unix socket: Permission denied 100319 10:29:02 [ERROR] Do you already have another mysqld server running on socket: /var/lib/mysql/mysql.sock ? 100319 10:29:02 [ERROR] Aborting

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  • MySQL command appends '@localhost' to username

    - by Mikee
    I just can't seem to figure this one out. I want to use the command line to connect to a MySQL database residing on another server. I went ahead and created the username and password for the user. I have also granted all privileges on that user for that database. When using the command: mysql -h <hostname> -u <username> -p, I get the following error: ERROR 1045 (28000): Access denied for user '<username>'@'<local_machine_hostname>' (using password: YES) The problem is that it keeps appending the current machine's hostname into the username. Obviously, that user@<local_machine_hostname> is not correct. It doesn't matter what I type. For instance, if I type: mysql -h <hostname> -u '<username>'@'<hostname>' -p It does the same, only in the error output, it says: Access denied for user '<username>@<hostname>'@'<local_machine_hostname>' Is there a setting in a configuration file which is allowing this to happen? It's really quite annoying. I need to set up a tikiwiki server, and it cannot connect because during the step where you set up mysql, it keeps appending the local machine's hostname to the mysql login name.

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  • Basic PHP OOPS Query

    - by appu
    Ok. I am starting out OOPS in PHP. Created a couple of classes: customer(parent) and sales(child) class that inherits from parent class. Created another testcustomer.php in which a new sales object is created however the salesprint() function defined in the sales class does not echo out customer's name though it is set to be "Jane" in the class.customer.php(parent). My thinking is that when sales class extends customer class PHP automatically includes all the code from class.customer.php to sales.customer.php and therefore the constructor in parent class set $name to "Jane". Here is the code: class.customer.php <?php class customer{ private $name; private $cust_no; public function __construct($customerid) { $this->name = 'Jane'; $this->cust_no = $customerid; } } ?> class.sales.php <?php require_once('class.customer.php'); class sales extends customer{ public function salesprint($customerid) { echo "Hello $this->name this is a print of your purchased products"; } } ?> testcustomer.php require_once('class.sales.php'); $objsales = new sales(17); $objsales->salesprint(17); ?> The Output I get Hello this is a print of your purchased products. What am i doing wrong ? thanks romesh

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  • how to debug mysql has gone?

    - by fefe
    I have a virtual machine(Ubuntu 12.04, MySQL 5.5) running under VMware and is dedicated to host a mysql server. I connect to this server on internal IP. I'm trying to find out why I get mysql server has gone error. One my windows machines apache it stops because of this issue. I have been trying to fine tune my mysql my.cnf with the following parameters but did not bring the desired result. # Instead of skip-networking the default is now to listen only on # localhost which is more compatible and is not less secure. bind-address = 0.0.0.0 # # * Fine Tuning # wait_timeout = 180 key_buffer = 384M max_allowed_packet = 64M thread_stack = 192K thread_cache_size = 8 # This replaces the startup script and checks MyISAM tables if needed # the first time they are touched myisam-recover = BACKUP max_connections = 500 table_cache = 64 #thread_concurrency = 10 # # * Query Cache Configuration # query_cache_limit = 1M query_cache_size = 32M how to debug this issue what is missing from configuration to avoid this error?

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  • stored procedure in mysql not working in 64 bit windows server 2008

    - by abhi
    i have application in spring .its is deployed in Linux machine and windows server 2008. i am using mysql 5.5.32 in my linux server and mysql 5.5.13 in windows server 2008. stored procedure in mysql is working perfectly in Linux machine but while calling stored procedure from windows,its is working partially that is some integer values is set as 0.if i restart the tomcat and call that stored procrdure then t is working. i dont know the exact reason .can any one help me to find issue.thanks in advance

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  • Unknown/unsupported storage engine: InnoDB | Mysql Ubuntu

    - by Kayle
    I recently upgraded from the previous LTS Ubuntu to Precise and now mysql refuses to start. It complains of the following when I attempt to start it: ?$ sudo service mysql restart stop: Unknown instance: start: Job failed to start And this shows in "/var/log/mysql/error.log": 120415 23:01:09 [Note] Plugin 'InnoDB' is disabled. 120415 23:01:09 [Note] Plugin 'FEDERATED' is disabled. 120415 23:01:09 [ERROR] Unknown/unsupported storage engine: InnoDB 120415 23:01:09 [ERROR] Aborting 120415 23:01:09 [Note] /usr/sbin/mysqld: Shutdown complete I've checked permissions on all the mysql directories to make sure it had ownership and I also renamed the previou ib_logs so that it could remake them. I'm just getting no where with this issue right now, after looking at google results for 2 hours.

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