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  • How do I force excel (and other office products) to stop opening files in the same application?

    - by KronoS
    Whenever I "double click" on an Excel file and another Excel file is open, the newly opened file automatically opens in the same application window as the previously opened Excel file. This isn't limited to just Excel, as I've seen Word do this as well. This poses a problem when wanting to compare documents side by side. The current solution I have for this is to actually open another Excel or Word instance, and then open the file from within that application window itself. Is there a way to force Office to open a new instance of the application when double clicking on the file icons? I'm currently using Office 2007 and Windows XP but I've seen this on Office 2010 and Windows Vista and 7. I'm looking for an overall solution if possible.

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  • My windows keyboard is being "clever" with the quote keys - how can I stop it?

    - by Marcin
    I'm using windows 7 on a laptop. On the laptop keyboard, for some reason, the quote key (which has both double and single quote on it) is doing some "clever" annoying things: When I press single-quote (or double-quote), windows doesn't send any characters until I press it twice (resulting in '' or "") When I press it before a vowel, I get some kind of accented character. As I usually only write English, this is annoying. The backtick/tilde key is subject to similar behaviour. I have not attempted to set up my computer to process anything other than English. My keyboard appears to be (in so far as these things are standard on laptops) a standard US qwerty keyboard. How can I stop this happening?

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  • Check if CSS Class exists in StyleSheet using javascript/jQuery

    - by Akhil Sekharan
    Is there a way to check if there is a class named 'some-class-name' in css? For example, I have: <style type="text/css"> .box { position: absolute; left: 150%; } </style> My intention is to randomly assign a class to a div on certain event: var classList = []; //Need to populate this array $('#updateClass').on('click', function() { $('#resultDiv').attr('class',classList[Math.floor((Math.random()*classList.length)+1)]); }); Is it possible to check by JS/jQuery whether a class named 'box' exists in the stylesheet? Thanks.

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  • Java M4A atom tagging free space issue

    - by Brett
    Hey, I've been trying to be able to read and write iTunes style M4A atoms and while I've successfully done the reading part, I've come to a bit of a halt in regards to the free space atoms. I figured that I should be able edit and shift the padding around to accommodate writing an atom with more data than it originally had. I've been stuck on this for about a day now, and I've been trying to figure out how to determine the closest free space atom with enough size to accommodate the new data. so far I have: private freeAtom acquireFreeSpaceAtom( long position ) { long atomStart = Long.MAX_VALUE; freeAtom atom = null; for( freeAtom a : freeSpace ) { if( Math.abs( position - atomStart ) > Math.abs( position - a.getAtomStart() ) ) atomStart = ( atom = a ).getAtomStart(); } return atom; } That code only takes into account the closest free space atom and completely disregards the fact that it should be greater than or equal to a certain size, but I can't quite figure out how I should check for both closeness and size efficiently.

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  • Drawing random circles

    - by ViktorC
    I am trying to draw a cupola circles at random positions in an Android application. I draw them on a bitmap and then draw that bitmap on the canvas. This is the function where a draw the circles: private void drawRandomCircles(int numOfCircles) { Canvas c = new Canvas(b); Paint cPaint = new Paint; cPaitn.setColor(Color.RED); for(int i = 0; i < numOfCircles; i++) { int x = Math.Random % 100; int y = Math.Random % 100; c.drawCircle(x, y, 20, cPaint) } } The Bitmap b is global. And after calling this function I just draw the bitmap in the onDraw method. Now the problem is that I only get one circle drawn on the screen, no matter the size of numOfCircles. Any clue what is happening here?

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  • error LNK2019 and fatal error LNK1120 i get these errors in c++.

    - by user320950
    #include <iostream> #include <fstream> using namespace std; int read_file_in_array(int exam[100][3]); double calculate_total(int exam1[], int exam2[], int exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; } i have no idea how to get these errors out. i wrote the whole code over and tried to see if it was a problem with brackets but that doesnt help either. i dont know what line it is but i believe it is in this function. error LNK2019: unresolved external symbol "int __cdecl read_file_in_array(int (* const)[3])" (?read_file_in_array@@YAHQAY02H@Z) referenced in function _main fatal error LNK1120: 1 unresolved externals // i believe this one has to do with brackets double calculate_total(int exam1[],int exam2[],int exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; int exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } return 0; } int main() { int go,go2,go3; int exam[100][3]; int exam1[100]; int exam2[100]; int exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; }

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  • C# animation - move object from A to B or by angle

    - by Nullstr1ng
    Hi am just doing a little animation which moves an object from point a to point b or by angle/radians. what I currently have is this Point CalcMove(Point pt, double angle, int speed) { Point ret = pt; ret.X = (int)(ret.X + speed * Math.Sin(DegToRad(angle))); ret.Y = (int)(ret.Y + speed * Math.Cos(DegToRad(angle))); return ret; } but it doesn't look what i expected. please help? update: oh and am using NETCF

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  • Please help me in creating a update query

    - by Rajesh Rolen- DotNet Developer
    I have got a table which contains 5 column and query requirements: update row no 8 (or id=8) set its column 2, column 3's value from id 9th column 2, column 3 value. means all value of column 2, 3 should be shifted to column 2, 3 of upper row (start from row no 8) and value of last row's 2, 3 will be null For example, with just 3 rows, the first row is untouched, the second to N-1th rows are shifted once, and the Nth row has nulls. id math science sst hindi english 1 11 12 13 14 15 2 21 22 23 24 25 3 31 32 33 34 35 The result of query of id=2 should be: id math science sst hindi english 1 11 12 13 14 15 2 31 32 23 24 25 //value of 3rd row (col 2,3) shifted to row 2 3 null null 33 34 35 This process should run for all rows whose id 2 Please help me to create this update query I am using MS sqlserver 2005

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  • problem with the programme!!

    - by hopefulLLl
    kindly tell me what is the pblm with this function wont it help me find the sum of digits of a number?? #include<stdio.h> #include(math.h) void main() { int a,i=0,j=10,k,n=0,m; scanf("%d",&a); while((a%j!=0)&&i>=0) { m=pow(10,(i+1)); k=a%m; n=(a-(k*m)-n)/(m/10)+n; j=m*10; i++; } n=n+(n/(m/10)); printf("%d",n); } i know the parenthesis used with math.h are nt right..what else is the pblm..i need to use just while loop..or the for loop!

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  • actionscript display timer

    - by Aaron
    ok so im using real basic code for a small game and ive got a timer set up on one room and cant get it to display in the endgame room please help? this is the code i used var gameStartTime:uint; var gameTime:uint; var gameTimeField:TextField; gameTimeField = new TextField(); gameTimeField.x = 900; gameTimeField.y = 50; addChild(gameTimeField); gameStartTime = getTimer(); gameTime = 0; addEventListener(Event.ENTER_FRAME,showTime); function showTime(event:Event) {gameTime = getTimer()-gameStartTime; gameTimeField.text = "Time: "+clockTime(gameTime); } function clockTime(ms:int) { var seconds:int = Math.floor(ms/100); var minutes:int = Math.floor(seconds/60); seconds -= minutes*60; var timeString:String = minutes+":"+String(seconds+100).substr(1,2); return timeString; }

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  • error in encryption program

    - by Raja
    #include<iostream> #include<math.h> #include<string> using namespace std; int gcd(int n,int m) { if(m<=n && n%m ==0) return m; if(n<m) return gcd(m,n); else return gcd(m,n%m); } int REncryptText(char m) { int p = 11, q = 3; int e = 3; int n = p * q; int phi = (p - 1) * (q - 1); int check1 = gcd(e, p - 1); int check2 = gcd(e, q - 1); int check3 = gcd(e, phi); // // Compute d such that ed = 1 (mod phi) //i.e. compute d = e-1 mod phi = 3-1 mod 20 //i.e. find a value for d such that phi divides (ed-1) //i.e. find d such that 20 divides 3d-1. //Simple testing (d = 1, 2, ...) gives d = 7 // double d = Math.Pow(e, -1) % phi; int d = 7; // public key = (n,e) // (33,3) //private key = (n,d) //(33 ,7) double g = pow(m,e); int ciphertext = g %n; // Now say we want to encrypt the message m = 7, c = me mod n = 73 mod 33 = 343 mod 33 = 13. Hence the ciphertext c = 13. //double decrypt = Math.Pow(ciphertext, d) % n; return ciphertext; } int main() { char plaintext[80],str[80]; cout<<" enter the text you want to encrpt"; cin.get(plaintext,79); int l =strlen(plaintext); for ( int i =0 ; i<l ; i++) { char s = plaintext[i]; str[i]=REncryptText(s); } for ( int i =0 ; i<l ; i++) { cout<<"the encryption of string"<<endl; cout<<str[i]; } return 0; }

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  • C++ Greatest Number Verification

    - by Daniel
    Hey guys, I was assigned to create a program that creates n arrays composed by 10 random integers. The the program should sum all the integers and display the result. After, it has to verify which of the sums is the greatest and it has to display that array and the result. Im having troubles getting it done and would like to get some help! Thanks once again. Here is my code so far: #include <iostream> #include <iomanip> #include <cmath> using namespace std; double random(unsigned int &seed); unsigned int seed = 5; void generateData(int set[10]); int sumData(int set[10]); void checkData(int sumResult, int arrayNumber); int main (int argc, char * const argv[]) { int arrayNumber, sumResult; int set[10]; do { cout << "Number of Arrays to Compare: " << endl; cin >> arrayNumber; } while (arrayNumber < 0); for (int i = 0; i < arrayNumber; ++i) { generateData(set); sumResult = sumData(set); cout << "Sum --> " << sumResult << endl; checkData(sumResult, arrayNumber); } return 0; } double random(unsigned int &seed) { const int MODULUS = 15749; const int MULTIPLIER = 69069; const int INCREMENT = 1; seed = ((MULTIPLIER * seed) + INCREMENT) % MODULUS; return double(seed) / double(MODULUS); } void generateData(int set[10]) { for (int i = 0; i < 10; ++i) { set[i] = int (5 + 6 * random(seed)); cout << set[i] << " || "; } } int sumData(int set[10]) { int sumTotal = 0; for (int i = 0; i < 10; ++i) sumTotal = sumTotal + set[i]; return sumTotal; } void checkData(int sumResult, int arrayNumber) { int largerNumber; int tempSet[2]; for (int i = 0; i < arrayNumber; ++i) { if (sumResult > largerNumber) { tempSet[i] = sumResult; } } }

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  • Actionscript 3 while loop with indexOf

    - by Hanpan
    Hi, Is there any reason why this loop is getting stuck? I can't quite get my head around it: var i:Number = -1; do { i = Math.round(Math.random() * _totalQuestions); } while(_usedQuestions.indexOf(i)); Where _usedQuestions is an array of numbers. This array starts empty. Thanks! Edit: I want the loop to end if i is NOT found in the array.. this way I know the question I have selected has not previously been asked.

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  • Can someone explain this color wheel code to me?

    - by user1869438
    I just started doing java and i need some help with understanding this code. I got it from a this website. This is supposed to be code for a color wheel but i don't really understand how it works, especially the final ints STEPS and SLICES. import java.awt.Color; import objectdraw.*; public class ColorWheel extends WindowController { private double brightness; private Text text; private FilledRect swatch; private Location center; private int size; private FilledRect brightnessOverlay; private static final int SLICES = 96; private static final int STEPS = 16; public void begin() { canvas.setBackground(Color.BLACK); brightness = 1.; size = Math.min(canvas.getWidth(), canvas.getHeight() - 20); center = new Location(canvas.getWidth() / 2, size / 2); for(int j = STEPS; j >= 1; j--) { int arcSize = size * j / STEPS; int x = center.getX() - arcSize / 2; int y = center.getY() - arcSize / 2; for(int i = 0; i < SLICES; i++) { Color c = Color.getHSBColor((float)i / SLICES, (float)j / STEPS, (float)brightness); new FilledArc(x, y, arcSize, arcSize, i * 360. / SLICES, 360. / SLICES + .5, c, canvas); } } swatch = new FilledRect(0, canvas.getHeight() - 20, canvas.getWidth(), 20, Color.BLACK, canvas); brightnessOverlay = new FilledRect(0, 0, canvas.getWidth(), canvas.getHeight() - 20, new Color(0, 0, 0, 0), canvas); text = new Text("", canvas.getWidth() / 2, canvas.getHeight() - 18, canvas); text.setAlignment(Text.CENTER, Text.TOP); text.setBold(true); } public void onMouseDrag(Location point) { brightness = (canvas.getHeight() - point.getY()) / (double)(canvas.getHeight()); if(brightness < 0) { brightness = 0; } else if(brightness > 1) { brightness = 1; } if(brightness < .5) { text.setColor(Color.WHITE); } else { text.setColor(Color.BLACK); } brightnessOverlay.setColor(new Color(0f, 0f, 0f, (float)(1 - brightness))); } public void onMouseMove(Location point) { double saturation = 2 * center.distanceTo(point) / size; if(saturation > 1) { text.setText(""); swatch.setColor(Color.BLACK); return; } double hue = -Math.atan2(point.getY() - center.getY(), point.getX() - center.getX()) / (2 * Math.PI); if(hue < 0) { hue += 1; } swatch.setColor(Color.getHSBColor((float)hue, (float)saturation, (float)brightness)); text.setText("Color.getHSBColor(" + Text.formatDecimal(hue, 2) + "f, " + Text.formatDecimal(saturation, 2) + "f, " + Text.formatDecimal(brightness, 2) + "f)"); } }

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  • Performance of: if (OBJECT_INSTANCE is TYPE)

    - by Axonn
    I am working both in C# and ActionScript 3. Both language are type-aware, so you can do verifications such as: if (some_object_instance is SomeClassName_ThatIs_SomeType) I'm doing these kind of verifications in a few places. Might be a dumb question, but I will ask it anyway, and I want answers from both camps, C# and ActionScript: What goes on behind the scenes? Is it Reflection? If is, isn't this a long verification which might degrade performance if done in thousands of loops? And by "degrade performance" I mean, is it more intensive than say if (Math.sqrt(8) > Math.sin(10))

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  • Need to get pixel averages of a vector sitting on a bitmap...

    - by user346511
    I'm currently involved in a hardware project where I am mapping triangular shaped LED to traditional bitmap images. I'd like to overlay a triangle vector onto an image and get the average pixel data within the bounds of that vector. However, I'm unfamiliar with the math needed to calculate this. Does anyone have an algorithm or a link that could send me in the right direction? I'm not even clear what this type of math is called. I've created a basic image of what I'm trying to capture here: http://imgur.com/Isjip.gif

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  • Project Euler #163 understanding

    - by Paul
    I spent quite a long time searching for a solution to this problem. I drew tons of cross-hatched triangles, counted the triangles in simple cases, and searched for some sort of pattern. Unfortunately, I hit the wall. I'm pretty sure my programming/math skills did not meet the prereq for this problem. So I found a solution online in order to gain access to the forums. I didn't understand most of the methods at all, and some just seemed too complicated. Can anyone give me an understanding of this problem? One of the methods, found here: http://www.math.uni-bielefeld.de/~sillke/SEQUENCES/grid-triangles (Problem C) allowed for a single function to be used. How did they come up with that solution? At this point, I'd really just like to understand some of the concepts behind this interesting problem. I know looking up the solution was not part of the Euler spirit, but I'm fairly sure I would not have solved this problem anyhow.

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  • location getting some times and sometimes not

    - by Chaitanya Sai
    // in this i'm getting location sometimes and sometimes location is not retrieving i had turned gps and gprs on and added permissions required . i'm bot getting what actually the problem is package com.example.addr; import java.util.List; import java.util.Locale; import android.location.Address; import android.location.Criteria; import android.location.Geocoder; import android.location.Location; import android.location.LocationListener; import android.location.LocationManager; import android.os.Bundle; import android.app.Activity; import android.content.Context; import android.view.Menu; import android.widget.TextView; public class MainActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); LocationManager locationManager; String context = Context.LOCATION_SERVICE; locationManager = (LocationManager)getSystemService(context); Criteria crta = new Criteria(); crta.setAccuracy(Criteria.ACCURACY_FINE); crta.setAltitudeRequired(false); crta.setBearingRequired(false); crta.setCostAllowed(true); crta.setPowerRequirement(Criteria.POWER_LOW); String provider = locationManager.getBestProvider(crta, true); // String provider = LocationManager.GPS_PROVIDER; Location location = locationManager.getLastKnownLocation(provider); updateWithNewLocation(location); locationManager.requestLocationUpdates(provider, 2000, 10, locationListener); } private final LocationListener locationListener = new LocationListener() { @Override public void onLocationChanged(Location location) { updateWithNewLocation(location); } @Override public void onProviderDisabled(String provider) { updateWithNewLocation(null); } @Override public void onProviderEnabled(String provider) { } @Override public void onStatusChanged(String provider, int status, Bundle extras) { } }; private void updateWithNewLocation(Location location) { String latLong; TextView myLocation; myLocation = (TextView) findViewById(R.id.myLocation); String addressString = "Sorry No Address Found"; if(location!=null) { double lat = location.getLatitude(); double lon = location.getLongitude(); latLong = "Lat:" + lat + "\nLong:" + lon; double lattitude = location.getLatitude(); double longitude = location.getLongitude(); Geocoder gc = new Geocoder(this,Locale.getDefault()); try { List<Address> addresses= gc.getFromLocation(lattitude, longitude, 1); StringBuilder sb = new StringBuilder(); if(addresses.size()>0) { Address address=addresses.get(0); for(int i=0;i<address.getMaxAddressLineIndex();i++) sb.append(address.getAddressLine(i)).append("\n"); sb.append(address.getLocality()).append("\n"); sb.append(address.getPostalCode()).append("\n"); sb.append(address.getCountryName()); } addressString = sb.toString(); } catch (Exception e) { } } else { latLong = " NO Location Found "; } myLocation.setText("Current Position is :\n"+ latLong + "\n"+ addressString ); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.activity_main, menu); return true; } }

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  • JQuery multiple-choice quiz script: how to ensure the correct answer is available?

    - by DavidR
    I have a function. I pass to it an object with a list of questions and answers. I generate a random number from a range equal to the number of questions in the object. The script check to see if that question has been asked, and if not, it asks it, the correct answer is then passed to a variable correct. I want to give 4 possible answers, each one randomly selected from the list of possible answers. I have this. I just want to know what is the best way to ensure that the correct answer is placed in the list. So far, this is what I have: it puts four answers into four targeted boxes. I want to ensure that the correct answer is in a randomly selected box. function getRandom(limit) { return Math.floor(Math.random() * limit ) } $("#answers > .answer").each(function(i){ r = getRandom(total_questions); $(this).text(answers[r]) });

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  • Start a VPN session using a Terminal script

    - by craibuc
    I use an OSX Terminal session to start a VPN connection. The command that I execute at the prompt is: /etc/netlock/cvc -c :: This works as expected. I would like to save this to a script file that I can simply double-click to start. I created a file, 'vpn.command', added the command (list above), save it, and given execute permission: chmod +x vpn.command When I double-click the file, Terminal opens a BASH shell, executes the command, then exits. Upon closer inspection, the command is now '/etc/netlock/cvc -c ::; exit;' Why is the extra '; exit;' appended to my command? BTW, is there a way to execute another command, /etc/netlock/cvc -d, when the Terminal session is being closed so I can close the VPN automatically?

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  • MySQL Join Comma Separated Field

    - by neeraj
    I have two tables. First Table is a batch table that contain comma separated student id in field "batch" batch -------------- id batch -------------- 1 1,2 2 3,4 Second Table is marks marks ---------------------- id studentid subject marks 1 1 English 50 2 2 English 40 3 3 English 70 4 1 Math 65 5 4 English 66 6 5 English 75 7 2 Math 55 How we can find those students of first batch id =1 who have scored more than 45 marks in English without using sub query. Problem i found to get this done using a single query is that we can not use IN as an association operator in JOIN statement What changes are required in below query to make it work? SELECT * FROM batch INNER JOIN marks ON marks.studentid IN(batch.batch) where batch.id = 1

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  • Can't get Jacobi algorithm to work in Objective-C

    - by Chris Long
    Hi, For some reason, I can't get this program to work. I've had other CS majors look at it and they can't figure it out either. This program performs the Jacobi algorithm (you can see step-by-step instructions and a MATLAB implementation here). BTW, it's different from the Wikipedia article of the same name. Since NSArray is one-dimensional, I added a method that makes it act like a two-dimensional C array. After running the Jacobi algorithm many times, the diagonal entries in the NSArray (i[0][0], i[1][1], etc.) are supposed to get bigger and the others approach 0. For some reason though, they all increase exponentially. For instance, i[2][4] should equal 0.0000009, not 9999999, while i[2][2] should be big. Thanks in advance, Chris NSArray+Matrix.m @implementation NSArray (Matrix) @dynamic offValue, transposed; - (double)offValue { double sum = 0.0; for ( MatrixItem *item in self ) if ( item.nonDiagonal ) sum += pow( item.value, 2.0 ); return sum; } - (NSMutableArray *)transposed { NSMutableArray *transpose = [[[NSMutableArray alloc] init] autorelease]; int i, j; for ( i = 0; i < 5; i++ ) { for ( j = 0; j < 5; j++ ) { [transpose addObject:[self objectAtRow:j andColumn:i]]; } } return transpose; } - (id)objectAtRow:(NSUInteger)row andColumn:(NSUInteger)column { NSUInteger index = 5 * row + column; return [self objectAtIndex:index]; } - (NSMutableArray *)multiplyWithMatrix:(NSArray *)array { NSMutableArray *result = [[NSMutableArray alloc] init]; int i = 0, j = 0, k = 0; double value; for ( i = 0; i < 5; i++ ) { value = 0.0; for ( j = 0; j < 5; j++ ) { for ( k = 0; k < 5; k++ ) { MatrixItem *firstItem = [self objectAtRow:i andColumn:k]; MatrixItem *secondItem = [array objectAtRow:k andColumn:j]; value += firstItem.value * secondItem.value; } MatrixItem *item = [[MatrixItem alloc] initWithValue:value]; item.row = i; item.column = j; [result addObject:item]; } } return result; } @end Jacobi_AlgorithmAppDelegate.m // ... - (void)jacobiAlgorithmWithEntry:(MatrixItem *)entry { MatrixItem *b11 = [matrix objectAtRow:entry.row andColumn:entry.row]; MatrixItem *b22 = [matrix objectAtRow:entry.column andColumn:entry.column]; double muPlus = ( b22.value + b11.value ) / 2.0; muPlus += sqrt( pow((b22.value - b11.value), 2.0) + 4.0 * pow(entry.value, 2.0) ); Vector *u1 = [[[Vector alloc] initWithX:(-1.0 * entry.value) andY:(b11.value - muPlus)] autorelease]; [u1 normalize]; Vector *u2 = [[[Vector alloc] initWithX:-u1.y andY:u1.x] autorelease]; NSMutableArray *g = [[[NSMutableArray alloc] init] autorelease]; for ( int i = 0; i <= 24; i++ ) { MatrixItem *item = [[[MatrixItem alloc] init] autorelease]; if ( i == 6*entry.row ) item.value = u1.x; else if ( i == 6*entry.column ) item.value = u2.y; else if ( i == ( 5*entry.row + entry.column ) || i == ( 5*entry.column + entry.row ) ) item.value = u1.y; else if ( i % 6 == 0 ) item.value = 1.0; else item.value = 0.0; [g addObject:item]; } NSMutableArray *firstResult = [[g.transposed multiplyWithMatrix:matrix] autorelease]; matrix = [firstResult multiplyWithMatrix:g]; } // ...

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  • Please help me in creating an update query

    - by Rajesh Rolen- DotNet Developer
    I have got a table which contains 5 column and query requirements: update row no 8 (or id=8) set its column 2, column 3's value from id 9th column 2, column 3 value. means all value of column 2, 3 should be shifted to column 2, 3 of upper row (start from row no 8) and value of last row's 2, 3 will be null For example, with just 3 rows, the first row is untouched, the second to N-1th rows are shifted once, and the Nth row has nulls. id math science sst hindi english 1 11 12 13 14 15 2 21 22 23 24 25 3 31 32 33 34 35 The result of query of id=2 should be: id math science sst hindi english 1 11 12 13 14 15 2 31 32 23 24 25 //value of 3rd row (col 2,3) shifted to row 2 3 null null 33 34 35 This process should run for all rows whose id 2 Please help me to create this update query I am using MS sqlserver 2005

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  • Default Program With Multiple Versions Installed

    - by Optimal Solutions
    I have multiple versions of Excel installed. Excel 2010, 2007 and 2003. I have them installed on one hard drive with Windows 7 Ultimate as the OS. When I double-click on an XLS file, Excel 2007 opens. I would like Excel 2010 to open. I read and followed the instructions to go to the Control Panel at "Control Panel\All Control Panel Items\Default Programs" and set the default programs. I changed the default to the physical EXE for Excel 2010 at the proper folder that it is installed. When I double-click on the XLS files, Excel 2007 still opens. So I tried to change it to Excel 2003 just to see if it changed to that and it still opens Excel 2007. What am I missing? I would really like the file extension to open Excel 2010, but can not seem to do that.

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  • How do I scope variables properly in jQuery?

    - by safetycopy
    I'm working on a jQuery plugin, but am having some trouble getting my variables properly scoped. Here's an example from my code: (function($) { $.fn.ksana = function(userOptions) { var o = $.extend({}, $.fn.ksana.defaultOptions, userOptions); return this.each(function() { alert(rotate()); // o is not defined }); }; function rotate() { return Math.round(o.negRot + (Math.random() * (o.posRot - o.negRot))); }; $.fn.ksana.defaultOptions = { negRot: -20, posRot: 20 }; })(jQuery); I'm trying to get the private function rotate to be able to see the o variable, but it just keeps alerting 'o is not defined'. I'm not sure what I'm doing wrong.

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