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• MySql products and categories tables using php and json

  - by Romina Mora

  I have just started learning all this coding language and the teacher is asking us to do the following. I know it may sound really easy for people who do this full time or have more time coding. The teacher is always telling us to GOOGLE everything and I have tried too many sites but I haven't found anything that helps me at all. I need to write two JSON documents (products and categories) using PHP that will dynamically read values from my MySQL database. When each document is called upon, it will return perfectly formatted JSON that will validate using http://jsonlint.com/ Honestly I don't know what to do. I don't understand PHP and now this JSON thing is making it more confusing.

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• mysql query - syntax error - cannot find out why

  - by Phil Jackson

  Hi all, im taring my hair out over this one. A query is throwing an error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM, SUBJECT, DATE, READ, MAIL ) VALUES ( 'EJackson', 'dfdf', '1270974101', 'fa' at line 1 I printed out the query to see what could be the problem: INSERT INTO db.tablename ( FROM, SUBJECT, DATE, READ, MAIL ) VALUES ( 'EJackson', 'dfdf', '1270974299', 'false', 'dfdsfdsfd' ) and finaly the structure consists of: CREATE TABLE db.tablename ( `ID` int(12) NOT NULL auto_increment, `FROM` varchar(255) NOT NULL, `SUBJECT` varchar(255) NOT NULL, `DATE` varchar(255) NOT NULL, `READ` varchar(255) NOT NULL, `MAIL` varchar(255) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; I cant find anything wrong. Any Help would be much appreciated. ( db.tablename is a replacement for the actual tablename )

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• mysql - filtering a list against keywords, both list and keywords > 20 million records

  - by threecheeseopera

  I have two tables, both having more than 20 million records; table1 is a list of terms, and table2 is a list of keywords that may or may not appear in those terms. I need to identify the terms that contain a keyword. My current strategy is: SELECT table1.term, table2.keyword FROM table1 INNER JOIN table2 ON table1.term LIKE CONCAT('%', table2.keyword, '%'); This is not working, it takes f o r e v e r. It's not the server (see notes). How might I rewrite this so that it runs in under a day? Notes: As for server optimization: both tables are myisam and have unique indexes on the matching fields; the myisam key buffer is greater than the sum of both index file sizes, and it is not even being fully taxed (key_blocks_unused is ... large); the server is a dual-xeon 2U beast with fast sas drives and 8G of ram, fine-tuned for the mysql workload.

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• Mysql advanced SELECT, or multiple SELECTS? Movies keywords

  - by Supyxy

  I have a mysql database with movies as follows: MOVIES(id,title) KEYWORDS_TABLE(id,key_id) [id is referenced to movies.id, key_id is refernced to keywords.id] KEYWORDS(id,keyword) //this doesn't matter on my example.. Basically i have movies with their titles and plot keywords for each one, i want to select all movies that have the same keywords with with a given movie id. I tried something like: SELECT key_id FROM keywords_table WHERE id=9 doing that in php and storing all the IDs in an array $key_id.. then i build another select that looks like: SELECT movies.title FROM movies,keywords_table WHERE keywords_table.key_id=$key_id[1] OR keywords_table.key_id=$key_id[2] OR ......... OR keywords_table.key_id=$key_id[n] This kinda works but it takes too much time as we talk about a database with thousands of thousands of records. So, any suggestions?? thanks!

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• php extract data from mysql

  - by florin

  I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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• Common views in viewControllers - Code re-usability

  - by Nitish

  I have few common views in most of my viewControllers. What I noticed is that I can reuse single code for all viewControllers which is absolutely wise. For this I decided to create a class Utils which has static methods like +(void)createCommonViews:(float)yAxis:(NSString*)text; In my case common views are three labels and two images. Problem : I am not able to add these views from Utils. I am wondering how can I send self as a parameter so that I may add the views from Utils. It may be wrong to add views outside the viewController. In that case what can be the solution? Taking all these views in a UIView, setting return type of Utils method as UIView and then adding UIView to viewController(after calling method from viewController) might solve my problem. But what I am looking for is some other solution. Thanks, Nitish

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• Inserting records in Mysql with INSERT IGNORE and NULL values

  - by Homer1980ar

  I have a partitioned table InnoDB with several fields. I'm trying to avoid duplicates on insert. Let's say: Field1 int null Field2 int null Field3 int null Field4 int null Field5 int null I have created a UNIQUE index on those fields. I try to insert some records with NULL values and then try to reinsert them with IGNORE feature on MySql. Unfortunately it seems to replicated the records when using NULL values. If I try with zeros instead of NULL cases everything works, but I do need the nulls there. Any idea? Thanks, Leonardo

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• Question about mysql indexes on low to medium cardinality columns

  - by Kevin J

  I have a general question about the way that database indexing works, particularly in mysql. Let's say I have a table with a million rows with a column "ClientID" that is distributed relatively equally among 30 values. Thus, this column is very low cardinality (30) relative to the primary key (1 million). Now, I understand that you shouldn't create indexes on low cardinality fields. However, in this case, queries are only ever done with one of the 30 clientIDs. Thus, wouldn't creating an index on ClientID be helpful, as the search space is automatically reduced to 1/30th what it normally would be? Or is my understanding of how the index works flawed? Thanks

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• setting codeigniter mysql datetime column to time() always sets it to 0

  - by Jake

  Hi guys. I'm using Codeigniter for a small project, and my model works correctly except for the dates. I have a column defined: created_at datetime not null and my model code includes in its array passed into db-insert: 'created_at' = time() This produces a datetime value of 0000-00-00 00:00:00. When I change it to: 'created_at' = "from_unixtime(" . time() . ")" it still produces the 0 datetime value. What am I doing wrong? How can I set this field to the given unix time? Also, I know mysql sets TIMESTAMP columns automatically for you - I'm not interested in that solution here. So far I can't find a complete example of this on the web.

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• MySQL Rank Not Matching High Score in Table

  - by boddie

  While making a game the MySQL call to get the top 10 is as follows: SELECT username, score FROM userinfo ORDER BY score DESC LIMIT 10 This seems to work decently enough, but when paired with a call to get a individual player's rank the numbers may be different if the player has a tied score with other players. The call to get the players rank is as follows: SELECT (SELECT COUNT(*) FROM userinfo ui WHERE (ui.score, ui.username) >= (uo.score, uo.username)) AS rank FROM userinfo uo WHERE username='boddie'; Example results from first call: +------------+-------+ | username | score | +------------+-------+ | admin | 4878 | | test3 | 3456 | | char | 785 | | test2 | 456 | | test1 | 253 | | test4 | 78 | | test7 | 0 | | boddie | 0 | | Lz | 0 | | char1 | 0 | +------------+-------+ Example results from second call +------+ | rank | +------+ | 10 | +------+ As can be seen, the first call ranks the player at number 8 on the list, but the second call puts him at number 10. What changes or what can I do to make these calls give matching results? Thank you in advance for any help!

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• MySql - only update some rows if the table exists - do not want an error thrown

  - by Pete Oakey

  I want to run an update query. The query will be run against multiple databases - not every database will have the table. I don't want the update to be attempted if the table does not exist. I don't want any error to be thrown - I just want the update to be ignored. Any ideas? EDIT: just to be clear - the query is executed in an automated deployment - no human interaction possible. EDIT2: the logic to say whether the update should run or not will need to be in the MySql query itself. This is not being run through a command prompt or batch or managed code.

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• Displaying mysql results as an object?

  - by Michael

  If I have a database with the structure: ___id_____|____value____ 1 | value1 2 | value2 3 | value3 How can I pull data from this MySQL database in PHP and have it formatted like this: Array ( [0] => stdClass Object ( [id] => 1 [value] => value1 ) [1] => stdClass Object ( [id] => 2 [value] => value2 ) [2] => stdClass Object ( [id] => 3 [value] => value3 ) )

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• INSERT INTO error MYSQL/PHP

  - by bat

  I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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• MySQL Conventions?

  - by Moe

  Hi There, I just moved my website to a new server (Shared to VPS) I expected errors, and the only error that is really puzzling me is this SQL statement. echo mysql_query("SELECT COUNT(*) FROM users_online_now") This returns nothing! And if I try the mysql_num_rows, it returns mysql_num_rows(): supplied argument is not a valid MySQL result resource.. If I query another table though eg: echo mysql_query("SELECT COUNT(*) FROM users") It works fine. I'm guessing it's something to do with the naming of the table? It worked fine on my previous host, is there some setting I should modify?

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• how to insert date in mysql table

  - by mithun1538

  Hello everyone, I have a mysql table called pollOfTheWeek. It has a column "pollDate" of type date. I have two questions regarding this : 1. I declared the column while creating the table as [pollDate date] What I wanted is that this column be set automatically, when the user doesnt enter any value for this column. How do i declare the column to achieve this? Assuming that I have the same declaration as above, how do I enter an empty value. I mean if the column was of type varchar, I would enter empty value as " ". But since it is of type date, I get error when I enter the value as " ". How do I enter empty value for the pollDate column?

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• MySQL Inserting into locked aliased table

  - by Whitey

  I am trying to insert data into a InnoDB MySQL table which is locked using an alias and I cannot for the life of me get it to work! The following works: LOCK TABLES Problems p1 WRITE, Problems p2 WRITE, Server READ; SELECT * FROM Problems p1; UNLOCK TABLES; But try and do an insert and it doesn't work (it claims there is a syntax error round the 'p1' in my INSERT): LOCK TABLES Problems p1 WRITE, Problems p2 WRITE, Server READ; INSERT INTO Problems p1 (SomeCol) VALUES(43534); UNLOCK TABLES; Help please!

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• inserting date timestamp value to mysql thru php in godaddy hosting site

  - by Suj

  Hi all, I'm using GoDaddy's Shared Linux hosting. Using php i am inserting or updating the mysql database with create date or modified date using the variables $datestring = "%Y:%m:%d %h:%i:%s"; $time = time(); $createdate= mdate($datestring, $time); In this $createdate will be the variable i use to insert or update the table. But its updating the wrong value. ITs not the server time or localtime. mostly its 30 mins delay with godaddy's server time. Pls help.

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• searching a mysql database

  - by Bill Parson

  currently i have a database of music that i have db'd in mysql, now i am writing a php frontend for it, and it will list out everything in a table, it works, but if i search "the beatles" it gives me 453 results(correct) however if i just search "beatles" it results in 0 rows, how would i go about making it able to search for something like that? heres my current line: $query2 = "SELECT * From `songs` WHERE `Artist` like '".$_REQUEST['q']."' OR `Album` like '".$_REQUEST['q']."' OR `Genre` like '".$_REQUEST['q']."' OR `Title` like '".$_REQUEST['q']."';";

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• mysql and .net: when using tableadapters I’m getting MySqlException “insert command denied for user”

  - by Deveti Putnik

  Hi! I am using mysql as db for my asp.net application. Here are the facts: I am using connection string from web.config which has both username and password. I can do SELECT with tableadapter. When I am trying to do INSERT with tableadapter, I am getting "mysqlexception insert command denied for user" error When I try to do INSERT programatically, i.e. using connection, command object, etc. everything is fine. In this case, I'm reading connection string from web.config, too. This can be only applied to GoDaddy hosting, but on local machine I don't have this kind of problems. Can anyone suggest what can I do to make it work on GoDaddy hosting? Regards, D

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• Automated URL checking from a MySQL table

  - by Rob

  Okay, I have a list of URLs in a MySQL table. I want the script to automatically check each link in the table for 404, and afterward I want it to store whether the URL was 404'd or not, as well as store a time for last checked. Is this even possible to do automatically, even if no one runs the script? ie, no one visits the page for a few days, but even with no one visiting the page, it automatically ran the test. If its possible, how could I go about making a button to do this?

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• MySQL: Get only count of result set.

  - by Varun

  I am using MVC with PHP/MySQL. Suppose I am using 10 functions with different queries for fetching details from the database. But at other times I may want to get only the count of the result that will be returned by the query. What is the standard way to handle such situation. Should I write 10 more functions which duplicate almost whole query and return only the count. Or Should I always return the count also with the result set Or I can pass a flag to indicate that the function should return count only, and then based on the flag I will dynamically generate the (select part of) query. Or Is there a better way?

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• Mysql Date formats and url query

  - by jasmine

  I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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• How do I locate instances of <CR><LF><LF> in a mysql longtext field

  - by Ilane

  I would like to query my table for how many rows contain one or more instances of <CR><LF><LF>. I can't figure out the correct syntax. I would try LIKE '%<CR><LF><LF>%', but I don't know how to specify these special characters. I did try where mydata REGEXP '%[.CR.][.LF.][.LF.]%', and that didn't get a syntax error but neither did it return any rows. So, I realized I need a way to insert the test data as well! Note: I am using mysql 5.0.

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• Mysql query - problem with order by

  - by Sergio

  I'm using two tables for selecting messages between users. Table "messages" for recording the messages and table "members" for checking users data (are they activ or deleted). This query working fine. What I need to do is list the received messsages order by last received. I tried to do with "ORDER BY messages.id DESC" at the end of this query but it didn't work. All messages are listed from first received. This is the mysql join table query that I'm using: sql = "select distinct messages.fromid, messages.readed, messages.fromid, messages.toid, members.id as pid From messages Inner Join members on members.id = messages.fromid Where messages.toid = ".$mid." AND members.status = 7 AND messages.kreaded !='1' AND messages.subject != 'readed' GROUP BY fromid" Is there any way to do this?

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• Mysql two table query

  - by Sergio

  I'm using two tables. First (friendlist), which contains users who are on the list of friends and the other table (members) that contains the basic data of the users. Friendlist looks like: id | myid | date | user ----------------------------------------- 001 | 50624 | 2010-01-01 | 32009 002 | 41009 | 2010-05-05 | 50624 003 | 50624 | 2010-03-02 | 23007 The column "myid" contains members who added other users (those from column "user") to their frindlist. I want to get the list of all users that I have added to list and those who add me to their friendlist. In this example, if my id is 50624, the list would look like: | allfriends | --------------- 32009 41009 23007 Then I need to check all users from "allfriend" list with data from the table "members". I want to get only the users with status 1. The members table looks like: id | status | photo -------------------------------- 32009 | 0 | 1.jpg 41009 | 1 | 2.jpg 23007 | 1 | 3.jpg How this mysql query should look like? Thanks for any help.

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