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• How to Add Serialized LINQ to SQL Entities to a Word 2007 Document

  - by Ryan Riley

  I built a template-based document generator using the Open XML SDK (1.0), the Word 2007 Content Control Toolkit and LINQ to SQL (using the CodeSmith PLINQO templates). To do this, I serialized the LINQ to SQL entities to XML by retrieving the entity using DataLoadOptions specified in the source code. This works great, except that to initially populate the XML in my template, I currently have to copy and paste the XML from the Immediate window in VS2008 into the Content Control Toolkit, and it still has all the data from the current entity. I'm looking for two solutions: 1) Is this a good way to build a document generator with Word 2007? 1) How can I generate just the XML I need without the data? I've thought of creating an XSD and then creating an empty XML document, but wasn't sure how to do that programatically so that a business user can get the XML for the template. (That's not a requirement, just a nice-to-have.) Thanks for your feedback, Ryan

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• SQL Query Not Functioning - No Error Message

  - by gamerzfuse

  // Write the data to the database $query = "INSERT INTO staff (name, lastname, username, password, position, department, birthmonth, birthday, birthyear, location, phone, email, street, city, state, country, zip, tags, photo) VALUES ('$name', '$lastname', '$username', '$password', '$position', '$department', '$birthmonth', '$birthday', '$birthyear', '$location', '$phone', '$email', '$street', '$city', '$state', '$country', '$zip', '$tags', '$photo')"; mysql_query($query); var_dump($query); echo '<p>' . $name . ' has been added to the Employee Directory.</p>'; if (!$query) { die('Invalid query: ' . mysql_error()); } Can someone tell me why the above code produced: string(332) "INSERT INTO staff (name, lastname, username, password, position, department, birthmonth, birthday, birthyear, location, phone, email, street, city, state, country, zip, tags, photo) VALUES ('Craig', 'Hooghiem', 'sdf', 'sdf', 'sdf', 'sdf', '01', '01', 'sdf', 'sdf', '', 'sdf', 'sdf', 'sd', 'sdf', 'sdf', 'sd', 'sdg', 'leftround.gif')" Craig has been added to the Employee Directory. But does not actually add anything into the database table "staff" ? I must be missing something obvious here.

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• Using Twitter OAuth for automatic status update

  - by ebae

  I want my website to automatically post status updates to a particular twitter account using OAuth in PHP. I test this using a URL www.mysite.com/update_status but it asks me for "user name" and "password", which is fine when I am testing it. But my website will not be able to insert this user name and password before posting the status update. So the question is how can a website which is in the server, automatically post a status update to an account without user filling out the user name and password. Is there any way to bypass this? I tried saving oAuth tokens, but it's not working. Thank you for your answer in advance!

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• SQLConnection.Open(); throwing exception

  - by flavour404

  Hi, Updating an old piece of software but in order to maintain backward compatibility I need to connect to a .mdb (access) database. I am using the following connection but keep getting an exception, why? I have validated the path, database existence etc. and that is all correct. string Server = "localhost"; string Database = drive + "\\btc2\\state\\states.mdb"; string Username = ""; string Password = "Lhotse"; string ConnectionString = "Data Source = " + Server + ";" + "Initial Catalog = " + Database + ";" + "User Id = '';" + "Password = " + Password + ";"; SqlConnection SQLConnection = new SqlConnection(); try { SQLConnection.ConnectionString = ConnectionString; SQLConnection.Open(); } catch (Exception Ex) { // Try to close the connection if (SQLConnection != null) SQLConnection.Dispose(); // //can't connect // // Stop here return false; }

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• How to use objetcs as modules/functors in Scala?

  - by Jeff

  Hi. I want to use object instances as modules/functors, more or less as shown below: abstract class Lattice[E] extends Set[E] { val minimum: E val maximum: E def meet(x: E, y: E): E def join(x: E, y: E): E def neg(x: E): E } class Calculus[E](val lat: Lattice[E]) { abstract class Expr case class Var(name: String) extends Expr {...} case class Val(value: E) extends Expr {...} case class Neg(e1: Expr) extends Expr {...} case class Cnj(e1: Expr, e2: Expr) extends Expr {...} case class Dsj(e1: Expr, e2: Expr) extends Expr {...} } So that I can create a different calculus instance for each lattice (the operations I will perform need the information of which are the maximum and minimum values of the lattice). I want to be able to mix expressions of the same calculus but not be allowed to mix expressions of different ones. So far, so good. I can create my calculus instances, but problem is that I can not write functions in other classes that manipulate them. For example, I am trying to create a parser to read expressions from a file and return them; I also was trying to write an random expression generator to use in my tests with ScalaCheck. Turns out that every time a function generates an Expr object I can't use it outside the function. Even if I create the Calculus instance and pass it as an argument to the function that will in turn generate the Expr objects, the return of the function is not recognized as being of the same type of the objects created outside the function. Maybe my english is not clear enough, let me try a toy example of what I would like to do (not the real ScalaCheck generator, but close enough). def genRndExpr[E](c: Calculus[E], level: Int): Calculus[E]#Expr = { if (level > MAX_LEVEL) { val select = util.Random.nextInt(2) select match { case 0 => genRndVar(c) case 1 => genRndVal(c) } } else { val select = util.Random.nextInt(3) select match { case 0 => new c.Neg(genRndExpr(c, level+1)) case 1 => new c.Dsj(genRndExpr(c, level+1), genRndExpr(c, level+1)) case 2 => new c.Cnj(genRndExpr(c, level+1), genRndExpr(c, level+1)) } } } Now, if I try to compile the above code I get lots of error: type mismatch; found : plg.mvfml.Calculus[E]#Expr required: c.Expr case 0 = new c.Neg(genRndExpr(c, level+1)) And the same happens if I try to do something like: val boolCalc = new Calculus(Bool) val e1: boolCalc.Expr = genRndExpr(boolCalc) Please note that the generator itself is not of concern, but I will need to do similar things (i.e. create and manipulate calculus instance expressions) a lot on the rest of the system. Am I doing something wrong? Is it possible to do what I want to do? Help on this matter is highly needed and appreciated. Thanks a lot in advance.

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• python, accessing a psycopg2 form a def?

  - by i-Malignus

  i'm trying to make a group of defs in one file so then i just can import them whenever i want to make a script in python i have tried this: def get_dblink( dbstring): """ Return a database cnx. """ global psycopg2 try cnx = psycopg2.connect( dbstring) except Exception, e: print "Unable to connect to DB. Error [%s]" % ( e,) exit( ) but i get this error: global name 'psycopg2' is not defined in my main file script.py i have: import psycopg2, psycopg2.extras from misc_defs import * hostname = '192.168.10.36' database = 'test' username = 'test' password = 'test' dbstring = "host='%s' dbname='%s' user='%s' password='%s'" % ( hostname, database, username, password) cnx = get_dblink( dbstring) can anyone give me a hand?

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• How to secure licensekey generation

  - by Jakob Gade

  Scenario, simplified for brevity: A developer creates an application for a customer. The customer sells this app to end-users. The app requires a license key to run, and this key is generated by the customer for each end-user with a simple tool created by the developer. The license key contains an expiry date for the license and is encrypted so the end-user can’t tamper with it. The problem here is that the developer (or anybody who has a copy of the license key generator) can easily create valid license keys. Should this generator fall into the wrong hands, it could spell disaster for the customers business. Ideally, the customer would have to use a password to create new license keys. And this password would be unknown to the developer, and somehow baked into the decryption algorithm in the application so it will fail if an attempt to use an unauthorized key is made. How would you implement a solution for this problem that is both transparent and secure?

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• How can I hide a database column in the entity model?

  - by Nick Butler

  Hi. I'm using the Entity Framework 4 and have a question: I have a password column in my database that I want to manage using custom SQL. So I don't want the model to know anything about it. I've tried deleting the property in the Mapping Details window, but then I got a compilation error: Error 3023: Problem in mapping fragments starting at line 1660:Column User.Password in table User must be mapped: It has no default value and is not nullable. So, I made the column nullable in the database and updated the model. Now I get this error: Error 3004: Problem in mapping fragments starting at line 1660:No mapping specified for properties User.Password, User.Salt in Set Users. An Entity with Key (PK) will not round-trip when: Entity is type [UserDirectoryModel.User] Any ideas please? Thanks, Nick

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• Discrete mathematics problem - Probability theory and counting

  - by Mohammad

  Hello All, I'm taking a discrete mathematics course, and I encountered a question and I need your help. I don't know if this is the right place for that though :) It says: Each user on a computer system has a password, which is six to eight characters long, where each character is an uppercase letter or a digit. Each password must contain at least one digit. How many possible passwords are there? The book solves this by adding the probabilities of having six,seven and eight characters long password. However, when he solves for probability of six characters he does this P6 = 36^6 - 26^6 and does P7 = 36^7 - 26^7 and P8 = 36^8 - 26^8 and then add them all I understand the solution, but my question is why doesn't calculating, P6 = 10*36^5 and the same for P7 and P8, work? 10 for the digit and 36 for the alphanumeric? Also, if anyone could give me another solution, other than the one in the book. Thank you very much :)

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• getting last insert id .sqlalchemy orm

  - by gummmibear

  Hi i use sqlalchemy, i need some help. import hashlib import sqlalchemy as sa from sqlalchemy import orm from allsun.model import meta t_user = sa.Table("users",meta.metadata,autoload=True) class Duplicat(Exception): pass class LoginExistsException(Exception): pass class EmailExistsException(Exception): pass class User(object): """ def __setattr__(self, key, value): if key=='password' : value=unicode(hashlib.sha512(value).hexdigset()) object.__setattr__(self,key,value) """ def loginExists(self): try: meta.Session.query(User).filter(User.login==self.login).one() except orm.exc.NoResultFound: pass else: raise LoginExistsException() def emailExists(self): try: meta.Session.query(User).filter(User.email==self.email).one() except orm.exc.NoResultFound: pass else: raise EmailExistsException() def save(self): meta.Session.begin() meta.Session.save(self) try: meta.Session.commit() except sa.exc.IntegrityError: raise Duplicat() How can i get inserted id when i call? user = User() user.login = request.params['login'] user.password = hashlib.sha512(request.params['password']).hexdigest() user.email = request.params['email'] user.save()

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• Import SQL dump into MySQL

  - by BryanWheelock

  I'm confused how to import a SQL dump file. I can't seem to import the database without creating the database first in MySQL. This is the error displayed when database_name has not yet been created: username = username of someone with access to the database on the original server. database_name = name of database from the original server $ mysql -u username -p -h localhost database_name < dumpfile.sql Enter password: ERROR 1049 (42000): Unknown database 'database_name' If I log into MySQL as root and create the database, database_name mysql -u root create database database_name; create user username;# same username as the user from the database I got the dump from. grant all privileges on database_name.* to username@"localhost" identified by 'password'; exit mysql then attempt to import the sql dump again: $ mysql -u username -p database_name < dumpfile.sql Enter password: ERROR 1007 (HY000) at line 21: Can't create database 'database_name'; database exists How am I supposed to import the SQL dumpfile?

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• GORM ID generation and belongsTo association ?

  - by fabien-barbier

  I have two domains : class CodeSetDetail { String id String codeSummaryId static hasMany = [codes:CodeSummary] static constraints = { id(unique:true,blank:false) } static mapping = { version false id column:'code_set_detail_id', generator: 'assigned' } } and : class CodeSummary { String id String codeClass String name String accession static belongsTo = [codeSetDetail:CodeSetDetail] static constraints = { id(unique:true,blank:false) } static mapping = { version false id column:'code_summary_id', generator: 'assigned' } } I get two tables with columns: code_set_detail: code_set_detail_id code_summary_id and code_summary: code_summary_id code_set_detail_id (should not exist) code_class name accession I would like to link code_set_detail table and code_summary table by 'code_summary_id' (and not by 'code_set_detail_id'). Note : 'code_summary_id' is define as column in code_set_detail table, and define as primary key in code_summary table. To sum-up, I would like define 'code_summary_id' as primary key in code_summary table, and map 'code_summary_id' in code_set_detail table. How to define a primary key in a table, and also map this key to another table ?

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• Downloading a Directory Tree with FTPLIB

  - by Anthony Lemmer

  I'd like to download a directory and all of its contents to the local HD. Here's the code I have thus far (crashes if there's a sub-directory, else grabs all the files): import ftplib import configparser import os def runBackups(): #Load INI filename = 'connections.ini' config = configparser.SafeConfigParser() config.read(filename) connections = config.sections() i = 0 while i < len(connections): #Load Settings uri = config.get(connections[i], "uri") username = config.get(connections[i], "username") password = config.get(connections[i], "password") backupPath = config.get(connections[i], "backuppath") archiveTo = config.get(connections[i], "archiveto") #Start Back-ups ftp = ftplib.FTP(uri) ftp.login(username, password) ftp.set_debuglevel(2) ftp.cwd(backupPath) files = ftp.nlst() for filename in files: ftp.retrbinary('RETR %s' % filename, open(os.path.join(archiveTo, filename), 'wb').write) ftp.quit() i += 1 print() print("Back-ups complete.") print()

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• PHP Error - Login Script

  - by gamerzfuse

  I am creating a new login script/members directory. I am creating it from scratch without any frameworks (advice on this matter would also be appreciated). The situation: // Look up the username and password in the database $query = "SELECT admin_id, username FROM admin WHERE adminname = '$admin_user' AND password = SHA1('$admin_pass')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { This bit of code keeps giving me an error (the last line in particular): Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in /home8/craighoo/public_html/employees/security/dir_admin.php on line 20 When echoing the query I get: SELECT admin_id, username FROM admin WHERE adminname = 'admin' AND password = SHA1('tera#byte') Thanks in advance!

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• Is it possible to scan Entities in jar files using JPA and hibernate

  - by user1260109

  I have the following situation : Project A - Contains a few entities and is independent Project B - Contains a few entities and is independent Project C - Contains few entities and is dependent on Project A & Project B. I am using Maven to manage dependencies and builds. When I try to test Project A and project B it goes through fine. Each of them has a persistence.xml and a separate persistent context. When I run Project C , It does map any of the entities. I have tried to use the auto-detect, specified the jar file attribute ... but nothing seems to work. It gives me a Mapping Exception saying unknown entity and wont persist or read the Entities from Projects A or B. I have posted the 3 persistence.xml files here. Also, I tried using the class attribute and using the same persistent context but it just wont find the files. Any help is really appreciated. Thanks in advance ! <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="A" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="B" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="C" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jar-file>A-0.0.1-SNAPSHOT.jar</jar-file> <jar-file>B-0.0.1-SNAPSHOT.jar</jar-file> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence>

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• Login to Gmail Inbox using Curl ?

  - by Vishwanath dalvi

  Hello friends, I'm doing a project where user will first save his gmail id and password and after confirmation,I will provide a link for directly login to gmail next time without entering his gmail id and password.. the saved password will passed as a parameters of userid and passwd using CURL I'm doing this using php.. I heard about curl to do this.. I tried lots of code but didn't get any working code.. Can anyone tell me.. how do i just login to gmail inbox .. using CURL in PHP ??

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• How safe am I signing into Google Spreadsheets with yeroon.net/ggplot2

  - by Farrel

  I am impressed by what I have seen of yeroon.net/ggplot2 which is a web interface for Hadley Wickham's R package ggplot2. I want to try it out on my own data. The part that has me very excited is that one can use data stored in one's own Google spreadsheet as the data. One just signs into their Google Account so that yeroon.net/ggplot2 can access the spreadsheet list. I have been hesitant to do it. If I sign in whilst on yeroon.net am I handing over my username and password to a third party? It would not be wise of me to divulge my google password to third parties since Google is fast becoming my repository of everything. How do I know if Jeroon's application is using ClientLogin or OAuth? My understanding is very basic and may be wrong but nevertheless here it is. OAuth would be better since it does not actually pass the password onto the third party application.

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• Django admin.py missing field error

  - by user782400

  When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

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• bi-directional o2m/m2o beats uni-directional o2m in SQL efficiency?

  - by Henry

  Use these 2 persistent CFCs for example: // Cat.cfc component persistent="true" { property name="id" fieldtype="id" generator="native"; property name="name"; } // Owner.cfc component persistent="true" { property name="id" fieldtype="id" generator="native"; property name="cats" type="array" fieldtype="one-to-many" cfc="cat" cascade="all"; } When one-to-many (unidirectional) Note: inverse=true on unidirectional will yield undesired result: insert into cat (name) values (?) insert into Owner default values update cat set Owner_id=? where id=? When one-to-many/many-to-one (bi-directional, inverse=true on Owner.cats): insert into Owner default values insert into cat (name, ownerId) values (?, ?) Does that mean setting up bi-directional o2m/m2o relationship is preferred 'cause the SQL for inserting the entities is more efficient?

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• Embedding generic sql queries into c# program

  - by Pooja Balkundi

  Okay referring to my first question code in the main, I want the user to enter employee name at runtime and then i take this name which user has entered and compare it with the e_name of my emp table , if it exists i want to display all information of that employee , how can I achieve this ? using System; using System.Collections.Generic; using System.Linq; using System.Windows.Forms; using MySql.Data.MySqlClient; namespace ConnectCsharppToMySQL { public class DBConnect { private MySqlConnection connection; private string server; private string database; private string uid; private string password; string name; //Constructor public DBConnect() { Initialize(); } //Initialize values private void Initialize() { server = "localhost"; database = "test"; uid = "root"; password = ""; string connectionString; connectionString = "SERVER=" + server + ";" + "DATABASE=" + database + ";" + "UID=" + uid + ";" + "PASSWORD=" + password + ";"; connection = new MySqlConnection(connectionString); } //open connection to database private bool OpenConnection() { try { connection.Open(); return true; } catch (MySqlException ex) { //When handling errors, you can your application's response based //on the error number. //The two most common error numbers when connecting are as follows: //0: Cannot connect to server. //1045: Invalid user name and/or password. switch (ex.Number) { case 0: MessageBox.Show("Cannot connect to server. Contact administrator"); break; case 1045: MessageBox.Show("Invalid username/password, please try again"); break; } return false; } } //Close connection private bool CloseConnection() { try { connection.Close(); return true; } catch (MySqlException ex) { MessageBox.Show(ex.Message); return false; } } //Insert statement public void Insert() { string query = "INSERT INTO emp (e_name, age) VALUES('Pooja R', '21')"; //open connection if (this.OpenConnection() == true) { //create command and assign the query and connection from the constructor MySqlCommand cmd = new MySqlCommand(query, connection); //Execute command cmd.ExecuteNonQuery(); //close connection this.CloseConnection(); } } //Update statement public void Update() { string query = "UPDATE emp SET e_name='Peachy', age='22' WHERE e_name='Pooja R'"; //Open connection if (this.OpenConnection() == true) { //create mysql command MySqlCommand cmd = new MySqlCommand(); //Assign the query using CommandText cmd.CommandText = query; //Assign the connection using Connection cmd.Connection = connection; //Execute query cmd.ExecuteNonQuery(); //close connection this.CloseConnection(); } } //Select statement public List<string>[] Select() { string query = "SELECT * FROM emp where e_name=(/*I WANT USER ENTERED NAME TO GET INSERTED HERE*/)"; //Create a list to store the result List<string>[] list = new List<string>[3]; list[0] = new List<string>(); list[1] = new List<string>(); list[2] = new List<string>(); //Open connection if (this.OpenConnection() == true) { //Create Command MySqlCommand cmd = new MySqlCommand(query, connection); //Create a data reader and Execute the command MySqlDataReader dataReader = cmd.ExecuteReader(); //Read the data and store them in the list while (dataReader.Read()) { list[0].Add(dataReader["e_id"] + ""); list[1].Add(dataReader["e_name"] + ""); list[2].Add(dataReader["age"] + ""); } //close Data Reader dataReader.Close(); //close Connection this.CloseConnection(); //return list to be displayed return list; } else { return list; } } public static void Main(String[] args) { DBConnect db1 = new DBConnect(); Console.WriteLine("Initializing"); db1.Initialize(); Console.WriteLine("Search :"); Console.WriteLine("Enter the employee name"); db1.name = Console.ReadLine(); db1.Select(); Console.ReadLine(); } } }

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• Proper way to set object instance variables

  - by ensnare

  I'm writing a class to insert users into a database, and before I get too far in, I just want to make sure that my OO approach is clean: class User(object): def setName(self,name): #Do sanity checks on name self._name = name def setPassword(self,password): #Check password length > 6 characters #Encrypt to md5 self._password = password def commit(self): #Commit to database >>u = User() >>u.setName('Jason Martinez') >>u.setPassword('linebreak') >>u.commit() Is this the right approach? Should I declare class variables up top? Should I use a _ in front of all the class variables to make them private? Thanks for helping out.

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• How do i use repoze.who?

  - by misterwebz

  I'm having some trouble understanding how repoze.who works. I've followed a tutorial i found by searching on google and here's what i already have: This is what i added in my middleware.py file from repoze.who.config import make_middleware_with_config as make_who_with_config app = make_who_with_config(app, global_conf, app_conf['who.config_file'], app_conf['who.log_file'], app_conf['who.log_level']) Here's the who.ini : http://pastebin.com/w5Tba2Fp Here's repoze_auth.py in /lib/auth/: from paste.httpexceptions import HTTPFound from iwant.model import User class UserModelPlugin(object): def authenticate(self, environ, identity): try: username = identity['login'] password = identity['password'] except KeyError: return None success = User.authenticate(username, password) return success def add_metadata(self, environ, identity): username = identity.get('repoze.who.userid') user = User.get(username) if user is not None: identity['user'] = user I've also checked the plugins in the repoze.who folder, but i failed to understand how it's supposed to be used. I'd appreciate it if someone would push me in the right direction.

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• Problem with HSQLDB & SequenceGenerator

  - by Srirangan

  Hi, I have an entity which has an ID field: @Id @Column(name = "`U##ID_VOIE`") @GeneratedValue(generator = "VOIE_SEQ") private String id; The class has the sequence generator defined as well: @SequenceGenerator(name = "VOIE_SEQ", sequenceName = "VOIE_SEQ") and the Oracle schema has the requisite sequence present. Everything works okay. We also have tests, which uses an in-memory HSQLDB. Before running the tests, all the tables are created based on the Hibernate entity classes. However the table for this particular class is not being created. And error pops up, because ID is a String and the SequenceGenerator in HSQLDB returns an INT / LONG / Numeric value. The application is using a legacy Oracle database and ID_VOIE column must remain a String / Varchar. Any solutions?

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• Help with MVC controller: passing a string from view to controller

  - by 109221793

  Hi guys, I'm having trouble with one particular issue, I was hoping someone could help me out. I've completed the MVC Music Store tutorial, and now I'm trying to add some administrator functionality - practice as I will have to do this in an MVC application in my job. The application is using the aspnet membership api, and what I have done so far is created a view to list the users. What I want to be able to do, is click on the users name in order to change their password. To try and carry the username to the changeUserPassword controller (custom made). I registered a new route in the global.asax.cs file in order to display the username in the URL, which is working so far. UserList View <%: Html.RouteLink(user.UserName, "AdminPassword", new { controller="StoreManager", action="changeUserPassword", username = user.UserName }) %> Global.asax.cs routes.MapRoute( "AdminPassword", //Route name "{controller}/{action}/{username}", //URL with parameters new { controller = "StoreManager", action = "changeUserPassword", username = UrlParameter.Optional} ); So now the URL looks like this when I reach the changeUserPassword view: http://localhost:51236/StoreManager/changeUserPassword/Administrator Here is the GET changeUserPassword action: public ActionResult changeUserPassword(string username) { ViewData["username"] = username; return View(); } I wanted to store the username in ViewData as I would like to use it in the GET changeUserPassword for display purposes, and also as a hidden value in the form. This is in order to pass it through to enable me to reset the password. Having debugged through the code, it seems that 'username' is null. How can I get this to work so that the username carries over from the Html.RouteLink, to the changeUserPassword action? Any help would be appreciated :) Here is my complete code: UserList.aspx <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Web.Security.MembershipUserCollection>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> UserList </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>UserList</h2> <table> <tr> <th>User Name</th> <th>Last Activity date</th> <th>Locked Out</th> </tr> <%foreach (MembershipUser user in Model){ %> <tr> <td><%: Html.RouteLink(user.UserName, "AdminPassword", new { controller="StoreManager", action="changeUserPassword", username = user.UserName }) %></td> <td><%: user.LastActivityDate %></td> <td><%: user.IsLockedOut %></td> </tr> <% }%> </table> </asp:Content> changeUserPassword.aspx <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<musicStoreMVC.ViewModels.ResetPasswordAdmin>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> changeUserPassword </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>Change Password: <%: ViewData["username"] %></h2> <% using (Html.BeginForm()) {%> <%: Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> <%: Html.Hidden("username",ViewData["username"]) %> <%: Html.LabelFor(model => model.password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.password) %> <%: Html.ValidationMessageFor(model => model.password) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.confirmPassword) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.confirmPassword) %> <%: Html.ValidationMessageFor(model => model.confirmPassword) %> </div> <p> <input type="submit" value="Create" /> </p> </fieldset> <% } %> <div> <%: Html.ActionLink("Back to List", "Index") %> </div> </asp:Content> My actions public ActionResult UserList() { var users = Membership.GetAllUsers(); return View(users); } public ActionResult changeUserPassword(string username) { ViewData["username"] = username; return View(); }

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• Where is a SharePoint Community for Webparts?

  - by elhombre

  Hi all I am searching a SharePoint Server 2007 Webpart which can do following * change password * lost password recovery (e-mail) * change password reminder (e-mail) I have been searching the Internet but somehow there aint as many webparts as for example WordPress Addons. When I am lucky I can find individuals which made an Webpart which matches one of the specs :( The only things which come near my specs are http://www.envisionit.com/Products/Pages/ExtranetModuleforSharePoint.aspx http://userchangepassword.codeplex.com I am wondering where I can find community's which have lots of Webparts to download or sell. Does anybody of you know such community's?

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