Search Results

Search found 12223 results on 489 pages for 'password generator'.

Page 141/489 | < Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >

  • Cross Domain Post - Losing POST Data

    - by Tomas Beblar
    I have 2 servers, both running R2 / IIS7 / ASP Classic sites (can't get around any of that) Server A is making the follow calls: Dim objXMLHTTP, xml Set xml = Server.CreateObject("Msxml2.ServerXmlHTTP.6.0") xml.Open "POST", templateName, false xml.setRequestHeader "Content-Type", "application/xml" xml.Send variables Where the templateName is the URL of Server B (It's an email template) ... and variables are a name value pair string like a query string password=myPassword&customerEmail=Dear+Bob,.... Server B receives the POST but all the POST data (password=myPassword&customerEmail=Dear+Bob,....) is missing from the POST password = Request.Form("templatePassword") customerEmail = Request.Form("RackAttackCustomerEmail") The above values are all empty. Here's the kicker. This all worked on our old servers (Windows Server 2003, IIS 6) But when we migrated over, this stopped working correctly. My question is: What would cause the POST data to be dropped in IIS 7 when it all worked in IIS 6? I've done about 3 days of research into this trying many different things and nothing has worked. The POST data is just gone.

    Read the article

  • Multiple Forms on the Same Page with Rails

    - by Eric Koslow
    So I'm building a rails app for high school students and I've hit a problem when it comes to creating users. I want the students to only be able to create accounts if they select their school and type in their school's password correctly. What is the correct / easiest way of doing this? Should I create a gatekeeper to the user#new action that they have to pass first or if their a way that on the same page a student can submit to forms. One would be the regular username, email, password using: form_for @user do ... end But then creating another form for the high-school / high-school password selection. Ideally the controller would be able to get the params of the high-school form, validate those, then go on to create the user from the user params. Is this possible using rails? My setup: Rails 3 and Ruby 1.9.2dev Thank you!

    Read the article

  • How to force grails GORM to respect DB scheme ?

    - by fabien-barbier
    I have two domains : class CodeSet { String id String owner String comments String geneRLF String systemAPF static hasMany = [cartridges:Cartridge] static constraints = { id(unique:true,blank:false) } static mapping = { table 'code_set' version false columns { id column:'code_set_id', generator: 'assigned' owner column:'owner' comments column:'comments' geneRLF column:'gene_rlf' systemAPF column:'system_apf' } } and : class Cartridge { String id String code_set_id Date runDate static belongsTo = CodeSet static constraints = { id(unique:true,blank:false) } static mapping = { table 'cartridge' version false columns { id column:'cartridge_id', generator: 'assigned' code_set_id column:'code_set_id' runDate column:'run_date' } } Actually, with those models, I get tables : - code_set, - cartridge, - and table : code_set_cartridge (two fields : code_set_cartridges_id, cartridge_id) I would like to not have code_set_cartridge table, but keep relationship : code_set -- 1:n -- cartridge In other words, how can I keep association between code_set and cartridge without intermediate table ? (using code_set_id as primary key in code_set and code_set_id as foreign key in cartridge). Mapping with GORM can be done without intermediate table?

    Read the article

  • What is the best way to marshal a char array function argument?

    - by Seh Hui 'Felix' Leong
    Let say that given the following signature in LegacyLib.dll: int Login(SysInst *inst, char username[8], char password[6]); The simple way to marshal this function in C# would be: [DllImport("LegacyLib.dll", CharSet=CharSet.Ansi)] public static extern int Login(ref SysInst inst, string username, string password); The problem of doing it in a such a naive way is that the managed string we passed into the username or password parameter could be longer than the array bounds and this could potentially cause a buffer overrun in LegacyLib.dll. Is there a better way which overcomes this problem? i.e. is there any quick [MarshalAs(…)] magic that I could use to counter that?

    Read the article

  • ASP MVC: Custom Validation Attribute

    - by user323395
    I'm trying to write my own Custom Validation attribute but i'm having some problems. The attribute i'm trying to write is that when a user logs in, the password will be compared against the confirmation password. namespace EventCompanion.Data.Attributes { public class ComparePassword : ValidationAttribute { public string PasswordToCompareWith { get; set; } public override bool IsValid(object value) { if (PasswordToCompareWith == (string)value) { return true; } return false; } } Now my problem is when i'm trying to set the attribute like this in the model file: [Required] [ComparePassword(PasswordToCompareWith=ConfirmPassword)] public string Password { get; set; } [Required] public string ConfirmPassword { get; set; } } I get the following error: Error 1 An object reference is required for the non-static field, method, or property 'Project.Data.Models.GebruikerRegistreerModel.ConfirmPassword.get' It seems that VS is not accepting the confirmpassword in the "PasswordToCompareWith=ConfirmPassword" part Now my question: What am i doing wrong? Thanks in advance!!!

    Read the article

  • How do I make an HTTP Post with HTTP Basic Authentication, using POCO?

    - by Alyoshak
    I'm trying to make an HTTP Post with HTTP Basic Authentication (cleartext username and password), using POCO. I found an example of a Get and have tried to modify it, but being a rookie I think I've mangled it beyond usefulness. Anyone know how to do this? Yes, I've already seen the other SO question on this: POCO C++ - NET SSL - how to POST HTTPS request, but I can't make sense of how it is trying to implement the username and password part. I also don't understand the use of "x-www-form-urlencoded". Is this required for a Post? I don't have a form. Just want to POST to the server with username and password parameters.

    Read the article

  • How to validate SWT form?

    - by Rahul
    Label label1 = new Label(container, SWT.NULL); label1.setText("Enter the Password "); text1 = new Text(container, SWT.BORDER | SWT.PASSWORD); text1.setText(""); text1.addKeyListener(new KeyListener() { public void keyPressed(KeyEvent e) { } public void keyReleased(KeyEvent e) { if (!text5.getText().isEmpty()) { setPageComplete(false); } } }); hi, i am creating form using SWT in eclipse can anyone tell me how to validate that form entry above is the sample code of that..actually i want to validate password field it should be minimum length of 6.How to do this please reply.

    Read the article

  • Using Api to submit userdata to external party

    - by Younes
    I have to submit subscription data to another website. I have got documentation on how to use this API however i'm not 100% sure of how to set this up. I do have all the information needed, like username / passwords etc. This is the API documentation: https://www.apiemail.net/api/documentation/?SID=4 How would my request / post / whatever look like in C# .net (vs 2008) when i'm trying to acces this API? This is what i have now, I think i'm not on the right track: public static string GArequestResponseHelper(string url, string token, string username, string password) { HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(url); myRequest.Headers.Add("Username: " + username); myRequest.Headers.Add("Password: " + password); HttpWebResponse myResponse = (HttpWebResponse)myRequest.GetResponse(); Stream responseBody = myResponse.GetResponseStream(); Encoding encode = System.Text.Encoding.GetEncoding("utf-8"); StreamReader readStream = new StreamReader(responseBody, encode); //return string itself (easier to work with) return readStream.ReadToEnd();

    Read the article

  • Update User Info with restful_authentication plugin in Rails?

    - by benoror
    Hi people, I want to give the users the ability to change their account info with restful_authentication plugin in rails. I added this two methods to my users controller: def edit @user = User.find(params[:id]) end def update @user = User.find(params[:id]) # Only update password when necessary params[:user].delete(:password) if pàrams[:user][:password].blank? respond_to do |format| if @user.update_attributes(params[:user]) flash[:notice] = 'User was successfully updated.' format.html { redirect_to(@user) } format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @user.errors, :status => :unprocessable_entity } end end end Also, I copied new.html.erb to edit.html.erb. Considering that resources are already defined in routes.rb I was expecting it to work easily, bute somehow when I click the save button it calls the create method, instead of update, using a POST http request. Inmediatly after that it autocatically log out form the session. Any ideas?

    Read the article

  • Objective-C "if" statements not retaining

    - by seanny94
    I know the title of this question is a bit confusing, but here it goes anyway: I'm creating an NSString after an if statement but it just doesn't seem to want to retain outside of the statement. My conditional looks like this: if ([[password stringValue] isEqualToString:@""]) { NSString *pwd = [[NSString alloc]initWithString:@"password"]; } else { NSString *pwd = [[NSString alloc]initWithFormat:@"%@", [password stringValue]]; } ... and I call pwd later in the script like this: NSArray *arguments; arguments = [NSArray arrayWithObjects: ip, pwd, nil]; [task setArguments: arguments]; But when I do so in this way, the first snippet returns a warning of Unused variable 'pwd' and the latter call ends up in an error of 'pwd' undeclared. What am I doing wrong here? Thanks in advance. ;)

    Read the article

  • Django : mysql : 1045, "Access denied for user

    - by PlanetUnknown
    I have the whole setup working for months on my local computer. I'm installing on a remote site now. Created a fresh mysql DB, and created a new user ("someuser") and gave it complete grants, like so - GRANT ALL PRIVILEGES ON . TO 'someuser'@'localhost' IDENTIFIED BY 'somepassword' WITH GRANT OPTION; I have sync'd the db, using "python manage.py syncdb" and the correct tables were created. My settings.py has this same user. But when I try to login a user through the application, and it hits the DB, I see the following in the logs - (1045, "Access denied for user 'someuser'@'localhost' (using password: YES)") I logged in through mysql (installed on the same box as django) and checked the grants and it correctly shows - Grants for djangouser@localhost GRANT ALL PRIVILEGES ON * . * TO 'someuser'@'localhost' IDENTIFIED BY PASSWORD '*thesaltedpasswordOverHere' WITH GRANT OPTION I don't want to use the root user/password for django, since it doesn't seem the correct way. Any pointers as to what might be wrong ?

    Read the article

  • not getting output from parmiko/ssh command

    - by Matt
    I am using paramiko/ssh/python to attempt to run a command on a remote server. When I ssh manually and run the command in question, I get the results I want. But if I use the python (co-opted from another thread on this site) below, there is no returned data. If I modify the command to be something more basic like 'pwd' or 'ls' I can then get the output. Any help is appreciated. Thanks, Matt import paramiko import time import sys, os, select import select username='medelman' password='Ru5h21iz' hostname='10.15.27.166' hostport=22 cmd='tail -f /x/web/mlog.txt' #works cmd='' #doesn't work client = paramiko.SSHClient() client.load_system_host_keys() client.connect(hostname=hostname, username=username, password=password) transport = client.get_transport() channel = transport.open_session() channel.exec_command(cmd) while True: rl, wl, xl = select.select([channel],[],[],0.0) if len(rl) 0: # Must be stdout print channel.recv(1024) time.sleep(1)

    Read the article

  • SQL Access INSERT INTO Autonumber Field

    - by KrazyKash
    I'm trying to make a visual basic application which is connected to a Microsoft Access Database using OLEDB. Inside my database I have a user table with the following layout ID - Autonumber Username - Text Password - Text Email - Text To insert data into the table I use the following query INSERT INTO Users (Username, Password, Email) VALUES ('004606', 'Password', '[email protected]') However I seem to get an error with this statement and according to VB it's a syntax error. But then I tried to use the following query INSERT INTO Users (Username) Values ('004606') This query seemed to work absolutely fine... So the problem is I can insert into just one field but not all 3 (excluding the ID field because it's an autonumber). Any help would be appreciated, Thanks

    Read the article

  • login form whith java/sqlite

    - by tuxou
    hi I would like to create a login form for my application with the possibility to add or remove users for an sqlite database, i have created the table users(nam, pass) but i can't unclud it in my login form, it someone could help me this is my login code: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class login extends JFrame { // Variables declaration private JLabel jLabel1; private JLabel jLabel2; private JTextField jTextField1; private JPasswordField jPasswordField1; private JButton jButton1; private JPanel contentPane; // End of variables declaration public login() { super(); create(); this.setVisible(true); } private void create() { jLabel1 = new JLabel(); jLabel2 = new JLabel(); jTextField1 = new JTextField(); jPasswordField1 = new JPasswordField(); jButton1 = new JButton(); contentPane = (JPanel)this.getContentPane(); // // jLabel1 // jLabel1.setHorizontalAlignment(SwingConstants.LEFT); jLabel1.setForeground(new Color(0, 0, 255)); jLabel1.setText("username:"); // // jLabel2 // jLabel2.setHorizontalAlignment(SwingConstants.LEFT); jLabel2.setForeground(new Color(0, 0, 255)); jLabel2.setText("password:"); // // jTextField1 // jTextField1.setForeground(new Color(0, 0, 255)); jTextField1.setSelectedTextColor(new Color(0, 0, 255)); jTextField1.setToolTipText("Enter your username"); jTextField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jTextField1_actionPerformed(e); } }); // // jPasswordField1 // jPasswordField1.setForeground(new Color(0, 0, 255)); jPasswordField1.setToolTipText("Enter your password"); jPasswordField1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jPasswordField1_actionPerformed(e); } }); // // jButton1 // jButton1.setBackground(new Color(204, 204, 204)); jButton1.setForeground(new Color(0, 0, 255)); jButton1.setText("Login"); jButton1.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { jButton1_actionPerformed(e); } }); // // contentPane // contentPane.setLayout(null); contentPane.setBorder(BorderFactory.createEtchedBorder()); contentPane.setBackground(new Color(204, 204, 204)); addComponent(contentPane, jLabel1, 5,10,106,18); addComponent(contentPane, jLabel2, 5,47,97,18); addComponent(contentPane, jTextField1, 110,10,183,22); addComponent(contentPane, jPasswordField1, 110,45,183,22); addComponent(contentPane, jButton1, 150,75,83,28); // // login // this.setTitle("Login To Members Area"); this.setLocation(new Point(76, 182)); this.setSize(new Dimension(335, 141)); this.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); this.setResizable(false); } /** Add Component Without a Layout Manager (Absolute Positioning) */ private void addComponent(Container container,Component c,int x,int y,int width,int height) { c.setBounds(x,y,width,height); container.add(c); } private void jTextField1_actionPerformed(ActionEvent e) { } private void jPasswordField1_actionPerformed(ActionEvent e) { } private void jButton1_actionPerformed(ActionEvent e) { System.out.println("\njButton1_actionPerformed(ActionEvent e) called."); String username = new String(jTextField1.getText()); String password = new String(jPasswordField1.getText()); if(username.equals("") || password.equals("")) // If password and username is empty Do this { jButton1.setEnabled(false); JLabel errorFields = new JLabel("You must enter a username and password to login."); JOptionPane.showMessageDialog(null,errorFields); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); this.setVisible(true); } else { JLabel optionLabel = new JLabel("You entered "+username+" as your username. Is this correct?"); int confirm =JOptionPane.showConfirmDialog(null,optionLabel); switch(confirm){ // Switch Case case JOptionPane.YES_OPTION: // Attempt to Login user jButton1.setEnabled(false); // Set button enable to false to prevent 2 login attempts break; case JOptionPane.NO_OPTION: // No Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; case JOptionPane.CANCEL_OPTION: // Cancel Case.(Go back. Set text to 0) jButton1.setEnabled(false); jTextField1.setText(""); jPasswordField1.setText(""); jButton1.setEnabled(true); break; } // End Switch Case } } public static void main(String[] args) { JFrame.setDefaultLookAndFeelDecorated(true); JDialog.setDefaultLookAndFeelDecorated(true); try { UIManager.setLookAndFeel("com.sun.java.swing.plaf.windows.WindowsLookAndFeel"); } catch (Exception ex) { System.out.println("Failed loading L&F: "); System.out.println(ex); } new login(); }; }

    Read the article

  • Installing PostgreSQL on Windows

    - by Ross
    I'm in a bit of a mess here. I installed PostgreSQL on my Vista computer a couple of days ago but then when asked to enter the password for the postgre user account I couldn't remember it (allegedly I was asked during setup but I don't remember that). Anyway, so I uninstalled Pg with the intention of reinstalling it, removed the user account, it's /Users/ directory and it's special privelleges ("Advanced user profile properties") but when I come to install Pg it seems to think the account still exists as when I supply a password during setup it says that it is not the correct password - meaning that the account still exists somewhere. Is there anyway I can recover this?

    Read the article

  • How to generate a cryptographically secure Double between 0 and 1?

    - by Portman
    I know how to generate a random number between 0 and 1 using the NextDouble method of the pseudo-random number generator. var rng1 = new System.Random(); var random1 = rng1.NextDouble(); // generates a random double between 0 and 1.0 And I know how to fill a random byte array using the cryptographically secure random number generator. Byte[] bytes = new Byte[8]; var rng2 = new System.Security.Cryptography.RNGCryptoServiceProvider(); rng2.GetBytes(bytes); // generates 8 random bytes But how can I convert the byte-array output of RNGCryptoServiceProvider into a random number between 0 (inclusive) and 1 (exclusive)?

    Read the article

  • Uploading videos to Twitter using OAuth

    - by deepa
    Hi, I am developing an iPhone app that uses Twitvid library for uploading videos to TwitVid. This library first authenticates the app using the user-name and password input parameters. Then it uploads the video. But, recently I switched to OAuth mechanism of authentication which leads to a web-page where user can enter the user-name and password. So, I cannot provide the input fields for user-name and password in my app for uploading video. Can someone help me out to solve this problem. Thanks and Regards, Deepa

    Read the article

  • I get a 400 Bad Request error while using django-piston

    - by Cheezo
    Hello, I am trying to use Piston to provide REST support to Django. I have implemented my handlers as per the documentation provided . The problem is that i can "read" and "delete" my resource but i cannot "create" or "update". Each time i hit the relevant api i get a 400 Bad request Error. I have extended the Resource class for csrf by using this commonly available code snippet: class CsrfExemptResource(Resource): """A Custom Resource that is csrf exempt""" def init(self, handler, authentication=None): super(CsrfExemptResource, self).init(handler, authentication) self.csrf_exempt = getattr(self.handler, 'csrf_exempt', True) My class (code snippet) looks like this: user_resource = CsrfExemptResource(User) class User(BaseHandler): allowed_methods = ('GET', 'POST', 'PUT', 'DELETE') @require_extended def create(self, request): email = request.GET['email'] password = request.GET['password'] phoneNumber = request.GET['phoneNumber'] firstName = request.GET['firstName'] lastName = request.GET['lastName'] self.createNewUser(self, email,password,phoneNumber,firstName,lastName) return rc.CREATED Please let me know how can i get the create method to work using the POST operation?

    Read the article

  • How to write a Compiler in C for C

    - by Kerb_z
    I want to write a Compiler for C. This is a Project for my College i am doing as per my University. I am an intermediate programmer in C, with understanding of Data Structures. Now i know a Compiler has the following parts: 1. Lexer 2. Parser 3. Intermediate Code Generator 4. Optimizer 5. Code Generator I want to begin with the Lexer part and move on to Parser. I am consulting the following book: Compilers: Principles, Techniques, and Tools by Alfred V. Aho, Ravi Sethi, Jeffrey D. Ullman. The thing is that this book is highly theoretical and perplexing to me. I really appreciate the authors. But the point is i am not able to begin my project, as if i am blinded where to go. Need guidance please help.

    Read the article

  • Do all header("Location: member.php?id=$username") have to be the first thing in a script? (PHP)

    - by ggfan
    I know in the Manuel it says that the header has to be the first thing in a script, but how come I see some codes where header("Location: member.php?id=$username") is in a if-statement? Ex: //a bunch of codes above if($result!="0"){ // authenication correct lets login $_SESSION["password"] = $password;; $_SESSION["username"] = $username; header("Location: member.php?id=$username"); } else { echo "Wrong username or password. Please try again!"; } But when I do this, it sometimes would/won't throw an error. How do I allow the header (); to be used in a script without any errors? I want to redirect the user back to the login if they click "no" and to the homepage if they click "yes".

    Read the article

  • A Simulator for a non-deterministic Push-Down Automaton

    - by shake
    Well, i need to make simulator for non-deterministic Push-Down Automaton. Everything is okey, i know i need to do recursion or something similar. But i do not know how to make that function which would simulate automaton. I got everything else under control, automaton generator, stack ... I am doing it in java, so this is maybe only issue that man can bump on, and i did it. So if anyone have done something similar, i could use advices. This is my current organisation of code: C lasses: class transit: list -contains non deterministic transitions state input sign stack sign class generator it generate automaton from file clas NPA public boolean start() - this function i am having trouble with Of course problem of separate stacks, and input for every branch. I tried to solve it with collection of objects NPA and try to start every object, but it doesn work :((..

    Read the article

  • SSIS XML Decryption Message

    - by Vaccano
    My SSIS package says it is successful, but when it runs it ends not doing anything (that I can see). The only thing wrong is this message (that it does not qualify as an error). Description: Failed to decrypt an encrypted XML node because the password was not specified or not correct. Package load will attempt to continue without the encrypted information I do have a password on my packages, but I don't see anywhere to put the password in when I load the Package into SSIS. Am I missing a step?

    Read the article

  • getting notice like undefined index

    - by user2533308
    $result = mysql_query("SELECT * FROM customers WHERE loginid='$_POST[login]' AND accpassword='$_POST[password]'"); if(mysql_num_rows($result) == 1) { while($recarr = mysql_fetch_array($result)) { $_SESSION[customerid] = $recarr[customerid]; $_SESSION[ifsccode] = $recarr[ifsccode]; $_SESSION[customername] = $recarr[firstname]. " ". $recarr[lastname]; $_SESSION[loginid] = $recarr[loginid]; $_SESSION[accstatus] = $recarr[accstatus]; $_SESSION[accopendate] = $recarr[accopendate]; $_SESSION[lastlogin] = $recarr[lastlogin]; } $_SESSION["loginid"] =$_POST["login"]; header("Location: accountalerts.php"); } else { $logininfo = "Invalid Username or password entered"; } Notice: Undefined index:login and Notice: Undefined index:password try to help me out getting error message in second line

    Read the article

  • NHibernate 'IdentifierGenerationException' on an Update trigger

    - by Jan Jongboom
    In my database I have an id column defined as [autonumber] [int] IDENTITY(1,1) NOT NULL which is mapped in my .hbm.xml like: <id name="Id" column="autonumber" type="int"> <generator class="identity" /> </id> When calling session.Save() updates are successful committed to the database. When adding a versioning trigger I however get the error this id generator generates Int64, Int32, Int16 of type IdentifierGenerationException. The trigger is defined as: ALTER TRIGGER [dbo].[CatchUpdates_NVM_FDK_Kenmerken] ON [dbo].[NVM_FDK_Kenmerken] INSTEAD OF UPDATE AS BEGIN SET NOCOUNT ON UPDATE NVM_FDK_Kenmerken SET idIsActive = 0 WHERE internalId IN (SELECT internalId FROM INSERTED) INSERT INTO dbo.NVM_FDK_Kenmerken ( vestigingNummer , internalId , someOtherColumns, dateInserted, idIsActive ) SELECT vestigingNummer, internalId, someOtherColumns, GETDATE(), 1 FROM INSERTED END What am I doing wrong here? When doing manual updates everything works just fine and as expected.

    Read the article

< Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >